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PHP - Searching Mysql With Form Variable
I have a form passing user's search term, ie name.
$pname = mysql_real_escape_string($pname; Not sure on proper syntax to include this in my select statement. I also want it to return for partial string matched, like 'mik' for 'mike': $result = mysql_query( "SELECT * FROM guest WHERE name like '$pname'" ); Similar TutorialsHello, I am working on a project and I cant seem to get this to work. I have a database (Kingsbury) that stores a contact list. I am trying to make an page were a user can search the database by state. The code from the HTML site is: Code: [Select] <form action = "sqlllist.php" method="post"><br /> Please enter the state you would like to search: <input type="text" name="state" /><br /> <p><input type="submit" value="Enter" /></p> </form> And then from the .php file Code: [Select] <?php $DBConnect = mysql_connect("*****", "*****", "********"); if ($DBConnect===FALSE) echo "<p>Connection Failed!.</p>\n"; else { $State == $_POST['state']; $Result = mysql_select_db("Kingsbury", $DBConnect); $queryresult = @mysql_query("SELECT * FROM contacts WHERE State = $State'", $DBConnect); echo "<table width='100%' border='1'>\n"; echo "<tr><th>User ID</th> <th>First Name</th> <th>Last Name</th> <th>Address</th> <th>State</th> <th>City</th> <th>Zip Code</th> <th>Area Code</th> <th>Phone Number</th>\n"; While (($Row = mysql_fetch_row($queryresult)) !== FALSE) { echo "<tr><td>{$Row[0]}</td>"; echo "<td>{$Row[1]}</td>"; echo "<td>{$Row[2]}</td>"; echo "<td>{$Row[3]}</td>"; echo "<td>{$Row[4]}</td>"; echo "<td>{$Row[5]}</td>"; echo "<td>{$Row[6]}</td>"; echo "<td>{$Row[7]}</td>"; echo "<td>{$Row[8]}</td>"; } echo "</table>\n"; mysql_free_result($queryresult); mysql_close($DBConnect); } ?> This, to me seems like it should be working, but it outputs the entire database. I'm trying to do something that I thought was very simple about 2 weeks ago :-( I want to put a form on my site and link it to a database so when a user types a surname into the form they can search the db and the page will only display the surnames that match the search criteria. I got the db set up using phpmyadmin in about 2 minutes flat, but keep getting error messages when I write the php. I'm currently working with the below script, which keeps giving me the error 'unexpected T_string' on line 176 I've searched every forum and help site I can find, and the mysql and php manuals are just mind-boggling. I'm sure I'm making some really amateur mistake, but I'd really appreciate help with this! thanks all! <html> <head> <title>SEARCH RECORDS</title> </head> <body> <FORM NAME ="Search" METHOD ="POST" ACTION = "test3"> <INPUT TYPE = "TEXT" VALUE ="surname" NAME = "surname"> <INPUT TYPE = "Submit" Name = "Search" VALUE = "Search"> </FORM> </body> </html> <? $user_name = "*****"; $password = "*****"; $database = "*****"; $server = "localhost"; $db_handle = mysql_connect($server, $user_name, $password); $db_found = mysql_select_db($database, $db_handle); if ($db_found) { $SQL = "SELECT * FROM *****" WHERE surname=$_POST['surname']; $result = mysql_query($SQL); while ($db_field = mysql_fetch_assoc($result)) { print $db_field['Grave'] . "<BR>"; print $db_field['Surname'] . "<BR>"; print $db_field['Forenames'] . "<BR>"; print $db_field['Death_Date'] . "<BR>"; print $db_field['Birth_Year'] . "<BR>"; } mysql_close($db_handle); } else { print "Database NOT Found "; mysql_close($db_handle); } ?> Hey, Looking to find a solution to something. I have been experimenting making a template engine for a website I am building. How can I search a variable for all occurrences of {VARIABLE} eg. {Username} {Title} {Content} so I can str_replace them. Thank you Hi Members,
I am search for the reason for the problem why my mysql query cannot fetch data and store in file based on id in $variable form. For example, $sql="SELECT * FROM mytable WHERE mine_id='1234'"; works for me. But when i use $sql="SELECT * FROM mytable WHERE mine_id='$id'";, files are created as empty. I chanaged the quotes and could not store the data in file. So anyone please help me.
For more clear, i attach the part of my code
for ($i=0;$i<=10;$i++)
{
$id=$seqs[$i];
$dbo = new PDO($dbc, $user, $pass);
echo $sql = "SELECT * FROM mine_id WHERE locus_id='$id'";
$qry = $dbo->prepare($sql);
$qry->execute();
$data = fopen('file.csv', 'w');
while ($row = $qry->fetch(PDO::FETCH_ASSOC))
{
fputcsv($data, $row);
}
}
Edited by phpnewbie007, 20 November 2014 - 02:17 AM. Dear All, Greetings! I am a student and have a final semester project of making a php based form to search a database. Database is already created: Username: test password: test1 Details: DB Name: resume_bank, Table Name: Candidate Table contents: Name, Phone, Address, DOB, Gender, Designation, experience_yrs, experience_months, Employment_Status I need the code which would give the user an option to search using AND, OR, ALL functions. Friends please help. The form should look like: Enter the Designation you are looking for: Enter the experience: Yrs___ Months___ Select Gender: The result must come in another webpage which has numbered display results, like page-1, page-2, page3... PLEASE HELP URGENTLY!!!!!!! ANY BODY HAS READY MADE CODE PLEASE SEND IT!!!!!! Thanks. im trying to crete a page that will search mysql for entrys from ??? days previous. ive not started on the php yet as i wanted to get the query done but im having a slight problem. date is in dd/mm/yyyy format. if i run this query SELECT * FROM `dsgi_serval` WHERE date >= '10/09/2010' it ONLY sorts by DD and not MM or YYYY, so anything greater than the 10th of the month shows regardless of what month. when i get to the php ill either do a drop down box with a preset number or days or a text box where u enter the number of days or even a txt box u enter the actual day u want to search from. im undecided which would be best. another problem i face with the php is how to tell the script to search from ? ?? when it says search from the past 3 days? <?php $date = date("d/m/y"); // todays date 04/12/2010 $_post= 3 days; // search from 01/12/2010 $date - $_post = $search; // 01/12/2010; $sql="SELECT * FROM $tbl_name" where date >= '$search'; echo the results ?> i no the above is not proper php but i hope it saya what im trying to do. Thanks Hi there,
I'm a bit of a newbie and I have done a search online, but i'm still confused.
I need to search my MYSQL database in a filed named date_mod I need to search for todays date only $date=gmdate("Y-m-d");
But however the field is a datetime option so how can I search only todays date and not both date and time.
Thank you for reading.
Hey guys, im trying to select only certain rows that matchs the address in a array. Not sure how to do this This is making the array $siege_check3 = "SELECT address FROM planets WHERE siege='".mysql_real_escape_string($_SESSION['goauld'])."'"; $siege_check2 = mysql_query($siege_check3) or die(mysql_error()); $arr = array(); while($siege_check1 = mysql_fetch_array($siege_check2)) { $siege_planets = $siege_check1['address']; $arr[] = $siege_planets; } Then I want to AND grab rows where defender_planet equals one of the address in the array above tried using in_array but telling me its not a valid function $alert3 = "SELECT * FROM travel WHERE defender_id = '" .($_SESSION['user_id'])."' AND stance = 2 AND stealth_tech < '".($stealth_tech)."' AND address= in_array(defender_planet,$arr) ORDER BY arrived_time DESC"; $alert2 = mysql_query($alert3) or die(mysql_error()); while($alert1 = mysql_fetch_assoc($alert2)) { } This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=322398.0 Hi, I cannot get my form to find the number "555" entered for a user in the database. There is a table field called "dob" with value 555 for a particular user. Below is the code I am trying to search the table and output a match. Please if anyone can help that would be great. thank you. Code: [Select] <?php $host = ""; $database = ""; $username = ""; $password = "*"; $tbl_name = "users"; $conn = mysql_connect($host, $username, $password) or die("Could not connect: " . mysql_error()); mysql_select_db($database); $dob = $_POST['dob']; //THE SEARCH FUNCTION $result = mysql_query ( "SELECT * FROM users WHERE dob LIKE '%$dob%' "); if(isset($_POST['submit'])) { while ($row = mysql_fetch_assoc($result)) { $message = $row["dob"]; } } ?> <html> <body> <form action="login_successBACKUP02.php" method="post"> <input name="dob" type="text" size="20" id="dob" /> Date of Birth<br /> <input type="submit" value="Store in database and search" /> <input type="reset" value="Reset fields" /> </form> </body> </html> I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here. It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere. <?PHP require('connect.php'); ?> <form action ='' method='post'> <select name="id"> <?php $extract = mysql_query("SELECT * FROM cars"); while($row=mysql_fetch_assoc($extract)){ $id = $row['id']; $make= $row['make']; $model= $row['model']; $year= $row['year']; $color= $row['color']; echo "<option value=$id>$color $year $make $model</option> ";}?> </select> Which attribute would you like to change?<br /> <input type="radio" name="getchanged" value="make"/>Make<br /> <input type="radio" name="getchanged" value="model"/>Model<br /> <input type="radio" name="getchanged" value="year" />Year<br /> <input type="radio" name="getchanged" value="color" />Color<br /><br /> <br /><input type='text' value='' name='tochange'> <input type='submit' value='Change' name='submit'> </form> //This is where I need help... <?PHP if(isset($_POST['submit'])&&($_POST['tochange'])){ mysql_query(" UPDATE cars SET '$_POST[getchanged]'='$_POST[tochange]' where id = '$_POST[id]' ");}?> I am trying to extract a value that is stored in a variable from my database. It will not work with how I have the code written. If I replace .$tournament with what I want it to find, it will give me the correct result. ANy suggestions? Below is my code: Code: [Select] $result = mysql_query("SELECT id FROM `2012_tournaments` WHERE tournament = .$tournament"); while($row = mysql_fetch_array($result)) { echo $row['id']; }; Hi, I am very new to this. Can someone point me in the right direction please. I have mysql database which contains a variable $pricelist. The client is registered via an admin area. Is sent the login (email and password). Once logged in they see their details. All this works fine. Each client will have a different price list, total number of price lists options will be about 10. In the database the variable will return pricelist1.pdf or pricelist2.pdf etc. This is also OK. My question is how do I provide a hyperlink to the pricelist1.pdf file (which is located on the server) for the client to view and download if they wish? Thanks in advance. I have a mysql field that I want to store a php variable in and then retrieve it.
Example:
Color table has the field named colorBackground with the value of #FF0000
CSS table has the field named cssBackground with the value of .background { background-color: #444444; }
What I want to do is make Color/colorBackground a variable {{$backgroundcolor = rsColor['colorBackground']
Then I want to change the CSS/cssBackground value to .background { background-color:$backgroundcolor; }
Creating the $backgroundcolor works fine. I'm just not sure how to put the $backgroundcolor in my CSS/cssBackground field.
Hi im trying to set that if a certain statement is echoed then set variables to an amount but they dont seem to be inserting into the table Code: [Select] if ($match_qutoe == "".$username2." lands a uppercut"){ $points = "4"; $fighter = $username2; } $query = mysql_query("INSERT INTO fight (bluecornerusername, redcornerusername, round, fighter, points, statement) VALUES('$username', '$username2', '$round', '$fighter', '$points', '$match_quote')"); its only $points and $fighter that are not inserting Thanks You guys are great, thanks again for the help last week. Now I almost got this working but a small hiccup. here is my code: Code: [Select] <?php include("config.php"); $my_t=getdate(date("U")); $my_t1=$my_t[weekday]; $result = mysql_query("SELECT * FROM tourney where day_of_week = '$my_t1'") or die(mysql_error()); if ($result == '') echo "<br>Empty Set\n"; print_r ($my_t1); This prints correctly Code: [Select] while ($result = mysql_fetch_array($result,MYSQL_ASSOC)) { This is my error. "Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /hermes/bosweb/web017/b172/ipg.dswdesignsnet/pp4c/charity1.php on line 8" Code: [Select] print "<b>Starting Time: <br></b>".$row{'start_time'}."<br><b>Tournament: </b><br>".$row{'tourney'}."<br><b>Buy-in: <br>".$row{'buy_in'}."<br><b>Starting Chips: <br>".$row{'start_chips'}."</font><p>"; This prints headers correctly, but no variables. Code: [Select] } mysql_close($dbh); ?> What did I forget to do or what did I do wrong. I'm still learning mysql and php. Can anyone point out how to write a MySQL query with a PHP variable in the WHERE clause. I've tried {} {'xx'} and () and it still doesn't work. Here is the code <?php ini_set('display_errors',1); error_reporting(E_ALL|E_STRICT); include ("include/connect.php"); include ("include/session.php"); $username = $session->userinfo['username']; $result = mysql_query("SELECT email FROM customer WHERE user = {'$username'} "); while($row = mysql_fetch_array($result)) { $custemail = $row['email']; } echo "Session username: " . $username . ""; echo "Session customer email: " . $custemail . ""; ?> So I'm trying to show the email address for a record that matches the username of the user logged in. I really appreciate the help. Hi anyone here know how to insert $GET variable into mysql, i don't know how to put this variable between curly bracket, when i put on top insert query, i got error 'Could not insert admin'...please help Code: [Select] <?php mysql_connect("localhost","root","") or die(mysql_error()); mysql_select_db("healthsystem") or die(msql_error()); [color=red]//GET varibable $id = $_GET['id'];[/color] // file properties $file = $_FILES['image']['tmp_name']; if (!isset($file)) echo "Please select an image"; else { $image = addslashes(file_get_contents($_FILES['image']['tmp_name'])); $image_name = addslashes($_FILES['image']['name']); $image_size = getimagesize($_FILES['image']['tmp_name']); if ($image_size==FALSE) echo "That's not an image."; else { $insert = "INSERT INTO image_tbl(m_id,name,image) VALUES ('$id','$image_name','$image')"; $insert2=mysql_query($insert) or die("Could not insert admin"); print "Personal Wellness Successfully Submitted"; } } ?> hello can anyone help me how to insert GET variable into mysql <?php $page_title = 'Personal Wellness'; include ('template/header.inc'); include_once('config.php'); $id = $_GET['id']; if(isset($_POST['submit'])) //if submit was pressed { if(strlen($_POST['height'])<1) //if there was no height { print "You did not enter a height."; } else if(strlen($_POST['weight'])<1) //no weight { print "You did not enter a weight."; } else if(strlen($_POST['bodyfat'])<1) //no bodyfat { print "You did not enter a Body Fat Range"; } else if (strlen ($_POST['bodywater'])<1) //no bodywater { print "You did not enter a Body Water Range"; } else if( strlen($_POST['musclemass'])<1) //no musclemass { print "You did not enter a Muscle Mass"; } else if (strlen ($_POST['physiqueratt'])<1) //no physiqueratt { print "You did not enter a Physique Ratings"; } else if (strlen ($_POST['bonemass'])<1) //no bonemass { print "You did not enter a Bone Mass"; } else if (strlen ($_POST['bmr'])<1) //no bmr { print "You did not enter a BMR"; } else if (strlen ($_POST['basalmetabolic'])<1) //no basalmetabolic { print "You did not enter a Basal Metabolic Age"; } else if (strlen ($_POST['visceralfat'])<1) //no visceralfat { print "You did not enter a Visceral Fat"; } else if(strlen($_POST['registrationmonth'] && $_POST['registrationday'] && $_POST['registrationyear'])<1) // no date { print "You did not enter a date of birth"; } else //all fields met { $id=$_GET['id']; $height=$_POST['height']; $weight=$_POST['weight']; $bodyfat=$_POST['bodyfat']; $bodywater=$_POST['bodywater']; $musclemass=$_POST['musclemass']; $physiqueratt=$_POST['physiqueratt']; $bonemass=$_POST['bonemass']; $bmr=$_POST['bmr']; $basalmetabolic=$_POST['basalmetabolic']; $visceralfat=$_POST['visceralfat']; $date=$_POST['registrationyear'] . '-' . $_POST['registrationmonth'] . '-' . $_POST['registrationday']; $insertadmin="INSERT into personalwelness (m_id,height,weight,body_fat,body_water,muscle_mas s,physique_ratt,bone_mass,bmr,basal_metabolic,visc eral_fat,evaluation_date) values ('$id','$height','$weight','$bodyfat','$bodywater','$mus clemass','$physiqueratt','$bonemass','$bmr','$basa lmetabolic','$visceralfat','$date')"; //registering admin in databae echo $insertadmin; $insertadmin2=mysql_query($insertadmin) or die("Could not insert admin"); print "Personal Wellness Successfully Submitted"; } } ?> <form method="post" class="form" action="<?php echo $_SERVER['PHP_SELF'];?>"> <fieldset><legend>Enter Personal Wellness Information in the form below:</legend> <table width="80%" border="0"> <tr> <td width="16%">Height(CM)</td> <td width="2%">:</td> <td width="82%"><label for="height"></label> <input type="text" name="height" id="height" value="<?php if (isset($_POST['height'])) echo $_POST['height'];?>" /></td> </tr> <tr> <td>Weight(KG)</td> <td>:</td> <td><label for="weight"></label> <input type="text" name="weight" id="weight" value="<?php if (isset($_POST['weight'])) echo $_POST['weight'];?>" /></td> </tr> <tr> <td >Body Fat Range</td> <td>:</td> <td><label for="body fat"></label> <input type="text" name="bodyfat" id="bodyfat" value="<?php if (isset($_POST['bodyfat'])) echo $_POST['bodyfat'];?>" ></td> </tr> <tr> <td>Body Water Range(%)</td> <td>:</td> <td><label for="bodywater"></label> <input type="text" name="bodywater" id="bodywater" value="<?php if (isset($_POST['bodywater'])) echo $_POST['bodywater'];?>"/></td> </tr> <tr> <td>Muscle Mass</td> <td>:</td> <td><label for="musclemass"></label> <input type="text" name="musclemass" id="musclemass" value="<?php if (isset($_POST['musclemass'])) echo $_POST['musclemass'];?>"></td> </tr> <tr> <td>Physique Ratings</td> <td>:</td> <td><label for="physiqueratt"></label> <input type="text" name="physiqueratt" id="physiqueratt" value="<?php if (isset($_POST['physiqueratt'])) echo $_POST['physiqueratt'];?>"></td> </tr> <tr> <td>Bone Mass</td> <td>:</td> <td><label for="bonemass"></label> <input type="text" name="bonemass" id="bonemass" value="<?php if (isset($_POST['bonemass'])) echo $_POST['bonemass'];?>" /></td> </tr> <tr> <td>BMR</td> <td>:</td> <td><label for="bmr"></label> <input type="text" name="bmr" id="bmr" value="<?php if (isset($_POST['bmr'])) echo $_POST['bmr'];?>"/></td> </tr> <tr> <td>Basal Metabolic Age</td> <td>:</td> <td><label for="basalmetabolic"></label> <input type="text" name="basalmetabolic" id="basalmetabolic" value="<?php if (isset($_POST['basalmetabolic'])) echo $_POST['basalmetabolic'];?>"></td> </tr> <tr> <td>Visceral Fat</td> <td>:</td> <td><label for="visceralfat"></label> <input type="text" name="visceralfat" id="visceralfat" value="<?php if (isset($_POST['visceralfat'])) echo $_POST['visceralfat'];?>"></td> </tr> <tr> <td>Evaluation Date</td> <td>:</td> <td> <?php echo date_picker("registration")?></td> </tr> </table> </fieldset> <div align="center"><input type="submit" name="submit" value="Submit" /> </div> </form> <?php function date_picker($name, $startyear=NULL, $endyear=NULL) { if($startyear==NULL) $startyear = date("Y")-100; if($endyear==NULL) $endyear=date("Y")+50; $months=array('','January','February','March','Apr il','May', 'June','July','August', 'September','October','November','December'); // Month dropdown $html="<select name=\"".$name."month\">"; for($i=1;$i<=12;$i++) { $html.="<option value='$i'>$months[$i]</option>"; } $html.="</select> "; // Day dropdown $html.="<select name=\"".$name."day\">"; for($i=1;$i<=31;$i++) { $html.="<option $selected value='$i'>$i</option>"; } $html.="</select> "; // Year dropdown $html.="<select name=\"".$name."year\">"; for($i=$startyear;$i<=$endyear;$i++) { $html.="<option value='$i'>$i</option>"; } $html.="</select> "; return $html; } ?> <?php include ('template/footer.inc'); ?> Hi again everyone, I am trying to compare a php variable to the value of a row in mysql, but keep getting the following error: Code: [Select] Wrong perameter count for mysql_result() What syntax would I use to accomplish this? Here is my code: // connects to server and selects database. include ("../includes/dbconnect.inc.php"); // table name $table_name = "availability"; // split up date into 3 separate fields $date = "12/25/2010"; $date_split = explode("/", $date); $month = $date_split[0]; $day = $date_split[1]; $year = $date_split[2]; // check if earth room is already reserved $taken = "Reserved"; $sql = "SELECT earth_room FROM $table_name WHERE month='$month' AND day='$day' AND year='$year' LIMIT 1"; $result = mysql_query($sql) or trigger_error("A mysql error has occurred!"); $row = mysql_result($result); if($row == $taken){ echo "Room Already Reserved"; } else{ echo "Room Available"; } Thanks for the help, kaiman |
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