PHP - How To Show The Current Date And Time In My Database Tables

I have a query that fetches all the dates in a date range then displays them in a Date:HH:MM;SS format.   However when displayed sometimes there are missing Hours as I don't have data for them and I would like to display it.  So right now I have something like this.

Date Column:                Revenue_Column:
07/29/2010 00:00:00   $250.00
07/29/2010 01:00:00   $150.00
07/29/2010 03:00:00   $350.00
07/29/2010 04:00:00   $450.00

As you can see 02:00:00 is missing, how can I use php or possibly mysql to fill in that gap?   I have tried creating an hours table and joining them and grouping by date however that doesn't seem to work.  Any ideas?

I have my database set to insert the current time stamp when an entry is made into the table, I am then trying to retrieve via the following code:


$select_view_idea="SELECT * FROM $tbl_name5 WHERE message_number='$message_number'";
$result_view_idea=mysql_query($select_view_idea);
while($row_view_idea=mysql_fetch_assoc($result_view_idea)){
extract($row_view_idea);
}
date_default_timezone_set('US/Eastern');
$date=date('l, F jS Y h:i:s A T', $date);
echo $date;


The above is outputting:
Wednesday, December 31st 1969 07:33:31 PM EST

the database contains:
2011-11-18 00:47:56

Currently the date is stored in the database as 28-02-2011 - 21:00:30 and the variable is: $date['mTime']

How can I format it too look "pretty" like this: February 28, 2011 - 10:00 PM? (don't need the seconds)

I have the date stored as: date( "d/m/Y" )

After it's pulled from the database, I would like it to display like:

date( "F j, Y" )

I have tried below, but the output makes d the month and m the day.

$dateStamp = strtotime($row['startrepeat']);
$dateFormatted = date("F j, Y", $dateStamp);

hiii all, i want to show the database field (alise name) as the url after index.php when page or site loads first time. how i can achieve it? please help.... thanks in advance

Hello,   I want to show checkbox is checked when there is entry of that id in a table in my database.    I have 2 tables page and access_level. I am getting data from page table and displays it in <ul><li> tag with checkbox to select all or only few. After selecting the checkbox, i will store only selected checkbox value in access_level table along with table id. Page link and page name details will be stored in page table.    Now if i want to edit , i should display all the pages which is there in page table and i should also mark checked to those which are already stored in access_level table.   I am using LEFT OUT JOIN, It displays all the pages. But it is not displaying the check mark to those which are already selected.   Here is my code

<?php $s1 = mysql_query("SELECT pages.page_id, pages.code, pages.page, pages.href, access_level.aid, access_level.page_id as pgid, access_level.department, access_level.position, access_level.active FROM pages LEFT OUTER JOIN access_level ON pages.page_id=access_level.page_id WHERE access_level.department=".$department." AND access_level.position=".$position." AND pages.code='sn'") or die(mysql_error());
				while($s2 = mysql_fetch_array($s1)) { ?>
				<tr><td><li><?php echo $s2['page']; ?>  </td><td><input type="checkbox" name="sn[]" value="<?php echo $s2['page_id']; ?>"  
                <?php if($row['pgid'] === $s2['page_id']) echo 'checked="checked"';?> />

here is my pages table     pages.JPG   26.55KB   0 downloads   access_level  access_level.JPG   19.09KB   0 downloads   In access_level table i do not have page ids 8 and 9. But i want to display that also from pages table and for 1 to 7 and 10 i should display check mark.    How i can achieve this? Please Help

Hey,

I'm using a script which allows you to click on a calendar to select the date to submit to the database.

The date is submitted like this: 2014-02-08

Is there a really simple way to prevent rows showing if the date is in the past?

Something like this:
if($currentdate < 2014-02-08 || $currentdate == 2014-02-08) {

}

Thanks very much,
Jack

Hey guys,
How would I go about subtracting Today from a previous day to find the difference?

For example, I want to subtract TODAY from a previous date in my database, to determine if the difference is greater than 1 day.

Any ideas? I tried doing the subraction in TIMESTAMPS, but when I convert the date back to Y-m-d H:i:s, I got some weird year and time.
 

(continuing from topic title)
So if I set a date of July 7 2011 into my script, hard coded in, I would like the current date to be checked against the hard coded date, and return true if the current date is within a week leading up to the hard coded date.

How could I go about doing this easily?

I've been researching dates in php but I can't seem to work out the best way to achieve what I'm after.

Cheers
Denno

Hi,

I have database stored a field of date. I want to check if the date in the DB field is the same as the current date, how to do it?

Code:

$oracle = mysqli_real_escape_string($con, $_POST['oracle']);
$query 	= mysqli_query($con, "SELECT indate FROM staff WHERE OracleID ='$oracle'");
$row	= mysqli_fetch_array($query);
$num_row = mysqli_num_rows($query);
		
	if ($num_row > 0) 
	{	
		$curdate = date();
		if ($row['indate'] !== $curdate)
		{
			$query1=mysqli_query($con, "update staff set ClockedIn = 0, ClockedOut = 0 where OracleID='$session_id'")or die('Error In Session');
			header('location:home.php');				
		}
	}

 

PHP date and time function is not showing correct time on my local system

I have the following php code

date_default_timezone_set("Africa/Lagos");

$date = date('d-m-y h:i:s');

echo "Server Time ".$date ."<br>";

echo "The time is " . date("h:i:sa")."<br>";

$current_datetime = date("Y-m-d") . ' ' . date("H:i:s", STRTOTIME(date('h:i:sa')));

echo "Current time1: ".$current_datetime . "<br>";

 

Output

Server Time 21-05-21 09:55:39
The time is 09:55:39am
Current time1: 2021-05-21 09:55:39

 

Expected Output

Server Time 21-05-21 10:55:39
The time is 10:55:39am
Current time1: 2021-05-21 10:55:3

 

Any help would be appreciated.

 

Edited May 21 by Ponel

Hi;   I would like to get the current timestamp but the question is that i want to get the real time which is the machine bios time that can't change by the server administrator and not the server time which can be modified to any value.   Thanks

I want to show a cookie of a referral's username on a sign up page. The link is like this, www.mysite.com/signup?ref=johnsmith.

The cookie doesn't show if I go to that url page. But it does show up once I reload the page.  So I'm wondering if it's possible to show the cookie the first time around, instead of reloading the page?

Here is my code.

// This is in the header
$url_ref_name = (!empty($_GET['ref']) ? $_GET['ref'] : null);

if(!empty($url_ref_name)) {

  $number_of_days = 365;
  $date_of_expiry = time() + 60 * 60 * 24 * $number_of_days;
  setcookie( "ref", $url_ref_name, $date_of_expiry,"/");

} else if(empty($url_ref_name)) {
  if(isset($_COOKIE['ref'])) {
    $user_cookie = $_COOKIE['ref'];
  }
} else {}

// This is for the sign up form
if(isset($_COOKIE['ref'])) {
  $user_cookie = $_COOKIE['ref'];
  ?>
  <fieldset>
    <label>Referred By</label>
    <div id="ref-one"><span><?php if(!empty($user_cookie)){echo $user_cookie;} ?></span></div>
    <input type="hidden" name="ref" value="<?php if(!empty($user_cookie)){echo $user_cookie;} ?>" maxlength="20" placeholder="Referrer's username" readonly onfocus="this.removeAttribute('readonly');" />
  </fieldset>
  <?php
}

 

Hi,

This may be something for JavaScript but I would like to know if and how it's possible to show who is currently active/viewing the page. Users are logged into the system with their own account.

The purpose of this is for a CRM where more than one person may be editing the same record, so undesired overwrites might occur which is what I'd like to avoid with this "other user editing this record" notification.

Hi guys,

I will like to insert a countdown timer of 5 mins after form has been submitted to a php page.

At the moment when they submit the form they see the date and time they submitted:

echo date("M d Y  H:i", time()) ";

Any ideas?