PHP - Debug Code For Retaining Selection

Hi guys, I had a problem before which is similar to the problem im about to describe, however Pikachu helped me solve the last problem so a big thanks to him! However this problem is slightly different and im struggling to find a solution. I will first describe the problem I had which pikachu helped me solve as it would be easier for me to describe this past problem.

I have an update form, so a user can edit existing records which are pulled from a database. When the user changes the values in a text field then submits the form, the values in the text fields updates fine. However if they change the values in the text box and then tries to submit the form but there was an error, the values in the text fields go back to the values from the database and the user has to change the text fields again.

Well this problem was solved with the help of pikachu and the this is what I did...

<?php if(isset($_POST['title'])){echo htmlspecialchars($_POST['title']);} else if (isset($title)) {echo htmlspecialchars($title);}?>

Again, the above works fine however the problem I have now is the same problem as described above however it relates to drop down menus and not text fields. I can't seem to figure out how to retain the values in a drop down menu the same way I have for text fields. Below is the code that im using that I thought would work however it isnt working, the values of the drop down menu (if there was an error) are going back to the values from the database. Heres the code...

<option value="Psychopathic" <?php if ((isset($_POST['category']))&&($_POST['category'] == 'Psychopathic')) { echo ' selected=selected'; }  else if ((isset($category))&&($category == 'Psychopathic')) { echo ' selected=selected'; } ?>>Psychopathic</option>

Does anybody know what i am doing wrong and how i can fix this problem? I understand what i need to do but i cant seem to get the code to do what i want to do and thats to retain values of a drop down menu when the page is returned with an error.

Any help would be much appreciated.

AJay

Hi all,

i need some help in retaining the values in an <option> textbox..

I have found a code to loop the date online, and use it for Javascript jump menu, but i have no ideas how to retain the option.. here are my codes(in red),

$year1 = date('Y');
$month1 = date('m');
$day1 = date('j');

$day1 = $day1 + 1;

$year2 = date('Y') + 2;
$month2 = date('m');
$day2 = date('j');

$start_date = "$year1-$month1-$day1";
$end_date = "$year2-$month2-$day2";


$date = mktime(0,0,0,$month1,$day1,$year1); //Gets Unix timestamp START DATE
$date1 = mktime(0,0,0,$month2,$day2,$year2); //Gets Unix timestamp END DATE
$difference = $date1-$date; //Calcuates Difference
$daysago = floor($difference /60/60/24); //Calculates Days Old



$i = 0;
while ($i <= $daysago +1) {
if ($i != 0) { $date = $date + 86400; }
else { $date = $date - 86400; }



$yy1 = date('Y',$date);
$mm1 = date('m',$date);
$dd1 = date('d',$date);
$date3 = "$yy1-$mm1-$dd1" ;



echo "<option value=\"test1234.php?m=$mm1&amp;y=$yy1&amp;d=$dd1\"  ";
echo ">".$date3 ."</option>";
$i++;
}

i know that i have to something selected, but i dun understand how this set of date code loop which left me helpless.

Here  is my hierarchy:

data      -logs folder-debug.log
htdocs   -index.php
include   -Contollers,Smarty,Templater,Zend
templates

Now when I launch index.php from htdocs, I get this un-seeming error:

"Fatal error: Uncaught exception 'Zend_Log_Exception' with message '"/var/htdocs/Books/practical_Web2.0/data/logs/debug.log" cannot be opened with mode "a"' in C:\xampp\php\PEAR\Zend\Log\Writer\Stream.php:69 Stack trace: #0 C:\xampp\htdocs\Books\practical_Web2.0\chapter-02\htdocs\index.php(11): Zend_Log_Writer_Stream->__construct('/var/htdocs/Boo...') #1 {main} thrown in C:\xampp\php\PEAR\Zend\Log\Writer\Stream.php on line 69 "

I went to the zend folder in xampp, php, pear, zend, log, writer.php dir and I found this:

/**
     * Class Constructor
     *
     * @param  streamOrUrl     Stream or URL to open as a stream
     * @param  mode            Mode, only applicable if a URL is given
     */
    public function __construct($streamOrUrl, $mode = 'a')
    {
        if (is_resource($streamOrUrl)) {
            if (get_resource_type($streamOrUrl) != 'stream') {
                require_once 'Zend/Log/Exception.php';
                throw new Zend_Log_Exception('Resource is not a stream');
            }

            if ($mode != 'a') {
                require_once 'Zend/Log/Exception.php';
                throw new Zend_Log_Exception('Mode cannot be changed on existing streams');
            }

            $this->_stream = $streamOrUrl;
        } else {
            if (! $this->_stream = @fopen($streamOrUrl, $mode, false)) {
                require_once 'Zend/Log/Exception.php';
                $msg = "\"$streamOrUrl\" cannot be opened with mode \"$mode\"";
                throw new Zend_Log_Exception($msg);
            }
        }

        $this->_formatter = new Zend_Log_Formatter_Simple();
    }
 

line 69 is =>throw new Zend_Log_Exception($msg);

What could be wrong?
Hint:

settings.conf
[development]

database.type       = pdo_mysql
database.hostname   = localhost
database.username   = root
database.password   =
database.database   = phpweb20

paths.base      = /var/htdocs/Books/practical_Web2.0
paths.data      = /var/htdocs/Books/practical_Web2.0/data
paths.templates = /var/htdocs/Books/practical_Web2.0/templates

logging.file = /var/htdocs/Books/practical_Web2.0/data/logs/debug.log


Any pointer as to why there is a fatal error?

I need help debugging some homework.I have narrowed the problem down to the switch. when it gets to the switch it is spitting out the default everytime, also in the default the $score in both echo statment is not showing. Its probably something small killing me I just can't see it and dont have enough experience with php yet.

<body>
    <?php
    $faceNamesSingular = array("one", "two", "three", "four", "five", "six");
    $faceNamesPlural = array("ones", "twos", "threes", "fours", "fives", "sixes");
    
    function checkForDoubles($die1, $die2) {
        global $faceNamesSingular;
        global $faceNamesPlural;
        $returnValue = false;
        if ($die1 == $die2) { //Doubles
            echo "The roll was double ", $faceNamesPlural[$die1-1], ".<br />";
            $returnValue = true;
        }
        else { // Not Doubles
            echo "The roll was a ", $faceNamesSingular[$die1-1], " and a ", $faceNamesSingular[$die2-1], ".<br />";
            $returnValue = false;
        }
        return $returnValue;
    }    
    function displayScoreText($scores, $doubles) {
        switch ($score) {
            case 2:
                echo "You rolled snake eyes!<br />";
                break;
            case 3:
                echo "You rolled a loose deuce!<br />";
                break;
            case 5:
                echo "You rolled a fever five!<br />";
                break;
            case 7:
                echo "You rolled a natural!<br />";
                break;
            case 9:
                echo "You rolled a nina!<br />";
                break;
            case 11:
                echo "You rolled a yo!<br />";
                break;
            case 12:
                echo "You rolled boxcars!<br />";
                break;
            default:
                if ($score % 2 == 0) {//any even number
                    if ($doubles) {
                        echo "You rolled a hard $score!<br />";
                    }
                    else { //Not Doubles
                        echo "You rolled an easy $score!<br />";
                    }
                }
                break;
        }
    }
    
    $dice = array();
    $dice[0] = rand(1,6);
    $dice[1] = rand(1,6);
    $score = $dice[0] + $dice[1];
    echo "<p>";
    echo "The total score for the roll was $score.<br />";
    
    $doubles = checkForDoubles($dice[0], $dice[1]);
    displayScoreText($score, $doubles);
    echo "</p>";
    ?>
</body>
</html>

Attached Files  DiceRoll.php   1.94KB   0 downloads

Hi all,

Well new to the forum. And New to PHP. I have a quick question.

I'm trying to figure out what the best pratice would be to get familier with a php installation. More specificly how to discover what php is specificly producing a specific part of the final rendered HTML. I have a MyBB Forum me and my cuzin are setting up and for the life of me i can find the right place to add our own HTML to change a specific Div in the Final page output.

here is the link to our URL http://destroyrebuilduntilgodshows.net/forum/ I specificly want to find out where i can edit the contents of the "wrapper_container" Div. I have searched for the source on my local machine. but all i can find is the CSS responsible for the styling and as it turns out the images being held in that div. My end goal is to replace the "advertise here" image with come JS that does our ad managment.


So, I guess my question is How would you find it. How would you find the responsible php for that section of the HTML.



Thanks All.

Cheers

I don't know how to debug this.  The if is being executed and I want to have the else be executed.  How can I find out what $_POST['id'] is?

Code: [Select]
if (isset($_POST['id']) === false)
{
echo 'Invalid user id.';
}
else
{
partner_request($_POST['id']);
echo "A request has been sent to the user";
}

I cannot figure out how to retain the inputted information once submit is pressed. I want the user to enter their first name, last name, hours of work, and hourly pay rate. Then, I want them to press submit. Their pay will be calculated and displayed, but I still want their inputted information to be visible. How can I do that??

Here is my code:
Code: [Select]
<html>
<head>

<?php

$pay = $_POST['pay'];
$hours = $_POST['hours'];
$extra = $_POST['extra'];
$rate = $_POST['rate'];

if ($hours > 40){
        $extra=$hours-40;
        $hours=40;
        $pay=($extra*1.5*$rate)+($hours*$rate);
} else {
        $pay=$hours*$rate;
}
echo "Your pay is:  <br /> $ $pay <br />"
;

?>
</head>
<body>

<form method='post' action='pay2.php'>
First Name: <input type='text' name='first'><br/>
Last Name: <input type='text' name='last'><br/>
Hours of Work: <input type='text' name='hours'><br/>
Hourly Pay Rate: <input type='text' name='rate'><br/>
<input type='submit' value='submit'>

</form>
</body>
</html>

Am new to php... I have been battling on my dynamic checkboxes in such a way that if none is checked the form is return, also I need to retain what was checked when the form postback due to other invalid inputs.

Code: [Select]
$result = mysql_query("SELECT * FROM course") or die(mysql_error()); if ($result) { while ($row = mysql_fetch_array($result)){ if (isset($_POST['courses']) and $_POST['courses'] == $row['cid']) {echo $row['cid'];} print "<input type=\"checkbox\" name=\"courses[]\" value=\"$row[cid]\">$row[cname]\n"; } }
Help needed purely on php codes. Thanks in advance

Hi there,   I am getting this in a PHP generated email:   ACWA Member/Subscriber: Melody’s Children’s Service   The line of code in the php is:     $subject = "ACWA Member/Subscriber: $membername";   I have tried htmlentitiies, html_entity_decode, htmlspecialchars but nothing seems to work.   I haven't used htmlentities anywhere else in the code for this variable.   Any suggestions?   All advice gratefully received.

Ok from one brick wall to the next. After lots of help with my last query I moved onto the next task an I'm completely stuck again.

I have a form thats created with a loop.  Here is that form


 <form action="" method="post" id="">
        <?php 
 for ($i = 1; $i <= $totalRows_rs_cacheNum; $i++) {
    echo "<label>Cache ".$i."</label>
          <span id='sprytextfield".$i."'>
         <input name='cache[$i]' type='text' value='".$_POST['cache[$i]']."'/>
         <span class='textfieldRequiredMsg'>Required!</span></span>
         <div class='clear'></div>";
}
?>
 <input name="nextbtn" type="submit" value="Next" />


When a user enters data in all the fields, If one piece of information is incorrect an error pops up saying one of the fields you entered does not match the fields in the database. At the same time however i wish to keep the data they have entered in each of the fields.

Normally you'd just write

value="<?php echo $_POST['fieldName'];?>"

but for some reason in this case it does not work. can someone point me in the right direction.  I've tried Google many different terms but I can not find the correct term to find my answer.  Hence me asking you guys again.

Thanks

I have a simple INSERT statement that isn't inserting anything into one of the columns: coin_name
I've gone over everything and can't figure out why. All other columns get data.
HTML form passes everything fine. Is there a good way to debug this? I've triple checked everything and there are no type-o's that I see. Driving me mad...


$query = "INSERT INTO Coin (coin_name, coin_value, coin_condition, year_minted, face_value, purchase_price) VALUES 
('$coin_name', '$coin_value', '$coin_condition', '$year_minted', '$face_value', '$purchase_price');";

I'm trying to debug a sporadic 500 error which users occasionally get when filling out form sections on my site. Whenever it happens, I try to recreate their environment and fill out the form exactly as they have done, but can never recreate the issue. I have checked my application logs for the framework I am using, but they report nothing related to the error. I'm hoping someone here might be able to help me catch this. This is where the 500 error is sometimes happening and this triggers the error which users report:

Code: [Select]
//In jquery AJAX function, which submits data to PHP form for processing
error: function(data,transport){
$.validationEngine.debug("error in ajax response: "+data.status+" "+transport)
}
Is there a way for me to try and catch what the exact error is here? The problem is I can't recreate the error, either using an AJAX call or not to call the PHP script. I need to catch the error response from the PHP script being called, but I never get an error when trying to recreate the user issue, i.e same OS/browser/form answers. The Apache error logs for the site have very little - unless I'm looking in the wrong place. I'm on CentOS, ran locate error_log and got an error_log.txt file in my vhosts directory for my site, but this just contained a 302 message log, nothing else. I also tried locate error | grep mysite.

Hello all.

I'm new here... and new to php... so please be gentle if I'm overlooking something that's blindingly obvious.

I have a 'view blog entries' page and an 'edit blog entries' page. When I go to the 'edit blog entries' page, I want the form fields to display the preexisting blog content for whatever entry I'm about to edit.

The code below does display the 'title' but it does not display the 'article' content. (However, the 'title' and 'article' content both show when I view the source code.)

Can anyone tell me what I could be doing wrong? Thanks in advance.

Code: [Select]
// Retrieve the blog post's information:
$q = "SELECT title, article FROM entries WHERE article_id=$article_id";
$r = @mysqli_query ($dbc, $q);

if (mysqli_num_rows($r) == 1) { // Valid blog entry ID, show the form.

// Get the blog entry's information:
$row = mysqli_fetch_array ($r, MYSQLI_NUM);

echo '<form action="edit_entry.php" method="post">

<p>Title:<br />
<input type="text" name="title" size="45" maxlength="80" value="' . $row[0] . '" /></p>
<p>Blog entry<br />
    <textarea name="article" id="article" cols="45" rows="5" ' . $row[1] . '></textarea>
  </p>

<p><input type="submit" name="submit" value="Submit" /></p>
<input type="hidden" name="submitted" value="TRUE" />
<input type="hidden" name="article_id" value="' . $article_id . '" />
</form>';

} else { // Not a valid entry ID.
echo '<p class="error">This page has been accessed in error.</p>';
}
mysqli_close($dbc);
?>

Hi I have a list of states using the array method in a form. The drop down menu works fine.  I want to save the user choice,if the form is re-displayed due to a blank field or pattern mismatch.  I know I can use the selected=selected, but don't know wher to put the statement:
My array is:
state_province = array ("list of states", "provinces")
Var in my labels array is "state"=>"state"
Here is my code for the select/option statement:

{
 if($field == "state")
   {
      echo "<div class='province_state'><label for='state' size='10'>* Province/State</label><select>";
            
      foreach($state_province as $state)
         {
         echo "\n<option value='$state_province' /> ";   
          echo $state ;
          echo "</option>";
         }
      echo "</select></div>\n";   

   }
?Is this the correct code to add and where would I add  it?
          if(@$_POST['state'] == $value)
     {
         echo "selected='selected'  ";
     }          

Hey,
Im needing some help with an update form that I have created using PHP/MySQL. Basically the form is working great (updating records, retrieving records and showing errors) but there is a problem with the errors.

If there are no errors and I edit the existing text input values, the database updates fine. However if I edit the existing text input values and there is an error, the edited input values dont save, they revert back to the values of the database.

I understand why this is happening, its because the text inputs are set to show the values of the database so if i edit the existing values and an error occurs or the page is refreshed, the values revert back to the database values. However id like it so that if any text in the text field have been edited and an error occurs, the text stays to how it is until the user by passes any errors and then the database is updated.

Hopefully this makes sense. I have attached the php page just incase anybody wants to look into it but any help would be much appreciated!

Also, im not looking for someone to just to fix this for me but if someone knows my problem and can guide me in the right direction, that would be great.