|
PHP - Syntax For Including Variables Within A Href Links
Code: [Select]
$query = mysql_query("SELECT name FROM business WHERE type ='Restaurant' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) { $i++; echo $nt[$i]."<br/>";} Now im trying to swap the last line; Code: [Select] echo $nt[$i]."<br/>";} for somthing more like Code: [Select] echo "<a href="$nt[$i].html">$nt[$i]</a>";} My syntax seems to be shot to pieces, and i recieve errors. any ideas welcome? The error i receive is "Parse error: syntax error, unexpected T_VARIABLE, expecting ',' or ';' " Many thanks. Similar TutorialsHi guys, I'm currently in the process of making a simple social networking type site for a uni project and have basically everything i want except the ability to use AJAX to link to my profiles in the search bar. I have this code to generate my XML: Code: [Select] <?php // create simplexml object $xml = new SimpleXMLElement('<rss version="2.0"></rss>'); // add channel information $xml->addChild('channel'); $xml->channel->addChild('title', 'The Social Network'); $xml->channel->addChild('link', 'http://reecesayer.com/projects/template/XML/news.rss'); $xml->channel->addChild('description', 'example'); // query database for article data include("phpfunctions.php"); db_connect(); $link = "www.reecesayer.com/projects/template/testprofile.php?id="; $select='SELECT email, id FROM users'; $result = mysql_query($select) or die(mysql_error()); while ($row = mysql_fetch_assoc($result)) { // add item element for each article $item = $xml->channel->addChild('item'); $item->addChild('email', $row['email']); $item->addChild('link', $row['id']); //I wanted to add a link before the $row['id'] } // save the xml to a file $xml->asXML('profiles.xml'); header ('Location: http://reecesayer.com/projects/template/XML/profiles.xml'); ?> I need to add a partial URL (http://reecesayer.com/projects/template/testprofile.php?id=) before the row is called so that when the email is searched it provides a link to the profile depending upon the id (http://reecesayer.com/projects/template/testprofile.php?id=8) Is there an easier way to do this or am i going the long way around? I'm only storing the data in XML as i saw a tutorial for a livesearch script on another site. Cheers, Reece Im looking to change my page ever so slightly to fit in with my .htaccess file. However I have a syntax issue. Can anybody explain how to fix the below syntax and what i have done wrong so that I can learn from it. Code: [Select] <?php $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Cars and Travel' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]); $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href="str_replace(' ','_',$nt[$i])">" . ucwords(strtolower (($nt[$i]))) . "</a>" . "<br/>"; /*THE SYNTAX ERROR Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' IS IN THE ABOVE LINE*/ $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> This is how it was before; <?php $nt = array(); $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Legal' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?subtype=$FileUsed'>" . ucwords(strtolower (($nt[$i]))) . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> The reason ive altered the top script is that i want my links to be like mysite.com/solicitor opposed to mysite.com/solicitor.php?subtype=solicitor The error is on line 47 which I have labelled in comments PS. I know my php is a bit of a wreck but when I get this syntax issue fixed Ill be working on it. I can't figure out how to write the a href part to make it blend in with the existing img syntax. How do I alter this? Code: [Select] <?php echo '<a href=\"{$r['feedusername']\"><img src="', getUserAvatar($r['feedusername']), "\" class=\"avatar mediumsmall newspadding f_left mrl\" title=\"${r['associate_name']}\" alt=\"${r['associate_name']}\" /></a>"; ?> Hi there! I'm trying to put 2 variables using href. Ive got it already, but when I tried to insert the page=1, which is the the variable for my paginated code.It doesn't work. When I used the codes below, from other page (I don't used variable) it works Code: [Select] <a href='module_viewpaginated.php?page=1' but when I used this code, I've got the variable $course and $program, but I don't know how to insert page for my pagination Code: [Select] <a href='module_viewpaginated.php?course=".$courseid."&program=".$program." ' I hope my problem is clear. I want to combine the two. Any help would be greatfull!! Hello everybody, I have a question about changing variables. In a website template I've created, I would like to only include some code from another file into the page if the variable changes. Example: Code: [Select] <?php $load_page1 = 0; ?> <a href="index.php#!/page1" onClick="<?php $load_page1 = 1; ?>">Page 1</a> <?php if($load_page1 == 1) { include('pages/page1.php'); } ?> The problem I'm having is Code: [Select] onClick="<?php $load_page1 = 1; ?>" always sets the variable to "1" even if not clicked. So the question is, how would I make it so the default is "0" and only after clicking the link, the variable is set to "1" and then the new code from the other file is included into the page. Please let me know if I need to clarify anything and thanks for any help in advance. Hi, I have an affiliate system that shows results on what product is purchased. The problem is that the tracker is only listing the first product in the purchase list, so if someone purchases multiple products it only shows the first product in the transaction report. Here is the code: Code: [Select] $module = fetchDbConfig('PostAffiliatePro'); $orderInv = $order->getOrderInv($_GET["cart_order_id"]); print_r($orderInv); $affCode = "<!-- Begin PostAffiliatePro Affiliate Tracker --> <img border='0' src='".$module['URL']."/scripts/sale.php?TotalCost=".sprintf("%.2f", $orderSum['subtotal'])."&OrderID=".$cart_order_id."&ProductID=".$orderInv['0']['productCode']."' width='0' height='0' alt='' /> <!-- End PostAffiliatePro Affiliate Tracker -->"; ?> The code I need help with syntax is: Code: [Select] "&ProductID=".$orderInv['0']['productCode']."The products are split into arrays by number (0,1,2,3). So for example, I would want to show results for .$orderInv['0']['productCode']. , then .$orderInv['1']['productCode']. , and so on. I would like the results to be posted with a ; between them, but I don't know the proper syntax to have it report more than just the first array. This seems pretty simple, but I only know the basics of PHP and I've adapted this from found code. Any guidance would be greatly appreciated. Thanks! What would be the correct way to use returned sql results as variables. I have tried the way in my script, but Im unsure of how I can echo just one of the $nt variables further on in my script. $code = $_GET['postcode']; $shortcode = substr($code,0,2); $query =mysql_query ("SELECT email FROM treesurgeons WHERE postcode like '%" . $shortcode . "%' ORDER BY companyName LIMIT 3"); echo mysql_error(); echo "<p>The email addresses you have requested are;</p>"; while($nt=mysql_fetch_row($query)){echo "$nt[0],$nt[1],$nt[2]<br>";} echo "<p>please use $nt[2] if you ever want to contact me</p>"; //this line doesnt work for me ?></body></html> is there is a way to assign variables such as; $nt[0] = $firstemail $nt[1] = $secondemail $nt[2] = $thirdemail this way I could use each of my sql values, just as I would any other variable? Hi guys; I've managed to find my way into something of a maze. <td> <a href="'Details/21/index.php'"?id= . $id .'>" . $row['id'] . "</a> </td> I'm looking at this line in the code. I realise it's currently in the wrong syntax but I'm just trying multiple different variations. At the moment I'm actually just trying to make it go to a static link but my real goal is to - get it to pick up the id number, of the id row I click, and concatenate that with the rest of my address string. Then use that as the href. Something like this: - "'Details/' + $id + '/index.php'" It's really confusing me though inside this loop and for some reason the id number is being picked up as an int, by the looks of things. It's getting above my level of understanding. Any chance one of you masters would through a n00b a lifeline?
This is my code below
<!DOCTYPE html>
<html>
<head>
<title>LifeSaver DB</title>
<h1> LifeSaver Database </h1>
</head>
<body>
<table>
<tr>
<th>Id</th>
<th>Location</th>
<th>Initials</th>
<th>TimeStamp</th>
<th>Notes</th>
</tr>
<?php
$conn = mysqli_connect("localhost", "meh", "pas", "DB");
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM LifeSaver1 ORDER BY id DESC";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
//for href row
$id = $row['id'];
$Footage = ['Footage'];
echo
"<tr>
<td> <a href="'Details/21/index.php'"?id= . $id .'>" . $row['id'] . "</a> </td>
<td>" . $row["Location"] . "</td>
<td>" . $row["Initials"]. "</td>
<td>" . $row["TimeStamp"]. "</td>
<td>" . $row["Notes"] . "</td>
</tr>";}
//show table
echo "</table>";
} else { echo "0 results"; }
$conn->close();
?>
</table>
</body>
<style>
table, td, th {
border: 1px solid black;
margin: auto;
}
table {
border-collapse: collapse;
color: #000; <!--font colour -->
font-family: monospace;
font-size: 18px;
text-align: center;}
th {
background-color: #337AFF;
color: white;
font-weight: bold; }
tr:nth-child(odd) {background-color: #add8e6}
</style>
</html>
Edited February 8, 2020 by JonnyDriller I have been looking at this code most of the morning and do not have a clue what is wrong with the code. I am hoping its not a stupid mistake, can someone please help me out? thank you
<title>Inputing Travel Detials</title>
<header>
<h1 align="center"> Adding Travel Detials </h1>
<body>
<p> <center><img src="cyberwarfareimage1.png" alt="Squadron logo" style="width:200px;height:200px" style="middle"></center>
<table border="1">
<tr>
<td><a href="index.php"> Home Page </a></td>
<td><a href="administratorhomepage.html">Administrator Home Page </a></td>
<td><a href="viewhomepage.html">View Home Page </a></td>
<td><a href="Inputhomepage.html">Input Home Page </a></td>
<td><a href="traveldetials.html">Enter More Travel Detials </a></td>
</table>
</p>
<?php
include "connection.php";
$Applicant_ID = $_POST["Applicant_ID"];
$Method_Of_Travel = $_POST["Method_Of_Travel"];
$Cost = $_POST["Cost"];
$ETA = $_POST["ETA"];
$Main_Gate_Advised = $_POST["Main_Gate_Advised"];
$query = ("UPDATE `int_board_applicant` SET `Method_Of_Travel`=`$Method_Of_Travel', `Cost`=`$Cost', `ETA`='$ETA', `Main_Gate_Advised`='$Main_Gate_Advised' WHERE `Applicant_ID`='$Applicant_ID'");
$result = mysqli_query($dbhandle, $query)
or die(mysqli_error($dbhandle));
if($result){ echo "Success!"; }
else{ echo "Error."; }
// successfully insert data into database, displays message "Successful".
if($query){
echo "Successful";
}
else {
echo "Data not Submitted";
}
//closing the connection
mysqli_close($dbhandle)
?>
Ok this is puzzleing. I am geting "Could not delete data: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1". but its is deleting the entry that needs to be removed. The "1" is the entry. Just not sure what is causing the error. I do have another delete php but I have put that on the back burning for the time being.
<?php $con = mysqli_connect("localhost","user","password","part_inventory"); // Check connection if (mysqli_connect_errno()) { printf("Connect failed: %s\n", mysqli_connect_error()); exit(); } else { $result = mysqli_query($con, "SELECT * FROM amp20 "); $amp20ptid = $_POST['amp20ptid']; // escape variables for security $amp20ptid = mysqli_real_escape_string($con, $_POST['amp20ptid']); mysqli_query($con, "DELETE FROM amp20 WHERE amp20ptid = '$amp20ptid'"); if (!mysqli_query($con, $amp20ptid)); { die('Could not delete data: ' . mysqli_error($con)); } echo "Part has been deleted to the database!!!\n"; mysqli_close($con); } ?> Hi guys
I have this code below and all works fine when submitting this online application apart from when someone types either ' # & into one of the comment fields in which it throws up the error. Have tried various fixes from across the internet but no joy. Can anyone offer suggestions?
<?php
$con = mysql_connect("localhost:3306","root","password");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db('sfapp', $con);
$sql="INSERT INTO 'sfapp' ('surname_add','forename_add','dob_add','hometele_add','mobiletele_add','homeadd_add','siblings_add','schoolname_add','headname_add','schooladd_add','schooltele_add','schoolem_add','alevel_add','personstate_add','nameprovided_add','pe_add','se_add','PredGrade_Art','PredGrade_AScience','PredGrade_BusStudies','PredGrade_Electronics','PredGrade_EnglishLang','PredGrade_EnglishLit','PredGrade_French','PredGrade_German','PredGrade_Geog','PredGrade_Graphics','PredGrade_History','PredGrade_Maths','PredGrade_SepScience','PredGrade_ProductDesign','PredGrade_Spanish','PredGrade_Other','Gender_Male','Gender_Female','Sub_EnglishLit','Sub_Maths','Sub_FurtherMaths','Sub_Biology','Sub_Chemistry','Sub_Physics','Sub_French','Sub_German','Sub_Spanish','Sub_Geography','Sub_History','Sub_RE','Sub_FineArt','Sub_Business','Sub_Computing','Sub_GlobPersp','Sub_DramaAndTheatre','Sub_PE','Sub_Dance','Sub_Politics','Sub_Psychology','Sub_Sociology','readprospect_chk','Sib_Yes','Sib_No','Current_Student_Yes','Current_Student_No','I_Understand_chk','Current_Education_chk','Local_Care_chk','Staff_Cwhls_chk','Sub_Film')
VALUES
('$_POST[surname_add]','$_POST[forename_add]','$_POST[dob_add]','$_POST[hometele_add]','$_POST[mobiletele_add]','$_POST[homeadd_add]','$_POST[siblings_add]','$_POST[schoolname_add]','$_POST[headname_add]','$_POST[schooladd_add]','$_POST[schooltele_add]','$_POST[schoolem_add]','$_POST[alevel_add]','$_POST[personstate_add]','$_POST[nameprovided_add]','$_POST[pe_add]','$_POST[se_add]','$_POST[PredGrade_Art]','$_POST[PredGrade_AScience]','$_POST[PredGrade_BusStudies]','$_POST[PredGrade_Electronics]','$_POST[PredGrade_EnglishLang]','$_POST[PredGrade_EnglishLit]','$_POST[PredGrade_French]','$_POST[PredGrade_German]','$_POST[PredGrade_Geog]','$_POST[PredGrade_Graphics]','$_POST[PredGrade_History]','$_POST[PredGrade_Maths]','$_POST[PredGrade_SepScience]','$_POST[PredGrade_ProductDesign]','$_POST[PredGrade_Spanish]','$_POST[PredGrade_Other]','$_POST[Gender_Male]','$_POST[Gender_Female]','$_POST[Sub_EnglishLit]','$_POST[Sub_Maths]','$_POST[Sub_FurtherMaths]','$_POST[Sub_Biology]','$_POST[Sub_Chemistry]','$_POST[Sub_Physics]','$_POST[Sub_French]','$_POST[Sub_German]','$_POST[Sub_Spanish]','$_POST[Sub_Geography]','$_POST[Sub_History]','$_POST[Sub_RE]','$_POST[Sub_FineArt]','$_POST[Sub_Business]','$_POST[Sub_Computing]','$_POST[Sub_GlobPersp]','$_POST[Sub_DramaAndTheatre]','$_POST[Sub_PE]','$_POST[Sub_Dance]','$_POST[Sub_Politics]','$_POST[Sub_Psychology]','$_POST[Sub_Sociology]','$_POST[readprospect_chk]','$_POST[Sib_Yes]','$_POST[Sib_No]','$_POST[Current_Student_Yes]','$_POST[Current_Student_No]','$_POST[I_Understand_chk]','$_POST[Current_Education_chk]','$_POST[Local_Care_chk]','$_POST[Staff_Cwhls_chk]','$_POST[Sub_Film]')";
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
?>
<?php
//if "email" variable is filled out, send email
if (isset($_REQUEST['pe_add'])) {
//Email information
$admin_email = $_REQUEST['pe_add'];
$forename = $_REQUEST['forename_add'];
$email = "autoreply@testing.com";
$subject = "Application";
$desc =
"Dear $forename
Thank you for submitting your online application, we will be in touch shortly.
"
;
//send email
mail($admin_email, "$subject", "$desc", "From:" . $email);
//Email response
echo "Thank you for contacting us!";
}
//if "email" variable is not filled out, display the form
else {
?>
If you are seeing this, you need to go back and fill out the Personal Email section!
<?php
}
header("location:complete.php");
mysql_close($con)
?>
Thanks in advance.
Hi.. I create mysql syntax for query testing before i input to my php code here is my mysql code: Code: [Select] set @t = 0; set @rqty=31968; SELECT LOT_CODE as code, DATE_ENTRY, CASE WHEN @t+OUTPUT_QTY > @rqty THEN @rqty -@t ELSE OUTPUT_QTY END as qty, @t := @t + d.OUTPUT_QTY as cumulative FROM dipping d WHERE SUBSTR(LOT_CODE, 9,4) = 'P28' AND (@t < @rqty); and i attach the sample output of the above query. Now that query test is work i will input that code to my php codes. $sql = "SELECT SKUCode, Materials, Comp, Qty FROM bom WHERE SKUCode = '$SKUCode'"; $res = mysql_query($sql, $con); ($row = mysql_fetch_assoc($res)); $Materials = $row['Materials']; $Qty = $row['Qty']; $Comp = $row['Comp']; //P28 //-----Compute Req Qty and Save to table---// $ReqQty = $Qty * $POReq; // 31968 $sql = "UPDATE bom SET ReqQty = '$ReqQty' WHERE SKUCode = '$SKUCode' AND Materials = '$Materials'"; $resReqQty = mysql_query($sql, $con); $t = 0; $sql = "SELECT LOT_CODE as code, DATE_ENTRY, CASE WHEN $t+OUTPUT_QTY > $ReqQty THEN $ReqQty -$t ELSE OUTPUT_QTY END as qty, $t := $t + d.OUTPUT_QTY as cumulative FROM dipping d WHERE SUBSTR(LOT_CODE, 9,4) = '$Comp' AND ($t < $ReqQty)"; when I echo the query: I got this: SELECT LOT_CODE as code, DATE_ENTRY, CASE WHEN 0+OUTPUT_QTY > 31968 THEN 31968 -0 ELSE OUTPUT_QTY END as qty, 0 := 0 + d.OUTPUT_QTY as cumulative FROM dipping d WHERE SUBSTR(LOT_CODE, 9,4) = 'P28' AND (0 < 31968) then I run it to the sql and I got an error: Error Code : 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ':= 0 + d.OUTPUT_QTY as cumulative FROM dipping d WHERE SUBSTR(LOT_CODE, 9,4) = '' at line 1 (0 ms taken) Any help is highly appreciated Thank you so much Hi everyone.... I have a simple search.php And I want to include that in my html output page. I tried using <?php include ('search.php'); ?> Below is my HTML code which is part of a php file...what am I doing wrong here? Code: [Select] // Final Output echo <<<__HTML_END <html> <head> <title>Photography</title> </head> <body> <table width='100%' border='0' align='center' style='width: 100%;'> $result_final <?php include("search.php");?> </table> </body> </html> __HTML_END; Hey all, I've a problem with including of my pages. When I do choose lotto on index.php , I do get the page and also can choose how many roster I want. But I can't see my lotto results, because it does refresh to the index.php again. How can I fix this problem ? this is the code of index.php: Code: [Select] <?php echo '<table class="achtergrond" border="1">'; echo '<tr><td colspan="3">'; /* Keuzelijst tonen */ echo '<center><form action="'.$_SERVER['php_self'].'" method="POST"><select name="test">'; echo '<option selected>Kies een formulier</option></center>'; echo '<option value="1">Lotto</option>'; echo '<option value="2">Euromillions</option>'; echo '</select>'; echo '<button type="submit" name="knop">OK</button>'; echo '</form>'; echo '</td></tr>'; /* Als er op de knop gedrukt is , voer het lottoformulier uit*/ if(isset($_POST['knop'])) { echo '<tr><td>'; echo $waarde; /* variabel $waarde een waarde insteken via keuzelijst */ switch($_POST['test']) { case 1; include('formulieren/lotto.php'); case 2; include('formulieren/euromillions.php'); } echo '</td></tr>'; echo '</table>'; } ?> and this is the code of lotto.php: Code: [Select] <?php echo '<table class="achtergrond">'; echo '<tr><td colspan="3">'; /* Keuzelijst tonen */ echo '<center><form action="'.$_SERVER['php_self'].'" method="POST"><select name="lotto">'; echo '<option selected>Kies aantal rooster</option></center>'; echo '<option value="1">2 roosters</option>'; echo '<option value="2">4 roosters</option>'; echo '<option value="3">6 roosters</option>'; echo '<option value="4">8 roosters</option>'; echo '<option value="5">10 roosters</option>'; echo '<option value="6">12 roosters</option>'; echo '</select>'; echo '<button type="submit" name="knop1">OK</button>'; echo '</form>'; echo '</td></tr>'; /* Als er op de knop gedrukt is , voer het lottoformulier uit*/ if(isset($_POST['knop1'])) { /* variabel $waarde een waarde insteken via keuzelijst */ switch($_POST['lotto']) { case 0; $waarde2 = 0; break; case 1; $waarde2 = 1; break; case 2; $waarde2 = 2; break; case 3; $waarde2 = 3; break; case 4; $waarde2 = 4; break; case 5; $waarde2 = 5; break; case 6; $waarde2 = 6; break; }... Hello: I wanted to see if someone can help me figure out how to include data from my included navigation file. Meaning: I have this file called myNav.php (the database table storing this is "myUpcomingEvents"): Code: [Select] function spLeftMenu() { $spLeftMenu = " <div id=\"sideEvents\"> echo \" $mySideBarData; \"; </div> "; return $spLeftMenu; } I am trying to pull it into the Index.php page like this (the database table storing this is "myHome"): Code: [Select] <?php include('include/myConn.php'); include('include/myNav.php'); $query=mysql_query("SELECT * FROM myHome,myUpcomingEvents") or die("Could not get data from db: ".mysql_error()); while($result=mysql_fetch_array($query)) { $myPageData=$result['myPageData']; $mySideBarPageData=$result['mySideBarPageData']; } ?> <!DOCTYPE HTML> <html> <head></head> <body> <div id="siteContainer"> <div id="leftColumn"> <?php echo spLeftMenu(); ?> </div> <div id="mainContent"> <?php echo $myPageData; ?> </div> </div> </body> </html> Can't get it to work. It just writes out: Code: [Select] echo " ; "; Anyone know how I can get this to work? Thanks. Okay so we all know Code: [Select] <?php include "theme.html"; print: "Hello"; ?> Would output the theme and output hello at the bottom of the page, my question is, how do you position hello to go on the current theme? Thanks. Hi, I have a class: Code: [Select] class Toplist { public function get_article($id) { $id = (int) $id; $articles = array(); $query = $db->sql_query("SELECT * FROM `toplist` WHERE `id` = '$id'"); $result = $db->sql_fetchrowset($query); return $articles; } } and I get Quote Notice: Undefined variable: db in classToplist.php on line 11 Fatal error: Call to a member function sql_query() on a non-object in classToplist.php on line 11 the variable db is in ./models/config.php and it isn't working on the classToplist. I have a feeling that this happens because the config file is not a class. How can I fix this? Hey all. I have a form with inputs "menuitem[]" array. Upon no user input to one of these fields I want to set a variable error and include the form generation page. Is my following code a feasible way to do this? foreach($_POST['menuitem'] as $value) { if(!isset($value) || $value == "") { $emptyvalue = TRUE; } } if ($emptyvalue) { $erroralert = "You must fill in all the form fields! Please try again!"; include "views/addmenus.php"; exit(); } If works but just a bit unsure about it. Cheers! I am making a framework for my site, and I have a folder which defines some things. One thing it defines is the location of the frame work: define('FRAMEWORK', '../../../framework'); Next I include a specific class that I include: include FRAMEWORK.'/commons/Music.php'; This class extends the main framework include '../Weblyize.php'; class Music extends Weblyize{ // Some code } This issue I am currently having is Warning: include(../Weblyize.php) the file Weblyize.php is a directory above Music.php So, here is where the webpage is located: http://96.42.108.211:3333/templates/music/music1/about.php Here is where the two classes are located (sub classes are in commons) http://96.42.108.211:3333/framework/Weblyize.php http://96.42.108.211:3333/framework/commons/Music.php What is a good way to link the files together with out this breaking no matter where the framework directory is located? |
|||||||