PHP - Keeping A Single Line In A Table.

I am trying to insert data from a mysql in a table. I want the data to appear with the image on the left, item name on the top right followed by description underneath.


<?php
$sql = 'SELECT * FROM tbl_products ORDER BY id';
$result = $db->query($sql);
$output[] = '<ul>';
$output[] = '<table border="3" bordercolor="#000000">';
while ($row = $result->fetch()) {

         $output[] = '<tr>';
         $output[] = '<td><img src="images/'.$row['pic'].'" width="67" height="100" /></td>';
         $output[] = '<td class="style10"><strong>'.$row['item_name'].'</strong></td>';
         $output[] = '<td>'.$row['item_description'].'</td>';
         $output[] = '</tr>';

}
$output[] = '</table>';
echo join('',$output);
?>

I would like the items to appear the same way as this page

http://aafcollection.info/items/list.php

Hello everyone, I'm just starting out with PHP as I need to create an online bookstore for a school project. I'm working by a magazine which should teach you exactly how to do this using PHP, but I've had a bunch of problems with the code they use and I don't really know what's going on. Anyway, this looks really simple and basically  what it does is allows you to post a comment on a book, then returns you to the book's page. Problem is, I'm getting the Header may not contain more than a single header, new line detected. error and I can't figure out why. I've tried researching into the matter but all the cases I found had to do with returning to an url, which is not my case.

Anyway, here's the snippet of code:

The form:

Code: [Select]
<div style="width:400px; border:1px solid #ffffff; background-color:#F9F1E7; padding:5px">
<b>Adauga opinia ta:</b>
<hr size="1">
<form action="adauga_comentariu.php" method="POST">
Nume: <input type="text" name="nume_utilizator"><br><br>
Email: <input type="text" name="adresa_email"><br><br>
Comentariu: <br> <textarea name="comentariu" cols="45"></textarea><br><br>
<input type="hidden" name="id_carte" value="<?=id_carte?>">
<center><input type="submit" value="Adauga"</center>
</form>
</div>
The script adaugare_comentariu.php:


Code: [Select]
<?php
ob_start();
include("conectare.php");
$numeFaraTags=strip_tags($_POST['nume_utilizator']);
$emailFaraTags=strip_tags($_POST['adresa_email']);
$comentariuFaraTags=strip_tags($_POST['comentariu']);
$sql="insert into comentarii (id_carte, nume_utilizator, adresa_email, comentariu) values(".$_POST['id_carte'].", '".$numeFaraTags."','".$emailFaraTags."','".$comentariuFaraTags."')";
mysql_query($sql);
$inapoi="carte.php?id_carte=".$_POST['id_carte'];
header("location:urldecode($inapoi)");
ob_end_flush();
?>
conectare.php connects to the mysql database. $inapoi is the variable which returns the user to carte.php (the book he posted a comment on), where id_carte is the book's unique id. I'm getting Header may not contain more than a single header, new line detected on line ten, which is the header line.

Can anyone help me? I've been stumped on this for a few days now and I've just let it pass and started working on other bits, but it's bugging me too much and I'd like to fix it. 

Hi,

I need to compare records in a table based on the 'datetime' field, like if the difference between time is less than 15min.

need to combine the records(rows) as a single resultant row until the time difference between them  is less than 15min and when a record's time difference is >15min that should return as another row and so on. Please find following sample table and the required output format

Sample Table:

Code: [Select]
ID NAME DATETIME
1   aaa    2011-10-10 06:30:00
2   bbb    2011-10-10 06:33:00
3   ccc    2011-10-10 06:38:00
4   ddd    2011-10-10 06:40:00
5   eee    2011-10-10 07:10:00
6   ffff    2011-10-10 07:14:00
7   sss    2011-10-10 08:16:00
8   jjj    2011-10-10 08:26:00
9   kkk    2011-10-10 08:28:00
10  mm    2011-10-10 09:46:00
11  ppp    2011-10-10 09:49:00
12  qqq    2011-10-10 09:52:00


Output Needed :

Code: [Select]
IDs START DATETIME END DATETIME
1,2,3,4 2011-10-10 06:30:00 2011-10-10 06:40:00
5,6 2011-10-10 07:10:00                      2011-10-10 07:14:00
7,8,9 2011-10-10 08:16:00 2011-10-10 08:28:00
10,11,12 2011-10-10 09:46:00                      2011-10-10 09:52:00

You can see 1st row in the output table having IDs 1,2,3,4 coz the time difference between them is less than 15minutes (it doesn't means time difference between start and end; it is actually the  time difference between current record and previous one ; ie; ID-1 and ID-2 have difference less than 15min and ID-2 & ID-3 have difference less than 15min and ID-3 & ID-4 have difference less than 15min, so those 4 records combine together as a single row also shows their start time and end time. Then you can see diff between ID-4 and ID-5 is greater than 15 min so it should display as new row, and so on)

How can I acheive above Output with mysql query ??

Please help..

PHP script return 20 UL LIST values like,

< ul >

A
B
C
D
E
F
G
H
I
J
K
L
M
N
O
P
Q
R
S
T

< /ul >

How to display UL LIST into row wise 5 columns like

A B C D
E F G H
I J K L
M N O P
Q R S T (20 ITEMS)

Edited December 7, 2019 by aveeva

Hi, I've been scratching my head for a while now about how to do this, I'm relatively new to php and mysql and perhaps foolishly taking on creating a user area for a website.  I have everything else working, all of my register account functions and confirmations and all of the login scripts etc. 

I have created a profile page which returns various information to the user (this bit works fine) and I've got some nice show/hide toggles running with some javascript/css but my intention is to allow the user to change thier information (e-mail address, contact phone number and also whether they are subscribed to the e-mail list), it also displays any support tickets or messages.

So after the long intro, here's what I'm struggling with...  I have a form in a visibility toggled <div> which submits a 'change_email' script, so a user wants to change their e-mail, clicks on change, the <div> appears, they bang in the new e-mail and hit submit.

My php script appears to work (because it doesn't throw up any errors), until you realise that actually it's not updated the record in the db...

I'm using mysql_query("UPDATE users SET email='$new_email' WHERE username='$user'");

Do I need to setup variables for all of the information in the db (name, username, password, email, contno etc etc) and include them in the command to get it to work or should that just pick the correct record and then update it? If that is the case is there a way I can include 'blank' variables so I don't have to set them all up...

e.g.  mysql_query("UPDATE users SET user='',password='',email='$new_email', etc WHERE username='$user'");

Many thanks in anticipation

I am trying to add a line to a table (actually a shopping cart) at the moment there is a box around the word Checkout and the lines are too close.
I've tried adding in a line using <tr> at the beginning and then </tr> at the end but am having no luck 
I am completely new to any kind of coding what so ever so i'm sorry if it is a dumb question.

At the moment the coding round the checkout is:

<td id='cart-widget-links' colspan="5">
<a target="_parent" href="<?php echo get_option('shopping_cart_url'); ?>" title="<?php _e('Checkout', 'wpsc'); ?>" class="gocheckout"><?php _e('Checkout', 'wpsc'); ?></a>
<form action="" method="post" class="wpsc_empty_the_cart">
<input type="hidden" name="wpsc_ajax_action" value="empty_cart" />
<a target="_parent" href="<?php echo htmlentities(add_query_arg('wpsc_ajax_action', 'empty_cart', remove_query_arg('ajax')), ENT_QUOTES, 'UTF-8'); ?>" class="emptycart" title="<?php _e('Empty Your Cart', 'wpsc'); ?>"><?php _e('', 'wpsc'); ?></a>

If anyone can help be I would really really appreciate it... I can beg if you want

Megan

Here is a link to the website I am designing. http://173.167.65.189/singleton/
the username and password is ksingleton
at the bottom where the calendar is the query is searching for scheduled events, i am only posting the company_id right now,  the problem I am having is I want a scheduled event that continues through the week to stay in line with the one before.  But if the schedule before ended and a new one continues it moves the next date company_id up.  How can i align the table rows or create an empty table row on all other days if there was a schedule before.  here is the code for the calendar.

Quote

<?php
$db = new mysqli();
$setdate=strtotime($_GET['date']);
$session=$_GET['session'];
$calview=$_GET['calview'];
if ($setdate <> "") {
   $date=$setdate;
} else {
$date=time();
}
$day=date('d',$date);
$month=date('m',$date);
$year=date('Y',$date);
$first_day=mktime(0,0,0,$month,1,$year);
$title=date('F',$first_day);

$day_of_week = date('D', $first_day);

switch($day_of_week) {
case "Sun": $blank = 0;break;
case "Mon": $blank = 1;break;
case "Tue": $blank = 2;break;
case "Wed": $blank = 3;break;
case "Thu": $blank = 4;break;
case "Fri": $blank = 5;break;
case "Sat": $blank = 6;break;
}

$days_in_month = cal_days_in_month(0, $month, $year);

echo "<table cellpadding=0 cellspacing=0 border=0>";
echo "<tbody>";
echo "<tr>";
echo "<td><a href=?session=$session&calview=day>Day</a></td>";
echo "<td><a href=?session=$session&calview=week>Week</a></td>";
echo "<td><a href=?session=$session&calview=month>Month</a></td>";
echo "</tr>";
echo   "<tr>";
echo      "<td colspan=3>";
if ($calview=="month") {
echo         "<table border=1 width=800>";
echo            "<tbody>";
echo               "<tr height=25><th colspan=7> $title $year </th></tr>";
echo               "<tr height=25><td width=58 align=center>Sunday</td><td width=58 align=center>Monday</td><td width=58 align=center>Tuesday</td><td width=58 align=center>Wednesday</td><td width=58 align=center>Thursday</td><td width=58 align=center>Friday</td><td width=58 align=center>Saturday</td></tr>";

$day_count = 1;

echo               "<tr height=50>";

while ( $blank > 0 ) {
echo               "<td></td>";
$blank = $blank-1;
$day_count++;
}

$day_num = 1;

while ($day_num <= $days_in_month ) {
$newdate = $month ."/". $day_num ."/". $year;
$msqlnewdate = date('m/d/Y',strtotime($newdate));
echo "<td valign=top><table cellpadding=0 cellspacing=0 border=0><tr><td><a href=?session=$session&calview=day&date=$newdate> $day_num </a></td></tr>";
$db = new mysqli('localhost','username','password', 'rsdata');

if (!$db) {
   echo 'ERROR: Could not connect to database.';
} else {
$query = $db->query("SELECT * FROM rentals WHERE date_format(str_to_date(pdate_out,'%Y-%m-%d'), '%m/%d/%Y') <= '$msqlnewdate' AND date_format(str_to_date(pdate_in, '%Y-%m-%d'), '%m/%d/%Y') >= '$msqlnewdate'");
if ($query) {
   while ($result = $query->fetch_object()) {
      echo "<tr><td>".$result->company_id."</td></tr>";
   }
}
echo "</table>";
}


$day_num++;
$day_count++;

if ($day_count > 7) {
echo "</tr><tr>";
$day_count=1;
}
}

while ($day_count >1 && $day_count <=7 ) {
echo "<td></td>";
$day_count++;
}
echo "</tr></table>";
} else if ($calview=="week") {

} else {

}
         
echo      "</td>";
echo   "</tr>";
echo "</tbody>";
echo "</table>";
?>


MOD EDIT: DB credentials edited out.

i have a mysql table which contains name like

mid           mname

101           AAA
102          BBB
103          CCC

now i have to print this name in a html table like AAA, BBB, CCC

i am getting this by while loop in a variable but when loop changes then value also change so please tell me how i get this only in one variable & print

what im trying to do is take a youtube embed code find the URL code for that video and remove all other parts of the code keeping only the URL of the video
after i get the URL by it self then replace the http://www.youtube.com/ part of the URL with http://i2.ytimg.com/vi/

to do this i know that i need something like this to get the URL of the video
http://www.youtube.com/((?:v|cp)/[A-Za-z0-9\-_=]+)
but how to only return just the URL is something idk how to do

then use str_replace http://www.youtube.com/(?:v|cp)/" with  http://i2.ytimg.com/vi/

so in the end im asking if anyone know how to remove all other codes i dont want  and only keep the URL


this may have to be done using "regex" im not sure as i dont know to much about regex and what it can do but does sound like it would help lol

Hi.

I want a simple textbox, that when submited, will replace very every new line, with the <br> tag.

What will happen, when it submits, it will take the contents of a textbox, add the <br> tag where a new line is suposed to be, and save the string to a MySQL Database.

I think this is the easiest way of allowing a user to edit what appears on a website when logged in, but if there is a easier way, then please tell me.

What I am trying to do, is a login page, and once logged in, you enter new text into the textbox, click submit, and on the website homepage, the main text will change to what was submitted. But if there is a new line, I think the only way in HTML to make one is to put a <br> tag, so I want the PHP to but that tag wherever there is a new line.

Sorry if I am confusing, I am not that advanced at PHP, but I would be very happy if you could supply me with the correct code. Time is running out...

If you do not understand me, please tell me

--
PHPLeader (not) 

i have to read a single line from a csv,  its a really big file and i only need one column. i need the response to be a string ,i made a search and found the following code but i dont have any idea how to get a single line from a single string per run .

<?php
$row = 1;
//open the file
if (($handle = fopen("file.csv", "r")) !== FALSE)
{
    while (($data = fgetcsv($handle, 0, ",")) !== FALSE)
    {
        $num = count($data);
        echo "<p> $num fields in line $row: <br /></p>\n";
        $row++;
        for ($c=0; $c < $num; $c++)
        {
            echo $data[$c] . "<br />\n";
        }
    }
    fclose($handle);
}
?>

Edited by bores_escalovsk, 16 May 2014 - 06:38 PM.

Dear All

           Good Day, i am new to PHP (a beautiful server side scripting language). i want to send a mail with line by line message i tried with different types like by placing the things in table and using  <br /> but the thing is the tags are also visible in the message of the mail.

Here is my code:

$message1  = "Name       :".  $_REQUEST['name']."<br />";
$message1 .= "Surname    :".  $_REQUEST['surname']."<br />";
$message1 .= "Cellphone  :".  $_REQUEST['mobileno']."<br />";
$message1 .= "Telephone  :".  $_REQUEST['landno']."<br />";
$message1 .= "Fax        :".  $_REQUEST['fax']."<br />";
$message1 .= "Company    :".  $_REQUEST['company']."<br />";
$message1 .= "Email      :".  $_REQUEST['email']."<br />";
$message1 .= "Country    :".  $_REQUEST['country']."<br />";
$message1 .= "Enquity    :".  $_REQUEST['enquiry']."<br />";
$message1 .= "Date&Time  :".  $date."<br />";

For this code if try to print/echo it it is working fine it is displaying line by line, but using this variable ($message1) in the mail these <br /> are also visible.
Can any one guide me to resolve(to remove these tags from the message part) this issue.
Thanks in Advance. :confused:

I'm updating my database with a set of data from another database.  When there is an item deleted from the source db, how would I make sure it's deleted from the db copy given that I have to run the update in a batch and can't run it when the item is deleted?  Would I truncate the db at the beginning of each update, then pull all the of data over?   

What are the different ways you can keep a User "logged in"?

From what I *vaguely* recall from a year or two ago when I read a whole hoard of PHP books, you commonly use cookies and sessions.

But I'm asking this more from an OOP standpoint than a PHP standpoint.

Let's say I have a User record in my database, and a User comes along and attempts to log in.

In OOP terms, I would think you'd call some class to help log them in, and upon successfully logging in, you would "load" the User object into memory and set the "LoggedIn" field to "True". Then as long as that field was set in their object, they could surf all over the place and do things like change their account and buy things.

Is that how you would do it in OOP?



TomTees

Like 6 years ago I had made a forum software for me and my buddies to post on. It had worked all great until my friend had posted a character that skewed my whole database, unintentionly, he knew nothing about computers. But I really haven't dabbed in PHP since 2008, I'm just now getting back into it again.

I need to know how I can make data from an input to be put into an MySQL database and not screw up my code. So something along the lines that make the code safe and not exploitable.

Also any third party scripts on captcha would be great!