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PHP - Receive And Email When Google Refers A Visitor Part 2.
Hi, didnt know how to add this to the repository so can an admin move this please.
this updated version will tell you still when you recieve a visitor but to identify who i have included so that it tracks the ip and tells you when its you!!! <?php // Script to email you when Google refers traffic to your site. $name=""; // add your name here $email_address=""; // add your email address here $keywords=""; $referrer=$_SERVER['HTTP_REFERER']; $known_ips = array( '01.01.01.01' => 'from the computer your are at now!', // etc. ); $ip = $_SERVER['REMOTE_ADDR']; if (array_key_exists($ip, $known_ips)) { $ip = $known_ips[$ip]; // you may want to use a different var name here now? } if( (stristr($referrer, "google")) && (stristr($referrer, "search")) ) { parse_str($referrer, $output); $keywords=$output['q']; $email_message="A visitor just arrived to the website after searching for '$keywords', Their IP address is '$ip'. ($referrer)"; mail ("$email_address","Google referred a visitor","$email_message"); } ?> hope it all works... give it a try and let me know. Similar TutorialsHey folks, I made a small shopping cart but I struggle with receiving an email with the orders; thanks in advance this is the mail.php <?php session_start(); if($_POST['sendemail'] == 'Email') { $headers = 'From: Sender <andrej13@gmail.com>'; mail('andrej13@gmail.com', 'Subject', $_SESSION["cart"], $headers); echo "DEBdsUG".$_POST["cart"]; echo 'Your mail has been sent'; } else { echo 'Your mail was not sent'; } ?> this is the cart.php <?php // Include MySQL class require_once('inc/mysql.class.php'); // Include database connection require_once('inc/global.inc.php'); // Include functions require_once('inc/functions.inc.php'); // Start the session session_start(); // Process actions $cart = $_SESSION['cart']; $action = $_GET['action']; switch ($action) { case 'add': if ($cart) { $cart .= ','.$_GET['id']; } else { $cart = $_GET['id']; } break; case 'delete': if ($cart) { $items = explode(',',$cart); $newcart = ''; foreach ($items as $item) { if ($_GET['id'] != $item) { if ($newcart != '') { $newcart .= ','.$item; } else { $newcart = $item; } } } $cart = $newcart; } break; case 'update': if ($cart) { $newcart = ''; foreach ($_POST as $key=>$value) { if (stristr($key,'qty')) { $id = str_replace('qty','',$key); $items = ($newcart != '') ? explode(',',$newcart) : explode(',',$cart); $newcart = ''; foreach ($items as $item) { if ($id != $item) { if ($newcart != '') { $newcart .= ','.$item; } else { $newcart = $item; } } } for ($i=1;$i<=$value;$i++) { if ($newcart != '') { $newcart .= ','.$id; } else { $newcart = $id; } } } } } $cart = $newcart; break; } $_SESSION['cart'] = $cart; ?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>PHP Shopping Cart Demo &#0183; Cart</title> <link rel="stylesheet" href="css/styles.css" /> </head> <body> <div id="shoppingcart"> <h1>Your Shopping Cart</h1> <?php echo writeShoppingCart(); ?> </div> <div id="contents"> <h1>Please check quantities...</h1> <?php echo showCart(); ?> <p><a href="index.php">Back to bookshop...</a></p> <form action="mail.php" method="post"> <input type="submit" name="sendemail" value="Email" /> <input type="hidden" name="cart" value="<?= $cart; ?>" /> </form> </div> </body> </html> Right now, the following PHP script claims to send an email for Google referrals, as your forum states. I put it in the first few lines of index.php. Is this wrong, because I still received zero emails, adding the site name to keywords below...? And, of course, I searched the same keyword from Google without success. <?php // Script to email you when Google refers traffic to your site. $name=""; // add your name here $email_address=""; // add your email address here $keywords=""; $referrer=$_SERVER['HTTP_REFERER']; if( (stristr($referrer, "google")) && (stristr($referrer, "search")) ) { parse_str($referrer, $output); $keywords=$output['q']; $email_message="Hi $name, A visitor just arrived to your site after searching for '$keywords'. ($referrer)"; mail ("$email_address","Google referred a visitor","$email_message"); } ?> If this is wrong, how DO I use such a PHP within my phpmyadmin folder? Need help. Has anyone ever used these. I want to develop a tool so users of my site can invite there friends. My query gets the results and orders by one of the fields. Once I get the MySQL results I would like to find the first entry that has a letter as the first character of the same field that the list was ordered by, then split the results in to two parts and swap them. So that the results that have a letter at the start of the same sorted field are as the begining and the results that have the numbers as the start at the end of the array. But also so that the array works the same way as the original results string, so i can use say $results['mysqlfield'] Code: [Select] <? $out = preg_replace('/^(.{701}[^.]*).*/i','$1.',$detrsltnewsrow[news_desc]); echo $out; ?> </td></tr><tr><td colspan="2" class="para" style="padding-left:10px;"> <?= substr(stripslashes(trim($detrsltnewsrow[news_desc])),701) ?> </td></tr> I have the above snippet.. The first php statement, basically grasp the first 701 characters with the closet next stop "." character and out puts it. then out puts the HTML tags I have a problem with the second statement. I want to output anything after what has been outputted by: Code: [Select] <? $out = preg_replace('/^(.{701}[^.]*).*/i','$1.',$detrsltnewsrow[news_desc]); echo $out; ?> So need the correct syntax for Code: [Select] <?= substr(stripslashes(trim($detrsltnewsrow[news_desc])),701) ?> Currently it breaks at exactly the 701 character, want it to continue from the sentence the first code ended in. An automated API is sending an XML message to a PHP file on my site. How do I deal with this? Hi, Anyone can help me on how to receive a file as a http upload? I have an application that sends an xml file with http (post method) to our server and I need to make a script that receives that, writes it to database and archives the file away. Tried to google something but no luck so far. If anyone have done something like this I appreciate any help you can give. Thanks. Not sure if my title line was worded correctly, but here is what I am trying to understand... I need to hook my website up to a payment gateway to accept credit cards. After I package up the customer's payment details and send the payment gateway an XML string, their server supposedly sends back a request for more information OR it indicates a Pass/Fail message. This is where I am getting lost. If I send data over HTTPS using POST, then how am I supposed to receive a message back from them? It's not like we are on the telephone and there is a "live" link between my web server and theirs?! Can someone please explain how this works? Thanks, Debbie Hey, I'm trying to send a form input to a page, and then get the response (as in, the body) from that page without leaving my PHP script. So instead of when you normally submit a form and it will take you to the 'action="/somepage"'. I want it to get that information and bring it back to the original page. No navigation should happen. I'm almost certain this is possible, but the only thing I've found at the moment requires a custom addon - which, isn't on most hosting sites. Sorry if I haven't described this very well, but any help would be appreciated Thanks tree Hi guys, I am having a problem of deleting the rows in the database. I just receive two warnings of mysql_real_escape_string which they a Code: [Select] Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'myusername'@'localhost' (using password: NO) in /home/username/public_html/mysite.com/delete.php on line 11 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in /home/username/public_html/mysite.com/delete.php on line 11 failed The error are jumping on this line: Code: [Select] return mysql_real_escape_string($value); Here it the full code: <?php session_start(); define('DB_HOST', 'localhost'); define('DB_USER', 'username'); define('DB_PASSWORD', 'password'); define('DB_DATABASE', 'databasename'); function clean($value) { return mysql_real_escape_string($value); } $id = clean($_GET['id']); if ($id != NULL) { $query = @mysql_db_query(_DB,"DELETE FROM table1 WHERE $id = 'id"); $deleted = @mysql_affected_rows(); if($deleted > 0) { echo("worked"); } else { echo("failed"); } }else{ echo("failed"); } @mysql_close($link); ?> I have input the correct password, so what's wrong?? $msg = "testing message"; $to = "$email"; $subjects = "testing"; $mailheaders = "From : singapore \n"; mail($to, $subjects, $msg, $mailheaders); Received in the email From : server name Question is I need it to receive as my domain name (FROM). Not the server name (FROM). Hi, I have been exploring twilio for an app that should be able to receive and store a text message. Do I need a SMS gateway to accomplish this? Thank you V. Hello, i want to send and receive data from https url. how it can be done in php? Thanks i want receive this API JSON : "https://api.cryptowat.ch/markets/binance/btcusdt/ohlc" in PHP And put it in a variable . so i did this :
<?php
$json= file_get_contents('https://api.cryptowat.ch/markets/binance/btcusdt/ohlc');
$json= json_decode($json , true);
foreach ($json as $row){
$price = $row['86400'] ?? "";
print_r($price) ;
}
and its worked ! but i want to show a specific price like : 86400 / 1122 / 0 and i don't know how ? Hello I am a total beginner and don't know first thing about php, but still trying to figure this out. So what I am trying to achieve is, send a http request from a software to my website with a ticket number, is it possible in php to receive that request and show it on a different webpage of the same site? It would be helpful if you can point me to some related articles. I have created a simple form that collects a comment or question from a visitor to my website. The problem is that if the visitor types: Your site looks Ok. I will get that message. But if the type: Your site needs "Work". I will get: Your site needs The script will not send the double quotes or anything after the double quotes What am I missing??? I have tried: addslashes() str_replace() preg_replace() with on change to the message. This is the script Code: [Select] <?php $recipient = $_POST['recipient']; $subject = $_POST['subject']; $first_name = $_POST['first_name']; $last_name = $_POST['last_name']; $senders_email_address = $_POST['senders_email_address']; $comments = $_POST['comments']; $mailheaders .= "To: Thin Dime Web. <$recipient>\n"; $mailheaders .= "From: $first_name $last_name <$senders_email_address>\n"; $body .= "Subject: $subject\n\n"; $body .= "Senders Name: $first_name $last_name\n"; $body .= "E-mail Address: $senders_email_address\n\n"; $body .= "The following Comments or Question came from a visitor to your website\n"; $body .= "\n"; $body .= "$comments\n"; mail("$recipient", "$subject", "$body", "$mailheaders"); ?> i wanting users to be able to update there email address and check to see if the new email already exists. if the email is the same as current email ignore the check. i have no errors showing up but if I enter a email already in the db it still accepts the new email instead of bringing the back the error message. Code: [Select] // email enterd from form // $email=$_POST['email']; $queryuser=mysql_query("SELECT * FROM members WHERE inv='$ivn' ") or die (mysql_error()); while($info = mysql_fetch_array( $queryuser )) { $check=$info['email']; // gets current email // } if($check!=$email){ // if check not equal to $email check the new email address already exists// $queryuser=mysql_query("SELECT * FROM members WHERE email='$email' "); //$result=mysql_query($sql); $checkuser=mysql_num_rows($queryuser); if($checkuser != 0) { $error= "0"; header('LOCATION:../pages/myprofile.php?id='.$error.''); } } cheers Hey, Well when they view my website from home. We get the same (public)ip. Is there a way to tell that these people are not the same person, not using the same ip, because i am saving data from the ip(visitors). The others will get the same date too, because of the same ip. Or is there any other way to get a unique id(number) from visitors? Hope you understand. Cheers. |
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