PHP - Help Getting Variable From Array
Hello. Can someone show the syntax to echo the variable from the array below that is showing "2010-08-31 23:19"? I need to grab that date and use it elsewhere in my script. Thanks.
Code: [Select] array(19) { ["name"]=> string(8) "com_jumi" ["params"]=> array(0) { } ["mainframe"]=> &object(JSite)#2 (6) { ["_clientId"]=> int(0) ["_messageQueue"]=> array(0) { } ["_name"]=> string(4) "site" ["scope"]=> string(8) "com_jumi" ["_errors"]=> array(0) { } ["requestTime"]=> string(16) "2010-08-31 23:19" } Similar TutorialsHi guys im in the middle of optimizing code.. Code: [Select] $sql = "SELECT * FROM sa_enemystats WHERE username='$username'"; $res = mysql_query($sql); while ($row = mysql_fetch_assoc($res)) { $enemy['current_health'] = $row['current_health']; $enemy['current_skill'] = $row['current_skill']; $enemy['level'] = $row['level']; $enemy['damage'] = $row['damage']; $enemy['evade'] = $row['evade']; $enemy['accuracy'] = $row['accuracy']; $enemy['speed'] = $row['speed']; $enemy['luck'] = $row['luck']; echo 'debug: variables synced with db table'; }I know that the setting of these variables are messy and can be done in a better way... but how? I have tried foreach and copying other's code for an array copy but it lead no where. Then again my syntax could be wrong... I used something like Code: [Select] foreach ( $enemy[$value] as $row => $value) { $enemy[$value] = $row[$value]; } I need a help in the following : I have an admin page from where the admin attaches an gif image.This attached image should be shown to the user as a scrolling image. The code for the scrolling image is done through javascript. So my actual problem is getting the name of the attached gif image to the javascript array which is used for scrolling horizontally. hi all, I have an language pack for example: languages/en.php: Code: [Select] $en['mail']['letter closing'] = "regards,\n your friend!"; and in my config: Code: [Select] $language = "en"; $include_language = @include("languages/".$language.".php"); if(!($include_language)) { $try_default_language = @include("languages/nl.php"); if(!($try_default_language)) { echo "kan de taalpakket niet vinden<br>"; echo "Could not find the language pack.<br>"; echo "example on error: ".$test." shows nothing"; exit; } } In my function I want to include the language pack for example i have $language = 'en' so I want to include $en['general']['letter closing'] I will do this: Code: [Select] global $language,${$language}['general']; But that gives an error unexpected '[' blah blah. How can i call the variable variable array in the valid php way? Code: [Select] $word = 'numbers'; $numbers= array('1', '2', '3', '4'); echo $$word[0]; I expected the output to be '1'. It ended up being nothing... Why does this not work? Is it not possible to have a variable variable array? And if not, is there a workaround? Cheers, Joe Hi Everyone
Please checkout the below code:
foreach ($joiners as $joiner) { $town = explode(',', $joiner['address']); if (isset($town[2])) { $town = $town[2]; $get_available_towns[] = $town; $get_available_towns = array(); }
foreach ($joiners as $joiner) { $town = explode(',', $joiner['address']); if (isset($town[2])) { $town = $town[2]; $get_available_towns[] = $town; $get_available_towns = array(); }I don't really understand what is happening. I know the code and everything is correct and it works but I really don't understand how the loop, arrray and variable is working. I wanted to print_r the $get_available_towns outside the loop but it would not work without the square brackets but also I did not even know the square brackets were required. The point was to loop through the data and print all the values. I understand how loops, array's and variables work but I've not seen them used like this. This makes me think I am missing some basic knowledge but I have looked around and I can't see any examples of how loops and arrays are used like this. I have also checked the php manual but still no joy. Can you guys tell me where I could find the information that would have examples on how something like the above code would work? Hey, im struggeling with a small piece of code.... Thats my code: Global $user_ID; $user_ID = get_current_user_id(); echo"User number $user_ID is loggedin";
Echo gives me this:
Now i want to add it to my array: $atts['href'] .= $user_ID . 'abc'; 'href' is set to "https://test.com/" What im getting now ist https://test.com/abc
Can someone tell my why the '2' is missing??
Hello Guys. I have a question here.. I have a photo upload script that uploads photos to the server and then sends the photo name to another page via POST. I only have one var name called $image_all when I echo it this is what I get (When uploading 2 files) Code: [Select] This is the list 2011-12-05_0751.png,2011-12-05_0747.png I also tested with "explode" Code: [Select] print_r(explode(',', $image_all, 10)); and I get this Code: [Select] Array ( [0] => 2011-12-05_0751.png [1] => 2011-12-05_0747.png [2] => What I would like for it to do is assign an incremental var name to each image uploaded and passed in the POST. Like this $image1 = 2011-xx.png $image2 = 2011-xx.png $image3 = 2011-xx.png It should created the variable names dynamically based on the number of images (Up to 10) Thanks for your help! hello all, I have an array value in my post array ($_POST['check0'] ) that I am trying to break up into php variables. For some reason if I do this: $var1 = $_POST['check0'][0]; all I get is the first letter of the string from the first value of the array? Hi, I am basically trying to apply a different amount to $defineMe for certain numbers of an array .. in this case it's array numbers 11 - 16 Code: [Select] <?php if ($defineNumber > 11 and $defineNumber < 16) { $defineMe = 35.00; } else { $defineMe = 50.00; } $defineNumber[01] = array('name'=>'Product 1'); $defineNumber[02] = array('name'=>'Product 2'); $defineNumber[03] = array('name'=>'Product 3'); $defineNumber[04] = array('name'=>'Product 4'); $defineNumber[05] = array('name'=>'Product 5'); $defineNumber[06] = array('name'=>'Product 6'); $defineNumber[11] = array('name'=>'Product 11'); $defineNumber[12] = array('name'=>'Product 12'); $defineNumber[13] = array('name'=>'Product 13'); $defineNumber[14] = array('name'=>'Product 14'); $defineNumber[15] = array('name'=>'Product 15'); $defineNumber[16] = array('name'=>'Product 16'); ?> Is this right? $admin = array('24.68.200.235','24.68.214.97'); $visitor_ip = $_SERVER['REMOTE_ADDR']; if($visitor_ip == $admin) { echo "k"; } else { die("dead"); Hi, I need help with this, I am quite new to arrays. This one works fine: echo array_sum(array(34,19,22,17,7,22,8,23,17,31,21,32,7,29,13,7))/count(array(34,19,22,17,7,22,8,23,17,31,21,32,7,29,13,7)); which gives "19..." it gets average number. What I want to put the values in the array in a variable so I do this: $t = "34,19,22,17,7,22,8,23,17,31,21,32,7,29,13,7"; so why can't I use array like this: echo array_sum(array($t))/count(array($t)); I need to use variable in array, please someone help. i have the following array $fruits = array("cherry" => "red", "apple" => "red", "kiwi" => "green", "strawberry" => "red", "pear" => "yellow", "melon" => "green", "grapes" => "green", "watermelon" => "red", "banana" => "yellow") using the array_count_values($fruits) i get Array ( => 4 => 3 [yellow] => 2 ) how can i asign the value of each key to a variable? hello, um i got a form that stored an array of variables upon users clicks. it submits to another page fine as an array and i can print them using if(!empty($_POST['langSpoken'])) { echo "\n<p><strong>You selected the following LangSpoken:</strong></p>\n<ul>"; foreach($langSpoken as $lang) { // exclude any items with chars we don't want, just in case someone is playing if(!preg_match('/^[-A-Z0-9\., ]+$/iD', $lang)) continue; // print the lang echo "\n\t<li>" . htmlspecialchars($lang) . "</li>"; } echo "\n</ul>"; } else { echo "\n<p>No items selected</p>"; } it prints a list a of array like english spanish but i need to store each one in one variable so i can store in a database is there a way? thanks I use a CURL script API with the header "$headers[] = 'Content-Type: application/json';" The script ends with "$result = curl_exec($ch);" If I simply echo the $result to my browser, I get an array that looks like this:
stdClass Object
[toAddress] => stdClass Object Do I really need to "json_decode" this array? I've spent 2 1/2 days trying every which way, with every permutation to access that one value:
echo $result["fromAddress"]["phone"]; Unfortunately I must have fallen asleep during the array lesson in PHP class ? Thank you. So here is my array:
array(1) { ["84EA0353-58EB-E311-A8B1-001D09E7525D"]=> array(1) { [0]=> object(stdClass)#7 (1) { ["data"]=> array(2) { ["amt"]=> string(7) "100.000" ["unit"]=> string(3) "BUC" } } }}I'm trying to set the variable $x to = amt. I've tried $x= $ArrayMap->amt; this but it comes up null. I've also tried: $x= $ArrayMap['amt'];But both come up NULL. Any ideas on what I'm doing wrong? Thanks, sanchez i have the following array $fruits = array("cherry" => "red", "apple" => "red", "kiwi" => "green", "strawberry" => "red", "pear" => "yellow", "melon" => "green", "grapes" => "green", "watermelon" => "red", "banana" => "yellow") using the array_count_values($fruits) i get Array ( => 4 => 3 [yellow] => 2 ) how can i asign the value of each key to a variable? Hi ! I'd like to count all occurences in "$thiscodestring" into a "dynamic?" array and print it out after the end of the loop, how do I assign the variablenames dynamically ? $query = "SELECT codes, status FROM table"; while ($row = mysql_fetch_assoc($result)) { $thiscodestring = $row[codes]; // looks like "a1 c2 d3 10 15 1 a1 a1"; $singlecodes = explode(" ", $thiscodestring); foreach($singlecodes as $thiscode) { $$thiscode[count] = $$thiscode[count] + 1; } } After all Mysql-Stuff is done I'd like to print out the counted codes, for example the code "a1" was found 100 times in all querys then $$a1[count] should be 100, c2 was found 15 times, then $$c2[count] should be 15 and so on. Question: How do I tell php to assign a "dynamic" variable with the name of the found string which was exploded (in this example a1, c2, d3... ) before ?! $$ does not seem to work. And how can I then print_r() the value if I dont know the name ? Thanks ! I am trying to use the variable $RATETHESE to include an array into file A. The array is in file B. PhP File A include_once(dirname(__FILE__) . '/PhpFileB.php'); global $RATETHESE; $VALID_RATING_IDS = $RATETHESE; Php File B $RATETHESE = "array("1", "2");" For some reason it is printing the array on the page, and the array is not being used to run the script. Did i do anything wrong? Hi all, I can't seem to designate an array key by using a variable and I was wondering if this is possible. I'm looking to do something like this: Code: [Select] <?php $key = "apple"; $arr = array($key => "fruit"); ?> Any suggestions would be appreciated! Hi everybody, im reading up on arrays and im still stuck... Is it possible to assign an array to a variable? I need something like... Code: [Select] &needvariable = $row->User Hopefully this makes sense... |