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PHP - Regarding Retrieving Data And Display In A Form
Hi,
My transaction table looks like this.It includes following fields. tran_ID,account_type,account_number,transaction_type,amount,Date The records regarding each transaction is stored in this table. I want to know how i retrieve the data from this table into another form or table.The coding is what i want... My actual purpose would be to allow cash supervisor to update records. But first it needs to retrieve data. Then only he can check things and update if necessary. Thanks, Heshan. Similar TutorialsHello, is it possible to retrieve data from remote form, from another domain that I can't control. I want to type in number in my local form text field and then post it to remote form and retrieve data. I know how to retrieve data from local mysql, but don't know how to retrieve it from remote form. Remote form: http://www.otto.de/is-bin/INTERSHOP.enfinity/WFS/Otto-OttoDe-Site/de_DE/-/EUR/PV_DirectOrder-Start?ls=0#lmPromo=la,3,hk,home,fl,Sidebar_Bestellen Working number: 31477682 I want to type in 31477682 on my local text field and retrieve data(price, color, status like "lieferbar") from another domain. Hello, I have coded a contact form in PHP and I want to know, if according to you, it is secure! I am new in PHP, so I want some feedback from you. Moreover, I have also two problems based on the contact form. It is a bit complicated to explain, thus, I will break each of my problem one by one. FIRST:The first thing I want to know, is if my contact form secure according to you: The HTML with the PHP codes: Code: [Select] <?php if ($_SERVER['REQUEST_METHOD'] == 'POST') { //Assigning variables to elements $first = htmlentities($_POST['first']); $last = htmlentities($_POST['last']); $sub = htmlentities($_POST['subject']); $email = htmlentities($_POST['email']); $web = htmlentities($_POST['website']); $heard = htmlentities($_POST['heard']); $comment = htmlentities($_POST['message']); $cap = htmlentities($_POST['captcha']); //Declaring the email address with body content $to = 'alithebestofall2010@gmail.com'; $body ="First name: '$first' \n\n Last name: '$last' \n\n Subject: '$sub' \n\n Email: '$email' \n\n Website: '$web' \n\n Heard from us: '$heard' \n\n Comments: '$comment'"; //Validate the forms if (empty($first) || empty($last) || empty($sub) || empty($email) || empty($comment) || empty($cap)) { echo '<p class="error">Required fields must be filled!</p>'; header ('refresh= 3; url= index.php'); return false; } elseif (filter_var($first, FILTER_VALIDATE_INT) || filter_var($last, FILTER_VALIDATE_INT)) { echo '<p class="error">You cannot enter a number as either the first or last name!</p>'; return false; } elseif (!filter_var($email, FILTER_VALIDATE_EMAIL)) { echo '<p class="error">Incorrect email address!</p>'; return false; } elseif (!($cap === '12')){ echo '<p class="error">Invalid captcha, try again!</p>'; return false; } else { mail ($to, $sub, $body); echo '<p class="success">Thank you for contacting us!</p>'; } } ?> <form action="<?php echo $_SERVER['PHP_SELF'];?>" method="post"> <p>Your first name: <span class="required">*</span></p> <p><input type="text" name="first" size="40" placeholder="Ex: Paul"/></p> <p>Your last name: <span class="required">*</span></p> <p><input type="text" name="last" size="40" placeholder="Ex: Smith"/></p> <p>Subject: <span class="required">*</span></p> <p><input type="text" name="subject" size="40" placeholder="Ex: Contact"/></p> <p>Your email address: <span class="required">*</span></p> <p><input type="text" name="email" size="40" placeholder="Ex: example@xxx.com"/></p> <p>Website:</p> <p><input type="text" name="website" size="40" placeholder="Ex: http//:google.com"/></p> <p>Where you have heard us?: <span class="required">*</span></p> <p><select name="heard"> <option>Internet</option> <option>Newspapers</option> <option>Friends or relatives</option> <option>Others</option> </select></p> <p>Your message: <span class="required">*</span></p> <p><textarea cols="75" rows="20" name="message"></textarea></p> <p>Are you human? Sum this please: 5 + 7 = ?: <span class="required">*</span></p></p> <p><input type="text" name="captcha" size="10"/></p> <p><input type="submit" name="submit" value="Send" class="button"/> <input type="reset" value="Reset" class="button"/></p> </form> SECOND PROBLEM:If a user has made a mistake, he gets the error message so that he can correct! However, when a mistake in the form occurs, all the data the user has entered are disappeared! I want the data to keep appearing so that the user does not start over again to fill the form. THIRD: When the erro message is displayed to notify the user that he made a mistake when submitting the form, the message is displaying on the top of the page. I want it to appear below each respective field. How to do that? In JQuery it is simple, but in PHP, I am confusing! Before I pull my hair out, can I: form1.html Retrieve 1 record, 5 columns from the db Display that data in a form Allow the user to change any of the column data on the form Use form action update.php, method post update.php use $_POST to capture variables update db My main concern is if the retrieved data will be displayed on the form. Thanks I was told that I could retreive a db record and the fields would display in a form, which I could subsequently change and then update the db. If I am going about it the right way I just can't get the data to display. The echo appears to show I am getting a record. form4_change_airplane.php <html> <head></head> <body> <?php // Connect to database===================================================== include("connect_db.php"); $table1='passwords'; $table2='airplanes'; $amano="940276"; $id="1"; // sending query =========================================================== $result = mysql_query("SELECT * FROM $table2 WHERE id='$id'") or die(mysql_error()); if (!$result) { die("Query to show fields from table failed"); } $num_rows = mysql_num_rows($result); echo "$num_rows"; ?> <form action="display1_airplanes.php" method="post"> ID #: <input type="text" name="id" size="6"> AMA #: <input name="ama" type="text" size="6"><br> Model Name: <input name="model_name" type="text" size="30"><br> Model Mfg: <input name="model_mfg" type="text" size="30"><br> Wingspan: <input name="wingspan" type="text" size="6"><br> Engine: <input name="engine" type="text" size="30"><br> Decibels: <input name="decibels" type="text" size="6"><br> <input type="submit" value="Send"> </form> </body> </html> how i want to display data from database to look like this : <table width="633" height="224" border="1"> <tr bgcolor="#999900"> <td width="45">Bil</td> <td width="121">Course_name</td> <td width="83">session</td> <td width="83">start_date</td> <td width="83">end_date</td> <td width="83">notes</td> <td width="89">pre-req</td> </tr> <tr bgcolor="#6A7AEA"> <td rowspan="2">1.</td> <td rowspan="2" bgcolor="#6A7AEA">Math</td> <td>1st session </td> <td>1 jan 11 </td> <td>6 jan 11 </td> <td rowspan="2"> </td> <td rowspan="2"><image icon that will link to the oter site> </td> </tr> <tr> <td bgcolor="#6A7AEA">2nd session </td> <td bgcolor="#6A7AEA">8 jan 11 </td> <td bgcolor="#6A7AEA">15 jan 11 </td> </tr> <tr> <td bgcolor="#0066CC">2.</td> <td bgcolor="#0066CC">English</td> <td bgcolor="#0066CC">1st session </td> <td bgcolor="#0066CC">1 feb 11 </td> <td bgcolor="#0066CC">6 feb 11 </td> <td bgcolor="#0066CC"> </td> <td bgcolor="#0066CC"><image icon that will link to the oter site></td> </tr> <tr> <td rowspan="2" bgcolor="#6A7AEA">3.</td> <td rowspan="2" bgcolor="#6A7AEA">Science</td> <td height="29" bgcolor="#6A7AEA">1st session </td> <td bgcolor="#6A7AEA">8 march 11 </td> <td bgcolor="#6A7AEA">15 march 11 </td> <td rowspan="2" bgcolor="#6A7AEA"> </td> <td rowspan="2" bgcolor="#6A7AEA"><image icon that will link to the oter site></td> </tr> <tr> <td bgcolor="#6A7AEA">2nd session</td> <td bgcolor="#6A7AEA">16 march 11 </td> <td bgcolor="#6A7AEA">21 march 11 </td> </tr> </table> ** all the view data is called from database including the icon image thanks... I have a basic table where I am trying to retrieve records that are filtered by a form request. Here is the code I have... $ps = $pdo->prepare("SELECT * FROM `Products` Where `Vendor` LIKE concat('%',?,'%'); $ps->execute(array($_POST['Vendor']));; echo "post=" . $_POST['vendor']; ////Displays correct data from form request $count = $ps->rowCount(); echo "Count=" . $count; ////Count = 0 although I know for a fact that there is 1 record that should be in there ////Used for display of records foreach ($ps as $row){ echo $row, PHP_EOL . "xxx<br>"; } Where is the incorrect code? I am new to php and pdo. Thank you in advance K Hi, I need to get data from an XML file, like the format below: Code: [Select] <ISBNdb server_time="2011-05-31T19:19:42Z"> <BookList total_results="1" page_size="10" page_number="1" shown_results="1"> <BookData book_id="build_your_own_database_driven_web_site_using_php_mysql_4th_" isbn="0980576814" isbn13="9780980576818"> <Title> Build Your Own Database Driven Web Site Using PHP & MySQL, 4th Edition </Title> <TitleLong/> <AuthorsText>Kevin Yank, </AuthorsText> <PublisherText publisher_id="sitepoint">SitePoint</PublisherText> <Details change_time="2009-04-02T00:30:10Z" price_time="2011-05-31T17:46:10Z" edition_info="Paperback; 2009-06-15" language="" physical_description_text="360 pages" lcc_number="" dewey_decimal_normalized="5" dewey_decimal="005"/> </BookData> </BookList> </ISBNdb> I need to know how you get the details from <title>,<AuthorsText><PublisherText> and Bookdata. Tried using the example on W3C, using simplexml_load_file but it only returns: Code: [Select] ISBNdb BookList: Code I'm currently using is: Code: [Select] $xml = simplexml_load_file("http://isbndb.com/api/books.xml?access_key=----&results=details&index1=isbn&value1=".$isbn); echo $xml->getName() . "<br />"; foreach($xml->children() as $child) { echo $child->getName() . ": " . $child . "<br />"; } I would like to display weather conditions on my website and store them in mysql database. I wonder if it is possible to load web page into php for parsing so the required info could be found and used? Is it doable with php and what functions could you recommend for this functionality? How can I have program running in the background on the server which would be triggered every so often to perform this task? Another question is if I want to trigger some action once a week like Tuesday at noon, is there function in php which could be used to check what day of the week and time it is ? I am new to website design so any help will be greatly appreciated. I have a simple query and need to print the result. My code does not print a resulr but the query is valid and returns a result. Any help appreciated. Code: [Select] $query = ("SELECT * FROM wp_book WHERE Author_ID = '$Author_ID'"); $result = mysql_query($query) or trigger_error("Query: $query\n<br />MySQL Error: " . mysql_error()); echo mysql_error(); if (!$result) { echo "<br />"; echo"No Result"; } echo"Result"; while($row = mysql_fetch_assoc($result)){ echo $row['WorkingTitle']; } Hi, i have a transaction table which includes following fields. tran_ID,account_number,account_type,transaction_type,amount,Date I want to know how these data can be retrieved and display in another table. The table is filled with several records. Thanks, Heshan I had this working, but when I try and get fancy and use AJAX the data doesn't display. I think this is a PHP problem though. My code for the select form including AJAX code Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en-GB"> <head> <title>AJAX Example</title> <link rel="stylesheet" type="text/css" href="Form.css" media="screen" /> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ $("tr:odd").addClass("odd"); }); </script> <script type="text/javascript"> function showPlayers(str) { var xmlhttp; if (str=="") { document.getElementById("DataDisplay").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); else {// code for IE6, IE5 } xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("DataDisplay").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","Query.php?category_id="+str,true); xmlhttp.send(); } </script> </head> <body> <h1">AJAX Example</h1> <?php #connect to MySQL $conn = @mysql_connect( "localhost","username","pw") or die( "You did not successfully connect to the DB!" ); #select the specified database $rs = @mysql_SELECT_DB ("MyDB", $conn ) or die ( "Error connecting to the database test!"); ?> <form name="sports" id="sports"> <legend>Select a Sport</legend> <select name="category_id" onChange="showPlayers(this.value)"> <option value="">Select a Sport:</option> <?php $sql = "SELECT category_id, sport FROM sports ". "ORDER BY sport"; $rs = mysql_query($sql); while($row = mysql_fetch_array($rs)) { echo "<option value=\"".$row['category_id']."\">".$row['sport']."</option>\n "; } ?> </select> </form> <br /> <div id="DataDisplay"></div> </body> </html> Query.php <?php #get the id $id=$_GET["category_id"]; #connect to MySQL $conn = @mysql_connect( "localhost","username","pw") or die( "Error connecting to MySQL" ); #select the specified database $rs = @mysql_SELECT_DB ("MyDB", $conn ) or die ( "Could not select that particular Database"); #$id="category_id"; #create the query $sql ="SELECT * FROM sports INNER JOIN players ON sports.category_id = players.category_id WHERE players.category_id = '".$id."'"; echo $sql; #execute the query $rs = mysql_query($sql,$conn); #start the table code echo "<table><tr><th>Category ID</th><th>Sport</th><th>First Name</th><th>Last Name</th></tr>"; #write the data while( $row = mysql_fetch_array( $rs) ) { echo ("<tr><td>"); echo ($row["category_id"] ); echo ("</td>"); echo ("<td>"); echo ($row["sport"]); echo ("</td>"); echo ("<td>"); echo ($row["first_name"]); echo ("</td>"); echo ("<td>"); echo ($row["last_name"]); echo ("</td></tr>"); } echo "</tr></table>"; mysql_close($conn); ?> I think the problem is either with this part in the AJAX Code: [Select] xmlhttp.open("GET","Query.php?category_id="+str,true); or most likely in my Query.php code when I wasn't using AJAX and using POST it worked fine, but adding the AJAX stuff and GET it doesn't work. When I echo out the SQL the result is Code: [Select] SELECT * FROM sports INNER JOIN players ON sports.category_id = players.category_id WHERE players.category_id = '' so the category_id is not being selected properly and that is the primary key/foreign key in the MySQL table which connects the JOIN. Hello, can someone help me with my proggraming problem please. Am new in this so i still have lots problems. I need to put all data from my MySQL table in one table in html. There is catch... i need to design output to give me table with x rows and 3 columns, so it means while reading data from database it need put every 4th in new row. And if there isnt 3 data (or better say if there isnt 3 full <td>) in row code will automatically add empty <td> or 2 in table. So...did somebody do this before or have some code ? All i got for now is Code: [Select] $td ='<td align="center"><img src="'.$row['name'].'.png" /> <p style="font-family:Verdana, Geneva, sans-serif; font-size:15px"> Number: <b style="font-size:40px;">'.$row['serial'].'</b></p> <br><img width="90" height="29" src="'.$logo.'"/></td>'; $tr ='<tr>'.$td.'</tr>'; $html='<table border="1" align="center">'.$tr.'</table>'; Thanks. Hi guys ..
please help me .. I don't know how to do this and I tried but there were no satisfied results..
I want to retrieve a Title (ing_title) from a database called k_db2 , in a table called content_langs
depending on its ID , which called ing_contID
example: if ing_contID=1 , then show the ing_title with this id ing_contID
the above code should be in a php file ..
then I want to include this php file inside the header of my website..
by importing the ing_contID from the database and depending on it the title should be shown..
I really tried but I couldn't find any solution ..
if you could help me in the first part of this problem I'll be glad ..
Hi There all, having an issue with simple xml... hopefully someone will be able to shed some light on this. I have this data in an xml feed from an API:
<ID>job no 1 </ID>
<Name>job name</Name>
<State>job status</State>
<Tasks>
<Task>
<Name>task name 1</Name>
</Task>
<Task>
<Name>task name 2</Name>
</Task>
<ID>job no 2</ID>
<Name>job name</Name>
<State>job status</State>
<Tasks>
<Task>
<Name>task name 1</Name>
</Task>
<Task>
<Name>task name 2</Name>
</Task>
I would like to display these in a table pretty much as it is shown above. Job no 1 job name job status job 1 task name 1 job 1 task name 2 Job no 2 job name job status job 2 task name 1 job 2 task name 2 etc my code looks like this : $required is narrowing down specific states not shown for clarity
$xml_current=simplexml_load_string($jobs_task_response) or die("Error: Cannot create object");
foreach($xml_current->Jobs->Job as $item_current) {
if (in_array((string)$item_current->State, $required)) {
$projects_current[] = array(
'job_no' => (string)$item_current->ID,
'job_name' => (string)$item_current->Name,
'job_status' => (string)$item_current->State,
);
foreach($item_current->Tasks->Task as $current_tasks){
$projects_task[] = array(
'job_tasks' => (string)$current_tasks->Name,
);
}
}
}
foreach ($projects_current as $proj_current) {
$job_no =$proj_current['job_no'];
$job_name =$proj_current['job_name'];
$job_status =$proj_current['job_status'];
$clr_current = $colors[$job_status];
$project_id = $job_no;
$tdata_1 .= "<tr id='current' class='card-body collapse-show'>";
$tdata_1 .= "<td class='th-sm-1 bg-white '><a href='../details/index.php?pid=$job_no' class='text-left ml-1'>$job_no</a></td>";
$tdata_1 .= "<td data-target='#" . $job_no . "' data-toggle='collapse' class='th-sm-2 bg-white text-left ml-1'>$job_name</td>";
$tdata_1 .= "<td class='th-sm-2 " . $clr_current . " text-left ml-1 '>$job_status</td>";
foreach ($projects_task as $proj_tasks){
$job_tasks =$proj_tasks['job_tasks'];
$tdata_1 .= "</tr>";
$tdata_1 .= "<tr id='" . $job_no . "' class='card-body collapse'> ";
$tdata_1 .= "<td class='th-sm bg-white text-left ml-1'></td>";
$tdata_1 .= "<td class='th-sm bg-white text-left ml-1'></td>";
$tdata_1 .= "<td class='th-sm " . $clr_current . " text-left ml-1'>$job_tasks</td>";
$tdata_1 .= "</tr>";
}
}
what I get with this code however is; Job no 1 job name job status job 1 task name 1 job 1 task name 2 job 2 task name 1 job 2 task name 2
Job no 2 job name job status job 1 task name 1 job 1 task name 2 job 2 task name 1 job 2 task name 2
I'm sure there is a simple answer to this, I just can't seem to put my finger on it. Can anyone help please? Much appreciated thanks in advance! As a complete newbie to php and webdesigning i have a following problem.I would like to retrieve the data from database and display it in a drop down menu.Then i should allow the user to select the values from drop down list along with other details,in other words i have to embed the drop down output as the form input for the user and store the form data in another table.I am running a xampp server and i am using php 5.4 version.Please help.My code is as follows.In this case project_name is displayed as the drop down output.but how do i use the same drop down output as a input in the form. <html> <head></head> <body> <?php error_reporting(E_ALL ^ E_DEPRECATED); include 'connect.php' ; $tbl_name="projects"; $sql="SELECT project_name FROM $tbl_name "; $result=mysql_query($sql); if($result === FALSE) { die(mysql_error()); } ?> <form name="resources" action="hourssubmit.php" method="post" > <?php echo "<select name='project_name'>"; while ($row = mysql_fetch_array($result)) { echo "<option value='" . $row['project_name'] ."'>" . $row['project_name'] ."</option>"; } echo "</select>"; ?> </form> </body> </html> Hello, I'm learning PHP, so a completely noob, right now. First to the question itself, I want to know how to retrieve the data(variables & it's values) from the url, which was made or generated(or whatever right word is) by using http_build_query() in php. I created a querystring($string) with certain variables & dynamic values that I'm passing to a url I have a very simple system (few files) having simple articles (only title and a paragraph description) stored in single text files. I catch the data by Code: [Select] $data=file('article1.txt'); $title=$data[0]; $description=$data[1]; This simple system works perfectly, but the problem appears when increasing the number of files (e.g. more than 10,000 articles). This is a problem connected with the OS behavior for handling huge number of files. My first question: Is there theoretically a faster system (e.g. database-based) for retrieving data, comparing with retrieving from plain text file? Second question: what can be an alternative for this very simple system (no search query or additional field)? 1. XML: It has the same problem if storing in different files. 2. Mysql: It is very advanced for this system. 3. SQLite:I am thinking of this, but it still have advanced structure of SQL. 4. DB Berkeley: I am not familiar with Oracle at all, and I need to install something new on my server. Is it really worth of trying? 5. Anything else? In general, I just need fast reading the data. I have no idea how much the speed of these systems are different to determine which is worth of consideration. Thanks for sharing your idea. Hi,
I need to log into a website to check for the latest data, and I want to automate this with php script that will use a cronjob to log in, retrieve the data and email it to me.
Currently I'm stuck on the logging in part (I'm testing the script below on my squirrelmail email login page). I've tried using the snoopy php class (sourceforge.net/projects/snoopy/) but it seems the POST variables aren't being recognised (because the email program is directing me to the log in page, as opposed to telling me that my username/password is wrong).
(is it even possible for a servers to accept POST variables in this way??? I'm kind of surprised but lots of poeple seem to use snoopy to login via userforms)
Please could someone point me in the right direction?
Thanks,
Stu
/ load the snoopy class and initialize the object / $snoopy = new Snoopy(); / set some values / $login_form['login_username'] = 'MY_USERNAME'; $login_form['secretkey'] = 'MY_PASSWORD'; $snoopy->cookies['vegetable'] = 'carrot'; $snoopy->cookies['something'] = 'value'; / submit the data and get the result / $snoopy->submit('http://webmail.MY_WE...rc/redirect.php' $p_data); / output the results / echo '<pre>' . htmlspecialchars($snoopy->results) . '</pre>'; Edited by stubarny, 14 June 2014 - 11:27 AM. This is for band website for its event listings. The main event page list everything fine, but once selecting the "Details" link which activates the switch event. Its no longer showing anything. When I had one event in the data base it worked fine, but now I have 3 events in the database and now its not working. Page can be viewed he http://184.66.66.169/ffy/event.php Code: [Select] <?php //Event Code Here $eventid = (isset($_GET["id"])) ? intval($_GET["id"]) : 0; switch($_GET["list"]=='true') { case "0": if($_GET["id"]== $eventid) { $result = mysql_query("SELECT * FROM event ORDER by eventdate DESC"); if (!$result) { die("query failed: " . msql_error()); } while ($row = mysql_fetch_array($result)) { list($id, $eventdate, $header, $description, $image, $location) = $row; $description = nl2br($description); $eventdate = date("M j, Y",strtotime("$eventdate")); print(' <table width="680" border="0" cellpadding="14" cellspacing="0"> <tr> <td> <div class="myFont"><font size="+1" color="#4e8baf">'.$eventdate.' - </font><font size="+1"><b>'.$header.'</b></font></div> <font size="-2" color="#CCCCCC"><a href="event.php?list=true&eventid='.$id.'">Details</a></font><br /> <hr color="#FFFFFF" width="100" align="left" size="1"> </td> </tr> </table> '); }} break; case "true": if($_GET["id"]==$eventid) { $resultd = mysql_query("SELECT * FROM event WHERE id=$eventid LIMIT 1"); if (!$resultd) { die("query failed: " . msql_error()); } while ($row = mysql_fetch_array($resultd)) { list($id, $eventdate, $header, $description, $image, $location) = $row; $description = nl2br($description); $eventdate = date("M j, Y",strtotime("$eventdate")); print(' <table width="680" border="0" cellpadding="14" cellspacing="0"> <tr> <td> <div class="myFont"><font size="+1" color="#4e8baf">'.$eventdate.' - </font><font size="+1"><b>'.$header.'</b></font></div> '.$description.'<br /> <hr color="#FFFFFF" width="100" align="left" size="1"> <center> '.$location.' </center> </td> </tr> </table> '); } break; }} ?> |
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