PHP - Help With Joining Multiple Tables, Facebook-like Activity Wall
Hey all,
Quick sum up: I have a social website where users can follow/post/vote etc. I am adding a new facebook-like activity wall feature to each users profiles. I have worked on this bit for a few days now and can't seem to get it to work properly. What I want is, well, exactly like the facebook wall as I mentioned...When a visitor visits a user's profile, that user's activity will display, whether they recently "voted" on a post, commented, or posted something of their own, I would like it to display on their profile and of course, have the most recent entries on top. The problems I am having right now a it's displaying some things twice and it's not sorting them by the most recent. I am working with 3 tables here (I only posted the columns that I am using): Code: [Select] Table structure for table votes_posts Field Type Null Default indexer int(11) No post_id int(11) No vote int(11) No user_name varchar(250) No date varchar(255) No Table structure for table posts Field Type Null Default id int(11) No name varchar(30) No content text No datetimerss varchar(255) No category int(11) No Table structure for table comments Field Type Null Default id int(12) No post_id int(12) No name varchar(30) No content text No type varchar(30) No datetimerss varchar(255) No $users is just $_GET['user'] The timeAgo() function, simply displays the very popular "posted xx ago" date time. <ul class="streamActivity"> <?php $checkActivity = "SELECT votes_posts.post_id, votes_posts.user_name, votes_posts.vote, votes_posts.date, posts.id, posts.content, posts.name, posts.datetimerss, categories.category, comments.post_id AS comm_postid, comments.content AS comm_content, comments.name AS comm_name, comments.datetimerss AS comm_date, comments.type FROM `votes_posts` LEFT OUTER JOIN `posts` ON votes_posts.post_id = posts.id LEFT OUTER JOIN `comments` ON posts.id = comments.post_id LEFT OUTER JOIN `categories` ON posts.category = categories.cat_id WHERE (votes_posts.post_id = posts.id AND user_name = '$user') OR (comments.post_id = posts.id AND comments.name = '$user') OR (posts.name = '$user') ORDER BY votes_posts.date, posts.datetimerss, comments.datetimerss ASC"; $checkActivityResult = mysql_query($checkActivity); if (mysql_num_rows($checkActivityResult) > 0) { while ($sessionAct = mysql_fetch_array($checkActivityResult)) { $category = strtolower($sessionAct['category']); $dateVote = timeAgo($sessionAct['date']); $datePost = timeAgo($sessionAct['datetimerss']); $dateComm = timeAgo($sessionAct['comm_date']); $namePost = $sessionAct['name']; $nameComm = $sessionAct['comm_name']; $nameVote = $sessionAct['user_name']; $idVote = $sessionAct['post_id']; $idPost = $sessionAct['id']; $idComm = $sessionAct['comm_postid']; $contentPost = $sessionAct['content']; $contentComm = $sessionAct['comm_content']; $typeComm = $sessionAct['type']; if ($namePost == $user) { $classList = 'storyPost'; $classIcon = 'iconMuttr'; $name = $namePost; $content = $contentPost .' ... read more'; $datetime = $datePost; } elseif ($nameComm == $user && $typeComm == "Comment") { $classList = 'actionPost'; $classIcon = 'iconComment'; $name = $nameComm; $content = 'Commented "'. $contentComm .'"'; $datetime = $dateComm; } elseif ($nameComm == $user && $typeComm == "Advice") { $classList = 'actionPost'; $classIcon = 'iconAdvice'; $name = $nameComm; $content = 'gave Advice "'. $contentComm .'"'; $datetime = $dateComm; } elseif ($nameVote == $user) { if ($sessionAct['vote'] == "1") { $classList = 'actionPost'; $classIcon = 'iconLaughed'; $name = $nameVote; $content = 'Laughed at "'. $contentPost .'"'; $datetime = $dateVote; } elseif ($sessionAct['vote'] == "2") { $classList = 'actionPost'; $classIcon = 'iconLoved'; $name = $nameVote; $content = 'Showed Love on "'. $contentPost .'"'; $datetime = $dateVote; } elseif ($sessionAct['vote'] == "3") { $classList = 'actionPost'; $classIcon = 'iconIdiot'; $name = $nameVote; $content = 'called '. $namePost .' an Idiot for "'. $contentPost .'"'; $datetime = $dateVote; } } ?> <li class="row-activity <?php echo $classList; ?>"> <a href="" class="avatar"><img src="/images/avatars/default_male.jpg" /></a> <div class="info"> <div class="userName"> <a href=""><?php echo $name; ?></a> </div> <span class="msgBody"><?php echo $content; ?></span> <div class="imgTimeStream"> <span class="img <?php echo $classIcon; ?>"></span> <span class="source"><?php echo $datetime; ?></span> </div> </div> </li> <?php } } else { echo '<p>This user has no recent activity.</p>'; } ?> </ul> I am by no means an expert programmer...everything I know I have pretty much taught myself over the past year or two, so I can only imagine how ugly this truly is lol. I am learning each and everyday though, and I hope to continue Also, within each type of activity, there will be slightly different CSS classes on some things. Example: if the result row is a post then the css class of the list item would be "post" if the result row is a vote then the css class of the list item would be "vote" etc. Any help would be appreciated! Similar TutorialsHi folks, i have been playing with a script i downloaded from the net and have made some progress with it, however i have a couple of issues which i cannot figure out. There are two undefined variables which keep cropping up, and i cant figure out why or how to deal with it. <?php include('dbcon.php'); function checkValues($value) { $value = trim($value); if (get_magic_quotes_gpc()) { $value = stripslashes($value); } $value = strtr($value,array_flip(get_html_translation_table(HTML_ENTITIES))); $value = strip_tags($value); $value = mysql_real_escape_string($value); $value = htmlspecialchars ($value); return $value; } function clickable_link($text = '') { $text = preg_replace('#(script|about|applet|activex|chrome):#is', "\\1:", $text); $ret = ' ' . $text; $ret = preg_replace("#(^|[\n ])([\w]+?://[\w\#$%&~/.\-;:=,?@\[\]+]*)#is", "\\1<a href=\"\\2\" target=\"_blank\">\\2</a>", $ret); $ret = preg_replace("#(^|[\n ])((www|ftp)\.[\w\#$%&~/.\-;:=,?@\[\]+]*)#is", "\\1<a href=\"http://\\2\" target=\"_blank\">\\2</a>", $ret); $ret = preg_replace("#(^|[\n ])([a-z0-9&\-_.]+?)@([\w\-]+\.([\w\-\.]+\.)*[\w]+)#i", "\\1<a href=\"mailto:\\2@\\3\">\\2@\\3</a>", $ret); $ret = substr($ret, 1); return $ret; } $next_records = 10; $show_more_button = 0; if(checkValues($_REQUEST['value'])) { $userip = $_SERVER['REMOTE_ADDR']; echo "INSERT INTO facebook_posts (post,f_name,userip,date_created) VALUES('".checkValues($_REQUEST['value'])."','99Points','".$userip."','".strtotime(date("Y-m-d H:i:s"))."')"; mysql_query("INSERT INTO facebook_posts (post,f_name,userip,date_created) VALUES('".checkValues($_REQUEST['value'])."','99Points','".$userip."','".strtotime(date("Y-m-d H:i:s"))."')"); $result = mysql_query("SELECT *, UNIX_TIMESTAMP() - date_created AS TimeSpent FROM facebook_posts order by p_id desc limit 1"); } } elseif($_REQUEST['show_more_post']) // more posting paging { i have highlighted the two variables which are showing as undefined. The javascript code (not complete script) which goes in hand with this script is: Code: [Select] <script type="text/javascript"> // <![CDATA[ $(document).ready(function(){ $('#shareButton').click(function(){ var a = $("#watermark").val(); if(a != "What's on your mind?") { $.post("posts.php?value="+a, { }, function(response){ $('#posting').prepend($(response).fadeIn('slow')); $("#watermark").val("What's on your mind?"); }); } }); $('a.more_records').livequery("click", function(e){ var next = $(this).attr('id').replace('more_',''); $.post("posts.php?show_more_post="+next, { }, function(response){ $('#bottomMoreButton').remove(); $('#posting').append($(response).fadeIn('slow')); }); }); Does anyone have any idea on how or what i can do to stop these error messages appearing? Any help would be appreciated... i have 2 tables. table 1 - Id -Name -ShortId table 2 -lots of data.... -Category (same value with table1 Id) im trying to join this 2 tables... Code: [Select] $query = "SELECT * FROM tblnews_categories WHERE ShortId != 0 ORDER BY `ShortId`"; $result = mysql_query($query); $query2 = "SELECT * FROM tblnews_categories, tblnews WHERE tblnews_categories.Id = tblnews.Category "; $result2 = mysql_query($query2); while($row = mysql_fetch_assoc($result)) { ?> <div class="quartetin2"> <div id="HomeMoreNewsIMG2"><div id="HomeMoreNewsTitle2"><a href="summary?catid=19167"><?php echo strtoupper($row['Name']);?></a></div></div> <div id="HomeMoreNewsText"> <?php while($row2 = mysql_fetch_assoc($result2)) { ?> <tr> <td id="HomeLatestNewsDate"><li><?php echo strtoupper($row2['Title']);?></li></td> </tr> <?php } ?> What i want to do is when Id = Category echo all data under the specific category Hello, I am very new to both php and sql. Hi, I have a table for the users detail in the database which stores their avatar and stuff. There is another called part, this is where the users unique ID from the users table is posted, so I can join these both tables and retrieve the data accordingly. The user table has a few rows for avatars for example avatar_1 , avatar_2 and avatar_3 these rows have paths to different avatars. The problem I am facing is the user table is looking really ugly thanks to these extra avatar rows. What I want to achieve is create a different table for avatars to store these 3 rows but I was wondering how will I join 3 of these tables the user table, the part table and finally the avatar table or should I do something else? Thanks any help is appreciated! Hello there, decided to try to have a joined table query, running into a couple of problems. Here is the query: $sql=mysql_query("SELECT * FROM `buds`, `unlocked_buds` WHERE `id`.buds = `bud_id`.unlocked_buds ORDER BY `id`.buds ASC") or die("A MySQL error has occurred.<br />Your Query: " . $sql . "<br /> Error: (" . mysql_errno() . ") " . mysql_error()); Which gives the error: Quote A MySQL error has occurred. Your Query: Error: (1054) Unknown column 'id.buds' in 'where clause' The two tables are 'buds' and 'unlocked_buds' Not really sure what to change, I have been following this tutorial http://www.sqltraining.org/selecting+data+from+multiple+tables/, but really is not helping that much. What exactly does that mean? What really is happening? I hope this is not confusing. Lets say I want to join 2 tables. When I put it through a while loop, how do I write the code so that all id's in table2 are on the SAME line for each referring id in table 1, before dropping to the next line and going to the next record in table 1? I THINK that actually makes sense if you read it carefully :-) I currently use the following query to get status's and count the number of likes from 2 different tables. However, I now want to join the user table to this query.
SELECT s.*, COUNT(l.likes_location_id) AS likeCount FROM stream AS s LEFT JOIN likes AS l ON ( l.likes_location_id = s.stream_id ) GROUP BY s.stream_id ORDER BY s.stream_id DESC LIMIT 50What do I need to add to include the 'user' table? Also, could anyone recommend a good tutorial for joining tables? Many thanks, $sql = "SELECT * FROM leads WHERE accesstoken = '".$_POST["userAc"]."'"; $result = mysql_query($sql) or trigger_error("Query Failed: " . mysql_error()); if(mysql_num_rows($result)>0) { while($row = mysql_fetch_array($result)) { $id= $row['id']; $fullname= $row['fullname']; $email= $row['email']; $to = $email; $message .= $_POST["userMessage"]; $subject = $_POST["userSubject"]; $headers = "From: " . $_POST["userEmail"] . "\r\n"; $headers .= "Reply-To: ". $_POST["userEmail"] . "\r\n"; $headers .= "MIME-Version: 1.0\r\n"; $headers .= "Content-Type: text/html; charset=ISO-8859-1\r\n"; if (mail($to, $subject, $message, $headers)) { $output = json_encode(array('type'=>'error', 'text' => '<p>Your Message was sent successfully!</p>')); die($output); } else { $output = json_encode(array('type'=>'error', 'text' => '<p>Your Message was not sent!</p>')); die($output); } } }I have another table called accounts that I want to join with this one, I need to select from ref to get the email from account table also! be something like this $sql = "SELECT * FROM accounts WHERE ref = '".$_POST["userAc"]."'"; $result = mysql_query($sql) or trigger_error("Query Failed: " . mysql_error()); Hi As I'm new to PHP/MySQL I need a little help concerning joining 4 tables in SQL query. I have 4 tables first is asort with 4+ columns id catid pid tipid ... id is primary key and catid, pid and tipid are foreign keys from tables kategorija, proizvod and tip I want to make a query to join this 4 tables and find for example all rows with pid=4 I tryed with Code: [Select] $q1 = "SELECT * FROM asort LEFT JOIN (kategorija, proizvod, tip) ON (kategorija.catid=asort.catid AND proizvod.pid=asort.pid AND tip.tipid=asort.tipid) where tipid='$_GET[tipid]' order by cijena asc"; but I got "Column 'tipid' in where clause is ambiguous" Thank you for reading this especially if you are able to help me out on this. Bye DVAL This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=308889.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=331758.0 I have a relational table call sales with prodcut_id and custmer_id tables. I also have a product and customer tables. products table with product_id as an auto increment and customer with custumer_id I want to join through the sales tables all t he fields of row 1 from tables customer and products and pull it at once. This is a member login script and I want to display the products by members. So far I have this query to display the products once the member is login in. $userid is the id of the customer coming from the $userid= $_SESSION['customer_id']; $mysqlSales="SELECT products.* FROM products JOIN sales ON (products.product_id = procuct_id ) WHERE sales.customer_id = '$userid'"; so far that statement is not working where should I have some type of incoherance with the english statement above expressing what I want the query to do. This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=332033.0 Hello,
I want to show checkbox is checked when there is entry of that id in a table in my database.
I have 2 tables page and access_level. I am getting data from page table and displays it in <ul><li> tag with checkbox to select all or only few. After selecting the checkbox, i will store only selected checkbox value in access_level table along with table id. Page link and page name details will be stored in page table.
Now if i want to edit , i should display all the pages which is there in page table and i should also mark checked to those which are already stored in access_level table.
I am using LEFT OUT JOIN, It displays all the pages. But it is not displaying the check mark to those which are already selected.
Here is my code
<?php $s1 = mysql_query("SELECT pages.page_id, pages.code, pages.page, pages.href, access_level.aid, access_level.page_id as pgid, access_level.department, access_level.position, access_level.active FROM pages LEFT OUTER JOIN access_level ON pages.page_id=access_level.page_id WHERE access_level.department=".$department." AND access_level.position=".$position." AND pages.code='sn'") or die(mysql_error()); while($s2 = mysql_fetch_array($s1)) { ?> <tr><td><li><?php echo $s2['page']; ?> </td><td><input type="checkbox" name="sn[]" value="<?php echo $s2['page_id']; ?>" <?php if($row['pgid'] === $s2['page_id']) echo 'checked="checked"';?> />here is my pages table pages.JPG 26.55KB 0 downloads access_level access_level.JPG 19.09KB 0 downloads In access_level table i do not have page ids 8 and 9. But i want to display that also from pages table and for 1 to 7 and 10 i should display check mark. How i can achieve this? Please Help This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=314265.0 I have 2 queries that I want to join together to make one row
I have a form where a user can duplicate part of a form like below: I've named the fields with the HTML arrays (ie. "fieldName[]") and came up with this: //--> CONTROLLERS $system_controllers_qty = $_POST['system_controllers_qty']; $system_controllers_make = $_POST['system_controllers_make']; $system_controllers_model = $_POST['system_controllers_model']; $system_controllers_serial_no = $_POST['system_controllers_serial_no']; for ($i = 0; $i < count($system_controllers_qty); $i++) { echo "qty " . clean($system_controllers_qty[$i]) . "<br/>"; echo "make " . clean($system_controllers_make[$i]) . "<br/>"; echo "model " . clean($system_controllers_model[$i]) . "<br/>"; echo "serial_no " . clean($system_controllers_serial_no[$i]) . "<br/>"; } //--> CPUS $system_cpus_qty = $_POST['system_cpus_qty']; $system_cpus_model = $_POST['system_cpus_model']; $system_cpus_serial_no = $_POST['system_cpus_serial_no']; $system_cpus_speed = $_POST['system_cpus_speed']; for ($i = 0; $i < count($system_cpus_qty); $i++) { echo "qty " . clean($system_cpus_qty[$i]) . "<br/>"; echo "model " . clean($system_cpus_model[$i]) . "<br/>"; echo "serial_no " . clean($system_cpus_serial_no[$i]) . "<br/>"; echo "speed " . clean($system_cpus_speed[$i]) . "<br/>"; } //--> DISKS $system_disks_qty = $_POST['system_disks_qty']; $system_disks_make = $_POST['system_disks_make']; $system_disks_model_no = $_POST['system_disks_model_no']; $system_disks_size = $_POST['system_disks_size']; $system_disks_serial_no = $_POST['system_disks_serial_no']; for ($i = 0; $i < count($system_disks_qty); $i++) { echo "qty " . clean($system_disks_qty[$i]) . "<br/>"; echo "make " . clean($system_disks_make[$i]) . "<br/>"; echo "model_no " . clean($system_disks_model_no[$i]) . "<br/>"; echo "size " . clean($system_disks_size[$i]) . "<br/>"; echo "serial_no " . clean($system_disks_serial_no[$i]) . "<br/>"; } //--> MEMORY $system_memory_qty = $_POST['system_memory_qty']; $system_memory_serial_no = $_POST['system_memory_serial_no']; $system_memory_manf = $_POST['system_memory_manf']; $system_memory_part_no = $_POST['system_memory_part_no']; $system_memory_size = $_POST['system_memory_size']; for ($i = 0; $i < count($system_memory_qty); $i++) { echo "qty " . clean($system_memory_qty[$i]) . "<br/>"; echo "serial " . clean($system_memory_serial_no[$i]) . "<br/>"; echo "manf " . clean($system_memory_manf[$i]) . "<br/>"; echo "part_no " . clean($system_memory_part_no[$i]) . "<br/>"; echo "size " . clean($system_memory_size[$i]) . "<br/>"; } This just outputs all the fields I post at the moment. Say I have 3 different disk types, it's going to loop 3 times. Is it possible to make this all into 1 giant query or am I better off doing each query separately? Each section is a different table. I have a search where I want to be able to search a string of words. The search is going to be looking in 2 different table joined by a left outer join. The tables are "quotes" and "categories". $sql="SELECT q.id, q.username, q.quote, q.by, q.voteup, q.votedown, q.servtime, c.quote_id, c.label FROM quotes q LEFT OUTER JOIN categories c ON q.id = c.quote_id WHERE ( q.username LIKE '$srch' OR q.quote LIKE '$srch' OR q.`by` LIKE '$srch' OR c.label LIKE '$srch')"; The above mysql statement works and returns values..BUT if say, I search "john" and "funny", and a quote is posted by the user "john", but has a category of "funny" it will output the same quote twice. I was wondering if there was a way to see if a quote has either 1 term or both terms, if so display that quote but only display it once. Below is what the query is outputting. [100] => Array ( [id] => 100 [username] => John [quote] => new test quote blah blah [by] => John [voteup] => 0 [votedown] => 0 [servtime] => 2010-12-02 @ 16:27:03 [label] => Array ( [0] => Historic [1] => Serious [2] => Funny ) ) Here is the code in full. //// $sword = explode(" ",$search); foreach($sword as $sterm){ $srch="%".$sterm."%"; echo"$srch<br />"; $sql="SELECT q.id, q.username, q.quote, q.by, q.voteup, q.votedown, q.servtime, c.quote_id, c.label FROM quotes q LEFT OUTER JOIN categories c ON q.id = c.quote_id WHERE ( q.username LIKE '$srch' OR q.quote LIKE '$srch' OR q.`by` LIKE '$srch' OR c.label LIKE '$srch')"; $result=mysql_query($sql); while($row=mysql_fetch_object($result)){ $quote[$row->id]['id'] = $row->id; $quote[$row->id]['username'] = $row->username; $quote[$row->id]['quote'] = $row->quote; $quote[$row->id]['by'] = $row->by; $quote[$row->id]['voteup'] = $row->voteup; $quote[$row->id]['votedown'] = $row->votedown; $quote[$row->id]['servtime'] = $row->servtime; $quote[$row->id]['label'][] = $row->label; } echo"<pre>"; print_r($quote); echo"</pre>"; I don't think this is the fastest way of doing this, as it loops for each item in the db, per each keyword that is search. Any help would be great!! -BaSk I am trying to export multiple csv files to download from 2 separate tables in my database. Some background: I have a web app that links to a phpmyadmin database. There are 2 tables in the database (entering and exiting). These tables hold the phone inventory information of employees currently entering or exiting the organization. The fields in my tables a location, firstname, lastname, username, extension, mac, type What I am trying to do is export the data in these 2 tables to CSV (which I have working now) but I need to have multiple CSVs for each. For example, for my exiting table, I need to have one CSV export all the fields in the table and I also need another CSV to export just the location and username field. I have a simple html form with a submit button which is currently working now: <form action="exportexiting.php" method="POST" style="width: 456px; height: 157px"> <div> <fieldset> <legend style="width: 102px; height: 25px"><strong>Entering CSV:</strong></legend> <input name="Export" type="submit" id="Export" value="Export"> </fieldset><br/> </div> </form> This links to my exportexiting.php file: <?php $host = 'localhost'; $user = 'root'; $pass = 'xxxx'; $db = 'PhoneInventory'; $table = 'exiting'; // Connect to the database $link = mysql_connect($host, $user, $pass); mysql_select_db($db); require 'exportcsv.inc.php'; exportMysqlToCsv($table); ?> Then to exportcsv.inc.php: <?php function exportMysqlToCsv($table,$filename = 'export.csv') { $csv_terminated = "\n"; $csv_separator = ","; $csv_enclosed = ''; $csv_escaped = "\\"; $sql_query = "select * from $table"; // Gets the data from the database $result = mysql_query($sql_query); $fields_cnt = mysql_num_fields($result); $schema_insert = ''; for ($i = 0; $i < $fields_cnt; $i++) { $l = $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, stripslashes(mysql_field_name($result, $i))) . $csv_enclosed; $schema_insert .= $l; $schema_insert .= $csv_separator; } // end for $out = trim(substr($schema_insert, 0, -1)); $out .= $csv_terminated; // Format the data while ($row = mysql_fetch_array($result)) { $schema_insert = ''; for ($j = 0; $j < $fields_cnt; $j++) { if ($row[$j] == '0' || $row[$j] != '') { if ($csv_enclosed == '') { $schema_insert .= $row[$j]; } else { $schema_insert .= $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, $row[$j]) . $csv_enclosed; } } else { $schema_insert .= ''; } if ($j < $fields_cnt - 1) { $schema_insert .= $csv_separator; } } // end for $out .= $schema_insert; $out .= $csv_terminated; } // end while header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Content-Length: " . strlen($out)); // Output to browser with appropriate mime type, you choose header("Content-type: text/x-csv"); //header("Content-type: text/csv"); //header("Content-type: application/csv"); header("Content-Disposition: attachment; filename=$filename"); echo $out; exit; } ?> Again, this is working perfectly for only exporting all the data from the exiting table into one CSV file. My question is, how can I make my one submit button export the 2 CSV files that I need? Thanks for the help... Retrieve Pages, Ads, Leads from multiple facebook accounts with Graph API - Help needed |