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PHP - Shouldn't Print() Return False If It's Executed After A Connection Is Aborted?
Say a script has
ignore_user_abort(true); set. If the user aborts the connection and print is called, the buffer doesn't get written anywhere. So shouldn't print() return false in this case? To clarify, I know it doesn't, but shouldn't it? If not, why not? Similar TutorialsI have a function with a query and then a while loop and then an if file_exists with an image path. I am getting the image path displayed as text. Would this be because I am running the query through json encoding? The below scenario works fine but why shouldnt you do this? Why can I not just run the mysql_connect and mysql_select_db at the top of each page and then run my queries under all of this. What I have read is that the mysql_connection will die after the script finishes (at the end of the page) any way so why do people create mysql_connection objects as php is stateless so it doesnt save this any way. Code: [Select] <?php mysql_connect('localhost', 'user', 'pass'); mysql_select_db('test'); ?> <html> <body> <?php $query = mysql_query("Select * from data"); while($row = mysql_fetch_array($query)) { echo $row['name']."<br />"; } ?> -------------- OTHER HTML HERE --------------- <?php $query = mysql_query("Select * from addresses"); while($row = mysql_fetch_array($query)) { echo $row['postcode']."<br />"; } ?> </body> </html> Hi guys! I'm new to PHP and I'm using Drupal and there's a function that one block will be called if PHP scripts returns value TRUE. Now I want my "Search" to only show at ALL THE other pages but not index. With the code: if (Url::exists('http://www.example.com')) I get my Search function to return TRUE so it will be showed on index page only, but not on any other pages!! So I kinda need this on reverse - how do I get a TRUE value for something that excists? In this case it would be www.example.com, or if anyone else has any other ideas I would be very thankful! Hey Everyone, I want to start out by saying thanks in advance for reading this. Since I started working with the XAMPP package this community has been a great resource, though this is my first post. most of my work has been modifying existing stuff in our network, this is my first project from scratch. I am working on an access control project where I am storing site names and RFID tags in a table, and using PHP to check for existing records. Basically, I want to submit 2 credentials from a host (site and RFID), check if they exist together in the table, if so return TRUE or 1, if not return FALSE or 0. I am new to both PHP and MySQL (although I took a course years ago) so I am looking here for help. On this server I have XAMPP installed and everything I need running. I have a table and created a few records for testing. My current trouble is getting PHP to return the proper values for the SQL query. The SQL query works fine, I think - it returns the number of rows that match and that record. I'm not sure this is the result I need to be able to deal with the way I want. Using other resources my current PHP statement looks like this: Code: [Select] if(mysql_num_rows(mysql_query("SELECT * FROM `users` WHERE 'site_name' LIKE 'berland' AND 'card_id' LIKE '290093C84E' LIMIT 0 , 30"))>0){echo '1';} else {echo '0';} So, my table has the entry as noted in this query above. Final one will be dynamic where the host will be sending those values - I will likely need help with that as well, but small steps first.;-) Anyway, I was playing around with the end statement >0{echo '1';} but wasn't able to make it do what I want. Any help is appreciated. Thank you. Aaron I am trying to do the following. Except I know that 'return' is not the right method to use, as it stops the script, so what ends up happening is only one row is returned, instead of the three that are there. With return, the data is being passed without being immediately printed, and I end up with the data (but not all of it, because the script stops) in correct place in the page. If I replace return () with echo(), it works fine, in terms of returning the correct data. However, with the way things are setup, if I use echo, the results print at the head of my page. I am using function CreateSideMenu to establish the values for content, and then another function, later on the index.php page, actually creates the page. So what I need is to have something, similar to return (), that passes the information on, but does not immediately print it. Do I make sense? see code below: function CreateSideMenu () { // open CreateSideMenu function include ('/Users/max/Sites/rdbase-llc/hidden/defin/kinnect01.php'); $query = "SELECT content_element_title, content_element_short_text FROM content_main"; $result = mysql_query ($query, $dbc); while ($row = mysql_fetch_array ($result, MYSQL_ASSOC)) { return ("<p>" . $row[content_element_title] . "</h2>\n<p>" . $row[content_element_short_text] . "</p>"); } Thanks ahead of time. hi there, is there a difference between if($var == false) and if(false == $var) thankyou! I have a games website called GPStudios.com. In a previous topic (that remains unresolved) I needed help fixing a view counter on a specific page that was sometimes executing a mysql query twice. I've since noticed that it is happening on other pages, maybe all of them. At the top of the php "playgame.php", is the statement: $updatesql = "update games set timesplayed = timesplayed+1, last_played = now() where gameid = $gameid"; mysql_query($updatesql); However, when I reload the page or check on phpMyAdmin, it has sometimes incremented by 2 (possibly 3). I have confirmed that no where else is calling the same query. I created a new table called "FUCK" and editted the code stated above to: $updatesql = "update FUCK set timesplayed = timesplayed+1, last_played = now() where gameid = $gameid"; mysql_query($updatesql); Upon loading the page, it did exactly the same thing. So I confirmed that the PHP must be being run twice. I have tried it on other pages on my website such as I had no luck on my other topic of the same problem, but hopefully someone might be able to tell me why or how this might be happening. Just remember - it is an absolute certainty that the query is NOT being run elsewhere. Thanks. Hello, I create tracking code file named "get_t.php". I call it using javascript: <script language='javascript' type='text/javascript'> var r=document.referrer; var counter = new Object(); counter.src = 'http://MyWebSite.com/get_t.php?aid=55&lid=F29&r='+r; </script><script src=http://MyWebSite.com/get_t.php?aid=55&lid=F29> </script> In this file all I do is to print "Hello World". Now, everything works fine most of the time. but sometimes the file does not executed for some reason, and empty page is displayed without showing message "Hello World". Please advice. Thanks, so a user fills out a form, data gets sent to send.php then if successful redirects back to index.php, how on that index.php can i get it to say, sent successfully? When I try to upload a file larger than the server's max limit, the following code is not executed. How am I supposed to inform the user that their file is too large? NOTE: I've stripped the code down for this post. Code: [Select] <?php if(isset($_POST['submit'])) { echo "test.."; } ?> <html> <head> <title>Upload Test</title> </head> <body> <form action='' enctype='multipart/form-data' method='POST'> <input type='file' name='file_upload' /> <input type='submit' name='submit' value='upload' /> </form> </body> </html> Hi all I have this problem on a server using php5, unix based, safe_mode is On globally, i have turned it off locally through php.ini. Ok, this is testing example script i used: $cmd = ( "php -v" ); $out = shell_exec( $cmd ); print $out; On my own server this returns php version. On this mentioned server i'm using (commercial) this causes complete server breakdown, when logged in with SSH, i can't even issue "ls" command after that, nor find and kill the process. What could be so wrong with it? I don't think calling php-cli would make any difference. Hi, we are trying to make a marketing wheel. This means we got a database with lots of persons in it each with a individual email adres. The simel example of how the basic database looks is seen in the picture below. This table is called "Clicks" As you might notice the field "Aan" is either a 0 or a 1. This is how it works, when someone fills in a form on the website asking for more information the form with all the personal information of this person is send to a random email adres found in this table. When this happens the field "Aan" changes from 0 to 1 this way we can make sure that the same person does not get a email again until everyone else has been used 1 time. So in other words until that the field "Aan" is value 1 for every person in the table. As you might have guessed this is sadly enough not working ... this is our code : Code: [Select] include_once('connection.php'); $data = array(); $i = 0; $result1 = mysql_query("SELECT * FROM `Clicks` WHERE Aan = 0"); while ($list1 = mysql_fetch_array($result1,MYSQL_ASSOC)) { if (empty($list1) ){ mysql_query("UPDATE `Clicks` SET `Aan`= 0 WHERE `Aan` = 1"); } $result = mysql_query("SELECT * FROM `Clicks` WHERE Aan = 0 ORDER BY RAND() LIMIT 1"); while ($list = mysql_fetch_array($result,MYSQL_ASSOC)) { foreach ($list as $key => $value) { // Met htmlentities() voorkom je dat html wordt uitgevoert. $value = htmlentities($value); $data[$i][$keyl] = $value; } $i++; } } mysql_free_result($result); $data = array_reverse($data); // Zet de nieuwste berichten bovenaan // in plaats van onderaan. $cnt = count($data); for($i = 0; $i < $cnt; ++$i) { $bericht = $data[$i]; echo(nl2br($bericht['bericht'])); // Met nl2br() worden alle enters in het // bericht omgezet naar <br/>. echo('</td></tr></table>'); $naarwie= $bericht['Email']; }mysql_query("UPDATE `Clicks` SET `Aan`= 1 WHERE `Email` = $naarwie"); mysql_close($Verbinding); // Sluit de verbinding. // We hebben hem nu niet meer nodig. So this code in short explained would be. It checks if all the "Aan" fields are on 0 if the list is empty so it means they are all on 1 he will reset all the fields of every user to 0. and then he will take a random person out and send the email to that person. And after the mail is send will change that person his value on "Aan" to value 1. Now if the list is not empty, that means there are still persons with value 0 in the list. Then he will take a random user out of all the persons who have "Aan" with value 0 send the mail to that user and change his "Aan" value to 1. This process will be repeated every time someone asks for information until all values of all users are on 1. And then again he will change them to 0 for everyone. I hope its clear what we are looking for. And I hope someone can help us out. We are clueless... Hello there, I have a problem where the following code is running the query before it should. private function isAccountRegistered($AccountUsername, $AccountEmail) { global $Class; if($Class['MySQL']->currentRows("SELECT * FROM xhost_accounts WHERE account_username = '".$Class['MySQL']->parseClientInput($AccountUsername)."'") == 1) { return USERNAME_REGISTERED; } else if($Class['MySQL']->currentRows("SELECT * FROM xhost_accounts WHERE account_email = '".$Class['MySQL']->parseClientInput($AccountEmail)."'") == 1) { return EMAIL_REGISTERED; } } public function createClientAccount($AccountUsername, $AccountPassword, $AccountEmail, $AccountRealname) { global $Class; if($this->isAccountRegistered($AccountUsername, $AccountEmail) == USERNAME_REGISTERED) { echo("<div class=\"warning\">Unfortunately this username is in use by another member!, please select another!.</div>"); } else if($this->isAccountRegistered($AccountUsername, $AccountEmail) == EMAIL_REGISTERED) { echo("<div class=\"warning\">Unfortunately this email address is in use by another member!, please select another!.</div>"); } else { if($Class['MySQL']->Query("INSERT INTO xhost_accounts (account_username, account_password, account_email, account_realname, account_regdate, account_regtime, account_level, account_balance, account_notifications) VALUES('".$Class['MySQL']->parseClientInput($AccountUsername)."', '".md5($Class['MySQL']->parseClientInput($AccountPassword))."', '".$Class['MySQL']->parseClientInput($AccountEmail)."', '".$Class['MySQL']->parseClientInput($AccountRealname)."', '".date("d/m/y")."', '".time()."', '0', '0.00', 'Enabled')")) { $Class['Core']->refresh('index.php'); } else { echo("<div class=\"warning\">Unfortunately something went wrong there, please try again!.</div>"); } } } For some reason when the code above is run it executes if($Class['MySQL']->Query("INSERT INTO xhost_accounts (account_username, account_password, account_email, account_realname, account_regdate, account_regtime, account_level, account_balance, account_notifications) VALUES('".$Class['MySQL']->parseClientInput($AccountUsername)."', '".md5($Class['MySQL']->parseClientInput($AccountPassword))."', '".$Class['MySQL']->parseClientInput($AccountEmail)."', '".$Class['MySQL']->parseClientInput($AccountRealname)."', '".date("d/m/y")."', '".time()."', '0', '0.00', 'Enabled')")) Before it runs: if($this->isAccountRegistered($AccountUsername, $AccountEmail) == USERNAME_REGISTERED) { echo("<div class=\"warning\">Unfortunately this username is in use by another member!, please select another!.</div>"); } Causing it to say that the username is registered every time yet still inserting the account into the database, its returning that its registered because it inserts it before doing the check, does anybody have any idea why, this really has confused me, thanks for your time. when the page loads it is showing "Registration Successful" under the form, even when nothing has yet to be submitted Code: [Select] <script language='javascript'> function verifyMe(){ var msg=''; if(document.getElementById('username').value==''){ msg+='- User Name\n\n';} if(document.getElementById('password').value==''){ msg+='- Password\n\n';} if(document.getElementById('userid').value==''){ msg+='- Eve User ID\n\n';} if(document.getElementById('api').value==''){ msg+='- Eve API\n\n';} if(msg!=''){ alert('The following fields are empty or invalid:\n\n'+msg); return false }else{ return true } } </script> <form name='Sign Up' action='signup.php' method='POST' onsubmit='return verifyMe();'> <table class='table_form_1' id='table_form_1' cellspacing='0'> <tr> <td class='ftbl_row_1' ><LABEL for='username' ACCESSKEY='none' ><b style='color:red'>*</b>User Name </td> <td class='ftbl_row_1a' ><input type='text' name='username' id='username' size='45' value=''> </td> </tr> <tr> <td class='ftbl_row_2' ><LABEL for='password' ACCESSKEY='none' ><b style='color:red'>*</b>Password </td> <td class='ftbl_row_2a' ><input type='password' name='password' id='password' size='45' value=''> </td> </tr> <tr> <td class='ftbl_row_1' ><LABEL for='userid' ACCESSKEY='none' ><b style='color:red'>*</b>Eve User ID </td> <td class='ftbl_row_1a' ><input type='text' name='userid' id='userid' size='45' value=''> </td> </tr> <tr> <td class='ftbl_row_2' ><LABEL for='api' ACCESSKEY='none' ><b style='color:red'>*</b>Eve API </td> <td class='ftbl_row_2a' ><input type='text' name='api' id='api' size='45' value=''> </td> </tr> <tr> <td class='ftbl_row_1' ><LABEL for='email' ACCESSKEY='none' ><b style='color:red'>*</b>E-mail </td> <td class='ftbl_row_1a' ><input type='text' name='email' id='email' size='45' value=''> </td> </tr> <tr> <td colspan='2' align='right'><input type='submit' name='submit' value='Sign Up'> <input type='reset' name='reset' value='Reset'><br /> </td> </tr> </table> </form> <?php $username = $_POST['username']; $password = $_POST['password']; $userid = $_POST['userid']; $api = $_POST['api']; $email= $_POST['email']; mysql_connect("x", "x", "x"); mysql_select_db ("evepay")or die(mysql_error()); $check = "select username from users where username = '".$_POST['username']."';"; $qry = mysql_query($check) or die ("Could not match data because ".mysql_error()); $num_rows = mysql_num_rows($qry); if ($num_rows != 0) { echo "Sorry, there the username $username is already taken. "; echo "Try again"; exit; } else { $query="insert into users (username, password, userid, api, email) values ('$username', '$password', '$userid', '$api', '$email)"; mysql_query($query); if($query) { echo "Registration Successful"; } else { echo "error in registration".mysql_error(); } } ?> How do I make it only show the successful message after the user fills out the form? Ok all I need some help with this. I have been stuck for two days. Basically I have a form that asks a registrant their gender and age, then my script spits out a list of race categories they qualify for. The situation calls for the registrant to be able to register for any category YOUNGER than them, but not older. Screen Shot #1 shows my database setup (this can be changed if you have any better ideas...) that holds the race category information. Here is the sql statement I am using to pull a female racer information, where $race_age is their submitted age. "SELECT * from counts where female=1 and $race_age < age_end and $race_age > age_start" This works, but doesn't pull any categories YOUNGER Than their age. I'm stumpped Thanks for any help in advance. Hello all
I'm new to this forum. I've been struggling on this problem for a few days now.
I’m writing a script to automatically push code to a git server.
exec(‘git config user.name "’ . $userName . ‘"’);
exec(‘git config user.email "’ . $userEmail . ‘"’);
exec('git checkout -b ’ . $branch);
exec(‘git add --all’);
exec(‘git commit -m "’ . $message . ‘"’);
exec('git push origin ’ . $branch);
When running the last command, the script stops and asks for a user name, then a password. I tried other forums, searching the net. I'm frustrated...
Thanks in advance. I have an IF statement that is constantly returning TRUE, even when it shouldn't be. Basically it checks if an array is empty. Code: [Select] <?php $error = array(); //No blanks if ($street_addr == "" || $city == "" || $state == "" || $zip == "" || $phone1 == "" || $phone2 == "" || $phone3 == "" || $county == "") $error[] = "You left something blank!"; //validate zip if(!preg_match("/^[0-9]{5}$/", $zip)) $error[] = "The ZIP code must be a 5-digit number."; //validate phone number if (!is_numeric($phone1) || !is_numeric($phone2) || !is_numeric($phone3)) $error[] = "Phone can only contain digits"; if (strlen($phone1) < 3 || strlen($phone2) < 3 || strlen($phone3) < 4) $error[] = "Invalid phone number"; $count_errors = count($error); if ($count_errors > 0){ echo "ERROR:<br />"; foreach ($error as $err){ echo "-$err<br />"; } } else { //Other code } ?> So the first part of the IF statement is always executing. $count_errors DOES return 0 when printed out. Any help would be greatly appreciated. Thanks! Hi All, I have a form that enables the user to know events that occur in a specific city. Most of the time they get the results in a few seconds, despite the fact that many rows in various tables might be searched for detailed infos about the events in that city. However, this form partly relies on a table against which a MySQL event regularly does some operations. If the user uses the form while the event is being executed, they have to wait up to 30 seconds before getting the results, and sometimes only part of the html page is generated. Is there a way to avoid this lengthy waiting time ? I am wondering whether or not the best would be putting the site on maintenance while the event is being executed, with a "please come back in a few minutes" message. Thanks in advance for your help. I'm working on a fairly straight forward facet of an image gallery application where the client can upload a zip file full of photos and it extracts them one by one to a temp folder, resizes it and moves it to the pic folder, creates a thumbnail, then deletes it from the temp folder All that works fine, but I'm testing it in a situation where I'm uploading a 56 MB zip file, my max_file_size is 128 MB, and it gives me the 'max_file_size' error. Anyone else ever have this problem or have any ideas on how to solve it? |
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