PHP - Change The Date Format
I need to change the date format to DD-MM-YYYY. Please help.
$SomeVar = $_POST['finco']; $query = "SELECT * FROM news_home WHERE code = '".$SomeVar."' ORDER BY timestamp DESC"; $results = mysql_query($query); $returnS=""; while($line = mysql_fetch_array($results)) { $returnS.= $line["subject"].",,".$line["timestamp"].",,".$line["News"].",,".$line["links"].",,,"; } echo $returnS; mysql_close($link); ?> Similar TutorialsHi i've been trying to change the format of the date which comes from the database row [ news-date ] this what i tried but di not work help please $query = "SELECT * FROM news, date_format [news_date](date,'%M %d, %Y') AS news_date "; $result = mysql_query($query); // see if any rows were returned if (mysql_num_rows($result) > 0) { // yes so print them one after another echo "<table cellpadding=10 border=1>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>".$row["news_id"]."</td>"; echo "<td>".$row["subject"]."</td>"; echo "<td>" .$row['news_date']. "</td>"; echo "<td>".$row["news_artical"]."</td>"; echo "<td><a href=delete2.php?id=".$row["id"].">Delete</a></td>"; echo "<td><a href=modifyform.php?id=".$row["id"].">Modify</a></td>"; echo "<td><a href=add.php?id=".$row["id"].">Add Row</a></td>"; echo "</tr>"; } //End While echo "</table>"; } //End if rows echo "<p> <strong>{news.SUBJECT} </strong></p>"; ?> I pass a variable (date) which contains the date in format of 03-02-2011 (m-d-Y) how could i quickly change that date format to show 02-MAR-2011 (d-M-Y) Is there a function that can quick do this? Hi, I am importing data from a csv file into mysql. Everything works fine except that the 'order_date' column in CSV is in the following format mm/dd/yy. Upon import I would like for that format to be changed to yyyy-mm-dd I am not sure how to modify the following code to be able to do so. Any help would be appreciated. <? include "connect.php"; if(isset($_POST['submit'])) { $filename=$_POST['filename']; $handle = fopen("$filename", "r"); while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) { $date = date("Y-m-d"); $import="INSERT into table (order_id, order_status, order_date, todays_date) values ('$data[0]', '$data[1]', '$data[2]', '$date')"; mysql_query($import) or die(mysql_error()); } fclose($handle); print "Import done"; } else { print "<form action='importnew.php' method='post'>"; print "Type file name to import:<br>"; print "<input type='text' name='filename' size='20'><br>"; print "<input type='submit' name='submit' value='submit'></form>"; } ?> I have tried a large number of "solutions" to this but everytime I use them I see 0000-00-00 in my date field instead of the date even though I echoed and can see that the date looks correct. Here's where I'm at: I have a drop down for the month (1-12) and date fields (1-31) as well as a text input field for the year. Using the POST array, I have combined them into the xxxx-xx-xx format that I am using in my field as a date field in mysql. <code> $date_value =$_POST['year'].'-'.$_POST['month'].'-'.$_POST['day']; echo $date_value; </code> This outputs 2012-5-7 in my test echo but 0000-00-00 in the database. I have tried unsuccessfully to use in a numberof suggested versions of: strtotime() mktime Any help would be extremely appreciated. I am aware that I need to validate this data and insure that it is a valid date. That I'm okay with. I would like some help on getting it into the database. Hi there, I have a string '12/04/1990', that's in the format dd/mm/yyyy. I'm attempting to convert that string to a Date, and then insert that date into a MySQL DATE field. The problem is, every time I try to do so, I keep getting values like this in the database: 1970-01-01. Any ideas? Much appreciated. Hi Guys
In MYSQL the date format seems to be YYYY-MM-DD, when I use a dynamic table in Dreamweaver the date is also displayed this way, is there a simple way to change this to UK format DD-MM-YYYY?
Anyone know what's up with this? <?php $days = floor($posts['timestamp'] / (60 * 60 * 24)); $remainder = $posts['timestamp'] % (60 * 60 * 24); $hours = floor($remainder / (60 * 60)); $remainder = $remainder % (60 * 60); $minutes = floor($remainder / 60); $seconds = $remainder % 60; if($days > 0) { echo date("d/m/y", $posts['timestamp']); echo " at "; echo date("H:i", $posts['timestamp']); }elseif($days == 0 && $hours == 0 && $minutes == 0) { echo "few seconds ago"; }elseif($days == 0 && $hours == 0) { echo $minutes.' minutes ago'; }elseif($days == 0 && $hours > 0){ echo $hours.' hour ago'; }else{ echo "few seconds ago"; } ?> What Date Format is this... Code: [Select] echo '<div class="date">Published: ' . date('F j, Y', strtotime($publishedOn)) . '</div>'; And where can I find a listing of the different Date and Time Formats that will work with this? (I would like to display my date as "2012-02-26 2:40pm" for what it is worth...) Thanks, Debbie Hi Guys, I'm sure i have done this before, is there a way to shorten dates like: December 16, 2010 to Dec 16, 2010 and January 16, 2010 to Jan 16, 2010 etc, i have used $dateFormatted2 = date("F j, Y", strtotime($d2)); to get the date format i have now. any help would be appreciated thansk guys Graham Code: [Select] $date =date("d F Y"); It will display 18 October 2011. If I need it to display 2011-10-18. How do it go about coding it? Hi Guys Could somebody tell me how i would put a line break into the code below i.e: 1.07 <br /> 2010 <?php echo date('d.m.Y',strtotime($news['created_at']));?> Thanks for your help I can't seem to get the syntax correct I want my date outputted as January 1st. Code: [Select] <span class="goal_head f_right mrm"><?php echo date($goal['complete_date'], 'F j'); ?></span> I have a date field in the database table of this format 2012-02-08. Now I want to select fields from the database where date >= $currentdate. Do I have to do someting like $currentdate=time(); //Then convert it into YYYY-MM-DD format? Hi guys I have this date script below which displays like so: 16/09/2011. Its fine but I now like it to display like this: 16 September 2011 Please I need help in twicking the code to do this Thanks! <?php //check to see if passing variable is set i.e. if true get day, month, year. if(isset($_GET['day'])){ $day = $_GET['day']; } else{ //Get today's date and put them in date, month, year $day = date("d"); } if(isset($_GET['month'])){ $month = $_GET['month']; } else{ $month = date("m"); } if(isset($_GET['year'])){ $year = $_GET['year']; } else{ $year = date("Y"); } echo $day."/".$month."/".$year; ?> I am trying to get the full date from form field using the date function and post method. $fromdate = $_POST[‘sdate’]; $todate = $_POST[‘edate’]; $fromday = date(‘F j, Y, g:i a’,’$fromdate’); $today1 = date(‘F j, Y, g:i a’,’$todate’); When trying to print i get the right format but i get extra information not sure from where? I am getting the date from the form fields of type date. Code Output: March 19, 2020, 4:16 pm,$31202019pm31Asia/Dubai why i am getting the second part! I'm trying to format a date to use in a mysql query and was wondering about the best way to do it. the form returns: mm/dd/yyyy and I need to format it to yyyy-mm-dd, any help would be greatly appretitaed, thanks in advance! Hi Guys.. How can I change a date on the fly ? Everything is UTC on my server. How can I change a date to something else on the fly? Ie: $timezone = "cet"; $datetime = "2011-09-04 19:53:00"; echo $datetime($timezone); So I can give it a datetime and have it echo the datetime as if it were in the other timezone? Thanks Graham Hi, I'm working on an application which interacts with an embedded device. Here I'm sending the time in EDT. The following code is used to send the time: Code: [Select] $time = date_format(date_create(null, timezone_open("EDT")), "s,i,H,d,m,Y,w"); Here 'm' is from 01 to 12. But at the receiving end the firmware expects the month to be in the range 0-11 (C-style). Yes I can explode the "$time" and subtract 1 from month. But is there any better way to do that..? Thanks, Girish I'm trying to make $time be a variable with the current time and I want it to have the same format as mysql. I can't figure out what I am doing wrong here Wrror: Warning: date_format() expects parameter 1 to be DateTime, integer given Code: [Select] $time = date_format(time(),'Y-m-d H:i:s'); I'm pulling some info from various XML files and am having problems converting the following date format so that it can be stored as a DATETIME field in a MySQL database. Tuesday,17 August 2010 09:25:00 This obvious newbie would appreciate a shove in the right direction... Thanks in advance |