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PHP - Moved: In Root, It Works; In Another Folder It Doesn't
This topic has been moved to Third Party PHP Scripts.
http://www.phpfreaks.com/forums/index.php?topic=308276.0 Similar TutorialsHi all, I have two PHP files, one in root and the other in a folder called admin. If I set $_SESSION in a file in the admin folder and then view $_SESSION in any other file within the admin folder, everything is OK. However, if I then go to a file in root $_SESSION is blank, and it is blank if I then go back to a file in admin. This problem only exists on my hosting and doesn't happen on a local dev machine. I've compared the php.ini session settings and there both the same. Any ideas? Files admin/test.php <?php session_start(); if( empty($_SESSION) ) { echo "Session not set<br />"; $_SESSION['test'] = "test"; } echo "<pre>";var_dump($_SESSION);echo "</pre>"; /test.php <?php session_start(); echo "<pre>";var_dump($_SESSION);echo "</pre>"; I was wondering of it was possible to have a file say style.css in the root folder of a site like www.example.com/style.css and then get a subdomain called www.sub.example.com which points to www.example.com/subarea to get that file without the use of absolute paths? Sorry if its not clear. This upload code is used for uploading a video file from html page, after recording via html5 screen <video></video>, however, ther file doesn't arrive in the uploads/ folder:
<?php
foreach (array('video', 'audio') as $type) {
if (isset($_FILES["${type}-blob"])) {
$fileName = $_POST["${type}-filename"];
$uploadDirectory = 'uploads/' .rand(5,500).$fileName;
if (!move_uploaded_file($_FILES["${type}-blob"]["tmp_name"], $uploadDirectory)) {
echo (" problem moving uploaded file");
}
}
}
when uploaded from iPhone. So, I don't know how to see errors on iPhone. Folder permission is 755. php.ini max file size is 2024M, any ideas/solutions are appreciated.
This topic has been moved to Linux. http://www.phpfreaks.com/forums/index.php?topic=333614.0 This may be a bit removed from straight php, but I have a submit button for an e-commerce site as the final step. It runs through all of the php steps and submits the order. The problem is....sometimes the submit button doesn't do anything for some users. They hit it and nothing happens. Is there a way I can verify everything is loaded correctly with php? Its hard to nail it down to a specific problem. Has anyone had this issue in the past? I have two functions that execute an exe program (personal project for a minecraft back end.) Windows only.
First one will execute the sending of commands (THIS ONE WORKS)
/* check to see if admin is sending commands to terminal via web */
if(isset($_POST['command'])) {
$content = $_POST['command'];
writeMCCommandTxt($content);
try {
exec(SERVER_DIR.'mcCommand.exe',$output);
} catch ( Exception $e ) {
die ($e->getMessage());
}
}// END COMMAND ENTRY
This has been a head scratcher for most the week - any help or suggestions would be great!! thanks!!
HTML <div id="commands"> <div id="command_input"> <form method="post" id="commandForm" action="index.php"> <label for="command" >Console Command:</label><br/> <input type="text" name="command" autofocuS/> <input type="submit" name="submit_command" value=" >> " /> <input type="button" value="Refresh page" onclick="location.reload(true);" /> </form> </div> </div>
This is used to start the server
// STARTING SERVER
if(isset($_POST['startServerBtn'])){
try {
exec(SERVER_DIR.'startServer.bat 2>&1' ,$output);
} catch( Exception $e ) {
die ($e->getMessage());
}
}
HTML <div id="server_control"> <ul> <li> <form action="index.php" method="post"> <input type="submit" value="START" id="startServerBtn" name="startServerBtn"/> </form> </li> </ul> </div> MCCOMMANDS.EXE will work from both browser(php) and file manager(tested) the STARTSERVER.EXE will NOT work from browser(php), but will work from file manager
The function IS being accessed - debug is showing it going there, and it seems to be running Both exe's are in the same folder Edited May 15, 2020 by Klyx99code tags missing Trying to create a very simple API script sending XML data. When I send the "hard coded" XML, it works perfectly. When I add a form to supply the data for the XML, I get a 500 Internal Server error. Have tried it on two different servers. No error in the logs. Stumped. Examples below are VERY simplified (and obviously won't do anything as-is) to show what I'm dealing with. This one works fine: <?php $xml = "<Order><UserId>foo</UserId><Password>foo</Password><Mode>Test</Mode><Name>Charles R. Hodges</Name>"; $xml .= "</Order>"; $url = 'http://sitename.com'; $ch = curl_init($url); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $xml); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); $response = curl_exec($ch); curl_close($ch); $xml = simplexml_load_string($response); print_r($xml); ?> And then I use this one and all heck breaks loose with the 500 Internal Error:
<?php
if (isset($_POST['submit'])) {
$xml = "<Order><UserId>foo</UserId><Password>foo</Password><Mode>Test</Mode><Name>{$_POST['name']}</Name>";
$xml .= "</Order>";
$url = 'http://sitename.com';
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $xml);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$response = curl_exec($ch);
curl_close($ch);
$xml = simplexml_load_string($response);
print_r($xml);
exit;
}
?>
<html>... etc
<form method="post" action="">
Name: <input type="text" name="name" />
<p><input type="submit" name="submit" "Add to XML string and send" />
</form>
?>
Code: [Select] <?php $objConnect = mysql_connect("localhost","","cgdfgdfg") or die(mysql_error()); $objDB = mysql_select_db("ffdfvbbd"); $pic2 = "SELECT * FROM images"; if (!isset($_GET['Page'])) $_GET['Page']='0'; $pic1 = mysql_query($pic2); $Num_Rows = mysql_num_rows($pic1); $Per_Page = 16; // Per Page $Page = $_GET["Page"]; if(!$_GET["Page"]) {$Page=1;} $Prev_Page = $Page-1; $Next_Page = $Page+1; $Page_Start = (($Per_Page*$Page)-$Per_Page); if($Num_Rows<=$Per_Page) {$Num_Pages =1;} else if(($Num_Rows % $Per_Page)==0) {$Num_Pages =($Num_Rows/$Per_Page) ;} else {$Num_Pages =($Num_Rows/$Per_Page)+1; $Num_Pages = (int)$Num_Pages;} $pic2 .="ORDER by thumbnailID DESC LIMIT $Page_Start , $Per_Page" ; $pic1 = mysql_query($pic2); $cell = 0; $link1 = "SELECT * FROM images"; echo ' <div id="tablediv"> <table border="0" cellpadding="17" cellspacing="0" class="table"> <tr>'; while($pic = mysql_fetch_array($pic1)) { if($cell % 4 == 0) { echo '</tr><tr>'; } if($cell == 2) { echo ' <td> filler </td>'; } elseif ($cell == 3) { echo ' <td> filler </td>'; } else { echo ' <td> <a href="/' . $pic["link"] . '.php"> <div class="image"> <img src="https://s3.amazonaws.com/images/' . $pic["pic"] . '.png" alt="' . $pic["alt"] . '" height="200" width="200" /> </div> </a> </td>'; } $cell++; } echo '</tr></table></div>'; ?>The code above works just fine. However, once I add a WHERE function,as shown below, I get a "Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource" error. Code: [Select] <?php $objConnect = mysql_connect("localhost","","cgdfgdfg") or die(mysql_error()); $objDB = mysql_select_db("ffdfvbbd"); $pic2 = "SELECT * FROM images WHERE folder = 'blog' "; //WHERE FUNCTION IS HERE if (!isset($_GET['Page'])) $_GET['Page']='0'; $pic1 = mysql_query($pic2); $Num_Rows = mysql_num_rows($pic1); $Per_Page = 16; // Per Page $Page = $_GET["Page"]; if(!$_GET["Page"]) {$Page=1;} $Prev_Page = $Page-1; $Next_Page = $Page+1; $Page_Start = (($Per_Page*$Page)-$Per_Page); if($Num_Rows<=$Per_Page) {$Num_Pages =1;} else if(($Num_Rows % $Per_Page)==0) {$Num_Pages =($Num_Rows/$Per_Page) ;} else {$Num_Pages =($Num_Rows/$Per_Page)+1; $Num_Pages = (int)$Num_Pages;} $pic2 .="ORDER by thumbnailID DESC LIMIT $Page_Start , $Per_Page" ; $pic1 = mysql_query($pic2); My mysql table includes column thumbnailID folder link pic alt time The folder column is there so I can specify what I want in the page. Anyhow, why won't it work? Hi there, If anyone has a spare minute, id really appreciate someone casting their eye over this and seeing if there's anything obviously wrong. Writing to the txt file works fine, but the redirect to the thankyou.html page doesn't. Cheers Guys. <?PHP $filename = "output.txt"; #CHMOD to 666 $forward = 1; # redirect? 1 : yes || 0 : no $location = "thankyou.html"; #set page to redirect to, if 1 is above ## set time up ## $date = date ("l, F jS, Y"); $time = date ("h:i A"); ## mail message ## $msg = ""; foreach ($_POST as $key => $value) { $msg .= ucfirst ($key) .", ". $value . ", "; } $msg .= "\n"; $fp = fopen ($filename, "a"); # w = write to the file only, create file if it does not exist, discard existing contents if ($fp) { fwrite ($fp, $msg); fclose ($fp); } else { $forward = 2; } if ($forward == 1) { header ("Location:$location"); } else if ($forward == 0) { echo ("Thank you for submitting our form. We will get back to you as soon as possible."); } else { "Error processing form. Please contact the webmaster"; } ?> Many thanks, Mike Hi, My site was working fine, but I just switched servers/web hosts and now I'm getting the following errors (in blue). The thing is, I don't get the error if I try to run the query loop after just using 'mysql_select_db' once, but if I use it again to select a different database and then run the query loop, I start getting the error. Code: [Select] mysql_select_db ("database1", $mysql_con); $mysql_query = mysql_query ("SELECT ID FROM someTable1", $mysql_con); $someVar1 = 0; while ($mysql_array = mysql_fetch_array ($mysql_query)) { $someVar1 ++; } ////// The above code gives me no error. But If I then try to select a different database and run a loop in the same way (in the same file), I start getting the below error... mysql_select_db ("database2", $mysql_con); $mysql_query = mysql_query ("SELECT ID FROM someTable2", $mysql_con); $someVar2 = 0; while ($mysql_array = mysql_fetch_array ($mysql_query)) { $someVar2 ++; } Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /home/snubby5/public_html/coozymcmillan.com/view.php on line 86 So I looked it up and somewhere it told me to add some extra code to handle errors better: Code: [Select] if ($mysql_query === FALSE) { die (mysql_error ()); // TODO: better error handling } But when I do that, I get a different error: Table 'database1.someTable2' doesn't exist It doesn't seem to recognize that I switched databases, and it says 'database1.someTable2' doesn't exist (because it doesn't), when really it should be checking for 'database2.someTable2' (which exists). So to reiterate, I can run the query loop fine after selecting database1, but after that if I select database2, it either gives me the first error, or If I add the 'die' code it gives me the second error. Thanks much! PS: I can get it working if I put everything into one database, but I have multiple websites (which sometimes need to call eachothers' databases) and it would be a huge hassle to cram them all into one database unless I have to. Hello everyone, I'm having this problem which is really annoying, tried to solve it but couldn't, I write that code in PHPMyAdmin and it works great, but it doesn't work in the website it self ok long story short, there are three tables, hotels, cities, countries hotels include in addition to hotel info, 2 columns (city_id) and (country_id) Cities include id and name and also countries include id and name what I was trying to do, that when a person inputs a city or country name in the search form, it should get the hotels that exists in this city or country, but unfortunately it shows all the hotels in all cities and countries, although the pagination code for number of pages works just fine, it count the number of hotels in that city or country and show the number of pages correctly so here is the code for both for hotel search Code: [Select] class hotelManager { public function getHotel($where) { $where = isset($_POST['where']) ? $_POST['where'] : ""; $dbObj = new DB(); $sql = "select * from hotels where city_id = (select id from cities where name = '$where' ) or country_id = (select id from countries where name = '$where' )"; $result = MYSQL_QUERY($sql); $arr = array(); echo "<table>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td valign=\"top\" width=\"120px\">"; $rowid = $row['id']; $imageqry=mysql_query("SELECT * FROM `hotelphotos` where hotel_id='$rowid' LIMIT 1"); $image=mysql_fetch_array($imageqry); $imagename=$image['attachmentName']; echo "<img src=\"foxmaincms/webroot/files/small/$imagename\"/>"; echo "</td>"; echo "<td valign=\"top\">"; echo "<table> <tr> <td valign=\"top\"> <a href=\"hotels.php?id=".$row['id']."\" class=\"titleslink\">".$row['name']."</a> </td> </tr> <tr> <td class=\"text\" valign=\"top\"> ".$row['location']." </td> </tr> </table>"; echo "</td>"; echo "</tr>"; } echo "</table>"; for hotel pagination Code: [Select] <?php include("includes/hotelsManager.php"); $hotelObj = new hotelManager(); $where = isset($_POST['where']) ? $_POST['where'] : ""; if(isset($_POST['where'])) { $hotelObj -> getHotel($where); $per_page = 9; //Calculating no of pages $sql = "select * from hotels where city_id = (select id from cities where name = '$where' ) or country_id = (select id from countries where name = '$where' )"; $result = MYSQL_QUERY($sql) or die("<br />No Hotels found in this city, please check the city name and try again"); $count = mysql_num_rows($result); $pages = ceil($count/$per_page) ?> <div id="loading" ></div> <div id="maincontent" ></div> <ul id="pagination"> thank you in advance
Hi, this query runs fine when I run it from PHPMyAdmin: UPDATE `tran_term_taxonomy` SET `description` = (SELECT keyword from `good_keywords` ORDER BY RAND() LIMIT 1,1) WHERE `tran_term_taxonomy`.`taxonomy` = 'post_tag' AND `tran_term_taxonomy`.`description` = "" LIMIT 1 However, when I run the same query in a PHP file on my server, the page doesn't load at all. The message I get is: www.somesite.com is currently unable to handle this request. HTTP ERROR 500. This is my PHP code:
<?php
include("/database/connection/path/db_connect.php");
$result4 = mysqli_query($GLOBALS["___mysqli_ston"], "UPDATE `tran_term_taxonomy` SET `description` = (SELECT keyword from `good_keywords` ORDER BY RAND() LIMIT 1,1) WHERE `tran_term_taxonomy`.`taxonomy` = 'post_tag' AND `tran_term_taxonomy`.`description` = "" LIMIT 1");
echo $result4;
?>
So how do I make this query work please? Thanks for your guidance. Hello, The following is my situation where I seem to get a 500 error code from the linux server: i have an 'index' file like this: Code: [Select] <?php require("includes/config.php"); $a = $_REQUEST['a']; switch ($a) { case "home": include("frontpage/main.php"); case "user-process": include("user-process.php"); } ?> config.php is something like this: Code: [Select] <?php require(includes/classes/session.class.php); require(includes/classes/user.class.php); require(includes/classes/db.class.php); ... ?> Now if we fall into the case "home" it works fine. Instead, if we fall into user-process it writes to the logs file Fatal Error: Class User does not exist bla bla bla. Why doesn't it exist ? every class is included in the config.php file then index.php includes first config.php ( which has all the classes) and then includes the requested page. I also have a .htaccess file which is as follows: Code: [Select] RewriteEngine On RewriteRule ^([^/\.]+)?/?([^/\.]+)?/?([^/\.]+)?/?([^/\.]+)?/?([^/\.]+)?/?([^/\.]+)?/?([^/\.]+)?$ index.php?a=$1&b=$2&c=$3&d=$4&e=$5&f=$6&g=$7 [NC,L] which is used to access in a SEO friendly way the pages that users request. This topic has been moved to Apache HTTP Server. http://www.phpfreaks.com/forums/index.php?topic=355947.0 This topic has been moved to Other Libraries and Frameworks. http://www.phpfreaks.com/forums/index.php?topic=321807.0 This topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=308625.0 This topic has been moved to mod_rewrite. http://www.phpfreaks.com/forums/index.php?topic=333010.0 This topic has been moved to PHP Installation & Configuration. http://www.phpfreaks.com/forums/index.php?topic=332517.0 I got this script: But it give me error, file_get_contents cannot open stream. I need to add the FTP connection with user/pass paramaters. then look in set http url, to get the file contents(images) and transfer to ftp server location. Can Anyone take alook and tell me if I am going down the right path and how to get there. Please Code: [Select] function postToHost($host, $port, $path, $postdata = array(), $filedata = array()) { $data = ""; $boundary = "---------------------".substr(md5(rand(0,32000)),0,10); $fp = fsockopen($host, $port); fputs($fp, "POST $path HTTP/1.0\n"); fputs($fp, "Host: $host\n"); fputs($fp, "Content-type: multipart/form-data; boundary=".$boundary."\n"); // Ab dieser Stelle sammeln wir erstmal alle Daten in einem String // Sammeln der POST Daten foreach($postdata as $key => $val){ $data .= "--$boundary\n"; $data .= "Content-Disposition: form-data; name=\"".$key."\"\n\n".$val."\n"; } // Sammeln der FILE Daten if($filedata) { $data .= "--$boundary\n"; $data .= "Content-Disposition: form-data; name=\"".$filedata['name']."\"; filename=\"".$filedata['name']."\"\n"; $data .= "Content-Type: ".$filedata['type']."\n"; $data .= "Content-Transfer-Encoding: binary\n\n"; $data .= $filedata['data']."\n"; $data .= "--$boundary--\n"; } // Senden aller Informationen fputs($fp, "Content-length: ".strlen($data)."\n\n"); fputs($fp, $data); // Auslesen der Antwort while(!feof($fp)) { $res .= fread($fp, 1); } fclose($fp); return $res; } $postdata = array('var1'=>'today', 'var2'=>'yesterday'); $filedata = array( 'type' => 'image/png', 'data' => file_get_contents('http://xxx/tdr-images/images/mapping/dynamic/deals/spot_map') ); echo '<pre>'.postToHost ("localhost", 80, "/test3.php", $postdata, $filedata).'</pre>'; This topic has been moved to CSS Help. http://www.phpfreaks.com/forums/index.php?topic=359215.0 |
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