PHP - Can Anyone Identify What I Am Doing Wrong? Can't Display Results..
Good Evening,
What I am trying to do in here is to display data based on my selected option in the drop down list. I don't have submit button, I just want it to automatically display results based on my selection. Here's my code: <link href="add_client.css" rel="stylesheet" type="text/css"> <?PHP include("dbconnection.php"); //Include database connection to file $query = "SELECT * FROM records"; if(isset($_POST["territory"])) { $query .= " WHERE territory LIKE '%".$_POST["territory"]."%' ORDER BY territory ASC LIMIT 0,15" ; $result = mysql_query($query, $connection) or die(mysql_error()); } ?> <!-- Start of table --> <table width="760" border="0" align="center" cellpadding="0" cellspacing="0"> <td> <table width="760" border="0" cellpadding="0" cellspacing="0"> <!-- Table data containing the Asia Logo --> <td width="199" align="center" valign="top"> <a href="login.html"> <img src="asia.gif" alt="" width="152" height="58" border="0" /> </a> </td> <!-- Table data containing Home button --> <td width="176" align="right" valign="bottom"> <a href="main.php"> <img src="Home.jpg" width="104" height="20" border="0"/> </a> </td> <!-- Table data containing View Client button --> <td width="130" align="right" valign="bottom"> <img src="View.jpg" width="104" height="20" border="0"/> </td> <!-- Table data containing the Add Client button --> <td width="146" align="right" valign="bottom"> <a href="add_client.php"> <img src="Add.jpg" width="104" height="20" border="0"/> </a> </td> <!-- Blank table data --> <td width="109" align="right" valign="bottom"> </td> </table> <!-- Table design division and body--> <table width="760" border="0" cellpadding="0" cellspacing="0"> <td width="200" height="3" bgcolor="#1B1C78"> <img src="images/topspacerblue.gif" alt="" width="1" height="3" /></td> <td width="560" bgcolor="#0076CC"> <img src="images/topspacerlblue.gif" alt="" width="1" height="3" /></td> <tr> <td height="500" colspan="2" align="center" valign="top" bgcolor="#F3FAFE"> <!-- Page contents --> <!-- Search Query --> <br> <form name="form" action="trustlist.php" method="post"> <table width="293" border="0"> <tr> <td width="140" align="left" valign="middle"> SEARCH RECORD: </td> <td width="143" align="center" valign="middle"><select name="territory" id="territory" style="width: 143px" width="230"> <option selected="selected" disabled="disabled">Select Territory</option> <option>Territory 01</option> <option>Territory 02</option> <option>Territory 03</option> <option>Territory 04</option> <option>Territory 05</option> <option>Territory 06</option> <option>Territory 07</option> <option>Territory 08</option> <option>Territory 09</option> <option>Territory 10</option> </select></td> </tr> </table> <br> <!-- End of search query--> <!-- Start of Search Results--> <table border="0" cellpadding="3" cellspacing="1" bordercolor="38619E" > <tr> <th width="148" align="center" bgcolor="#E0E8F3">Acute Trusts</th> <th width="262" align="center" bgcolor="#E0E8F3">Employer</th> <th width="160" align="center" bgcolor="#E0E8F3">Name</th> <th width="80" align="center" valign="middle" bgcolor="#E0E8F3"> </th> </tr> <?php if($result) { for($i=0; $i<mysql_num_rows($result); $i++) { $id = trim(mysql_result($result, $i, "id")); $territory = trim(mysql_result($result, $i, "territory")); $employer = trim(mysql_result($result, $i, "employer")); $first_name = trim(mysql_result($result, $i, "first_name")); $last_name = trim(mysql_result($result, $i, "last_name")); echo "<tr>"; echo "<td>".$territory."</td>"; echo "<td>".$employer."</td>"; echo "<td>".$last_name.", ".$first_name."</td>"; echo "<td><a href='edit_client.php?id=".$id."'>edit</a> | <a href='delete_client.php?id=".$id."'>delete</a></td>"; echo "</tr>"; } } ?> </table> </form> <!-- End of page --> </td> </tr> </table> </td> <tr> <td height="38"> <table width="760" border="0" cellpadding="0" cellspacing="0"> <td width="200" height="35" align="center" bgcolor="#1B1C78" class=white> <a href="disclaimer.html"> <font color="#FFFFFF">Legal Disclaimer</font> </a> </td> <td width="560" align="center" bgcolor="#0076CC"> Copyright © 2006 - 2010 AsiaLimited. All rights reserved. </td> </table></td> </tr> </table> Similar TutorialsI have two arrays of strings, one is read in from a file, the other is collected on a previous page using js and passed with a form through $_POST. The array from the file I label $oldImages and the array from the previous page I label $newImages (each is a list of image URLs). I need to compare the two and add them together so that there are no duplicate entries. I'm using array_diff() on them and the result I'm getting includes one entry that is in both arrays. I've tried different ways of reading the file, none of them seem to make any difference in the results. I've been printing the arrays with print_r() to have a look at the contents of the arrays and I decided to use implode() and explode(), and str_replace() to try to remove any irregularities that might be in the objects somehow which I'm not seeing. I'm not a PHP programmer, BTW. Here is some code. I've also attached a screenshot for you--link at the bottom. Code: [Select] <body> <?php $file = file("image_list.txt") or exit("Unable to open file!"); $oldImages = implode($file); $oldImages = str_replace(" ", "", $oldImages); $oldImages = explode("\n", $oldImages); $newImages = implode($_POST); $newImages = str_replace(" ", "", $newImages); $newImages = explode("\n", $newImages); $newAdditions = array_diff($newImages, $oldImages); print_r($newImages); echo '<br><br>'; print_r($oldImages); echo ' <form method="post" action="#"> New Images<br> <textarea id="displayText" rows="5" cols="105" wrap="off" name="existing"> '; foreach($newImages as $key => $entry) echo $entry; //echo $newImages; echo ' </textarea> <br> Stored Images<br> <textarea id="newText" rows="5" cols="105" wrap="off" name="new"> '; foreach($oldImages as $key => $entry) echo $entry; //echo $oldImages; echo ' </textarea> <input type="submit" class="button" value="Submit"><br> </form> Newly Generated Image List<br> <textarea id="newText" rows="30" cols="105" wrap="off" name="new"> '; foreach($newAdditions as $key => $entry) echo $entry; echo ' </textarea> '; ?> <div class="clear"></div> </body> Here is the code from the previous page which produces the array that is stored in $_POST. What you can't see in this code is the javascript functions toggleEntry() and displayList(). All they do is handle the addition and removal of image URL strings to/from the textarea object, which I do using document.getElementById('text').InnerHTML=$myList, where $myList has strings being added or removed to/from it. Code: [Select] <script type="text/javascript" src="/js/user_selection_list_builder.js"></script> <script type="text/javascript"> function toggleAndDisplay(key) { toggleEntry(key); displayList(); } </script> </head> <body> <form method="post" action="add_images2.php"> Selected Images<br> <textarea id="displayText" rows="10" cols="90" wrap="off" name="comments"> </textarea> <input type="submit" class="button" value="Submit"> </form> <div class="clear"></div> <?php $i = 2; include 'simple_html_dom.php'; if($i===1) $html = file_get_html('lookbook-source.htm'); elseif($i===2) $html = file_get_html('http://lookbook.nu/preference/look-list-gender/girls'); elseif($i===3) $html = file_get_html('http://lookbook.nu/new'); // Match all div tags of the class 'look_photo'. foreach($html->find('div[class=look_photo]') as $key => $entry) { echo " <div class='imgBox'> <a href='javascript:toggleAndDisplay(".$key.")'><img id='".$key."' src='".$entry->last_child()->last_child()->src."'></a> </div> "; } ?> </body> I'm practising how to do date and time in PHP. I wanted to see if I can get all of the date/time variables from user submission and format them correctly. I went with ISO 8601 date... // From the Manual: // date('c', mktime(1, 2, 3, 4, 5, 2006)); // Prints something like: 2006-04-05T01:02:03+00:00 ...but my attempts always produce a slightly different result for the year, month and timezone... Code: [Select] $inputTime = date('c', mktime((int)$timeHour, (int)$timeMins, (int)$timezone, (int)$dateMonth, (int)$dateDay, (int)$dateYear)); echo $inputTime; // Should return: 2013-11-02T02:30:01+00:00 // Instead returns: 2012-12-02T02:30:01-08:00 The timezone value coming from HTML... <option value="1.0">(GMT +1:00)</option> I noticed; 1. It always picks a year less than whatever year I select. 2. It always selects 12 as the month. 3. It always adds -08:00 after the picking the correct timezone. How come? Thanks in advance. Hi everyone. I'm stuck on the following query. I need to display all the fields listed below on a page, but linked via communications.CommID. I'd appreciate any assistance you can provide. thank you. Code: [Select] <?php $result = mysql_query("SELECT records.NameFirst_1, records.NameLast_1, records.CompanyName, records.CompanyBranch, records.CompanyReferenceNumber, records.CaseOwnerSelect, communications.ConversionType, communications.Contact, communications.ContactFrom, communications.CommID, communications.ContactPosition, communications.ContactTelephone, communications.ContactEmail, communications.ContactFax, communications.CallDate, communications.CallTime, communications.ActionTextField FROM records INNER JOIN communications ON records.IDNumber = '$IDNumber'") or die(mysql_error()); $row = mysql_fetch_array($result); ?> Our product is running on LAMP(PHP) architecture. For MySQL operation PDO library has been used. We are in the process of moving the product to a new Linux server. On the new server we are facing MySQL query output related issue. At the end of the post I have listed the server configuration details of both the servers and the sample PHP program with the output. It works fine in server 1 but when the same code moved to Server 2, the output is not correct. Would appreciate any points to solve this problem The following piece of code is tested and output is also given. <?php /*** mysql hostname ***/ $hostname = 'localhost'; /*** mysql username ***/ $username = 'ram'; /*** mysql password ***/ $password = 'tellmehow'; try { $dbh = new PDO("mysql:host=$hostname;dbname=inhouse", $username, $password); $sql = "SELECT first_name,last_name,user_id,email FROM users LIMIT 1"; $stmt = $dbh->prepare($sql,array(PDO::MYSQL_ATTR_USE_BUFFERED_QUERY => TRUE)); $stmt->execute(); $result = $stmt->fetch(PDO::FETCH_OBJ); $stmt->closeCursor(); /*foreach($result as $key=>$val) { echo $key.' - '.$val.'<br />'; }*/ print_r($result); $dbh = null; } catch(PDOException $e) { echo $e->getMessage(); } ?> Output for server 1: stdClass Object ( [first_name] => super [last_name] => admin [user_id]=>1 [email] => ram@greynium.com ) output for server 2: stdClass Object ( [first_name] => super [last_name] => admin [users] => ram@greynium.com ) On server 2 I am not getting the output for field 'user_id' from the table 'users'. For the field 'email' from 'users' table, it is displaying the name of the table itself (users). Not sure what is wrong. The configuration of the servers are given below Server 1 -------- OS Details: Linux 2.6.9-5.ELsmp PHP Details: PHP 5.2.3 (cli) (built: Aug 28 2007 11:48:30) Copyright (c) 1997-2007 The PHP Group Zend Engine v2.2.0, Copyright (c) 1998-2007 Zend Technologies with Suhosin v0.9.22, Copyright (c) 2007, by SektionEins GmbH PDO details: PDO PDO support => enabled PDO drivers => sqlite2, sqlite, mysql PDO Driver for MySQL, client library version => 5.0.37 PDO Driver for SQLite 3.x => enabled Server 2 --------- OS Details: Linux 2.6.18-8.el5 PHP Details: eAccelerator requires Zend Engine API version 220060519. The Zend Engine API version 220090626 which is installed, is newer. Contact eAccelerator at http://eaccelerator.net for a later version of eAccelerator. PHP 5.3.2 (cli) (built: Jul 6 2010 17:57:31) Copyright (c) 1997-2010 The PHP Group Zend Engine v2.3.0, Copyright (c) 1998-2010 Zend Technologies PDO Details: PDO PDO support => enabled PDO drivers => mysql, sqlite, sqlite2 PDO Driver for MySQL => enabled PDO Driver for SQLite 3.x => enabled hi friends. to fetch results from the database i made a function and how i call the function on a page like $results = GetResults($someID); when i print_r the $results i get all the results, but now im confused on how do i print the rows individually? say i got Title row how will i only get the Title row from the $results VAR? Hey guys so my code below is not working, it will get the app information for the user but its only display 3 results like every time a new user "installs" an new app like it stops showing the last result and starts displaying the new result. Like for example right now it should be showing 7 results but only displaying 3 is there something wrong with my query. (PS: this is just developement testing purposes so thats why my code is sorta sloppy) Thanks!
$default_apps = mysql_query("SELECT * FROM apps WHERE `default`='1'") or die(mysql_error()); $user_apps = mysql_query("SELECT * FROM user_apps WHERE `user_id`='$user_id'") or die(mysql_error()); while($row = mysql_fetch_array($default_apps)) { $url = $row['download_url']; $name = $row['name']; echo $row['name']; echo "<a href='$url'>$name</a><br />"; } while($raw = mysql_fetch_array($user_apps)){ $app_id = $raw['app_id']; } $select_user_apps = mysql_query("SELECT * FROM apps WHERE `app_id`='$app_id' "); while($rop = mysql_fetch_array($select_user_apps)) { $name = $rop['name']; $url = $rop['download_url']; echo $name; echo $url; } I'm new to php and been trying to follow along with different tutorials to try and build my own site, i followed a tutorial on making a search feature for the site and have it working perfectly, but i want to change the way how to search displays the results. I want to make it display them how there displayed on the index page. here is the index page how there displayed <div id="table"> <table> <tr class="top"> <th>Account</th> <th>Country</th> <th>Info</th> <th>Login</th> <th>Pass</th> <th>Price</th> <th>Buy</th> </tr> <?php $class = 'grey'; ?> <?php $items = getItems(); ?> <?php if(empty ($items)): ?> <h3>No Items Found</h3> <?php else: ?> <?php foreach($items as $item): ?> <?php $class = ($class == 'grey') ? 'grey2' : 'grey'; ?> <tr class="<?php echo $class; ?>"> <td><?php echo $item['item_account']; ?></td> <td><?php echo $item['item_country']; ?></td> <td><?php echo $item['item_info']; ?></td> <td><?php echo maskUser($item['item_login']); ?></td> <td><?php echo maskPass($item['item_pass']); ?></td> <td><?php echo $item['item_price']; ?> </td> <td><form method="post" action="https://sci.libertyreserve.com/"><input type="submit" name="buy" value="Buy" class="button" /></form></td> </tr> <?php endforeach; ?> <?php endif; ?> how the search is display if (strlen($search) <= 2) { echo 'Search keyword is too short.'; } else { echo "You searched for <b>$search</b><hr size='1'>"; $search_exploded = explode(" ", $search); foreach($search_exploded as $search_each) { $x++; if ($x == 1) $construct .= "item_account LIKE '%$search_each%'"; else $construct .= " OR item_account LIKE '%$search_each%'"; } $construct = "SELECT * FROM items WHERE $construct"; $run = mysql_query($construct); $foundnum = mysql_num_rows($run); if ($foundnum == 0) { echo 'No results found.'; } else { echo "$foundnum results found!</p>"; while ($numrows = mysql_fetch_assoc($run)) { $item_id = $numrows['item_id']; $itemAccount = $numrows['item_account']; $itemI = $numrows['item_info']; $itemLogin = $numrows['item_login']; $itemPass = $numrows['item_pass']; $itemPrice = $numrows['item_price']; echo " <b>$itemAccount</b><br /> $itemI <br /> " . maskUser($itemLogin) . '<br />' . maskPass($itemPass, 0) . '<br />'; } } } my question is im not sure how to edit the search code to display the results in the same format as the index page thanks Folks,
I managed to get this piece of code working. But I need you to check if it is buggy or in error or not. I will add VALIDATION later. Just let me know is this how you query db with mysqli_stmt_bind_result (prepared statement using procedural style) and display results on screen ? Don't worry about pagination. i will add that later. Just let me know if I got the basics correct or not to display results from db or not. That is all. Note my comments in CAPITALS. They are questions to which I need answers. conn.php <?php $db_server = 'localhost'; $db_user = 'root'; $db_password = ''; $db_database = 'test'; $conn = mysqli_connect("$db_server","$db_user","","$db_database"); //SHOULD I KEEP FOLLOWING 1 LINE INTACT HERE OR DUMP IT TO main file search.php ? $conn->set_charset('utf8mb4');//Always use Charset. //HOW TO CONVERT ABOVE LINE TPO PROCEDURAL ? if (!$conn) { //HOW TO WRITE CODE SO FOLLOWING TECHNICAL ERROR IS WRITTEN TO ERROR FILE AND NOT SHOWN TO USER ? //Error Message to show user in technical/development mode to see errors. die("Database Error : " . mysqli_error($conn)); //Error Message to show User in Layman's mode to see errors. die("Database error."); exit(); } ?> Q1. Do not forget to answer my question you see in CAPITALS in above code (conn.php). Check the search.php before replying.
error_reporting.php <?php ini_set('error_reporting','E_ALL'); ini_set('display_errors','1'); ini_set('display_startup_errors','1'); error_reporting(E_ALL); //SHOULD I KEEP FOLLOWING 1 LINE INTACT HERE OR DUMP IT TO main file search.php ? mysqli_report(MYSQLI_REPORT_ERROR|MYSQLI_REPORT_STRICT); ?> Q2. Do not forget to answer my question you see in CAPITALS in above code (error_reporting.php). Check the search.php before replying.
search.php <?php //include('error_reporting.php'); error_reporting(E_ALL); ini_set('error_reporting',E_ALL); ini_set('display_errors','1'); ini_set('display_startup_errors','1'); ?> <form name = "search" method = "POST" action=""> <label for="keywords">Keywords:*</label> <input type="text" name="keywords" id="keywords" placeholder="Input Keywords" required> <br> <button type="submit">Submit</button><br> <button type="submit" value="submit">Submit</button><br> <input type="submit" value="submit"><br> <button name=submit value=" ">Search</button><br> <button type="submit" name="submit" value="submit">Search</button> <br> <input type="reset"> <br> </form> <?php if($_SERVER['REQUEST_METHOD'] === 'POST') { if(ISSET($_POST['submit'])) { if(ISSET($_POST['keywords'])) { $keywords = $_POST['keywords']; } //SHOULD I KEEP FOLLOWING 1 LINE INTACT HERE OR DUMP IT TO error_reporting.php ? mysqli_report(MYSQLI_REPORT_ERROR|MYSQLI_REPORT_STRICT); //SHOULD I KEEP FOLLOWING 5 LINES INTACT HERE OR DUMP IT TO conn.php ? $conn = mysqli_connect("localhost","root","","test"); $conn->set_charset("utf8mb4"); if(mysqli_connect_error()) { echo "Could not connect!" . mysqli_connect_error(); } $query = "SELECT page_url,link_anchor_text,page_description,keyphrases,keywords FROM links WHERE keywords = ?"; $stmt = mysqli_stmt_init($conn); //FIRST ATTEMPT TO DISPLAY TBL RESULTS USING mysqli_stmt_bind_result() FUNCTION. TEST RESULT: ATTEMPT A FAILURE! if(mysqli_stmt_prepare($stmt,$query)) { mysqli_stmt_bind_param($stmt,'s',$keywords); $stmt_execution = mysqli_stmt_execute($stmt); if($stmt_execution === FALSE) { printf("Error: %s.\n", mysqli_stmt_error($stmt)); printf("Error: %d.\n", mysqli_stmt_errno($stmt)); die; } $bind_result = mysqli_stmt_bind_result($stmt,$page_url,$link_anchor_text,$page_description,$keyphrase,$keywords); if($bind_result === FALSE) { printf("Error: %s.\n", mysqli_stmt_error($stmt)); printf("Error: %d.\n", mysqli_stmt_errno($stmt)); die; } $stmt_fetch = mysqli_stmt_fetch($stmt); if($stmt_fetch === FALSE) { printf("Error: %s.\n", mysqli_stmt_error($stmt)); printf("Error: %d.\n", mysqli_stmt_errno($stmt)); die; } while(mysqli_stmt_fetch($stmt)) { echo "$page_url"; echo "<br>"; echo "$link_anchor_text"; echo "<br>"; echo "$page_description"; echo "<br>"; echo "$keyphrase"; echo "<br>"; echo "$keywords"; echo "<br>"; echo "|"; echo "<br>"; } mysqli_stmt_close($stmt); mysqli_close($conn); } else { die("QUERY failed!)"; }
Q3. Anything I should know ? Edited July 17, 2020 by 2020Hi I have the following code: Code: [Select] $result = mysql_query("SELECT * FROM xbox_games order by gameid"); $row = mysql_fetch_assoc($result); $id = $row["gameid"]; $title = $row["gametitle"]; $cover = $row["cover"]; <?php echo $title;?> Which displays only the first result from my database. How can i change this to display all the results either as a list, or in a table? Thanks Hello all, I have made the multi level marketing downline tree, but the problem with it now, it gives only the downline of one result, as the query gives 2 results what I want now is to make it give the downline of both results not just one, and it's always 2 results, not more here is my code Code: [Select] <?php $id = $_GET['id']; $result = mysql_query("SELECT id FROM users WHERE id = '".$id."' ORDER BY id"); $row = mysql_fetch_assoc($result); if ($row['id'] == 0) { echo" <table> <div id=\".piccenter\""; echo "<tr>"; echo "<img src=\"icon.gif\" border=0 align=\"center\">"; echo ""; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$row['id']."'"; echo ""; echo "</div>"; } } $result2 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$row['id']."'"); $rows2 = mysql_fetch_assoc($result2); foreach ($rows2 as $row2) { if ($row2['id'] == 0) { echo" <div id=\".picleft\"> <img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0 >"; echo "<br />"; echo "'".$row2['id']."'"; echo "</div>"; echo " <td>"; echo "</td> "; } } $result3 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows2['id']."'"); $row3 = mysql_fetch_assoc($result3); if ($row3['id'] == 0) { echo"<div id=\".picright\"> <img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$row3['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result4 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$row3['id']."'"); $rows4 = mysql_fetch_assoc($result4); if ($rows4['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows4['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result5 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows4['id']."'"); $rows5 = mysql_fetch_assoc($result5); if ($rows5['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows5['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result6 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows5['id']."'"); $rows6 = mysql_fetch_assoc($result6); if ($rows6['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows6['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result7 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows6['id']."'"); $rows7 = mysql_fetch_assoc($result7); if ($rows7['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows7['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result8 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows7['id']."'"); $rows8 = mysql_fetch_assoc($result8); if ($rows8['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows8['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result9 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows8['id']."'"); $rows9 = mysql_fetch_assoc($result9); if ($rows9['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows9['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> </tbody> </table> "; } ?> I am pulling some info from a mysql table, checking some logic, and displaying in on a page. The way this is written now it shows all of the items in a one column table, I simply want to break it up into multiple columns (ideally by specifying say 20 items per column). I know I need a counter and a loop but I'm just not sure how it all fits in with my existing program. Any help would be greatly appreciated. Here is my code Code: [Select] $result2 = mysql_query("SELECT * FROM propertyids ORDER BY propertyname ASC"); while($row2 = mysql_fetch_array($result2)){ ${'resp'.$row2['id']} = curl_multi_getcontent(${'ch'.$row2['id']}); ${'status'.$row2['id']} = strpos(${'resp'.$row2['id']},$httpvar); if(${'status'.$row2['id']} === false) { echo "<tr><td>"; echo "<img src='images/down.png'> <a href='" . $row2['primaryurl'] . "' target='_blank'>" . $row2['propertyname'] . "</a>"; echo "</td></tr>"; } else { echo "<tr><td>"; echo "<img src='images/up.png'> <a href='" . $row2['primaryurl'] . "' target='_blank'>" . $row2['propertyname'] . "</a>"; echo "</td></tr>"; } } echo "</td></table>"; Hello, I know this should be pretty simple to figure out, but everything I try is giving me absolutely no results. I have a mysql query selecting columns from my database and returning results. I have the results printing out right now, so I can see that this part is working. All I want to do is take the results and put them into a table to display on my page. Basically, take what's in the database table and copy it to a table I can put on the web. FYI I am using sourcerer so the "connect" code is taken care of for me in the "JFactory" bit of code. Here is the first part of my code, selecting the information from the database. {source} <?php $db = JFactory::getDbo(); $query = $db -> getQuery(true); $query -> SELECT($db -> quoteName(array('first_dept_name', 'last_name', 'dept', 'position', 'phone_num'))); $query -> FROM ($db -> quoteName('#__custom_contacts')); $query -> ORDER ('first_dept_name DESC'); $query -> WHERE ($db -> quoteName('contact_category')."=".$db -> quote('YTown Employees')); $db -> setQuery($query); $results = $db -> loadObjectList(); print_r($results); Here is where I am trying to print the results into a table. I got this code directly from a PHP book, but I am getting nothing at all returned back to me. I get table headers, but no data. <?php echo "<table><tr><th>Name</th><th>Department</th></tr>"; while ($row = mysqli_fetch_array ($result)){ echo "<tr>"; echo "<td>".$row['last_name']."</td>"; echo "<td>".$row['dept']."</td>"; echo "</tr>"; } echo "</table>"; ?> {/source} I have a program which have written with c+ +. This program is a generic server stats program for all Silkroad versions. ( Silkroad = MMORPG game like WoW ). " So if you have a website, you can upload the file via FTP to your own directory and write a simple PHP script or ASP script to parse the file and display the results. Or, you can post the data via PHP via a web URL. " I need to make this what i write that write the results. This write the following data: Code: [Select] Server Id Server Name Current Players Max Players State (1 = open, 0 = check) For example: 2 220 Zeus 354 2500 1 221 Venus 539 2500 1 And save this data to any.txt file. Here is the site: http://www.error-soft.net/forum/prvsro.php u need to se the server stats : Server Name Players State Status Total Capacity 2059 / 6000 [34%] ZSZC(Fire) 0 / 2000 Empty Offline ZSZC (Water) 2059 / 2000 Full Online ZSZC (Retro) 0 / 2000 Empty Offline i have the program what check the server and write this information to text file, but i do not know how can i parse this information like this website. EDIT: sorry - new to posting guidelines - using XAMPP with mysql 5.1.44 (I think this is correct!!) Newbie question he I have successfully created a form that that displays students (based on a selected lesson/group/date) with the ability to enter scores. I'm now trying to set the form up so that if data already exists then it is displayed in the form. Eg: if a member of staff choses group 7AS, lesson 1, 24/09/2010 and another member of staff has entered a score already for one student it shows up in the <select> drop down by using Code: [Select] <option>" . $scorevalue . "</option> I had this working at one point but have made a change somewhere and cannot get it working again! can anyone spot an obvious mistake I am making? The code I am using is as follows: Code: [Select] <input type="hidden" name="tutor" value="<?php echo $_GET["tutor"]; ?>" /> <input type="hidden" name="date" value="<?php echo $_GET["date"]; ?>" /> <input type="hidden" name="lesson" value="<?php echo $_GET["lesson"]; ?>" /> <?php error_reporting(-1); $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("lakeside", $con); $result = mysql_query("SELECT students.admin, students.fname, students.surname, students.tutor FROM students WHERE tutor='$_GET[tutor]' ORDER BY students.tutor, students.surname"); echo "<table class='scores'> <tr> <th>Admin</th> <th>Firstname</th> <th>Surname</th> <th>Tutor</th> <th>Score</th> <th>Code</th> <th>Comment</th> </tr>"; while($row = mysql_fetch_array($result)) { $sqlstatement = "SELECT * FROM scores where admin = '" . $row['admin'] . "' and lesson = '" . $_GET[lesson] . "' and date = '" . $_GET[date] . "' "; $scorevalue = mysql_query($sqlstatement); echo " . $score . "; while($rowvalue = mysql_fetch_array($scorevalue)) { $score = $rowvalue['score']; $comment = $rowvalue['comment']; $code = $rowvalue['code']; } echo "<tr>"; echo "<td>" . $row['admin'] . "</td>"; echo "<td>" . $row['fname'] . "</td>"; echo "<td>" . $row['surname'] . "</td>"; echo "<td>" . $row['tutor'] . "</td>"; echo "<td><select name='score" . $row['admin'] . "' value='{$row['score']}' /> <option>" . $scorevalue . "</option> <option>0</option> <option>1</option> <option>2</option> <option>2.5</option> <option >3</option> <option>3.5</option> <option>4</option> </select> </td>"; I am trying to display certain MySQL data based off of what link is clicked. For example.. I want to display all the entries from 2009 when a link for 2009 is clicked; maybe like.. <a href="http://website.com/page?yr=09">2009</a> But I am having trouble doing so.. any help would be great! P.S. The years are in my database with only the last two numbers.. 10, 09, 08, etc. $result = mysql_query("select setlist_id, month, day, year, name, venue, location, label1, set1, set2, set3, encore, notes, photos, recording, poster from $database_table order by setlist_id DESC, year, month, day",$db) or die_now("Could not select setlists"); while($row = mysql_fetch_array($result)) { $the_id = $row["setlist_id"]; $the_month = $row["month"]; $the_day = $row["day"]; $the_year = $row["year"]; $the_name = $row["name"]; $the_venue = $row["venue"]; $the_location = $row["location"]; $the_label1 = $row["label1"]; $the_set1 = $row["set1"]; $the_set2 = $row["set2"]; $the_set3 = $row["set3"]; $the_encore = $row["encore"]; $the_notes = $row["notes"]; $the_photos = $row["photos"]; $the_recording = $row["recording"]; $the_poster = $row["poster"]; echo("<div class='date' id='date' tabindex='0'>" . "$the_month" . "." . "$the_day" . "." . "$the_year" . " - "); echo ($the_name != '') ? "" . "$the_name" . " - " : ''; echo("" . "$the_venue" . " - " . "$the_location" . "</div>"); echo("<div class='set'>" . "$the_label1" . ":<br /></div><div class='list'>" . "$the_set1" . "<br /></div>"); echo ($the_set2 != '') ? "<div class='set'>Set Two:<br /></div><div class='list'>" . "$the_set2" . "<br /></div>" : ''; echo ($the_set3 != '') ? "<div class='set'>Set Three:<br /></div><div class='list'>" . "$the_set3" . "<br /></div>" : ''; echo ($the_encore != '') ? "<div class='set'>Enco <br /></div><div class='list'>" . "$the_encore" . "<br /></sdiv>" : ''; echo("<div class='line'></div>"); echo nl2br("<div class='notes'>" . "$the_notes" . "</div>"); } When I replace the $result line with... $result = mysql_query("SELECT * FROM `$database_table` WHERE `year` = '09' order by setlist_id DESC, year, month, day",$db) or die_now("Could not select shows");... I get all the results from just 2009, which is what I want, but I want the results to depend on what link has been clicked. I hope I am making sense. what I need is for a loop to run to make tabbed pannels according to categories. then I need the buttons to be put into the correct tab based on the category it falls under. then a subcategory tabs inside the other tabs for products that have that specific sub category. here is what I sorta made....it doesn't work though.... Code: [Select] <div id="TabbedPanels1" class="TabbedPanels"> <ul class="TabbedPanelsTabGroup"><?php $sql = mysql_query("SELECT * FROM categories"); while($row = mysql_fetch_array($sql)){ $category = $row["category"]; $sub =$row["subcategory"]; ?> <li class="TabbedPanelsTab" tabindex="0"><?php echo $category; ?></li> <div class="TabbedPanelsContentGroup"> <div class="TabbedPanelsContent"> <?php // set layout vars $x = 1; // set $x $start = array ('1', '10', '19', '28', '37', '46', '55', '64', '73', '82', '91', '100', '109', '118', '127', '135'); //columns will be started at each of these numbers $end = array( '9', '18', '27', '36', '45', '54', '63', '72', '81', '90', '99','108','117', '126' ); // set numbers to end columns at ?> <?php echo '<table border="1px" cellpadding="0px" cellspacing="0px" ><tr height=\'50px\'>'; //start the table, and the row. // Query member data from the database and ready it for display $sql = mysql_query("SELECT * FROM products where category=".$category.""); while($row = mysql_fetch_array($sql)){ $product = $row["product"]; $id =$row["id"]; $price =$row["price"]; if (in_array($x, $start)) { // if x equals a number in the start array echo '<td width="100">'; // start a column } ?> <?php $sql = mysql_query("SELECT * FROM categories"); while($row = mysql_fetch_array($sql)){ $category = $row["category"]; $sub =$row["subcategory"]; ?> <?php } ?> <div id="products"> <form action="" method="POST" name="myform<?php echo $id; ?>" class="myform<?php echo $id; ?>"> <input type="hidden" name="hiddenField" class="hiddenField" value="<?php echo $product; ?>" /> <input type="hidden" name="hiddenField2" class="hiddenField2" value="<?php echo $id; ?>" /> <input type="hidden" name="hiddenField1" class="hiddenField1" value="<?php echo $price; ?>" /> <input type="submit" name="submit" class="submit" value="<?php echo $product; ?>" style="background-color:lightgreen; height:50px; padding: 0px; margin:0px; width:100px;"> </form> </div> <?php if (!in_array($x, $end)){ // if $x equals anything OTHER than 9, 18, etc - put in a line break } else { // else if it DOES equal 9, 18 ,etc end the column echo '</td>'; } $x ++; // increase x to keep count } // while loop ends //now outside of the loop, $x = $x - 1; //subtract the last $X++ so you know exactly how many buttons were added if (!in_array($x, $end)){ // if $x equals anything OTHER than 9, 18, etc - end the column as it wouldn't have ended itself echo '</td>'; } echo '</tr></table>'; // close the row and table ?><?php } ?> </div> </ul> </div> any help is greatly appreciated. Hey all. I have a query that selects data from a datbase based on a criteria. Easy enough. But now I am growing and the amount displaying is too much. How can you, via php, have a queries result be displayed only so many at a time and auto create links that show the rest? Like if query returns 82 results, I want it to display 25 immediately and create 3 links at the bottom. The next link would show 26-50. The next 51-75. And the final 76-82. etc Example: Code: [Select] $result = mysql_query("SELECT * FROM pay"); $num_rows = mysql_num_rows($result); while($row = mysql_fetch_array($result)) { echo $row['first_name']; echo $row['last_name']; echo $row['item_name']; echo $row['option_selection1']; echo $row['payment_date']; echo $row['stat']; } This is simple. But what happens when the results are 125? I want to limit it to displaying 25 at a time. Is the only way to manually create seperate pages and have each one show 1-25, then 26-50, etc? Or is there a way to have the script do it, itself? Any tutorials out there on this specifically? Hopefully I am making sense. Thanks! Hello all. I'm using this code to go through the database and output certain user-defined numbers Code: [Select] <?php mysql_connect ("pdb1.awardspace.com", "anastasov_db","moscow1945") or die (mysql_error()); mysql_select_db ("anastasov_db"); $term = $_POST['term']; $sql = mysql_query("select * FROM countries WHERE cocode = '$term'"); while ($row = mysql_fetch_array($sql)){ echo '<br/> Code: '.$row['cocode']; echo '<br/> Country: '.$row['coname']; echo '<br/><br/>'; } ?> Now how would I go about making a page that appears if the script can't find any results in the database? Thank you in advance friends my url is like this Category=Love&ID=1 now in url if i do something like this Category4637=Hate19203&ID=1 the details are still showing, how can i fix this? if someone type Capegory instead of Category and a wrong category name which do not exist with that id in db send them to index.php? I am looking to accomplish the following but have been hitting a brick wall: * User enters a single keyword into a text field, and conducts a search keyword search. * The results are pulled from the campusbooks.com API(API docs attached) * result are then output in <div> class and includes all the book details and its corresponding url./img etc I'm trying to simplify this process but I continue to receive syntax errors. A step by step practical explanation would do me justice! |