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PHP - Multiple Select Boxes In Array
Hi
I am trying to have the following as an example: Code: [Select] <select name="test[]" multiple="multiple">options here</select> <select name="test[]" multiple="multiple">options here</select> Then using $_POST['test'] to grab the boxes in the array. I want to then loop over each box so for example: Code: [Select] $boxes = $_POST['test']; foreach ( $boxes as $box ) // now here i would of expected $box to be an array of the options, } but it's not working like this, all the options from all submitted select boxes come in one array so I cannot distinguish which select box in the array they relate to, is there a way to do this?? Similar TutorialsI need some help with the query for a form that selects values across multiple columns, and allow users to select multiple values in several columns. http://brinsterinc.com/tpa/tpasearch.php I assume you build the where clause for the sql by determining if there is an option value has been selected in the single-value select boxes. But how do I handle the multi-select list boxes? I'm desperate for help! Need to get somewhere with this over the weekend! TIA! Hello, I had 8 select boxes(dropdowns) in a form. Its like a search kind of implementation in the website. I don't know what the user selects, he may choose different select boxes, any number of select boxes. So, based upon the user selection, I need to generate the data. The data fields to be generated would be almost same. So, How would I know what the user selection is and how many select boxes has been selected and how could I generate different data based upon selected boxes. I had to make a small note abt this, that the data generation fields may change for some of the user select combinations, but most of the result fields would be same. so, can you please help me out, how to do, how to make different combination data generations, because, i had 8 fields, i had to make 8! combinations, that would result in a big code. hirealimo.com.au/code1.php this works as i want it: Quote SELECT * FROM price INNER JOIN vehicle USING (vehicleID) WHERE vehicle.passengers >= 1 AND price.townID = 1 AND price.eventID = 1 but apparelty selecting * is not a good thing???? but if I do this: Quote SELECT priceID, price FROM price INNER JOIN vehicle....etc it works but i lose the info from the vehicle table. but how do i make this work: Quote SELECT priceID, price, type, description, passengers FROM price INNER JOIN vehicle....etc so that i am specifiying which colums from which tables to query?? thanks Hi There, Is there any way that I can get a select box to auto-select the value from a SQL query? For example, if I have a select box like this: Dave,Jon,Simon,Fred And a select statement that brings back the value of Fred then the select box (in HTML) would: <select name='people'><option>Dave</option><option>Jon</option><option>Simon</option><option selected='selected'>Fred</option></select> Same as if the name was Dave, or Simon etc etc. Hope that makes sense? Cheers Matt Hey guys,
My problem is, iam loading with mysql_fetch_array a table from my database and draw it into my website page.
The table is a user table which has an id, user, password and rights(Admin, Mod , User).
Only the rights are given out as <select> </select> boxes with the 3 options(Admin, Mod , User).
And i also have 1 more column which has for each row a href to a new site with the id of the array_index as paramter.
My Problem is i want to know which select box was changed and which option is selected so i can change the rights in my database of this user with the right id.
At the moment i cant post the code in here cause i have a problem with my laptop now.
I hope you can help me,
Thank you
Edited by Kandey, 30 October 2014 - 02:28 PM. Brand new to the forum, and have only been working with HTML, PHP, & MySQL for about 3 months. I've run into an issue I can't seem to figure out how to work around. I want to have two select boxes, that are dependent on one another. For Example: First box lists types of games: RPG LARP Board Game Miniatures CCG The second box displays game names of the type selected above. I have a MySQL table setup for the second box. To be honest I kinda already have it working... with one small but MAJOR glitch. I select the first box and the page submits using onchange='this.form.submit()'. When the page reloads the first select box reverts back to it's default setting, but the second box does correctly filter & show the content based on the selection that was made in the first box. My Question: How do I set this up so that the first box displays the user selected setting while also passing the $_POST information to the second box? My Code: <table> <tr> <td width=50%> Game Type: </td> <td width=50%> <form name='game_type' action='event_submit.php' method='post'> <select name='game_type' align=center onchange='this.form.submit()' style="width:150px;margin:5px 0 5px 0;"> <option value=''>Chose a Game Type</option> <option value='RPG'>RPG</option> <option value='LARP'>LARP</option> <option value='Board Game'>Board Game</option> <option value='CCG'>Collectable Cards & Games</option> <option value='Miniatures'>Miniatures</option> </select> </form> </td> </tr> <tr> <td width=50%> Game System: </td> <td width=50%> <?php $game_type = $_POST['game_type']; echo "$game_type"; if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("DrowCon", $con); $result = mysql_query("SELECT * FROM Games WHERE Type='$game_type' ORDER BY System ASC"); echo "<form name='game_system' action='event_submit_form.php' method='post'>"; echo "<select name='game_system' align=center style='width:150px;margin:5px 0 5px 0;'>"; echo "<option value=''>Chose a Game System</option>"; while($row_game = mysql_fetch_array($result)) { echo "<option value=''>".$row_game['System']."</option>"; } echo "</form>"; mysql_close($con); ?> </td> </tr> </table> Dear Support, Here is my code: <?php if ( strtolower($_SERVER['REQUEST_METHOD']) === 'post' ) { $name = isset($_POST['name]) ? htmlspecialchars($_POST['name']) : ""; $area = isset($_POST['area']) ? htmlspecialchars($_POST['area']) : ""; $choice = isset($_POST['choice ']) ? htmlspecialchars($_POST['choice ']) : ""; //Do Others } ?> <form class="customersForm" method="post"> <div class=""> <p>Name<br /> <select style="width:120px;" name="name"> <?php $sql = "select * from `name_info` order by `name`"; $query = mysql_query($sql); $dd = '<option>Name</option>'; while($row = mysql_fetch_object($query)) { $dd .= '<option>'.$row->name.'</option>'; } echo $dd; ?> </select> </p> </div> <div class=""> <p>Area<br /> <select style="width:120px;" area="area"> <?php $sql = "select * from `area_info` order by `area`"; $query = mysql_query($sql); $dd = '<option>Area</option>'; while($row = mysql_fetch_object($query)) { $dd .= '<option>'.$row->area.'</option>'; } echo $dd; ?> </select> </p> </div> <div class=""> <p>Choice<br /> <select style="width:120px;" choice="choice"> <?php $sql = "select * from `choice_info` where `name`='".$name."' and `area`='".$area."' order by `choice`"; $query = mysql_query($sql); $dd = '<option>Choice</option>'; while($row = mysql_fetch_object($query)) { $dd .= '<option>'.$row->choice.'</option>'; } echo $dd; ?> </select> </p> </div> ......//Others input fields ...some text fields ... </ form> I have the above code, where I would like to show the choice Drop-down box, depends on $name and $area match of the choice_info table. $name field and $area field needs to have any dependency and straight from the MySQL table. But, choice needs to depend on $name & $area. How can I do it without much using Javacript? I do not mind to use JavaScript, but prefer to minimal. By the way, I will have some other input fields too. It's an input form but, one drop-down box will be depends on two others choice. Thanks for your help. This seems to be a bit of a challenge but I am creating a multiple page form and on one of the pages I have a select field. I would like the user to have the ability to select multiple options but I am using some functions to move the data in hidden fields from page to page. I don't think my functions are jiving with my my foreach loop cause I keep getting an invalid argument error. Thanks in advance for any help. Here is my function: function setSelected($fieldName, $fieldValue) { if(isset($_POST[$fieldName]) && $_POST[$fieldName] == $fieldValue) { echo 'selected="selected"'; } } And here is my loop: $selections = ""; if(isset($_POST["selections"])) { foreach ($_POST["selections"] as $selection) { $selections .= $selection . ", "; } } Is it possible to have multiple check boxes on a single form and a single submit button tp post the values into different rows of DB Kenny I want to create a calculator that allows you to type in how many pieces of data you have, or how many averages you have. Once that is done, the amount of boxes pop up correctly - and you can enter in your data. But how can I get all those pieces of data from EACH box using one form? Current Example: http://novacms.vacau.com/ Code: <?php $boxes = $_POST['input']; if(!$boxes) { echo '<b>How many pieces of data do you have?</b> <form action="index.php" method="POST"><input type="text" name="input"><input type="submit"></form><br/><font size="2">Ex: 88.8,92.3,76.5 - That would be 3 pieces of data</font>'; } else { echo '<form action="index.php" method="POST">'; for($i = 0; $i <= $boxes; $i++) { echo '<input type="text"><br/>'; } echo '<input type="submit" value="Get average"></form>'; } ?> Hi, I had a form which contains, 8 select boxes. In those 8 select boxes, 3 of the boxes are interlinked, like, I am able to generate data in other 2 select boxes, if one box is been selected. i.e. based upon selection of one select box, and i am able to generate data in other select box. So, 3 select boxes are interlinked. And remaining 5 selects are optional, if the user selects, then we need to generate data based upon selection of the user. Here the main issue is how to grab data in the post back form, like, how to capture the number of selects boxes selected and what are those selected, and based upon that we need to generate data. Here one more important thing is that, in the report generation form(postback form), I need to show the data in a table. So , in table I had 9 columns and these would be common to whatever the selection made, but, only the requeired data would be changed based upon the selection of the remaining 5 optional boxes. Hope you got me!!!! Hello, I have the following function function make_agent_drop($dropname,$parent=''){ $agents = mysql_query("SELECT * FROM ad_category WHERE cat_status='1' AND parent_id='".(is_numeric($parent)?$parent:"0")."'") or die(mysql_error()); $anum = mysql_num_rows($agents); if($anum>0){ $agentdrop='<select style="width:150px; height:20px; margin-left:100px; font-size:11px;" name="'.$dropname.'" id="'.$dropname.'" class="text" '.(is_numeric($parent)?'':'onchange="update_subcatdrop($(this).val());').'"> <option value="0">Select a Category</option>'; while($row= mysql_fetch_array($agents)){ $agentdrop.='<option value="'.$row['cat_id'].'">'.$row['cat_name'].'</option>'; } $agentdrop.='</select>'; }else{ $agentdrop= 'No '.(is_numeric($parent)?'Sub':'').'Categories Found.'; } return $agentdrop; ; } I creates a drop down from database cats and sub cats.. I am trying to figure out how to add a submit button to dynamically appear when it displays the sub category... Thanks! Dan Hi guys, I am struggling with a form containing multiple checkboxes with corresponding textboxes. Eg.: there are 5 checkboxes (XS, S, M, L, XL) and 5 textboxes (with values 3,4,5,6,8) that correspond to the checkboxes. I give all the checkboxes the name 'size[]' and the textboxes the name 'price[]'. The aim is to have my script set a boolean to true and update the corresponding price if the checkbox is selected. Unfortunately it does not work this way: checkboxes are only put in the array when they are selected, meaning that if I select only checkbox S and L, the array length is 2 only, but array length price is always 5, so size[1] does not correspond to price[1] necessarily. There probably is a better way to achieve what I need. Could anyone point me in the right direction? edit: BTW the number of items is dynamic: sometimes there will also be XXL or some items will be missing and I also need to set the price for items where the checkbox is not checked. Hi, guys. I am a php newb and stuck (see title). I it will only send the value of 1 tick box over to the page "delete_message.php" This is what i have so far: Code: [Select] <?php // get messages $result = mysql_query("SELECT * FROM tbl_pvt_msg WHERE to_UID='$UID'"); if (!$result) die("Query to show fields from table failed"); while ($data=mysql_fetch_array($result)) { $_SESSION['from_UID']=$data['1']; UIDtoemail(); $from_email=$_SESSION['from_email']; $contents=$data['3']; $timesent=$data['4']; $msg_ID=$data['0']; echo "<form action='scripts/delete_message.php' method='POST' >"; echo "<tr><td>$from_email</td><td>$contents</td><td>$timesent</td><td><input type='checkbox' value='$msg_ID' name='msg_ID' /></td> </tr>"; } // turn uid into email function UIDtoemail(){ $from_UID=$_SESSION['from_UID']; $result = mysql_query("SELECT * FROM tbl_usr WHERE UID='$from_UID'"); if (!$result) die("Query to show fields from table failed"); $data=mysql_fetch_array($result); $_SESSION['from_email']=$data['7']; } ?> </table> <input type="submit" value="Delete" id="delete" /> </form> I have a simple (1 table, 14 fields) database. I'm using 9 separate search boxes from my search page : http://www.cinemaposter.com/database.html There are currently 162 entries. Hitting "submit" throws them all out, same with valid input into any box, with the exception of "country" - example : entering "F" gives 20results; "PL" gives 34 results. Here's my code (to simplify, I only went down to the 4th box ('country' - the last and only one giving correct results). I'm one sorry newbie.... please help ! Here's the code : ------------------ <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/1998/REC-html40-19980424/loose.dtd"> <html> <head> <title>Search Results</title> <meta name="generator" content="BBEdit 6.5"> <style type="text/css"> td { color: #000000; font-family: arial; font-size: 10px; } </style> </head> <body> <?php $link = mysql_connect("xxxx", "xxxx", "xxxx") or die("Could not connect"); ///print "Connected successfully<BR>"; mysql_select_db("xxxx") or die("Could not select database"); { $Author = $_POST['Author']; $sql = "SELECT * FROM posters WHERE Author LIKE '%$Author%'"; } { $Title = $_POST['Title']; $sql = "SELECT * FROM posters WHERE Title LIKE '%$Title%'"; } { $Originaltitle =$_POST['Originalitle']; $sql="SELECT * FROM posters WHERE Originaltitle LIKE '%$Originaltitle%'"; } { $Country =$_POST['Country']; $sql="SELECT * FROM posters WHERE Country LIKE '%$Country%'"; } $result = mysql_query ($sql) or die("Query failed : " . mysql_error()); $numrs = mysql_num_rows($result); if ($numrs > 0){ if ($numrs==1){ print ("<p><font face=\"Arial\"><b>There is $numrs record in our database.</B> <BR><BR>"); }elseif($numrs>1){ print ("<p><font face=\"Arial\"><b>There are $numrs records in our database. </B><BR><BR>");//Apparently, he wan't to be able to search again...</b><form method \"POST\" action=\"$PHP_SELF\">Search Again:"); } echo("<a href='javascript:history.go(-1)'>Go Back</a></p>"); print("<P align=center>Click on the column heading links to sort the results.<br><br />"); print ("<TABLE CELLPADDING=\"1\" CELLSPACING=\"2\" BORDER=\"0\">\n"); PRINT ("<TR BGCOLOR=\"#FFFF77\"> <TD COLSPAN=2><P align=center>Author</td> <TD><P align=center>Title</TD> <TD><P align=center>Original Title</TD> <TD><P align=center>Country</TD> <TD><P align=center>Director</TD> <TD><P align=center>Cast</TD> <TD><P align=center>Year</TD> <TD><P align=center>Original Year</TD> <TD><P align=center>Photo</TD> <TD><P align=center>Producer</TD> <TD><P align=center>Circulation</TD> <TD><P align=center>Size</TD> <TD><P align=center>Print type</TD> <TD><P align=center>Remarks</TD></TR>"); $z=1; while ($line = mysql_fetch_array($result)) { $num=$z++; //Note here that I'm assigning the found objects new names (indicated by lowercase) to that php wont get confused..... $auth=$line['Author']; $title=$line['Title']; $originaltitle=$line['Originaltitle']; $country=$line['Country']; $director=$line['Director']; $cast=$line['Cast']; $year=$line['Year']; $originalyear=$line['Originalyear']; $producer=$line['Producer']; $circ=$line['Circulation']; $size=$line['Size']; $print=$line['Print']; $remarks=$line['Remarks']; $pict=$line['Picture']; //Set the formatting $bgcolor = ($i++ & 1) ? '#d3d3d3' : '#c0c0c0'; PRINT("<TR BGCOLOR=$bgcolor> <TD>$num.</TD> <TD>$auth</td> <TD>$title</TD> <TD>$originaltitle</TD> <TD><P align=center>$country</TD> <TD>$director</TD> <TD>$cast</TD> <TD><P align=center>$year</TD> <TD><P align=center>$originalyear</TD><TD>"); // This is the test to find do we have a picture if ($pict) { // If there is a picture, display it: print ("<P align=center><a href='zdjecie.php?zdj= $pict&autor=$auth&opis=$title&orig=$originaltitle&rok=$year' target='_blank'> <img src=$pict height=\"150\"></a>"); } else { // We don't have a picture, so we print some text instead: print ("<P align=center>no picture available"); } print ("</TD><TD>$producer</TD> <TD><P align=center>$circ</TD> <TD>$size</TD> <TD>$print</TD> <TD>$remarks</TD></TR>"); } PRINT("</TABLE><BR><font face=\"Arial\"><a href=\"javascript:history.go(-1);\">Search Again</a></font>"); }else { print ("<font face=\"Arial\">Sorry, there were no results for your search. <a href=\"javascript:history.go(-1);\">Please try again</a></font>"); } //mysql_close($link); ?> </body> </html> Hello, Iv written a small script in JS to add input boxes of the type file to the page.. My problem is when i use multiple of those input boxes and submit the form the $_FILES variable only reads 1 of those boxes.. This is the javascript im using: Code: [Select] function addImageBox() { var imageBoxes = document.getElementById("imageBoxes"); var tr = document.createElement("tr"); var td = document.createElement("td"); var td2 = document.createElement("td"); var inputFile = document.createElement("input"); inputFile.setAttribute("type", "file"); inputFile.setAttribute("name", "image[]"); inputFile.setAttribute("style", "width: 450px"); td.appendChild(document.createTextNode("Image")); td2.appendChild(inputFile); tr.appendChild(td); tr.appendChild(td2); imageBoxes.appendChild(tr); } When i add 2 boxes (making it 3 boxes on the page in total) and count the $_FILES var after submiting the form, the count method returns 1, and when i var_dump it only 1 array is in $_FILES. Any idea's? thanks! I am attempting to submit a form that includes multiple check boxes for one data field. I have set it up the implode the data and make it a comma delimited array. I am able to echo the results, yet I have not been able to post the information to the database. I believe that I have just one simple thig to do, yet I am not being successful. Here is my code I have attached the .txt file also: <?php require_once('Connections/rotarysantarosa.php'); ?> <?php if (isset($_POST['submit'])) { if (isset($_POST['currentClubPosition'])) { $strcurrentClubPosition = implode(",", $_POST['currentClubPosition']); } else { $strcurrentClubPosition = ""; } } ?> <?php if (!function_exists("GetSQLValueString")) { function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") { if (PHP_VERSION < 6) { $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue; } $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue); switch ($theType) { case "text": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "long": case "int": $theValue = ($theValue != "") ? intval($theValue) : "NULL"; break; case "double": $theValue = ($theValue != "") ? doubleval($theValue) : "NULL"; break; case "date": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "defined": $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue; break; } return $theValue; } } $editFormAction = $_SERVER['PHP_SELF']; if (isset($_SERVER['QUERY_STRING'])) { $editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']); } if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "frmMemberInsert")) { $insertSQL = sprintf("INSERT INTO members (firstName, lastName, photo, pastPresident, currentClubPosition, classification, workPosition, company, workAddress, workCity, workState, workZip, officePhone, fax, homePhone, cellPhone, email, website, homeAddress, homeCity, homeState, homeZip, birthdayMonth, birthdayDay, spouse, yearJoined) VALUES (%s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s)", GetSQLValueString($_POST['firstName'], "text"), GetSQLValueString($_POST['lastName'], "text"), GetSQLValueString($_POST['photo'], "text"), GetSQLValueString($_POST['pastPresident'], "text"), GetSQLValueString($_POST['currentClubPosition'], "text"), GetSQLValueString($_POST['classification'], "text"), GetSQLValueString($_POST['workPosition'], "text"), GetSQLValueString($_POST['company'], "text"), GetSQLValueString($_POST['workAddress'], "text"), GetSQLValueString($_POST['workCity'], "text"), GetSQLValueString($_POST['workState'], "text"), GetSQLValueString($_POST['workZip'], "text"), GetSQLValueString($_POST['officePhone'], "text"), GetSQLValueString($_POST['fax'], "text"), GetSQLValueString($_POST['homePhone'], "text"), GetSQLValueString($_POST['cellPhone'], "text"), GetSQLValueString($_POST['email'], "text"), GetSQLValueString($_POST['website'], "text"), GetSQLValueString($_POST['homeAddress'], "text"), GetSQLValueString($_POST['homeCity'], "text"), GetSQLValueString($_POST['homeState'], "text"), GetSQLValueString($_POST['homeZip'], "text"), GetSQLValueString($_POST['birthdayMonth'], "text"), GetSQLValueString($_POST['birthdayDay'], "int"), GetSQLValueString($_POST['spouse'], "text"), GetSQLValueString($_POST['yearJoined'], "int")); mysql_select_db($database_rotarysantarosa, $rotarysantarosa); $Result1 = mysql_query($insertSQL, $rotarysantarosa) or die(mysql_error()); $insertGoTo = "members.php"; if (isset($_SERVER['QUERY_STRING'])) { $insertGoTo .= (strpos($insertGoTo, '?')) ? "&" : "?"; $insertGoTo .= $_SERVER['QUERY_STRING']; } header(sprintf("Location: %s", $insertGoTo)); } mysql_select_db($database_rotarysantarosa, $rotarysantarosa); $query_rsStates = "SELECT * FROM states ORDER BY stateName ASC"; $rsStates = mysql_query($query_rsStates, $rotarysantarosa) or die(mysql_error()); $row_rsStates = mysql_fetch_assoc($rsStates); $totalRows_rsStates = mysql_num_rows($rsStates); mysql_select_db($database_rotarysantarosa, $rotarysantarosa); $query_rsMemberInsert = "SELECT * FROM members ORDER BY lastName ASC"; $rsMemberInsert = mysql_query($query_rsMemberInsert, $rotarysantarosa) or die(mysql_error()); $row_rsMemberInsert = mysql_fetch_assoc($rsMemberInsert); $totalRows_rsMemberInsert = mysql_num_rows($rsMemberInsert); mysql_select_db($database_rotarysantarosa, $rotarysantarosa); $query_rsClubPosition = "SELECT * FROM clubpositions ORDER BY `Club Position` ASC"; $rsClubPosition = mysql_query($query_rsClubPosition, $rotarysantarosa) or die(mysql_error()); $row_rsClubPosition = mysql_fetch_assoc($rsClubPosition); $totalRows_rsClubPosition = mysql_num_rows($rsClubPosition); mysql_select_db($database_rotarysantarosa, $rotarysantarosa); $query_rsClassification = "SELECT * FROM classifications ORDER BY Classification ASC"; $rsClassification = mysql_query($query_rsClassification, $rotarysantarosa) or die(mysql_error()); $row_rsClassification = mysql_fetch_assoc($rsClassification); $totalRows_rsClassification = mysql_num_rows($rsClassification); mysql_select_db($database_rotarysantarosa, $rotarysantarosa); $query_rsBirthMonth = "SELECT * FROM birthdaymonth"; $rsBirthMonth = mysql_query($query_rsBirthMonth, $rotarysantarosa) or die(mysql_error()); $row_rsBirthMonth = mysql_fetch_assoc($rsBirthMonth); $totalRows_rsBirthMonth = mysql_num_rows($rsBirthMonth); mysql_select_db($database_rotarysantarosa, $rotarysantarosa); $query_rsBirthDay = "SELECT * FROM birthdayday ORDER BY birthdayday ASC"; $rsBirthDay = mysql_query($query_rsBirthDay, $rotarysantarosa) or die(mysql_error()); $row_rsBirthDay = mysql_fetch_assoc($rsBirthDay); $totalRows_rsBirthDay = mysql_num_rows($rsBirthDay); ?> I have a form that has a section where you can pick multiple check boxes and when the info is returned to me it has the word Array at the end of it. There are 2 check boxes on the form one fo Steve and one for Ben Below is the code I am using in my PHP file foreach($_POST['TestGroup'] as $val) { echo $val . "\n"; } The output from the PHP code is----Steve Ben Array.------ How do I keep Array from coming up? So I'm trying to create an Array from a comma separated string containing array{s}. How can I take a string full of comma separated hex values such as : <?php $myStr = ( "00ffff", "00cccc", "009999", "007777", "004444", "001111", "01ffff", "01cccc", "019999" ); ?> & turn it into 3 separated arrays like : <?php $myNewArrs = [ Array1 ( 3 ), Array2 ( 3 ), Array3 ( 3 ), ]; ?> which REALLY looks like :
<?php
$myNewArrs = [
Array ( "00ffff", "00cccc", "009999" ),
Array ( "007777", "004444", "001111" ),
Array ( "01ffff", "01cccc", "019999" ),
];
?>
? Thank you & have a great afternoon!
Edited May 27 by AquariaXI |
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