PHP - Skipping Code?!

I have a script that uploads and images, creates 2 versions of it, re-sizes the images and inserts all the info into a DB.

The odd thing is that if I don't have an image to upload, it will still run the script but it will completely skip over the description.  If I upload an image, it works fine.  Not too sure what the issue is.
Is it because my variable of $desc causing a conflict?

Here's my code:

Code: [Select]

<?php 
ini_set("display_errors",1);
include 'dbconn.php';

$change="";
$abc="";


 define ("MAX_SIZE"," 10000");
 function getExtension($str) {
         $i = strrpos($str,".");
         if (!$i) { return ""; }
         $l = strlen($str) - $i;
         $ext = substr($str,$i+1,$l);
         return $ext;
 }

 $errors=0;
  
 if($_SERVER["REQUEST_METHOD"] == "POST")
 {
  $image =$_FILES["file"]["name"];
$uploadedfile = $_FILES['file']['tmp_name'];
     
 
  if ($image) 
  {
 
  $filename = stripslashes($_FILES['file']['name']);
 
   $extension = getExtension($filename);
  $extension = strtolower($extension);


 if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif")) 
  {

  $change='<div class="msgdiv">Unknown Image extension </div> ';
  $errors=1;
  }
  else
  {

 $size=filesize($_FILES['file']['tmp_name']);


if ($size > MAX_SIZE*1024)
{
$change='<div class="msgdiv">You have exceeded the size limit!</div> ';
$errors=1;
}


if($extension=="jpg" || $extension=="jpeg" )
{
$uploadedfile = $_FILES['file']['tmp_name'];
$src = imagecreatefromjpeg($uploadedfile);

}
else if($extension=="png")
{
$uploadedfile = $_FILES['file']['tmp_name'];
$src = imagecreatefrompng($uploadedfile);

}
else 
{
$src = imagecreatefromgif($uploadedfile);
}

echo $scr;

list($width,$height)=getimagesize($uploadedfile);


$newwidth=150;
$newheight=($height/$width)*$newwidth;
$tmp=imagecreatetruecolor($newwidth,$newheight);


$newwidth1=50;
$newheight1=($height/$width)*$newwidth1;
$tmp1=imagecreatetruecolor($newwidth1,$newheight1);

imagecopyresampled($tmp,$src,0,0,0,0,$newwidth,$newheight,$width,$height);

imagecopyresampled($tmp1,$src,0,0,0,0,$newwidth1,$newheight1,$width,$height);

$famname = $_POST['famname'];
$desc =  $_POST['description'];
$petname = $_POST['petname'];
$letter = $_POST['letter'];
$filename = "images/". $_FILES['file']['name'];
$filename1 = "images/small". $_FILES['file']['name'];



imagejpeg($tmp,$filename,100);

imagejpeg($tmp1,$filename1,100);

imagedestroy($src);
imagedestroy($tmp);
imagedestroy($tmp1);
}}

}

//If no errors registred, print the success message
 if(isset($_POST['Submit']) && !$errors) 
 {
 
 $insert="insert ignore into tbl_tribue (petname,familyname,letter,description,imgpath,thumbpath) values ('$petname','$famname','$letter','$desc','$filename','$filename1')";
   mysql_query($insert);
   //mysql_query("update gallery set imgpath='$filename'");
  $change=' <div class="msgdiv">Pet Added Successfully!</div>';

print $insert;

 }
 
?>


I had turned on the error and the print to see the output.  Anyone have any ideas?  Thanks!

I have a simple foreach loop. The array has four rows in it. Really simple. I have confirmed the data in the array with var_dump. For some reason I cannot fathom, the loop is only processing rows 0 and 2 and is not processing 1 and 3.   Here's the code snippet:

<?php
    foreach ($postCals as $key=>$cal){
        var_dump($postCals, $cal, $key);
        echo '<td style="text-align:right;>' . $cal . "</td>";
    }
?>

$postCals has precisely 4 values. Here's the output from this part of the code (in terms of the var_dumps).   array (size=4)
0 => string '2.00000' (length=7)
1 => string '2.00000' (length=7)
2 => string '3.20000' (length=7)
3 => string '4.00000' (length=7)
string '2.00000' (length=7)
int 0
array (size=4)
0 => string '2.00000' (length=7)
1 => string '2.00000' (length=7)
2 => string '3.20000' (length=7)
3 => string '4.00000' (length=7)
string '3.20000' (length=7)
int 2   That's it. I two other foreach loops identical to this and they run fine!   Any ideas?   (misc info:   php: 5.4.7 running on XAMPP/Windows )

This is new. For some reason, the PHP errors are not counting my //commented lines.   Example:

<?php
//my comment
:
?>

Parse error: syntax error, unexpected ':' in D:\www\myscript.php on line 2   The error is on line 3. If I add more comments, the error is the same:

<?php
//my comment
//my comment
//my comment
//my comment
//my comment
:
?>

Parse error: syntax error, unexpected ':' in D:\www\myscript.php on line 2   Where is this setting? Thanks.

I have this code:

Code: [Select]
$data = array_combine($data4, $addfinal);

foreach( $data as $key => $value){
?>

<tr>
<td><?php echo $key;?></td><td><?php echo $value; ?></td><td></td><td>Safeco</td><td><a href="ajax/map.php?address=<?php echo urlencode($value);?>">Map It</a></td>
</tr>
<?php
}
That uses an array that looks like this (but longer):
Code: [Select]
Array ( [Business Name 1] =>
Business Address 1 [Business Name 2] =>
Business Address 2 [Business Name 3] =>
Business Address 3)
But it skips every other array entry? Any ideas? So its displaying Business Name 1, Business Name 3, etc.

My foreach loop is skipping an element?   How is this possible?

echo '<p>-- Begining of Vardump --</p>
';
var_dump($EventTotals);
echo '
<p>-- End of Vardump --</p>

<p>-- Begining of Just echo --</p>
<p>'.$EventTotals[1]['TITLE'].'</p>
<p>'.$EventTotals[2]['TITLE'].'</p>
<p>-- End of Just echo --</p>

<p>-- Begining of Foreach --</p>
';
foreach ($EventTotals as $DATA);
{

echo '<p>'.$DATA['TITLE']."</p>\n";
}
echo '<p>-- End of Foreach --</p>
'; 

Gives me this output:

<p>-- Begining of Vardump --</p>
array(2) {
  [2]=>
  array(3) {
    ["TITLE"]=>
    string(9) "Book Sale"
    ["TARGETHOURS"]=>
    string(4) "0.00"
    ["HOURS"]=>
    float(4)
  }
  [1]=>
  array(3) {
    ["TITLE"]=>
    string(15) "Spring Jogathon"
    ["TARGETHOURS"]=>
    string(5) "10.00"
    ["HOURS"]=>
    float(7)
  }
}

<p>-- End of Vardump --</p>

<p>-- Begining of Just echo --</p>
<p>Spring Jogathon</p>
<p>Book Sale</p>
<p>-- End of Just echo --</p>

<p>-- Begining of Foreach --</p>
<p>Spring Jogathon</p>
<p>-- End of Foreach --</p> 

Why does the foreach skip one of the elements of the array?  Bug or am I missing something obvious?
Edited by Firemankurt, 04 October 2014 - 04:36 PM.

We have a php application that is just a form, that takes in data to a mysql database and then displays that data in queue(php web page) for the client. It has been working for the past 5  or more years. Six weeks ago, the client noticed that the numbering started skipping a number each time a request was entered.  It then seemed to stop, now it has started again.  See attached image.

Some detail he   after user has completed web form and hits submit, three fields are populated in the mysql "REQUEST" table, then the actually data from the submitted web form is sent to the ANSWER table.  The REQUEST table is in sync and is always populated, and numbering is in sequence but upon submit, the actual data from the request does NOT always go to the ANSWER table hence the "skipping of numbers."
     
What do I even begin looking at/for to determine what happened?  Reminder: this is a 5+ year old app that worked fine until maybe 6 weeks ago.  No changes have been made to the database or the code base since 2008.  The code that adds the data to the ANSWER table [the one that appears to skip] is below.  The applicate is in php 4.3.1, mysql 5, linux server.

Hey, So what im trying to do is put my database variables into a session array. So this is what im trying to accomplish...

$_SESSION['Name_of_Row'] = $value

 This is the script I wrote:

Code: [Select]
Function setupSession(){
session_start();
$query = "SELECT * FROM users WHERE u_id ='{$this->u_id}'";
    $result = mysql_query($query);
        $row = mysql_fetch_array($result);

foreach($row as $key => $value){
    if(!empty($value)){
        $_SESSION[$key] = $value;   
            }
                }
}

When that runs I get the following warning. Can anyone tell me what this means and how to fix it?

Error: Notice: Unknown: Skipping numeric key 0 in Unknown on line 0

Hi, I have some code which displays my blog post in a foreach loop, and I want to add some social sharing code(FB like button, share on Twitter etc.), but the problem is the way I have my code now, creates 3 instances of the sharing buttons, but if you like one post, all three are liked and any thing you do affects all of the blog post. How can I fix this?


<?php
include ("includes/includes.php");

$blogPosts = GetBlogPosts();

foreach ($blogPosts as $post)
{
echo "<div class='post'>";
echo "<h2>" . $post->title . "</h2>";
echo "<p class='postnote'>" . $post->post . "</p";
echo "<span class='footer'>Posted By: " . $post->author . "</span>";
echo "<span class='footer'>Posted On: " . $post->datePosted . "</span>";
echo "<span class='footer'>Tags: " . $post->tags . "</span>";
echo '
<div class="addthis_toolbox addthis_default_style ">
<a class="addthis_button_facebook_like" fb:like:layout="button_count"></a>
<a class="addthis_button_tweet"></a>
<a class="addthis_counter addthis_pill_style"></a>
</div>
<script type="text/javascript">var addthis_config = {"data_track_clickback":true};</script>
<script type="text/javascript" src="http://s7.addthis.com/js/250/addthis_widget.js#username=webguync"></script>';

echo "</div>";
}


?>

I have the following code in html:

<html>
<head>
<script type="text/javascript">
<!--
function delayer(){
    window.location = "http://VARIABLEVALUE.mysite.com"
}
//-->
</script>
<title>Redirecting ...</title>
</head>
<body onLoad="setTimeout('delayer()', 1000)">



<script type="text/javascript">
var sc_project=71304545;
var sc_invisible=1;
var sc_security="9c433fretre";
</script>

<script type="text/javascript"
src="http://www.statcounter.com/counter/counter.js"></script><noscript>
<div
class="statcounter"><a title="vBulletin statistics"
href="http://statcounter.com/vbulletin/"
target="_blank"><img class="statcounter"
src="http://c.statcounter.com/71304545/0/9c433fretre/1/"
alt="vBulletin statistics" ></a></div></noscript>


</body>
</html>

Is a basic html webpage with a timer redirect script and a stascounter code.

I know a bit about html and javascript, but almost nothing about php.

My question is:

How a can convert this html code into a php file, in order to send a variable value using GET Method and display this variable value inside the javascript code where says VARIABLEVALUE.

Thanks in adavance for your help.

Advance thank you.

Can you help please.

The error.....

Warning: mysql_fetch_assoc() expects parameter 1 to be resource, string given in C:\wamp\www\test_dabase.php on line 24

code.
Code: [Select]
<?php

//database connection.
$DB = mysql_connect("localhost","root") or die(mysql_error());

if($DB){

//database name.
$DB_NAME="mysql";

//select database and name.
$CON=mysql_select_db($DB_NAME,$DB)or die(mysql_error()."\nPlease change database name");


// if connection.
}if($CON){
    
    //show tables.
  $mysql_show="SHOW TABLES";
    
    //select show and show.
      $mysql_select2="mysql_query(".$mysql_show.") or die(mysql_error())";
    
    }
    
    //if allowed to show.
    if($mysql_select2){
        
        //while it and
    while($data=mysql_fetch_assoc($mysql_select2)){
        
        //show it.
        echo $data;
        
        }
    }    
    ?>

Hi, I need to insert some code into my current form code which will check to see if a username exist and if so will display an echo message. If it does not exist will post the form (assuming everything else is filled in correctly). I have tried some code in a few places but it doesn't work correctly as I get the username message exist no matter what. I think I am inserting the code into the wrong area, so need assistance as to how to incorporate the username check code.

$sql="select * from Profile where username = '$username';
$result = mysql_query( $sql, $conn )
      or die( "ERR: SQL 1" );
if(mysql_num_rows($result)!=0)
{
process form
}
else
{
echo "That username already exist!";
}


the current code of the form


<?PHP
//session_start();
require_once "formvalidator.php";
$show_form=true;

if (!isset($_POST['Submit'])) {



$human_number1 = rand(1, 12);



$human_number2 = rand(1, 38);



$human_answer = $human_number1 + $human_number2;



$_SESSION['check_answer'] = $human_answer;
}

if(isset($_POST['Submit']))
{





if (!isset($_SESSION['check_answer'])) {
echo "<p>Error: Answer session not set</p>";
}


if($_POST['math'] != $_SESSION['check_answer']) {
echo "<p>You did not pass the human check.</p>";
exit();
}


   $validator = new FormValidator();
    $validator->addValidation("FirstName","req","Please fill in FirstName");







$validator->addValidation("LastName","req","Please fill in LastName");
$validator->addValidation("UserName","req","Please fill in UserName");
$validator->addValidation("Password","req","Please fill in a Password");
$validator->addValidation("Password2","req","Please re-enter your password");
$validator->addValidation("Password2","eqelmnt=Password","Your passwords do not match!");
$validator->addValidation("email","email","The input for Email should be a valid email value");
$validator->addValidation("email","req","Please fill in Email");
$validator->addValidation("Zip","req","Please fill in your Zip Code");
$validator->addValidation("Security","req","Please fill in your Security Question");
$validator->addValidation("Security2","req","Please fill in your Security Answer");
    if($validator->ValidateForm())
    {
        $con = mysql_connect("localhost","uname","pw") or die('Could not connect: ' . mysql_error());
        mysql_select_db("beatthis_beatthis") or die(mysql_error());
$FirstName=mysql_real_escape_string($_POST['FirstName']); //This value has to be the same as in the HTML form file
$LastName=mysql_real_escape_string($_POST['LastName']); //This value has to be the same as in the HTML form file
$UserName=mysql_real_escape_string($_POST['UserName']); //This value has to be the same as in the HTML form file
$Password= md5($_POST['Password']); //This value has to be the same as in the HTML form file
$Password2= md5($_POST['Password2']); //This value has to be the same as in the HTML form file
$email=mysql_real_escape_string($_POST['email']); //This value has to be the same as in the HTML form file
$Zip=mysql_real_escape_string($_POST['Zip']); //This value has to be the same as in the HTML form file
$Birthday=mysql_real_escape_string($_POST['Birthday']); //This value has to be the same as in the HTML form file
$Security=mysql_real_escape_string($_POST['Security']); //This value has to be the same as in the HTML form file
$Security2=mysql_real_escape_string($_POST['Security2']); //This value has to be the same as in the HTML form file



$sql="INSERT INTO Profile (`FirstName`,`LastName`,`Username`,`Password`,`Password2`,`email`,`Zip`,`Birthday`,`Security`,`Security2`) VALUES ('$FirstName','$LastName','$UserName','$Password','$Password2','$email','$Zip','$Birthday','$Security','$Security2')"; 
//echo $sql;
if (!mysql_query($sql,$con)) {

 die('Error: ' . mysql_error());

} else{



mail('email@gmail.com','A profile has been submitted!',$FirstName.' has submitted their profile',$body);

echo "<h3>Your profile information has been submitted successfully.</h3>";
}

mysql_close($con);
        $show_form=false;
    }
    else
    {
        echo "<h3 class='ErrorTitle'>Validation Errors:</h3>";

        $error_hash = $validator->GetErrors();
        foreach($error_hash as $inpname => $inp_err)
        {
            echo "<p class='errors'>$inpname : $inp_err</p>\n";
        }        
    }
}

if(true == $show_form)
{
?>

hey gurus, i am a newbie php coder.. i am learning by example.

what i am trying to do is write a piece of code which will alter 3 tables (user, bonus_credit, bonus_credit_usage)

----------------------------------------------------------------
the table structure that will be used is as follows:

user.bonus_credit
user.ID

bonus_credit.bonusCode
bonus_credit.qty
bonus_credit.value

bonus_credit_usage.bonusCode
bonus_credit_usage.usedBy

----------------------------------------------------------------
so lets say, in bonus_credit i have the following
bonusCode = 'facebook' (this is the code they have to type to redeem the bonus
qty = '10' ( number of times the bonusCode can be redeemed, but same person can't redeem it more than once)
value = '5' (this is the  amount of bonus_credit for each qty)

Now, I need to write a code that check to see if the code has been redeemed in the bonus_credit_usage table and if the user.ID exists in this table as bonus_code_usage.usedBy, then give an error that its already been used and if it hasn't been used, then subtract 1 from qty, add ID to usedBy and then add the value to the bonus_credit

-----------------------
i have started the steps just to create a simple textbox and entering a numeric value to bonus_credit, and that works.. but now i have to use JOIN and IF and ELSE.. which is a little too advanced for me.. so i'd appreciate a guide as i write the code.

if(isset($_REQUEST['btnBonus']))

{

$bonus_credit = addslashes($_REQUEST['bonusCode']);

$query = "update user set bonus_credit=bonus_credit+'".$bonus_credit."' where id='".$_SESSION['SESS_USERID']."'";

echo "<script>window.location='myreferrals.php?msgs=2';</script>";

mysql_query($query) or die(mysql_error());

}

Can you help me integrate this code :

<form method="post" action="submit.php">
<input type="checkbox" class="required" /> Click to check
<br />
<input disabled="disabled" type='submit' id="submitBtn" value="Submit">
</form>

In to this Contact Form code, please?

<form action="../page.php?page=1" method="post" name="contact_us" onSubmit="return capCheck(this);">
<table cellpadding="5" width="100%">
<tr>
<td width="10" class="required_field">*</td>
<td width="80">Your Name</td>
<td><input type="text" name="name" maxlength="40" style="width:400px;/></td>
</tr>
<tr>
<td class="required_field">*</td>
<td>Email Address</td>
<td><input type="text" name="email" maxlength="40" style="width:400px;/></td>
</tr>
<tr>
<td></td>
<td>Comments:</td>
<td><textarea name="comments" style="width: 400px; height: 250px;"></textarea></td>
</tr>
</table>
</form

I use this type of a code to send automatic emails from my website:

Code: [Select]
$headers = ;
$headers .= ;
$to = ;

Click here to go to Google.

", $headers);

I am having hard time figuring out how to do hyperlink on words (like here). If I do something like this:

Code: [Select]
<a href='http://www.google.com'>here</a>
it spits out that exact thing out.

Thanks you for your input

Can I combine also HTML code in PHP function?
For example, can a PHP function include HTML form and the PHP code to handle this form?

If yes, this will make my main code much more smaller and readable.

If not, is there a way to define an "external macro" like, which allow me to replace pre-defined lines of code with short alias?