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PHP - Select Date Fields In The Future But Remove Those That Have Past
My query is a fixtures list for my local sports team- There seems little point including fixtures from the past as they are in a results query anyway.
I'm ordering by date (see below) but how can I remove the ones already past? $query = "SELECT * FROM fix10 ORDER BY Date"; TIA Nick Similar TutorialsI have a calendar select date function for my form that returns the date in the calendar format for USA: 02/16/2012. I need to have this appear as is for the form and in the db for the 'record_date' column, but I need to format this date in mysql DATE format (2012-02-16) and submit it at the same time with another column name 'new_date' in the database in a hidden input field. Is there a way to do this possibly with a temporary table or something? Any ideas would be welcome. Doug Hi i have this drop down list current the year is 2010 and downwards but i want to change the list to 2010 upwards u can notice on the 50-- so shows current year minus so current is 2010 to 61 how can i change 2010 to 2030 or sunfin?? echo '<select name="year_of_birth">',"\n"; $year = date("Y"); for ($i = $year;$i > $year-50;$i--) { if($i == $thisYear) { $s = ' selected'; } else { $s=''; } echo '<option value="' ,$i, '"',$s,'>' ,$i, '</option>',"\n"; } echo '</select>',"\n"; Hi, I'm looking for a code to view the date of the past weekdays. Forexample, if it's thursday, I want it to view the dates for wednesday, tuesday, monday, Friday before. Thank you in advance. Hi, I am using this function to output a list of dates for every friday over the next 12months. This is working fine. Code: [Select] [php] //function function nextWeeksDay($date_begin,$nbrweek) { $nextweek=array(); for($i = 1; $i <= $nbrweek; $i++) { // 52 week in one year of course $nextweek[$i]=date('Y-m-d', strtotime('+'.$i.' week',$date_begin)); } return $nextweek; } /// end function /// example of a select date // var $date_begin=strtotime('this Friday'); $nbrweek=52; // call function $result=nextWeeksDay($date_begin,$nbrweek); // Insert //$date1=date('Y-m-d', $date_begin); for($i = 1; $i <= $nbrweek; $i++) { //$date=$result[$i]; echo $result[$i]."<br/>"; } [/php] My problem is that when I alter the code to try and get the date for every second Friday for the next year the script freezes. Code: [Select] [php] //function function nextWeeksDay($date_begin,$nbrweek) { $nextweek=array(); for($i = 2; $i <= $nbrweek; $i+2) { // 52 week in one year of course $nextweek[$i]=date('Y-m-d', strtotime('+'.$i.' week',$date_begin)); } return $nextweek; } /// end function /// example of a select date // var $date_begin=strtotime('this Friday'); $nbrweek=52; // call function $result=nextWeeksDay($date_begin,$nbrweek); // Insert //$date1=date('Y-m-d', $date_begin); for($i = 2; $i <= $nbrweek; $i+2) { //$date=$result[$i]; echo $result[$i]."<br/>"; } [/php] I really don't understand why?? Does anyone know why? Thanks Hi, I want to calculate the future month, i have used following code to calculate the date $date = date('Y-m-d',strtotime(date("Y-m-d", strtotime('2010-01-31')) . " +3 month")); It gives me 2010-03-03 But i need to get 2010-02-28 OR just month is enough like 2010-02 Thank you Nikhil I was wondering if there was a way to have the MAX function NOT return a Date that is more than 2 days into the future (from the current day)? If there is a Date that is more than 2 days into the future I would like to return the one closest to the current day. Here is the code I have: Code: [Select] <?php mysql_connect("local", "xxx", "xxx") or die(mysql_error()); mysql_select_db("pricelink") or die(mysql_error()); // Get a specific result from the "ft9_fuel_tax_price_lines" table $query ="SELECT ItemNumber,TableCode,Cost, MAX(`Date`) as `max_date`, MAX(`Time`) as 'max_time' FROM `ft9_fuel_tax_price_lines` GROUP BY `ItemNumber`,`TableCode`"; $result = mysql_query($query) or die(mysql_error()); echo "<table border='1'>"; echo "<tr> <th>ItemNumber</th> <th>TableCode</th> <th>Date</th> <th>Time</th> <th>Cost</th> </tr>"; // keeps getting the next row until there are no more to get while($row=mysql_fetch_array($result)) { // Print out the contents of each row into a table echo "<tr><td>"; echo $row['ItemNumber']; echo "</td><td>"; echo $row['TableCode']; echo "</td><td>"; echo $row['max_date']; echo "</td><td>"; echo $row['max_time']; echo "</td><td>"; echo $row['Cost']; echo "</td></tr>"; } echo "</table>"; ?> Any help would be appreciated. Thanks! Hi, I am trying to get the number of days between the current date and a date in the future specified by column 'end_date'. The code I have seems to be working but it displays the number of days as a negative number, how do I change this to be a positive number? I have tried simply changing $days = $now - $end_date; to $days = $end_date - $now; but that doesn't work as I thought it would! Thanks in advance.. Code: [Select] $now = time(); $end_date = strtotime($row['end_date']); $days = $now - $end_date; echo floor($days/(60*60*24)); I want to set a never expire date, so I figured I would set the date 99 years into the future. No dice. After trial and error, it appears you can only make it 25 years into futu date("Y-m-d",strtotime("+25 years")); I wonder if it is the absolute date, or the number 25. If it is the maximum date (i.e. nothing after 2035) then I will have a problem with this code next year! Hey guys,
Thank you in advance... here is my situation, I have a form with three (3) fields in it, the 'student name' is unlimited textfield with an "add more" button to it and I have two select fields ('number of shirts' and 'trophies') that depend on the number of entries for 'student name'...
I want to create the select fields based on this math, for as many 'student name' entries:
1- i want to have the select form for 'number of shirts' to be 0 up to that number... so if there are 6 'student name' entries, the select options will be 0,1,3,4,5,6,7
2- I want to have the select form for 'trophies' to be 5 'student name' entries to 1 'trophies', for example if there are 6 'student name' entries, the select options will be 0,1... if there are 13 entries, options will be 0,1,2... So if there are less than 5 'student name' entries, the select field will not show (hidden)
of course if there are no 'student name' entries, these two fields won't show up (hidden)
let me know if that make sense and ANY help or directions will be GREATLY APPRECIATED.
Thanks guys!
Hi, This one has been driving me up the wall, so hopefully some kind person can help me. I'm trying to make a validation script. $creststartdate comes in from a form as a UK formatted date (d/m/Y), and if $creststartdate is more than a month ahead of today, then it gets rejected. here's the code I have now... Code: [Select] $today = date("m/d/y"); $onemonth = strtotime ('+1 month', strtotime($today)); $nextmonth = date ('d/m/Y', $onemonth); $csd = date("m/d/y", $creststartdate); $strcsd = strtotime($csd); $newdate = date ('d/m/Y', $strcsd); if ($newdate > $nextmonth) { $creststartdatefailed = "The Crest Start Date cannot be more than 1 month in the future."; $creststartdatevalid = "NO"; } As it stands, this version of the code means that nothing is getting rejected. Please help?? Cheers Hi guys I hav a form where a user selects an end time and the date will be 4 days from today. I have been able to get the date to populate, but I am trying to join the two fields together but with no luck. I have the end date caluclated using the code below and this works Code: [Select] $end_date=date("Y-m-d",$dateplus4); The end time is selected from a menu where the user selects either 12 or 17 (12:00:00 or 17:00:00) I have tried Code: [Select] $end_date_time=$end_date." ".$end_time; I have also tried strtotime and mktime, but obviuosly not doing it properly. Any help would be great. Hello
I'm using a small script (that I found online) to dynamically add fields to an order form.
It works well with normal text fields but I would like to use it with a select box fields (as it draws data from MySQL).
My problem is, that when the field is 'cloned' it contains the product id and not the product name - which is what the user needs to see.
<?php
echo '<form method="post" name="orderform">';
// lots of form fields...
echo '<div id="itemRows">';
echo 'Item quantity: <input type="text" name="add_qty" size="4" />';
$prod = "SELECT prod_id, product FROM products ORDER BY product ASC";
$prodRes = $mysqli->query($prod);
echo 'Item name : <select name="add_name">';
while ($p = $prodRes->fetch_assoc()) {
echo'<option value="'.$p['prod_id'].'">'.$p['product'].'</option>';
}
echo '</select>';
echo '<input onclick="addRow(this.form);" type="button" value="Add row" /> (Won't be saved until you click on "Add row")';
if(isset($product['qty']) && isset($product['name'])) {
?>
<p id="oldRow<?=$product['id']?>">
Item quantity: <input type="text" name="qty<?=$product['id']?>" size="4" value="<?=$product['qty']?>" />
Item name: <input type="text" name="name<?=$product['id']?>" value="<?=$product['add_name']?>" />
<input type="checkbox" name="delete_ids[]" value="<?=$product['id']?>"> Mark to delete
</p>
</div>
<?php
}
?>
</div>
<input type="submit" value="Submit new order" name="addOrder">
</fieldset>
</div>
</form>
<script type="text/javascript">
var rowNum = 0;
function addRow(frm) {
rowNum ++;
var row = '<p id="rowNum'+rowNum+'">Item quantity: <input type="text" name="qty[]" size="4" value="'+frm.add_qty.value+'"> Item name: <input type="text" name="name[]" value="'+frm.add_name.value+'"> <input type="button" value="Remove" onclick="removeRow('+rowNum+');"></p>';
jQuery('#itemRows').append(row);
frm.add_qty.value = '';
frm.add_name.value = '';
}
function removeRow(rnum) {
jQuery('#rowNum'+rnum).remove();
}
</script>
I know I could use the $p['product'] value in the select box field, but when it is submiitted - it loses its $p['prod_id'] value which I need to input back into the MySQL database.
I did try
echo'<option value="'.$p['prod_id'].':'.$p['product'].'">'.$p['product'].'</option>';and then explode...
foreach($_POST['name'] as $key => $value) {
$items[] = current(explode(":", $value));
}
...but clearly, that is a dreradful solution and looks awful to the user.
Any thoughts, please?
Thank you.
Edited by tHud, 14 July 2014 - 09:31 AM. Hi i would like to submit the following code to my database as a mutiple selection box. when i submit i just get the last selected value for example if i hold ctrl and press 1 2 3 4 i am only receiving 4 on my database. any ideas? thanks in advance for any help! Code: [Select] Hours Of Availability:<br> <select name="availability" multiple="multiple" size="9"> <option value="Monday - Period 1">Monday - Period 1</option> <option value="Monday - Period 2">Monday - Period 2</option> <option value="Monday - Period 3">Monday - Period 3</option> <option value="Monday - Period 4">Monday - Period 4</option> <option value="Monday - Period 5">Monday - Period 5</option> <option value="Monday - Period 6">Monday - Period 6</option> <option value="Monday - Period 7">Monday - Period 7</option> <option value="Monday - Period 8">Monday - Period 8</option> <option value="Monday - Period 9">Monday - Period 9</option> </select> <select name="availability" multiple="multiple" size="9"> <option value="Tuesday - Period 1">Tuesday - Period 1</option> <option value="Tuesday - Period 2">Tuesday - Period 2</option> <option value="Tuesday - Period 3">Tuesday - Period 3</option> <option value="Tuesday - Period 4">Tuesday - Period 4</option> <option value="Tuesday - Period 5">Tuesday - Period 5</option> <option value="Tuesday - Period 6">Tuesday - Period 6</option> <option value="Tuesday - Period 7">Tuesday - Period 7</option> <option value="Tuesday - Period 8">Tuesday - Period 8</option> <option value="Tuesday - Period 9">Tuesday - Period 9</option> </select> <select name="availability" multiple="multiple" size="9"> <option value="Wednesday - Period 1">Wednesday - Period 1</option> <option value="Wednesday - Period 2">Wednesday - Period 2</option> <option value="Wednesday - Period 3">Wednesday - Period 3</option> <option value="Wednesday - Period 4">Wednesday - Period 4</option> <option value="Wednesday - Period 5">Wednesday - Period 5</option> <option value="Wednesday - Period 6">Wednesday - Period 6</option> <option value="Wednesday - Period 7">Wednesday - Period 7</option> <option value="Wednesday - Period 8">Wednesday - Period 8</option> <option value="Wednesday - Period 9">Wednesday - Period 9</option> </select> <select name="availability" multiple="multiple" size="9"> <option value="Thursday - Period 1">Thursday - Period 1</option> <option value="Thursday - Period 2">Thursday - Period 2</option> <option value="Thursday - Period 3">Thursday - Period 3</option> <option value="Thursday - Period 4">Thursday - Period 4</option> <option value="Thursday - Period 5">Thursday - Period 5</option> <option value="Thursday - Period 6">Thursday - Period 6</option> <option value="Thursday - Period 7">Thursday - Period 7</option> <option value="Thursday - Period 8">Thursday - Period 8</option> <option value="Thursday - Period 9">Thursday - Period 9</option> </select> <select name="availability" multiple="multiple" size="9"> <option value="Friday - Period 1">Friday - Period 1</option> <option value="Friday - Period 2">Friday - Period 2</option> <option value="Friday - Period 3">Friday - Period 3</option> <option value="Friday - Period 4">Friday - Period 4</option> <option value="Friday - Period 5">Friday - Period 5</option> <option value="Friday - Period 6">Friday - Period 6</option> <option value="Friday - Period 7">Friday - Period 7</option> <option value="Friday - Period 8">Friday - Period 8</option> <option value="Friday - Period 9">Friday - Period 9</option> </select> <select name="availability" multiple="multiple" size="9"> <option value="Saturday - Period 1">Saturday - Period 1</option> <option value="Saturday - Period 2">Saturday - Period 2</option> <option value="Saturday - Period 3">Saturday - Period 3</option> <option value="Saturday - Period 4">Saturday - Period 4</option> <option value="Saturday - Period 5">Saturday - Period 5</option> <option value="Saturday - Period 6">Saturday - Period 6</option> <option value="Saturday - Period 7">Saturday - Period 7</option> <option value="Saturday - Period 8">Saturday - Period 8</option> <option value="Saturday - Period 9">Saturday - Period 9</option> </select> <br>Press + Hold Ctrl For Multiple</p> I'm looking for a way to have 5 different select menus. Each one pre-php-populated with the same data to begin with. Lets say numbers 1 through 5.
If user selects #2 in any of the lists, all the other lists #2 will dissapear from. With ultimately only one unique selection in each list (1 through 5).
Like having a list of 5 things to do and a select list next to each one to select the priority in which it gets done.
Is there a way to do this with ajax?
Hi there, wanted to see how I would have the columns I specified in
$fields = array('id','type');
then be generated dynamically in the while loop and any other field I state in
$fields = array('id','type');
then its added to the while loop in the below
include('db.php');
class SelectData{
public function wpquery_select($conn,$sql,$fields){
$results = $conn->query($sql);
if($results->num_rows > 0){
while($row = $results->fetch_assoc()){
// How would you process the array $fields which holds all the rows specified and dynamically create echo $row['id'], $row['id'] and so on?
}
}
$conn->close();
}
}
$select = new SelectData();
$sql = "SELECT * FROM orders";
$fields = array('id','type');
$select->wpquery_select($conn,$sql,$fields);
Thank you So this is a simple code that finds out the difference between two dates and displays it in number of days.
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
// RESULT
+272 days
My first question. Is it possible to remove the + sign in the result above? Second question. Is it possible to show "months" if it's greater than 30 days? And years if the days are greater than 365? How would I do this? I have got a date field in my mysql database with events, and as you know date in MYSQL uses yyyy/mm/dd but I would first like to turn this around to dd/mm/yyyy but also turn this into for example "Tuesday - May 1990" would anyone like to point me into the right direction? Much appreciated! I have the following html code and php code. I would like clients to select which fields in the mysql database they would like to have appear in the resultant table by checking the text box next to the field in the html form. For instance they should be able to select first name and city and have only those columns appear in the resultant table. # <html> # <head> # <title>Search Clients Database</title> # </head> # # <body> # <h1>Clients Database Search Page</h1> # <form action="searchclients.php" method="post"> # <table width="100%" border="1" cellspacing="1" cellpadding="1"> # <tr> # <th width="37" scope="col"> </th> # <th width="114" scope="col">Fields</th> # <th width="169" scope="col">Filter Value</th> # <th width="1157" scope="col"> </th> # </tr> # <tr> # <td><input type="checkbox" name="idc" id="idc"></td> # <td>ID</td> # <td><input type="text" name="ID" id="ID"></td> # <td> </td> # </tr> # <tr> # <td><label> # <input type="checkbox" name="fnc" id="fnc"> # </label></td> # <td>First Name</td> # <td><input type="text" name="FirstName" id="FirstName"></td> # <td> </td> # </tr> # <tr> # <td><label> # <input type="checkbox" name="lnc" id="lnc"> # </label></td> # <td>Last Name</td> # <td><input type="text" name="LastName" id="LastName"></td> # <td> </td> # </tr> # <tr> # <td><label> # <input type="checkbox" name="cc" id="cc"> # </label></td> # <td>City</td> # <td><input type="text" name="City" id="City"></td> # <td> </td> # </tr> # <tr> # <td><label> # <input type="checkbox" name="pc" id="pc"> # </label></td> # <td>Province</td> # <td><select name="Province" id="Province"> # <option selected> </option> # <option>KZN</option> # <option>North West Province</option> # <option>Gauteng</option> # <option>Free State</option> # <option>Mpumalanga</option> # <option>Eastern Cape</option> # <option>Limpopo Province</option> # <option>Northern Cape</option> # <option>Western Cape</option> # </select></td> # <td> </td> # </tr> # </table> # <p> # <input type="submit" name="submit" value="Search" /> # </p> # </form> # # </body> # </html> # <?php # mysql_connect ("localhost", "username","password") or die (mysql_error()); # mysql_select_db ("clients"); # # $fn = $_POST['FirstName']; # $ln = $_POST['LastName']; # $city = $_POST['City']; # $prov = $_POST['Province']; # # $idc = $_POST['idc']; # $fnc = $_POST['fnc']; # $lnc = $_POST['lnc']; # $cc = $_POST['cc']; # $pc = $_POST['pc']; # # ?> # # <html> # <body> # # <table border=1> # <tr> # <th>ID</th> # <th>First Name</th> # <th>Last Name</th> # <th>City</th> # <th>Province</th> # </tr> # # <?php # $sql = mysql_query("select ID, FirstName, LastName, City, Province from clients where FirstName like '%$fn%' and LastName like '%$ln%' and City like '%$city%' and Province like '%$prov%'"); # # while ($row = mysql_fetch_array($sql)){ # # $id = $row['ID']; # $fname = $row['FirstName']; # $lname = $row['LastName']; # $city = $row['City']; # $prov = $row['Province']; # # ?> # # <tr> # <th><?php echo $id;?></th> # <th><?php echo $fname;?></th> # <th><?php echo $lname;?></th> # <th><?php echo $city;?></th> # <th><?php echo $prov;?></th> # </tr> # # <?php } //this ends the if?> # # </table> # </html> This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=349563.0 Hey all, Im currently working on a site which I save a cookie on users computer for 1 month as well a row in a table with the 1 month expiring date plus cookie id. What I would like to know is if theres a way to make the server check the table every day at say 12pm to see if any corresponding user cookies in each row have expired on that day as to remove them from the table to match the expiring cookie on the users computer? I would like not to have to rely on a user/admin accessing in to make a script run instead have something thats timed to go off automatically instead? Is there anyway of doing this? Thanks! |
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