PHP - Loop | Echo Text File Line

This is a section of my code that goes and gets videos from any video site. What I’m having issues with is having it post a random title, that are all in a text file called titles.txt. What I’m wanting to accomplish is have my script go pull the video embed code, the duration, the tags, etc. Which all works fine until I get to the title part where it pulls locally from the server from the text file. I'm not an advance programmer so not sure if I am even approaching this correct way. Here is the code I have that is responsible for putting the title in. I appreciate your help.

$video = array(
‘user_id’ => $this->user_id,
‘status’ => $this->status,
‘site’ => ‘my site’,
‘id’ => ‘’,
‘embeddable’ => true,
‘url’ => ‘’,
‘titles’ => ‘’,
‘title’ => ‘’,
‘description’ => ‘’,
‘tags’ => ‘’,
‘category’ => ‘’,
‘thumbs’ => array(),
‘duration’ => 0,
‘embed’ => ‘’
);

function random_title ()
{
$titles = file (“titles.txt”, FILE_IGNORE_NEW_LINES);
$num = rand (0, intval (count ($titles) / 3)) * 3;
return ucwords($titles[$num]);
}

//Title
if(preg_match(’/title="(.*?)"/’, $match, $matches_title)) {
$video[‘title’] = random_title(). ’ - My site name’;
} else {
$this->errors[] = ‘Failed to get video title for ‘.$video[‘url’].’!’;
if (!$this->debug) continue;
else $debug_e[] = ‘TITLE’;
}

 

I'm ok with PHP but probably not half as good as some of you guys on here.

I am basically trying to find a way to grab a line from a huge and I mean huge text file.... its basically a list of keywords I want to call by line number but without preferably going through them all before I get to that line.....otherwise couldmcrash my server obviously.

At the moment im using this

Code: [Select]
$lines = file('http://www.mysite.com/keywords.txt');

// Loop through our array, show HTML source as HTML source; and line numbers too.
foreach ($lines as $line_num => $line) {
echo "$line_num";
}
This works but im sure theres gotta be a better way of doing to save on usuage because this is putting the whole file into the memory and if I can simply say to php give me line number 97, would umm RULE....

Hope you guys can come up with a solution as your much smarter than me ty

I have a PHP file that is executed via batch file very frequently for live updating. This is a sort of "sync" file for reading/writing to a MySQL database. I am able to get it functioning absolutely fine when executed manually via a web browser (and my echo debug lines output the expected information), yet when I run the same PHP file via the command line, it seems to just not be capable of opening any file for reading, so the equivalent variables that are correct when executed on a web browser are blank when echoed through the command line.

Is there a different way of handling reading of files when running a php script via the command line, or should it function exactly the same as when run via a browser?

For instance:

$k = "0";
$line = file("examplefile.log")[$k];
echo $line;

How to get this echo line to display as one line?
No matter what I have done it displays as two lines.  I even tried <nobr></nobr>

Teachers Name:
John Jones

$userid = mysql_real_escape_string($_GET['user_id']);
$sql = "select * from users where `id`='$userid' ";

$rs = mysql_query($sql);
while($row = mysql_fetch_array($rs))
{ 
echo  "<h3>Teachers Name: </h3>" . $row["first_name"] . " " . $row["last_name"]  ;  }


Thanks for your help.

Hi   I try to echo out random lines of a html file and want after submit password to whole content of the same html file. I have two Problems. 1st Problem When I echo out the random lines of the html file I don't get just the text but the code of the html file as well. I don't want that. I just want the text. How to do that?

for($x = 1;$x<=40;$x++) {
		$lines = file("$filename.html");
        echo $lines[rand(0, count($lines)-1)]."<br>";
        }

I tried instead of "file("$filename.html");" "readfile("$filename.html");" But then I get the random lines plus the whole content. Is there anything else I can use instead of file so that I get the random lines of text  without the html code?P.S file_get_contents doesn't work either have tried that one.     2nd Problem:   As you could see in my first problem I have a file called $filename.html. After I submit the value of a password I want the whole content. But it is like the program did forget what $filename.html is. How can I make the program remember what $filename.html is? Or with other words how to get the whole content of the html file?   My code:

if($_POST['submitPasswordIT']){
if ($_POST['passIT']== $password ){
$my_file = file_get_contents("$filename.html");
echo $my_file;
}
else{
echo "You entered wrong password";
}
}

If the password isn't correct I get: You entered wrong password. If the password is correct I get nothing. I probably need to create a path to the file "$filename.html", but I don't know exactly how to do that.   

Hi, here the bit of code:

Code: [Select]
echo 'You\'ll be redirected in'; include('script.html'); echo 'secs. If not, click <a href="visit.php">here</a></div>.';
this is being displayed on 3 lines I want to have it all on 1 line, how is this done?
(script.html is a javascript countdown clock)

thanks

hello guys, suppose I want to echo out the text given below exactly as what has been set against, including the line breaks. How do I do it? coz each time i did it so, there s no line breaks but the output is usually a dense lump of words with no paragraphs.
Code: [Select]
I took her out it was a Friday night
I wore cologne to get the feeling right
We started making out and she took off my pants
But then I turned on the TV

And that's about the time she walked away from me
Nobody likes you when you're 23
I'm still more amused by TV shows
What the hell is ADD?
My friends say I should act my age
What's my age again?
What's my age again?
please help


P.S.
The whole set of phrase give above are treated as a single variable coz I use a WHILE loops when making an echo.
tthanks

How can i simply put the input box at the end of echo $page_pagination;
instead of dropping down to a new line.
Code: [Select]



echo $page_pagination;

echo '<FORM NAME="Library Search" ACTION="z3950get.php" METHOD="POST">';
echo '&nbsp&nbsp&nbsp&nbsp Or go to page number ';
echo '<input type="text"SIZE="5" name="pageinput2" value="'. $page_num.'">';
echo '<input type="hidden" name="recordcount" value="'.$recordcount.'"/>';
echo '<button type="submit" name="pageinput1" value="search">Search</button>';
echo '</FORM>';

echo '<BR><BR>';
echo 'Showing Page Number -> '.$page_num. ' | Total number of results -> '.$numrows . ' | Total number of pages -> '.$numofpages.'<BR><BR>';

<td><label for='images'> <b>File to upload:</b> </label></td>
            <td><input type='file'  name = 'drama_image' '<?php echo $row['drama_image']; ?>'/></
                       </tr>
         
   <?php
            $target_path = "images/";
            $target_path = $target_path . basename( $_FILES['images']['name']);

            if(move_uploaded_file($_FILES['images']['tmp_name'], $target_path)) {
                echo "The file ".  basename( $_FILES['images']['name']).
             " has been uploaded";
            } else{
                echo $row['drama_image'];
            }
         
     ?>

['drama_image'] is the name of the file

I wanna echo it out in the box of file upload so when I save , the default picture will still be there instead of being overwritten as the box does not have any value in it.

Currently whether data from the queries are found or not, its surrounded inside the div tags...

i want to somehow echo the div tags inside the while loop, but only echo once.

the confusing part for me is that the queries are connecting to 2 different tables for data.. and both need to be found for the div to be echo.
 
if($item['quantity'] >= 1){   
if($item2['type'] == 'weapon'){


code below....


Code: [Select]

<div class="g_content"><h3 style="text-align: left">&nbsp;&nbsp;Weapons</h3><div class="g_text">
<table align='center' cellspacing='10'>
<?php

$current_col = 1;
$max_col = 4;


$query = $db->execute("select * from items where `player_id`=?", array($player->id));

while($item = $query->fetchrow())
{
$query2 = $db->execute("select * from `blueprint_items` where `id`=?",array($item['item_id']));
$item2 = $query2->fetchrow();


//DISPLAY IF QUANTITY IS 1 OR MORE.
if($item['quantity'] >= 1){
if($item2['type'] == 'weapon'){
    //Open new row if first column
    if($current_col==1)
    {
        echo "<tr>\n";
    }

    //Display current record

    echo "<td width='25%'>";
echo "<center><img src=\"{$item2['img']}\" width='80' height='80' style=\"border: 1px solid #CC9900\"></center>";
    echo "<center><a href=\"../description.php?id={$item2['id']}\">{$item2['name']}</a> [x".$english_format_number = number_format($item['quantity'])."]</center>";
    echo "<center>$".$english_format_number = number_format($item2['value'])."</center>";
echo "<center>[<a href='../item.php?sell=".$item['id']."'>Sell</a>] [<a href='../item.php?market=".$item['id']."'>Market</a>] <br>[<a href='../item.php?send=".$item['id']."'>Send</a>] [<a href='../item.php?equip=".$item['id']."'>Equip</a>]</center><br>";
    echo "</td>\n";
 //Close row if last column
    if($current_col==$max_col)
    {
        echo "<tr>\n";
        $current_col = 0;  //<---Changed
    }
    $current_col++;
}
}

}
//Close last row if needed
if ($current_col!=1)
{
    for(; $current_col<=$max_col; $current_col++)
    {
        echo "<td>&nbsp;</td>\n";
    }
}

?>
</table>
</div></div>

Hi,

I am pretty much a new newbie when it comes to PHP, and have a problem that I need to solve, for a website that has to go live tomorrow.

Basically I have been using a javascript upload script called 'uploadify' which had an option for the upload folder which was added to the script in the form:

Code: [Select]
'folder'    : '/songs/<?php echo $_SESSION["name"];?>',
I added the php echo to return the username from a PHP login, so it gets added to the path to the upload folder (each user has their own subfolder for uploading to).

With the new version of the uploadify script, the folder option has been moved to a separate PHP file where it is now in the form:

Code: [Select]
$targetFolder = '/songs/';
I need to find a way of adding the username variable to this line.  I have tried using echo in various ways, and googled about, but it has stumped me, simple as it may be.

If anyone could let me know how I construct this line I'd be very grateful.  Time is of the essence, as they say...

Thanks,

Nick

my output is this below:

Course: INFO101 - Bsc Information Communication Technology Course Mark:



Course: INFO101 - Bsc Information Communication Technology Course Mark:


Module: CHI2550 - Modern Database Applications Module Mark: 41 Mark Percentage: 68 Grade: B

Session: AAB Session Mark: 72 Session Weight Contribution 20%

Session: AAE Session Mark: 67 Session Weight Contribution 40%

Module: CHI2513 - Systems Strategy Module Mark: 31 Mark Percentage: 62 Grade: B

Session: AAD Session Mark: 61 Session Weight Contribution 50%

As it shows 2 different Modules, it shows the "Course" details twice, I only want the "Course" details appear once as you can see both course details are the same.

How can I display the "Course" Details only once in the foreach loop.

To display the "Course" details I use this code: echo Code: [Select]
`"<p><br><strong>Course:</strong> {$courseId} - {$courseName} <strong>Course Mark:</strong></p><br>\n";`

Below is the code for the function and foreach loop:


Code: [Select]
     function outputModule($courseId, $courseName, $moduleId, $moduleName, $sessionData)
        {
       
            if(!count($sessionData))
            {
                return false;
            }
       
            $markTotal = 0;
            $markGrade = 0;
            $weightSession = 0;
            $courseTotal = 0;
            $grade = "";
            $sessionsHTML = "";
           
            foreach($sessionData as $session)
            {
       
                $sessionsHTML .= "<p><strong>Session:</strong> {$session['SessionId']} <strong>Session Mark:</strong> {$session['Mark']}</strong> <strong>Session Weight Contribution</strong> {$session['SessionWeight']}%</p>\n";
               
                $markTotal += round($session['Mark'] / 100 * $session['SessionWeight']);
                $weightSession  += ($session['SessionWeight']);
                $markGrade = round($markTotal /  $weightSession * 100);
                     
                if ($markGrade >= 70)
                {
                    $grade = "A";
                }
       
                else if ($markGrade >= 60 && $markGrade <= 69)
                {
                    $grade = "B";
                }
       
                else if ($markGrade >= 50 && $markGrade <= 59)
                {
                    $grade = "C";
                }
       
                else if ($markGrade >= 40 && $markGrade <= 49)
                {
                    $grade = "D";
                }
       
                else if ($markGrade >= 30 && $markGrade <= 39)
                {
                    $grade = "E";
                }
       
                else if ($markGrade >= 0 && $markGrade <= 29)
                {
                    $grade = "F";
                }
        }
       
            echo "<p><br><strong>Course:</strong> {$courseId} - {$courseName} <strong>Course Mark:</strong></p><br>\n";
            $moduleHTML = "<p><strong>Module:</strong> {$moduleId} - {$moduleName} <strong>Module Mark:</strong> {$markTotal} <strong>Mark Percentage:</strong> {$markGrade} <strong>Grade:</strong> {$grade} </p>\n";
       
            return $moduleHTML . $sessionsHTML;
        }

I wrote a short script that takes a list of keywords and does a Google search to find how often they are used in the title of a page.  However, I cannot get it to echo the results in real time.  On one server I use it works fine.  On the other it runs the entire list and then outputs everything in the end.  The problem is sometimes this takes several minutes and therefore it times out after not receiving a response.

Any suggestions?

Thanks in advance.

<?php 

$file = file('words.txt'); 

$results = ''; 
foreach ($file as $line) { 
    $data     = file_get_contents("http://www.google.com/search?hl=en&q=allintitle%3A%22" . urlencode($line) . "%22&btnG=Google+Search"); 
    preg_match('/of about <b>([0-9,]*)?<\/b>/si', $data, $number); 
    $results .= $line . ";" . $number[1]; 
    echo $results . "</br>"; 
    $results = "";
    sleep(2);
} 

?>

I have a script that reads a .gz file into an array and prints the name of each record but will not work on larger files. Is there a way to read 1 line at a time?
Here is the code I have so far.
Code: [Select]
<?php

if ($handle = opendir('.')) {

print "<ol>";
    
    while (false !== ($file = readdir($handle))) {
if($file != '..' && $file!="." && $file!="start_update.php" && $file!="sharons_dbinfo.inc.php" && $file!="root.php" && $file!="read_directory.php" && $file!="read_dir.php" && $file!="new_category.php" && $file!="index.php" && $file!="file_count.php" && $file!="dir_loop2.php" && $file!="dir_loop1.php" && $file!=".htaccess" && $file!="Answer.txt" && $file!="Crucial_Technology-Crucial_US_Product_Catalog_Data_Feed.txt"){
$filename = $file;
$go = filesize($filename);
if($go >= 1){
$filename2 = explode("-", $filename);
$filename2 = $filename2[0];
echo str_replace("_"," ",$filename2) . ' | Filesize is: ' . filesize($filename) . ' bytes<br>';
$gz = gzopen($filename, 'r');
$lines = gzfile($filename,10000);
foreach ($lines as $line) {
$line2 = explode(",", $line);
$line2 = str_replace("," , "-" , $line2);
    echo "<li>".str_replace("," , "-" , $line2[4])."</li><br>";
}

}
}
    }

    closedir($handle);
}
?>
</ol>