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PHP - <input Type='file'> But Select Directory/filename.txt Instead!
Hey guys!
I'm making a locally run web based application for entering/storing/editing data. I am trying to do this thing where I export a 'records.txt' file to a different location which can be selected by the user. I have a lame <input type='text' value='H:\'> box going on which I was going to use to define the path for the file to be saved, but I want to be able to use a pop up windows (or whatever native OS finder application) just like the one which appears when you use <input type='file'>. Now that I think about it, I think this is more of a html question, but it's 2.30am and my project is due today... See! what the hell, I just habitually pressed ctrl-s after working in dreamweaver for hours and the exact function which I am looking for popped up, how do I do that?! Please thanks guys Similar TutorialsHello, Iv written a small script in JS to add input boxes of the type file to the page.. My problem is when i use multiple of those input boxes and submit the form the $_FILES variable only reads 1 of those boxes.. This is the javascript im using: Code: [Select] function addImageBox() { var imageBoxes = document.getElementById("imageBoxes"); var tr = document.createElement("tr"); var td = document.createElement("td"); var td2 = document.createElement("td"); var inputFile = document.createElement("input"); inputFile.setAttribute("type", "file"); inputFile.setAttribute("name", "image[]"); inputFile.setAttribute("style", "width: 450px"); td.appendChild(document.createTextNode("Image")); td2.appendChild(inputFile); tr.appendChild(td); tr.appendChild(td2); imageBoxes.appendChild(tr); } When i add 2 boxes (making it 3 boxes on the page in total) and count the $_FILES var after submiting the form, the count method returns 1, and when i var_dump it only 1 array is in $_FILES. Any idea's? thanks! Hello. I have a directory with files that look like this: priceguide_20100809.pdf priceguide_20100808.pdf priceguide_20100807.pdf priceguide_20100806.pdf I am trying to come up with a function that will grab and save the filename with the biggest date .. ie: priceguide_20100809.pdf. Any assistance would be greatly appreciated!! I am trying to display images on a html page alphabetically in descending order by their filename. <?php $dir = "./plate_cache"; $handle = opendir($dir); while (($file = readdir($handle))!==false) { if (strpos($file, '.png',1)) { echo "<img id=\"plates\" src=\"/tags/plate_cache/$file\"></a><br />;"; } } closedir($handle); } ?> Any help is greatly appreciated! I'm experiencing a very strange issue, and I'm not 100% sure it's PHP-related, but I'd like to at least rule it out if it's not. I've setup a test page he http://www.linkboard.org/test/ Included on that page are two bookmarks files exported from a browser: one contains data-URI encoded favicons, and the other does not. Uploading both files via the above URL should work just fine in any browser (an array dump of characters should be the result). However, if you change the above URL to include the 'index.php', uploading the file with favicons in it no longer works - it results in a browser time out. If i change the name of the test page to something else, i.e. 'test.php', it will never work since I would always have to specify the page filename in the URL. So, anybody have any ideas? Could this be a server config issue? It doesn't appear to be a browser problem because I experience the exact same issue in Chrome, Firefox, and IE. Edit: Here's the code I'm using on the page: Code: [Select] <?php if (isset($_POST['submit'])) { if (is_uploaded_file($_FILES['bookmarks_file']['tmp_name'])) { $file = fopen($_FILES['bookmarks_file']['tmp_name'], "r"); if ($file != false && $_FILES['bookmarks_file']['type'] == 'text/html') { $charArray = array(); while (!feof($file)) { $charArray[] = fgetc($file); } fclose($file); var_dump($charArray); } } } ?> <h2>Test Import</h2> <p><a href="bookmarks_4_24_12-favicon.html">Bookmarks file <strong>with</strong> Favicons</a><br /> <a href="bookmarks_4_24_12.html">Bookmarks file <strong>without</strong> Favicons</a></p> <p>Upload one of the above files with this form. If successful, the program will print out file contents.</p> <form enctype="multipart/form-data" action="<?php echo $PHP_SELF; ?>" method="POST"> <input type="file" name="bookmarks_file" /><br /><br /> <button type="submit" name="submit">Submit</button> </form> Hiya, Firstly, I'm a complete novice, apologies! But I have got my upload.php working which is nice. I will post the code below. However, I would now like to restrict the file size and file type to only word documents. I currently have a restriction of 200KB but it's not working - no idea why as I've looked at other similar codes and they look the same. Also, just to complicate things - can I stop files overwriting each other when uploaded? At the moment, if 2 people upload files with the same name one will overwrite the other. Is this too many questions in 1? Any help is very much appreciated! Code below: Code: [Select] <form enctype="multipart/form-data" action="careers.php" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; //This is our size condition if ($uploaded_size > 200) { echo "Your file is too large.<br>"; $ok=0; } //This is our limit file type condition if ($uploaded_type =="text/php") { echo "No PHP files<br>"; $ok=0; } //Here we check that $ok was not set to 0 by an error if ($ok==0) { Echo "Sorry your file was not uploaded"; } //If everything is ok we try to upload it else { if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "Your file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded."; } else { echo "Sorry, there was a problem uploading your file."; } } ?> Hi Guys, Appreciate any help here please... Basically I want to hide some inputs on my registration page and populate them will default values. Everything works okay, apart from the input below: Code: [Select] <input type="hidden" name="seek_location" value="Anywhere"> When I use the above, the MYSQL database field for seek_location is left empty... I've noticed that the code below pulls the location into a dropdown list. You know the kind of thing, Australia, UK, USA etc etc: Code: [Select] $seek_location = $wcr[$seek_location]; Code: [Select] <? $p=0;asort($wcr);reset($wcr); while (list ($p, $val) = each ($wcr)) { echo '<option value="'.$p.'">'.$val; } ?> So, all I want to do is have: Code: [Select] <input type="hidden" name="seek_location" value="Anywhere"> Populate seek_location with Anywhere Any help appreciated Thanks Rob This is a cross between HTML, PHP, and MySQL. I'm not exactly sure which to blame (other than myself of course) I'm collecting a bid price in a standard form <input type="number" name="maxbid" value="<?php echo $maxbid ?>"/> I have recalled the value from the database where I store it and display it in the field if it exists. If the field has never been entered, the field shows nothing. It's not required that a bid be entered. There are other fields of data that may be updated and this field is left blank. On the page called by the submit button I'm retrieving the fields $maxbid=$_POST[maxbid]; Then I store the fields in the database either with an INSERT or an UPDATE if(mysql_num_rows(mysql_query("SELECT id FROM data WHERE id = '$id'"))) { echo "Updating....."; mysql_query("UPDATE data SET maxbid='$maxbid', name='$name' where id='$id'"); } else { echo "Inserting....."; mysql_query("INSERT INTO data (id, maxbid,name) VALUES ('$id','$maxbid',$'name')"); } I know I'm not handling the Numeric values correctly, and I'm having a hard time finding the correct method for doing so. Right now, if the name is entered byt the maxbid is left blank, nothing gets inserted or updated. if I enter both the maxbid and the name it works. I can't have maxbid show up as a 0, I need it to be blank if nothing is entered. Also when I check $maxbid, it's not an INTEGER (per INTVAL) when I check it, even though maxbid in the table is an INTEGER. When I pass it around, it seems to lose it's INTEGER value, but still shows as a number. I know this sounds confusing, heck I'm confused. If someone could point me to a good tutorial, I'd figure it all out, but most tutorials don't get into the data type that much, and the combination of the form, passing the variables, reading the values from the database, etc. is what's causing me grief. Any guidance would be appreciated. I havent included the whole title as it wouldnt let me but I was wondering if someone could help me on this? I know this is possible as torrentflux caters for this but unsure of where to start. I dont want to allow file or directory uploads or creation in my /etc/php.ini file (this is turned off). Yet then torrentflux allows me to link a torrent from an external source (using legal downloads of course ) but then it uploads it on my server and creates folders on a per user basis. How is this possible can someone give me some pointers please? I look forward to any replies, Jeremy. i have the following code: <li>Have you read the <?php echo link_to('FAQ','util/faq') ?> ? <select id="yesnolist" onChange="getChoice(this.value)"> <option value="yes" selected="selected">Yes</option> <option value="no">No</option> </select> </li> <input type="hidden" name="text" size=30 id="yesandno"> <?php if ($_GET['yesandno'] == "no") { echo "anything!!!!!!!!!!!!!!!!!!!"; } ?> then my java script for getCoice(): function getChoice(val) { yesNo = new Array("Yes", "No"); var getsel = document.contactus.yesnolist.value; var e = document.getElementById("yesnolist"); var strUser = e.options[e.selectedIndex].value; document.contactus.yesandno.value = strUser; alert(document.contactus.yesandno.value); return strUser; } my alert will gove yes or no depending on what i chose in the dropdown but HOWCOME it does not go into the if ($_GET['yesandno'] == "no") ???? please help??? How can I make it so that the things that the user recently typed in an input is not displayed as a drop down. I want nothing to be displayed. Folks,
I am building a membership script for 21 months now!!! That long!!!
Not pasting the whole script as really long. Would do your head in.
if($_SERVER["REQUEST_METHOD"] == "POST")
{
if(!isset($_FILES["id_verification_video_file"])) //REtype
{
echo "no isset";
}
else
{
$id_verification_video_file = $_FILES['id_verification_video_file']; //REtype
//Feed Id Video Verification File Upload Directory Path.
$directory_path = "uploads/videos/id_verifications/";
//Make Directory under $user in 'uploads/videos/id_verifications' Folder.
if(!is_dir("$directory_path" . "$user"))
{
$mode = "0777";
mkdir("$directory_path" . "$user", "$mode", TRUE); //Thanks Requinix for my "$mode" typo hint.
}
//Grab Uploading File details.
$Errors = Array(); //SHOULD I KEEP THIS LINE OR NOT ?
$file_name = $_FILES["id_verification_video_file"]["name"];
$file_tmp = $_FILES["id_verification_video_file"]["tmp_name"];
$file_type = $_FILES["id_verification_video_file"]["type"];
$file_size = $_FILES["id_verification_video_file"]["size"];
$file_error = $_FILES['id_verification_video_file']['error'];
//Grab File Extension details.
$file_extension = pathinfo($file_name, PATHINFO_EXTENSION);
if(file_exists('$directory_path' . '$user/' . '$file_name'))
{
$Errors[] = "Error: You have already uploaded a video file to verify your ID!";
exit();
}
else
{
//Feed allowed File Extension(s).
$allowed_file_extensions = array("mp4" => "video/mp4","wmv" => "video/wmv");
//Feed allowed file size.
$max_file_size_allowed_in_bytes = 1024*1024*100; //Allowed limit: 100MB.
$max_file_size_allowed_in_kilobytes = 1024*100;
$max_file_size_allowed_in_megabytes = 100;
$max_file_size_allowed = "$max_file_size_allowed_in_bytes"; //RETYPE
//Verify File Extension.
if(!array_key_exists($file_extension,$allowed_file_extensions)) die("Error: Select a valid video file format. Select an MP4 or WAV file.");
//Verify MIME Type of the file.
elseif(!in_array($file_type,$allowed_file_extensions))
{
echo "Error:<font size ='5' font color ='red'><b>There was a problem uploading your video file $file_name! Make sure your file is an MP4 or a WAV file. You may try again now.</b></color></size>"; //THANKS TO REQUINIX FOR BRINNGING IT TO MY ATTENTION I AM STILL PROCESSING THE SCRIPT AFTER THIS LINE WHEN I SHOULD NOT.
exit();
}
//Verify File Size. Allowed Max Limit: 100MB.
elseif($file_size>$max_file_size_allowed) die("Error: Your Video File Size is larger than the allowed limit of: $max_file_size_allowed_in_megabytes."); //Fixed variable name typo. Thanks to Requinix & Simon JM.
//Move uploaded File to newly created directory on the server.
move_uploaded_file("file_tmp","$directory_path" . "$user/" . "$file_name");
//Notify user their File was uploaded successfully.
echo "<font size ='5' font color ='red'><b>Your Video File \"$file_name\" has been uploaded successfully! You will get notified once your Id has been verified successfully.</b></color></size>";
Can you spot my coding error ? This function is throwing the following error: invalid input syntax for type timestamp "1301297896" Code: [Select] function removeInactiveUsers(){ if(!TRACK_VISITORS) return; $timeout = time()-USER_TIMEOUT*60; $result = pg_query_params($this->connection, "delete from active_users where timestamp < $1", array($timeout)); $this->calcNumActiveUsers(); } I know the problem is with $timeout using a php timestamp vs postgresql timestamp but I'm not sure how to fix that Ok basic setup is Table name = unit_data I have a field unit_paid_date colum type = DATE unit_paid_date = 2011-03-02 thats yyyy-mm-dd lets say for example the DueDate is the Second of every month I need to select all records from unit_data that are PAST DUE so if the last paid date is 2011-01-02 that record will pop up as PAST DUE BUT if that paid date is say 2011-03-10 it will not be shown because the invoice was paid Ahead of due date I had this almost working properly -- but can use any help you guys offer. I was attempting to use mysql WHERE queries and do checks against paid_date but failed Thanks hidden input field type doesnt display the full value i get from table, say if it is a first name and last name i get only the first name. here is my input field echo "<input type=hidden name=proid value=$result_row[project_id]></include>"; echo "<input type=text value=$result_row[project_name] readonly></include>"; my sql query returns the full name but when i input into the text field it returns an incomplete project name like say if it is fans of soccer, i just get the value "fans" in my display..... I think I understand that there can only be one "submit" button on a page.
I want buttons for separate forms to not trigger the empty errors on the other forms...
How do you accomplish specific button actions?
I think I've tried it with javascript but you can do it with PHP right?
Thanks for any help.
Long time lurker, first time poster here. I am having a problem with a multiple file uploader form I am trying to build. I am using the CodeIgniter framework, but I believe my problem is with the form itself. Here is the form: Code: [Select] <form action="http://localhost/show/submit" id="sendfiles" method="post" name="sendfiles" enctype="multipart/form-data"> <input type="hidden" name="doup" value="1" /> <input type="file" name="userfile1" value="" id="userfile1" size="20" /> <br /> <input type="file" name="userfile2" value="" id="userfile2" size="20" /> <br /> <input type="file" name="userfile3" value="" id="userfile3" size="20" /> <br /> <input type="submit" name="submit_btn" value="Upload" /> </form> The form is being passed to this function: if(empty($_POST['doup'])){ foreach($_REQUEST as $k => $v) print ">>> $k : $v <br />"; $data['form_open'] = form_open_multipart(uri_string(), array( 'id' => 'sendfiles', 'method' => 'post', 'name' => 'sendfiles' )); $data['form_flag'] = form_hidden('doup', '1'); $data['file1'] = form_input(array( 'id' => 'userfile1', 'name' => 'userfile1', 'size' => '20', 'type' => 'file', )); $data['file2'] = form_input(array( 'id' => 'userfile2', 'name' => 'userfile2', 'size' => '20', 'type' => 'file', )); $data['file3'] = form_input(array( 'id' => 'userfile3', 'name' => 'userfile3', 'size' => '20', 'type' => 'file', )); $data['form_submit'] = form_submit('submit_btn', 'Upload'); $data['form_close'] = form_close(); $this->load->view('show/submit', $data); } else { $config['allowed_types'] = 'mp3'; $config['max_size'] = '10240'; $config['upload_path'] = $this->config->item('file_upload_path'); $uploaded_files = array(); for($nona=1; $nona<4; $nona++){ if (strlen($_FILES['userfile'.$nona]['tmp_name']) <=0){ echo "tempname$nona failed"; continue; } //print "------ USERFILE $nona ------ <br />"; //print sizeof($_FILES['userfile'.$nona])."<br />"; //foreach ($_FILES['userfile'.$nona] as $k => $v){ // print "$k : $v <br />"; //} $this->upload->initialize($config); $upload = $this->upload->do_upload('userfile'.$nona); if (!$upload){ $form_errors = array('form_errors' => $this->upload->display_errors()); $this->load->view('show/submit', $form_errors); break; } else { $data = array('upload_data' => $this->upload->data()); $data = $data['upload_data']; $fp = $data['full_path']; $filename = strtolower(random_string('numeric', 16) . $data['file_ext']); $rel_path = 'show/submissons/uploaded/'; $path = $this->config->item('media_root_path') . $rel_path; exec('mkdir -p ' . $path , $a1, $r1); exec('mv ' . $fp . ' ' . $path . $filename, $a2, $r2); array_push($uploaded_files, $path . $filename); } } $this->session->set_flashdata('img_data',implode("||", $uploaded_files)); // redirect("show/submit_info"); } The problem is this: When I choose only one file to upload, it works. I can choose any of the 3 inputs and it works great. But as soon as I try to choose 2 or more files, the form fails to post. When I press submit, the page simply reloads and none of the form variables get posted. I have checked settings in php.ini and tried building and rebuilding this form. I'm hoping someone here can provide some insight into what I'm doing wrong? I have a calendar select date function for my form that returns the date in the calendar format for USA: 02/16/2012. I need to have this appear as is for the form and in the db for the 'record_date' column, but I need to format this date in mysql DATE format (2012-02-16) and submit it at the same time with another column name 'new_date' in the database in a hidden input field. Is there a way to do this possibly with a temporary table or something? Any ideas would be welcome. Doug Why does this code: Code: [Select] require_once "../../media/php/classes/Mysql.inc.php"; Work when I go to: http://mysite.com/API/v1/index.php But when I go to: http://mysite.com/index.php it doesn't work. The require is being called from another class, which I call from the two pages above. The class loads, but in the second link, I get failed to open stream: No such file or directory but the first one works fine. What would cause this? could this be an htaccess thing? htaccess: Code: [Select] Options +FollowSymlinks RewriteEngine On RewriteBase / RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteCond %{REQUEST_FILENAME}.php -f RewriteRule ^(.+)$ /$1.php [L,QSA] I'm in the middle of making my own CMS system, where a user can create a page online via a text editor, I know how to create and save the file, but to make the process easier I would like to a function where a user can click a button find a list of files and folders, pick the folder location to save a new file to. Instead of having to type something like this /commonPages/aboutUs/ with the file name being test.php What would be the easiest way to do this? I have just been looking at opendir() and my first thought was to use <input type="file" />, but then I remember that was only for inputting a particular file name, which would be useful for renaming a file at a later date. For example, if we wanted to change test.php to something more meaningful ie history.php In my script, I'm trying to create a file with the name of a variable in a different directory. My code is: Code: [Select] $handle = fopen("cheese/" . $page . ".html", "w");Output: Warning: fopen(cheese/test.html) [function.fopen]: failed to open stream: No such file or directory in /home/a5938041/public_html/newfile/newpage.php on line 6 What's happening here? (sorry I'm a total noob.) |
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