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PHP - If Statement For Importing Into Mysql Database.
Hi everyone,
I am currently making a page for a friend to upload a bunch of photos at a time. I was quite pleased that after a bit of googling and trial and error, I figured out how to do this so that multiple records could be added to my table with one submit button. However, my form has 10 browse iconcs. A few tests have revealed that my problem is that if only one picture is uploaded, I still get 9 entries in my database, which I don't want. My question is how can I alter the code so that a row is only populated in the database if an image is uploaded. I guess something that sort of says : if($imgx!="") { populate that row in the table } else { don't } ...and the same for $imgx002 through to $imgx010 The current query is below. Any pointers are much appreciated. Code: [Select] $query = "INSERT INTO photo_uploads (date, photo_name)" . "VALUES (NOW(), '$imgx'), (NOW(), '$imgx002'), (NOW(), '$imgx003'), (NOW(), '$imgx004'), (NOW(), '$imgx005'), (NOW(), '$imgx006'), (NOW(), '$imgx007'), (NOW(), '$imgx008'), (NOW(), '$imgx009'), (NOW(), '$imgx010')"; Similar TutorialsHi friends i need a small help in importing csv files into mySQL database table i tried all possible options but i am no where... here is the example for what i am trying to do Mysql DB name = raw Table name is = dump +--------------------+--------------------+ + Account + Bal + +--------------------+--------------------+ + + + +--------------------+--------------------+ CSV Format 50************13, 11095 When they upload the file it should automatically get inserted into appropriate fields any help would be great i tried all possible scripts found in the net could nothing is happening I'm attempting to import a mysql database backup via php unfortunately I keep getting this error: Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SOURCE file.sql' at line 1 Code: mysql_query("SOURCE file.sql") or die (mysql_error()); I've researched this online and this seems to be the way everyone suggests to use, unfortunately it isn't working. If it helps here is the first 4 lines of file.sql as that may be the problem for all I know: -- phpMyAdmin SQL Dump -- version 3.2.4 -- http://www.phpmyadmin.net -- Am trying to import a csv file into mysql. below is the code am using.
<?php //connect to the database include('mysql_connect.php');//select the table // if ($_FILES[csv][size] > 0) { //get the csv file $file = $_FILES[csv][tmp_name]; $handle = fopen($file,"r"); //loop through the csv file and insert into database do { if ($data[0]) { mysql_query("INSERT INTO requisition (department, contact_last, contact_email) VALUES ( '".addslashes($data[0])."', '".addslashes($data[1])."', '".addslashes($data[2])."' ) "); } } while ($data = fgetcsv($handle,1000,",","'")); // //redirect header('Location: import.php?success=1'); die; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR...nsitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Import a CSV File with PHP & MySQL</title> </head> <body> <?php if (!empty($_GET[success])) { echo "<b>Your file has been imported.</b><br><br>"; } //generic success notice ?> <form action="" method="post" enctype="multipart/form-data" name="form1" id="form1"> Choose your file: <br /> <input name="csv" type="file" id="csv" /> <input type="submit" name="Submit" value="Submit" /> </form> </body> </html> ........................................................................................................................................... On page load, it gives some erros Notice: Use of undefined constant csv - assumed 'csv' in C:\wamp\www\orango\upload_data.php on line 7 Notice: Use of undefined constant size - assumed 'size' in C:\wamp\www\orango\upload_data.php on line 7 Notice: Undefined index: csv in C:\wamp\www\orango\upload_data.php on line 7 Notice: Use of undefined constant success - assumed 'success' in C:\wamp\www\orango\upload_data.php on line 43 I try to ignore the errors to see if it would work but it didn't save in the DB. please help me out Hello,
I am trying to import a CSV file into an existing mysql table but it doesn't seem to work well.
Here is how my mysql is looking like:
1 a_id int(11) AUTO_INCREMENT 2 a_lobecoid int(7) 3 a_code varchar(30) utf8_general_ci 4 a_omschint varchar(60) utf8_general_ci 5 a_beveiligingniv int(5) 6 a_type varchar(5) utf8_general_ci 7 a_assortiment int(5) 8 a_discipline varchar(30) utf8_general_ci 9 a_brutoprijs varchar(50) utf8_general_ci 10 a_status varchar(5) utf8_general_ci 11 a_levcode varchar(10) utf8_general_ci 12 a_omschr_nl varchar(60) utf8_general_ci 13 a_omschr_fr varchar(60) utf8_general_cithese are some lines from my CSV file 16158|-H|Factory installed heater|10|S|400|CCTV|45.0|E| 1829|Factory installed heater|Factory installed heater 16159|-IR|Factory installed IR LED ring|10|S|400|CCTV|50.0|E| 1829|Factory installed IR LED ring|Factory installed IR LED ring 9001|00-SBN2|Smoke box niet geaspireerd,230VAC|10|S|267|BRAND|1587.03|D| 642|Smoke box niet geaspireerd,230VAC|Smoke box pas aspiré,230VCA 9003|00-TP1|Telescopische verlengstok voor Smoke box,2,4-4,6m|10|S|267|BRAND|644.09000000000003|D| 642|Telescopische verlengstok voor Smoke box,2,4-4,6m|Rallonge téléscopique pour Smoke box,2,4-4,6m 9004|00-TP2|Telescopische verlengstok voor Smoke box,2,4-9,2m|10|S|267|BRAND|944.64999999999998|D| 642|Telescopische verlengstok voor Smoke box,2,4-9,2m|Rallonge téléscopique pour Smoke box,2,4-9,2m 12161|001-0081|Thermistor probe,rood, high temp. 0-+150°C|10|S|52|INBRAAK|136.91|D| 1731|Thermistor probe,rood, high temp. 0-+150°C|Sonde température,rouge,high temp. 0-+150°CHere you have the code for the import: $upload_article_query = "LOAD DATA INFILE 'ARTIKELS.CSV' INTO TABLE artikelen FIELDS TERMINATED BY '|' LINES TERMINATED BY '\\r\\n' (a_lobecoid, a_code, a_omschint, a_beveiligingniv, a_type, a_assortiment, a_discipline, a_brutoprijs, a_status, a_levcode, a_omschr_nl, a_omschr_fr)"; $upload_article_stmt = $dbh->prepare($upload_article_query); $upload_article_stmt->execute();If i use the code then in the MYSQL table the first line is filled in but where the second line has to start it just writes it into the last column and doesn't start a new line. Also if i edit that first line it shows a lot of "?" (questionmarks) into a window symbol. Anyone has an idea what i am doing wrong? In attachment some printscreens of my table after the insert. Apologies for the Dutch language. Thanks in advance Attached Files pic1.jpg 6.13KB 0 downloads pic2.jpg 37.9KB 0 downloads Hey guys! So I have this script to import a CSV file into my database:
<?php
$databasehost = "localhost";
$databasename = "import";
$databasetable = "import";
$databaseusername="username";
$databasepassword = "password";
$fieldseparator = ",";
$lineseparator = "\n";
$csvfile = "test.csv";
if(!file_exists($csvfile)) {
die("File not found. Make sure you specified the correct path.");
}
try {
$pdo = new PDO("mysql:host=$databasehost;dbname=$databasename",
$databaseusername, $databasepassword,
array(
PDO::MYSQL_ATTR_LOCAL_INFILE => true,
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION
)
);
} catch (PDOException $e) {
die("database connection failed: ".$e->getMessage());
}
$pdo->exec("TRUNCATE TABLE `$databasetable`");
$affectedRows = $pdo->exec("
LOAD DATA LOCAL INFILE ".$pdo->quote($csvfile)." REPLACE INTO TABLE `$databasetable`
FIELDS TERMINATED BY ".$pdo->quote($fieldseparator)."
LINES TERMINATED BY ".$pdo->quote($lineseparator)."
IGNORE 1 LINES");
echo "Loaded a total of $affectedRows records from this csv file.\n";
?>
So that script basically imports a csv replacing all of the other data.
The issue I am having is that the data inside one of the columns contains commas, they are wrapped in quotations.
Here is an example:
,"1 Registered Keeper, Full Service History, Central Locking, Electric Windows, Electric Mirrors, ABS, Traction Control, Climate Control, Power Steering, Drivers Airbag, Passenger Airbag, Side Airbags, Cruise Control, Alarm, Immobiliser, Half Leather Interior, Alloy Wheels",
How could I make the script determine the text within those quotation marks as a whole value instead of separating them into individual columns?
Thanks any help on this would be great!
Hi all,
I'm working on a project involving an orders set of APIs, and having trouble coming up with the best logic to handle this - with the smallest amount of overhead and client facing slowness. Here's the jist of what I'm looking at...
There are 21 API methods to pull different types of orders, and each of them handle paging by requesting a number of records (10 - 500), and a page number. So I could say in my URI, "page-no=1&no-of-records=50", followed by "page-no=2&no-of-records=50", to get subsequent records. The API will return in each call the total records returned as well as the total records in their database.
Now, I want to insert all of this into my database, and so that means something like 21 APIs * 3 SQL requests each = 63 sql queries (check it exists, if so update - else insert).
This seems to me like way too much work for a client facing application. Any suggestions?
Hi Guys Just need some advice to go in the right direction. I'm working on a csv upload script (part of a bigger thing i'm building), so i read in the csv to a multipdimensional array and then build a query that inputs all rows in one query - i read this is the most efficient way to import multiple rows of data at once(rather than multiple insert statements). Just for illustration here's the code i use to build the query so you understand what i'm on about: Code: [Select] $sql = "INSERT INTO teams (company, teamname, teamnum, amountraised, country, president) VALUES "; // $rows is a count of the rows in the csv for($i=1; $i<$rows; $i++){ $sql.="('{$myarray[$i][0]}','{$myarray[$i][1]}','{$myarray[$i][2]}','{$myarray[$i][3]}','{$myarray[$i][4]}','{$myarray[$i][5]}')"; echo $i . "<br/>"; if($i >= 1 && $i < $rows - 1) { $sql.= ","; } } Anyway, the issue is that one of the fields("teamnum") needs to be unique - so i've set this as unique on the table in mysql. But when i run my query it doesn't import anything if one of the records isn't unique. What i really want is for it to import the ones it can and catch the ones it cant import to present to the user. So my question is - to acheive the above would i need to rewrite the query so that it inserts each row one at a time, instead of all together? Or can someone point me in the right direction for a better solution? Probably something very simple i've missed i am sure... Thanks chaps! does anyone know who to resolve this issue of importing a CSV file from excel into sql? I get this error when I do. LOAD DATA LOCAL INFILE '/tmp/phpq2aAbU' INTO TABLE `Events` FIELDS TERMINATED BY ',' ENCLOSED BY '\\"' ESCAPED BY '\\\\' LINES TERMINATED BY '\r\n' Hi Can you please help me with an issue I am having? I have three description fields that I am pulling from a database. I did this so when it displays it isn't one long string. However the issue I am running into is if the 3rd description box is empty I do not what to display it. I cant figure out why it is only hitting the first display option. I created this variable $dishdesc3 = $_POST["dish_desc_3"]. I would like to say when it is NULL display the only the first 2 description boxes. Otherwise have it display all three description boxes. Is there a way to do that?
<?php
// Include the database configuration file
require_once 'con_php.php';
//check connection
if ($con -> connect_error){
die ("connection failed: " . $con -> connect_error);
}
$chsql = "SELECT * FROM dish_pic where cat_name = 'Chicken'";
$chresult = $con ->query($chsql);
$dishdesc3 = $_POST["dish_desc_3"];
if ($chresult-> num_rows >0){
while ($row = $chresult -> fetch_assoc()){
if ($dishdesc3 = "3")
{
echo"<table border='0' cellpadding='4' cellspacing='0' width='100%'>";
echo" <tr><td class='style1' align='center' colspan='3' valign='top'>". $row["dish_name"] .".........................$" . $row["price"] . "<br><td></tr>
<tr>
<td class='style2' align='center' >" . $row["dish_desc"] . "<br>
" . $row["dish_desc_2"] . "<br>
<tr><td class='style3' align='center' >Serving " . $row["dish_size"] . " Calories " . $row["dish_cal"] . " Total Carbs " . $row["dish_tot_carbs"] . " Net Carbs " . $row["dish_net_carbs"] . " Fat " . $row["dish_fat"] . " Fiber " . $row["dish_fiber"] ." Protein " . $row["dish_protein"] . "<br></td></tr>
<tr><td class='style2' align='center' >Recommend Side " . $row["dish_recommend"] . "</td></tr>
<br>
";
echo"</table>";
}
Else
{
echo"<table border='0' cellpadding='4' cellspacing='0' width='100%'>";
echo" <tr><td class='style1' align='center' colspan='3' valign='top'>". $row["dish_name"] .".........................$" . $row["price"] . "<br><td></tr>
<tr>
<td class='style2' align='center' >" . $row["dish_desc"] . "<br>
" . $row["dish_desc_2"] . "<br>
" . $row["dish_desc_3"] . "<br></td></tr>
<tr><td class='style3' align='center' >Serving " . $row["dish_size"] . " Calories " . $row["dish_cal"] . " Total Carbs " . $row["dish_tot_carbs"] . " Net Carbs " . $row["dish_net_carbs"] . " Fat " . $row["dish_fat"] . " Fiber " . $row["dish_fiber"] ." Protein " . $row["dish_protein"] . "<br></td></tr>
<tr><td class='style2' align='center' >Recommend Side " . $row["dish_recommend"] . "</td></tr>
<br>
";
echo"</table>";
}
}
}
$con->close();
?>
Sorry going to be a big post, but trying to query a sql database for a value Original code <?php if($this->item->params->get('catItemExtraFields') && count($this->item->extra_fields)): ?> <!-- Item extra fields --> <div class="catItemExtraFields"> <h4><?php echo JText::_('K2_ADDITIONAL_INFO'); ?></h4> <ul> <?php foreach ($this->item->extra_fields as $key=>$extraField): ?> <?php if($extraField->value): ?> <li class="<?php echo ($key%2) ? "odd" : "even"; ?> type<?php echo ucfirst($extraField->type); ?> group<?php echo $extraField->group; ?>"> <span class="catItemExtraFieldsLabel"><?php echo $extraField->name; ?></span> <span class="catItemExtraFieldsValue"><?php echo $extraField->value; ?></span> </li> <?php endif; ?> <?php endforeach; ?> </ul> <div class="clr"></div> </div> <?php endif; ?> Now I want to check the name field for a value and if it is Closing Date print out something different from the value in value, so I've changed the red code to <span class="catItemExtraFieldsLabel"><?php if $extraField->name ="Closing date"; ?></span> { <span class="catItemExtraFieldsLabel"><?php echo $extraField->name; ?></span> <span class="catItemExtraFieldsValue"><?php echo $this->item->publish_down, JText::_('K2_DATE_FORMAT_LC2')); ?></span> } else { <span class="catItemExtraFieldsLabel"><?php echo $extraField->name; ?></span> <span class="catItemExtraFieldsValue"><?php echo $extraField->value; ?></span> } <?php endif; ?> Doesn't work though, tried a heap of variations but can't figure it out. Thanks Marc Hello I am creating a simple Discussion Forum, and I cant get past my IF Statement to verify topics exist? Please help? <?php //check for required info from the query string if (!$_GET[topic_id]) { header("Location: topiclist.php"); exit; } //connect to server and select database $link = mysql_connect('votpservicescom.ipagemysql.com', 'mantest', 'testman') or die(mysql_error()); mysql_select_db("learn2db",$link) or die(mysql_error()); just a little confused where ( brackets go in this statement . im just wanting to to display the information differently depending on which message is returned from the database. thanks Code: [Select] if ($info['message'])="<a href=\"freindacept.php?username=$myusername\">Has sent you a friend request </a>";{ Echo "<a href='viewprofile.php?username={$info['username']}'><img src='http://datenight.netne.net/images/".$info['img'] ."' width='30' height='30''></a>".$info['from_user']." ".$info['message']; }elseif ($info['message'])="You have sent a contact request to"; Echo " .$info['message']<a href='viewprofile.php?username={$info['username']}'><img src='http://datenight.netne.net/images/".$info['img'] ."' width='30' height='30''></a>".$info['from_user']."; } } I have database that is a list of categories that I would like to insert into a switch statement. This is the only way that I know how to do it right off hand and of course it doesn't work. I've looked on the internet and found examples but they are slightly over my head as ways to do it. Depending on $group which comes from the url a title an h1 would be assigned. Code: [Select] $q = "SELECT * FROM categories"; $r = @mysqli_query ($dbc, $q); switch ($group) { if ($r) { //If $r ran OK while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)){ case '$row['id_cat']': $h1 = '.$row['group']'; break; } } } Thanks S At the moment I am creating a search function for my website. The approach I have in mind is a pseudo-PHP database. To give an example: A HTML form will submit the results to a PHP file. HTML FORM - Colour: Black PHP RESULT PAGE - if ($_POST['color'] == 'Black') {readfile("./products/black/*.html");} HTML FORM - Price: <$50 PHP RESULT PAGE - if ($_POST['Price'] == '<$50') {readfile("./products/less50/*.html");} The problem here is if there is an item that is black and costs less than $50, then its going to be listed twice. There is probably some code I can write to ommit the listing of duplicate entries, but it is probably going to be messy, so I am wondering if its better to use a centralized MySQL database, rather than a pseudo-PHP database? I've never used MySQL and don't know much about it and this is my first real attempt at using PHP. I have a table with 5 records with the following "id_number" for each record in ASC order: 2, 6, 74, 86,87 There is one other field called "tag_number" and for each record in ASC order here is the data: 50670, 50077, 1234, 1235, 1236 I have a text field and if I search for a spastic "tag_number" I want to return the record but count and display what record like this: Record 3 of 5 The above 3 of 5 means I searched for "1234". I'm not sure what loop I need and how to count the records, any help would be great! Here is what I'm thinking: $id_number = 74; $result = db_query("select * from table order by id_number ASC"); $num_rows = mysql_num_rows($result); //this will provide how many records are in the table $result = db_query("select * from table where id_number = '$id_number' order by id_number ASC"); for ($i = 1; $i == $num_rows; $i = $i + 1) { if ($result['id_number'] == $id_number) { This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=312323.0 Hello everyone! I'm new here on phpfreaks - Here's my problem. I get "1 <br/> 2" echoed, but not the query results. the connect() function connects and selects a table in a mysql database. Here's the code: Code: [Select] <?php connect(); $query = "SELECT `title`, `body`, `date` FROM `tutorials` ORDER BY `date` DESC" or die ("Query Error"); $counter = 0; if ($query_run = mysql_query($query)) { while ($query_row = mysql_fetch_assoc($query_run)) && ($counter <= 2) { $title = $query_row['title']; $body = $query_row['body']; $date = $query_row['date']; $counter ++; echo $counter; echo "<br/>"; echo $title; echo $body; echo $date; } } ?> If anyone has any idea, please help! - I'm been battling this for a few hours now Hi Guys I don't know if this is possible but can someone point me in the right direction. I have a php function which takes two inputs and returns an output. for simplicity's sake let's say it's an addition function. What I want to do is use a mysql select statement to show all the rows from a database where field1 and field2 equal '3'. Here's the sort of thing I mean. function addNumbers($one,$two) { return $one + $two; } mysql_query("SELECT * FROM table WHERE 'addNumbers(field1,field2)' = '3'"); What I actually want to do is a lot more complex than this but I am trying to understand how to make the syntax work in simple terms first. Can anybody help? Many Thanks Dan This isn't the entire code just enough to see what I'm trying to do. Everything was working until I added the mysql update query in the if statement. Is this possible or am I doing something wrong? When I run the script it just echos "No results found" twice as $num_results = 2. Code: [Select] <?php include("../includes/connect.php"); $query = "SELECT ........ "; $result = $db->query($query); $num_results = $result->num_rows; if ($num_results == 0) { exit; } else { $i=0; while ($i < $num_results) { $row = $result->fetch_assoc(); $id = $row['id']; if ($expiration_date > $today) { ### EMAIL CODE HERE ### $update = "UPDATE model SET reminder_sent = '1' WHERE id = '$id' "; $result_2 = $db->query($update); $i++; } else { echo "No results found."; $i++; } } } ?> |
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