PHP - File_exists With Only Part File Name??

Hi    I want to echo out something when I post the value of a radio button and this value matches the same name of a html file. How can I formulate my code to achieve that?     What I have so far:

 <?php  
 
   if (isset($_POST['submitradio']))
{ 
    $selected_dir = $_POST['radio1'];

  echo substr($selected_dir, 0, -4);
  echo '<img src="'.$selected_dir.'" />';
  
} 
?>

So far I get for example the name of the image(order.gif) and the image order. gif.   What I now want is to formulate my code so that I can say if I have an image called "order.gif" and a file called "order.html" that I can then echo out some thing. I don't want to actually name the image or the html file. I just want to say if I have two different file types that start with the same name then I can echo out what ever. How can I do that?

My query gets the results and orders by one of the fields.

Once I get the MySQL results I would like to find the first entry that has a letter as the first character of the same field that the list was ordered by, then split the results in to two parts and swap them.

So that the results that have a letter at the start of the same sorted field are as the begining and the results that have the numbers as the start at the end of the array.

But also so that the array works the same way as the original results string, so i can use say $results['mysqlfield']

Code: [Select]
<?
$out = preg_replace('/^(.{701}[^.]*).*/i','$1.',$detrsltnewsrow[news_desc]);
echo $out;
?>

</td></tr><tr><td colspan="2" class="para" style="padding-left:10px;">

<?=
substr(stripslashes(trim($detrsltnewsrow[news_desc])),701)
?>
                                             
</td></tr>

I have the above snippet.. The first php statement, basically grasp the first 701 characters with the closet next stop "." character and out puts it. then out puts the HTML tags

I have a problem with the second statement. I want to output anything after what has been outputted by:
Code: [Select]
<?
$out = preg_replace('/^(.{701}[^.]*).*/i','$1.',$detrsltnewsrow[news_desc]);
echo $out;
?>

So need the correct syntax for
Code: [Select]
<?=
substr(stripslashes(trim($detrsltnewsrow[news_desc])),701)
?>
Currently it breaks at exactly the 701 character, want it to continue from the sentence the first code ended in.

I am trying to do a loop which uses file_exists to check if an image exists and if so display it using the following code:

<?php
$i = 1;
while ($i <= 8) {

$filename = $img_loc . "/hovers-800px/" . $image . "-" . $i . ".jpg";

if (file_exists($filename)) {
?>
<a class="fuglybox" rel="gxr" href="<?php echo $filename; ?>"> <!--Main thumbnail image-->
      <img src="<?php echo $img_loc; ?>/product-detail-90px/<?php $image . "-" . $i . ".jpg"; ?>" alt="" width="90" height="90" /></a>
<?php

}

$i++;

}

?>

I have echoed out $filename to check my directory structure and filename is fine and copied the echoed directory out. The structure is however http://Http://www.xxxxxx.com/img/filename.jpg. Could this be whats causing the problem?

<code>
$jpg_path = '../../../users/user_avatars/' . $_SESSION['the_user'] . '.jpg';
$jpeg_path = '../../../users/user_avatars/' . $_SESSION['the_user'] . '.jpeg';
$gif_path = '../../../users/user_avatars/' . $_SESSION['the_user'] . '.gif';
$png_path = '../../../users/user_avatars/' . $_SESSION['the_user'] . '.png';
$jpg_test = file_exists($jpg_path);
$jpeg_test = file_exists($jpeg_path);
$gif_test = file_exists($gif_path);
$png_test = file_exists($png_path);
</code>

the path is EXACTLY correct I've checked and rechecked and everything. echoed the path and everything else that is relevant. but later when I call if ($png_test == '1') {
blah blah blah
}
it won't return 1. even though I KNOW that the picture is there and it is at that path. if i echo the path in a src for an image it appears. hmm?

I've read as many previous posts as I can find and tried all the suggested solutions but the following simple test code will not work for me (the session variable has been echoed and is correct).   Instead of echoing the correct answer, the if(file_exists($target_file)) skips the true result and always displays the false one.  I've tested it with files that do and don't exist of course.  Here is the code :-

$filename = $_SESSION["filename"];
$target_file = $_SERVER['CONTEXT_DOCUMENT_ROOT'] . '/folder/' . $_SESSION["filename"];

if (file_exists($target_file)) {
    echo 'Selected file is ' . $filename . ' and will be written.';
} else {
    echo "Selected file " . $filename . " doesn't exist.";
} 

I'd really appreciate any help on this please.

Edited July 11, 2020 by oldcelt

Hi,


I am trying to verify if the given url exists or not, by using file_exists() function.

It always returns 'FALSE' , according to my understanding it happening because the file to be checked on the given url is located in safe mode.

Could anyone please suggest as to how this could be overcome, by similar function or by using alternative method.

Regards
Abhishek Madhani

Hello all,

I am a real newby to this but need some help with a file_exists / while loop issue i have.

I am trying to show a table of pictures (with their own ID's) but also if someone hasn't uploaded a picture to the server a default picture will be shown instead.

I get the error: Parse error: syntax error, unexpected T_VARIABLE, expecting ',' or ';' in /home/thefrien/public_html/members1.php on line 103

Here is my code:

$i = 1;
echo "<table border='1' align='center'><tr>";
$result = mysql_query( "SELECT * FROM membership order by L_ID asc" );
while ( $row = mysql_fetch_assoc( $result ) ) {
    echo "<td align='center' bgcolor='#DDDEFF'><a href='profile_view.php?L_ID=".$row["L_ID"] ."'>"
   $pic = 'images/avatar/'. $row["L_ID"] .'s.jpg';   
if (file_exists($pic)) {
   echo '<img src=http://www.thefriendzconnection.co.uk/images/avatar/'.$row["L_ID"] ."s.jpg>";
} else {
   echo '<img src=http://www.thefriendzconnection.co.uk/images/0s.jpg border='0'>';
}
   "</a>
   <br><font size='1' face='Arial, Helvetica, sans-serif'>".$row["name"] ."</font>
   <br><font size='1' face='Arial, Helvetica, sans-serif'>ID: ".$row["L_ID"] ."</font>
   <br>&nbsp;</td>";
    if ( $i % 6 == 0 ) { echo "</tr><tr>"; }
    $i++;
}
mysql_free_result( $result );
echo "</tr></table>";



The line I am having issues with seems to be: $pic = 'images/avatar/'. $row["L_ID"] .'s.jpg';

Any suggestions would be greatfully received

Thanks.

My setup: (everything on a local network)
Web server: Ubuntu Server 8.10 -- Workgroup
File server: Windows Server 2008 x64 -- domain
Test server: Win 2000 running WAMP -- domain

I'm trying to run the code snippet below. $file is a file on the File server above. It definitely exists.
Running the code below on the Test server works perfectly. But the file cannot be found when running from the Web server.
$file = '//server/share/file.txt';
if (file_exists($file))
echo 'yay!';
else
echo 'error';

What with the safe mode considerations, I've also tried to add:
ini_set('safe_mode', 'Off'); to no effect. And since file, and fopen similarly not work, I'm pretty sure it's not that either.

The File & Test servers are on the same Windows domain, but that's definitely not the reason. I tried the code on a file on a Linux computer in the Workgroup (where the Web server is) with the same results: Test server works, Web server does not.

Please advise; I'm really lost.

PHP Warning:  file_exists() expects parameter 1 to be string, array given in /home/mysite/public_html/display.mysite.com/wp-content/themes/mytheme/form.php on line 9

PHP Warning:  file_exists() expects parameter 1 to be string, array given in /home/mysite/public_html/display.mysite.com/wp-content/themes/mytheme/form.php on line 13

I have a form that is having some issues and in the error log I see a bunch of these warnings. What is wrong with this??   I numbered the offending lines below (lines 9 & 13)   Thanks for any help on this.

function CheckExistance($VUrl)

{

/*9*/    if ( file_exists($VUrl) )

        echo $VUrl;

/*13*/    elseif ( file_exists(str_replace('www.display.mysite.com','www.display.com', $VUrl)) )

        echo str_replace('www.display.mysite.com','www.mysite.com', $VUrl);

    else

        echo str_replace('www.mysite.com','www.display.mysite.com', $VUrl);

}

Edited by damion, 02 July 2014 - 06:01 PM.

Hi ppl

got code problem cant get it show users avatar & blank avatar at same time not that good at
php ppl.

avatar box page

Code: [Select]
<style type="text/css">
#name_area{height:20px; padding:3px;};
</style>
<script language="javascript">
<!--
function member_change(id){
<?php
$allgames = mysql_query("SELECT * FROM games") or die (mysql_error());
$allgames_total = @mysql_num_rows($allgames);
if($allgames_total!=0)
{
$i=0;
while($i<$allgames_total)
{
?>
document.getElementById('<?php echo mysql_result($allgames, $i, 'game_id'); ?>').style.display = "none";
<?php
$i++;
}
}
?>
document.getElementById(id).style.display = "block";
}
function show_name(name){

document.getElementById('name_area').innerHTML = name;
}
function hide_name(){
document.getElementById('name_area').innerHTML = '';
}
//-->
</script>

<div style="text-align:left;">
Choose Squad: <select name="D1" onchange="member_change(this.options[this.selectedIndex].value)" class="standardforms">
<?php
$allgames = mysql_query("SELECT * FROM games") or die (mysql_error());
$allgames_total = @mysql_num_rows($allgames);

if($allgames_total!=0)
{
$i=0;
while($i<$allgames_total)
{
$game = mysql_result($allgames, $i, 'game_title');
$members_total2 = mysql_num_rows(mysql_query("SELECT * FROM members WHERE game = '$game'"));

if($members_total2!=0)
{
?>
<option value="<?php echo mysql_result($allgames, $i, 'game_id'); ?>"><?php echo mysql_result($allgames, $i, 'game_title'); ?></option>
<?php
}
$i++;
}
}
?>
</select><br /><br />
</div>
<?php
$allgames = mysql_query("SELECT * FROM games") or die (mysql_error());
$allgames_total = @mysql_num_rows($allgames);
if($allgames_total!=0)
{
$i=0;
while($i<$allgames_total)
{
$game = mysql_result($allgames, $i, 'game_title');
$members = mysql_query("SELECT * FROM members WHERE game = '$game'");
$members_total = @mysql_num_rows($members);

if($allgames_total!=0)
{
?>
<div id="<?php echo mysql_result($allgames, $i, 'game_id'); ?>" style="display: block; text-align:left;">
<?php

if($members_total!=0)
{
$d=0;
while($d<$members_total)
{

?>
<a href="index.php?page=members&amp;id=<?php echo mysql_result($members, $d, 'id'); ?>"><img onmouseover="show_name('<?php echo mysql_result($members, $d, 'username'); ?>')" onmouseout="hide_name()" src="user/<?php

  echo mysql_result($members, $d, 'avatar_link');

$filename = 'avatar_link';

if (file_exists($filename)) {
     echo "avatar_link";
} else {
     echo "avatars/blank.jpg";
}


?>" width="50" height="50" alt="<?php echo mysql_result($members, $d, 'username'); ?>" title="<?php echo mysql_result($members, $d, 'username'); ?>"/></a>
<?php
$d++;
}
}
}
echo "</div>";
$i++;
}
}
?>
<div id="name_area"></div>

From my old gentoo server I run the following code with success. "/mnt/images" is a cifs mount!
Code: [Select]
<?php
$source = '/mnt/images/1001.jpg';
$target = '/tmp/1001.jpg';

if ( file_exists($source) )
echo "file_exists: TRUE<br/>";
else
echo "file_exists: FALSE<br/>";

if ( is_file($source) )
echo "is_file: TRUE<br/>";
else
echo "is_file: FALSE<br/>";

if ( copy($source, $target) )
echo "copy: TRUE<br/>";
else
echo "copy: FALSE<br/>";

echo "filesize source: ".filesize($source)."<br/>";
echo "filesize target: ".filesize($target)."<br/>";
?>The output is
Quote

file_exists: TRUE
is_file: TRUE
copy: TRUE
filesize source: 4715
filesize target: 4715

When I try this on my newly installed CentOS machine I get
Quote

file_exists: FALSE
is_file: FALSE

Warning: copy(/mnt/images/1001.jpg) [function.copy]: failed to open stream: Permission denied in /var/www/html/filetest.php on line 16
copy: FALSE

Warning: filesize() [function.filesize]: stat failed for /mnt/images/1001.jpg in /var/www/html/filetest.php on line 21
filesize source:

Warning: filesize() [function.filesize]: stat failed for /tmp/1001.jpg in /var/www/html/filetest.php on line 22
filesize target:

Every function fails. Then I found that when I disable SELinux with "echo 0 > /selinux/enforce" file_exists() and copy() works.
Quote

file_exists: TRUE
is_file: FALSE
copy: TRUE

Warning: filesize() [function.filesize]: stat failed for /mnt/images/1001.jpg in /var/www/html/filetest.php on line 21
filesize source:
filesize target: 4715

But is_file() and filesize() still doesn't work. They all work when I run them on local files so it is somewhat related to the cifs mount.
What could be the problem here?

I am having problems making it so that if I typed site.php?url=http://example.com it would auto get rid of the http://.

Here's my code.

$url="{$_GET['url']}";
str_replace('http://', '', $url);
echo "<a href=\"http://$url\">$url</a>";

I'm using PHP to get a list of names from a mysql database, which then produces a drop down list for the user to select an option and then progress to the next page where the selection is displayed with other stuff. My problem is that my drop down list works fine, but when the user goes to the next page only the first part of the string is displayed, ie if the string is Fred Bloggs, only Fred is shown. I can get it to work by adding ' ' around the string name in the option section, but this shows 'Fred Bloggs' in the drop down list which isn't very pretty.

I haven't got the actual code to hand at the moment, but any ideas on where I'm going wrong?

Cheers