PHP - Echo $test With Class
Hi there i just need to assign a class to my echoed vairable.
Code: [Select] echo $test class="somecssclass"; Im sure im missing some braces here or something but i cant seem to find it out. Heres the error: Parse error: syntax error, unexpected T_CLASS, expecting ',' or ';' Please help Thanks Similar TutorialsI have an issue that with some testing on an Access class with a method getControlAccess it should only return true or false but as soon as I place a string of any sort into the return my tests always returns true. Any help to point out if it is the way I am testing or the way I have written the method would be great. In the example below it would return true. In one class I have this method Code: [Select] class Access{ public function getControlAccess(){ return 'I am stuffed'; } } In the second class I have this Code: [Select] class AccessTests extends Access{ public function controlAccessTest(){ $return = "<ul>"; if ($this->getControlAccess() == TRUE){ $return .= "<li>getControlAcess should be true and is returning:<b> ". $this->getControlAccess() ."</b></li>"; } elseif ($this->getControlAccess() == FALSE){ $return .= "<li>getControlAcess should be false and is returning:<b> ". $this->getControlAccess() ."<b></li>"; } else { $return .= "<li>getControlAcess is really stuffed:<b>". $this->getControlAccess() ."<b></li>"; } $return .= "</ul>"; return $return; } public function setAccessTest($set){ return $set; } } hello dear friends - i want to test if the DOMdocument [class] exists? Can i do this in the shell (on OpenSuse 11.3)? bool class_exists ( string $class_name [, bool $autoload = true ] ) bool class_exists ( string $DOMdocument [, bool $autoload = true ] ) or do i have to create a file that i call itself in the shell!? look forward for an idea / hint / tipp regards db1 This probably doesn't matter much, but I am using a 'Display' class for final output to the browser. The class will display the obvious HTML header and then display either the full site or the mobile site. It also displays the CSS / JS (which is previously selected in the page-specific controller code as there are variations based on server-side checks). Basically it is the ONLY class that actually needs to send anything to the browser. When I begin output and echo inside the class, that is the end of the script - there is no more server-side code to execute. If I shouldn;t echo inside the class, is it that bad to do so? Hi im having trouble getting the below code to listen to my css margin settings. Just to clear up the server side of things, can anybody tell me wether or not im using the correct syntax in the code below? Code: [Select] else { echo("<p class=\"passed\">Thankyou for submiting your details, you will be added to our directory shortly</p>"); }} Can you echo class constants? This does not work for me. echo “here is a class constant: self::CLASS_CONSTANT”; // using double quotesInstead I *must* concatenate it: echo ‘here is a class constant: ‘ . self::CLASS_CONSTANT;But of course I do not have to do this with a normal variable, which will echo a variable fine: echo “my name is $name_variable”;Am I doing something wrong or is this normal behavior? Edited by E_Leeder, 30 October 2014 - 11:04 AM. OK, have no idea what's going on... I've done this a million times... why wont this output!?? I must have a major brain meltdown and dont know it yet!!! Code: [Select] <?php // this echoes just fine: echo $_POST['testfield']; // but this wont echo: echo if (isset($_POST['testfield'])) { $_POST['testfield'] = $test; } echo $test; /// or even this DOESNT echo either!: $_POST['testfield'] = $test; echo $test; ?> Hi All, I'm trying to echo the response from an SLA query, the query works and returns the data when I test it on an SQL application.. but when I run it on my webpage it won't echo the result. Please help? <?php $mysqli = mysqli_connect("removed", "removed", "removed", "removed"); $sql = "SELECT posts.message FROM posts INNER JOIN threads ON posts.pid=threads.firstpost WHERE threads.firstpost='1'"; $result = mysqli_query($mysqli, $sql); echo {$result['message']}; ?> I have mysqli object in Database class base: [color=]database class:[/color] class Database { private $dbLink = null; public function __construct() { if (is_null($this->dbLink)) { // load db information to connect $init_array = parse_ini_file("../init.ini.inc", true); $this->dbLink = new mysqli($init_array['database']['host'], $init_array['database']['usr'], $init_array['database']['pwd'], $init_array['database']['db']); if (mysqli_connect_errno()) { $this->dbLink = null; } } } public function __destruct() { $this->dbLink->close(); } } Class derived is Articles where I use object dBLink in base (or parent) class and I can't access to mysqli methods (dbLink member of base class): Articles class: require_once ('./includes/db.inc'); class Articles extends Database{ private $id, .... .... $visible = null; public function __construct() { // Set date as 2009-07-08 07:35:00 $this->lastUpdDate = date('Y-m-d H:i:s'); $this->creationDate = date('Y-m-d H:i:s'); } // Setter .... .... // Getter .... .... public function getArticlesByPosition($numArticles) { if ($result = $this->dbLink->query('SELECT * FROM articles ORDER BY position LIMIT '.$numArticles)) { $i = 0; while ($ret = $result->fetch_array(MYSQLI_ASSOC)) { $arts[$i] = $ret; } $result->close(); return $arts; } } } In my front page php I use article class: include_once('./includes/articles.inc'); $articlesObj = new articles(); $articles = $articlesObj->getArticlesByPosition(1); var_dump($articles); [color=]Error that go out is follow[/color] Notice: Undefined property: Articles::$dbLink in articles.inc on line 89 Fatal error: Call to a member function query() on a non-object in articles.inc on line 89 If I remove constructor on derived class Articles result don't change Please help me Ok. I know you can pass the object of a class as an argument. Example: class A { function test() { echo "This is TEST from class A"; } } class B { function __construct( $obj ) { $this->a = $obj; } function test() { $this->a->test(); } } Then you could do: $a = new A(); $b = new B($a); Ok so that's one way i know of. I also thought that you could make a method static, and do this: (assuming class A's test is 'static') class B { function test() { A::test(); } } But that is not working. I'd like to know all possible ways of accomplishing this. Any hints are appreciated. thanks Hi Can you call Class A's methods or properties from Class B's methods? Thanks. If a class has a constructor but also has a static method, if I call the static method does the constructor run so that I can use an output from the constructor in my static method? --Kenoli I have an existing instance of my class Database, now I want to call that instance in my Session class, how would I go about doing this? Hi, I need to be able to call a class based on variables. E.G. I would normally do: Code: [Select] $action = new pattern1() but i would like to be able to do it dynamicaly: Code: [Select] $patNum = 1; $action = new pattern.$patNum.() Im wondering if that's possible? If so what would the correct syntax be? Many Thanks. I have a log system that allows 10 logs on each side(Left and right). I am trying to make it so that the left side has the 10 most recent logs, then the right as the next 10. Any ideas? So I need to echo a row from my database with php, but where i need to echo is already inside an echo. This is my part of my code: $con = mysql_connect("$host","$username","$password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("main", $con); $result = mysql_query("SELECT * FROM Vendor"); while($row = mysql_fetch_array($result)) { //I need to echo right here .................. but I get a blank page when I try this. Please Help. echo '<option value=$row['vendor_id']>'; echo $row['vendor_id']; echo '</option>'; } mysql_close($con); Result: A Blank page. Thanks in advance! Hi
so i've been learning php for 3 mouth now by reading php 6 Bible and watching lynda and so on...
i was looking for a job in few past weeks and i found out i don't have that kind of self confidence to go for it ! you know when they say : PHP Project Manager , it scar's me...
the thing is , i know all about basic to medium php , array...MySQL....all those essentials but i don't know what do they want from a php web developer .
so i began to search for intern job somewhere and i told myself i should bust my ass 24/7 for few mouth and after that i ll be real php guy and it seems like there is no place to reach not php but almost all programming languages
a year ago i was searching for the same thing but in networking section and there was 100's of intern ship jobs but in programming there is none !
so i want some one to give me (us) simple to pro real life projects .
what do they want php junior or senior developer's for ? what do they do?
what is the most common needs ?
what is the most essential things to know?
what is a hired php developer should do in the office?
some people doesn't need you in the office and want you to work from home , they give you project's , what's that?
is there any source in the web to offer what is need ?
i know its too much , but this was my last option , so if anyone can help i would practically owe him/her my whole future salaries...
Hello All happy new year I am trying to make a php page that detects if something is plugged in to the ethernet port. This would be complex if not impossible. I however managed to do something similar the device that will be plugged in has a static address 192.168.1.1. so I created a ping that says if the device is up or down. function ping($host, $port, $timeout) { $fP = fSockOpen($host, $port, $errno, $errstr, $timeout); $status; if ($fP) { echo "Device is ready to accept data";} else { echo "Device Down - Retrying connection"; } } What I would like to do is have a script that is constantly checking is the device is plugged or when it is not (so sort of a loop or auto detect). The idea is to have an image with the device up or down. Regards and a happy new year JG I am trying to select text to display on condition of the current date. I've set a Unix timestamp for the current date: <?php $todays_date = date("Y-m-d"); $today = strtotime($todays_date); ?> Next I test for the first condition. I want the text to appear for 2 weeks then terminate: <?php $exp_date = "2011-05-09"; $expiration_date = strtotime($exp_date); $start_date = strtotime("-14 days", $expiration_date); if ($start_date < $today && $expiration_date > $today) { echo "<h2>Special Event #1</h2>"; } elseif { At this point, I want to set the exp_date for the next event and test again, but I don't know how to do it. The techniques I've tried appear to evaluate as false and display the default text which follows the final "else": } else { echo "<h2>Default Text</h2>"; } ?> I got this script for change language and don't know is it working. In this array are supported language s for this site, so if you come from some of this 7 country should open your language, for others english version. Don't know any other way to test it! http://www.lacman.hr/index.php Code: [Select] $jezici = array("hr", "en", "de", "it", "fr", "cz", "pl"); write the algorithm to draw a sphere, the function should have parameters 1. diameter (how many line) 2. character (use which character to draw) eg, draw_sphere(10, '8') will produce: 88888 8888888888888 8888888888888888888 888888888888888888888 88888888888888888888888 88888888888888888888888 888888888888888888888 8888888888888888888 8888888888888 88888 the above is a sphere of 10 lines, which is drawn using the character "8" i cant figure out how to do it, thanks in advanved! |