PHP - Selecting Parts Of An Extracted Mysql Array Row

How can i use
$query = "SELECT * FROM klanovi WHERE naziv = '{$trazi}' OR tag =  '{$trazi}'";
but i need to search from base where that $trazi is contained in naziv or tag, i mean like wildacards?
And how can i search that text but no matter of lowercase or uppercase ?

Hey guys,

I have a drop down menu like so <select name="Categories[]">
                                                     <Option value="Horror" Name="Horror">Horror</Option>
                                                     <Option value="Romance" Name="Romance">Romance</Option>

                                                     .........................................

Like that, just out of interest once the user has selected the option I am unsure on how to extract what the user chose from the drop down menu, how do you grab the value from array of the drop down menu that the user has selected. Any help A.S.A.P would really be appreciated. It also has to be an array.

I also thought of using the $_POST['Categories']; to try grab the value if that is the correct way to go about it.


Thank you in advance.

Hello. Many thanks for your help.

I am writing a PHP/MySQL dating-site and have hit a programming impass.

I have a database full of members and a search form consisting of checkboxes.

So to search, a member ticks say...gender: female; age: 21,22,23,24,25,26; height: 5'4",5'5",5'6",5'7"; county: cornwall,devon,somerset

How can a run a check on the database selecting all entries that fall into the selected criteria. For example a 23 year old female of 5'5" living in Cornwall and a 26 year old female of 5'4" living in Somerset?

The key index of my database is 'id' and the fields a age,height,county
The names of the form checkboxes a
Gender: male, female; Age: 21,22,23,24 etc; Height: 5_4,5_5,5_6 etc; county: cornwall,devon etc

Hi all,

I am trying to get data from MySQL to display in a html table in TCPDF but it is only displaying the ID.

$accom = '<h3>Accommodation:</h3>
<table cellpadding="1" cellspacing="1" border="1" style="text-align:center;">
<tr>

<th><strong>Organisation</strong></th>
<th><strong>Contact</strong></th>
<th><strong>Phone</strong></th>
</tr>
<tbody>
<tr>'.
$id = $_GET['id'];
$location = $row['location'];
$sql = "SELECT * FROM tours WHERE id = $id";
$result = $con->query($sql);

if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {

'<td>'.$location.'</td>
<td>David</td>
<td>0412345678</td>
</tbody>';
}
}
'</tr>
</table>';

Anyone got any ideas?

I have the following code, and really can't see what is wrong with it. Any help would be great.

<?php
if (!mysql_connect('127.0.0.1', 'root', '')) {
echo 'Could not connect to mysql';
exit;
}

$dbname = 'Requests';
$result = mysql_list_tables($dbname);
if (!$result) {
echo "DB Error, could not list tables\n";
echo 'MySQL Error: ' . mysql_error();
exit;
}

while($row2 = mysql_fetch_row($result)) {
   foreach ($row2[0] as $table_id) {
      
$query = "SELECT * FROM $table_id";
$dbresult = mysql_query($query);

// added code to use the tablename and select all records from that table
// create a new XML document
$doc = new DomDocument('1.0');
// create root node
$root = $doc->createElement('mixes');
$root = $doc->appendChild($root);
// process one row at a time
while($row = mysql_fetch_assoc($dbresult)) {
     // add node for each row
  $occ = $doc->createElement($table_id);
  $occ = $root->appendChild($occ);
   // add a child node for each field
  foreach ($row as $fieldname => $fieldvalue) {
       $child = $doc->createElement($fieldname);
    $child = $occ->appendChild($child);
   $value = $doc->createTextNode($fieldvalue);
    $value = $child->appendChild($value);
     } // foreach
} // while
}
}


echo 'Wrote: ' . $doc->save("s.xml") . ' bytes'; // Wrote: 72 bytes

?>

Hi, basically, here's the deal:
I have a lit of checkboxes that are added by the admin (there's an unlimited amount, just depends on how many are added). Then, those are put in a form, in which the user picks whichever ones need to be chosen and those values get sent to a MySQL table.

Here's the code that displays the checkboxes

Code: [Select]
<?php
$sql="SELECT * FROM category ORDER BY categoryID ASC";
$result=mysql_query($sql); 

while($row=mysql_fetch_array($result)){
    echo "<input type='checkbox' id='". $row['categoryName'] ."' name='licensed[]' value='" . $row['categoryID'] ."' /><label for='". $row['categoryName'] ."'><br>" . $row['categoryName'] ."</label><br>";
}
?>
What I'm making now, is an edit form where whichever checkboxes were checked, will show up checked in the edit form. But I'm not really sure how to go about this, since there is only one actual input tag in the code, I can't select the different ones.

I also have this SQL query which selects whichever boxes were inputted into the DB

Code: [Select]
$sql2="SELECT * FROM category, categoryInfo WHERE category.categoryID = categoryInfo.categoryID AND categoryInfo.parentID = $parentID";
$result2=mysql_query($sql2);
Where $parentID is the ID of whichever form you're editing.

But yes, I'm basically not really sure how to go about this and would like some help figuring this out

Thanks for your time

I wish to return the object in an array with the highest index where its index falls between between integers, and return null should one not exist.

For instance, with the following and a min and max of 10,000 and 15,000, it should return OBJ4, and with a min and max of 15,000 and 20,000 it should return NULL.

Any thoughts?  Thanks

function getObj(int $min, int $max):?OBJ {
    $list=[
        12314=>'OBJ1',
        321=>'OBJ2',
        42142=>'OBJ3',
        14314=>'OBJ4',
        123=>'OBJ5',
        13314=>'OBJ6'
    ];
    return getIt($list, $min, $max);
}

 

We recently upgraded from PHP4 to PHP5 and the below script that was working perfectly in 4 has completely stopped working and I can't figure out why for the life of me. I'm not an experienced PHP programmer--I've done some forms, but this is the first time I've used a database.

What needs to (and was) happen: A user enters their username in the form and gets a readout of their participation so far that month.

The problem(s): I know that it's storing the variable 'user' because it echoes it back properly, but the database is no longer allowing me to select the row based on that variable. I know it's not that I can't connect to the database because if instead of '$user' I change the code to a username I know is in there, I get the proper readout. This all started as soon as I transferred over to PHP5--before that, no problems at all.

The database information is all correct, I just took it out for privacy's sake.

<form id="feedback" method="post" action="index.php">

<input name="user" type="text" value="Enter user name" size="20" maxlength="50" /><br />

<input name="send" id="send" type="submit" value="Submit" />
</form>
<?php
if (isset($_POST['user'])) { 
$_session['user'] = $_POST['user'];
} 
?>

<p>You entered your username as: <strong><? echo $_session['user'];?></strong>. If this is not correct or you do not see your information below, please re-enter your username and click Submit again.</p>

<?php
$con = mysql_connect("database","username","password");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("database", $con);

$result = mysql_query("SELECT * FROM March WHERE Username='$user'") or die ('Error: '.mysql_error ());

while($row = mysql_fetch_array($result))
  {
  echo "<table border='0'>";
  echo "<tr>";
  echo "<td><strong>Username:</strong> </td><td>" . $row['Username'] . "</td></tr>";
  echo "<tr><td><strong>Mar. 2 Discussion:</strong></td><td>" . $row['Mar2Q'] . "</td></tr>";
  echo "<tr><td><strong>Mar. 2 Poll:</strong></td><td>" . $row['Mar2P'] . "</td></tr>";
  echo "<tr><td><strong>Mar. 9 Discussion:</strong></td><td>" . $row['Mar9Q'] . "</td></tr>";
  echo "<tr><td><strong>Mar. 9 Poll:</strong></td><td>" . $row['Mar9P'] . "</td></tr>";
  echo "<tr><td><strong>Mar. 16 Discussion:</strong></td><td>" . $row['Mar16Q'] . "</td></tr>";
  echo "<tr><td><strong>Mar. 16 Poll:</strong></td><td>" . $row['Mar16P'] . "</td></tr>";
  echo "<tr><td><strong>March Participation To-Date:</strong></td><td>" . $row['Participation'] . "</td></tr>";
  echo "</tr>";
  } 
  echo "</table>";

mysql_close($con);
?> 

ANY help would be greatly appreciated! I've got a couple hundred people who use this on a regular basis and are starting to ask why it's not working.

SELECT * FROM `booking_tbl` WHERE booking_status = 'Check In' AND departure_date_time = NOW()"

I use the datetime datatype for the departure_date_time so i can get data from that data because it checking the date and time   but i want it to check on the date from the datetime datatype   So how can i get the data only with that date without the time in the mysql datetime datatype

I am trying to make a filter to show posts from mutual friends between you and the persons profile you're on, I have somewhat of an idea on how to write the mysql query (it needs to be just one query, not two(which would be the easy way of doing it)).

the "friends" table has:
"friend_1" and "friend_2"

and the "posts" table:
"to_id" and "from_id"

The PHP variables would be:
"$session" and "$id"
id would be the users Id of the profile you're on.

Thanks, any help would be appreciated.

My query gets the results and orders by one of the fields.

Once I get the MySQL results I would like to find the first entry that has a letter as the first character of the same field that the list was ordered by, then split the results in to two parts and swap them.

So that the results that have a letter at the start of the same sorted field are as the begining and the results that have the numbers as the start at the end of the array.

But also so that the array works the same way as the original results string, so i can use say $results['mysqlfield']

Hi I am trying to select and order data/numbers from a colum in a mysql data base however i run the code and it returns no value just a blank page no errors or any thing so i think the code is working right but then it returns no result? Please help thanks

Here is the code:

<?php
$host= "XXXXXX";
$mysql_user = "XXXXXX";
$mysql_password = "XXXXXX";
$mysql_database = "XXXXXXX";

$connection = mysql_connect("$host","$mysql_user","$mysql_password") or die ("Unable to connect to MySQL server.");
mysql_select_db($mysql_database) or die ("Unable to select requested database.");

$row = mysql_fetch_assoc( mysql_query( "SELECT XP FROM Game ORDER BY number DESC LIMIT 1" ) );
$number = mysql_result(mysql_query("SELECT XP FROM Game ORDER BY number DESC LIMIT 1"), 0);

echo "The the highest XP is $number";

?>

How can i save array from inputs, witch is $igraci and it have 5 values, to mysql base, i tryed but in mysql it shows Array.
This is form:
        <form action="dodaj_klan.php" method="post" >
            <p>
            <label>Naziv klana:</label>
            <input name="naziv" type="text" size="20%" />
            <label>Web Sajt:</label>
            <input name="website" type="text" size="20%" />
            <label>E-Mail:</label>
            <input name="email" type="text" size="20%" />
            <br /><br />
            <label>Igraci klana(5):</label>
            <input name="lider" type="radio" value="1" />
            <input name="igraci[]" type="text" size="20%" /><br />
            <input name="lider" type="radio" value="2" />
            <input name="igraci[]" type="text" size="20%" /><br />
            <input name="lider" type="radio" value="3" />
            <input name="igraci[]" type="text" size="20%" /><br />
            <input name="lider" type="radio" value="4" />
            <input name="igraci[]" type="text" size="20%" /><br />
            <input name="lider" type="radio" value="5" />
            <input name="igraci[]" type="text" size="20%" />
            <label><i>(obelezi lidera klana)</i></label>
            <br /><br />
            <input class="button" type="submit" name="submit" value="Dodaj" />&nbsp;&nbsp;
            </p>
        </form>
Now i wonna save this igraci[] array in mysql, i tried like this but it doesn't work:
$igraci = $_POST['igraci'];
$query = "INSERT INTO klanovi (naziv, website, email, igraci) VALUES ('{$naziv}', '{$website}', '{$email}', '{$igraci}')";
$result = mysql_query($query, $connection);

How can i do this?
Thanks..

So I'm querying my database to add the results (mapID's) into a PHP array.
The MySQL query I used in the below code would usually return 10 values (only 10 mapID's in the database)

Code: [Select]
while($data = mysql_fetch_array(mysql_query("SELECT mapID FROM maps"))){
$sqlsearchdata[] = $data['mapID'];
}
Instead the page takes ages to load then gives this error:
Quote

Fatal error: Allowed memory size of 8388608 bytes exhausted (tried to allocate 16 bytes)

It says the error begins on the first line of the above code. I'm assuming this is not the right way to add the value from the MySQL array into a normal PHP array.

Can anyone help me?

Hello everyone,

Sorry if this has been answered but if it has I can't find it anywhere. So, from the begining then.  Lets say I had a member table and in it I wanted to store what their top 3 interests are.  Their$ row has all the usual things to identify them userID and password etc.. and I had a further 3 columns which were labled top3_1 top3_2 & top3_3 to put each of their interests in from a post form.

If instead I wanted to store this data as a PHP Array instead (using 1 column instead of 3) is there a way to store it as readable data when you open the PHPmyadmin?

At the moment all it says is array and when I call it back to the browser (say on a page where they could review and update their interests) it displays 'a' as top3_01 'r' as top3_02 and 'r' as top3_03 (in each putting what would be 'array' as it appears in the table if there were 5 results. Does anyone know what I mean?

For example -

If we had a form which collected the top 3 interests to put in a table called users,

Code: [Select]
<form action="back_to_same_page_for_processing.php" method="post" enctype="multipart/form-data">
   
    <input name="top3_01" type="text" value="enter interest number 1 here" />
    <input name="top3_02" type="text" value="enter interest number 2 here" />
    <input name="top3_03" type="text" value="enter interest number 3 here" />
    <input type="submit" name="update_button" value=" Save and Update! " />

   
    </form> // If my quick code example for this form is not correct dont worry its not the point im getting at :)
And they put 'bowling' in top3_01, 'running' in top3_02 and 'diving' in top3_03 and we catch that on the same page with some PHP at the top -->

Code: [Select]
        if (isset($_POST)['update_button']) {
   
    $top3_01 = $_POST['top3_01']; // i.e, 'bowling' changing POST vars to local vars
    $top3_02 = $_POST['top3_02']; // i.e, 'running'
    $top3_03 = $_POST['top3_03']; // i.e, 'diving'

With me so far? If I had a table which had 3 columns (1 for each interest) I could put something like -

  Code: [Select]
   include('connect_msql.php');
   
    mysql_query("Select * FROM users WHERE id='$id' AND blah blah blah");
   
    mysql_query("UPDATE users SET top3_01='$top3_01', top3_02='$top3_02', top3_03='$top3_03' WHERE id='$id'");


And hopefully if ive got it right, it will put them each in their own little column. Easy enough huh? But heres the thing, I want to put all these into an array to be stored in the 1 column (say called 'top3') and whats more have them clearly readable in PHPmyadmin and editable from there yet still be able to be called back an rendered on page when requested.

Continuing the example then, assuming ive changed the table for the 'top3' column instead of individual colums,  I could put something like this -


Code: [Select]
            if (isset($_POST)['update_button']) {
       
        $top3_01 = $_POST['top3_01']; // i.e, 'bowling' changing POST vars to local vars
        $top3_02 = $_POST['top3_02']; // i.e, 'running'
        $top3_03 = $_POST['top3_03']; // i.e, 'diving'
   
    $top3_array = array($top3_01,$top3_02,$top3_03);
   
    include('connect_msql.php');
   
    mysql_query("UPDATE members SET top3='$top3_array' WHERE id='$id' AND blah blah blah");
But it will appear in the column as 'Array' and when its called for using a query it will render the literal string. a r r in each field instead.  Now I know you can use the 'serialize()' & 'unserialize()' funtcions but it makes the entry in the database practically unreadable. Is there a way to make it readable and editable without having to create a content management system?

If so please let me know and I'll be your friend forever, lol, ok maybe not but I'd really appreciate the help anyways.  The other thing is, If you can do this or something like it, how am I to add entries to that array to go back into the data base?

I hope ive explained myself enough here, but if not say so and I'll have another go.  Thanks very much people,  L-PLate (P.s if I sort this out on my own ill post it all here)