PHP - Help With Converting A Date

I have tried a large number of "solutions" to  this but everytime I use them I see 0000-00-00 in my date field instead of  the date even though I echoed and can see that the date looks correct.

Here's where I'm at:
I have a drop down for the month (1-12) and date fields (1-31) as well as a text input field for the year.  Using the POST array, I  have combined them into the xxxx-xx-xx format that I am using in my field as a date field in mysql. 

<code>
$date_value =$_POST['year'].'-'.$_POST['month'].'-'.$_POST['day'];
echo $date_value;
</code>

This outputs 2012-5-7 in my test echo but 0000-00-00 in the database.

I have tried unsuccessfully to use in a numberof suggested versions of:
strtotime()
mktime

Any help would be extremely appreciated.
I am aware that I need to validate this data and insure  that it is a valid date. That I'm okay with. I would like some help on getting it into the database.

Hi,

I have a job listing website which displays the closing date of applications using:

$expired_date

(This displays a date such as 31st December 2019)

I am trying to show a countdown/number of days left until the closing date.

I have put this together, but I can't get it to show the number of days.

                    <?php 
                    $expired_date = get_post_meta( $post->ID, '_job_expires', true );
                    $hide_expiration = get_post_meta( $post->ID, '_hide_expiration', true );
                    if(empty($hide_expiration )) {
                        if(!empty($expired_date)) { ?>
                                <span><?php echo date_i18n( get_option( 'date_format' ), strtotime( get_post_meta( $post->ID, '_job_expires', true ) ) ) ?></span>
                    
                    <?php
                                        $datetime1 = new DateTime($expired_date);
                                        $datetime2 = date('d');
                                        $interval = $datetime1->diff($datetime2);
                                        echo $interval->d;

                     ?>
                        <?php }
                    } 
                    ?>

Can anyone help me with what I have wrong?

Many thanks

(continuing from topic title)
So if I set a date of July 7 2011 into my script, hard coded in, I would like the current date to be checked against the hard coded date, and return true if the current date is within a week leading up to the hard coded date.

How could I go about doing this easily?

I've been researching dates in php but I can't seem to work out the best way to achieve what I'm after.

Cheers
Denno

Hi Guys..

How can I change a date on the fly ?
Everything is UTC on my server.

How can I change a date to something else on the fly?

Ie:

$timezone = "cet";
$datetime = "2011-09-04 19:53:00";

echo $datetime($timezone);

So I can give it a datetime and have it echo the datetime as if it were in the other timezone?

Thanks
Graham

I'm getting this Time Zone error.
Perhaps it's a compatibility issue with PHP 5.3. Looked all over for an answer without finding one.
Here is the error message


Warning: date() [function.date]: It is not safe to rely on the system's timezone settings.
You are *required* to use the date.timezone setting or the date_default_timezone_set() function.
In case you used any of those methods and you are still getting this warning,
you most likely misspelled the timezone identifier. We selected 'America/New_York' for 'EST/-5.0/no DST'
instead in /blocked.php on line 41
12/02/12

Here is the code. Line 41 is near the bottom, the one with the d,m,y.  Perhaps the echo date (d/m/y") needs to be changed. Appreciate any help!

Code: [Select]
   <table border="3" width="16%" align="center" cellspacing="0" bgcolor="#FF6600" bordercolor="red" bordercolordark="red" bordercolorlight="red">
                            <tr>
                                    <td width="176">

                                            <p align="center"><?php // shows IP Number on Page
            echo $ip; ?> </p>

                                    </td>
                            </tr>
                    </table>
                    <p align="center"><?php // Show the user agent
        echo 'Your user agent is: <b>'.$_SERVER['HTTP_USER_AGENT'].'</b><br />';?></p>
                    [b]<h1 align="center"><?php echo date("d/m/y");?></h1>[/b]
            </td>
    </tr>
</table
[,code]

Hi there,

I have a string '12/04/1990', that's in the format dd/mm/yyyy.

I'm attempting to convert that string to a Date, and then insert that date into a MySQL DATE field.

The problem is, every time I try to do so, I keep getting values like this in the database: 1970-01-01.


Any ideas?


Much appreciated.

Hi guys, I'm putting together a small event system where I want the user to add his own date and time into a textfield (I'll probably make this a series of drop-downs/a date picker later).
This is then stored as a timestamp - "0000-00-00 00:00:00" which displays fine until I try to echo it out as a UK date in this format - jS F Y, which just gives today's date but not the inputted date.



Here's the code I have right now:

Code: [Select]
$result = mysql_query("SELECT * FROM stuff.events ORDER BY eventdate ASC");

echo "<br />";
echo mysql_result($result, $i, 'eventvenue');
echo ", ";

$dt = new DateTime($eventdate);

echo $dt->format("jS F Y");


In my mysql table eventdate is set up as follows:
 
field - eventdate
type - timestamp
length/values - blank
default - current_timestamp
collation - blank
attributes - on update CURRENT_TIMESTAMP
null - blank
auto_increment - blank


Any help as to why this could be happening would be much appreciated, thanks.

Hi, Currently I am making a module for joomla. every article has an publish date, if the article was published in 7 days ago, it will displayed as "article in last week", My idea is to use today's date - publish date, if the result is greater than 7 and smaller than 14, the article will be displayed as "article in last week.
Any one know how to write this code?
Here is what I have got, but not working.

<?php
$todays_date = date("Y-m-d"); 

$result = mysql_query("select * from jos_content where $test between $todays_date-14 and $todays_date-7");  
while($row = mysql_fetch_array($result))
  {
echo "$todays_date - $row[title]";
}
?>

i have a table that shows payments made but  want to the payments only showing from a set date(06/12/14) and before this date i dont want to show   this is my sql that doesnt seem to work and is showing dates before the specified date. .

"SELECT * FROM payments2014, signup2014, editprop2014 WHERE signup2014.userid = payments2014.payment_userid AND editprop2014.prop_id = signup2014.prop_id AND signup2014.userid !='page1' AND signup2014.userid !='page6' AND signup2014.userid !='page4' AND payments2014.payment_transaction_status !='none' AND payments2014.payment_transaction_status !='CANCELLEDa' AND payments2014.payment_type !='deposit' AND payments2014.payment_paid_timestamp NOT LIKE '%2012%' AND payments2014.payment_paid_timestamp NOT LIKE '%2011%' AND payments2014.payment_paid_timestamp >= '06/12/14' ORDER BY payments2014.payment_id DESC"

i have some other parts in the statment but this one that should be filtering is 

host_payments2014.payment_paid_timestamp >= '06/12/14' 

thanks in advance

Hi,

I am trying to convert a String date into numeric date using PHP function's, but haven't found such function.
Had a look at date(), strtotime(), getdate();

e.g. Apr 1 2011  ->    04-01-2011

Could someone please shed some light on this?

Regards,
Abhishek

Hi Guys,

I am trying to use htmlentities and htmlspecialchars to convert a ampersand (&) to the html markup eqivalant (&amp;) to no avail. any ideas ?

htmlentities("this is & that");

Would someone please take a look at this.

I am trying to use a form to allow users to answer yes or no with radio buttons, and then print it out on another page.
I can only get the script to print the number 1 no matter which button is selected.
When I check the database the number 1 is recorded no matter which button is selected.
In the top of the input form I have
Code: [Select]
<input type='hidden' name='electricity' value='0'>In the body of the input form I have
Code: [Select]
Electricity <input type='radio' name='electricity' value='0'>no <input type='radio' name='electricity' value='1'>yesAnd on the output page I have
Code: [Select]
$electricity = $row['electricity'];
if ($electricity == 1) 
{
$answer = "YES";
}
else
{
$answer = "NO";
}and
Code: [Select]
echo $row['electricity'];I have been over and over this and can not discover my error.
Thank you for looking.

xml file:
Code: [Select]
<PRICES>
<PRICE>
<WIC>HDE0AAFGRBOX</WIC>
<STOCK>100+</STOCK>
<MY_PRICE>219.00</MY_PRICE>
</PRICE>
</PRICES>php file:
Code: [Select]
<?
$filexml='stock.xml';
if (file_exists($filexml)) {
$xml = simplexml_load_file($filexml);
$f = fopen('stock.csv', 'w');
foreach($xml->PRICES->PRICE as $price) {
fputcsv($f, get_object_vars($price),',','"');
}
fclose($f);
}
?>
Error:
Warning: Invalid argument supplied for foreach() in C:\xampp\htdocs\stock.php on line 6

Please help with this.

Hi All,

I am trying to "echo" a result from a SQL query, that returns a size in KB, but I want this to read in MB or GB - can PHP change this for me, or is it something I need to do in SQL?

Cheers
Matt