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PHP - Php Date() Function
Hi all,
I want to include the date and time in the web page to display when a user logged into the site. I found a code.I want to know how it could modify with relevant to our local time? <?php $today = date("d M Y h:i A"); echo $today ?> Thanks, Similar TutorialsI'm getting this Time Zone error. Perhaps it's a compatibility issue with PHP 5.3. Looked all over for an answer without finding one. Here is the error message Warning: date() [function.date]: It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'America/New_York' for 'EST/-5.0/no DST' instead in /blocked.php on line 41 12/02/12 Here is the code. Line 41 is near the bottom, the one with the d,m,y. Perhaps the echo date (d/m/y") needs to be changed. Appreciate any help! Code: [Select] <table border="3" width="16%" align="center" cellspacing="0" bgcolor="#FF6600" bordercolor="red" bordercolordark="red" bordercolorlight="red"> <tr> <td width="176"> <p align="center"><?php // shows IP Number on Page echo $ip; ?> </p> </td> </tr> </table> <p align="center"><?php // Show the user agent echo 'Your user agent is: <b>'.$_SERVER['HTTP_USER_AGENT'].'</b><br />';?></p> [b]<h1 align="center"><?php echo date("d/m/y");?></h1>[/b] </td> </tr> </table [,code] $date=date("Y-m-d H:i:s"); This is returning me the GMT time instead of EST. I get 15:26:08 as the time instead of 10:26:08. How can I get around this? How would you use the date function to display a birthday with an user's input? Hello Again guys, I have varous dates stored in a database , these dates can look like this 2010-08-06 07/08/2010 07-08-2010 The problem is I dont know what format they are stored in.. What I need is a function which takes in 1 date at a time and returns it in a format I need it to be.. the format I need is 07/08/2010 thank you again for all you help I have been looking at thr date() but not been able to answer my qustion yet I am doing somthing complicated with dates and I think I am making it harder than I should. I need to subtract "x" number of months from the current date, then create 2 dates in that month that represent the first day, and last day of the month. Then make it in a format that SQL can read to get the SUMS I need between those dates. My last 2 strtotimes are wrong and are giving me the 1969 dates. Code: [Select] function commiss($nummonth){ $repnum = $_SESSION['REPID']; $date = date("Y-m-d", strtotime("-" . $nummonth . "")); $time2 = " 00:00:01"; $time = " 23:59:59"; $date1 =date("Y-m-d", strtotime(date('m').'/01/'.date('Y'))); $date2 =date("Y-m-d", strtotime('-1 second',strtotime('+1 month',strtotime(date('m').'/01/'.date('Y'))))); $date1 = date("Y-m-d", strtotime("-" . $nummonth . "", $date1)); $date2 = date("Y-m-d", strtotime("-" . $nummonth . "", $date2)); $date1 = $date1 . $time2; $date2 = $date2 . $time; $string = "SELECT SUM(premium), SUM(repcom) FROM commission WHERE repnum = '$repnum' BETWEEN '$date1' AND '$date2'"; $sqltotal = mysql_query($string)or die (mysql_error()); $sqlprem = mysql_fetch_array('[SUM(premium)]'); $sqlcomm = mysql_fetch_array('[SUM(repcom)]'); echo "Premium: " . $sqlprem; echo "\n Rep Commission: " . $sqlprem; } i just want to display the values form database which i have saved before and just want to be displayed when specific time comes as i told above in e.g if i have stored some thing like value let say ( 10,20,30,40 and so on ) in database now i just want a php code to display it on site but on specific time only like this, i time = 10:00am display value = 10 when time = 10:30am display value = 20 when time = 11:00am display value = 30 and so own simple. Hi, I have the following code which lists all the dates since October 5th 2007 until yesterday's date, and displays it as a link. This part works fine. What I want to do is omit the weekends, so the first few lines would read like so: 05/10/2007 08/10/2007 09/10/2007 10/10/2007 11/10/2007 12/10/2007 15/10/2007 Does anyone know how I can modify this code, or have any other methods of doing this? Code: [Select] <?php function dates_between($start_date, $end_date = false) { if ( !$end_date ) { $end_date = date("Y-m-d"); } $start_date = is_int($start_date) ? $start_date : strtotime($start_date); $end_date = is_int($end_date) ? $end_date : strtotime($end_date); $end_date -= (60 * 60 * 24 + 1); $test_date = $start_date; $day_incrementer = 1; do { $test_date = $start_date + ($day_incrementer * 60 * 60 * 24); echo '<a href="http://markets.ft.com/RESEARCH/markets/DataArchiveFetchReport?Category=CU&Type=WORL&Date=' . date("m/d/Y", $test_date) . '">' . date("d/m/Y", $test_date) . "\n</a><br>"; } while ( $test_date < $end_date && ++$day_incrementer ); } dates_between("2007-10-04"); echo "\n\n"; ?> Thanks, Dave I am scraping Birthdays from a webpage that are in this format September 15, 1987 $age = 15; $page = source code of a html page; so far i have made this function How do i return the function as true if the date scaped makes the person over 15 and false if the person is younger? function checkForAge($page,$age) { preg_match('|Born on ([a-zA-Z]*\s[0-9]*,\s[0-9]*)\\\u003c\\\/span>|', $page, $match); if($match && count($match)>0) { echo "Match Found"; $dateOfBirth = str_replace(",","",$match[1]); // $dateOfBirth = date('d/m/Y', strtotime($dateOfBirth)); $dateOfBirth = strtotime($dateOfBirth); /* if("date of birth makes person over $age) { return true; } else { return false; } */ } Hi there, what I have been trying to do is add some additional logic.. My problem is I want to stop displaying the month and day after the year 2000? I know I need to add an if and else statement but this is my first actual project and I am a little stuck.. here is the page, it's a plugin for a timeline http://www.llandover...oject-timeline/
And the file is attached below.. any help would be appreciated. The plugin code was too long to just post in here, didn't want to cause any slow loading issues for people on a slow connection.. Thanks and I appreciate any help.
Attached Files
annual_archive.php 18.15KB
5 downloads want something like: Code: [Select] date('F j, Y, g:i a') but in central timezone, how do I change the timezone to central? hello i got this small function i`m working on to get the date of a month something like get current date - 1 but not sure how to handle jan month can someone help me please ? $month = date('m') - 1; $date_startt = date('Y').'-'.$luna.'-01'; $timestamp_start = strtotime($data_start); Hi, I am using this function to output a list of dates for every friday over the next 12months. This is working fine. Code: [Select] [php] //function function nextWeeksDay($date_begin,$nbrweek) { $nextweek=array(); for($i = 1; $i <= $nbrweek; $i++) { // 52 week in one year of course $nextweek[$i]=date('Y-m-d', strtotime('+'.$i.' week',$date_begin)); } return $nextweek; } /// end function /// example of a select date // var $date_begin=strtotime('this Friday'); $nbrweek=52; // call function $result=nextWeeksDay($date_begin,$nbrweek); // Insert //$date1=date('Y-m-d', $date_begin); for($i = 1; $i <= $nbrweek; $i++) { //$date=$result[$i]; echo $result[$i]."<br/>"; } [/php] My problem is that when I alter the code to try and get the date for every second Friday for the next year the script freezes. Code: [Select] [php] //function function nextWeeksDay($date_begin,$nbrweek) { $nextweek=array(); for($i = 2; $i <= $nbrweek; $i+2) { // 52 week in one year of course $nextweek[$i]=date('Y-m-d', strtotime('+'.$i.' week',$date_begin)); } return $nextweek; } /// end function /// example of a select date // var $date_begin=strtotime('this Friday'); $nbrweek=52; // call function $result=nextWeeksDay($date_begin,$nbrweek); // Insert //$date1=date('Y-m-d', $date_begin); for($i = 2; $i <= $nbrweek; $i+2) { //$date=$result[$i]; echo $result[$i]."<br/>"; } [/php] I really don't understand why?? Does anyone know why? Thanks I am working on a project where I need PHP and mysql to perform calculations on dates, so I am storing them in the mysql format 2011-09-12, I am writing a custom function that will convert this into a date('M d Y') format, but all I get when I run my function is "1" This is my first custom function, so i am sure it is a simple fix, I am just at the end of my spectrum on functions. I can do this as an inline script, but will need this on various pages Code: [Select] function readableDateConvert($mysqlTime) { $phpTime = strtotime($mysqlTime); $readableTime = date('M d Y',$newTime); return $readableTime; } Hi, I'm making an RSS feed http://dev.subverb.net/mixes_rss.php and as you see the date('r', $row['date']) function is not converting it. I've echo'd $row['date'] into the description to show what format the date is in (just mysql datetime. Am I missing something? Thanks I cant figure out how to add $recieved into this needs to take place of time hope someone knows how to do this what im doing is adding in the UNIX time i want to offset Code: [Select] <?php $offset = date('m/d/Y/H:i:s', time()+$send1['time_offset']); ?> Hello: I have this snippet of code that will write the current year onto a page if it's embedded on the page itself: Code: [Select] <?php echo date("Y") ?> Works fine. But, when I include it in an included file and pull it onto the page with a function, it does not work. Like this: MyNav.php Code: [Select] <?php function spFooter() { $spFooter = " <p> © <?php echo date(\"Y\") ?> </p> "; return $spFooter; } ?> MyPage.php Code: [Select] <?php include('include/myNav.php'); ?> <html> ... <?php echo spFooter(); ?> ... </html> What is the proper way to do this, and also what are the basic rules for properly nesting PHP scripts like this? Thanks for the help. i have been trying to insert date with when users post there comment but when i echo the date() with the comments..it just display 0000.00.00.00 just like that and when i checked my DB it was like that too..please what can i do.this is my code Thankd in advance Code: [Select] <?php include"header.php"; if(isset($_POST['submit'])) { $postdate=mktime(0,0,0,date("m"),date("d")+1,date("y")); $comment=mysql_real_escape_string($_POST['comment']); if($comment!=='') { $ins="INSERT INTO post(post_content,post_date)VALUES('$comment','$postdate')"; mysql_query($ins) or die(mysql_error()); } else { echo"You can not post an empty page"; } } I need to know which day of week was on particular date, so for example I would provide date lets say "Nov 22, 2010" formatted as needed and the function would return "Monday", is there a function in php to do that or how can it be done? I think it is unusual but i dont know to fix it. when my computer clock shows 16: 13 hours , date() reuturns 10:43:16 . My systems time zone is +5.30 GMT. how does date() subtracts 5.30 hrs from the system time? First, I would like to say when i tried to recover my account from this website, I took me 10 attempts to get the captcha right and then finally it said it sent me an email to my gmail account. I checked spam folder and everything there was no such email from this site. Then I decided to create a new account, well, it took me another 10 attempts to get the captcha right and finally when it was submitted, the page was loading for around 3 minutes before it signed me in.
My question is about the php date() function. It accepts a format to display a time. In the following example I use F for full representation of month, d for 2-digit day of month with leading zeros, Y for full year, g for 12-hour format without leading 0s, s for seconds and A for meridiem. It uses the correct format, but it gives me the wrong time. My local time is 4:43 and it prints out 4:12:
<?php echo "<p>order processed on " . date("F d, Y g:sA") . "</p>"; ?> Why is it 30 minutes behind? |
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