PHP - Php Script And Buttons
Hi all, I was just wondering if it possible to execute a php-script when someone presses a button without the page to reload or is this done with javascript.
So for instance a calculator. I would be more than pleased to hear and if possible even a short example. All i know is to work with a form method but as far as I know that requires the page to reload. thanks! Similar TutorialsHi everyone! I've been working on a php script to replace links that contain a query with direct links to the files they would redirect to. I'm having trouble echoing $year in my script. Listed below is the script, just below ,$result = mysql_query("SELECT * FROM $dbname WHERE class LIKE '%$search%'") or die(mysql_error());, in the script I try to echo $year. It doesn't show up in the table on the webpage. Everything else works fine. Any help wold be appreciated greatly. Thanks in advance. <?php include 'config2.php'; $search=$_GET["search"]; // Connect to server and select database. mysql_connect($dbhost, $dbuser, $dbpass)or die("cannot connect"); mysql_select_db("vetman")or die("cannot select DB"); $result = mysql_query("SELECT * FROM $dbname WHERE class LIKE '%$search%'") or die(mysql_error()); // store the record of the "" table into $row //$current = ''; echo "<table align=center border=1>"; echo "<br>"; echo "<tr>"; echo "<td align=center>"; ?> <div style="float: center;"><a><h1><?php echo $year; ?></h1></a></div> <?php echo "</td>"; echo "</tr>"; echo "</table>"; // keeps getting the next row until there are no more to get if($result && mysql_num_rows($result) > 0) { $i = 0; $max_columns = 2; echo "<table align=center>"; echo "<br>"; while($row = mysql_fetch_array($result)) { // make the variables easy to deal with extract($row); // open row if counter is zero if($i == 0) echo "<tr>"; echo "<td align=center>"; ?> <div style="float: left;"> <div><img src="<?php echo $image1; ?>"></div> </div> <?php echo "</td>"; // increment counter - if counter = max columns, reset counter and close row if(++$i == $max_columns) { echo "</tr>"; $i=0; } // end if } // end while } // end if results // clean up table - makes your code valid! if($i > 0) { for($j=$i; $j<$max_columns;$j++) echo "<td> </td>"; echo '</tr>'; } mysql_close(); ?> </table> Hi i have this upload script which works fine it uploads image to a specified folder and sends the the details to the database. but now i am trying to instead make a modify script which is Update set so i tried to change insert to update but didnt work can someone help me out please this my insert image script which works fine but want to change to modify instead Code: [Select] <?php mysql_connect("localhost", "root", "") or die(mysql_error()) ; mysql_select_db("upload") or die(mysql_error()) ; // my file the name of the input area on the form type is the extension of the file //echo $_FILES["myfile"]["type"]; //myfile is the name of the input area on the form $name = $_FILES["image"] ["name"]; // name of the file $type = $_FILES["image"]["type"]; //type of the file $size = $_FILES["image"]["size"]; //the size of the file $temp = $_FILES["image"]["tmp_name"];//temporary file location when click upload it temporary stores on the computer and gives it a temporary name $error =array(); // this an empty array where you can then call on all of the error messages $allowed_exts = array('jpg', 'jpeg', 'png', 'gif'); // array with the following extension name values $image_type = array('image/jpg', 'image/jpeg', 'image/png', 'image/gif'); // array with the following image type values $location = 'images/'; //location of the file or directory where the file will be stored $appendic_name = "news".$name;//this append the word [news] before the name so the image would be news[nameofimage].gif // substr counts the number of carachters and then you the specify how how many you letters you want to cut off from the beginning of the word example drivers.jpg it would cut off dri, and would display vers.jpg //echo $extension = substr($name, 3); //using both substr and strpos, strpos it will delete anything before the dot in this case it finds the dot on the $name file deletes and + 1 says read after the last letter you delete because you want to display the letters after the dot. if remove the +1 it will display .gif which what we want is just gif $extension = strtolower(substr($name, strpos ($name, '.') +1));//strlower turn the extension non capital in case extension is capital example JPG will strtolower will make jpg // another way of doing is with explode // $image_ext strtolower(end(explode('.',$name))); will explode from where you want in this case from the dot adn end will display from the end after the explode $myfile = $_POST["myfile"]; if (isset($image)) // if you choose a file name do the if bellow { // if extension is not equal to any of the variables in the array $allowed_exts error appears if(in_array($extension, $allowed_exts) === false ) { $error[] = 'Extension not allowed! gif, jpg, jpeg, png only<br />'; // if no errror read next if line } // if file type is not equal to any of the variables in array $image_type error appears if(in_array($type, $image_type) === false) { $error[] = 'Type of file not allowed! only images allowed<br />'; } // if file bigger than the number bellow error message if($size > 2097152) { $error[] = 'File size must be under 2MB!'; } // check if folder exist in the server if(!file_exists ($location)) { $error[] = 'No directory ' . $location. ' on the server Please create a folder ' .$location; } } // if no error found do the move upload function if (empty($error)){ if (move_uploaded_file($temp, $location .$appendic_name)) { // insert data into database first are the field name teh values are the variables you want to insert into those fields appendic is the new name of the image mysql_query("INSERT INTO image (myfile ,image) VALUES ('$myfile', '$appendic_name')") ; exit(); } } else { foreach ($error as $error) { echo $error; } } //echo $type; ?> I was wondering if you can have a form that has different actions depending on what submit button is pressed. I have two button and with one I was to use <form action="<?php echo ( $_SERVER['PHP_SELF'] ); ?>" method="post"> and with the other I want to use <form action="preview.php" method="post"> I was to do this because I want to user to be able to preview their content before submitting. I want the preview page to use the post variables as the value of the input fields so the user doesn't have to input their data again. However because the form doesn't redirect the user to the preview page I have to save all the post variables as session variables. Hello guys. I am learning PHP little by little and am writing a VERY basic quiz. For functionality in the future I want to be able to change questions and answers in one "included" php doc. The problem i am having with my current code is that I would like to place a variable in the "value" definition on the radio input. I am unable to do this I guess. Any suggestions to accomplish the same thing? Sorry for my horrible code, this is the first thing I have written from scratch. The form page: Code: [Select] <?php include ("test.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>Untitled Document</title> </head> <body> <h2><? print $q1; ?></h2> <form method="post" action="test.php"> <input type="radio" name="q1answered" value="Basketball"/> <?php print $q1ans[0]; ?> <input type="radio" name="q1answered" value="Football"/> <?php print $q1ans[1]; ?> <br /><br /> <input type="submit" value="Submit Your Answer!" name="submit" /> </form> </body> </html> The php Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>Untitled Document</title> </head> <body> <?php //Enter all questions below $q1 = "What is your favorite Sport?"; $q2 = "What is your favorite hobby?"; //End Questions //Enter Asnwer choices for each question $q1ans = array("Basketball", "Football"); //End Answers //All question defined variables here to make grading easier $qbank = array ($q1, $q2,); if (isset($_POST["submit"])) { $choice = $_POST["q1answered"]; if ($choice == $q1ans[0]){ print "Your Favorite Sport is $q1ans[0]."; } else { print "Your Favorite Sport is $q1ans[1]."; } } ?> </body> </html> Thanks! Hi i'm making a new website based on PHP. I bumped on a problem now... The problem is that I have a loop where i get all records out of my sql database and get them into a form. Every record has a differend form with a button to. Every button then has a unique ID. Now i tried everyting i could think of to get the value out of a button when a button is clicked. But nothing worked... here is the part of the code where everything is for the form and the POST. Code: [Select] while($record = mysql_fetch_object($result)){ $id = $record->id; echo"<form action='home.php' method='post'>"; echo"<b>name:</b>".$record->name." <b>Price: </b>".$record->price.""; echo'<input type="hidden" name="id" value='.$id.'>'; echo"<input type='submit' value='Buy' /><br />"; echo"</form>"; } if($_POST) { $ID = intval($_POST['id']); $query1 = "SELECT price FROM items WHERE id = ".$ID.""; $result1 = mysql_query($query1); list($cost) = mysql_fetch_row($result1); $gold = getStat('gc',$userID); if($gold > $cost) { setStat('gc',$userID,($gold - $cost)); $queryw = "INSERT INTO users_inventory(item_id,user_id, quantity) VALUES ('".$ID."','".$userID."','1')"; $resultw = mysql_query($queryw); } else { echo"You can't afford this weapons."; } } The only thing that doesn't seem to work is this part Code: [Select] $ID = intval($_POST['id']); is always gives me this error: Notice: Undefined index: id in shop.php on line 26 Please help me out here i have no idea what to do from here on... I have made a form which includes text fields and radio buttons. The user completes the fields and makes their selections. Once the form is submit, they are then directed to a php file which displays their entries and selections. Atm I can't quite work out how to post their radio button selections. Here is the form: <legend>Car type</legend> <input name="cartype" type="radio" value="1" id="carone" /> <label for="carone">Compact</label><br /> <input name="cartype" type="radio" value="2" id="cartwo" /> <label for="cartwo">Saloon</label><br /> <input name="cartype" type="radio" value="3" id="carthree" /> <label for="carthree">SUV</label> and here is my current code for the text fields: <?php $firstname = $_POST['firstname']; $lastname = $_POST['lastname']; $emailaddress = $_POST['emailaddress']; $phone = $_POST['phone']; echo "Dear ". $firstname . " " . $lastname . ",<br />"; echo "Thank you for your order. <br />"; echo "Your contact details a - <br />"; echo "phone: " . $phone . "<br />"; echo "email: " . $emailaddress . "<br />"; ?> </body></html> If anyone could give a hand I'd be very grateful! I'm totally naive to php coding and i'm trying to modify my website which was written for me by someone else in php. So i'm kind of shooting in the dark - but my modification really isn't that difficult... here goes. I already have a form set up allowing the user to select values from drop down menus. To this I want to add a further selection from a choice of 4 radio buttons. This is the coding I've used (i've stripped it down to basics for simplicity) it's inserted between the 'form' tags <input type=radio name="choice" value="FP"> Front Print<br> <input type=radio name="choice" value="BP"> Back Print<br> <input type=radio name="choice" value="PP"> Pocket Print<br> <input type=radio name="choice" value="CP"> Custom Print<br> Ok - this part displays ok and seems to function as expected. The form 'Action' sends the user to another php page so i need to access these values on a different page. This is where I'm running blind. I just want a simple 'if' statement to set a variable based on the value of the radio buttons. So something that looks like this.... if (choice[1].checked=true) {$printchoice = "Front Print";} if (choice[2].checked=true) {$printchoice = "Back Print";} if (choice[3].checked=true) {$printchoice = "Pocket Print";} if (choice[4].checked=true) {$printchoice = "Custom Print";} This part doesn't work - i've tried various combinations but i'm just taking wild guesses. Any help would be much appreciated - thanks Code: [Select] if ($cartype = 1 ) { echo "Compact <br/>"; } elseif ($cartype == 2 ) { echo "Saloon <br/>"; } else if ($cartype == 3 ) { echo "SUV <br/>"; } This code will only display the first radio button atm. How do I fix this? I'm not sure how to use foreach to send multiple form information to the database. <form> <input id="<?php print $row['id'];?>" name="attendance" type="radio" value="1" checked="checked" /> <input id="<?php print $row['id'];?>" name="attendance" type="radio" value="2" /> <input id="<?php print $row['id'];?>" name="attendance" type="radio" value="3" /> </form> I have a group of 3 buttons for three different options and this is in a php while loop,and there could be anywhere from 1 to 30 of these forms that ineed to send the data to the database at the same time. each one of these groups are next to a user to mark if they were present, tardy, or absent. I need it to get the id of the user for each one of these and send the value to the database as well. I have been at this for far too long and really need some help. I am just trying to check if a radio button has been set or not when someone hits submit. My validation looks something like this: function protect($string){ $string = trim(strip_tags(addslashes($string))); return $string; } if(isset($_POST['submit'])){ //protect and then add the posted data to variables $username = protect($_POST['username']); $password = protect($_POST['password']); $passconf = protect($_POST['passconf']); $email = protect($_POST['email']); $fname = protect($_POST['fname']); $lname = protect($_POST['lname']); $address = protect($_POST['address']); $phone = protect($_POST['phone']); $gender = $_POST['gender']; if(!$username || !$password || !$passconf || !$email || !$fname || !$lname || !$address || !$phone || !isset($gender)){ echo "<p>Please enter all required fields</p>"; }else{ and my form for the radio button is like this... <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <h1>General</h1> <p> <label for="username">Username: </label> <input type="text" name="username" value="<?=$_POST['username'] ?>" /> </p> <p> <label for="password">Password: </label> <input type="password" name="password" value="<?=$_POST['password'] ?>" /> </p> <p> <label for="passconf">Confirm Password: </label> <input type="password" name="passconf" value="<?=$_POST['passconf'] ?>" /> </p> <p> <label for="email">Email: </label> <input type="text" name="email" value="<?=$_POST['email'] ?>" size="25"/> </p> <p> <label for="fname">First Name: </label> <input type="text" name="fname" value="<?=$_POST['fname'] ?>" size="25"/> </p> <p> <label for="lname">Last Name: </label> <input type="text" name="lname" value="<?=$_POST['lname'] ?>" size="25"/> </p> <p> <label for="address">Home Address: </label> <input type="text" name="address" value="<?=$_POST['address'] ?>" /> </p> <p> <label for="phone">Primary Phone Number: </label> <input type="text" name="phone" value="<?=$_POST['phone'] ?>" size="10" /> </p> <p> <label for="genders">Gender: </label> <input type="radio" name"gender" value="male" /> Male <input type="radio" name"gender" value="female" /> Female </p> everytime i hit submit i get this error: "Notice: Undefined index: gender in C:\wamp\www\LoginRegistration\register.php on line 37 Please enter all required fields" can anyone help me please? I have a search form which uses an image to perform the search. The search performs correctly however it inserts details of the image in the URL, is this normal? searchdisplaytest.php?term=red-widget&image.x=50&image.y=23 Can I get rid of the "&image.x=50&image.y=23" Code: [Select] <div class="homepagesearchtext"> <input type="text" name="term" size="20" class="homepagesearch" /> </div> <div class="searchbuttonbox"> <input type="image" name="image" value="Submit" src="http://wwwdomain.com/earch.PNG" alt="Search" name="image" > I have two drop down boxes that give me the result $extract and $extract2. The user can not pick the same seat in each drop down box. I am having a problem getting my IF statement to work, well it is working but not as I would like. When the page loads both boxes are null and are therefore the the same and the 'else' statement is shown. Is there a way to say...IF button is NULL on the page load then ignore? //SUBMIT BUTTON echo "<br>"; echo "<br>"; echo "<input type='submit' name='select' value='Select Seats'>"; echo "</form>"; //IF TO SEE IF TWO SEATS ARE SAME if ($_POST['select']="") { echo "please choose seats"; } if ($_SESSION['extract']==$_SESSION['extract2']) { echo "You have choosen the same seat twice, please choose two different seats. <a href='confirm.php'> Go Back</a>"; } Thanks. =) I am trying to create a registration form for upcoming events, and would like to have an "Add-to-Cart" button next to each choice like this... Code: [Select] Car Show *Add-to-Cart* Oct, 1, 2011 $20 Craft Show *Add-to-Cart* Oct 2, 2011 $30 Fishing Show *Add-to-Cart* Oct 8, 2011 $25 I think I have the HTML/CSS figured out, but am unsure of how to get the buttons working?! Do I need an HTML Form? How do I have having several "Add-to-Cart" buttons? The idea is that whichever button the user clicks, that will then tell my PHP to store the "Event ID" and "Quantity" in either a Cookie, Session, or Database record. So I'm not even sure that I need an HTML Form... Sincerely, Debbie Hi Guys, I am writing a web site for a Company. I have two issues the First one is how can or is it possable to check weather a user is logged in and then call on of two functions depending on the outcome. The second one and the more important ones is it possable to call a PHP Function by a user Clicking a Link or a button? If it is possable how would I go about doing this. Each functions build a different section of the site so for Example; The Function 'Data' will bring back a table displaying the Data from a set table, and then the Function 'Data_Input' would display a different page that allows the users to input data to the tables. I don't want these two functions to be dispalying at the sametime but to one Display and then the other and so on for other functions. Hi, I have the below code which pulls pet types from the database, and when you pick the particular type by selecting a radio button amd press 'Select Pet Type' you are brought to a page listing all examples of that pet. Is there any way of changing this so the pet types are listed as hyperlinks instead and when you click each particular hyperlink you are brought to a page where that pet type is listed? <?php /* Program: PetCatalog.php * Desc: Displays a list of pet categories from the PetType table. Includes descriptions. * Displays radio buttons for user to check. */ ?> <html> <head><title>Pet Types</title></head> <body> <?php include("misc.inc"); #12 $cxn = mysqli_connect($host,$user,$password,$dbname) #14 or die ("couldn't connect to server"); /* Select all categories from PetType table */ $query = "SELECT * FROM pettype ORDER BY petType"; #18 $result = mysqli_query($cxn,$query) or die ("Couldn't execute query."); #20 /* Display text before form */ echo "<div style='margin-left: .1in'>\n <h1 style='text-align: center'>Pet Catalog</h1>\n <h2 style='text-align: center'>The following animal friends are waiting for you.</h2>\n <p style='text-align: center'>Find just what you want and hurry in to the store to pick up your new friend.</p> <h3>Which pet are you interested in?</h3>\n"; /* Create form containing selection list */ echo "<form action='ShowPets.php' method='POST'>\n"; #33 echo "<table cellpadding='5' border='1'>"; $counter=1; #35 while($row = mysqli_fetch_assoc($result)) #36 { extract($row); #38 echo "<tr><td valign='top' width='15%' style='font-weight: bold; font-size: 1.2em'\n"; echo "<input type='radio' name='interest' value='$petType'\n"; #43 if( $counter == 1 ) #44 { echo "checked"; } echo ">$petType</td>"; #48 echo "<td>$typeDescription</td></tr>"; #49 $counter++; #50 } echo "</table>"; echo "<p><input type='submit' value='Select Pet Type'> </form></p>\n"; #54 ?> </div> </body></html> Hi guys, thanks in advance. What im trying to do is present clickable linked buttons depending on results of the if statements. I want to replace the standard href links into the buttons if possible? Here is some of the code. Code: [Select] <?php if ($DetectionPercent <= 30){ // beg echo '<li><a href="http://www.google.com"> View Personalised Detection Content</a>'; } elseif ($DetectionPercent > 30 && $DetectionPercent <= 60){ //int echo '<li><a href="http://www.youtube.com"> View Personalised Detection Content</a>'; } else //exp { echo '<li><a href="http://www.facebook.com">View Personalised Detection Content</a>'; } ?><HR> Been looking into it a while and just can seem to find anyway to do this. Thanks Lance I have been searching for something like this to use so I am trying to implement these ideas for my form but unable to get it to work. The concept is similar so I am posting here but if I would make a new post just let me know. it is not posting the info when the radio button is checked. Someone with a keener eye that mine can give a look and tell what I have done incorrectly it would be appreciated. Code: [Select] echo ' <form action="" method="get"><div id="avatar_section"> <div id="avatar_stack"> <p> <img src="herotmb/face0.png" alt="" /><input name="avatar[head]" type="radio" value="face0" checked="checked" /> </p> <p> <img src="herotmb/face0.png" alt="" /><input type="radio" name="avatar[face]" value="face0" /> <img src="herotmb/face1.png" alt="" /><input type="radio" name="avatar[face]" value="face1" /> <img src="herotmb/face2.png" alt="" /><input type="radio" name="avatar[face]" value="face2" /> <img src="herotmb/face3.png" alt="" /><input type="radio" name="avatar[face]" value="face3" /> </p> <span name="color"> <p> <img src="herotmb/color0.png" alt="" /><input type="radio" name="avatar[color]" value="black" id="black" onclick="color(black);" /> <img src="herotmb/color1.png" alt="" /><input type="radio" name="avatar[color]" value="brown" id="brown" /> <img src="herotmb/color2.png" alt="" /><input type="radio" name="avatar[color]" value="darkbrown" id="darkbrown" onclick="color(darkbrown);" /> <img src="herotmb/color3.png" alt="" /><input type="radio" name="avatar[color]" value="yellow" id="red" onclick="color(red);" /> <img src="herotmb/color4.png" alt="" /><input type="radio" name="avatar[color]" value="red" id="yellow" onclick="color(yellow);" /> </p> </span> '; $selected_radio = '$_POST[avatar[color]]'; if ($selected_radio == 'black') { echo ' <p> <img src="herotmb/hair0-black.png" alt="" /><input name="avatar[hair]" type="radio" value="hair0-black" /> <img src="herotmb/hair1-black.png" alt="" /><input name="avatar[hair]" type="radio" value="hair1-black" /> <img src="herotmb/hair2-black.png" alt="" /><input name="avatar[hair]" type="radio" value="hair2-black" /> <img src="herotmb/hair3-black.png" alt="" /><input name="avatar[hair]" type="radio" value="hair3-black" /> <img src="herotmb/hair4-black.png" alt="" /><input name="avatar[hair]" type="radio" value="hair4-black" /> <img src="herotmb/hair5-black.png" alt="" /><input name="avatar[hair]" type="radio" value="hair5-black" /> <img src="herotmb/hair6-black.png" alt="" /><input name="avatar[hair]" type="radio" value="hair6-black" /> <img src="herotmb/hairNone-black.png" alt="" /><input name="avatar[hair]" type="radio" value="hairNone" /> </p>'; } else if ($selected_radio == 'brown') { echo 'Table 2 Here.'; } else if ($selected_radio == 'darkbrown') { echo 'Table 3 Here.'; } else if ($selected_radio == 'red') { echo 'Table 4 Here.'; } else if ($selected_radio == 'yellow') { echo 'Table 5 Here.'; } echo ' <p id="submit" > <input type="submit" value="Save" /> </p> </form>'; Hi community. The radio buttons on my form suddenly stopped working. For the life of me I can’t figure out why. Everything seems to look fine. I did some moving around on servers so I wonder if something got messed up during the transfer. I’m wondering if a new version of PHP was installed and made something obsolete. I was wondering if someone could take a look. Thank you in advance for your advise.
<form action="brian_1.php" method="post" name="form1" id="form1"> <input name="name" type="text" id="name" size="30" tabindex="1"/> Company if Applicable: <input name="company" type="text" id="company" size="30" tabindex="2"/> Phone: <input name="phone" type="text" id="phone" tabindex="3" onkeypress="return formatPhone(event,this)" onkeydown="return getKey(event,this)" size="13" maxlength="12"/> Example: XXXXXXXXXX Alternate Phone: <input name="altphone" type="text" id="altphone" tabindex="4" onkeypress="return formatPhone(event,this)" onkeydown="return getKey(event,this)" size="13" maxlength="13"/> Example: XXXXXXXXXX Street Address:<input name="mail" type="text" id="mail" size="60" tabindex="5"/> City, State, Zip Code: <input name="city" type="text" id="city" size="60" tabindex="5"/> E-mail: <input name="emai" type="text" id="emai" size="60" tabindex="6"/> Would you like to be part of our mailing list? <label><input type="radio" name="list" value="Yes" id="RadioGroup1_0" tabindex="7"/>Yes</label><label><input type="radio" name="list" value="No" id="RadioGroup1_1" tabindex="8"/>No</label> Are you interested in volunteering for upcoming events? <label><input type="radio" name="volunteer" value="Yes" id="RadioGroup2_0" tabindex="9"/>Yes</label><label><input type="radio" name="volunteer" value="No" id="RadioGroup2_1" tabindex="10"/>No</label> Are you interested in becoming a sponsor by receiving opportunities to advertise through us? <label><input type="radio" name="opportunities" value="Yes" id="RadioGroup3_0" tabindex="11"/>Yes</label><label><input type="radio" name="opportunities" value="No" id="RadioGroup3_1" tabindex="12"/>No</label> Would you like to join our efforts by offering your services or products to further our cause? <label><input type="radio" name="cause" value="Yes" id="RadioGroup4_0" tabindex="15"/>Yes</label><label><input type="radio" name="cause" value="No" id="RadioGroup4_1" tabindex="16"/>No</label> If so, in what ways would you like to contribute? <textarea name="contribute" cols="60" rows="4"></textarea> <input type="submit" name="Submit" value="Sumbit" /><input type="reset" name="reset" id="reset" value="Clear" /> </form> <?php /* Email Variables */ $emailSubject = 'Contact Form'; $webMaster = 'brianewagnerfund@gmail.com'; $webMaster = 'matt@webskillsplus.com'; //$webMaster = 'murrterr@rcn.com'; /* Data Variables */ $name = $_POST['name']; $company = $_POST['company']; $phone = $_POST['phone']; $altphone = $_POST['altphone']; $mail = $_POST['mail']; $city = $_POST['city']; $emai = $_POST['emai']; if (isset($_POST["submit"])) { echo $_POST["list"]; } if (isset($_POST["submit"])) { echo $_POST["volunteer"]; } if (isset($_POST["submit"])) { echo $_POST["opportunities"]; } if (isset($_POST["submit"])) { echo $_POST["cause"]; } $contribute = $_POST['contribute']; $body = <<<EOD \r\n \r\n <br> Name(s): $name \r\n <br> Company if Applicable: $company \r\n <br> Phone: $phone \r\n <br> Alternate Phone: $altphone \r\n <br> Street Address: $mail \r\n <br> City, State, Zip Code: $city \r\n <br> Email: $emai \r\n <br> Would you like to be part of our mailing list? $list \r\n <br> Are you interested in volunteering for upcoming events? $volunteer \r\n <br> Are you interested in becoming a sponsor by receiving opportunities to advertise through us? $opportunities \r\n <br> Would you like to join our efforts by offering your services or products to further our cause? $cause \r\n <br> If so, in what ways would you like to contribute? $contribute \r\n <br> EOD; $from = "From: BrianEWagnerFund@gmail.com\r\n"; $from .= "Reply-To: ".$emai."\r\n"; $from .= "Content-type: text/html\r\n"; mail($webMaster, $emailSubject, $body, $from); /* Results rendered as HTML */ echo "<meta http-equiv=\"refresh\" content=\"0;URL=http://www.brianewagnerfund.org/thankyou.html\">"; ?> Hi guys...I need some help in matching data from results of checkboxs and radio buttons. My Intentions: There are 3 radio buttons and 8 check boxes. Users can select any one but cannot don't select at all. I separate the calss and categories because for classes, users can only select 1 option whereas for categories users can select many. For example, User select class 1 but do not select anything else and click submit...the system will then retrieve that he selected and check the data base if he have the pre requisites to allow him to go through. Coding for my form: Code: [Select] <form id="applicationoptions" method="post" action="s_apply_now.php"> <div id="optionshead">Class :</div> <div id="classoptions"> <input type="radio" name="class" value="1" /> Class 1 Permit <input type="radio" name="class" value="2" /> Class 2 Permit <input type="radio" name="class" value="3" /> Class 3 Permit </div> <div id="optionshead2">Categories :</div> <div id="catoptions"> <input type="checkbox" name="cat" value="1" /> CAT 2PG <input type="checkbox" name="cat" value="2" /> CAT 1OR <input type="checkbox" name="cat" value="3" /> CAT 2TT <br/><br/> <input type="checkbox" name="cat" value="4" /> CAT 3PG <input type="checkbox" name="cat" value="5" /> CAT 2OR <input type="checkbox" name="cat" value="6" /> CAT 3TT <br/><br/> <input type="checkbox" name="cat" value="7" /> CAT 4PG <input type="checkbox" name="cat" value="8" /> CAT 3OR </div> <div class="applynext"> <input class="applynextbutton" type="submit" name="applynextbutton" value="PROCEED" /> </div> </form> Lets say if user do not select any class, but select CAT 3PG, system will check if user have the pre-requisites before proceeding to next step. Any one can help me or give me hints?? most importantly is i do not know how to retreieve the values selected from the form. Is it possible to do it using php or must i hunt for javascript's script?? Thanks in advance guys...greatly appreciate. |