PHP - First String In Array Doesn't Show?
I'm trying to expand my knowledge on some more str type functions, and I've always wanted to learn implode and explode, but I was just too lazy.
Anyways, for some reason, if I type in: salad,pizza,apples - the first value in the array, salad, doesn't show up. o.O <?php $favorite_food = $_POST['favorite_food']; if(!$favorite_food) { ?> <form action="words.php" method="POST"> <input type="text" name="favorite_food"> <input type="submit"> </form> <?php } else { $ex = explode(",", $favorite_food); $amount = count($ex) + 1; while($i < $amount) { echo $ex[$i]."<br/>"; ++$i; } } ?> I know arrays start at 0, so thats why I added 1 to the count. Similar Tutorialshey guys, I'm in the process of transforming my static html website into "something" more dynamic. I came across an article on bilingual website (http://www.jacksonengineering.net/proj_phplanguage.php) and I basically used the same idea for my project. Everything works fine except for one thing - links to different language web pages are generated correctly page.php?lang=pl but when I click on the link, the url loses the variable and looks like page.pl.php What to do? Code: [Select] language.php <?php //the url ? language declaration should have preference over the page name $pagename = basename($_SERVER['PHP_SELF'],".php"); $pagenamearray = explode(".",$pagename); if (count($pagenamearray) == 2){ //there is currently a bi-lingual site page loaded $_SESSION['language'] = $pagenamearray[1]; $urllang = $pagenamearray[1]; }else{ //this page must be a non bi-lingual page $urllang = 'en'; } //check for a language selection on the url if(isset($_GET["lang"])){//language has been passed via url $_SESSION['language'] = htmlspecialchars($_GET["lang"]); //set it what was found } ///if there still is no language set, go with english for a default if(!isset($_SESSION['language'])){ $_SESSION['language'] = 'en'; } //now we think we have the session language figured out // //now check for a version of the current page in the desired language //lets make some things clear first //the current page url is either en or pl from $urllang if($urllang != $_SESSION['language']){ //if the url isn't the same as the $_SESSION if($_SESSION['language'] == 'en'){//if it should be english then load the english header("Location: $pagenamearray[0].php"); exit; } if($_SESSION['language'] == 'pl'){ //construct the name of the file if it existed filename.pl.php $plVersion = $pagenamearray[0] . ".pl.php"; //we have to check if a pl version actually exists of this page if(file_exists($plVersion)){//redirect if it exists header("Location: $plVersion"); exit;//stop executing things }else{$pagelangnotfound = true;} } } ?> Code: [Select] header.php <?php if ($_SESSION['language'] != 'en'){ echo 'Select Language: <a href="'. $_SERVER['PHP_SELF'] . '?lang=en"><img src="img/gb.gif" alt="English" class="off" /></a>'; }else{echo 'Wybierz J&#281;zyk: <img src="img/gb.gif" alt="English" />';} ?> <?php if ($_SESSION['language'] != 'pl'){ echo '<a href="'. $_SERVER['PHP_SELF'] . '?lang=pl"><img src="img/pl.gif" alt="Polish" class="off" /></a>'; }else{ echo '<img src="img/pl.gif" alt="Polish" />'; } ?> Code: [Select] menu.php <?php if($pageOn == 'index.php'){?> id="selected"<?php }?>> <a href="index.php">Main Page</a> Code: [Select] page.php <?php session_start(); include "language.php"; $pageOn = basename($_SERVER['PHP_SELF']); $mItem = $pageOn; ?> <?php include("header.php"); ?> <?php include("menu.php"); ?> English content Code: [Select] page.pl.php <?php session_start(); include "language.php"; $pageOn = basename($_SERVER['PHP_SELF']); $mItem = $pageOn; ?> <?php include("header.php"); ?> <?php include("menu.php"); ?> Polish content I'm trying to do a simple PHP form with Securimage Captcha and whenever I add this variable "$securimage = new Securimage();" the page displays nothing. Could someone please help me with this? My php file is already in the securimage directory so that's why I'm pointing directly to the file. Hi im trying to pass a variable through a url. Here's the code : echo"<td class='tableContent'><span onmouseover=\"tooltip.show('Click to add details to ".$result['workObject']."');\" onmouseout=\"tooltip.hide();\"><a href='addRemarksBucc.php?workObject=".$result['workObject']."'>".$result['systemRemarks']."</a></span></td>"; and here's the code to the next page: <table width="550" border="0" cellspacing="5" cellpadding="0"> <tr> <td width="78" valign="top">Work Object</td> <td><input name="workObject" id="workObject" type="text" value="<?php $_GET['workObject']; ?>" /></td> </tr> <tr> <td valign="top">Remark Details</td> <td><textarea name="errorMessage2" cols="50" rows="10" id="errorMessage2" accesskey="p" tabindex="1"></textarea> <input name="workObject2" type="hidden" value="" /></td> </tr> <tr> <td valign="top"> </td> <td> </td> </tr> <tr> <td> </td> <td><input name="submit" type="submit" class="btn" id="submit" accesskey="R" tabindex="11" value="Submit" /> <input name="reset" type="reset" class="btn" id="reset" accesskey="e" tabindex="12" value="Reset" /></td> </tr> </table> What am I doing wrong? The address bar shows the right url but the second page doesn't display any value for workObject. Thanks! I need to copy a table from one code to another. But I couldn't figure out how to do it properly. Just tried to copy code from one file to another but it doesn't work the same. I need to find where to change the code to show right columns.
https://easyupload.io/maoa9h - zipped cart.php (original code with right table) and review.php (the one that doesn't show right table)
We need to copy the table from cart.php: But it doesn't work. The quantity column doesn't show in review.php - as you can see here https://ibb.co/brP0yy1 I have a page that shows entries in a guestbook I'm making, and below the entries there is supposed to be a form to write an entry. Except, none of the HTML after the script to show the entries shows up on the page. I have no clue what's wrong. Here is the script to show the entries. $n is name, $d is date, $s is site (optional), and $m is message. $file = fopen("posts.txt", 'rb'); flock($file, LOCK_SH); while(!feof($file)){ $entry = fgetcsv($file, 0, '|'); if(empty($entry)){exit;} $d = $entry[1]; $n = $entry[2]; $s = $entry[3]; $m = $entry[4]; echo ' <table style="border: #3399AA 1px solid;"><tr style="background: #3399AA; font: bold 10px verdana,sans-serif; color: #FFFFFF;"> <td width="170">'.$n.'</td> <td align="right" width="170">'.$d.'</td> </tr> '; if($s != 'none'){ echo ' <tr><td colspan="2" style="font: 10px verdana,sans-serif; color: #3399AA;"> <b>Site: </b><a href="'.$s.'">'.$s.'</a> <center><div style="width: 250; height: 1px; background: #3399AA; margin: 10px;"></div></center></td></tr> '; } echo ' <tr> <td colspan="2" style="font: 10px verdana,sans-serif; color: #3399AA;">'.$m.'</td> </tr></table><br> '; } flock($file, LOCK_UN); fclose($file); The file it is reading looks like this: Code: [Select] |11:51 am, 3rd Nov 2010|Memoria|none|Hello. :) |11:51 am, 3rd Nov 2010|Memoria|http://sitehere|Hello again. |11:51 am, 3rd Nov 2010|Memoria|none|How are you doing? Thanks! So I'm trying to create an Array from a comma separated string containing array{s}. How can I take a string full of comma separated hex values such as : <?php $myStr = ( "00ffff", "00cccc", "009999", "007777", "004444", "001111", "01ffff", "01cccc", "019999" ); ?> & turn it into 3 separated arrays like : <?php $myNewArrs = [ Array1 ( 3 ), Array2 ( 3 ), Array3 ( 3 ), ]; ?> which REALLY looks like : <?php $myNewArrs = [ Array ( "00ffff", "00cccc", "009999" ), Array ( "007777", "004444", "001111" ), Array ( "01ffff", "01cccc", "019999" ), ]; ?>
? Thank you & have a great afternoon!
Edited May 27 by AquariaXI I've done pretty much everything I can come up with. The method itself works fine, if I print_r(); just before returning it, it successfully returns the array. But once returned, it's empty. Heres my code: Code: [Select] <?php include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/class_database.php"; include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/values.php"; ?> <?php class User { private $database; public function __construct(MySqlDatabase $database) { //Type Hinting $this->database = $database; } public function hash_password($password) { $result = hash(sha512, $password . SUOLA); return $result; } public function find_all() { $result = $this->database->db_query("SELECT * FROM users"); $final = mysqli_fetch_array($result); return $final; } public function find_by_id($id=1) { $result = $this->database->db_query("SELECT * FROM users WHERE id={$id}"); $final = mysqli_fetch_array($result); return $final; } public function check_required($array) { // this method gets called first if (empty($array['username']) || empty($array['first_name']) || empty($array['last_name']) || empty($array['password']) || empty($array['email']) || empty($array['secret_question']) || empty($array['password2']) || empty($array['secret_answer']) || !($array['email'] === $array['email2']) || !($array['password'] === $array['password2'])) { die("Fill required fields!" . "<br />" . "<a href='javascript:history.go(-1)'>Go back</a>"); } else { $this->database->array_query_prep($array); // it then continues to the next method automatically } } public function create_user($array) { $date = date('d-m-Y H:i:s'); $sql = "INSERT INTO users (username, first_name, "; $sql .= "last_name, password, email, secret_question, "; $sql .= "secret_answer, create_time) VALUES "; $sql .= "('{$array['username']}', '{$array['first_name']}', '{$array['last_name']}', "; $sql .= "'{$array['password']}', '{$array['email']}', '{$array['secret_question']}', '{$array['secret_answer']}', "; $sql .= "'{$date}');"; $this->database->db_query($sql); } } ?> Code: [Select] <?php include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/values.php"; include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/class_user.php"; ?> <?php class MySqlDatabase extends MySQLi { function __construct() { //Check if constants are missing if (!defined("DB_USERNAME") || !defined("DB_SERVER") || !defined("DB_PASSWORD") || !defined("DB_NAME")) { die("One or more of the database constants are missing!"); } //Establish connection if constants are present using the parent class parent::__construct(DB_SERVER, DB_USERNAME, DB_PASSWORD, DB_NAME); //Echo error message if connection has failed if ($this->connect_errno) { die("Database connection has failed: " . $this->connect_errno); } } public function db_query($sql) { $result = $this->query($sql); if (!$result) { die("Database query failed: " . $this->errno); } } public function array_query_prep($array) { // continues to this method $result = array_map(array($this, 'real_escape_string'), $array); if (!$result) { die("Preparing query failed: " . $this->errno); } // if i print_r here, it returns the array as it should return $result; } } ?> Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <link rel="stylesheet" type="text/css" href="../stylesheets/main.css"/> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body class="main_body"> <div id="container"> <div id="header"> <div id="top"> <div id="login"> <form action="" method="post" target="/login/"> <label for="username">Username:</label><br /> <input name="username" type="text" class="text" maxlength="20" /><br /> <label for="password">Password:</label><br /> <input name="password" type="password" class="text" maxlength="30" /><br /> <input name="submit" type="submit" class="loginbtn" value="Login" /></form> </div> </div> <div> <h1>Welcome to _________ website!</h1> </div> <?php include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/values.php"; include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/functions.php"; include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/class_database.php"; include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/class_user.php"; ?> <?php $database = new MySqlDatabase(); $user = new User($database); if (isset($_POST['submit'])) { $result = $user->check_required($_POST); //this is where I get nothing back $user->create_user($result); die("Registration was successful!"); } else { $username = ""; $first_name = ""; $last_name = ""; $password = ""; $email = ""; $email2 = ""; $secret_question = ""; $secret_answer = ""; unset($_POST); } ?> <form action="" method="post" target="_self"> Username: <input type="text" name="username" class="text" maxlength="20" value="<?php echo htmlentities($username); ?>" /><br /> First Name: <input type="text" name="first_name" class="text" maxlength="20" value="<?php echo htmlentities($first_name); ?>" /><br /> Last Name: <input type="text" name="last_name" class="text" maxlength="20" value="<?php echo htmlentities($last_name); ?>" /><br /> Password: <input type="password" name="password" class="text" maxlength="30" value="<?php echo htmlentities($password); ?>" /><br /> Enter again: Password: <input type="password" name="password2" class="text" maxlength="30" value="<?php echo htmlentities($password2); ?>" /><br /> Email: <input type="text" name="email" class="text" maxlength="30" value="<?php echo htmlentities($email); ?>" /><br /> Enter again: Email: <input type="text" name="email2" class="text" maxlength="30" value="<?php echo htmlentities($email2); ?>" /><br /> Secret Question: <input type="text" name="secret_question" class="text" maxlength="35" value="<?php echo htmlentities($secret_question); ?>" /><br /> Secret Answer: <input type="text" name="secret_answer" class="text" maxlength="35" value="<?php echo htmlentities($secret_answer); ?>" /><br /> <input type="submit" name="submit" class="submitbtn" value="Submit" /> <?php ?> </div> </div> </body> </html> [/quote] Any ideas? Hi all, Im so stuck on this! Cant figure out a solution... $precip_array[0] has a value of "80" in it as a string. I need to compare it to an integer. echo (int)$precip_array[0] returns a "0". Ive also tried adding a 0 but that results in the same. I did a var_dump on $precip_array[0] which returns string(17) "80" I think 17 signifies the length of the string, but I only see 2 digits when I echo this. Any help is much appreciated. Hi I need to know how to arrange this thing looking something like an array to be able to find values from it. The problem is, I don't really even know what I am dealing with here. Wonder if you could help me out. I have the following mess stored in a $messages variable: {"messages":[{"message_id":2314446,"from":"441234568790","timestamp":1280703181,"text":"first text"},{"message_id":2315147,"from":"123456789014","timestamp":1280755014,"text":"another text"}],"unread":0} and I don't know how to do the following: I need is to get only the message text from any message that matches my wanted phone number. For example: I want to get the text value from message which from is 123456789014. /Henry OK so here is what I want to do. I have a bunch of strings stored in a table. The strings are like this grandparent.parent.child. some are just parent.child What I want to do is Select all and then put them into an array. soooo x.y.z would become $Var['x']['y']['z'] and a.b would become $Var['a']['b'] It has to be dynamic because some strings are just 2 levels, and it goes all the way up to 6 levels. I have different plans for setting the variably to something but I can handle that. Any ideas? Hi, I have a members page and i want it to post the members id from an php array file that i created, like for this website. Thanks is advance Hi, I have been working on a directory/cms script (first large script to build from scratch). I am stuck on a small part of it where is shows users a list of the listings they have put in the directory. Below is the code that generates the table that shows the list of listings which is pulled from the 'listings' table in my database. Code: [Select] <?php ### List of listings user has posted ### if(isset($_SESSION['userlogged'])) { $user_id = $_SESSION['userlogged']; $sqlCommand = "SELECT listing_id, cat_id, listing_title, listing_date, showing FROM listings WHERE showing='0' AND user_id='$user_id' ORDER BY listing_id ASC"; $query = mysql_query($sqlCommand,$con) or die (mysql_error()); $ListingDisplay = ''; while ($row = mysql_fetch_array($query)) { $listing_id = $row["listing_id"]; $cat_id = $row['cat_id']; if ($cat_id == '1') { $cat_name = "Carpenters"; } if ($cat_id == '2') { $cat_name = "Stone Masons"; } if ($cat_id == '3') { $cat_name = "Plumbers"; } if ($cat_id == '4') { $cat_name = "Landscapers"; } $listing_title = $row["listing_title"]; $listing_date = $row["listing_date"]; $ListingDisplay .= ' <tr class="listingaccount"> <td><a href="edit_listing.php?lid=' . $listing_id . '">' . $listing_id . '</a></td> <td>' . $cat_name . '</td> <td>' . $listing_title . '</td> <td>' . $listing_date . '</td> <td><a class="hoverBtn" href="edit_listing.php?lid=' . $listing_id . '"><img src="images/btnedit.png" border="0"></a></td> <td><a class="hoverBtn" href="remove_listing.php?lid=' . $listing_id . '"><img src="images/btndelete.png" border="0"></a></td> </tr>'; } mysql_free_result($query); ?> <table width="680" border="0" align="right" cellpadding="0" cellspacing="0"> <tr> <td colspan="2"><h2>My Listings</h2></td> </tr> <tr> <td> </td> <td> </td> </tr> <tr> <td><a href="account_add_listing.php">Add New Listing</a></td> <td> </td> </tr> <tr> <td> </td> <td> </td> </tr> <tr> <td colspan="2" valign="top"> <table width="100%" border="0" cellspacing="0" cellpadding="0"> <tr> <td>Listing Code</td> <td>Category</td> <td>Title</td> <td>Date Entered</td> <td> </td> </tr> <?php echo $ListingDisplay; ?> </table> </td> </tr> </table> <?php } ?> That all works just fine, but I would like to be able to generate the categories automatically. I am thinking some sort of array, but im not quite sure how to go about it and was hoping maybe someone could give me a starting point I could work from. My categories table is like this: -------------------------- | cat_id | cat_name | -------------------------- Many thanks Eoin Hello there, I have this snippet of code Code: [Select] echo "<td><a href='inc/browse.php?act=view&id=$id'>$title</a></td><td>$author</td>"; } } //close up the table echo "</tr></table>"; This is the code that actually displays the links that go to the listing. The problem is, they all show on one line across the screen. How can it be configured to where the next listing is displayed below the previous one. I tried putting: Code: [Select] echo "<br />" But didn't do it. Any ideas? How can I get rid of "Notice:Array to string conversion on line 78" error from this code? can i get a little help please? This is line 78 : $table .= $columnValue; Basically this code's supposed to do is to group the values from grpa, grpb of datatb to 4 different categories according to their value. and as end result, category index number of each category is put into the html table. Thanks.
<?php include ("configd.php"); $sql = "SELECT grpa, grpb From datatb"; $result = $conn->query($sql); //categories $cat = [ 4 => [1, 2, 3, 4], 3 => [5, 6], 2 => [7, 8], 1 => [9, 10] ]; while ($row = $result->fetch_assoc()) { foreach ($cat as $catKey => $catValue) { $columns[$catKey] = array_filter($row, function ($col) use ($cat, $catKey) { if (in_array($col, $cat[$catKey])) { return true; } }); } $output[] = $columns; } // the output $table = <<<EOT <table class='maintable'> <tr><th>9:10</th></tr> <tr><th>7:8</th></tr> <tr><th>5:6</th></tr> <tr><th>1:4</th></tr> </table> EOT; foreach ($output as $row) { $table .= "<table class='maintable'>"; foreach ($row as $columnKey => $columnValue) { $table .= "<tr>"; $table .= "<td>"; $table .= $columnValue; $table .= "</td>"; } $table .= "</tr>"; $table .= "</table>"; } echo $table; ?> Edited June 30, 2020 by mattix small additions. Hello I am facing a problem which i can not handle. I appreciate for any help. My Database is: Code: [Select] CREATE TABLE IF NOT EXISTS `shops` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `options` text, `user_name` varchar(250) NOT NULL , PRIMARY KEY (`id`), UNIQUE KEY `user_name` (`user_name`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 COMMENT='user data stored' AUTO_INCREMENT=1 ; And some sample data as below: Code: [Select] INSERT INTO `users` (`id`, `options`, `user_name`) VALUES (1, 'apple-orange-grape-bmw-toyota-fig-', 'user1'), (4, 'apple-tomato-pc-notebook-yellow-', 'user2'), (5, 'blue-green-orange-cdrom-', 'user3'), (6, 'orange-yellow-blue-pink-bread-', 'user4'); How can i display how many apples or green or any item selected by user? So far i tried in_array, array_count_values but seems no one is working. Regards If I wanted to print a string that contains a variable that also contains an array, how would I do so? I want to put the resulting echo into a log file. Example: “These are the books: $userArray and these are the pages: $pagesArray”; With just an array, I can use print_r($array, true) to get an array formatted for use in a string (which works well for my purposes) but this doesn’t work with two arrays unless I do this manually. (Such as setting the $user_array = print_r($userArray). But I want to write a function that will take a string, potentially containing arrays (as variables), and interpolate/make them legible for humans. (Some of the arrays are also multidimensional.) But it looks like I can't even concatenate a string and an array. $string = $string . $array. gives an error, array to string conversion. I don’t understand PHP very well so please explain what is going on here. and the best way to record something like the Example above. I need to assign unknown array keys and their values to strings. The code I am using is: Code: [Select] $cart = $_SESSION['cart']; $items = explode(',',$cart); $qty = array(); foreach ($items as $item) { $qty[$item] = $qty[$item] + 1; } print_r($qty); The keys change and are not ordered. I do not know what the key or it's value may be. So as an example, I might have: Code: [Select] Array ( [2] => 5 [4] => 8 ) or in a different scenario, I might have: Code: [Select] Array ( [1] => 6 ) What those numbers represent is a product id (the key), and the quantity (the value of the key). Can someone help me to assign these to a string? I have been reading all morning, and not making any progress. Thank you!
<?php $srs = array(); for ($section = 1; $section < 5; $section++) { for ($row = $section; $row < 10; $row++) { for ($seat = $row; $seat < 20; $seat++) { $srs[] = array( 'section_name' => $section, 'row_name' => $row, 'seat_name' => $seat); } } } output(convert_array($srs)); // Converts the array function convert_array($input) { return $input; } function output($obj) { echo "<pre>"; print_r($obj); echo "</pre>"; die; } ?>
I'm trying to convert those array number to string, add implode() to make it happen, but seem PHP didn't recognize variable in $input. Like this implode("Section: ", $input) or (Section: ", $srs). Can you help me? Thanks, Gary Edited October 16, 2019 by sigmahokiesHello, I'm going to be sending emails to users from a community calendar showing events for the day or a time frame specified elsewhere. The problem I'm having is turning results of DB query into a string when there are multiple results for the day. It works just fine with single results. I understand why it doesn't work but can't figure out how to solve the problem. Don't worry about the $eventdate as that comes from the same array as the $event_id used to call the array shown below. I tried foreach and implode but couldn't get it working so I'm starting over and asking for your guidance on how is the best way to pull this off. Thanks for your help. Code: [Select] $getevent = mysql_query("SELECT title, description from ".$conf['tbl']['events']." WHERE event_id=$event_id AND private=0"); WHILE ($gtevent = mysql_fetch_array($getevent)) { $event_title=$gtevent['title']; $event_description=$gtevent['description']; $message="<p><span style=\"font-size:24px\">$event_title</span><br />$eventdate</p><p>$event_description</p>"; } Hi everybody, I need some help about how to convert string to array name. I have the following function which pass $_REQUEST type as parameter. It is not working because I don't know how to convert $method to $_GET or $_POST in a proper way. Do anybody know how? Code: [Select] function validateIfFilled($method, $fields) { $exploded=explode(",",$fields); foreach($exploded as $field){ if(empty($method[trim($field)])){ return false; } } return true; }; if(!validateIfFilled('$_GET', "email, password, address")) ... Thank you! |