PHP - Help With Setting Certian Values
ok, I run a samp server that has mysql and i'm creating a website to register on the server, Ok, I got it so you can set your charcter age (it's a role play server) but i need help with setting fighting styles, The gamemode uses pawno scirpt lang and the values i use to set each fighting style is 5,6,15 and 26.
I have it set it a drop down menu, I want to convert this code so it shows certian names and when you select those certian names it sets the value for that name Here is the code for my age but i want set to like i said above </select> <tr> <td><b>Age:</b></td> <td><select name="age"> <option value="---">Fighting Style</option> '; for ($i=18;$i<99;$i++) { $metai = date('Y') - $i; echo '<option value="'. $i .'">'. $i .' (' .$metai. ')</option> '; } echo ' </select> Instead of it outputting the Age and the Year i want it to Output those values i mention before and the style Example These are in the drop down menu Kung_Fu (6) Elbow (26) Boxing (5) Kick Boxing (6) When you select it, It writes to the database Similar Tutorials
Table Issue - Multiple Location Values For User Pushes Values Out Of Row Instead Of Wrapping In Cell
I am working on a little project for my site and I am trying to get this script to ignore the index.html file and the .htaccess file in there. I just want it to display all files like .zip, .rar, .tar, .gz, .gtar, .ace, ect... echo " <td width='70%'><select id='download'>"; echo " <option value=''>None</option>"; if ($handle = opendir("./modules/Downloads/files")) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != "..") { echo " <option value='".$file."'>".$file."</option>"; } } closedir($handle); } echo " </td>\n"; Here is my situation. I have an exam application built in Flash, where after the taker is finished and submits their scores a record is created in MySQL in a log table. Basically there is a column called attempt which is populated with a 1 after they have successfully finished the exam. When this column has a 1, the user is locked out and cannot access the exam when they try and login. The Flash part was built a while back in AS3 and is very cumbersome to try and figure out and make changes, so I have been trying to improve some things on the PHP/MySQL end. What I have now is a php based login which uses if else statements to determine if a user has passed and if they have not uses a DELETE statement to delete their log record and thus they regain access to taking the exam. Code below. <?php if(($pcnt[$i]*100) > 89) { echo "<span class='green'>you did great!</span>"; } else { $query_delete = "DELETE FROM log_March2011 USING log_March2011 INNER JOIN roster_March2011 WHERE log_March2011.user_id =roster_March2011.user_id AND roster_March2011.user_id = '{$_SESSION['user_id']}'"; //echo $query_delete; //for debugging test $result_delete = mysql_query($query_delete) or trigger_error('Query failed: ' .mysql_error()); //$num = mysql_affected_rows($db); if ($result_delete) { echo "<span class='red'>Please review missed questions/sections below</span><br />You can now retake the exam"; }// end if else { echo "No record of taking exam"; } //end else } ?> what I would like to do to improve the application is to be able to implement a set number of attempts allowed before the user is disallowed to take the exam again, but not sure how to implement this or is even possible? Dear All Members here is my table data.. (4 Columns/1row in mysql table)
id order_no order_date miles How to split(miles) single column into (state, miles) two columns and output like following 5 columns /4rows in mysql using php code.
(5 Columns in mysql table) id order_no order_date state miles 310 001 02-15-2020 MI 108.53 310 001 02-15-2020 Oh 194.57 310 001 02-15-2020 PA 182.22
310 001 02-15-2020 WA 238.57 ------------------my php code -----------
<?php
if(isset($_POST["add"]))
$miles = explode("\r\n", $_POST["miles"]);
$query = $dbh->prepare($sql);
$lastInsertId = $dbh->lastInsertId(); if($query->execute()) {
$sql = "update tis_invoice set flag='1' where order_no=:order_no"; $query->execute();
} ----------------- my form code ------------------
<?php -- Can any one help how to correct my code..present nothing inserted on table
Thank You Edited February 8, 2020 by karthicbabuHi, My company has 240+ locations and as such some users (general managers) cover multiple sites. When I run a query to pull user information, when the user has multiple sites to his or her name, its adds the second / third sites to the next columns, rather than wrapping it inside the same table cell. It also works the opposite way, if a piece of data is missing in the database and is blank, its pull the following columns in. Both cases mess up the table and formatting. I'm extremely new to any kind of programming and maybe this isn't the forum for this question but figured I'd give it a chance since I'm stuck. The HTML/PHP code is below: <table id="datatables-column-search-select-inputs" class="table table-striped" style="width:100%"> <thead> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> <th>Actions</th> </tr> </thead> <tbody> <?php //QUERY TO SELECT ALL USERS FROM DATABASE $query = "SELECT * FROM users"; $select_users = mysqli_query($connection,$query);
// SET VARIABLE TO ARRAY FROM QUERY while($row = mysqli_fetch_assoc($select_users)) { $user_id = $row['user_id']; $user_firstname = $row['user_firstname']; $user_lastname = $row['user_lastname']; $username = $row['username']; $user_phone = $row['user_phone']; $user_image = $row['user_image']; $user_title_id = $row['user_title_id']; $user_role_id = $row['user_role_id'];
// POPULATES DATA INTO THE TABLE echo "<tr>"; echo "<td>{$user_id}</td>"; echo "<td>{$user_firstname}</td>"; echo "<td>{$user_lastname}</td>"; echo "<td>{$username}</td>"; echo "<td>{$user_phone}</td>";
//PULL SITE STATUS BASED ON SITE STATUS ID $query = "SELECT * FROM sites WHERE site_manager_id = {$user_id} "; $select_site = mysqli_query($connection, $query); while($row = mysqli_fetch_assoc($select_site)) { $site_name = $row['site_name']; echo "<td>{$site_name}</td>"; } echo "<td>{$user_title_id}</td>"; echo "<td>{$user_role_id}</td>"; echo "<td class='table-action'> <a href='#'><i class='align-middle' data-feather='edit-2'></i></a> <a href='#'><i class='align-middle' data-feather='trash'></i></a> </td>"; //echo "<td><a href='users.php?source=edit_user&p_id={$user_id}'>Edit</a></td>"; echo "</tr>"; } ?>
<tr> <td>ID</td> <td>FirstName</td> <td>LastName</td> <td>Username</td> <td>Phone #</td> <td>Location</td> <td>Title</td> <td>Role</td> <td class="table-action"> <a href="#"><i class="align-middle" data-feather="edit-2"></i></a> <a href="#"><i class="align-middle" data-feather="trash"></i></a> </td> </tr> </tbody> <tfoot> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> </tr> </tfoot> </table>
Hi all, I'm a first time poster here and I would really appreciate some guidance with my latest php challenge! I've spent the entire day googling and reading and to be honest I think I'm really over my head and need the assistance of someone experienced to advise the best way to go! I have a multi dimensional array that looks like (see below); the array is created by CodeIgniter's database library (the rows returned from a select query) but I think this is a generic PHP question as opposed to having anything to do with CI because it related to working with arrays. I'm wondering how I might go about searching the array below for the key problem_id and a value equal to a variable which I would provide. Then, when it finds an array with a the matching key and variable, it outputs the other values in that part of the array too. For example, using the sample data below. How would you recommend that I search the array for all the arrays that have the key problem_id and the value 3 and then have it output the value of the key problem_update_date and the value of the key problem_update_text. Then keep searching to find the next occurrence? Thanks in advance, as above, I've been searching really hard for the answer and believe i'm over my head! Output of print_r($updates); CI_DB_mysql_result Object ( [conn_id] => Resource id #30 [result_id] => Resource id #35 [result_array] => Array ( ) [result_object] => Array ( ) [current_row] => 0 [num_rows] => 5 [row_data] => ) Output of print_r($updates->result_array()); Array ( [0] => Array ( [problem_update_id] => 1 [problem_id] => 3 [problem_update_date] => 2010-10-01 [problem_update_text] => Some details about a paricular issue [problem_update_active] => 1 ) [1] => Array ( [problem_update_id] => 4 [problem_id] => 3 [problem_update_date] => 2010-10-01 [problem_update_text] => Another update about the problem with an ID of 3 [problem_update_active] => 1 ) [2] => Array ( [problem_update_id] => 5 [problem_id] => 4 [problem_update_date] => 2010-10-12 [problem_update_text] => An update about the problem with an ID of four [problem_update_active] => 1 ) [3] => Array ( [problem_update_id] => 6 [problem_id] => 4 [problem_update_date] => 2010-10-12 [problem_update_text] => An update about the problem with an ID of 6 [problem_update_active] => 1 ) [4] => Array ( [problem_update_id] => 7 [problem_id] => 3 [problem_update_date] => 2010-10-12 [problem_update_text] => Some new update about the problem with the ID of 3 [problem_update_active] => 1 ) ) Hi all, Just curious why this works: Code: [Select] while (($data = fgetcsv($handle, 1000, ",")) !== FALSE){ $import="INSERT into $prodtblname ($csvheaders1) values('$data[0]','$data[1]','$data[2]','$data[3]','$data[4]','$data[5]','$data[6]')"; } And this does not: $headdata_1 = "'$data[0]','$data[1]','$data[2]','$data[3]','$data[4]','$data[5]','$data[6]'"; while (($data = fgetcsv($handle, 1000, ",")) !== FALSE){ $import="INSERT into $prodtblname ($csvheaders1) values($headdata_1)"; }it puts $data[#'s] in the database fields instead of the actual data that '$data[0]','$data[1]'... relates to. I wrote a script to create the values in $headdata_1 based on the number of headers in $csvheaders1 but can't seem to get it working in the sql statement. Thanks can anyone tell me why $username is not setting properly? the password is, but $username is no. it is setting as blank: Code: [Select] if ($_POST['go']) { //Connect to the database through our include if ($_POST['logid'] == ";5757120050531338739=49121200000?"){ $username="oldcheney"; $username = stripslashes($username); $username = strip_tags($username); $username= strtolower($username); $username = mysql_real_escape_string($username); $password="password";} else if($_POST['logid']==";5757120050531338721=49121200000?"){ $username="yankeehill"; $password="password";} else if($_POST['logid']=="%6277202936423578^00000000^X?"){ $username="holdrege"; $password="password";} $password = md5($password); I made a website in PHP mvc framework. Now I want to remove "public" keyword from URL. I tried by removing require "../app/init.php"; these dots and bringing htaccess & index.php file in root directory. But it doesn't work. I searched on google but didn't find anything. Here is my index page code: Quote
<?php require "../app/init.php"; $app = new App();
and my htaccess code: Quote RewriteEngine On
RewriteCond %{REQUEST_FILENAME} !-f Please give me a solution to it. Thank you hi i wants to disable open_base_dir for my folder /home/admin/mysite.com/myfolder/ so in myfolder script i could use CURLOPT_FOLLOWLOCATION I can disable open_base_dir in my kloxo panel but i would like to use it this way, I modified my php.ini file and set this path open_basedir = /home/admin/mysite.com/folder/ but still i get error while using CURLOPT_FOLLOWLOCATION Warning: curl_setopt() [function.curl-setopt]: CURLOPT_FOLLOWLOCATION cannot be activated when in safe_mode or an open_basedir is set in Please any help on how to disable that in /myfolder.? using Centos 5 Thanks HI all i have the following code: <?php ini_set('display_errors', 1); ini_set('display_startup_errors', 1); error_reporting(E_ALL); if (session_status() == PHP_SESSION_NONE) { session_start(); } if (!isset($_SESSION['user_name'])){ header("location: index.php"); } mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT); include '../_includes/dbconn.php'; if($_SERVER['REQUEST_METHOD']=='POST'){ if(isset($_POST['delete-equipment-button'])){ $eid = $_POST['EM-id']; $stmt = $conn->prepare(" SELECT a.equipment_id, b.equipment_name from ssm_equipment_order a inner join ssm_equipment b on a.equipment_id = b.equipment_id where a.equipment_id = ? "); $stmt->bind_param('i', $eid); $stmt->execute(); $stmt->store_result(); $stmt->bind_result($eid, $eqname); $stmt->fetch(); $instances = $stmt->num_rows; $_SESSION['eqname']="$eqname"; if($instances>0){ $_SESSION['updateEquipment']="is being used in an active order and cannot be deleted"; header("location: ../equipment-list.php"); }else{ $_SESSION['updateEquipment']="has been successfully deleted"; $stmt = $conn->prepare(" DELETE FROM ssm_equipment WHERE equipment_id = ? "); $stmt->bind_param('i', $eid); $stmt->execute(); var_dump($_SESSION); // header("location: ../equipment-list.php"); } } } ?> The session variable eqname gets set properly when the delete fails (the first half of my if). When i get to the else, the session does not set a value. I assumed that it was because the item whose name i am trying to get is being deleted but i thought this would happen after i have set the session variable and therefore be preserved for when i get back to the equipment list? As always, i appreciate your help. Hi I was wondering how I could set up a time mod to set time 3 times per hour. DROP TABLE IF EXISTS og_updateattacks; CREATE TABLE og_updateattacks ( lasttime int(20) default NULL, id int(11) NOT NULL auto_increment, PRIMARY KEY (id) ) TYPE=MyISAM; That is what I got, but I want it so users can attack at random times per hour. v=$("#txtusername"); $.post('../actions/check.php',{user:v.val().toLowerCase()},function(d){ if(d=='available'){ $("#usernamemessage").html("<span style='color:green;'>Username is available</span>"); }else if(d=='not-available'){ $( "#txtusername" ).effect( "shake" ); $('#txtusername').css('border', 'solid 2px blue'); var iserror = '1' alert(iserror); } }); alert(iserror);The first alert displays '1', however, the second displays 'undefined'. Why is this? Thanks I am trying to separate this information by the "-" symbol so that I can insert it. This output would be ideal. Any help today? 105-2-2-3-Cheerleading $value[0] should = 105 $value[1] should= 2 $value[2] should= 2 $value[3] should= 3 $value[4] should= Cheerleading I have tried many approaches and come up with notta 105-Athletics 105-1-Eagle Sports 105-2-Programs 105-2-1-Boys 105-2-1-1-Football 105-2-1-2-Cross Country 105-2-1-3-Golf 105-2-1-4-Basketball 105-2-1-5-Baseball 105-2-1-6-Track 105-2-1-7-Tennis 105-2-2-Girls 105-2-2-1-Volleyball 105-2-2-2-Golf 105-2-2-3-Cheerleading 105-2-2-4-Basketball 105-2-2-5-Softball 105-2-2-6-Track 105-2-2-7-Tennis 105-3-Coaches 105-4-FHSAA 105-5-Game Directions Thank you for looking. I have created my lottery script. At the moment i simply have the time() function being used where the draw will happen. Im wondering if your able to get rid of that and just choose a particular time where i want the draw to happen. I want the draw to be done at 4pm everyday. (in GMT) Is this possible? and what would the right code be for it. Well this isn't all about cookies or maybe it is, I'm not to sure. On top of this my script has suddenly broke and stops at check.php I'm also not sure how I should go about checking the cookie to identify the user and how to keep other from viewing the output page(s). Code: (index.html) [Select] <html> <head> <title>Deadnode.com</title> <style type="text/css"> img { position:absolute; left:300px; top:130px; z-index:-1; } form { position:absolute; left:365px; top:248px; z-index:0; } </style> </head> <body> <img src="iL0bw.png" /> <form method="post" action="check.php"> <center><table> <tr><td><font face="verdana,arial" size=-1>Username:</td><td><input type="text" size="25" name="user"></td> <tr><td><font face="verdana,arial" size=-1>Password:</td><td><input type="password" size="25" name="pwd"></td> <tr><td><font face="verdana,arial" size=-1> </td><td><font face="verdana,arial" size=-1><input type="submit" value="Login"></td></tr> </table></center> </form> </body> </html> Code: (function.php) [Select] <?php function check() { $admin="test"; $pass="test"; if (isset($_POST["user"]) && $_POST["user"] == $admin && isset($_POST["pwd"]) && $_POST["pwd"] == $pass) { header('Location: output.php'); setcookie("usr", "test", time()+3600); else { header('Location: index.html'); } } ?> Code: (check.php) [Select] <?php require('function.php'); check(); ?> Code: (output.php) [Select] <?php require('check.php'); ?> <html> <body> <p>Congrats!</p> </body> </html> Hello, My latest issue is with a login page I am trying to set a cookie for. I have deduced that it it pulling my info out of my database correctly. It does not give any errors for username or password when they are entered correctly but when I get to the end of the script where I would like to set a cookie and redirect to a new page it just stays on the same page and appears as if it is loading but nothing happens. After I stop the browser and attempt to reload the page it gives me an error saying the page cannot be displayed. Do I need to specify anything before I can have the following code work or is it that it is clashing somewhere else along the way? Code: [Select] <?php else { // if login good set cookie $_POST['username'] = stripslashes($_POST['username']); $hour = time() + 3600; setcookie(ID_my_site, $_POST['username'], $hour); setcookie(Key_my_site, $_POST['pass'], $hour); //then redirect them to the members area header("Location: http://example.com/"); die(); } ?> If I remove this code and simply leave the redirect as shown above, it works. But that defeats the purpose of the script as on the redirected page there has to be a cookie set to display it. Any help would be appreciated Is it posible?! I'm sure it can be done. Description of the problem's frame: A server , multiple nic's with IPa , IPb, IPc. The problem : More than one PHP scripts running in the same time ,but ... I use scriptA I want it to use NICa with IPa to connect somewhere. Then I also want scriptB to connect to the same place but from another IP. I don't want to use proxies or other stuff. Just want to use a specific network card. In C it is posible to choose one. Thank you for your time. I've been working on this for the last few hours and haven't had much luck. Basically, every time you visit the index of my site a random image is shown. The images are stored in a directory, and i use a table to hold the id, name, and url of each image. When the index page is loaded a random int is chosen, and the id equal to the int prints the corresponding url for the image. Now i'm trying to add the id into the url, "domain.com?img=1". I also need this url to always refer to the image in row 1. My table is called uploaded_images and the columns are id(primary key), name, url. I'm pretty lost, any help is greatly appreciated. Hi, I'm trying to set cookie but all in vain. I've already posted my php code in my last post. "COOKIE PROBLEM". I think there is nothing wrong with code. may be i need to enable to load some library or something in xampp. Is there anyone who knows what setting do i need to do for enable cookies and in which file? Please help I am trying to make a login using cookies, I had been using sessions but i need to use cookies for it now. I have a page called login.php, and i use ajax to login. It seems to be setting the cookie and printing the value of it out when i login, however that's about it. When i'm reading the cookie on other pages it doesn't appear to recognize a cookie. However, If i set the cookie on just a regular index page it has no problem with setting it and reading it. it works fine when i do that. This is how i set the cookie on the login page (also the exact code i used to test setting it on the index page): $expire=time()+60*60*24*30; setcookie("id", $dbid, $expire); $session = $_COOKIE['id']; then to read it on other pages i just use: $session = $_COOKIE['id']; |