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PHP - Click A Button To Open 'custom' Urls
Hello, I have to do repetative search tasks over 3 websites. To make mylife easier (and for the fun of programming this), i'm trying to create the below:
[text input box] link1 (checkbox) link2 (checkbox) link3 (checkbox) [submit button] I would like each checkbox to represent a custom URL, which (when checked) will then enter the search 'term' from the input textbox and open the generated URL in a new window. For example my 3 URLS will look like the below. I need to replace the search term ('my search term' in this example) and add the "+" symbol for each word. h.ttp://www.google.com/search?num=100&hl=en&tbs=nws:1,sbd:1&q=my+search+term&aq=f&aqi=&aql=&oq=&gs_rfai= h.ttp://search.ft.com/search?ftsearchType=type_news&sortBy=gadatetimearticle&queryText=my+search+term h.ttp://www.reuters.com/search?blob=my+search+term Would anyone have some code snippets in order to get me started? I'm new to PHP and custom forms, but can 'read' code rather well as I have previous coding experiences. Any help at all would be hugely appreciated! Similar TutorialsI have a list names in a database table in MySQL that I need to repeat the same search for on my system to get the associated information. Is there a Loop command or some type of trick to making a php script search table1.row1 then table1.row2 then table1.row3 etc. Basically using the row in the table as a variable for the other commands in the code. I really need some direction. Thanks. This topic has been moved to mod_rewrite. http://www.phpfreaks.com/forums/index.php?topic=315930.0 Hello Everyone, I wanted to check in with this amazing community and see if anyone knows how to fully hide all URLs (phases) in a redirection sequence. Basically, I do not want anything in between a click and a land to be visible. Thanks, Josh Hello there, I'm trying to make when you click on a record, it opens another page with full details about this record the code for it is Code: [Select] <td><a href=\"user.php?id=".$row['id']."\">".$row['id']."</a></td> and it's working right, but when it opens the other page, no records is shown about the user with that ID So I figure the problem that I need to pass $row['id'] to my second page and make it search for it in the database how can I do that? here is the code from the second page (details of the record) Code: [Select] $dbObj = new DB(); $result = mysql_query("select * from users where id = '$userID'"); return $result; $row = @mysql_fetch_array($result); echo "<table width=98%>"; echo "<tr>"; echo "<td valign=\"top\" width=\"120px\">"; $rowid = $row['id']; echo "<td valign=\"top\">"; echo "<table> <tr> <td valign=\"top\" class=\"searchtitle\"> ".$row['fname']. ' ' .$row['mname']. ' ' .$row['lname']." </td> </tr> <tr> <td class=\"text\" valign=\"top\"> ".$row['mobile']." </td> </tr> <tr> <td> <a href=\"user.php?id=".$row['recruiterid']."\" class=\"link\">".$row['recruiterid']."</a> </td> </tr> </table>"; echo "</td>"; echo "</tr>"; echo "</table>"; Hello there, I was wondering what coding would be required to block users from clicking/viewing content. My idea was only to allow people to request songs every 2 minutes. would I use PHP for this in terms of the request form template which is: <?php $song = file_get_contents('http://site.com/song.php'); if(!empty($song)) { header('Location: song-requests-interface.php'); } else { header('Location: offline.html'); } ?> Or would I use JS. The trouble is, I'm unsure if JS would be able to remember the users details. They could easily refresh the page. Many thanks I have buttons for clocking in and clocking out at my school. When pressed they will get into DB and record current date and time. how to achieve the on click event in php?
<?php
include('dbcon.php');
include('session.php');
$result=mysqli_query($con, "select * from staff where OracleID='$session_id'")or die('Error In Session');
$row=mysqli_fetch_array($result);
echo("\n");
?>
<html>
<head>
<link rel="stylesheet" type="text/css" href="style.css">
</head>
<body>
<div class="form-wrapper">
<center>
<h3>Welcome: <?php echo $row['StaffName']; ?> </h3>
<?php if ($row['ClockedIn'] == True and $row['ClockedOut'] == False) {echo "You already clockedIn today, please clockOut";
echo '<button hidden> type="button" class="buttonstyle" >Clock Time IN!</button>';
echo '<button type="button" class="buttonstyle">Clock Time OUT!</button>';} ?>
<?php if ($row['ClockedOut'] == False and $row['ClockedIn'] == False) {echo '<button type="button" class="buttonstyle" >Clock Time IN!</button>';
echo '<button type="button" class="buttonstyle" >Clock Time OUT!</button>';} ?>
<?php if ($row['ClockedIn'] == True and $row['ClockedOut'] == True) {echo "You already clockedIn and ClockedOut today!";
echo '<button hidden> type="button" class="buttonstyle" >Clock Time IN!</button>';
echo '<button hidden> type="button" class="buttonstyle">Clock Time OUT!</button>';} ?>
</center>
</div>
</body>
</html>
Hi all, I am looking a developing a script that instead of using something like mysite.com/showproduct.php?id=1 I would like it to appear as mysite.com/php-editor Is their a simple way of doing this? I would still need to pull info from a database so the page would still need to be dynamic, I just want it to appear static! I am used to using the get id function of php, what would the workaround be? would the id be hidden from the url but still usable in a query? I have had a look at the apache mod_rewrite, but quite frankly, I dont understand it! Cheers Folks,
Look at this weird thing. I load the page and get echoed as expected: Did Not REQUEST_METHOD! Then, I click the SUBMIT button and to my astonishment I get echoed: Did Not POST->Submit! Got 2 buttons. Same result whenever clicking any. Why is that ? Check it out:
<?php
//include('error_reporting.php');
ini_set('error_reporting',E_ALL);//Same as: error_reporting(E_ALL);
ini_set('display_errors','1');
ini_set('display_startup_errors','1');
?>
<form name = "submit" method = "POST" action="">
<label for="domain">Domain:</label>
<input type="text" name="domain" id="domain" placeholder="Input Domain">
<br>
<label for="domain_email">Domain Email:</label>
<input type="email" name="domain_email" id="domain_email" placeholder="Input Domain Email">
<br>
<label for="url">Url:</label>
<input type="url" name="url" id="url" placeholder="Input Url">
<br>
<label for="link_anchor_text">Link Anchor Text:</label>
<input type="text" name="link_anchor_text" id="link_anchor_text" placeholder="Input Link Anchor Text">
<br>
<textarea rows="10" cols="20">Page Description</textarea>
<br>
<label for="keywords">Keywords:</label>
<input type="text" name="keywords" id="keywords" placeholder="Input Keywords related to Page">
<br>
<input type="checkbox" name="alert_visitor_type" id="alert_visitor_type" value="Give Alert: Visitor Type">
</label for="alert_visitor_type">Give Alert: Visitor Type</lablel>
<input type="checkbox" name="alert_visitor_potential" id="alert_visitor_potential" value="Give Alert: Potential Visitor">
</label for="alert_visitor_potential">Give Alert: Potential Visitor</lablel>
<br>
<input type="radio" name="tos_agree" id="tos_agree_yes" value="yes">
<label for="tos_agree_yes">Yes:</label>
<input type="radio" name="tos_agree" id="tos_agree_no" value="no">
<label for="tos_agree_no">No:</label>
<br>
<label for="tos_agreement">Agree to TOS or not ?</label>
<select name="tos_agreement" id="tos_agreement">
<option value="yes">Yes</option>
<option value="no">No</option>
</select>
<br>
<button type="submit" value="submit">Submit</button><br>
<button type="submit">Submit</button>
<br>
<input type="reset">
<br>
</form>
<?php
if($_SERVER['REQUEST_METHOD'] === 'POST')
{
if(isset($_POST['submit']))
{
mysqli_report(MYSQLI_REPORT_ALL|MYSQLI_REPORT_STRICT);
mysqli_connect("localhost","root","","test");
$conn->set_charset("utf8mb4");
$query = "INSERT into links (domain,domain_email,url,link_anchor_text,page_description,keywords,alert_visitor_type,alert_visitor_potential) VALUES (?,?,?,?,?,?,?,?)";
$stmt = mysqli_stmt_init($conn);
if(mysqli_stmt_prepare($stmt,$query))
{
mysqli_stmt_bind_param($stmt,'ssssssss',$_POST['domain'],$_POST['domain_email'],$_POST['url'],$_POST['link_anchor_text'],$_POST['page_description'],$_POST['keywords'],$_POST['alert_visitor_type'],$_POST['alert_visitor_potential']);
if(mysqli_stmt_execute($stmt) === FALSE)
{
die("Error\" . mysqli_stmt_error()");
}
mysqli_stmt_close($stmt);
mysqli_close($conn);
}
else
{
die("Did not INSERT!");
}
}
else
{
die("Did Not POST->Submit!");
}
}
else
{
die("Did Not REQUEST_METHOD!");
}
?>
Hello I am working in moodle and its code base is in PHP. I am a novice to moodle as well as PHP and not quite familiar with PHP syntax. Right now I have built a Web page in moodle, and its view.php file I need to implement a fuctionality on click of a button. On click of submit button, I am trying to implement a functionality and I have written the code for that under if(isset($_POST['submit])) { ...my code...} Also while creating the form I have set the attributes as follows: echo "<form method='post' action='" . $_SERVER['PHP_SELF']."?inpopup=". $_GET['inpopup']."&id=" . $_GET['id'] . "'>"; But irrespective of whether or not I click the button, whenevr the page loads for the first time, it perform the code written in IF loop as well. So Am i going wrong in implementing a functionality on click of button in PHP or is it something related to moodle, if anyone knows? Any help or suggestions would be appreciated. As I am stuck with this logic since last three days. Regards Code: [Select] <?php $db = mysql_connect("localhost", "root") or die("Could not connect."); //username and password if(!$db) die("no db"); if(!mysql_select_db("simple",$db)){ if(!mysql_select_db("regis",$db)){//database name die("No database selected.");}} $message=$_POST['message']; print "<form action='registration.php' method='post'onsubmit='return msg();'>"; print "Your message:<br>"; print "<textarea name='message' cols='40' rows='2'></textarea><br>"; print "<a onClick=\"addSmiley(':)')\"><img src='smile.gif'></a> "; print "<a onClick=\"addSmiley(':(')\"><img src='blush.gif'></a> "; print "<a onClick=\"addSmiley(';)')\"><img src='images/wink.gif'></a> "; print "<input type='submit' name='submit' value='Set Name'></form>"; print "<script language=\"Java Script\" type=\"text/javascript\">\n"; print "function addSmiley(a)\n"; print "{\n"; print "document.form.message.value += a;"; print "document.form.message.focus();\n"; print "}\n"; print "</script>\n"; print "<br><br>"; ?> <script type="text/javascript"> <?php function msg(){ if(isset($_POST['submit'])) //if submit button push has been detected { if(strlen($message)<1) { // print "You did not input a message"; echo"<SCRIPT LANGUAGE='javascript'>alert('You did not input a message')</SCRIPT>"; } else { $message=strip_tags($message); $IP=$_SERVER["REMOTE_ADDR"]; //grabs poster's IP $checkforbanned="SELECT IP from admin where IP='$IP'"; $checkforbanned2=mysql_query($checkforbanned) or die("Could not check for banned IPS"); if(mysql_num_rows($checkforbanned2)>0) //IP is in the banned list { print "You IP is banned from posting."; } else if(strlen($message)>=1) { $message=strip_tags($message); echo("<SCRIPT LANGUAGE='JavaScript'>window.alert('$message')</SCRIPT>"); // die("<meta http-equiv=\"refresh\" content=\"0; url=registration.php\">"); } $message=$_POST['message']; $message=strip_tags($message); /* if($_POST['username'] && $_POST['pass']) { $name = mysql_query("SELECT * FROM Persons"); $thedate = date("U"); //grab date and time of the post $insertmessage="INSERT into mesej (name,IP,postime,message) values('$name','$IP','$thedate','$message')"; mysql_query($insertmessage) or die("Could not insert message"); } */ } } return false; } return true; </script> ?> This is my code in my submit2.php im clicked submit button but if it is empty it should return an javascript alert error but why it directs through registration.php without reading the rules? I am new at php. I am trying to loop a number in each click of a button. See attached picture for reference. 1 should iterate after the click of the button and will stop to iterate when it gets to 5.
Here is my code:
<!DOCTYPE html>
<html>
<body>
<div>Question <?php $num = 5; $n = 1; $n <= $num; echo $n; ?> of <?php echo $num;?></div>
<form method="post"> <button id="button" class="button" value="add" name="add">Click</button> </form>
</body>
</html>
If I try to loop it this way,
<!DOCTYPE html>
<html>
<body>
<div>Question <?php $num = 5; for($i = 1; $i <= $num; $i++){ echo $i; } ?> of <?php echo $num;?></div>
<form method="post"> <button id="button" class="button" value="add" name="add">Click</button> </form>
</body>
</html>
the result is Question 12345 of 5.
Hi all I need some help, i have a list of orders on the left column and want to click on each order and display related db information in the right column in a div or other method for each record click. screenshot attached.
Hi.. I encountered problem in displaying joborder number or JO_No inside while loop. I want to happen is only JO_No will display after I click the Approved button and it will only appear on the row where the Approved button was click. Now in my code the JO_No was display automatically in the row of JO_No . here is my code: <?php error_reporting(0); date_default_timezone_set("Asia/Singapore"); //set the time zone $con = mysql_connect('localhost', 'root',''); if (!$con) { echo 'failed'; die(); } mysql_select_db("mes", $con); $Date_Shelve =date('Y-m-d H:i:s'); ?> <html> <head> <title>Job Order</title> <link rel="stylesheet" type="text/css" href="kanban.css" /> </head> <body> <div id="SR_date"> <label>Date :</label> <input type="text" name="Date_Shelve" id="Date_Shelve" value="<?php echo $Date_Shelve; ?>" size="16" readonly="readonly" style="border: none;"> </div> <div id="kanban_table"> <table width="auto"> <th> JO No.</th> <th> ETD </th> <th> PO No. </th> <th> SKU Code </th> <th> Description </th> <th> PO Req </th> <th> Requirements </th> <th> Priority</th> <?php $sql = "SELECT ETD, PO_No, SKUCode, Description, POReq FROM sales_order"; $res_so = mysql_query($sql, $con); $Approved = isset($_POST['priority']); if ($Approved) { $PO_No = $_POST['PO_No']; //----I want to display only the jo_number after click the approved button and it only display on the row where I click the approved button--- $sql = "SELECT jo_number FROM job_order ORDER BY jo_date DESC LIMIT 1"; $result = mysql_query($sql, $con); if (!$result) { echo 'failed'; die(); } $total = mysql_num_rows($result); if ($total <= 0) { $currentSRNum = 1; $currentYear = (int)(date('y')); $currentMonth = (int)(date('m')); $currentDay = (int)(date('d')); $currentSRYMD = substr($row['jo_number'], 0, 6); $currentYMD = date("ymd"); if ($currentYMD > $currentSRYMD) { $currentSRNum = 1; } else { $currentSRNum += 1; } } else { //---------------------------------------- $row = mysql_fetch_assoc($result); $currentSRNum = (int)(substr($row['jo_number'],0,3)); $currentSRYear = (int)(substr($row['jo_number'],2,2)); $currentSRMonth = (int)(substr($row['jo_number'],0,2)); $currentSRNum = (int)(substr($row['jo_number'],6,4)); $currentYear = (int)(date('y')); $currentMonth = (int)(date('m')); $currentDay = (int)(date('d')); $currentSRYMD = substr($row['jo_number'], 0, 6); $currentYMD = date("ymd"); if ($currentYMD > $currentSRYMD) { $currentSRNum = 1; } else { $currentSRNum += 1; } } $yearMonth = date('ymd'); $currentSR = $currentYMD . sprintf("%04d", $currentSRNum); //JO_No } while($row = mysql_fetch_assoc($res_so)){ echo "<form name='joborder_form' action='' method='post'>"; $PO_No = $row['PO_No']; echo "<tr> <td><input type='text' name='JO_No' id='JO_No' value='$currentSR' style='border:none;width:auto;' size='10'></td> <td><input type='text' name='ETD' id='ETD' value='$row[ETD]' style='border:none;width:auto;' size='10'></td> <td><input type='text' name='PO_No' id='PO_No' value='$row[PO_No]' style='border:none;' size='30'></td> <td><input type='text' name='SKUCode' id='SKUCode' value='$row[SKUCode]' style='border:none;' size='15'></td> <td><input type='text' name='Description' id='Description' value='$row[Description]' style='border:none;' size='35'></td> <td><input type='text' name='POReq' id='POReq' value='$row[POReq]' style='border:none;width:auto;' size='10'></td> <td> </td> <td><input type='submit' name='priority' value='Approved' id='priority'></td> </tr>"; echo "</form>"; } ?> </table> </div> </body> </html> I attach the sample image of my form. Any help is highly appreciated Thank you I have posted this problem in the PHP section but someone suggested I take it here because the hangup is likely in the JS. I have tried removing the JS validator with varying results; sometimes the form still requires double-clicking and sometimes it works fine. Please see my original post below:
Hello all,
I am an absolute beginner when it comes to PHP and Javascript but wanted a simple contact form for my website. I used the PHP code from one source and the Javascript validator code from another source and all is working fine except for one very annoying bug: I have to press the Submit button twice in order for the form to send the email. I've found that if the validator is already triggered, however, I only need to press the button once for it to submit. I have scoured the internet for a solution to this problem but am realizing this must be a hangup in the particular code I'm using and I'm just not experienced enough to troubleshoot it.
A little help is greatly appreciated. Thank you for your time.
Here's the client side code (truncated to only show relevant parts):
<html>
<head>
<script src="js/gen_validatorv4.js" type="text/javascript"></script>
</head>
<body>
<form method="post" action="contact.php" name="contactform">
<div class="row collapse-at-2 half">
<div class="6u">
<input name="name" placeholder="Name" type="text" />
</div>
<div class="6u">
<input name="email" placeholder="Email" type="text" />
</div>
</div>
<div class="row half">
<div class="12u">
<textarea name="message" placeholder="Message"></textarea>
</div>
</div>
<div class="row half">
<div class="12u">
<ul class="actions">
<li><input type="submit" value="Send Message" /></li>
<li><input type="reset" value="Clear form" /></li>
</ul>
</div>
</div>
</form>
<script type="text/javascript">
var myformValidator = new Validator("contactform");
myformValidator.addValidation("name","req",
"Please provide your name.");
myformValidator.addValidation("email","req",
"Please provide your email.");
myformValidator.addValidation("message","req",
"Please enter your message.");
myformValidator.addValidation("email","email",
"Please enter a valid email address.");
</script>
</body>
</html>
Just a quick help here... When you click click this radio button. <input type="radio" name="radio" id="radio_id_card" /> ID Card it will open the form below the radio button. <form> First Name: <input type="text" name="textfield" id="textfield" /> Last Name: <input type="text" name="textfield" id="textfield" /> <input type="submit" id="Send" value="Submit" /> </form> ------------------------------- hope someone can help me... i really have a bad time thinking of ways to do it.. thank you in advance.. I have dynamic images that have the "Like" button, it's basically like a wishlist. The way I want it to work is that when a user is not logged in, the 'Like' button will navigate them to a login popup (which I already made). You would think the answer would be all over the Internet and easy to find, but it’s not. I have searched many times, and in all the multitude of search results I have still never found an adequate usable answer. The MOST you ever find is someone saying how easy it is with PHP, but they don’t tell you how, even when the person they are answering asks them (odd). You can be that one in a billion person who finally answers it for real and helps someone out. I have a simple HTML form with data fields first_name, last_name, email, phone, country, a few hidden inputs, and a single submit button, like so: (Please note: the method is GET, not Post.) <form action="https://MyDomainOnMyServer.com/MyPHPScript.php”> <input type="text" name="first_name" value="" /> <input type="text" name="last_name" value="" /> <input type="text" name="email" value="" /> <input type="text" name="phone" value="" /> <input type="hidden" name="type" value="type123"> <input type="hidden" name="project" value="new123"> <select required name="country"> <option value="">Choose your country</option> <option value="US">United States</option> <option value="CA">Canada</option> <option value="GB">United Kingdom</option> <option value="Many More">Many More Countries</option> </select> <input type="submit" value="Submit Form" /> </form> NOTE: Originally, the form action would have been: action="https://TheirExampleDomainOnTheirRemoteServer.com/TheirRemotePHPScript.php" name="form1234" Upon clicking the single submit button only, what I need to have happen is this: 1. Send me an email to whatever@whatever.tld containing all the form submission data 2. Place the form submission data into a MySQL database having the corresponding data fields 3. Send the form submission contents including the hidden input values to "https://TheirExampleDomainOnTheirRemoteServer.com/TheirRemotePHPScript.php" name="form1234" AS IF that had remained set as the original form action to begin with So basically what I’m trying to obtain is the cleanest possible PHP script that will do those three things, which is essentially what others have asked for over the years in search results I have found, but no one has ever provided it in a clear instance that works. If I can just see such a script, I should be able to see how it works and then do what I need. Thanks. Reply I'm sure it's not much, but I'm not understanding something with custom error handlers: I've created a custom error handler, which I initially set when my page loads : set_error_handler(array ( new ErrorHandler(), 'handleError' ));
It seems to catch all internal PHP errors, such as if I: var_dump($non_existing_var); right after the set_error_handler.... Now, I have an object that throws an exception after: set_error_handler(array ( new ErrorHandler(), 'handleError' )); $locale = new \CorbeauPerdu\i18n\Locale(...); // this should throw an exception ... I thought that with an error handler set, I could 'skip' the try/catch for it, but doing so, PHP spits out in its internal log: PHP Fatal error: Uncaught CorbeauPerdu\i18n\LocaleException: ....
My error handler doesn't catch it at all before, thus my page breaks!! If I want it to go through the error handler, I have to init my Locale with a try/catch and use trigger_error() like so:
set_error_handler(array ( new ErrorHandler(), 'handleError' ));
try {
$locale = new \CorbeauPerdu\i18n\Locale(...); // this should throw an exception
}
catch(Exception $e) {
trigger_error($e->getMessage(), E_USER_ERROR);
}
...
Is this normal ? I thought one of the goals of the error_handler was to catch anything that wasn't dealt with? Thanks for your answers! |
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