PHP - Basic Question On Update Query

Ok, I know this is a really simple one, but I haven't done any coding for a couple of month and i'm a bit rusty.

I'm trying to add a field from a MySQL query to a Google calendar add button link so I can create a dynamic 'add to calendar' button from my gig list.

So on the gig list page that echo's all the dates from the database, I want to add the venue name to the 'text' section of the google URL -

Code: [Select]
<a href=\"http://www.google.com/calendar/event?action=TEMPLATE&text=VENUE HERE&dates=20060101T000000Z/20060101T000000Z&details=gig%20text&location=gig%20town&trp=false&sprop=www.the-guards.co.uk&sprop=name:The%20Guards\" target=\"_blank\"><img src=\"http://www.google.com/calendar/images/ext/gc_button6.gif\" border=0></a>
if I echo the field like so -

Code: [Select]
echo"{$row['gl_venue']}";
I get the correct result - I just can remember how to embed the php within the html, everything i've tried has failed so far.

Once i've got this sorted i can go ahead and add the date, location fields etc.

Hello all,   Based on the suggestion of you wonderful folks here, I went away for a few days (to learn about PDO and Prepared Statements) in order to replace the MySQLi commands in my code. That's gone pretty well thus far...with me having learnt and successfully replaced most of my "bad" code with elegant, SQL-Injection-proof code (or so I hope).   The one-and-only problem I'm having (for now at least) is that I'm having trouble understanding how to execute an UPDATE query within the resultset of a SELECT query (using PDO and prepared statements, of course).   Let me explain (my scenario), and since a picture speaks a thousand words I've also inlcuded a screenshot to show you guys my setup:   In my table I have two columns (which are essentially flags i.e. Y/N), one for "items alreay purchased" and the other for "items to be purchased later". The first flag, if/when set ON (Y) will highlight row(s) in red...and the second flag will highlight row(s) in blue (when set ON).   I initially had four buttons, two each for setting the flags/columns to "Y", and another two to reverse the columns/flags to "N". That was when I had my delete functionality as a separate operation on a separate tab/list item, and that was fine.   Now that I've realized I can include both operations (update and delete) on just the one tab, I've also figured it would be better to pare down those four buttons (into just two), and set them up as a toggle feature i.e. if the value is currently "Y" then the button will set it to "N", and vice versa.   So, looking at my attached picture, if a person selects (using the checkboxes) the first four rows and clicks the first button (labeled "Toggle selected items as Purchased/Not Purchased") then the following must happen:   1. The purchased_flag for rows # 2 and 4 must be switched OFF (set to N)...so they will no longer be highlighted in red. 2. The purchased_flag for row # 3 must be switched ON (set to Y)...so that row will now be highlighted in red. 3. Nothing must be done to rows # 1 and 5 since: a) row 5 was not selected/checked to begin with, and b) row # 1 has its purchase_later_flag set ON (to Y), so it must be skipped over.   Looking at my code below, I'm guessing (and here's where I need the help) that there's something wrong in the code within the section that says "/*** loop through the results/collection of checked items ***/". I've probably made it more complex than it should be, and that's due to the fact that I have no idea what I'm doing (or rather, how I should be doing it), and this has driven me insane for the last 2 days...which prompted me to "throw in the towel" and seek the help of you very helpful and intellegent folks. BTW, I am a newbie at this, so if I could be provided the exact code, that would be most wonderful, and much highly appreciated.   Thanks to you folks, I'm feeling real good (with a great sense of achievement) after having come here and got the great advice to learn PDO and prepared statements.   Just this one nasty little hurdle is stopping me from getting to "end-of-job" on my very first WebApp. BTW, sorry about the long post...this is the best/only way I could clearly explaing my situation.   Cheers guys!

case "update-delete":
	if(isset($_POST['highlight-purchased'])) 
		{
			// ****** Setup customized query to obtain only items that are checked ******
			$sql = "SELECT * FROM shoplist WHERE";
					for($i=0; $i < count($_POST['checkboxes']); $i++)
						{
							$sql=$sql . " idnumber=" . $_POST['checkboxes'][$i] . " or";
						}
					$sql= rtrim($sql, "or");
											
			$statement = $conn->prepare($sql);
			$statement->execute();
																						
			// *** fetch results for all checked items (1st query) *** //
			$result = $statement->fetchAll();

			$statement->closeCursor();
											
			// Setup query that will change the purchased flag to "N", if it's currently set to "Y"
			$sqlSetToN = "UPDATE shoplist SET purchased = 'N' WHERE purchased = 'Y'";
											
			// Setup query that will change the purchased flag to "Y", if it's currently set to "N", "", or NULL
			$sqlSetToY = "UPDATE shoplist SET purchased = 'Y' WHERE purchased = 'N' OR purchased = '' OR purchased IS NULL";

			$statementSetToN = $conn->prepare($sqlSetToN);
			$statementSetToY = $conn->prepare($sqlSetToY);
											
			/*** loop through the results/collection of checked items ***/
			foreach($result as $row)
				{
					if ($row["purchased"] != "Y")
						{
							// *** fetch one row at a time pertaining to the 2nd query *** //
							$resultSetToY = $statementSetToY->fetch();
															
							foreach($resultSetToY as $row)
								{															
									$statementSetToY->execute();																
								}
						}
					else
						{
							// *** fetch one row at a time pertaining to the 2nd query *** //
							$resultSetToN = $statementSetToN->fetch();
															
							foreach($resultSetToN as $row)
								{															
									$statementSetToN->execute();																
								}
						}
				}
				break;
		}

 CRUD Queston.png   20.68KB   0 downloads    

I created this code to upload a member's main picture on his member page on website.  I'll only include the query part of the code since that's what is relevant to my problem.  The idea is basically to upload a new picture onto the database if no picture already exists for that member and display the picture on the page.  If a picture already exists, then the script replaces the old picture with the new one upon upload.    But for whatever reason
I don't understand,  when I try to replace the old pic, it gets inserted in a new row on the database instead of replacing the old row, and the new pic gets displayed on the web page alongside the old. Code: [Select]
$query = "SELECT username FROM images WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'";
        $result = @mysql_query($query);
        $num = @mysql_num_rows($result);
       
        if ($num> 0)   {

    //Update the image

    $update = mysql_query("UPDATE images SET image = '" . $image['name'] . "' WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'"); 

   
          $_SESSION['error'] = "File updated successfully.";  //really should be session success message.

                    header("Location: member.php");


    exit;
}

else

{
// NOTE: This is where a lot of people make mistakes.
// We are *not* putting the image into the database; we are putting a reference to the file's location on the server

    $sql = "insert into images (member_id, image_cartegory, image_date, image) values ('{$_SESSION['id']}', 'main', NOW(), '" . $image['name'] . "')";

    $result = mysql_query($sql) or die ("Could not insert data into DB: " . mysql_error());

    $_SESSION['error'] = "File uploaded succussfully.";  //really should be session success message.

                    header("Location: member.php");
                                }


So can anyone tell me what the problem is?  Could the fact that my insert script actually uploads the image onto a folder on my server and only stores the path name in the database have anything to contribute to the mixup?  Appreciate your responses in advance.

I have a table 'combo' with two fields, id and char. I want to populate a table, with the following query which fails. $sql = mysql_query("SELECT id,char FROM combo ORDER BY id DESC LIMIT 28");  I a bit rusty on sql but can't see what is wrong with this. Can anyone help please.

Hello,

Im from the Netherlands and i have a little question about php.

I have a form in php where administrators can make new users. They can fill in a name, password, age and can select a role. The role is a dropdown menu where they can select athlete, researcher and trainer. My problem is that when they select a role, i want that selected role transfert to a php variable. I want to use the variable in a if statment, when sporter selected a new dropdown appears with options like tennis, hockey....

I have seen a lot on google about this with jquery and stuff, but i cant find a good example.

Can u help me?

Thanks.