PHP - Obtain Such A Reference In The Script

Hi,

I just need someone to check that a couple of lines I've written do what I believe them to do... i.e. check my logic!

I'm developing a booking form for booking on events. Each booking needs a unique reference, which needs to be meaningless to the customer, so I am BASE36 encloding it.

As the booking is be saved to a MySql database, my approach is to use the auto-incremented ID for the record to make the reference unique. The increment starts at 10000, and I add a random number before coding to make the encoded reference longer. I then BASE36 encode it to make it appear random.

Am I right in thinking the reference produced WILL be unique ... provided the auto-inc ID is unique?

$ref = rand(100,999) . $auto_incremented_id; //e.g. 354 & 10012 = 35410001
$ref_encoded = strtoupper(base_convert($rand, 10, 36)); // e.g.UD4J8P
Thanks

Hello, I've just started learning PHP, JavaScript and I've got a big problem on my website. I'm getting this ReferenceError. I know what's the problem, but I don't know how to solve it, and I know people can do it for money but I don't have money, I'm searching for someone who's willing to help newbie. As I said I'm begginer, and I know something. The main problem is because I want to use GKPlugin and Player(jwplayer). Plugin need to use object, example:

<object id="flashplayer" classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" width="600" height="400">
<param name="movie" value="player.swf" />
<param name="allowFullScreen" value="true" />
<param name="allowScriptAccess" value="always" />
<param name="FlashVars" value="plugins=plugins/proxy.swf&proxy.link=http://www.vidbull.com/53qx9uo10k5d" />
<embed name="flashplayer" src="player.swf" FlashVars="plugins=plugins/proxy.swf&proxy.link=http://www.vidbull.com/53qx9uo10k5d" type="application/x-shockwave-flash" allowfullscreen="true" allowScriptAccess="always" width="600" height="400" />
</object>

Script is generetad just to embed with iframe, and the problem is when I replace it with object, then I'm getting this error. I know that JS can't "call" that iframe to show because I've replaced it with object. You guys probably know about what I'm talking. I'm just searching for some instructions, guidelines from you.
 

    ReferenceError: embeds is not defined
    

    if (embeds[embedid].indexOf("rapidplayer")== iframe_ad){

Here's the rest of code, I think it's used to show iframe.

 

    elseif (substr_count($link,"gorillavid")){
    $video_id = explode("/",$link);
    if (isset($video_id[count($video_id)-1])){
    $video_id = $video_id[count($video_id)-1];
    $embed = '<object id="flashplayer" classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000"                                                                      width="600" height="400">
    <param name="movie" value="http://www.kiinc.com/videott/player.swf" />
    <param name="allowFullScreen" value="true" />
    <param name="allowScriptAccess" value="always" />
    <param name="FlashVars" value="plugins=http://www.kiinc.com/videott/plugins/proxy.swf&proxy.link=http://gorillavid.in/'.$video_id.'" />
    <embed name="flashplayer" src="player.swf" FlashVars="plugins=http://www.kiinc.com/videott/plugins/proxy.swf&proxy.link=http://gorillavid.in/'.$video_id.'" type="application/x-shockwave-flash" allowfullscreen="true" allowScriptAccess="always" width="600" height="400" />
    </object>';

This is the original code. Don't look at providers(source as gorillavid) because I used gorillavid in previous an posted another example from another source (zalaa)
 

    elseif (substr_count($link,"zalaa")){
    $video_id = explode("/",$link);
    if (isset($video_id[count($video_id)-1])){
    $video_id = $video_id[count($video_id)-1];
    $embed = '<IFRAME SRC="http://www.zalaa.com/embed-'.$video_id.'.html" FRAMEBORDER=0 MARGINWIDTH=0 MARGINHEIGHT=0 SCROLLING=NO WIDTH='.$width.' HEIGHT='.$height.'></IFRAME>';

Function which embed links and should embed GKPlugin/Player:

// general image link

    if (!$embed){
    $embed = "<div style='background-color:#000000; width: ".$width."px; height: ".$height."px;text-align:center;cursor:pointer;' onclick='window.open(\"$link\");'>";
    $embed.= "<p style='text-align:center; padding-top: 70px;'>";
    $embed.= "<a href='$link' target='_blank' style='font-size:24px; color: #ffffff !important'>Click here to play this video</a>";
    $embed.= "</p>";
    $embed.= "</div>";
    }
    return $embed;
    }

JavaScript code:

 

  function getEmbed(embedid){
        if (embeds[embedid].indexOf("rapidplayer")== iframe_ad){
            var html_content =     "<div class='fake_embed' id='fake_embed"+embedid+"' onclick='closeFakeEmbed("+embedid+");'>" +
                                    "<br /><br />" +
                                    "<div class='fake_embed_ad_close'><a href='javascript:void(0);' onclick='closeFakeEmbed("+embedid+");'>Close Ad</a></div>" +
                                    "<div class='fake_embed_ad' id='fake_embed_ad" + embedid +"'>" +
                                        "<iframe src='"+baseurl+"/iframe_ad.php' width='300' height='300' frameborder='NO' border='0'></iframe>" +
                                    "</div>" +
                                    "<div class='fake_embed_bar'><span class='fake_embed_bar_right'></span></div>" +
                                "</div>" +
                                "<div id='real_embed"+embedid+"' style='display:none'>"+embeds[embedid]+"</div>";
            
            
            jQuery('#videoBox'+embedid).html(html_content);
            jQuery('#videoBox'+embedid).show();
        } else {
            jQuery('#videoBox'+embedid).html(embeds[embedid]);
            jQuery('#videoBox'+embedid).show();
        }    
        
    }
    
    function countDown(embedid){
        showCounter = showCounter-1;
        jQuery('span#counter').html(showCounter);
        if (showCounter>0){
            showTimer = setTimeout('countDown('+embedid+');',1000);
        } else {
            showTimer = null;
            showCounter = 20;
            getEmbed(embedid);
        }
    }
    
    function changeEmbed(embedid, counter){
        if (counter == 0){
            jQuery('.embedcontainer').html('');
            jQuery('.embedcontainer').hide();
            getEmbed(embedid);
        } else {
            if (showTimer){
                clearTimeout(showTimer);
            }
            showTimer = null;
            showCounter = counter;
            
            jQuery('.embedcontainer').html('');
            jQuery('.embedcontainer').hide();
            jQuery('#videoBox'+embedid).html(js_lang.ticker);
            jQuery('#videoBox'+embedid+' span#counter').html(showCounter);
            jQuery('#videoBox'+embedid).slideDown("slow");
            
            showTimer = setTimeout('countDown('+embedid+');',1000);
        }
        /*
        jQuery('li.selected').removeClass('selected');
        jQuery('#selector'+embedid).addClass('selected');
        */
    }

hello.

say i have list and i want the correct children under each parent

so i have
$id
$parent_id
$type
$name

in the db i have
4 parents each with 2 children

id=1 - type=parent - parent_id=0 - name=p1
id=2 - type=parent - parent_id=0 - name=p2
id=3 - type=parent - parent_id=0 - name=p3
id=4 - type=parent - parent_id=0 - name=p4
id=5 - type=child - parent_id=1 - name=c1
id=6 - type=child - parent_id=1 - name=c2
id=7 - type=child - parent_id=2 - name=c3
id=8 - type=child - parent_id=2 - name=c4
id=9 - type=child - parent_id=3 - name=c5
id=10 - type=child - parent_id=3 - name=c6
id=11 - type=child - parent_id=4 - name=c7
id=12 - type=child - parent_id=4 - name=c8

so how would i do the code?

i thought i could do it like this but its not working.

Code: [Select]
<?php

$family = Family::find_all();
foreach($family as $familys){

$id = $familys->id;
$type = $familys->type;
$parent_id = $familys->parent_id;
$name = $familys->name;


echo'
<ul>';
if($type == "parent"){
echo $name;
} 
echo' </ul>


<li>';
if($type == "child" && $parent_id == $id){
echo $name;
} 
echo' 
</li>';
}
?>


all i get back is

    p1

    p2

    p3

    p4


no children

??



if i remove Quote

$parent_id == $id

from Quote

if($type == "child" && $parent_id == $id){


i get this

    p1

    p2

    p3

    p4

c1

c2

c3

c4

c5

c6

c7

c8

but they are not listed under the correct parent





i also tried moving the </ul> to the bottom but i get the same
Code: [Select]
<?php

$family = Family::find_all();
foreach($family as $familys){

$id = $familys->id;
$type = $familys->type;
$parent_id = $familys->parent_id;
$name = $familys->name;



echo'
<ul>';
if($type == "parent"){
echo $name;
} 
echo'


<li>';
if($type == "child"){
echo $name;
} 
echo' 
</li>
</ul>';
}
?>



any thoughts?

thanks

rick

Can someone explain this strange behavior:


$aArray = array(
1 => null,
2 => null,
3 => null,
);
foreach($aArray as $key => &$val)
{
$val = "Some Value";
foreach($aArray as $Xkey => $Xval){} // Second foreach
}
var_dump($aArray);

Rsult is:
array(3) {
  [1]=>
  string(10) "Some Value"
  [2]=>
  NULL
  [3]=>
  NULL
}


It looks like second foreach breaks reference, why?

Hi all,

I have been coding in PHP for a fair while now and I have come across variables by reference, but I don't really know:
a) how they work;
b) when to use them;
c) why they are used;

Can anyone here please clarify these issues please.

Thanks in advance!

Dear All,

Am new to PHP. now i want to online cargo tracking system in php. in that i create the reference id for each user to track the shipments. in that user must login and track the shipments. now i need the code for the specific user only view they shipments only. the other user can't be check the other shipments. so i need how to link the user and reference id. kindly advice me.

OK, so I have the following file that has database functions:

<?php

function dbDelete($param){
$conDelete = mysql_connect($url,'username','password',true);
mysql_select_db('my_db',$conDelete);
mysql_query($param,$conDelete);
mysql_close();
   if(isset($conDelete)){
   mysql_close($conDelete);
   }
}
?>

I include the above file in a session handling file.  But for some reason the new file can't call the above function as follows:
<?php
include_once 'the above stated file';
function timeOut(){
        dbDelete("DELETE FROM acctussessi WHERE acctussessi_usid = '$sessius[0]'");
   $_SESSION = array();
   setcookie(session_name(),'',time()-4200);
   session_destroy();
}
//CHECK FOR TIMEOUT REQUEST
switch($_GET['xyz']){
   case 'timeout':
   timeOut();
   header("Location: /?xyz=timedout");
   break;
   case 'logout':
   timeOut();
   header("Location: /?xyz=loggedout");   
   break;
   case 'refresh':
   dbUpdate("UPDATE acctussessi SET acctussessi_time = ".time()." WHERE acctussessi_unid ='".$token."'");   
   break;
}
?>

dbDelete isn't being called inside of the TimeOut() function.  The only way it works is by doing the following:

<?php
function timeOut(){
   $_SESSION = array();
   setcookie(session_name(),'',time()-4200);
   session_destroy();
}
//CHECK FOR TIMEOUT REQUEST
switch($_GET['xyz']){
   case 'timeout':
      dbDelete("DELETE FROM acctussessi WHERE acctussessi_usid = '$sessius[0]'");
   timeOut();
   header("Location: /?xyz=timedout");
   break;
   case 'logout':
      dbDelete("DELETE FROM acctussessi WHERE acctussessi_usid = '$sessius[0]'");
   timeOut();
   header("Location: /?xyz=loggedout");   
   break;
   case 'refresh':
      dbUpdate("UPDATE acctussessi SET acctussessi_time = ".time()." WHERE acctussessi_unid ='".$token."'");   
   break;
}
?>
But this is annoying and repetitive.  What is going on?

Thanks in advance.

Hi everyone,

This is driving me crazy. I need to reference different files located in different folder structure. For example, I have the following file structure.

/my_project/
/my_project/database/database_script.php
/my_project/index.php

1. If I want to reference /my_project/index.php from /my_project/database/database_script.php, how can I reference it ?
2. From /my_project/index.php to /my_project/database/database_script.php , it's obvious all I gotta do it include("/database/database_script.php").

I use $_SERVER('DOCUMENT_ROOT"), to solve the 1. problem. It works on my XAMPP local machine but when I uplode it onto the server, there's a problem.  The path becomes '/my_project/my_project/database/database_script.php". Is there a universal way (more like a standard way) to reference files in php so that I won't need to change every file path once I upload those onto the server ?

Regards,

If getValue is given a path which doesn't exist, I can use the isset check to return null.

I can also use the uncommitted $tmp =&$tmp[$key];.  Why does this prevent an undefined index warning?

 

    public function getValue(string $path) {
        $path=explode('.', $path);
        $tmp=$this->config;
        foreach($path as $key) {
            //if(!isset($tmp[$key])) return null;
            //$tmp =$tmp[$key];
            $tmp =&$tmp[$key];
        }
        return $tmp;
    }

 

Hi Guys

Probably a simple answer to this.

Writing a script where I have a foreach to escape data in a multi dimensionsal array - destined for the database.

I want to preserve the the escaped values in the array so I've passed in the value by referece. See code below:

Code: [Select]
foreach($myarray as $key=>$value){

foreach($value as $k=>$v){

$v =   $mysqli->real_escape_string(&$v);
echo  $v ."<br/>";

}
 
  }


I've switched on error_reporting(E_STRICT), because i read it was good practice to build your scripts with this on.

Anyway - when i pass by reference I get a message as follows:

Quote

Deprecated: Call-time pass-by-reference has been deprecated in C:\wamp\www\wh\C.php on line 105


So if pass by reference is deprecated, what's the alternative?

I realise i could pass the new values to a new array. But does this mean i shouldn't pass by reference anymore?

Many thanks and sorry for going round the planet to ask such a simple question.

Drongo

Hi all, I'm trying to understand passing by reference.  Here is a copy of the code and the results:
Code: [Select]
<?php

        $a1 = 15;
        $b1 = 20;
        
        echo addone($a1, $b1);
        echo "<br/>";
        
        function addone($n1, $n2){
            $n1 = $n1 += 2;
            $n2 = $n2 += 2;
            return $n1 . " " . $n2;
        };
        
        echo addonetwo($a1, $b1);
        
        function addonetwo($n1, $n2){
            $n1 = $n1 += 2;
            $n2 = $n2 += 2;
            return $n1 . " " . $n2;
        }
        ?>
The result output is:
17 22
17 22

If I change the code to add "&" before the "addone" function:
Code: [Select]
function addone(&$n1, &$n2){
            $n1 = $n1 += 2;
            $n2 = $n2 += 2;
            return $n1 . " " . $n2;
        };
Then the output is:
17 22
19 24

I don't understand what's going on.  Why is the "&" incrementing the changed variable and in the first example it's incrementing the variables as defined.

I am writting a php function that uses mysql to get user data - pretty common, right

Well, my issue is that I need to run a check in my file system.  Users profile pictures are stored in my image directory as .png's.  I need to have my function check that directory and if an image matches their id, then return their information.  I only want the user data if they have an image uploaded.

Here is my current function:

Code: [Select]
function fetch_users_login($limit)
{
$limit = $limit(int);

$sql = "SELECT
                `users`.`id`,
                `users`.`firstname`,
                `users`.`lastname`,
                `users`.`username`,
`user_privacy`.`avatar`
            FROM `users`
LEFT JOIN `user_privacy`
            ON `users`.`id` = `user_privacy`.`uid`
WHERE `users`.`status` > 2
AND `user_privacy`.`avatar` = 1
ORDER BY `users`.`id` DESC
LIMIT 0, {$limit}";

$result = mysql_query($sql) or die(mysql_error());

$users = array();

$i = 0;

while(($row = mysql_fetch_assoc($result)) !== false)
{
$users[$i] = array(
'id' => $row['id'],
'firstname' => $row['firstname'],
'lastname' => $row['lastname'],
);

$users[$i]['avatar'] = getUserAvatar($row['username']);

$i++;
}

return $users;
}

Im trying to understand the code below. (taken from an O'REILLY book)

Im trying to get my head around this, so can anyone tell me if im thinking about this in the right way;

The function (fix_names) borrows the values from $a1,$a2 and $a3 and puts them into $n1,$n2, and $n3. It then processes the strings contained within these newly created variables and then returns the processed values back into $a1,$a2,and $a3?

The variables $n1,$n2, and $n3 cannot be echoed as they were created within the function.?

Please correct me if im wrong.

Code: [Select]
<html>
<head>
</head>
<body>
<?php

$a1 = "EDWARD";  $a2 = "thomas";  $a3 = "wriGHT";

fix_names($a1,$a2,$a3);
echo $a1." ".$a2." ".$a3;

function fix_names(&$n1,&$n2,&$n3)
{
$n1 = ucfirst(strtolower($n1));
$n2 = ucfirst(strtolower($n2));
$n3 = ucfirst(strtolower($n3));
}

?>
</body>
</html>

Hello all,
   I'm a PHP newbie, so please pardon me if this question has already been asked somewhere in this forum. I have been reading the PHP documentation. On this page http://www.php.net/manual/en/language.references.pass.php, I came across this code:

<?php
... snip ...
function &bar()
{
    $a = 5;
    return $a;
}
foo(bar());
?>

This is returning a reference to local variable $a. Coming from a C/C++ background, my intuition tells me this just shouldn't work, since the local variable $a should be deleted as soon as the function "bar" returns. The code seems to work, though. My guess is that PHP is basically ref-counting and garbage collecting local variables like $a, and so it will not be automatically cleaned up on call exit. Is this about right? Thanks!

WN

I am wondering how can I insert integers in the database without manually input it in the form.

I am looking to fill the product_id and customer_id table. I would do it but only by sequence and '' quotes at the VALUE part of an INSERT statement. Also condition the insert of product_id and customer_id according to the id in the SESSION variable.

Code: [Select]
<?php 
session_start();
 
if (isset($_SESSION['id'])) {
    $userid = $_SESSION['id'];
    $username = $_SESSION['username'];
   

$fname = $_POST['firstname'];
$lname = $_POST['lastname']; 
$telephone = $_POST['telephone'];
        $city = $_POST['city'];
$state = $_POST['state'];
$itemname = $_POST['product_name'];
$price = $_POST['price'];
$details = $_POST['details'];
        $category = $_POST['category'];
$subcategory = $_POST['subcategory'];
        $product_id = $_POST['product_id'];
$customer_id = $_POST['customer_id'];
        $date_sold = $_POST['date_sold'];



      $sqlinsert = "INSERT INTO customers
                            (id,firstname,lastname,telephone,city,state,product_name,price,details)            
                            VALUES('','$fname','$lname', '$telephone','$city','$state','$itemname','$price','$details')";

      $sqlinsert2 = "INSERT INTO products
                            (id,product_name,price,details,category,subcategory)            
                            VALUES('','$itemname','$price','$details','$category','$subcategory')";

$sqlinsert3 = "INSERT INTO sales
                               (id,product_id, customer_id, date_sold)            
                               VALUES('','$product_id','$customer_id','$date_sold')";


$enterquery = mysql_query($sqlinsert) or die(mysql_error()); 
$enterquery2 = mysql_query($sqlinsert2) or die(mysql_error()); 
$enterquery3 = mysql_query($sqlinsert3) or die(mysql_error()); 
}
?>
The above insert its respective fields in each table but how is it possible to INSERT it according to the SESSION['id]; so that it INSERT according to the costumer id plus that it generates and INSERT automatically in the product_id and customer_id related to the product_id and customer_id fields in products and customer table? without manually doing it.

any references will be appriciated because the above code seems like the product_id and customer_id won't INSERT in relations to the customer and product table.

One more thing the product_id and customer_id won't be pass from the form to this file but rather a value will be INSERT it in their field according to the id in customer and products table.