PHP - Displaying Mysql Data In A Grid
Hi guys. I'm trying to build a games site for a friend. Currently, the front-end (HTML/CSS) of the site is done. Now, I want to make a way for him to easily add games to the site. Ideally, I'd like to make a database with the following columns: ID, Name, Category, Link, Thumbnail_Link. So, those would be the ID, name of the game, the category, a link to the game, and a link to the 50x50 thumbnail image respectively. Then, using PHP, I'd like to call the first x number (not sure what it will be yet, let's say 50) and make format it as a grid in the following way: There's the thumbnail image followed by the game name, and they're all a clickable link to the game URL. Is this possible? How would I go about doing this? I've already set up a database for a login module to the site, so each page has already opened a connection to the MySQL database. However, I've only ever done basic PHP for mail forms and am otherwise extremely new to it, and am especially new to MySQL.
Could anyone walk me through how to do this or even give me a quick example script to work off of? Thanks, any of your time is greatly appreciated! Similar TutorialsThis topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=327455.0 Ok... I need some help - I want to show a players balance in a game beside there name (Balance is in mysql database)I can do that but... - I also want to show if there online or offline at the same time( This is stored in a different database) I have the code which says whether they are online or offline <?PHP // Conect to the Mysql Server $connect = mysql_connect("localhost","scswccla_bukkit","********"); //connect to the database mysql_select_db("scswccla_bukkit"); //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 1"); //title echo "<font size='100'>NovaCraft Users</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='black'>|Online|<br><font color='green'>$users</font></font><br>"; endwhile; //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 0"); //title echo "<font color='black'>|Offline|</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='red'>$users</font><br>"; endwhile; ?> Here is the page: www.scswc.com/Offline_Users.php displaying that But I want to Create something like this: Nocvacraft Players |Online| Name:Player Balance:$20 |Offline| Name:Player Balance:$15 Here is what I have tried: <?PHP // Conect to the Mysql Server $connect = mysql_connect("localhost","scswccla_bukkit","**********"); //connect to the database mysql_select_db("scswccla_bukkit"); //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 1"); $query2 =mysql_query("SELECT * FROM iBalances WHERE player = $users"); //title echo "<font size='100'>NovaCraft Users</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query) $rows2 = mysql_fetch_array($query2)): $users = $rows['name']; $balance = $rows2['balance']; echo "<font color='black'>|Online|<br><font color='green'>Name:$usersBalance:$balance</font></font><br>"; endwhile; //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 0"); //title echo "<font color='black'>|Offline|</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='red'>$users</font><br>"; endwhile; ?> I know I am trying to use a variable before it is been set - but if I don't how I have tried this as well... <?PHP // Conect to the Mysql Server $connect = mysql_connect("localhost","scswccla_bukkit","**********"); //connect to the database mysql_select_db("scswccla_bukkit"); //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 1"); //title echo "<font size='100'>NovaCraft Users</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='black'>|Online|<br><font color='green'>Name:$users</font></font><br>"; endwhile; //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 0"); //title echo "<font color='black'>|Offline|</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='red'>$users</font><br>"; endwhile; $query = mysql_query("SELECT * FROM iBalances WHERE player = $users"); WHILE($rows = mysql_fetch_array($query)): $balance = $rows['balance']; echo "<font color='red'>$users $balance</font><br>"; endwhile; // ?> Can you use variables in mysql_query()?Is that why it isn't working? This is my first php script so if I need to give you more information for you to help me just tell me Thanks Here is database pictures iBalances users_online So i pull some records out of a mysql table and i want to display them in 5 even columns. I'm not entirely sure how to do the math & logic to accomplish this. The pull is simple $qry = "SELECT DIST_PART_NUM FROM $tablename"; $sql = mysql_query($qry) or die(mysql_error()); while($res = mysql_fetch_assoc($sql)) { // CREATE 5 even columns here. } so let's say i just retrieved 5,000 part numbers, i'd like to display then in a table of 5 columns with 1000 records per column. This is easy math, but i need the script to automatically figure out the #'s. Also the tricky part is that i dont want to display the part numbers like so 11111 22222 33333 44444 55555 66666 77777 88888 99999 00000 but rather 11111 44444 77777 22222 55555 88888 33333 66666 99999 00000 the remainder if there is one can go in the last column or whatever is easier. I'd tried googling this, but it's not easy to phrase what i'm looking for. Thanks for the help. PS: I'm not looking to copy and paste code, if possible please explain your way so that i can learn the logic. Hey guys have been trying to get this script to work for a while now, i am new to php and mysql so i am sure i am missing something simple. I have DB setup and need to pull data based on the key item code and get the following I want to get the fields item_code description allergy_statement useable_units region_availability order_lead_time ingredients for item_code 12-100 LITERALLY 12-100, no range, but like i said before i am really new to php and mysql. I have 1187 items that when a user clicks a link in search results it takes them to the product details page for that item code All that data is in my database just can't figure out how to get it out of the database. Is this even the right script to achieve that result. here is the code to get the data from database Code: [Select] <?php require_once('includes/mysql_connect_nfacts_ro.php'); $query = "SELECT item_code, description, allergy_statement, useable_units, region_availability, order_lead_time, ingredients " . "FROM products " . "WHERE item_code = '12-100' "; $resuts = mysql_query($query) or die(mysql_error()); ?> And need to display the data like so : Code: [Select] <td width="715" align="center" valign="top"> <h1>Product Details</h1> <h3>DISPLAY description HERE</h3> <table width="420" border="0"> <td class="ingreg"> </td> </table> <h5>Item Number</h5> <table width="420" border="0"> <tr> <td class="ingreg">DISPLAY ITEM_CODE HERE</td> </tr> </table> <h3>Ingredients:</h3> <table width="420" border="0"> <tr> <td class="ingreg">DISPLAY INGREDIENTS HERE</td> </tr> </table> <h4>Allergy Statement:</h4> <table width="420" border="0"> <tr> <td class="ingreg">DISPLAY Allergy Statement HERE</td> </tr> </table> <h4>Useable Units Per Package:</h4> <table width="420" border="0"> <tr> <td class="ingreg">DISPLAY Useable Units Per Package HERE</td> </tr> </table> <h4>Region Availability: </h4> <table width="420" border="0"> <tr> <td class="ingreg">&DISPLAY ITEM_CODE HERE</td> </tr> </table> <h4>Order Lead Time:</h4> <table width="420" border="0"> <tr> <td class="ingreg">&DISPLAY order lead time HERE</td> </tr> </table> <p> </p> <div align="right"></div></td> </tr> </table> how do i get data in database to display where i need it to? Can any one shine some light on this I am querying my database to show the visit statistics for a particular week and it shows the number of visits for the countries, but does not display the country name.
I have proved that the MySQL works by going into phpMyAdmin and pasting the query into SQL query tab, replacing the POST with 1, for week 1.
I can't see why it is not displying the country.
Here is the code:
<?php include('connect_visits.php'); doDB7(); $WVisit_data="SELECT WeekNo15.WNo, WeekNo15.WCom, Countries.Country, Countries.CID, ctryvisits15.CVisits FROM ctryvisits15 LEFT JOIN Countries ON ctryvisits15.country = Countries.CID LEFT JOIN WeekNo15 ON ctryvisits15.WNo = WeekNo15.WNo WHERE ctryvisits15.WNo = '{$_POST['WeekNo']}' ORDER BY ctryvisits15.CVisits DESC"; $WVisit_data_res = mysqli_query($mysqli, $WVisit_data) or die(mysqli_error($mysqli)); $display_block =" <table width=\"20%\" cellpadding=\"3\" cellspacing=\"1\" border=\"1\" BGCOLOR=\"white\" > <tr> <th>Country</th> <th>Visits</> </tr>"; while ($WV_info = mysqli_fetch_array($WVisit_data_res)){ $Ctry = $WV_info['country']; $Visits = $WV_info['CVisits']; //add to display $display_block .=" <tr> <td width=\"10%\" valign=\"top\">".$Ctry."<br/></td> <td width=\"5%\" valign=\"top\">".$Visits."<br/></td> "; } mysqli_free_result($WVisit_data_res); mysqli_close($mysqli); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <!-- Design by Free CSS Templates http://www.freecsstemplates.org Released for free under a Creative Commons Attribution 2.5 License Name : Yosemite Description: A two-column, fixed-width design with dark color scheme. Version : 1.0 Released : 20091106 --> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta name="keywords" content="" /> <meta name="description" content="" /> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <title>1066 Cards 4U - Stats for country</title> <link href="style.css" rel="stylesheet" type="text/css" media="screen" /> </head> <body> <div id="wrapper"> <div id="menu"> <ul> <li class="current_page_item"><a href="index.php">Home</a></li> <li><a href="Links.html">Links</a></li> <li><a href="Verse_Menu.html">Verses</a></li> <li><a href="Techniques.html">Techniques</a></li> <li><a href="blog.php">Blog</a></li> <li><a href="Gallery.html">Gallery</a></li> <li><a href="contact.html">Contact</a></li> <li><a href="AboutUs.html">About Us</a></li> <li><a href="stats1.html">Stats</a></li> </ul> </div><!-- end #menu --> <div id="header"> <div id="logo"> <h1><a href="http://www.1066cards4u.co.uk">1066 Cards 4U</a></h1> </div><!-- end #wrapper --> </div><!-- end #header --> <div id="page"> <div id="page-bgtop"> <div id="page-bgbtm"> <div id="content"> <h3>Statistics for Week Commencing <? echo $WkCom; ?> in 2015</h3> <div id="table"> <?php echo $display_block; ?></div> </div><!-- end #content --> </body> </html>Can you help please? Edited by rocky48, 07 January 2015 - 07:33 AM. Hi all, I'm trying to display a form based on a dropd own selection. The drop down is propagated from a database query. I have the drop down list displaying, but when I click submit, I can't get the result to display. Code: [Select] $sql="SELECT id, company_name FROM webprojects ORDER BY company_name ASC"; $result=mysql_query($sql); $options=""; while ($row=mysql_fetch_array($result)) { $id=$row["id"]; $company_name=$row["company_name"]; $options.="<OPTION VALUE=\"$id\">".$company_name; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>PHP Dynamic Drop Down Menu</title> </head> <body> <form id="form1" name="form1" method="post" action="selected.php"> <SELECT NAME=id> <OPTION VALUE=0>Choose <?=$options.="<OPTION VALUE=\"$id\">".$company_name.'</option>';?> </SELECT> <label> <input type="submit" name="submit" id="submit" value="Submit" /> </label> </form> </body> </html> Any help is greatly appreciated I have a table in a mysql database with 5 columns, id, Name, Wifi, Bluetooth, GPS, with rows that are for example 1, Galaxy S2, yes, yes, yes. So basically i want to build a form that has check boxes (3 checkboxes for wifi bluetooth and GPS respectively) that once selected will query the database depending on which check boxes are selected. I have made the form but need to know what to put in the filter.php to make the results be displayed accordingly. Ideally if anyone knows how i would want it so the results were shown on the same page which i believe u need to use ajax to happen but any help on how to show the results will be greatful. the code for the form i have made is as follows: Code: [Select] <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>test</title> </head> <body> <form action="filter.php" method="post"> <INPUT TYPE=CHECKBOX NAME="option[]" VALUE="Wifi" id="r1">Wifi <INPUT TYPE=CHECKBOX NAME="option[]" VALUE="Bluetooth" id="b1">Bluetooth <INPUT TYPE=CHECKBOX NAME="option[]" VALUE="GPS" id="g1">GPS <input type="submit" name="formSubmit" value="Submit" /> </form> </body> </html> im not sure on how to make the filter.php page but i do have this code for displaying the all the data but i want to kno how to make it only display the data from the choices on the checkboxes Code: [Select] <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>pls work</title> </head> <body> <?php function h($s) { echo htmlspecialchars($s); } mysql_connect("localhost", "root", "") or die (mysql_error()); mysql_select_db("project") or die (mysql_error()); $result= mysql_query('SELECT * FROM test') or die('Error, query failed'); ?> <?php if (mysql_num_rows($result)==0) { ?> Database is empty <br/> <?php } else { ?> <table> <tr> <th></th> <th>Name</th> <th>Wifi</th> <th>Bluetooth</th> <th>GPS</th> </tr> <?php while ($row= mysql_fetch_assoc($result)) { ?> <tr> <td> <a href="uploaded-images/<?php h($row['Name']); ?>.jpg"> <img src="uploaded-images/<?php h($row['Name']); ?>.jpg" alt="test"/> </a> </td> <td><a href="textonly.html"><?php h($row['Name']); ?></a></td> <td><?php h($row['Wifi']); ?></td> <td><?php h($row['Bluetooth']); ?></td> <td><?php h($row['GPS']); ?></td> </tr> <?php } ?> </table> <?php } ?> </body> </html> Hello everyone, I begin in everything web related but I have been programming for years. I tried to code something simple : small Mysql DB (works fine) and to begin a search bar to browse data. I adapted a code that I understood provided here : https://www.cloudways.com/blog/live-search-php-mysql-ajax/. Base principle is simple : as you type in your query, it will pass the text to script.js that will forward this request to ajax.php file. In the ajax.php, a javascript function named “fill()” will pass the fetched results. This function will also display the result(s) into “display” div in the “search.php” file. The problem is that when I type anything it displays, below the search bar, at the moment I type a character: Quote
'; //Fetching result from database. while ($Result = MySQLi_fetch_array($ExecQuery)) { ?> ")'>
instead of the actual answer from my database (no error in the browser console). I tested the SQL query + the user I provide and everything seems fine. Any clue what could be the root cause ? I strongly suspect a mistake in the code as I already corrected one (script.js instead of scripts.js) but I really cannot figure out where. Thanks in advance,
problematic code (ajax.php):
<?php //Including Database configuration file. include "db.php"; //Getting value of "search" variable from "script.js". if (isset($_POST['search'])) { //Search box value assigning to $Name variable. $Name = $_POST['search']; //Search query. $Query = "SELECT Name FROM search WHERE Name LIKE '%$Name%' LIMIT 5"; //Query execution $ExecQuery = MySQLi_query($con, $Query); //Creating unordered list to display result. echo ' <ul> '; //Fetching result from database. while ($Result = MySQLi_fetch_array($ExecQuery)) { ?> <!-- Creating unordered list items. Calling javascript function named as "fill" found in "script.js" file. By passing fetched result as parameter. --> <li onclick='fill("<?php echo $Result['Name']; ?>")'> <a> <!-- Assigning searched result in "Search box" in "search.php" file. --> <?php echo $Result['Name']; ?> </li></a> <!-- Below php code is just for closing parenthesis. Don't be confused. --> <?php }} ?> </ul>
Hi There! Hopefully someone can help. I'm looking for some php script that allows me to display mysql table data in alternating row colors (eg 5 columns and 500 rows). I would also like to add pagination and limit number of rows displayed at a time to e.g. 50. If possible I'd like to be able to sort asc/desc using titles(links) at the top of the displayed data. Hopefully someone may have a script like this that also shows the mysql connection code (sample host, pass, user etc...) - a working php file so to speak that I can edit. Would really appreciate the help. If you could recommend some software or a wizard that could generate the php code for me I would really appreciate it too! THANKS! Hi, I'm trying to make a dynamic html table to contain the mysql data that is generated via php. I'm trying to display a user's friends in a table of two columns and however many rows, but can't seem to figure out what is needed to make this work. Here's my code as it stands: Code: [Select] <?php //Begin mysql query $sql = "SELECT * FROM friends WHERE username = '{$_GET['username']}' AND status = 'Active' ORDER BY friends_with ASC"; $result = mysql_query($sql); $count = mysql_num_rows($result); $sql_2 = "SELECT * FROM friends WHERE friends_with = '{$_GET['username']}' AND status = 'Active' ORDER BY username ASC"; $result_2 = mysql_query($sql_2); $count_2 = mysql_num_rows($result_2); while ($row = mysql_fetch_array($result)) { echo $row["friendswith"] . "<br>"; } while ($row_2 = mysql_fetch_array($result_2)) { echo $row_2["username"] . "<br>"; } ?> The above simply outputs all records of a user's friends (their usernames) in alphabetical order. The question of how I'd generate a new row each time a certain amount of columns have been met, however, is beyond me. Anyone know of any helpful resources that may solve my problem? Thanks in advance =) Hello all: Let me give you some background, over the past 10 years I have dealt with many forums, and even built some limited PHP scripts myself for various things related to those forums. Usually modifications to expand the forums abilities. So I had thought I had a fairly good handle on PHP in general... LOL, that is until recently when I decided to take on a slightly different/larger challenge. Recently one of my forum users requested the creation of a X,Y Coordinate grid, where they could put into it certain bits of information and it would return showing them the X,Y location of thier various work attached in some way shape or form to his site. I had thought this would be a simple project, as I have worked with GD image creation before, as well as SQL statements many times, it simply should have been a blending of my exsisting knowledge into one program. While this was a unique challenge for me, its one I seem to have been unable to plug. I have searched the web extensively the last 2 weeks hoping to find a tutorial, and sadly while I can find a great many related to bar graphs and line graphs, I can't seem to find a single one related to a simple X Y coordinate graph, yet I know I have seen them done many times. I am at a total loss on this one and so far my attempts have garnered me 0 results. I can't even create a 20 x 20 grid with any success... LOL. I am hoping one of you would be kind enough to post a tutorial, with a simple code that would produce a grid using GD, or even some other form of image generation, with 1 - X Y plot in it generated either from SQL or from the program its self, so that I could see a working version and with luck go from there to expand it to my needs. Thank you. Need help in achieving a data entry grid. I have two tables am_user (idam_user, name) and am_activity (idam_act, act) with the data Data for am_user is 1, John 2, Mary 3, Kate Data for am_activity is 1, Cooking 2, Cleaning 3, Painting I have a third table that stores the role played by each user for the activities. am_role (idam_role, role) 1, Manage 2, Observe 3, Documents I want my User table to be my header, Activity table to my 1st column and Role table to populate the data grid John Mary Kate Cooking Manage Document Observe Cleaning Document null Manage Painting Observe Document Manage By putting two while loops I am able to generate the header and 1st column but I need help in populating the grid in between. Also I want my data entry area (rows and column besides header and 1st column) to have lookup where they can select values from the am_role table. So, John can "Manage" "Painting" tomorrow if he wants to The two while loops are Code: [Select] $query = "select idam_user, Name "; $query .= " from am_user "; $result = mysql_query($query) or die(mysql_error()); // display data in table echo "<center>"; echo "<table>"; echo "<tr>"; echo "<th></th>"; // loop through results of database query, displaying them in the table while($row = mysql_fetch_array( $result )) { // echo out the contents of each row into a table echo '<th>' . $row['name'] . ' '; echo "</th>"; } echo "</tr>"; $query = "select idam_act, act "; $query .= " from am_activity "; $result = mysql_query($query) or die(mysql_error()); // display data in table // loop through results of database query, displaying them in the table while($row = mysql_fetch_array( $result )) { // echo out the contents of each row into a table echo '<tr>'; echo '<td>' . $row['act'] . '</td>'; echo '</tr>'; } // close table> echo "</table>"; echo "</center>"; Please advise if this thought is realistic and how can I achieve it. Thanks in anticipation. Hey folks! I am looking to build a small adventure game in PHP and the key to this will be a 3x3 (or possibly bigger) grids of squares, with the user situated in the centre. I therefore need to be able to figure out the co-ords of the surrounding squares. Presumably I will need to define the size of the master grid, then using the co-ords of the current square (defined from a database containing the users location), calculate the co-ords for the surrounding 8 grid squares. Has anyone had any experience with this? Where should I start? (Maths isn't my strong point tbh, but I can pick things up quickly) Thanks in advance! EDIT - in case it wasn't too clear, the "world map" would be something like 1000x1000 squares, but the player can only see the 3x3 grid at there location. I don't want to use AI, or a primary key to sort the data, as it could create some problems if the items are visited out of order, but I want to sort it always based upon a single element for speed.
I'm creating a table that will be populated (built), when it's corresponding entry doesn't exist, how do I get it sorted out if someone visits 2, then 7 before they visit 5 to read what's there? It's not a 2d number line, but a 3d number grid.
Edited by Q695, 09 September 2014 - 11:30 PM. Hello to all, I have problem figuring out how to properly display data fetched from MySQL database in a HTML table. In the below example I am using two while loops, where the second one is nested inside first one, that check two different expressions fetching data from tables found in a MySQL database. The second expression compares the two tables IDs and after their match it displays the email of the account holder in each column in the HTML table. The main problem is that the 'email' row is displayed properly while its while expression is not nested and alone(meaning the other data is omitted or commented out), but either nested or neighbored to the first while loop, it is displayed horizontally and the other data ('validity', 'valid_from', 'valid_to') is not displayed.'
Can someone help me on this, I guess the problem lies in the while loop? <thead> <tr> <th data-column-id="id" data-type="numeric">ID</th> <th data-column-id="email">Subscriber's Email</th> <th data-column-id="validity">Validity</th> <th data-column-id="valid_from">Valid From</th> <th data-column-id="valid_to">Valid To</th> </tr> </thead> Here is part of the PHP code:
<?php while($row = $stmt->fetch(PDO::FETCH_ASSOC)) { echo ' <tr> <td>'.$row["id"].'</td> '; while ($row1 = $stmt1->fetch(PDO::FETCH_ASSOC)) { echo ' <td>'.$row1["email"].'</td> '; } if($row["validity"] == 1) { echo '<td>'.$row["validity"].' month</td>'; }else{ echo '<td>'.$row["validity"].' months</td>'; } echo ' <td>'.$row["valid_from"].'</td> <td>'.$row["valid_to"].'</td> </tr>'; } ?>
Thank you. This could be PHP or MySql so putting it in PHP forum for now... I have code below (last code listed) which processes a dynamically created Form which could have anywhere from 0 to 6 fields. So I clean all fields whether they were posted or not and then I update the mySQL table. The problem with this code below is that if, say, $cextra was not posted (i.e. it wasnt on the dynamically created form), then this code would enter a blank into the table for $cextra (i.e. if there was already a value in the table for $cextra, it gets overwritten, which is bad). What is the best way to handle this? I'm thinking i have to break my SQL query into a bunch of if/else statements like this... Code: [Select] $sql = "UPDATE cluesanswers SET "; if (isset($_POST['ctext'])){ echo "ctext='$ctext',"; } else { //do nothing } and so on 5 more times.... That seems horribly hackish/inefficient. Is there a better way? Code: [Select] if (isset($_POST['hidden']) && $_POST['hidden'] == "edit") { $cimage=trim(mysql_prep($_POST['cimage'])); $ctext=trim(mysql_prep($_POST['ctext'])); $cextra=trim(mysql_prep($_POST['cextra'])); $atext=trim(mysql_prep($_POST['atext'])); $aextra=trim(mysql_prep($_POST['aextra'])); $aimage=trim(mysql_prep($_POST['aimage'])); //update the answer edits $sql = "UPDATE cluesanswers SET ctext='$ctext', cextra='$cextra', cimage='$cimage', atext='$atext', aextra='$aextra', aimage='$aimage'"; $result = mysql_query($sql, $connection); if (!$result) { die("Database query failed: " . mysql_error()); } else { } Hi I am trying to select and order data/numbers from a colum in a mysql data base however i run the code and it returns no value just a blank page no errors or any thing so i think the code is working right but then it returns no result? Please help thanks Here is the code: <?php $host= "XXXXXX"; $mysql_user = "XXXXXX"; $mysql_password = "XXXXXX"; $mysql_database = "XXXXXXX"; $connection = mysql_connect("$host","$mysql_user","$mysql_password") or die ("Unable to connect to MySQL server."); mysql_select_db($mysql_database) or die ("Unable to select requested database."); $row = mysql_fetch_assoc( mysql_query( "SELECT XP FROM Game ORDER BY number DESC LIMIT 1" ) ); $number = mysql_result(mysql_query("SELECT XP FROM Game ORDER BY number DESC LIMIT 1"), 0); echo "The the highest XP is $number"; ?> hi guys, im new to this forum I'm new also to php, I need help from you guys: I want to display personal information from a certain person (the data is on the mysql database) using his name as a link: example: (index.php) names 1. Bill Gates 2. Mr. nice Guy i want to click Bill Gates (output.php) Name: Bill Gates Country:xxxx Age: xx etc. How can i make this or how to learn this? Hello im working on a project which involves marking attendance via an RFID tag and saving the time into an sql file. Everything seems to be working fine and the time stamp is successfully punched into the SQL but something is wrong with the php code thats supposed to display this data. Please if any one can take a look and help.
MY CODE for displaying the data (ViewAttendance.php): <?php include_once("header.php"); $attData = array(); $totDays = 0; if(isset($_REQUEST['submit'])){ $totDays = cal_days_in_month(CAL_GREGORIAN,$_REQUEST['month'],$_REQUEST['year']); $attData = $commonObj->getAttendanceData($_REQUEST['month'],$_REQUEST['year']); //print_r($attData); //print_r(date("d",strtotime($attData[0]['punch_time']))); } ?> <div class="container"> <div class="row"> <div class="col-sm-12"> <h4>Showing Attendance</h4> <form name="showAtt" method="post"> <div class="col-sm-4"><label>Select Month</label> <select name="month" class="form-control"> <?php for($i=1;$i<=12;$i++){?> <option value="<?php echo $i;?>"><?php echo $i;?></option> <?php }?> </select> </div> <div class="col-sm-4"><label>Select Year</label> <select name="year" class="form-control"> <?php for($i=date("Y");$i>=2010;$i--){?> <option value="<?php echo $i;?>"><?php echo $i;?></option> <?php }?> </select> </div> <div class="col-sm-4"> <p> </p> <input type="submit" value="Show" name="submit" class="btn btn-primary"> </div> </form> </div> </div> <div class="row"> <div class="col-sm-2"> <label class="btn btn-success btn-sm">Month:<?php echo @$_REQUEST['month'];?></label> </div> <div class="col-sm-2"><label class="btn btn-info btn-sm">Year: <?php echo @$_REQUEST['year'];?></label></div> </div> <div class="row"> <div class="col-sm-12" style="overflow: scroll;"> <?php if($totDays>0){?> <table class="table table-striped"> <tr> <th> Employee Name </th> <?php for($i=1;$i<=$totDays;$i++){?> <th> <?php echo $i;?> </th> <?php }?> <?php foreach($attData as $attk=>$attv){ $punchin = $commonObj->getTimeOfDate($attData[$attk]['punchin']); $punchout = $commonObj->getTimeOfDate($attData[$attk]['punchout']); ?> <tr> <th class="danger"> <?php echo $attv['name'];?> </th> <?php for($i=1;$i<=$totDays;$i++){?> <?php if($commonObj->getDayOfDate($attData[$attk]['punch_time']) == $i){ echo "<td class='success' id='att_$i'>".$punchin.'-'.$punchout;?> <table class="table table-responsive"style="display: none; position:relative;min-width:100px;max-width:200px; margin-top: -40px;" id="<?php echo "det_att_".$i;?>"> <tr> <td>Total hours:</td> <td><?php echo $commonObj->getHoursBetweenDates($attData[$attk]['punchin'],$attData[$attk]['punchout']);?> </td></tr> <tr> <td>UID:</td> <td><?php echo $attData[$attk]['rfid_uid'];?></td> </tr> </table> <?php }else {echo "<td class='info'>#na";}?> </td> <?php }?> </tr> <?php }?> </tr> </table> <?php }?> </div> </div> </div> </body> </html> <script> $(document).ready(function(){ $("td").hover( function () { var id = "#det_"+this.id; $(id).css({"display":"block"}); }, function () { var id = "#det_"+this.id; $(id).css({"display":"none"}); //console.log(id); //$(id).css("display","block"); }); }); </script> Display of (ViewAttendance.php):
MY SQL TABLE :
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