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PHP - Does Including (or Requiring) A File Execute It Immediately?
Or is it all pieced together into one file then executed?
I ask because I'm thinking of a weird way to handle errors on my site that would integrate with the interface smoothly without much work on my part. Every page on my site requires template_top.php at the start of the script and template_bottom.php at the bottom. I believe this is a pretty common thing to do, and it standardizes all my menus and interfaces and whatever else, plus it gives me a nice place to deliver messages to the user. What I want to do is something like this simplified example: template_top.php: <?php // layout stuff here try { ?> index.php: <?php require_once('template_top.php'); // a wild error appears! throw new Exception('oh no!'); require_once('template_bottom.php'); ?> template_bottom.php: <?php } catch (Exception $e) { echo 'An error occured! Message: ' . $e->getMessage(); } // layout stuff here ?> So that's where my question comes in. Both template files contain code that, if executed on it's own, is invalid. Pieced together in my pages though, it forms correct code. I'd really like to do this since all I'd have to do if my script encounters a problem is throw an Exception and everything is instantly handled without me having to fight with display issues. If this isn't possible, does anybody have any better suggestions? Similar TutorialsHello, I have a problem with a script I'm making and I'm pretty stumped. I have coded a template parser that parses tags in {} and I am allowing users to integrate a part of my script with the {integrate} tag. This is my script tags. // Template Tags $data = array(); $data[title] = $config[title]; $data[page] = $mcore->currentPage(); $data[integrate] = $mcore->pageSwitch(); page switch function: function pageSwitch() { if(!$_GET['act']) { $use = "news.php"; } else { $use = $_GET['act']; } $this->file = $use; return $this->file; } I want it to include the file where the person puts the {integrate} tag in their template. But when I call it, it includes the file at the top of the template, rather than where the put it. How would I get it to include the template only where they put it? I can post my template class if needed. How can i find out parent (including) file of included file? Lets imagine that we want to for example auto_prepend file to each file on our server that would write out the name of file its being executed. I know, i can use PHP_SELF but what if i want to write name of file which is already included? I have a web page and i want on it show its name even if it was included, but not the included page itself is showing name but auto_prepend file to each php file, its duty of this auto_prepend_file to write it out i dont want myself to echo it on each page? do you feel me? Hello. The title is a little confusing, but: What I am trying to do is build a simple CMS where all requests are routed through the root index.php file. This file will be where all constants are defined and importantly where the database connection is estabilished. There will be a folder where template files will reside and, based on the URI, a template file will be included into the root index.php file. Here's some code: Code: [Select] <?php //Sets the database connection and defines some constants require ( "includes/config.php" ); //Where I will place the core functions of the CMS, one being the navigation builder require ( "includes/functions.php" ); //Home page template file require ( "views/cms/index.php" ); ?> So as you can see, I want to be able to call the navigation builder function, called "getMenuItems();", from the home page template. However, I get the following error: Code: [Select] Fatal error: Call to undefined function getMenuItems() in C:\wamp\www\cms\views\cms\index.php on line 3 How can I access functions that have been defined in the "includes/functions.php" file, from the required template file "views/cms/index.php"? If you need anything else explaining then please ask. If this has already been posted, I apologise in advance! I have searched Google and the forums but nothing turned up. Chris Hi everyone.... I have a simple search.php And I want to include that in my html output page. I tried using <?php include ('search.php'); ?> Below is my HTML code which is part of a php file...what am I doing wrong here? Code: [Select] // Final Output echo <<<__HTML_END <html> <head> <title>Photography</title> </head> <body> <table width='100%' border='0' align='center' style='width: 100%;'> $result_final <?php include("search.php");?> </table> </body> </html> __HTML_END; how to get the name of the file including a file from the included file, This one has me mixed up a bit.. I am trying to record site activity information from a common.php file using a user object. But since the file is included into different php files based on different situations I need a dynamic way of finding the file name that is including it. I could be over complicating things but right now this seems like the best solution other wise I'll have to rewrite the code on every page i write. Is there a function for doing this? Or if someone gets what I'm trying to do if they could point me to the direction of some more information on it. Thanks. I have written a Validation class that checks to see if a file being uploaded to the server meets certain conditions. That works a treat. The next step is to actually upload it to the server and I have an Upload class that can do that. Again, that works perfectly fine. Once the file uploads, I am passing the $location of that of that file to my DB class. The DB class is full of methods that prepare and then execute strings that are SQL queries that are required in other areas of my application. Nothing I have at the moment is suitable for just running an SQL file so I don't know what to do now.. My procedural code, that works, looks like this;
$dbh2 = new PDO("mysql:host=localhost;dbname=DB360transfer", $login_user,
$login_password);
$sql =
file_get_contents($path.$new_file_name);
$qr = $dbh2->exec($sql);
I'm not sure how to replicate this up in a PDO/OOP application.My DB Class script is attached. The run_from_file code starts on line 98. I've left in the other stuff as I suspect the answer has something to do with using the $this or the self:: - but really I have no idea. So my question is, what is the correct syntax for executing a file in OOP? Attached Files DB.php 2.92KB 6 downloads See if I can explain this right.
I am currently using static files for a very basic set of pages.
Right now i have a main file that has three includes. a header include, body and footer.
Due to needing to add pages, i don't want to keep adding more and more files. instead I want to use php to change one of the includes based on the url.
so thissite.com/index.php?lesson1 would change this
<?php include("header.php"); ?>
<?php include("content-lessons.html"); ?>
<?php include("footer.php"); ?>
to this
<?php include("header.php"); ?>
<?php include("lesson1.html"); ?>
<?php include("footer.php"); ?>
or whichever way would be the best way to set the second include.
my guess was that if the second line had something like this?
if(isset($_GET['lesson1'])){
include('include/in-'.$_GET['lesson1.html']
can someone give me a starting place here? i am pretty sure i can pick ti up if someone gets me going in the right direction.
thanks a ton.
Edited by story97, 12 January 2015 - 09:03 PM. The root directory:
header.php
stylesheet.css
In the following example I am trying to include the header.php file in a sub folder.
When I include the header.php like in the following example then the stylesheet.css file will not work anymo
<?php
include("../header.php");
?>
The stylesheet.css file is included in the head tags of the header.php file.
Is the above example the right way to do it? If yes, how can I do it so the stylesheet.css file will work too.
I don't know if this relevant to php or css in my template folder I have file named (index.template.php). It contains this code <?php echo '<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <meta name="Keywords" content="BHL-SimpleTool Content Manager System" /> <meta name="Author" content="BHL-SimpleTool is coded by Othman A. Taha" /> <meta name="Description" content="Site Powered by BHL-SimpleTool CMS" /> <title>BHL-SimpleTool v1.0 - Alpha</title> <link rel="stylesheet" href="themes/default/style.css" media="all" type="text/css" /> <link rel="stylesheet" href="themes/default/forms/forms.css" media="all" type="text/css" /> <link rel="stylesheet" href="modules/forum/Themes/default/style.css" type="text/css" /> <link rel="stylesheet" href="inc/jq/css/style.css" type="text/css" /> <script language="javascript" type="text/javascript" src="js/bbcodes.js"></script> <script language="javascript" type="text/javascript" src="js/smileys.js"></script> <script type="text/javascript" src="js/jquery.js"></script> <script type="text/javascript" src="js/easySlider1.5.js"></script> </head> <body> <div id="wrapper"> my website run here </div> </body> </html>'; ?> It works fine( I made the top-margin to be 0px). But when I include index.template.php in my main (index.php) the top margin show a big margin from the top Note: I included (index.template.php) in my main (index.php) like this: <?php function __autoload($class_name) { require_once 'classes/Sessions' . '.php'; } $sessInfo = new Sessions(); $sessInfo->RunAllBhlSimpeToolStuff(); ?> Hey everyone, I have an SQL file called "Cype.sql" and I was wanting to have it run when the install feature is going on. However I can't seem to figure out why exactly the code is not working. is it possible to have it run without getting too in depth the PHP coding? I'm not OOP Literate yet. //Connection is opened //While in installation file $sqlFile = "Cype.sql"; if(!file_exists($sqlFile)){ echo "File not found"; } else{ $openFile = fopen($sqlFile, "r"); $tryQuery = mysql_query($openFile); } Now obviously, I'm not the best coder. I've been out of the works of PHP for quite some time now as well. However, I have researched it and found no answers to my issue. Any help would be greatly appreciate. Thank you. I'm looking to get php to write to file when someone visits one of my sites without javascript.
From the research I've done, it seems that an css hidden, iframe within the noscript tag would work, and the php file would then write to a log.
I just want a simple tick log that increments by 1, but perhaps also lists the user-agent.
My one concern is that I want to include this same code on multiple sites, all of which could be trying to access, and write a tick to the same "no JS log". Is that going to cause problems the way php writes to files?
Can someone help me create the code that will write to this log file, that won't cause errors or problems when multiple sites/visitors could be making writes to the log?
I'm a php noob, so while I can research how to get php to write to a file and save, most of the tutorials don't mention if it would be a safe method to use, if multiple domains were trying to write to that same file, at the same time, and trying to add their own "tick" to increment the number within the flat file.
Extended help that I'm looking for is getting ticks per user-agent/search bot, so bots/web users that visit my pages, that don't run JS, could have ticks by them. eg:
Google Bot: 3
Mozilla Firefox 31.0: 15
Any help on this would be appreciated, or any flaws that you see in this type of tracking, thanks!
Suppose, i have created a sub.domain.com and i want to include a file 'config.php' from root directory i.e domain.com . While i tried include("../config.php"); i wasn't successful. Anyone can help me please?? I need the solution very urgently, so please help me soon. pracasify@yahoo.com facebook.com/agptj guys i wand to execute a program on my seerver, i use the $_SESSION['tmp'] = exec("print.exe", $results); and works but when i change the directory $_SESSION['tmp'] = exec("d:\\print\\user1\\print.exe", $results); dont work, works only in root directory, is any way to set the execution to other directorys?? thanks This topic has been moved to Apache HTTP Server. http://www.phpfreaks.com/forums/index.php?topic=352264.0 Hi Guys, how to execute batch file in wamp server php code. Could you please help on that.
Basically what I am trying to achieve is making sure any $page called originates from my server, but if no $page is defined, to include a default page I have set up. This is my code, and I cannot figure out what's wrong with it. Code: [Select] <?php $path = 'pages/'; $extension = '.txt'; if ( preg_match("#^[a-z0-9_]+$#i",$page) ){ $filename = $path.$page.$extension; include($filename); } if (!$page) include 'pages/main.txt'; ?> An example URL I am using is www.mywebsite.com/index.php?$page=pages/tester What am I doing wrong? Okay so we all know Code: [Select] <?php include "theme.html"; print: "Hello"; ?> Would output the theme and output hello at the bottom of the page, my question is, how do you position hello to go on the current theme? Thanks. Hello: I wanted to see if someone can help me figure out how to include data from my included navigation file. Meaning: I have this file called myNav.php (the database table storing this is "myUpcomingEvents"): Code: [Select] function spLeftMenu() { $spLeftMenu = " <div id=\"sideEvents\"> echo \" $mySideBarData; \"; </div> "; return $spLeftMenu; } I am trying to pull it into the Index.php page like this (the database table storing this is "myHome"): Code: [Select] <?php include('include/myConn.php'); include('include/myNav.php'); $query=mysql_query("SELECT * FROM myHome,myUpcomingEvents") or die("Could not get data from db: ".mysql_error()); while($result=mysql_fetch_array($query)) { $myPageData=$result['myPageData']; $mySideBarPageData=$result['mySideBarPageData']; } ?> <!DOCTYPE HTML> <html> <head></head> <body> <div id="siteContainer"> <div id="leftColumn"> <?php echo spLeftMenu(); ?> </div> <div id="mainContent"> <?php echo $myPageData; ?> </div> </div> </body> </html> Can't get it to work. It just writes out: Code: [Select] echo " ; "; Anyone know how I can get this to work? Thanks. Hi, I have a class: Code: [Select] class Toplist { public function get_article($id) { $id = (int) $id; $articles = array(); $query = $db->sql_query("SELECT * FROM `toplist` WHERE `id` = '$id'"); $result = $db->sql_fetchrowset($query); return $articles; } } and I get Quote Notice: Undefined variable: db in classToplist.php on line 11 Fatal error: Call to a member function sql_query() on a non-object in classToplist.php on line 11 the variable db is in ./models/config.php and it isn't working on the classToplist. I have a feeling that this happens because the config file is not a class. How can I fix this? |
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