PHP - Saving Image Resource Onto Subdirectory
Hey.
I'm just wondering what would be the most logical or most efficient way to save an image resource that has been constructed on say the www. to a subdirectory or on another webserver? For eg The script on www.example.com constructs an image using the GD library from image1.png and image2.png. It has now got the final image resource for what's been constructed. I now want to save this image onto images.example.com How would you suggest? Similar TutorialsHi I'm really new to php and could really do with some help. I am using the following script http://test.dpetroff.ru/jquery.iviewer.test/test/ which basically allows me to position an image within a DIV area My question is, how can I get PHP to save just the image within the DIV area, so it's almost acting like a crop tool I've tried a few things but so far not managed to get anything working I was trying to use one of the many PHP routers like klein, when I kept hitting an issue.
The issue was my root folder was a subdirectory of the www folder .
So instead of requesting http://localhost/index.php (as one would if the index.php was located in /var/www) I was requesting http://localhost/issues/web/index.php (index.php in /var/www/issues/web)
Naturally the router looked for a match for the whole path(issues/web/index.php) instead of just the relative path(/index.php) Which caused it not to match anything !
Questions:
1. Is this a viable solution for this problem (Got this from https://github.com/c...ry-Installation? Any possible gotchas I should be on the look out for ?
$base = dirname($_SERVER['PHP_SELF']); // Update request when we have a subdirectory if(ltrim($base, '/')){ $_SERVER['REQUEST_URI'] = substr($_SERVER['REQUEST_URI'], strlen($base)); } //initialize router code.2. This must be an extremely common situation! How do people deal with this ? OR is it simply not common for routers to be installed to subfolders and called from there ? Thanks Hi Guys, Using this code i am able to overlay a logo onto an image: <?php // Load the image where the logo will be embeded into $image = imagecreatefromjpeg("box.jpg"); // Load the logo image $logoImage = imagecreatefrompng("logo.png"); imagealphablending($logoImage, true); // Get dimensions $imageWidth=imagesx($image); $imageHeight=imagesy($image); $logoWidth=imagesx($logoImage); $logoHeight=imagesy($logoImage); // Paste the logo imagecopy( // source $image, // destination $logoImage, // destination x and y $imageWidth-$logoWidth, $imageHeight-$logoHeight, // source x and y 0, 0, // width and height of the area of the source to copy $logoWidth, $logoHeight); // Set type of image and send the output //header("Content-type: image/png"); //imagePng($image); imagejpeg($logoImage, "imageWithLogo.jpg", 100); // Release memory imageDestroy($image); imageDestroy($imageLogo); ?> this part: //header("Content-type: image/png"); //imagePng($image); shows me the complete image with the logo ontop, what i'm having trouble with is saving the image. any help would be appreciated thanks guys Graham Hello dear, I'm willing to use thumbnails into my website which is mainly like websites directory. I've been thinking to save url thumbnails into certain directory ! If i've index.php with the following image code (this would show thumbnail image of the website ANY_SITE.COM Code: [Select] <img src='http://thumbnails_provider.com/url=ANY_SITE.COM'/> then how to save the generated image into certain directory like my_site.com/thumbnails i've been thinking about Using cURL but i don't know how to apply it any help ~thanks Hello. I'm using an Amazon S3 class to uploaded to S3. I have 2 upload boxes - The first uploads once and the second needs to upload twice - 1 full size, 1 thumb. The issue i'm having is that the 2nd image (the thumb) seems to be failing, although if I don't save the first full sized image I am able to upload the thumb. So I think the issue is with using the temp file twice? This is my code: //retreive post variables $fileName = $randomString . "_" . $_FILES['theFile']['name']; $fileTempName = $_FILES['theFile']['tmp_name']; $fileName2 = $randomString . "_" . $_FILES['theFile2']['name']; $fileTempName2 = $_FILES['theFile2']['tmp_name']; //move the file if ($s3->putObjectFile($fileTempName, "containerhere", $fileName, S3::ACL_PUBLIC_READ)) { echo "<strong>Uploaded Image</strong>"; }else{ echo "<strong>Something went wrong while uploading your file... sorry.</strong>"; } //move the file if ($s3->putObjectFile($fileTempName2, "containerhere", $fileName2, S3::ACL_PUBLIC_READ)) { echo "<strong>Uploaded Image</strong>"; }else{ echo "<strong>Something went wrong while uploading your file... sorry.</strong>"; } include('simpleImage.php'); $image = new SimpleImage(); $image->load($_FILES['theFile2']['tmp_name']); $image->resizeToWidth(100); $image->save($_FILES['theFile2']['tmp_name']); $fileName3 = $randomString . "_" . $_FILES['theFile2']['name']; $fileTempName3 = $_FILES['theFile2']['tmp_name']; //move the file if ($s3->putObjectFile($fileTempName3, "containerhere", "thumbs/" . $fileName3, S3::ACL_PUBLIC_READ)) { echo "<strong>Uploaded Image</strong>"; }else{ echo "<strong>Something went wrong while uploading your file... sorry.</strong>"; } Can anyone offer any advice? Thanks. How to include root files from subdirectory in php? I have tried include '../configure.php'; but got error. Also tried include($DOCUMENT_ROOT."../configure.php"); but same result. For example, I have "root/admin" directory, and can't connect (from "/admin" dir) to the file configure.php which is in root. There are also other files to include. How does one get the absolute filepath of this:
$_FILES["myfile"]["name"]
On a web-server?
Currently I'm feeding my image as a resource into imagejpg.
http://php.net/manua...n.imagejpeg.php
However, I need to get the file-path so I can send them to an S3 bucket.
Thanks for any help!
Edited by arbitrageur, 02 November 2014 - 09:35 PM. Hi All, This is my first post on here. I'd really appreciate any help with this, it's driving me mad. I'm trying to create a form to save a image into a mySQL database. I have a website hosted by UK2.net which has a mysql db with a table called gallery(name (varchar 30), size (int), type varchar(30), thePic(mediumBlob)). I have a form with this: Code: [Select] <td><p><label>Pic: </label></td><td><input name="userfile" type="file" id="userfile" /></td></p> Which when submitted actions addImage.php. The code for this looks like this: Code: [Select] <?php $fileName = $_FILES['userfile']['name']; $tmpName = $_FILES['userfile']['tmp_name']; $fileSize = $_FILES['userfile']['size']; $fileType = $_FILES['userfile']['type']; $fp = fopen($tmpName, 'r'); $content = fread($fp, filesize($tmpName)); $content = addslashes($content); fclose($fp); if(!get_magic_quotes_gpc()) { $fileName = addslashes($fileName); } $con = mysql_connect("localhost", "userName", "password") or die(mysql_error()); mysql_select_db("dbName", $con) or die(mysql_error()); $query = "INSERT INTO gallery (name, size, type, thePic) ". "VALUES ('$fileName', '$fileSize', '$fileType', '$content')"; if (!mysql_query($query,$con)) { die('Error: ' . mysql_error()); } echo "<br>File $fileName uploaded<br>"; ?> I get the following error message: Quote Warning: fopen() [function.fopen]: Filename cannot be empty in /home/hiddenje/public_html/addImage.php on line 13 Does anyone know what this is about? I've been on out friend google and a lot of people seem to be pointing to permissions but I can't seem to apply it to my scenario and just can't get it to work. Im a developer by trade, but this is my first step into the...interesting world of PHP and mySQL. Again, I'd appreciate any help with this. I'd love someone to talk me through exactly what I'm missing or doing wrong. Thanks in advance. I am working on a simple gallery. I want to have an option to download full scale image without users having to right click and "save as". Using this code you get a image preview: <a href="pictures/img-(1).jpg"><img src="thumbnails/img-(1).jpg"></a> How can I modify it so when user clicks on thumbnail of image 1 it will prompt him to save the image instead of viewing it. Thanks so I have an array with a bunch of photos, and I'm trying to create a thumbnail of each to display on a page with a link to the full sized image but I'm getting the error in the subject title... if I just display the images in the array without trying to resize them it works fine... can anyone clue me into why this isn't working please. echo ("<a href='" . $img['file'] . "'>"); $new_width = (floor($img['size'][0] * ".25")); $new_height = (floor($img['size'][1] * ".25")); $tmp_img = imagecreatetruecolor($new_width, $new_height); imagecopyresized($tmp_img, $img['file'], 0, 0, 0, 0, $new_width, $new_height, $img['size'][0], $img['size'][1]); echo ("<img src='" . $tmp_img . " . $img['size'][3] , "' alt=''><br>\n"); echo basename($img['file']); echo "</a><br>\n"; I have a .php code that gets data from a database and saves it in a variables as xml. However how can I then save all of the data in this variable as a .xml file somewhere? Thanks for any help. i have made 2 classes. the first "point" has an array of 3 floats and some functions to help manipulate the values the second "triangle" has an array of 3 points. in this way if i want to make a tetrahedron i can make 4 points and assign them to 4 triangles. problem is for some reason each triangle point group seems to use 1k. any idea why? Hi All... I am looking for a way of saving currently open webpage as a pdf file.........I searched for that and even gone for this site http://www.tcpdf.org. But there also I didn't find any perfect way of doing this all....If somebody else has tried tcpdf for that or done something like that, then plzzzzz plzzz plzzzz do help me....Thanx...... Hi, I'm completely new to anything that is not html but I'm wondering if in something like php I can get a checkbox to permanently save through reloads and different machines. My idea was just to have a page with only a checkbox on it, and then load that through and iframe in html. If anybody could give me the code for that checkbox page (complete if possible as I don't really know anything about that type of programming) I would be very grateful. Thank You I have problem how to saving all my record.
when I save I just got 1 record saved in mySQL and it the last record on that table. Here is my code =
<?php if (!function_exists("GetSQLValueString")) { function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") { if (PHP_VERSION < 6) { $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue; } $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue); switch ($theType) { case "text": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "long": case "int": $theValue = ($theValue != "") ? intval($theValue) : "NULL"; break; case "double": $theValue = ($theValue != "") ? doubleval($theValue) : "NULL"; break; case "date": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "defined": $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue; break; } return $theValue; } } $editFormAction = $_SERVER['PHP_SELF']; if (isset($_SERVER['QUERY_STRING'])) { $editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']); } if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "form1")) { $insertSQL = sprintf("INSERT INTO thasil (nrp, nama, pangkat, mgolongan, mtes_fisik, mkemampuan, hasil) VALUES (%s, %s, %s, %s, %s, %s, %s)", GetSQLValueString($_POST['nrp'], "int"), GetSQLValueString($_POST['nama'], "text"), GetSQLValueString($_POST['pangkat'], "text"), GetSQLValueString($_POST['mgolongan'], "int"), GetSQLValueString($_POST['mtes_fisik'], "double"), GetSQLValueString($_POST['mkemampuan'], "double"), GetSQLValueString($_POST['hasil'], "double")); mysql_select_db($database_stok, $stok); $Result1 = mysql_query($insertSQL, $stok) or die(mysql_error()); $insertGoTo = ""; if (isset($_SERVER['QUERY_STRING'])) { $insertGoTo .= (strpos($insertGoTo, '?')) ? "&" : "?"; $insertGoTo .= $_SERVER['QUERY_STRING']; } header(sprintf("Location: %s", $insertGoTo)); } mysql_select_db($database_stok, $stok); $query_anggotaset = "SELECT * FROM tanggota ORDER BY nrp ASC"; $anggotaset = mysql_query($query_anggotaset, $stok) or die(mysql_error()); $row_anggotaset = mysql_fetch_assoc($anggotaset); $totalRows_anggotaset = mysql_num_rows($anggotaset); mysql_select_db($database_stok, $stok); $query_bobotset = "SELECT * FROM tbobot"; $bobotset = mysql_query($query_bobotset, $stok) or die(mysql_error()); $row_bobotset = mysql_fetch_assoc($bobotset); $totalRows_bobotset = mysql_num_rows($bobotset); $crMax = mysql_query("SELECT min(Golongan) as minK1, max(tes_fisik) as maxK2, max(kemampuan) as maxK3 FROM tanggota"); $max = mysql_fetch_array($crMax); $no=1; ?> <?php include ('header.php') ?> <div id="conten-wrapper"> <div id="conten"> <h1> Normalisasi Anggota Kesamaptaan </h1> <p> <a href="cetak.php"><img src="../images/btn_list.png" height="20"/> >>> Lihat & Cetak Hasil Akhir Perangkingan</a></p> <form action="<?php echo $editFormAction; ?>" method="post" name="form1" id="form1"> <table border="1" cellpadding="3" cellspacing="1"> <tr> <td>no</td> <td>nrp</td> <td>nama</td> <td>pangkat</td> <td>C1 Golongan</td> <td>C2 tes_fisik</td> <td>C3 kemampuan</td> <td>hasil</td> </tr> <?php do { $hasil= round (($max['minK1']/$row_anggotaset['Golongan']*$row_bobotset['golongan']+ $row_anggotaset['tes_fisik']/$max['maxK2']*$row_bobotset['tes_fisik']+ $row_anggotaset['kemampuan']/$max['maxK3']*$row_bobotset['kemampuan']),2) ; ?> <tr> <td><?php echo $no; $no++;?></td> <td><input type="text" name="nrp" value="<?php echo $row_anggotaset['nrp']; ?>" readonly/></td> <td><input type="text" name="nama" value="<?php echo $row_anggotaset['nama']; ?>" readonly/></td> <td><input type="text" name="pangkat" value="<?php echo $row_anggotaset['pangkat']; ?>" size="4" readonly/></td> <td><input type="text" name="mgolongan" value="<?php echo round ($max['minK1']/$row_anggotaset['Golongan'] *$row_bobotset['golongan'],2); ?>" size="2" readonly/></td> <td><input type="text" name="mtes_fisik" value="<?php echo round ($row_anggotaset['tes_fisik']/$max['maxK2'] *$row_bobotset['tes_fisik'],2); ?>" size="2" readonly/></td> <td><input type="text" name="mkemampuan" value="<?php echo round ($row_anggotaset['kemampuan']/$max['maxK3'] *$row_bobotset['kemampuan'],2); ?>" size="3" readonly/></td> <td><input type="text" name="hasil" value="<?php echo $hasil ?>" size="2" readonly/></td> </tr> <?php } while ($row_anggotaset = mysql_fetch_assoc($anggotaset));?> <tr valign="baseline"> <td colspan="8" align="right" nowrap="nowrap"><input type="submit" value="Insert record" /></td> </tr> </table> <input type="hidden" name="MM_insert" value="form1" /> </form> </div> <?php include ('footer.php') ?> </body> </html> <?php mysql_free_result($anggotaset); mysql_free_result($bobotset); ?> Am trying to update a table called "budget_request" and also inserting the data of that table into another table called "Budget". The Update works but it is not inserting into the other table. please help me out.. check my code below
<?php $id = $_GET['id']; ?> <?php include('mysql_connect.php'); $q = mysql_query("UPDATE budget_request SET status = 'Approved' WHERE id = '$id'") or die(mysql_error()); // send the details to the budget database $query = mysql_query("SELECT * FROM budget_request WHERE id = '$id' ") or die (mysql_error()); $dat = mysql_fetch_array($query); $department = $dat['department']; $amount = $dat['amount']; // Add the data to the Budget DB $que = (" INSERT INTO budget (id, department, amount, actual) VALUES ( ' ','$department', '$amount', '$amount')" ) or die(mysql_error()); header("Location: add_budget.php"); ?> I'm trying to get an equation from a user that types it in the url, ex) 1+2+3. I can get the 1,2,3 fine, but the + operator is no longer in the string. Same with the * and / operators. Is there a way to keep them as a string using $_GET?
$new_relation->save(); echo "after save".$requestor_profile->getId()." ".$requestee_profile->getId(); return true; }catch(PropelException $e) { echo "in die"; die($e); return false; } }//end - if (!$res) [/PHP] the echo after the save executes but when i look in my db table there is nothing???? please help??? I was expecting a return string, but got Resource id #2 instead. How do I have a string returned instead of that? heres my table user code Bob One Ted Two I dont get it Code: [Select] <html> <body> <?php $con = mysql_connect("localhost","user","PassWord"); if (!$con) { echo 'Could not connect to MySQL server. <br />Error # ', mysql_errno(), ' Error msg: ', mysql_error(); exit; } $db = mysql_select_db("userdb") or die("Unable to select database"); if (!$db) { echo 'Could not select db. <br />Error # ', mysql_errno(), ' Error msg: ', mysql_error(); exit; } $query = "SELECT code from usertbl WHERE user = 'Ted' LIMIT 0 , 30"; $result = mysql_query($query, $con); if (!$result) { echo 'Could not query server. <br />Error # ', mysql_errno(), ' Error msg: ', mysql_error(); exit; } echo $result; ?> </body> </html> When I use that query in phpmyadmin it works Any pointers much appreciated This works...
$result = mysql_query("SELECT * FROM login_attempts"); while($row = mysql_fetch_array($result)) { $diff = strtotime($row['login_date'])-time(); if ($diff > -300){ $count = $count + 1; } if ($count > 4) { $result = "locked"; } }This returns Resource ID 5... $result = mysql_query("SELECT * FROM login_attempts WHERE login_username='$username'"); while($row = mysql_fetch_array($result)) { $diff = strtotime($row['login_date'])-time(); if ($diff > -300){ $count = $count + 1; } if ($count > 4) { $result = "locked"; } }What's the problem? Many thanks, |