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PHP - Tiny Indented Rectagle Showing On Site.
Sorry in advance for my lack of knowledge. I am not trained and I know almost zero about site building.
On my site there is a tiny rectangle that is showing up on a drop down menu... It hasn't always been there. I'm pretty sure it showed up after upgrading to the newest Internet Explorer. I've been staring at it and finally decided to figure out what it is doing there.... Please, any and all help will be greatly appreciated. The rectangle is not hindering the site, it is just an eye sore. Thanks in advance! Yelhsa See Attachment for Screenshot. Link to Site: www.georgiafarmandforest.com Coding (this is the drop down menu part of the coding, I don't know if you need more than this.... If so, does viewing the source work?): Menu1=new Array("Home","index.php","",0,20,140); Menu2=new Array("Counties","#","",11,0,140); Menu2_1=new Array("Bartow","bartow.php","",0,20,140); Menu2_2=new Array("Carroll","carroll.php","",0,20,0); Menu2_3=new Array("Catoosa","catoosa.php","",0,20,140); Menu2_4=new Array("Chattooga","chattooga.php","",0,20,140); Menu2_5=new Array("Dade","dade.php","",0,20,140); Menu2_6=new Array("Floyd","floyd.php","",0,20,140); Menu2_7=new Array("Gordon","gordon.php","",0,20,140); Menu2_8=new Array("Murray","murray.php","",0,20,140); Menu2_9=new Array("Polk","polk.php","",0,20,140); Menu2_10=new Array("Walker","walker.php","",0,20,140); Menu2_11=new Array("Whitfield","whitfield.php","",0,20,80); Menu3=new Array("Resources","resources.php","",0,0,140); Menu4=new Array("Contact Us","contact.php","",0,20,140); Menu5=new Array("Submit Land Wanted","submit.php","",0,0,160); Similar TutorialsHi, My first post here is a cry for help I have a Windows 2003 server running IIS6/PHP5, the server hosts multiple web sites. The problem is include files that are for site A are showing on site B (each site having its own includes as part of the site files in its own site folder), though not every time, its very random, sometimes the correct includes show, sometimes ones from another site on the same server. This only occurs where the include files for both sites have the same name, such as 'inc-header.php' for example. I can only assume PHP is caching includes and because they have the same name is showing the wrong one on other sites sometimes, if I rename them to something unique then the problem goes away, but its not a practical solution to rename all include files to unique names so I find myself looking for a 'real' fix. I have a feeling its to do with the include_path in the php.ini, but right now its disabled with a semi-colon, and I don't want to set one as I have no global includes, all includes are site specific. Any help would be very much appreciated! Phil I am trying to update a tiny int i have the if statement which says when tiny int is 1 echo closed and when tiny int 0 echo open. The problem is i am trying to query the result in a drop down but the option of status Closed doesnt appear. Code: [Select] <?php //connect to database $con=mysql_connect("localhost","root","15AE@ea27") or die("couldn't connect to mysql"); //select database $db=mysql_select_db("ac_res",$con) or die("database not found"); //get ID to Edit $id = $_GET['id']; //Query Fields to edit $sql = 'SELECT * FROM `ac_reservation` WHERE `id` = "'.$id.'"'; $query = mysql_query($sql) or die("Couldn't execute query. ". mysql_error()); $results = mysql_fetch_array($query); $status = 'status'; //Query the waiter table $waiter=mysql_query("SELECT fname FROM waiter") or die("query error"); ?> <form id="edituser" name="edituser" method="post" action="editresexec.php"> <table width="300" border="0" align="center" cellpadding="2" cellspacing="0"> <tr> <th> </th> <td><input name="id" type="hidden" class="textfield" value= <?php echo $results[id]?> /> </td> </tr> <tr> <th>First Name </th> <td><input name="fl_name" id="keyboard2" type="text" class="textfield" value= <?php echo $results[fl_name]?> /> </td> </tr> <tr> <th>Number of People</th> <td><input name="n_people" id="keyboard3" type="text" class="textfield" value= <?php echo $results[n_people]?> /> </td> </tr> <tr> <th>Table Number</th> <td><input id="t_number"name="t_number" type="text" class="textfield" value= <?php echo $results[t_number]?> /></td> </tr> <tr> <th>Waiter</th> <td><?php echo "<select name=waiter>"; while($r=mysql_fetch_array($waiter)) { //echo waiter name echo "<option value='".$r['fname']."'>".$r['fname']."</option>"; } echo "</select>"; ?> </td> </tr> <tr> <th>Status</th> <td><?php //If statement if($rows['status'] == 1) { $status = "Close"; } else $status = "Open"; //Drop Down Menu For Status echo "<select>"; echo "<option value='".$status."'>".$status."</option>"; echo "</select>"; ?> </td> </tr> <tr> <td> </td> <td><input type="submit" name="Update" value="Update" /></td> </tr> </table> </form> Hello nice php experts :-) I've just changed the theme on my wordpress page but wish to add a couple of links to my non-wordpress pages to it. This is the line of code where I wish to add some more links. I'm going to use the page-link class to format the links but I'm not sure where I would add the extra divs in amongst all of those commas and brackets. <?php wp_link_pages( array( 'before' => '<div class="page-link">' . __( 'Pages:', '' ), 'after' => '</div>' ) ); ?> Any help is gratefully accepted. I use the following code to create a 48x7 array for my application: Code: [Select] // Loop through each time division for($i=0; $i<$div; $i++) { // Loop through the week we're displaying for($j=0;$j<$dayPerPage; $j++) { $dateArray = getDate( mktime( 0, 0, 0, date("m"), date("d")+$j+$dateOffset, date("Y") ) ); $date = sprintf('%04d-%02d-%02d',$dateArray["year"],$dateArray["mon"],$dateArray["mday"]); $datetime[]="$time|$date"; list($start_date) = explode('|',$datetime[1]); list($end_date) = explode('|',end($datetime)); } $min += $step_size; if($min >= 60) { $min = 0; $hr++; } $time = sprintf('%02d:%02d:00',$hr,$min); }Now, I'm under the assumption that list($start_date) and list($end_date) should give me the beginning and ending dates inside the array (say 2011-10-01 and 2011-10-07), but instead I get the beginning and ending times in it ('00:00:00' AND '23:30:00'). Could someone clarify what I'm doing wrong and how I can fix it? I'm really new to php EDIT: Sorry... used the wrong tags for the code the first time around. Fixed. preg_match_all('/(www.DOMAIN.com\/([^"]+))\"/i', $html, $matches); How do you make this match any URL on the domain including URLs with ? = & type of characters. I am pretty new to PHP and am trying to create a simple (so I assumed) page to takes data from one html page(works fine) and updates a MYSQL Database. I am getting no error message, but the connect string down to the end of the body section is showing up as plain text in my browser window. I do not know how to correct this. I have tried using two different types of connect strings and have verified my names from the HTML page are the same as listed within the php page. Suggestions on what I need to look for to correct would be great. I have looked online, but so far all I am getting is how to connect, or how to create a comment, so I thought I would try here. Thank you for any assistance I may get!! - Amy - Code: [Select] <body><font color="006600"> <div style="background-color:#f9f9dd;"> <fieldset> <h1>Asset Entry Results</h1> <?php // create short variable names $tag=$_POST['tag']; $serial=$_POST['serial']; $category=$_POST['category']; $status=$_POST['status']; $branch=$_POST['branch']; $comments=$_POST['comments']; if (!$tag || !$serial || !$category || !$status || !$branch) { echo "You have not entered all the required details.<br />" ."Please go back and try again."; exit; } if (!get_magic_quotes_gpc()) { $tag = addslashes($tag); $serial = addslashes($serial); $category = addslashes($category); $status = addslashes($status); $branch = addslashes($branch); $comments = addslashes($comments); } //@ $db = new mysqli('localhost', 'id', 'pw', 'inventory'); $db = DBI->connect("dbi:mysql:inventory:localhost","id","pw") or die("couldnt connect to database"); $query = "insert into assets values ('".$serial."', '".$tag."', '".$branch."', '".$status."', '".$category."', '".$comments."')"; $result = $db->query($query); if ($result) { echo $db->affected_rows." asset inserted into Inventory."; } else { echo "An error has occurred. The item was not added."; } $db->close(); ?> </fieldset> </div> </body> I have several "sites" located in my html directory, and each has a "general" access point and an "administrator" access point:
/var/www/html/site1/index.php /var/www/html/site1/administrator/index.php /var/www/html/site2/index.php /var/www/html/site2/administrator/index.php /var/www/html/site3/index.php /var/www/html/site3/administrator/index.phpAll sites are similar except that data will be specific to site1, site2, or site3, etc. Users who log onto /var/www/html/siteX/index.php are totally unrelated to those who logon to /var/www/html/siteX/administrator/index.php, will have different logon credentials, are stored in different DB tables, and each should have their own session. If a user logs off of either the general or administrator site, it should not effect the other site even if they were previously logged on to both on the same PC (and of course not effect other sites). When a user logs off, I would like to destroy their previous cookie and associated session. Users for either will only use https. I am using Apache to rewrite https://www.mysite.com/ to https://mysite.com/. While I named the administrator site "administrator" above, the administrator user has the ability to change the directory name. I am thinking I need to use session_set_cookie_params to specify where I wish the session cookie to be stored since /var/www/html/siteX/administrator/index.php is a sub-directory to /var/www/html/siteX/index.php, but am not really sure. Sorry for the cryptic post, but I am not very well versed in this subject. How would you recommend setting up cookies/sessions for this scenario? Thank you now i use this code to show where the visitors came from to my site. <?php $referer=$_SERVER['HTTP_REFERER']; echo $referer; ?> now, i want to show the 5 latest vistors referer's site url on my site ? Not sure if I'm trying to achieve something totally crazy here, or if this is something pretty standard. Didn't have much luck with searching as I'm not fully down with all the terms. (A) I have one site providing an RSS feed. (B) I have one site I want to search, once for each of the items in the feed A. (C) I want the results of the search in (B) to be displayed on page (C). So for example, the feed on (A) says; apples bananas oranges cheese I want site (B) to search for each of those terms (by passing the item in the feed (A) to the ?search= part of the URL of that page) and then show the results from THAT search on page C. Bit of a complex one, let me know if you need me to clarify. Thanks for any help! Transferring data from sub-domain.site.com Reading sub-domain.site.com What is this all about? I'm going to put all .. images into a separate sub-domain eg: images.site.com. This would create a folder inside my public_HTML called "images" Now when sites have that Transferring data, and Reading... is this .. something relating to what I want. Facebook also does it, and they get their images for the site from a sub domain, how is it all done? I'm not sure if its entirely PHP, but I hope someone can help. Thanks I'm currently running a classified ads site and planning to display my own content from database combined with and external site rss. So here is what i got right now after the db query for the jobs ads (procedural php),
while ($row = mysqli_fetch_array($results, MYSQLI_ASSOC)){
echo '<div class="media margin-none">
<a class="pull-left bg-inverse innerAll text-center" href="#"><img src="'.$foto.'" share_alt="" width="100" height="100"></a>
<div class="media-body innerAll">
<h4 class="media-heading innerT">
<a href="' . $row['title'] .'-da' . $row['id_ad'] . '" class="text-inverse">'. $remuneracion .' ' . substr(ucfirst(strtolower($row['title'])), 0, 53) . '</a> <small class="pull-right label label-default"><i class="fa fa-fw fa-calendar-o"></i> ' . $row['date_created'] . '</small></h4>
<p>' . substr(ucfirst(strtolower($row['description'])), 0, 80) . ' ...</p>';
echo '</div>
</div>
<div class="col-separator-h"></div>';
}
echo pagination($statement,$per_page,$page, $url_filtros, $filtros);
?>
it is the while loop that i use to display ads from my database, what could be the best way to display (in this same loop?) other site's rss feed so i can show my content combined with the external rss?
Thanks
Hi I made a new design for my website and I made some changes. I want to use layout for my second site.
I'll like to know if my site is easier to browse through now and if you like the design better?. I test my site on internet explorer, chrome, and firefox. It is best to use site on better browsers like firefox and chrome to get a better experience of site. Thanks.
http://adjade.com
This topic has been moved to mod_rewrite. http://www.phpfreaks.com/forums/index.php?topic=318858.0 How do I only redirect the page when index.php is present? How can i make echo "<b>Site:</b> ".$req_user_info['site']."<br>"; linkable The site raw fron the db contains an site url. Regards I decided to redo the individual roster page I have on my site and came up with this. <?php if(isset($_GET['username']) && $_GET['username'] != '') { $username = $_GET['username']; $query = "SELECT bio.username AS username, bio.charactername AS charactername, bio.id AS id, bio.style_id AS style FROM `efed_bio` AS bio ON bio.id = ebw.bio_id WHERE bio.username = '$username'"; if(!$result = mysql_query($query)) while ($row = mysql_fetch_assoc($result)) { $fieldarray=array('id','username','charactername','style'); foreach ($fieldarray as $fieldlabel) { if (isset($row[$fieldlabel])) { $$fieldlabel=$row[$fieldlabel]; $$fieldlabel=cleanquerydata($$fieldlabel); } } } } ?> <h1><?php echo $charactername; ?>'s Biography</h1> <?php echo getBioMenu($style,$username); ?> <? //If the GET page variable is biography, display the biography page if ($page == 'biography') { echo getBiopgrahy($style,$id); } //Or if the GET page variable is gallery, display the gallery page elseif ($page == 'gallery') { echo getGallery($style,$id); } //If the GET page variable is news, display the news page elseif ($page == 'news') { echo getNews($$id); } //If the GET page variable is segments, display the segments page elseif ($page == 'segments') { echo getBioSegments($id,S); } //If the GET page variable is matches, display the matches page elseif ($page == 'matches') { echo getBioSegments($id,M); } elseif ($page == 'chronology') { echo getChronology($id); } //Otherwise display the bio else { echo getBio($style,$id); } ?> The list of characters are listed he http://kansasoutlawwrestling.com/roster An example of someone's individual roster page is located he http://kansasoutlawwrestling.com/bio?username=oriel Hi all, I have table, named: tb_event (id, f_date, f_title, f_image, f_status) How to manage, while if 'f_status' from all records NOT EQUAL to 'Published' then show ABCDE Note: on tb_event should be only the latest record (1 record only) that will be shown/published I have code: <? $qry = mysql_query( "SELECT * FROM tb_event WHERE f_status = 'Published'") or die(mysql_error()); while($res = mysql_fetch_array($qry)) { if ($res[f_status] = "Published") { echo ' <img src="images/uploads/'.$res[f_image].'" border="0" /> '; } else { echo ' ABCDE '; } } ?> The result is 'ABCDE' not shown while f_image (all records) is OFF Please help me.. thanks Hi, I just connect to my server through ftp. i want to edit php.ini file. which is placed in /etc/php.ini "etc" folder. but i'm unable to see etc folder. there are only two folders one is cgi-bin and other is www. can anyone help me to find out etc folder. i've check to show hidden files in filezilla. Thanks I have a really strange query for you all to figure out why I'm not coming up with the right SELECT statement. I've echoed it and I'll show you what I get for a result from the echo as well. Table- Users Fields- id,creator_id,username,password,firstname,lastname,email,status_id,isadmin,datecreated $query = "SELECT CONCAT_WS(' ', firstname, lastname) AS name, CONCAT_WS(' ', firstname, lastname) AS handler, DATE_FORMAT(datecreated, '%M %d, %Y') AS datecreated, id, username, email FROM handlers WHERE handlers.id = handlers.creator_id"; produced this result... SELECT CONCAT_WS(' ', firstname, lastname) AS name, CONCAT_WS(' ', firstname, lastname) AS handler, DATE_FORMAT(datecreated, '%M %d, %Y') AS datecreated, id, username, email FROM handlers WHERE handlers.id = handlers.creator_id php data table code: <?php $query = "SELECT CONCAT_WS(' ', firstname, lastname) AS name, CONCAT_WS(' ', firstname, lastname) AS handler, DATE_FORMAT(datecreated, '%M %d, %Y') AS datecreated, id, username, email FROM handlers WHERE handlers.id = handlers.creator_id"; $result = mysqli_query ( $dbc, $query ); // Run The Query $rows = mysqli_num_rows($result); echo $query; <?php if ($rows > 0) { ?> <table cellspacing="0" class="listTable" id="handlersPageList"> <!-- Thead --> <thead> <tr> <th class="first"><div></div></th> <th><a href="#" title="Handler Name">Handler Name</a></th> <th><a href="#" title="Handler Username">Handler Username</a></th> <th><a href="#" title="Handler Emal">Handler Email</a></th> <th><a href="#" title="Creator">Creator</a></th> <th class="last"><a href="#" title="Date Created">Date Created</a></th> </tr> </thead> while ( $row = mysqli_fetch_array ( $result, MYSQL_ASSOC ) ) { echo ' <tr> <td><input type=checkbox class=checkbox value="' . $row['id'] . '" /></td> <td>' . $row['handler'] . '</td> <td>' . $row['username'] . '</td> <td><a href="mailto:' . $row['email'] . '>' . $row['email'] . '</a></td> <td>' . $row['name'] . '</td> <td class=last>' . $row['datecreated'] . '</td> </tr>'; } ?> I just decided to take out the parts of the page that would be needed to answer this problem instead of the whole file. This is a little confusing okay lets say the first user is the Administrator with an id of 1 obviously has a first name and last name and username and email and the date he registered is his datecreated and his creator_id is going to be preset because he created it himself so its going to be 1. The 1st row in the database displays fine however I have 4 other rows that for some reason aren't displaying. And don't know why. For handlers 2-4 they all have their own first and last names and usernames and everything else however when it comes to the creator_id those 3 have a creator_id of 1 representing that the Administrator created it so in the data table instead of it showing the value of 1 for the creator_id I just want it to get the CONCCAT version of the first and last name of the Administrator. In the past I have not done a very good job of explaining things so I hope this is more than clarified my intention with my code and what it should do and what it is doing wrong right now. If you have any other questions please ask. |
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