PHP - Why Won't Strip_tags() Work On This String?

Hi all,

Thanks for reading. I have this code:

Code: [Select]
$message = strip_tags($_POST['message'], '<p><strong><em>');

My question is however, is there a way that I could disable the onmouseover features in those tags?

Thank you.

Hi All,

Hope you can help, I'm having problems with the strip_tags code, I'm having problems getting it to work with certain tags, the code below shows my issue:


$print_description = <span style="color: #ff99cc; font-size: large">4 x BLUE handmade clay feet</span>

$print_description = strip_tags($print_description); //remove html because of danger of broken tags

I've cut down the code to show the problem. So I want to strip the Span tags; the problem I am having is as soon as you have a style attribute with more than one attribute and you use a ; symbol strip_tag will strip the entire content of the <span>AND ALL THE TEXT IN THE MIDDLE</span>.

I want to just be left with '4 x BLUE handmade clay feet'

If I take the ; out and just have one style it works fine. I am using tiny_MCE so don't have the option not to use what it makes me use.

I've searched the net and have tried a few things to make it work but now I'm at a loss.

Any help would be gratefully received.

This is what I have


$eeee = $_POST['forum_reply'];
 $eeee = strip_tags($eeee, '<p>');
echo $eeee;

this is what prints out

Quote

Untitled document
 testinggg


this is a print_r of $_Post

Quote

Array ( [forum_reply] => testinggg
[form_reply_submit] => Reply )


Please someone tell me what in binary's name is going on!

Hi guys

I was just wondering if there is some date combination for which this type of comparisons will not work.

var_dump("2010-15-1">"2010-4-01");

Provided the date is always in the YYYY-mm-dd format with optional preceding 0 .

Thanks

Hi there - can anyone lend me a little advise as to what I'm doing wrong here.

I have this line:
$query=mysql_query("SELECT * FROM gallery a JOIN gallery_image b ON a.id = b.gallery_id where gallery_id=$gallery_id");

I am trying to add an order by statement: order by gallery_image.priority

So I created:
$query=mysql_query("SELECT * FROM gallery a JOIN gallery_image b ON a.id = b.gallery_id where gallery_id=$gallery_id order by gallery_image.priority");

But, I receive the error (even though there is table called "Gallery Image" and a column called "Priority":
Code: [Select]
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/***/public_html/***/gallery.php on line 5
select: Unknown column 'gallery_image.priority' in 'order clause'

Hi,

I am trying to make some adjustments to uploadify.php which comes with the latest version of uploadify (3.0 beta), so that it works with a session variable that stores the login username and adds it to the path for uploads.  Here is uploadify.php as it currently looks:

Code: [Select]
<?php
session_name("MyLogin");
session_start();

$targetFolder = '/songs/' . $_SESSION['name']; // Relative to the root

if (!empty($_FILES)) {
$tempFile = $_FILES['Filedata']['tmp_name'];
$targetPath = $_SERVER['DOCUMENT_ROOT'] . $targetFolder;
$targetFile = rtrim($targetPath,'/') .'/'. $_FILES['Filedata']['name'];

// Validate the file type
$fileTypes = array('m4a','mp3','flac','ogg'); // File extensions
$fileParts = pathinfo($_FILES['Filedata']['name']);

if (in_array($fileParts['extension'],$fileTypes)) {
move_uploaded_file($tempFile,$targetFile);
echo '1';
} else {
echo 'Invalid file type.';
}
}

echo $targetFolder;

?>
I added Code: [Select]
echo $targetFolder; at the bottom so that I could make sure that the string returned was correct, and it is, i.e. '/songs/nick'.  For some reason though, uploads are not going to the correct folder, i.e. the username folder, but instead are going to the parent folder 'songs'.  The folder for username exists, with correct permissions, and when I manually enter Code: [Select]
$targetFolder = '/songs/nick';all works fine.  Which strikes me as rather strange.  I have limited experience of using php, but wonder how if the correct string is returned by the session variable, the upload works differently than with the manually entered string.

Any help would be much appreciated.  It's the last issue with a website that was due to go live 2 days ago!

Thanks,

Nick

This topic has been moved to PHP Regex.

http://www.phpfreaks.com/forums/index.php?topic=326004.0

Hello all,

I'm trying to change the end of a javascript call based on the end of the url string. The common part of all the url strings is sobi2Id=, I'm trying to do this with strstr but am having no luck. I'm new to php so my syntax knowledge is terrible!

at the moment i've got

Code: [Select]
<?php

       $url = $_SERVER['REQUEST_URI'];

     $tag = strstr ($url, 'sobi2Id=');

       echo $tag; 
?>
but this returns an unexpected T_STRING, expecting ',' or ';'

Can anyone debug this? I may well be being really silly!

Hey there,

Thanks for taking the time to read my thread. My issue is that I can't think of a way to edit a XML file using PHP's XML functionality and then assign the edited contents to a string instead of saving the file. Because my issue is that I have to edit the XML file based upon a string brought from a remote location then give it back to that remote location using a string again, to be exact I am doing it via Linux command line utilizing SSH2.

This is what I managed to complete on my own.


function CheckIVMPConfig($ServerID)
{
global $Panel;

if(is_numeric($ServerID) && $this->IsValidServer($ServerID))
{
// We select the game server that the FTP account was created for.
$Servers = mysql_query("SELECT * FROM control_servers WHERE server_id = '".mysql_real_escape_string($FTPAccount['ftp_server'])."'");
$Server = mysql_fetch_array($Servers);

// Here we select the Box ID that the game server is on.
$Boxs = mysql_query("SELECT * FROM control_machines WHERE machine_id = '".$Server['server_machine']."'");
$Box = mysql_fetch_array($Boxs);

// Now we select the required package for the box.
$Packages = mysql_query("SELECT * FROM control_packages WHERE package_id = '".$Server['server_package']."'");
$Package = mysql_fetch_array($Packages);

// Retrive the file.
$Config = $CProtocol->exec("cat /home/{$Server['server_id']}/{$Package['package_config']}");

$Parse = SimpleXMLElement($Config);

foreach($Parse as $Entry) // loop through our books
{
if($Entry->port != $Server['server_port'])
{
// edit the value
}
else if($Entry->maxplayers > $Server['server_slots'])
{
// edit the value
}
}
}
}

hey guys im trying to find a string inside a string which could be made up of different things eg...

{$test}, {$test1}, {$test2}   
etc (but the varable inside could be called anything hence maybe using regex im not sure?)
is this possible?...i hope you guys understand....thanks

I have the following function, which takes a string with commas in it and attempts remove those commas. The way I have it here is that I use explode to take out the commas, which makes an array, and then iterate through that array to put a string back together without the commas.

function tags_to_sort_by( $sortMeta ) {      
   $sortByArray = explode(",", $sortMeta);
   $sortByCount = count($sortByArray);
   for ($i = 0; $i < $sortByCount; $i++) {
      $sortByString += $sortByArray[$i];
   }
   return $sortByString;
}

What does not work is the following line:
$sortByString += $sortByArray[$i];
Somehow that outputs a 0, which I don't understand. It should output something like: arrayItem1 arrayItem2 array3 etc.

My question is if there either is an easier way to remove the commas from the original string or what I am doing wrong in this line:
$sortByString += $sortByArray[$i];  // I am trying to concatenate each part of the array back into the string.

Thanks a lot for help with this!

In PHP Version 8.0 shows error as :
PHP Fatal error:  Uncaught TypeError: Unsupported operand types: string * string 
String is as under :
$TAXVALUE= round($QNTY*($PRICE- ($PRICE*$DISC/100)),2);

In previous versions of PHP it does not show any error.

Please resolve the issue.

Ok... I had typed this post out ONCE already and when I clicked REFRESH IMAGE to get a diff captcha it ERASED MY POST

LMAO this is not my night....


What I need help with is probably more simple then I can even think right now - ive been digging at this for 3 hrs now and im out of time for the night

I have a DB Record storing ID's between PIPES |

when the initial entry is made in DB it stores it like so
|47|      NOTE: the number could be different these are ID's number doesnt matter its just between Pipes

When the second entry is added its added like so

|47||67|

say we have a total of 5 Entries

|47||67||82||55||69|

I need to find ID 82 in that string and it has to be between Pipes
Find 82 in data between | and return that ID 82

I am putting between pipes because the ID's can be duplicate digits in different lengths
so say I have 8 as my ID and down the string i have another id as 88  -- I cant possibly find the correct ID without some sort of seperation character so i used Pipes

soo my end goal is the ability to search and if true or false do action

if ($result == $find_id){
echo "ID is there";
}else{
echo "NOT THERE -- Adding it";
}
Any help is appreciated guys
Thanks
SangrelX

I am looking for a date within larger string, lets say the date is December 4, 2010.
To find it I use pattern and function below:

$Pattern='/[(January|February|March|April|May|June|July|August|September|October|November|December)] \d, \d\d\d\d/i';
preg_match_all($Pattern, $String, $Matches, PREG_OFFSET_CAPTURE, $NumberPosition);

The function finds the dates within the string but to my supprise the result I get in $Matches is: r 4, 2010
What I would like to get is: December 4, 2010 but don't know how it should be fixed. I thought that with the pattern I am using but obviously that is not the case.