PHP - Php Script To Parse Xml And Insert Into Mysql
Hello, I am very new to both PHP and MYSQL but I am eager to learn.
What I want to do is write a PHP script that will parse an XML file and insert the results into a MYSQL database. I've read a bunch of guides online and I think I have the parser structure down. I created a parser using xml_parser_create(). As I understand it, I need to create functions to handle each of the three events, startTag, endTag, and contents. This is where I am not sure what to do. What do I need to tell these functions to do when these events are triggered? I know I need to connect to the MYSQL database at some point but I do not know when. If anyone could point me in the right direction, I'd appreciate it. Similar TutorialsCan anyone tell me why this is not INSERTing? My array data is coming out just fine.. I've tried everything I can think of and cannot get anything to insert.. Ahhhh! <?php $query = "SELECT RegionID, City FROM geo_cities WHERE RegionID='135'"; $results = mysqli_query($cxn, $query); $row_cnt = mysqli_num_rows($results); echo $row_cnt . " Total Records in Query.<br /><br />"; if (mysqli_num_rows($results)) { while ($row = mysqli_fetch_array($results)) { $insert_city_query = "INSERT INTO all_illinois SET state_id=$row[RegionID], city_name=$row[City] WHERE id = null" or mysqli_error(); $insert = mysqli_query($cxn, $insert_city_query); if (!$insert) { echo "INSERT is NOT working!"; exit(); } echo $row['City'] . "<br />"; echo "<pre>"; echo print_r($row); echo "</pre>"; } //while ($rows = mysqli_fetch_array($results)) } //if (mysqli_num_rows($results)) else { echo "No results to get!"; } ?> Here is my all_illinois INSERT table structu CREATE TABLE IF NOT EXISTS `all_illinois` ( `state_id` varchar(255) NOT NULL, `city_name` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Here is my source table geo_cities structu CREATE TABLE IF NOT EXISTS `1` ( `CityId` varchar(255) NOT NULL, `CountryID` varchar(255) NOT NULL, `RegionID` varchar(255) NOT NULL, `City` varchar(255) NOT NULL, `Latitude` varchar(255) NOT NULL, `Longitude` varchar(255) NOT NULL, `TimeZone` varchar(255) NOT NULL, `DmaId` varchar(255) NOT NULL, `Code` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Hi i have this upload script which works fine it uploads image to a specified folder and sends the the details to the database. but now i am trying to instead make a modify script which is Update set so i tried to change insert to update but didnt work can someone help me out please this my insert image script which works fine but want to change to modify instead Code: [Select] <?php mysql_connect("localhost", "root", "") or die(mysql_error()) ; mysql_select_db("upload") or die(mysql_error()) ; // my file the name of the input area on the form type is the extension of the file //echo $_FILES["myfile"]["type"]; //myfile is the name of the input area on the form $name = $_FILES["image"] ["name"]; // name of the file $type = $_FILES["image"]["type"]; //type of the file $size = $_FILES["image"]["size"]; //the size of the file $temp = $_FILES["image"]["tmp_name"];//temporary file location when click upload it temporary stores on the computer and gives it a temporary name $error =array(); // this an empty array where you can then call on all of the error messages $allowed_exts = array('jpg', 'jpeg', 'png', 'gif'); // array with the following extension name values $image_type = array('image/jpg', 'image/jpeg', 'image/png', 'image/gif'); // array with the following image type values $location = 'images/'; //location of the file or directory where the file will be stored $appendic_name = "news".$name;//this append the word [news] before the name so the image would be news[nameofimage].gif // substr counts the number of carachters and then you the specify how how many you letters you want to cut off from the beginning of the word example drivers.jpg it would cut off dri, and would display vers.jpg //echo $extension = substr($name, 3); //using both substr and strpos, strpos it will delete anything before the dot in this case it finds the dot on the $name file deletes and + 1 says read after the last letter you delete because you want to display the letters after the dot. if remove the +1 it will display .gif which what we want is just gif $extension = strtolower(substr($name, strpos ($name, '.') +1));//strlower turn the extension non capital in case extension is capital example JPG will strtolower will make jpg // another way of doing is with explode // $image_ext strtolower(end(explode('.',$name))); will explode from where you want in this case from the dot adn end will display from the end after the explode $myfile = $_POST["myfile"]; if (isset($image)) // if you choose a file name do the if bellow { // if extension is not equal to any of the variables in the array $allowed_exts error appears if(in_array($extension, $allowed_exts) === false ) { $error[] = 'Extension not allowed! gif, jpg, jpeg, png only<br />'; // if no errror read next if line } // if file type is not equal to any of the variables in array $image_type error appears if(in_array($type, $image_type) === false) { $error[] = 'Type of file not allowed! only images allowed<br />'; } // if file bigger than the number bellow error message if($size > 2097152) { $error[] = 'File size must be under 2MB!'; } // check if folder exist in the server if(!file_exists ($location)) { $error[] = 'No directory ' . $location. ' on the server Please create a folder ' .$location; } } // if no error found do the move upload function if (empty($error)){ if (move_uploaded_file($temp, $location .$appendic_name)) { // insert data into database first are the field name teh values are the variables you want to insert into those fields appendic is the new name of the image mysql_query("INSERT INTO image (myfile ,image) VALUES ('$myfile', '$appendic_name')") ; exit(); } } else { foreach ($error as $error) { echo $error; } } //echo $type; ?> Hi there I am having trouble with the code below The difficulty is with this bit I think ('input type="submit"','value="Submit"') Many thanks Doug <?php echo tep_draw_form('advanced_search', tep_href_link(FILENAME_ADVANCED_SEARCH_RESULT, '', 'NONSSL', false), 'get') . tep_draw_hidden_field('search_in_description','1') . tep_draw_input_field('keywords', TEXT_ENTER_KEYWORDS , 'size="10" maxlength="30" onFocus="emptyMe()" style="width: ' . (BOX_WIDTH-25) . 'px"'); ?> <?php echo tep_hide_session_id() . ('input type="submit"','value="Submit"') . '</form>';?> I need PHP script that will parse XML-based (.xspf format) live stream playlist stored on web server, retrieve track data and print it on my web page. Print inside div as scrolling text (one line). The track data on page need be refreshed synchronously to show current track info. XSPF playlist example: Code: [Select] <?xml version="1.0" encoding="UTF-8"?> <playlist xmlns="http://xspf.org/ns/0/" version="1"> <title/> <creator/> <trackList> <track> <location>http://geodesid5.streams.audioveduct.com:80/di_ambient7</location> <title>Bruno Sanfilippo - Piano Textures 2 II</title> <annotation>Stream Title: Ambient - DIGITALLY IMPORTED - a blend of ambient, downtempo, and chillout Content Type:audio/mpeg Current Listeners: 0 Peak Listeners: 0 Stream Gen Electronic Ambient Downtempo</annotation> <info>http://www.di.fm</info> </track> </trackList> </playlist> I need get data from fields 'title' and 'annotation' (only text between Stream Title and Content Type). Also, after these two, I want scroll small custom text, when required. I searched some close example, but didn't find yet. Will be DOMDocument method suitable for this task? Can someone show me the right method to do this? Hello, I'm having a bit of a problem here, all help to this issues would be much appreciated I am trying to use text boxes to insert numbers into the database based on what is inputed. If I have a string, like this for example: $variable = 09385493; And I want to insert it into the database like this: mysql_query("INSERT INTO integers(number) VALUES ('$variable')"); When checking the integers table in my database, looking at the number field, the $variable that was inserted is outputted as 9385493 Notice the number zero was taken out of the front of the number. If the number is double 0's (009385493), both of those zero's would disappear, too. Thanks I'm new to PHP/MySQL and have been searching high and low for a solution to this... When using my PHP script to insert a row into the database it errors out but does not give me a specific error. When I use the MySQL command line client I can insert the first, second, third, or any number of rows without a problem. What I don't understand is, once I have inserted a row using the command line client, my PHP script will insert rows without issue. So my question is, what is it about the first row being inserted that makes it so special? One of the columns in the table is an AUTO_INCREMENT field, so i'm guessing that has something to do with it? I've used this on like three other scripts I don't know why it won't insert now <?php date_default_timezone_set('America/Los_Angeles'); $timestamp = date('H:m:s m.d'); $admin = '24.68.214.97'; $visitor_ip = $_SERVER['REMOTE_ADDR']; $host="mysql"; // Host name $username="15557_test"; // Mysql username $password="**********"; // Mysql password $db_name="15557_test"; // Database name $tbl="announce"; // Table name mysql_connect("$host", "$username", "$password")or die("cannot connect to server"); mysql_select_db("$db_name")or die("cannot select DB"); $body = $_POST["body"]; if ($visitor_ip == $admin) { mysql_query("INSERT INTO $tbl (body, date) VALUES ('$body', '$timestamp')"); //right here, i can echo $body and see what I wrote, but I can't insert into $tbl } else { die("no"); } ?> <meta http-equiv="REFRESH" content="0;url=http://testchan.dcfilms.org/board-b.php"> Hi guys I have a registration form working fine, my database is as below: userid username password repeatpassword I have added another column which is "name", users can update their profile once they have logged in so I have created updateprofile.php and when I login-->go to update profile and insert my name nothing adds to mysql name column this is my code below: <?php include ("global.php"); //username session $_SESSION['username']=='$username'; $username=$_SESSION['username']; //welcome messaage echo "Welcome, " .$_SESSION['username']."!<p>"; if ($_POST['register']) { //get form data $name = addslashes(strip_tags($_POST['name'])); $update = mysql_query("INSERT INTO users (name) VALUES ('$_POST[name]') WHERE username='$username'"); } ?> <form action='updateprofile.php' method='POST'> Company Name:<br /> <input type='text' name='name'><p /> <input type='submit' name='register' value='Register'> </form> can you please tell me where in this code is wrong? Im new in php so please excuse me if I have silly mistakes. thanks in advance I have this code: <?php $con = mysql_connect("localhost","hhh","hhh"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("hhh", $con); // -------------------- // Avatar insert check // -------------------- session_start(); $name = $_POST[name]; $group = $_POST[group]; $age = $_POST[age]; $usernameid = $_SESSION[id]; $result = mysql_query("SELECT * FROM avatars WHERE name='$_POST[name]'"); $num = mysql_numrows($result); if ($num == 0) { mysql_query("INSERT INTO avatars (id, usernameid, name, group, age, xp) VALUES ('', '$usernameid', '$name', '$group', '$age', '0')"); header( 'Location: me/' ) ; } else echo 'Sorry, please pick a new name'; ?> And it does everything but put the data into the datebase. If I add a session befor and after '$request' they both run, but the sql doesn't. No error returns, if just redirects to the other page. Any help? well this is truely embarrising...i have a insert statement which works within phpmyadmin but when using mysqli_query it returns a error.
INSERT INTO users (username, timestamp) VALUES ('test', UTC_TIMESTAMP())Unknown column 'timestamp' in 'field list' i've been playing about with this for a few hours now ...tried changing the column name (timestamp), adding ` around column names as well as table name. the column exists which is the strangest part, and ive even checked there is no space after the column name in the db. whats going on please? I need help badly! What I want to do is insert into database the value from the selected radio group buttons.. All of them. There are 10 radio groups total (they can be less, but not more). Thanks! Code: [Select] <?php require_once('Connections/strana.php'); mysql_select_db($database_strana, $strana); ?> <link href="css/styles.css" rel="stylesheet" type="text/css" /> <table width="100%" height="100%" style="margin-left:auto;margin-right:auto;" border="0"> <tr> <td align="center"> <form action="" method="post" enctype="multipart/form-data" name="form1"> <table> <?php $tema = mysql_query("SELECT * from prasanja where tip=2")or die(mysql_error()); function odgovor1($string) { $string1 = explode("/", $string); echo $string1[0]; } function odgovor2($string) { $string1 = explode("/", $string); echo $string1[1]; } while ($row=mysql_fetch_array($tema)) { $id=$row['prasanje_id']; $prasanje=$row['prasanje_tekst']; $tekst=$row['odgovor']; ?> <tr> <td> </td> </tr> <tr> <td class="formaP"> <?php echo $prasanje?> </td> </tr> <tr> <td class="formaO"> <p> <label> <input type="radio" name="Group<?php echo $id?>" value="<?php odgovor1($tekst) ?>" /> <?php odgovor1($tekst) ?></label> <br /> <label> <input type="radio" name="Group<?php echo $id?>" value="<?php odgovor2($tekst) ?>" /> <?php odgovor2($tekst) ?></label> <br /> </p></td> </tr> <tr> <td> <br /> </td> </tr> <?php } ?> </table> <input align="left"type="submit" name="submit" value="Внеси" > </form> </td> </tr> </table> prasanje = question tekst/odgovor = answer The answer table: id - primary question_id - the questions ID whose answer is selected in the radio group user_id - cookie takes care of this answer - the value from radio group date - automatic I don't understand where the empty value is. I've substituted the variables for text and still have the same problem. Code: Code: [Select] $sql = "INSERT INTO courses (course#, name, subject, semester, ap)VALUES('$courseNum', '$courseName', '$subject', '$semester', '$ap')"; Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 Hello, I'm trying to write my first database using SQL and PHP, without much luck, I'm afraid. After inserting a new record (for which I didn't have a problem), I wanted to automatically generate a username which is the person's first name (they'll then be able to change it later). Trying to use Dreamweaver as a model, I've come up with this: $updateSQL = sprintf("UPDATE users SET username=%s", GetSQLValueString($_POST['first_name'], "text")) Well...it does update the username, but it does so on ALL of the records as opposed to the one that was just inserted. Any help would be appreciated... Thank you. i have got this script which displays all folders within a folder but what i want to do now is get it to display a random picture for each of the folders that it is showing in the grid. i know how to display a random image using array_rand() but i don't know how i would implement it. Code: [Select] <form name="Gallery" method="post"> <?php $path = "gallery_files/gallery/"; $dir_handle = @opendir($path) or die("Unable to open folder"); echo "<table cellspacing='15'>"; echo "<tr>"; while (false !== ($folder = readdir($dir_handle))) { if($folder == "pictures.php") continue; if($folder == ".") continue; if($folder == "..") continue; echo ($x % 6 == 0) ? "</tr><tr>" : ""; echo "<td><a href='pictures/?folder=$folder'><img src='path/to/random/image' style='height:auto;width:110px;' alt='$folder'></a><br /><a href='pictures/?folder=$folder'>$folder</a></td>"; $x++; } echo "</tr>"; echo "</table>"; closedir($dir_handle); ?> </form>
Array ( [data] => Array ( [0] => Array ( [latitude] => 22.934566 [longitude] => 79.08728 [type] => county [distance] => 44.328 [name] => Narsinghpur [number] => [postal_code] => [street] => [confidence] => 0.5 [region] => Madhya Pradesh [region_code] => MP [county] => Narsinghpur [locality] => [administrative_area] => [neighbourhood] => [country] => India [country_code] => IND [continent] => Asia [label] => Narsinghpur, India ) ) ) I am attempting something similar to the following: Code: [Select] mysql_query("UPDATE table SET name='$name' WHERE id=$id"); if (mysql_affected_rows()==0) { mysql_query("INSERT INTO table (id, name) VALUES ('$name',$id); } If the $id row does not exists in the table, mysql_affected_rows() returns 0 and a new $id row gets inserted but if the $id row already exists and UPDATE changes nothing, mysql_affected_rows() still returns 0 and gives an 'duplicate id' error as expected. I know I could use a SELECT to test for the existance of the $id row. In Perl there is an '0E0', 'zero but true', condition to handle this. Is there an equivilant in PHP? I'm trying to insert array of posts categories into MySQL. I'm getting category IDs from drop down list.. ERR: Notice: Notice: Array to string conversion in C:\laragon\*********\includes\functions.php on line 477
Array Array ( [0] => Array ( [0] => 4 [1] => 5 ) )
PHP try { $sql = "INSERT INTO posts_category_ids (post_id, category_id) VALUES"; $insertQuery = array(); $insertData = array(); foreach ($filter_category as $row) { $insertQuery[] = '(?, ?)'; $insertData[] = $id; $insertData[] = $row; } if (!empty($insertQuery)) { $stmt = $this->conn->prepare($sql); $stmt->execute($insertData); //477 } }catch (Exception $e){ echo $e->getMessage(); } }
I am trying to add a value, input into a form, to a MySQL database. However, something must be wrong with the casting, because if there is a space in the form value, then I get an error, as in: //$_POST['string'] == '1blah 2blah'; sql = "INSERT INTO table (some_string) VALUES ($_POST[string])"; $sql_result = mysql_query($sql) or die ('The error is as follows: ' . mysql_error() . '<br /><br />Value could not be added.'); Then I get the following error: The error is as follows: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '2blah' at line 1 I've entered paragraphs into a database before, so this error is now to me. The column 'some_value' is a type: varchar(50). I have a problem where I am getting these errors after a form has been submitted from join.html Here are the errors: Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'scswccla'@'localhost' (using password: NO) in /home/scswccla/public_html/insert.php on line 9 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in /home/scswccla/public_html/insert.php on line 9 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'scswccla'@'localhost' (using password: NO) in /home/scswccla/public_html/insert.php on line 9 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in /home/scswccla/public_html/insert.php on line 9 Here is the insert.php file http://pastebin.com/EVtgidQC And the join.html file - http://pastebin.com/hqDtGLe5 How would I fix those errors - I got the code from http://forum.hey0.net/showthread.php?tid=2509 The form is at scswc.com/join.html if you want to look at it. I really want to get this working so if you need any more info to help fix it just ask thanks! |