|
PHP - Super Simple Fopen Question
Using:
$file = fopen("file1.txt", "r") or exit("Unable to open file!"); I have multiple files (file1.txt, file2.txt, etc.) how can I edit this so it just takes ANY file that ends in .txt and opens it? Similar TutorialsHello again, I got a problem with one of my pages that uses MySql. I didn't expect my site to shoot up into the 1000's per hour but it has but has destroyed the loading time of one of my pages. Below is the function that is super slow! Code: [Select] function get_top($timeframe='today', $time=10, $friends=true, $limit=5, $unique=true, $me_only=false){ if($friends===false){$q='';}else{ $q=' AND (username IN ('; // This array can have upto 500 items in it. global $friend_id_array, $me;$tarray=$friend_id_array; $tarray[]=$me['id']; $x= implode(',',$tarray);$q.=$x; $q.= '))'; } if($me_only){ $q=' AND username = \''.$me['id'].'\' '; } if($timeframe=='today'){ $q_timeframe='AND DATE(thedate) = DATE(NOW()) AND YEAR(thedate) = YEAR(NOW())'; // Checking the date could be slow }else if($timeframe=='week'){ $q_timeframe='AND WEEK(thedate) = WEEK(NOW()) AND YEAR(thedate) = YEAR(NOW())'; }else if($timeframe=='month'){ $q_timeframe='AND MONTH(thedate) = MONTH(NOW()) AND YEAR(thedate) = YEAR(NOW())'; }else if($timeframe=='all'){ $q_timeframe=''; } if($unique){$q_unique='GROUP BY username';} $query="SELECT MAX(score) as highscore, username, timeframe, thedate FROM other_click WHERE (timeframe = '$time') $q $q_timeframe $q_unique ORDER BY highscore DESC LIMIT 0, $limit"; // A very long query $result=@mysql_query($query)or die(mysql_error()); if(@mysql_num_rows($result)>0){ while($row=@mysql_fetch_array($result)){ // Maybe resorting the array makes it super slow $id_array[]=$row; } return $id_array;}else{return false;} } I've commented the lines which I think maybe making this page load slowly. I also thought the way the page is loaded. The page is called 6 times per user but with different settings eg, Friends only and only scores added today. Please help because this is crippling my site. Thank-you all Paul Hey all, I'm well aware of associative arrays (key/value pairs) and how you can index them in an array like this: $character = array (name=>"John", occupation=>"Programmer", age=>22, "Learned language "=>"PHP" ); Then it makes sense to iterate through the key/value pairs of the array using foreach: foreach ( $character as $key=>$val ){ print "$key = $val<br>"; } However, I was watching a video tutorial where he created a $_SESSION array and then created an array associative array: $_SESSION['cart'] = array(); [/PHP] Then he added a function add_to_cart: function add_to_cart($id){ if(isset($_SESSION['cart'][$id])){ $_SESSION['cart'][$id]++; return true; } else { $_SESSION['cart'][$id] = 1; return true; } return false; } Now that $id variable holds an id converted to integer from the dataabse. So if first item is clicked, id holds a value of integer 1. When I see this: $_SESSION['cart'][$id] I see an array that holds two indexes, each index containing an associative array: [[array() => ''], [1 => '']]. So at index 0 of $_SESSION is [array() => '']. But then he uses the foreach iterator like this: function total_items($cart){ $items = 0; if(is_array($cart)){ foreach($cart as $id => $qty){ $items += $qty; d } } return $items; } Now I'm very confused. As you can see in that foreach method, it says that $id (and its corresponding value) is an associative array of $cart array, not $_SESSION array. I don't see how that happened. I thought $cart and id$ were distinct indexes of $_SESSION. I don't see how $id is a key of the $cart array. Thanks for any explanation to clear my confusion. Hi all. What am I doing wrong here? I cannot read from the file with fopen, this is the code. <html> <body> <?php $file=fopen("welcome.txt","r"); ?> </body> </html> I get a blank page, although I have text written in that file. Whenever I set it to "w" it still shows nothing - when I check the file manually with notepad, I see that it's blanked - but I think thats meant to happen, after all "w" clears the file. Have I understood correctly? This still shows a blank page, but it says it can't find the file if it's not in the directory - how it should be. <html> <body> <?php $file=fopen("welcome2123.txt","r") or exit("Unable to open file!"); ?> </body> </html> tl;dr - Why doesn't fopen read anything from the txt file? Encodings match - everything is in UTF-8, although I doubt thats the problem... Help? hi, I want to write pdf file but it is getting garbage value i check following url http://bugs.php.net/bug.php?id=21904&edit=1 Code: [Select] $fp = fopen($fdirandname,'wb'); fwrite($fp,$pdfcode); fclose($fp); Hi, I currently have an if, elseif, else program that starts off with Code: [Select] if( $v_name == "" || $v_msg == "" ) echo "something" how do I turn this into a switch? but the very next elseif I have Code: [Select] elseif( strcspn( $_REQUEST['msg'], '0123456789' ) == strlen( $_REQUEST['msg'] ) ) echo "something" is it possible to turn this into a switch with 2 different strings like that to evaluate? So I am tryting to create a script to upload a CSV file into a MySql DB. It has like 10K records into SQL
My Code is copy below ...
I get the following errors.
Line 16 is the $handle
line 18 is the While Statement
Error:
Warning: fopen(): Filename cannot be empty in C:\local\htdocs\ADPStorage\DemandCSV.php on line 16 Warning: fopen()expects parameter 1 to be resource, boolean given in C:\local\htdocs\ADPStorage\DemandCSV.php on line 18 I use my script for another table and it worked like a charm. Less data and less colums do. Bad Code: (good Code sample below. this one)
<?php
$today = date("m.d.y.h.m.s");
echo $today;
$BPTD_fy = '2014';
$BPTD_updatedate = $today;
$conn = mysql_connect("Localhost","root","password") or die (mysql_error());
mysql_select_db("ds_storage",$conn);
if(isset($_POST['submit']))
{
$file = $_FILES['file']['tmp_name'];
$handle = fopen($file, "r");
while(($fileop = fgetcsv($handle, 100000, ",")) !==FALSE)
{
$BPTD_fy = $fileop[0];
$BPTD_Status = $fileop[1];
$BPTD_Classification = $fileop[2];
$BPTD_ProcureCat = $fileop[3];
$BPTD_Product = $fileop[4];
$BPTD_Project = $fileop[5];
$BPTD_DSCategory = $fileop[6];
$BPTD_Calculated = $fileop[7];
$BPTD_CapacityType = $fileop[8];
$BPTD_Amount = $fileop[9];
$BPTD_Jul = $fileop[10];
$BPTD_Aug = $fileop[11];
$BPTD_Sep = $fileop[12];
$BPTD_Oct = $fileop[13];
$BPTD_Nov = $fileop[14];
$BPTD_Dec = $fileop[15];
$BPTD_Jan = $fileop[16];
$BPTD_Feb = $fileop[17];
$BPTD_Mar = $fileop[18];
$BPTD_Apr = $fileop[19];
$BPTD_May = $fileop[20];
$BPTD_Jun = $fileop[21];
$BPTD_Location = $fileop[22];
$BPTD_Env = $fileop[23];
$BPTD_Requester = $fileop[24];
$BPTD_ServiceArea = $fileop[25];
$BPTD_ServiceGroup = $fileop[26];
$BPTD_DepHead = $fileop[27];
$BPTD_Recgroup = $fileop[28];
$BPTD_RecOwner = $fileop[29];
$BPTD_Entrydate = $fileop[30];
$BPTD_updatedate = $fileop[31];
$sql = mysql_query("INSERT INTO inv_bpt_demand (Status, Classification, ProcureCat, Product, Project, DSCategory, Calculated, CapacityType, Amount, Jul, Aug, Sep, Oct, Nov, Dec,
Jan, Feb, Mar, Apr, May, Jun, Location, Env, Requester, ServiceArea, ServiceGroup, DepHead, Recgroup, RecOwner, Entrydate, updatedate)
VALUES ('$BPTD_Status', '$BPTD_Classification', '$BPTD_ProcureCat', '$BPTD_Product', '$BPTD_Project', '$BPTD_DSCategory', '$BPTD_Calculated', '$BPTD_CapacityType', '$BPTD_Amount',
'$BPTD_Jul', '$BPTD_Aug', '$BPTD_Sep', '$BPTD_Oct', '$BPTD_Nov', '$BPTD_Dec', '$BPTD_Jan', '$BPTD_Feb', '$BPTD_Mar', '$BPTD_Apr','$BPTD_May', '$BPTD_Jun','$BPTD_Location',
'$BPTD_Env','$BPTD_Requester', '$BPTD_ServiceArea', '$BPTD_ServiceGroup','$BPTD_DepHead', '$BPTD_Recgroup','$BPTD_RecOwner','$BPTD_Entrydate','$BPTD_updatedate')");
if($sql)
{
echo 'Data Uploaded Successfully';
}
}
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>BPT Demand CSV</title>
<link rel="stylesheet" type="text/css" href="file:///C|/local/htdocs/style/style.css" />
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
</head>
<body>
<div id="mainWrapper">
<form method="post" action="https://localhost/Storage/DemandCSV.php" enctype="multipart/form-data">
<input type="file" name="file" />
<br />
<input type="submit" name="submit" value="Submit" />
</form>
</div><!--end mainWrapper-->
</body>
</html>
Similar Working code (good)
<?php
$conn = mysql_connect("Localhost","root","password") or die (mysql_error());
mysql_select_db("ds_storage",$conn);
if(isset($_POST['submit']))
{
$file = $_FILES['file']['tmp_name'];
$handle = fopen($file, "r");
while(($fileop = fgetcsv($handle,1000,",")) !==FALSE)
{
$PC_Num = $fileop[0];
$PC_Name = $fileop[1];
$PC_BPTNUM = $fileop[2];
$PC_busclass = $fileop[3];
$PC_Note = $fileop[4];
$PC_Acro = $fileop[5];
$PC_type = $fileop[6];
///echo $fileop[1];
$sql = mysql_query("INSERT INTO inv_names (PC_Num, PC_Name, PC_BPTNUM, PC_busclass, PC_Note, PC_Acro, PC_type)
VALUES ('$PC_Num', '$PC_Name', '$PC_BPTNUM', '$PC_busclass', '$PC_Note', '$PC_Acro', '$PC_type')");
if($sql)
{
echo 'Data Uploaded Successfully';
}
}
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>Upload CSV</title>
<link rel="stylesheet" type="text/css" href="file:///C|/local/htdocs/style/style.css" />
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
</head>
<body>
<div id="mainWrapper">
<form method="post" action="https://localhost/Storage/Storage_CSV.php" enctype="multipart/form-data">
<input type="file" name="file" />
<br />
<input type="submit" name="submit" value="Submit" />
</form>
</div><!--end mainWrapper-->
</body>
</html>
Please help and thx in advance
~J
Quote '31.100.x.x is not allowed to connect to this MySQL server in /home/member/insert.php on line 13 I asked a question about this a few weeks ago, and someone solved it saying that the server was blocking connections. Its confusing the hell out of me. I did as they said, and contacted my admin. they told me to fork over money, and it would be solved. I am a broke student, and dont have the cash anyway. What gets me is they said I had to be a paid member to have a sql database and connect to it with scripts on the server. But I can run a phpBB3 forum. it runs sql. I know it does. WTF? I know they are just trying to get money from me, but no matter how much I try i cant figure out how the forums connect. mine is Code: [Select] $username="a162_bento"; $password="Password123"; $database="a162_siteDB"; $localhost="host.com"; mysql_connect($localhost,$user,$password) I wish could figure out how xampp worked. If someone has time to help me I would really appreciate it. Im trying really hard but getting kick every time i get on the stage. Hi I'm currently experiencing problems with my super global outputs.
I'm using
$_SERVER['HTTP_X_MXIT_NICK']; Ok so I have a single mySQL database on a dedicated server hosted through hostgator.. In this database I have 1 table that is a very large table it has well over 900,000 rows on it and we anticipate another 8.1 million records to be added within another 6 months and from there expect the table to grow regularly. Right now my issue is and can only foresee it getting worse as the size gets larger. Is that my queries are running slower and slower. Sometimes even resulting in the DB crashing. So what I am trying to figure out is how do I speed this up. I've tried 101 ways to query the DB to speed it up and can't get it to load 10 results 10.. in less than 30 seconds. I know some of my issue is the fact that I need distinct results or unique ones rather. As there are several duplicate entries but I only need to pull out one of each for this particular function which is a search. So that said is there any advice one can give me to speed up my query results. I would offer up a sample of my current queries but its just your common query using distinct. I've got my own proprietary framework. I call it Brain. It uses composer, and installation is done with a single composer file, which is handy. Here's an example:
{
"name": "skunkbad/brain-test",
"description": "My Awesome App",
"license": "proprietary",
"minimum-stability": "dev",
"repositories": [
{
"type": "hg",
"url": "ssh://hg@bitbucket.org/skunkbad/brain"
}
],
"require": {
"skunkbad/brain": "default"
},
"scripts": {
"post-install-cmd": "Brain\\Statics\\BrainInstallScript::run"
}
}
Brain has it's own dependencies, which aren't all really dependencies, but I've added them all to its composer.json file so I get everything I want for a new project. Here is it's composer.json:
{
"name": "skunkbad/brain",
"version": "1.0.0",
"type": "framework",
"license": "Proprietary",
"authors": [
{
"name": "Robert B Gottier",
"email": "xXxXxXxXx@gmail.com",
"homepage": "http://brianswebdesign.com",
"role": "Developer"
}
],
"require": {
"pimple/pimple" : "v2.0.0",
"swiftmailer/swiftmailer": "v5.2.0",
"dompdf/dompdf" : "0.6.1",
"phpseclib/phpseclib" : "0.3.6",
"stripe/stripe-php" : "v1.15.0",
"firephp/firephp-core" : "dev-master",
"doctrine/dbal" : "v2.4.2"
},
"autoload": {
"psr-4": {
"Brain\\": "/",
"App\\": "../../../App/"
},
"classmap": [
"Statics/"
]
}
}
In Windows terminal, I can run composer install or composer install --prefer-dist, and it seems that especially when the doctrine packages are being downloaded or cloned (whatever it does), its super slow. Some of them hang for so long that occasionally the terminal will give me a message indicating a particular package timed out (5 mins).
So I was wondering if this is just the norm. Feels like I'm on dial-up, but my internet connection is Verizon FiOS (fiber optic). Here is an example of the time-out message I get from Composer:
Failed to download doctrine/common from source: The process "git clone --no-checkout "git://github.com/doctrine/common.git" "C:\XXXxxx" && cd /D "C:\XXXxxx" && git remote add composer "git://github.com/doctrine/common.git" && git fetch composer" exceeded the timeout of 300 seconds.
I timed my install, and composer/common actually hung for about 7 mins. Total time was 9.5 mins.
Hi guys, I am trying out this code but it does not work, any idea what I am doing wrong? <?php include 'connect.php'; $tbl_name="users"; $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); $count=mysql_num_rows($result); ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <td><form name="form1" method="post" action=""> <table width="400" border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td bgcolor="#FFFFFF"> </td> <td colspan="4" bgcolor="#FFFFFF"><strong>Delete multiple rows in mysql</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF">#</td> <td align="center" bgcolor="#FFFFFF"><strong>Id</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Firstname</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Lastname</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Location</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Email</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Website</strong></td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td align="center" bgcolor="#FFFFFF"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<? echo $rows['id']; ?>"></td> <td bgcolor="#FFFFFF"><? echo $rows['userID']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['firstname']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['lastname']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['location']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['email']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['website']; ?></td> </tr> <?php } ?> <tr> <td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete" value="Delete"></td> </tr> <? if($delete){ for($i=0;$i<$count;$i++){ $del_id = $checkbox[$i]; $sql = "DELETE FROM $tbl_name WHERE id='$del_id'"; $result = mysql_query($sql); } if($result){ echo "<meta http-equiv=\"refresh\" content=\"0;URL=showusers2.php\">"; } } mysql_close(); ?> </table> </form> </td> </tr> </table> I've seen this, Code: [Select] <?php } ?> in a lot of scripts at the very end of the script. What does this piece of code do? Hi,
I am trying to convert a php function into perl and need to understand the following line in red :
function pagination($query, $per_page = 10,$page = 1, $url = '?'){ $query = "SELECT COUNT(*) as `num` FROM {$query}"; $row = mysql_fetch_array(mysql_query($query)); $total = $row['num']; $adjacents = "2"; $page = ($page == 0 ? 1 : $page); $start = ($page - 1) * $per_page; $prev = $page - 1; $next = $page + 1; $lastpage = ceil($total/$per_page); $lpm1 = $lastpage - 1; $pagination = ""; if($lastpage > 1) { ......................................... What will be the output of this line above in red. Thank you very much. Regards. Tonya Hi guys, this function below is for card validation, however anycard i enter i get the invalid card number, this is not connected to any gateways, this is just an Luhn card validation demonstration. can you tell me please why i get that? <?php if ($_POST['pay']) { $cardNo = addslashes(strip_tags($_POST['cardNo'])); function luhnCheck($cardNo) { $cardNo = str_replace(" ", "", trim($cardNo)); if(!is_numeric($cardNo) or strlen($cardNo)>19) return false; $skip = $newNum = $total = 0; for($i=0;$i<=(strlen($cardNo)-1);$i++) { if($skip ==0) { $tmpNum = ($cardNo[$i]*2); $total += (strlen($tmpNum)==2 ? (substr($tmpNum, 0, 1)+substr($tmpNum, 1)) : $tmpNum); $skip = 1; }else{ $total += $cardNo[$i]; $skip = 0; } } return (($total % 10) == 0); } /* Example Usage */ if(luhnCheck($_GET['cc'])) { echo("Valid Number."); }else{ echo("Invalid Number."); } } ?> <form name="confirm" method="post" action=""> <input type="text" name="cardNo"> <input type="submit" name="pay" value="Pay Now"> </form> I know it could be a issue with this line if(luhnCheck($_GET['cc'])) { but im wondering where should and how put this cc in my form? regards I'm teaching myself php and mysql -- and my coding is a little rough. But what i'm trying to do is display information from a mysql table in another table on a website. I can do this just fine simply displaying the table, but i want a little something different. I am only displaying one column of the table, instead of displaying it all in one column, i want to display the information in 5 columns. for example..... the table from mysql has names scott, john, james, mary, simon. with the code I have i can make it display like this: scott scott scott scott scott john john john john john james james james james james mary mary mary mary mary simon simon simon simon simon i want it to diplay like this: scott john james mary simon new names will continue down here is my code: <?php require ("connectigb.php"); $result = mysql_query ("SELECT pledgeName FROM pledgewall"); $fields_num = mysql_num_fields($result); echo "<center> <h1>TSA It Gets Better Pledge Wall</h1>"; echo "<table border='1' align='center' style='width:960px;'><tr>"; while($row = mysql_fetch_row($result)) { echo "<tr>"; // $row is array... foreach( .. ) puts every element // of $row to $cell variable foreach($row as $cell) if ($cell != "") { for ($j=0; $j<5; $j++) { echo "<td>$cell</td>"; } } echo "</tr>\n"; } mysql_free_result($result); echo "</table></center>"; ?> any ideas on what i can do here, i'm sure this is a simply fix. i just haven't come across it yet. thanks for the help in advance. Hello there fellow programmers, I was just wondering if there was any difference between doing this: Code: [Select] echo "Say Something Here"; and this Code: [Select] echo "Say "; echo "Something "; echo "Here"; Thank you in advance. Notice: I am aware of the fact that they will output the same thing, my question is regarding resources. Hey! I have a drop down field for my "register" form, but this is clearly easy to edit, I just used tamperdata for firefox and yeah...pretty easy, is there any way that you could prevent tampering with the values when submitting this form!? Hi. I have an ID in md5 format but in the database its not. I pass the md5 ID to a page and then I am trying to load the correct record via a look up in the database of that ID. Im wondering is this code possible? <?php $query = mysql_query("SELECT * FROM table WHERE ".md5(tableID)." = $ID"); ?> Thanks Hello everyone! I am a new user and I have a simple question. How do I set a password for a user to log in to my site with PHP? I have no MySQL database just a iOS code/host app. I know this isn’t secure but only me and my friends are on the site. Any help is appreciated. Hello to everyone I would like to ask for this simple question.. Im trying to put if and else condition on my php code. However this condition is not working.. Code: [Select] if($file == #3#){ echo "No results found"; }else{ echo "results has been found"; } This variable $file is the result after i used an API.. If the API does not see any results they would return #3# as the result. This means they returned a transaction code of 3 which you can see here http://developer.textapp.net/WebService/TransactionCodes.aspx means that there was nothing to return. The condition does not function well even if i make 3 or #3# as part of the condition. Can you help me guys? thanks |
|||||||