PHP - Rounding Up Or Down Based On Decimal

So I just started working with php (not programming) a couple days ago. In this formula, I need to round something down to the nearest 5 OR 0. Whatever comes first. Any thoughts on how i might do this?

Here's what I have so far.
<?php
$magicLevel = $_POST['magicLevel'];
$playerLevel = $_POST['playerLevel'];
$rune = $_POST['rune']; //gets the value "lmm"
$maxDamage = 0;

switch($rune) {
case "lmm":
$maxDamage = ($playerLevel*0.2)+($magicLevel*0.81)+4;
break;
}


echo $maxDamage;

?>

What I need to round down is this part: ($playerLevel*0.2)

Thanks in advance!

How can I round this with 2 decimals:

Code: [Select]
echo " $row[team_treasure] ";
I've tried round($row[team_treasure],2) but doesn't seem to work inside my echo tags :/

hi there all,

I need some help for rounding currency issue..

example:

0.98 round to 0.95
0.95 when round = 0.95
0.91 roun to 0.95.

mean.
i wanna round the end of number 0.98.
if the end of number is 0.01,0.02,0.03&0.04 it would be automatic round to nearest 0.05
*0.01 round = 0.05
*if the mineral water =$0.71 i should get $0.75

and if the end of number is 0.06,0.07,0.08,0.09 it would automatic round to nearest -0.05
*0.06 round = 0.05
*if the mineral water = $0.79 then i should get $0.75

i had googling this for 2months and no answer.. 
please help me.TQ

I am trying to take a number (three for example) and want to round it to five, or sixty-seven up to seventy.  I looked at round and ceil, but those don't seem like they are the right things.

Thanks,
Joseph

I am very new to PHP and programming in general. About 3 weeks into this.
I have this simple expression and some echo in my code.

    $x1 = $lat_b + $lat_a1;
    echo "<br>lat b: ".$lat_b;
    echo "<br>lat a1: ".$lat_a1;   
    echo "<br>x1: ".$x1;

$lat_b and $lat_a1 are derived from some xml extractions from a yahoo geocode api (that part works fine).

The results of the expression and echos above are as follows:

    lat b: 40.402866
    lat a1: 40.252590
    x1: 80

Why is $x1 rounding automatically on me?

Later, I substituted the expression above with  $x1 = 40.402866 + 40.252590 ; The new result (shown below) makes sense to me.

   lat b: 40.402866
   lat a1: 40.252590
   x1: 80.655456

Here is the number:



$GrandTotal = "68.835";
$Deposit = round($GrandTotal , 2) * .5;

echo $Deposit;



I am looking for: 68.84 but the function doesn't seem to work right.

Any help?

Hi,

Having trouble rounding the output. I would need to be sure the output is not longer than 2 spaces after comma.
Any ideas?

My code
Code: [Select]
<script type="text/javascript">
$(document).ready(function() {
  $("<?php echo "#".$input_end_time; ?>").blur(function(){
   var start_time = $("<?php echo "#".$input_start_time; ?>").val();
   var end_time = $("<?php echo "#".$input_end_time; ?>").val();
  $.getJSON("include/timedifferencecalculation.php?s="+start_time+"&e="+end_time, function(data){
   var success = data.success;
    if (success == 1) {
     $("<?php echo "#".$input_difference; ?>" ).val(data.hours + " h " + data.minutes + " m ");
  if (data.hours + data.minutes/60 >= 6){
$("<?php echo "#".$hours_difference; ?>").val(data.hours + data.minutes/60 - 0.5);
}else { $("<?php echo "#".$hours_difference; ?>").val(data.hours + data.minutes/60); }
  }else { $("#message").text("Viga! " + data.reason); }
    })
    });
  });
</script>

Code: [Select]
This is before
$("<?php echo "#".$hours_difference; ?>").val(data.hours + data.minutes/60 - 0.5);

This is what im trying to get but its not working.
$("<?php echo "#".$hours_difference; ?>").val( round(data.hours + data.minutes/60 - 0.5), 2 );

Hi fellas,

Can anyone show me why my script is still rounding up / down?

printf ("<tr> %s Avg gun Ahit %%</td> %s %.2f %%</td></tr>\n",$tdo,$tdor,number_format($ahit/$fired*100, 3, '.', ''));

Do I have a syntax error as I cannot get my math equation to display more than 2 decimal places even though it's set to 3?

Any help or advice would be really great.

Hey Everybody,

I was replying to someone elses question about number formatting and came up with a class that will format a number of any length with decimal or not, without rounding. It works perfectly, but after a comment by a noteworthy member my curiosity was aroused.

Is there an easier/faster/better way to achieve this??


My Object:

<?php

/*GHETTO NUMBER FORMATTER v1.0*/

class ghettoNumber {

private $input;
private $output;

public $whole;
public $decimal;
public $number;

function __construct($input){
$this->input = $input;
$this->output = $output;
$this->number = $number;
$this->whole = $whole;
$this->decimal = $decimal;
}

private function ghettoFormat(){

//Split number at the .(decimal)
$this->number = explode('.', $this->input);
//Define the whole number
$this->whole = $this->number[0];
//Format the whole number
$this->whole = number_format($this->whole, 0,'', ',');
//Define the decimal
$this->decimal = $this->number[1];
//Format the decimal
$this->decimal = rtrim($this->decimal, '0');

if(is_string($this->input)){
$this->output = $this->decimal != '' ? $this->whole.'.'.$this->decimal : $this->whole;
}
else{
$this->output = '<strong>ERROR:</strong> Input arg must be passed as type: <em>string</em>';
}

//Return result
return 'Original - '.$this->input.'<br>
  GhettoFormat - '.$this->output.'
<br><br>';

}

public function makeItGhetto(){
return $this->ghettoFormat();
}
}

?>


Sample Instantiation:

$ghettoFormat = new ghettoNumber('12565456565.123401201001210000');
                print $ghettoFormat->makeItGhetto();



I will reiterate my question once more...
Is there, in your opinion, a BETTER way to achieve this (number formatting w/o rounding)?

Thanks People,

E

$f15 = 0.345677 (output from sql data pull)

<?php echo number_format ($f15,3); ?>
 output = 0.345

<?php echo ltrim($f15,"0"); number_format ($f15,3); ?>
output = .345677

How do I combine these so that I am BOTH rounding the result AND trimming a leading zero?  Seems I can get one or the other, but not both.

Suggestions on the syntax?

HI. I have written a mysql database query to add up invoice totals. It seems to be automatilaly adding .01 to the result when I run a group by. Let me explain more ..   When I do a select on the field that I am adding up the result is $132.25 - the query is as follows select ttl_invoice_due from 65_it where st_id = 96011;   When I run the following query that uses sum and group by - the $132.25 becomes $132.26 - the sum query is   SELECT 65_st.job_compid, 65_client.uid_client,  65_client.comp_name, Sum(65_it.ttl_invoice_due) AS SumOftotal_due, Sum(65_it.ttl_invoice) AS SumOftotal_invoice, Sum(65_it.ttl_invoice_payments) AS SumOftotal_amnt_paid FROM 65_client INNER JOIN (65_st INNER JOIN 65_it ON 65_st.st_id = 65_it.st_id) ON 65_client.uid_client = 65_st.uid_client WHERE   65_st.uid_client = 1905 and 65_st.job_compid = 1 and 65_st.sales_date<=curdate() GROUP BY 65_st.job_compid, 65_client.uid_client HAVING (((Sum(65_it.ttl_invoice_due))<>0)) order by 65_client.comp_name;   The 65_it.ttl_invoice_due field is defined in the table as Double(12,2)   I dont know why the sum is returing $132.26 where it should be $132.25 as in the simple query ?.    

       

Hi there,

I have a database with table column called EXPAMOUNT

if EXPAMOUNT value was £5.50
it only displays £5.5. when i echo it. How do i get it to display 2 decimal places. So £5.50

My code at moment

echo “Total Expenses &nbsp &pound” . $row[‘SUM(EXPAMOUNT)’]. “

Hi, I'm trying to force 2 decimal places with the following function but it 's not working.  Any suggestions? 

Code: [Select]
function ShippingCost() {
$shippingCost = 4.00;
    number_format($shippingCost,2);
return $shippingCost;
}

Hi I need to convert hex or Decimal to Binary but can't find any function. Any one have one or ideas please.

I'm making a connection to Active Directory using ADODB connection. I can read almost everything from this but some outputs are in an Octet format.
For example objectSID is giving me only a ?.
Is there somebody that knows how to read or convert this?

I've found a converter function in ASP maybe someone can translate this to PHP?

Code: [Select]
TXT_ObjectGUID = HexStrToDecStr(OctetToHexStr(objRecordSet.fields("objectSID")))

Function OctetToHexStr(arrbytOctet)
' Function to convert OctetString (byte array) to Hex string.
Dim k
OctetToHexStr = ""
For k = 1 To Lenb(arrbytOctet)
OctetToHexStr = OctetToHexStr _
& Right("0" & Hex(Ascb(Midb(arrbytOctet, k, 1))), 2)
Next
End Function

Function HexStrToDecStr(strSid)
' Function to convert hex Sid to decimal (SDDL) Sid.
Dim arrbytSid, lngTemp, j

ReDim arrbytSid(Len(strSid)/2 - 1)
For j = 0 To UBound(arrbytSid)
arrbytSid(j) = CInt("&H" & Mid(strSid, 2*j + 1, 2))
Next

HexStrToDecStr = "S-" & arrbytSid(0) & "-" _
& arrbytSid(1) & "-" & arrbytSid(8)

lngTemp = arrbytSid(15)
lngTemp = lngTemp * 256 + arrbytSid(14)
lngTemp = lngTemp * 256 + arrbytSid(13)
lngTemp = lngTemp * 256 + arrbytSid(12)

HexStrToDecStr = HexStrToDecStr & "-" & CStr(lngTemp)

lngTemp = arrbytSid(19)
lngTemp = lngTemp * 256 + arrbytSid(18)
lngTemp = lngTemp * 256 + arrbytSid(17)
lngTemp = lngTemp * 256 + arrbytSid(16)

HexStrToDecStr = HexStrToDecStr & "-" & CStr(lngTemp)

lngTemp = arrbytSid(23)
lngTemp = lngTemp * 256 + arrbytSid(22)
lngTemp = lngTemp * 256 + arrbytSid(21)
lngTemp = lngTemp * 256 + arrbytSid(20)

HexStrToDecStr = HexStrToDecStr & "-" & CStr(lngTemp)

lngTemp = arrbytSid(25)
lngTemp = lngTemp * 256 + arrbytSid(24)

HexStrToDecStr = HexStrToDecStr & "-" & CStr(lngTemp)

End Function