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PHP - Adding An If Statement To A Query
So I have this snippet of code:
Code: [Select] $row['ratings'] = ""; $ratingsSQL = $this->ipsclass->DB->query( "SELECT `pid` , `rating` , COUNT(`rating`) as ratings FROM `ibf_ratings` WHERE `pid` = '" . $row['pid'] . "' GROUP BY `rating` "); $i = 0; $ratingshtml = ""; if( $this->ipsclass->DB->get_num_rows( $ratingsSQL ) ) { while( $rrow = $this->ipsclass->DB->fetch_row( $ratingsSQL ) ) { $ratingshtml .= "<div class=\"rate_it_display\" style=\"background-image: url( 'style_images/rate/" . str_replace( ' ' , '' , strtolower( $this->ratings[$rrow['rating']] ) ) . ".png' ) \"> " . $rrow['ratings']. " x " . $this->ratings[$rrow['rating']] . "!</div>"; $i++; } $ratingshtml .= "<a href=\"#\" onclick=\"return RateItExpand( {$row['pid']} );\" style=\"color: #999;\">(list)</a>"; } $row['ratings'] = $this->ipsclass->compiled_templates['skin_topic']->ratings( $row['pid'] , $row['author_id'] , $ratingshtml ); I want to add an if statement to the code so that the ratings won't load unless a user clicks a button at the top of the screen. Can anyone help me with this? I'd be very appreciative. Thanks in advance. Similar TutorialsThis topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=315503.0 Hi, My issue here is that I cant get my query string variables to ONLY feed into if/else statement on my secondary page. I include my secondary page (fine.php) from my index page. My query string variables keep being fed back into my original if/ese statement on index.php. here is the if/else on index.php (these links work fine): <?php if($_SERVER['QUERY_STRING']=='/index.php' || $_SERVER['QUERY_STRING']=='') { include 'port.php'; } elseif (isset($_GET['pos'])){ include 'pos.php'; } elseif (isset($_GET['web'])){ include 'web.php'; } elseif (isset($_GET['fine'])){ include 'fine.php'; } else {include '404.php';} here is the if/else on my secondary page (fine.php). These links are supposed to alert the if/else in the next table cell. However, they instead alert the if/else in index.php. <td><br/> <a href="?backset"><img src="fine/thumbs/x-backset.jpg" border="0"></a><br/><br/> <a href="?backside"><img src="fine/thumbs/x-backside.jpg" border="0"></a><br/><br/> <a href="?bannerprint"><img src="fine/thumbs/x-bannerprint.jpg" border="0"></a><br/><br/> <a href="?chopu"><img src="fine/thumbs/x-chopu.jpg" border="0"></a><br/><br/> </td> <td><br/> <div id="DivPiece" align="left"> <?PHP if (isset($_GET['backset'])){ include 'fine/backset.php'; } elseif (isset($_GET['backside'])){ include 'fine/backside.php'; } elseif (isset($_GET['bannerprint'])){ include 'fine/bannerprint.php'; } elseif (isset($_GET['chopu'])){ include 'fine/chopu.php'; } ?> </div> </td> How can I get the links on the secondary page to only alert the if/else statement on that page, and BLOCK the if/else statement on index.php from seeing them? I still want to use the query string though. Thanks! [/quote] I am just wanting to know what the other forms of this type of conditonal would be, the type of if statement is as follows: if ($_POST) {print_r($_POST);} Just seen it a few times now, I know this means if $_POST exists. use the print_r() function to display the entire post array suber global variable. But what are the other combinations other than just if true? Like how are they used like this, like if I wanted to see if a random variable is not identical to another etc. Any helps appreciated, Jez. Hi and thank you for reading my topic.
I'm building a search engine from a tutorial and I'm getting the famous "Warning: mysql_num_rows() expects parameter 1" boolean etc..
I know mysql_num_rows() is depricated and I promise not to use it in the future but for now I'm using it in other projects on the same server and all's ok.
I'm quite sure it's a problem with the SQL syntax because when I paste SELECT * FROM searchengine WHERE keywords LIKE 'any_keyword_from_the_column' -into Phpmyadmin it won't return results, however a simple SELECT * FROM searchengine returns results.
So, without using mysql_error() I get: Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\research2\search.php on line 42
But after I applyin mysql_error() to everything I narrowed it down to this: $query = mysql_query($query) or die (mysql_error());:
I get the error msg:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'OR keywords LIKE 'search' OR keywords LIKE 'term'' at line 1
I've checked multiple times to see if I've left out any columns in the db or mismatched them in while loop.
Below I have included the code which you can paste into a file called search.php along with the mysql dump file to pase into phpmyadmin query box. I'm using xampp.
In the code the WHERE clause is extended into the if statement and concatenated into the $query variable. This is done to break the words in the text box so they can be searched as an array.
As I said, I really think it is the SQL syntax and not the mysql_* functions but I could be wrong.
I'd really like to get this code working and mess with it. It looks like it could be very useful as a private website search engine.
Thanks for your time and mental energy.
<html>
<head>
<title></title>
<meta http-equiv="content-type" content="text/html;charset=utf-8" />
</head>
<body>
<h2>Search Engine</h2>
<form action = './search.php ' method = 'get'>
<input type = 'text' name = 'k' size = '50' value = '<?php echo $_GET['k']; ?>' />
<input type = 'submit' value = 'Search'>
</form>
<hr />
results <br>
<?php
$k = $_GET['k'];
$terms = explode(" ", $k);
$query = "SELECT * FROM searchengine WHERE ";
foreach ($terms as $each) {
$i = 0;
if ($i == 1)
$query .= "keywords LIKE '$each' ";
else
$query .= "OR keywords LIKE '$each' ";
}
mysql_connect("localhost", "root", "") or die (mysql_error());
mysql_select_db("search2") or die (mysql_error());
$query = mysql_query($query) or die (mysql_error());
$numrows = mysql_num_rows($query) ;
if ($numrows > 0) {
while ($row = mysql_fetch_assoc($query)) {
$id = $row['id'];
$title = $row['title'];
$description = $row['description'];
$keywords = $row['keywords'];
$link = $row['link'];
echo "<h2><a href='$link'>$title</a></h2>
$description<br /><br />";
}
}
else
echo $k ;
?>
</body>
</html>
and here is the SQL dump (I called my db search2 and my table searchengine
-- phpMyAdmin SQL Dump -- version 4.2.7.1 -- http://www.phpmyadmin.net -- -- Host: 127.0.0.1 -- Generation Time: Nov 27, 2014 at 11:54 AM -- Server version: 5.6.20 -- PHP Version: 5.5.15 SET SQL_MODE = "NO_AUTO_VALUE_ON_ZERO"; SET time_zone = "+00:00"; /*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */; /*!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS */; /*!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION */; /*!40101 SET NAMES utf8 */; -- -- Database: `search2` -- CREATE DATABASE IF NOT EXISTS `search2` DEFAULT CHARACTER SET latin1 COLLATE latin1_swedish_ci; USE `search2`; -- -------------------------------------------------------- -- -- Table structure for table `searchengine` -- CREATE TABLE IF NOT EXISTS `searchengine` ( `id` int(11) NOT NULL, `title` varchar(250) NOT NULL, `description` varchar(250) NOT NULL, `keywords` text NOT NULL, `link` varchar(250) NOT NULL ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=5 ; -- -- Dumping data for table `searchengine` -- INSERT INTO `searchengine` (`id`, `title`, `description`, `keywords`, `link`) VALUES (1, 'Nick Frosty''s Official Web Site', 'Welcome to Nick''s', 'Nickfrosty Website tutorials videos web design', 'http://www.nickfrosty.com'), (2, 'Google search engine', 'The best search engine', 'google web site search ', 'http://www.google.oom'), (3, 'The Yahoo Search Engine', 'Not as good as Google', 'Yahoo search engine website', 'http://www.google.com'), (4, 'This is a test', 'This is a test website', 'Google', 'http://www.google.com'); -- -- Indexes for dumped tables -- -- -- Indexes for table `searchengine` -- ALTER TABLE `searchengine` ADD PRIMARY KEY (`id`); -- -- AUTO_INCREMENT for dumped tables -- -- -- AUTO_INCREMENT for table `searchengine` -- ALTER TABLE `searchengine` MODIFY `id` int(11) NOT NULL AUTO_INCREMENT,AUTO_INCREMENT=5; /*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */; /*!40101 SET CHARACTER_SET_RESULTS=@OLD_CHARACTER_SET_RESULTS */; /*!40101 SET COLLATION_CONNECTION=@OLD_COLLATION_CONNECTION */;If you have any questions about any details of this code please ask me. Thanks for your time I need to convert the following select statement to a pdo->query but have no idea how to get it working: SELECT t.id FROM ( SELECT g.* FROM location AS g WHERE g.start <= 16785408 ORDER BY g.start DESC, g.end DESC LIMIT 1 ) AS t WHERE t.end >= 16785408; Here's the code I'm trying:
<?php
$php_scripts = '../../php/';
require $php_scripts . 'PDO_Connection_Select.php';
require $php_scripts . 'GetUserIpAddr.php';
function mydloader($l_filename=NULL)
{
$ip = GetUserIpAddr();
if (!$pdo = PDOConnect("foxclone_data"))
{
exit;
}
if( isset( $l_filename ) ) {
$ext = pathinfo($l_filename, PATHINFO_EXTENSION);
$stmt = $pdo->prepare("INSERT INTO download (address, filename,ip_address) VALUES (?, ?, inet_aton('$ip'))");
$stmt->execute([$ip, $ext]) ;
$test = $pdo->prepare("SELECT t.id FROM ( SELECT g.id FROM lookup AS g WHERE g.start <= inet_aton($ip) ORDER BY g.start DESC, g.end DESC ) AS t WHERE t.end >=inet_aton($ip)");
$test ->execute() ;
$ref = $test->fetchColumn();
$ref = intval($ref);
$stmt = $pdo->prepare("UPDATE download SET ref = '$ref' WHERE address = '$ip'");
$stmt->execute() ;
header('Content-Type: octet-stream');
header("Content-Disposition: attachment; filename={$l_filename}");
header('Pragma: no-cache');
header('Expires: 0');
readfile($l_filename);
}
else {
echo "isset failed";
}
}
mydloader($_GET["f"]);
exit;
It gives the following error: QuoteFatal error: Uncaught PDOException: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '.144.181) ORDER BY g.start DESC, g.end DESC ) AS t WHERE t.end >=inet_aton(7' at line 1 in /home/foxclone/test.foxclone.com/download/mydloader.php:19 Stack trace: #0 /home/foxclone/test.foxclone.com/download/mydloader.php(19): PDO->prepare('SELECT t.id FRO...') #1 /home/foxclone/test.foxclone.com/download/mydloader.php(38): mydloader('foxclone40a_amd...') #2 {main} thrown in /home/foxclone/test.foxclone.com/download/mydloader.php on line 19 How do I fix this? This isn't the entire code just enough to see what I'm trying to do. Everything was working until I added the mysql update query in the if statement. Is this possible or am I doing something wrong? When I run the script it just echos "No results found" twice as $num_results = 2. Code: [Select] <?php include("../includes/connect.php"); $query = "SELECT ........ "; $result = $db->query($query); $num_results = $result->num_rows; if ($num_results == 0) { exit; } else { $i=0; while ($i < $num_results) { $row = $result->fetch_assoc(); $id = $row['id']; if ($expiration_date > $today) { ### EMAIL CODE HERE ### $update = "UPDATE model SET reminder_sent = '1' WHERE id = '$id' "; $result_2 = $db->query($update); $i++; } else { echo "No results found."; $i++; } } } ?> Hi, This is probably very easy for someone who knows how but I cant seem to get it working. Can someone please tell me how I can alter this query to select a 'WHERE gender = female' so instead of picking a random user it picks a random female user ? Code: [Select] $offset_result = mysql_query( " SELECT FLOOR(RAND() * COUNT(*)) AS `offset` FROM `users` "); $offset_row = mysql_fetch_object( $offset_result ); $offset = $offset_row->offset; $user1b = mysql_query( " SELECT * FROM `users` LIMIT $offset, 1 " ); $user1= mysql_fetch_array($user1b); Also, would it be easy to modify it so it picks a second random user that isnt the same as the first user ? so I end up with 2 random females ( $user1 and $user2 ) Many thanks, Scott I'm trying to create a INSERT query statement that makes use of the content of 'include' files. When I call up the include it simply echos it to the screen but I can't seem to capture the text string and actually make it function as part of the query. I've tried setting the include as a variable but again it only outputs to the screen. Help please! Here's a portion of the code... if (($_POST['sched_templates']) == "sched_TestingOnly.htm") { $query = include 'sched_TestingOnlyQuery1.htm'; } if (@mysql_query ($query)) { mysql_close(); // End adding Registration to the database header ('Location: redirectfile.htm'); exit(); } else { print "<p><b>Sorry, your entry could not be entered. } Hey, I was wondering if there is a way to pull multiple rows at once using a list of unique identifiers. For example, I want to pull the rows with the IDs of 4,13,91 and 252 I know the WHERE part of this query is incorrect, but I'm putting it to hopefully help you guys understand what I'm looking for. $result = mysql_query("SELECT * FROM $table WHERE id='4' OR '13' OR '91' OR '252'"); while($row = mysql_fetch_array($result)) { echo($row['name']); } Or is the best way simply to do it one query at a time without a while statement? There could be as many as a few dozen records being pulled per page. Greetings, I need a bit of php coding help. I have a query that gives me results. What I need to do is take those results and, I think, use php to compare the results and add a 1 to the correct section. Example: 3 tables table name- retail_sales id sales_id amount week table name- online_sales id sales_id amount week table name- sales_person sales_id name I have the query that breaks down results by week: week 1 | retail_sales.amount | online_sales.amount What I need is some php code that will then compare the two together and: if retail_sales.amount > online_sales.amount +1 to retail OR if retail_sales.amount < online_sales.amount +1 to online so you would end up with a result like a sports record (6-2) Any ideas Thank you for any help If ($_GET['CODE'] == '1') { $ThreadID = mysql_escape_string($_GET['threadid']); $ForumID = mysql_result(mysql_query("SELECT forum_id FROM ".FORUM_THREADS." WHERE thread_id='{$ThreadID}'", $db), 0, 'forum_id'); $PostText = mysql_escape_string($_POST['replytext']); $IP = $_SERVER['REMOTE_ADDR']; $PostQuery = "INSERT INTO ".FORUM_POSTS." (`user_id`, `thread_id`, `post_text`, `forum_id`, `ip_address`, `timestamp`) VALUES ('{$memid}', '{$ThreadID}', '{$PostText}', '{$ForumID}', '{$IP}' , CURRENT_TIMESTAMP)"; $PostRes = mysql_query($PostQuery, $db); For some reason whenever this query goes through, it also adds a blank result using all the same information but without any $PostTest so essentially it does query: Code: [Select] INSERT INTO ".FORUM_POSTS." (`user_id`, `thread_id`, `post_text`, `forum_id`, `ip_address`, `timestamp`) VALUES ('{$memid}', '{$ThreadID}', '', '{$ForumID}', '{$IP}' , CURRENT_TIMESTAMP) This is the only query that does this part of the code and I can't see why it is adding 2 queries. FORUM_POSTS = constant containing table name. I need to add likes_username to this query and use a DISTINCT on it.
It currently counts how many likes a status has but in the table there are some statuses with multiple likes from the same username.
SELECT s.*, COUNT(l.likes_location_id) AS likeCount FROM stream AS s LEFT JOIN likes AS l ON ( l.likes_location_id = s.stream_id ) GROUP BY s.stream_id ORDER BY s.stream_id DESC LIMIT 50Many thanks, Is it possible to add a query string for example some_var=jk84 to any sort of link be it, http://www.website.com , http://www.website.com/?some_id=4, or http://www.website.com/post=45&category=9 or http://www.website.com/somepost/ ? While adding that extra query string how can I make sure I'm not affecting the website's content or causing some script error? Hello, The query below works well. It pulls information from 3 MySQL tables: login, submission, and comment. It creates a value called totalScore2 based on calculation of values pulled from these three tables. The MySQL tables "comment" and "submission" both have the following fields: Code: [Select] loginid submissionid In the table "submission," each "submissionid" has only one entry/row, and thus only one "loginid" associated with it. In the table "comment," the field "submissionid" could have several entries/rows, and could be associated with multiple "loginid"s. Each time one of the "submissionid"s in "comment" is associated with the same "loginid" that it has in the table "submission," I would like to add this as a factor to the equation below. I would like to multiple instances like this times (-10). How could I do this? Thanks in advance, John $sqlStr2 = "SELECT l.loginid, l.username, l.created, DATEDIFF(NOW(), l.created) + COALESCE(s.total, 0) * 5 + COALESCE(scs.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore2 FROM login l LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM submission GROUP BY loginid ) s ON l.loginid = s.loginid LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM comment GROUP BY loginid ) c ON l.loginid = c.loginid LEFT JOIN ( SELECT S2.loginid, COUNT(1) AS total FROM submission S2 INNER JOIN comment C2 ON C2.submissionid = S2.submissionid GROUP BY S2.loginid ) scs ON scs.loginid = l.loginid GROUP BY l.loginid ORDER BY totalScore2 DESC LIMIT 25"; mysql_query("update pupils set record='running' where pid !='$testing[0]' Say I do a query from a database that only asks for one field in return (which always has a number in it). How do you write the PHP to take the first number returned and add it to the next number returned (NOTE: There may be more than two numbers returned, but for now, I'm always dealing with two) For example, say I do a query that returns the number 27 first and then the number 10 second. FYI, these numbers will be available in the variable $diff['result']. So the code after the query would look something like this, but obviously i'm struggling with the part in comments... Code: [Select] if (!$numbers) { die("Database query failed: " . mysql_error()); } else { while ($diff = mysql_fetch_array($numbers)) { //this would bring back 27 first, in the variable $diff['result'] and then on the 2nd loop through, it would bring back 10 in the $diff['result'] variable //ultimately, i just want the difference between the numbers (which in the case would be 17). It's just a simple addition, so Im obviously an idiot because I can't figure out the syntax for adding the first returned number to the next returned number:) } } HI. I have written a mysql database query to add up invoice totals. It seems to be automatilaly adding .01 to the result when I run a group by. Let me explain more ..
When I do a select on the field that I am adding up the result is $132.25 - the query is as follows
select ttl_invoice_due from 65_it where st_id = 96011;
When I run the following query that uses sum and group by - the $132.25 becomes $132.26 - the sum query is
SELECT 65_st.job_compid, 65_client.uid_client, 65_client.comp_name, Sum(65_it.ttl_invoice_due) AS SumOftotal_due, Sum(65_it.ttl_invoice) AS SumOftotal_invoice, Sum(65_it.ttl_invoice_payments) AS SumOftotal_amnt_paid FROM 65_client INNER JOIN (65_st INNER JOIN 65_it ON 65_st.st_id = 65_it.st_id) ON 65_client.uid_client = 65_st.uid_client WHERE 65_st.uid_client = 1905 and 65_st.job_compid = 1 and 65_st.sales_date<=curdate() GROUP BY 65_st.job_compid, 65_client.uid_client HAVING (((Sum(65_it.ttl_invoice_due))<>0)) order by 65_client.comp_name;
The 65_it.ttl_invoice_due field is defined in the table as Double(12,2)
I dont know why the sum is returing $132.26 where it should be $132.25 as in the simple query ?.
So I'm querying my database to add the results (mapID's) into a PHP array. The MySQL query I used in the below code would usually return 10 values (only 10 mapID's in the database) Code: [Select] while($data = mysql_fetch_array(mysql_query("SELECT mapID FROM maps"))){ $sqlsearchdata[] = $data['mapID']; } Instead the page takes ages to load then gives this error: Quote Fatal error: Allowed memory size of 8388608 bytes exhausted (tried to allocate 16 bytes) It says the error begins on the first line of the above code. I'm assuming this is not the right way to add the value from the MySQL array into a normal PHP array. Can anyone help me? I'm having issues with the following: Code: [Select] <?php session_start(); $_SESSION['username']=$_POST['username']; $_SESSION['password']=$_POST['password']; if($_SESSION['username']=="username" && $_SESSION['password']=="password"){ if($_GET['product']=="add"){ $content.=' <p><label>Product Name:</label> <input type="text" name="product_name" size="30" /> <label>Product Price:</label> <input type="text" name="product_price" size="5" /> </p> <p><label>Product Category:</label> <input type="text" name="product_category" size="30" /></p> <p><label>Product Link:</label> <input type="text" name="product_link" size="30" /></p> <p><label>Product Image:</label> <input type="text" name="product_image" size="30" /></p> <p><label>Product Tag:</label> <input type="text" name="product_tag" size="30" /></p> <p><label>Product Keywords:</label> <input type="text" name="keyword" size="30" /></p> <p><label>Product Features:</label><br /> <textarea name="product_features" rows="10" cols="60"></textarea> </p> <p><label>Product Pros:</label><br /> <textarea name="product_pros" rows="5" cols="30"></textarea> </p> <p><label>Product Cons:</label><br /> <textarea name="product_cons" rows="5" cols="30"></textarea> </p> <p><label>Product Description:</label><br /> <textarea name="product_description" rows="10" cols="60"></textarea> </p> <p><label>Product Notes:</label><br /> <textarea name="product_notes" rows="5" cols="30"></textarea> </p> '; $logout='<div><a href="./acp_admincp.php?log-out">Log-Out</a></div>'; } elseif($_GET['product']=="view"){ } else{ $content.=' <a href="./admincp.php?product=add">Add New Product</a> <br /> <a href="./admincp.php?product=view">View Products</a> '; } } elseif(isset($_GET['log-out'])){ session_start(); session_unset(); session_destroy(); header("Location: ./admincp.php"); } else{ $content=' <form action="./admincp.php" method="post"> <p><label>Username:</label> <input type="text" name="username" size="30" />'; $content.='</p> <p><label>Password:</label> <input type="password" name="password" /></p>'; $content.='<p><input type="submit" value="Submit" name="Submit" /></p> </form>'; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> <head> <base href="http://ghosthuntersportal.com/" /> <title>Ghost Hunter's Portal - Admin Control Panel</title> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <meta name="verify-v1" content="" /> <meta name="keywords" content="ghost, hunters, hunter, ghosts, spirit, spirits, paranormal, investigation, investigator, investigators, k2, emf, meter, kii" /> <meta name="description" content="Ghost Hunters Potal. Parnormal research equipment store." /> <meta name="author" content="Andrew McCarrick" /> <meta name="robots" content="index, follow" <link rel="stylesheet" type="text/css" href="style.css" /> </head> <body> <img src="./logo.png" alt="Ghost Hunter's Portal Admin Control Panel" /> <br /> <div style="color: #AA44AA; font-size: 26px; margin-top: -30px; margin-left: 125px;">Admin Control Panel</div> <?php echo $logout; echo $content; ?> </body> </html> I can log-in, and get to the page with the two links on it. However, once I click one of the links it falls back to the log-in page, and it ends up being a never ending loop. It's doing this: Log-In --> Page with links ---> Log-In page again Should be doing this: Log-In --> Page with links --> Add Product page or View Products page I can never get into the the actual sub page. Just to be clear, the address bar actually shows product=add or product=view, but it still shows the log-in page. Hello Everyone, I have to change the if statements to a switch statement, in this game. Can anyone help? Thanks.
var checkKeyPressed = function (e) {
// Press key A or key D to make dog run to the left or right
// The running speed is specified by the step variable, 10 by default.
// If you replace 10 with a larger integer, the dog will run faster.
//press A, dog runs left
if (e.keyCode == "65") {
if (prex[0] > 5) {
prex[0] = prex[0] - step;
}
}
//press D, dog runs right
if (e.keyCode == "68") {
if (prex[0] < right) {
prex[0] = prex[0] + step;
}
}
};
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