PHP - How To Get This Echo Line To Display As One Line?

what im trying to do is take a youtube embed code find the URL code for that video and remove all other parts of the code keeping only the URL of the video
after i get the URL by it self then replace the http://www.youtube.com/ part of the URL with http://i2.ytimg.com/vi/

to do this i know that i need something like this to get the URL of the video
http://www.youtube.com/((?:v|cp)/[A-Za-z0-9\-_=]+)
but how to only return just the URL is something idk how to do

then use str_replace http://www.youtube.com/(?:v|cp)/" with  http://i2.ytimg.com/vi/

so in the end im asking if anyone know how to remove all other codes i dont want  and only keep the URL


this may have to be done using "regex" im not sure as i dont know to much about regex and what it can do but does sound like it would help lol

Dear All

           Good Day, i am new to PHP (a beautiful server side scripting language). i want to send a mail with line by line message i tried with different types like by placing the things in table and using  <br /> but the thing is the tags are also visible in the message of the mail.

Here is my code:

$message1  = "Name       :".  $_REQUEST['name']."<br />";
$message1 .= "Surname    :".  $_REQUEST['surname']."<br />";
$message1 .= "Cellphone  :".  $_REQUEST['mobileno']."<br />";
$message1 .= "Telephone  :".  $_REQUEST['landno']."<br />";
$message1 .= "Fax        :".  $_REQUEST['fax']."<br />";
$message1 .= "Company    :".  $_REQUEST['company']."<br />";
$message1 .= "Email      :".  $_REQUEST['email']."<br />";
$message1 .= "Country    :".  $_REQUEST['country']."<br />";
$message1 .= "Enquity    :".  $_REQUEST['enquiry']."<br />";
$message1 .= "Date&Time  :".  $date."<br />";

For this code if try to print/echo it it is working fine it is displaying line by line, but using this variable ($message1) in the mail these <br /> are also visible.
Can any one guide me to resolve(to remove these tags from the message part) this issue.
Thanks in Advance. :confused:

Hi.

I want a simple textbox, that when submited, will replace very every new line, with the <br> tag.

What will happen, when it submits, it will take the contents of a textbox, add the <br> tag where a new line is suposed to be, and save the string to a MySQL Database.

I think this is the easiest way of allowing a user to edit what appears on a website when logged in, but if there is a easier way, then please tell me.

What I am trying to do, is a login page, and once logged in, you enter new text into the textbox, click submit, and on the website homepage, the main text will change to what was submitted. But if there is a new line, I think the only way in HTML to make one is to put a <br> tag, so I want the PHP to but that tag wherever there is a new line.

Sorry if I am confusing, I am not that advanced at PHP, but I would be very happy if you could supply me with the correct code. Time is running out...

If you do not understand me, please tell me

--
PHPLeader (not) 

i have to read a single line from a csv,  its a really big file and i only need one column. i need the response to be a string ,i made a search and found the following code but i dont have any idea how to get a single line from a single string per run .

<?php
$row = 1;
//open the file
if (($handle = fopen("file.csv", "r")) !== FALSE)
{
    while (($data = fgetcsv($handle, 0, ",")) !== FALSE)
    {
        $num = count($data);
        echo "<p> $num fields in line $row: <br /></p>\n";
        $row++;
        for ($c=0; $c < $num; $c++)
        {
            echo $data[$c] . "<br />\n";
        }
    }
    fclose($handle);
}
?>

Edited by bores_escalovsk, 16 May 2014 - 06:38 PM.

i have a mysql table which contains name like

mid           mname

101           AAA
102          BBB
103          CCC

now i have to print this name in a html table like AAA, BBB, CCC

i am getting this by while loop in a variable but when loop changes then value also change so please tell me how i get this only in one variable & print

I have a script that reads a .gz file into an array and prints the name of each record but will not work on larger files. Is there a way to read 1 line at a time?
Here is the code I have so far.
Code: [Select]
<?php

if ($handle = opendir('.')) {

print "<ol>";
    
    while (false !== ($file = readdir($handle))) {
if($file != '..' && $file!="." && $file!="start_update.php" && $file!="sharons_dbinfo.inc.php" && $file!="root.php" && $file!="read_directory.php" && $file!="read_dir.php" && $file!="new_category.php" && $file!="index.php" && $file!="file_count.php" && $file!="dir_loop2.php" && $file!="dir_loop1.php" && $file!=".htaccess" && $file!="Answer.txt" && $file!="Crucial_Technology-Crucial_US_Product_Catalog_Data_Feed.txt"){
$filename = $file;
$go = filesize($filename);
if($go >= 1){
$filename2 = explode("-", $filename);
$filename2 = $filename2[0];
echo str_replace("_"," ",$filename2) . ' | Filesize is: ' . filesize($filename) . ' bytes<br>';
$gz = gzopen($filename, 'r');
$lines = gzfile($filename,10000);
foreach ($lines as $line) {
$line2 = explode(",", $line);
$line2 = str_replace("," , "-" , $line2);
    echo "<li>".str_replace("," , "-" , $line2[4])."</li><br>";
}

}
}
    }

    closedir($handle);
}
?>
</ol>

I'm so sorry to ask such a "newbee question," but believe me I have been on Google for the better part of the week trying to find an answer.   I'll start with the brief question. Then I'll give an example to show what I mean. Then, I'll give the BESTEST "pseudo-code" I could come up with (to PROVE that I've really given it my best).   Question: How do I make PHP loop through a big file, make the changes line by line, and to save the resultant file.   Example: I have a 100mb text file ("animals.txt") with 500,000 lines. If any lines have the word "cat" in it, I want to add "Be careful with cats!" to the end of the line:   From this: A fish and his tank. A cat and his toy. A bird and her cage. A frog and his lilly. A cat and her friend.   To this: A fish and his tank. A cat and his toy. Be careful with cats! A bird and her cage. A frog and his lilly. A cat and her friend. Be careful with cats!   The best "pseudo-code" I can come up with is:   <?php $data = file_get_contents("animals.txt"); $lines = explode(PHP_EOL,$data);

I want my application will send a email after 10 minutes of sending another email.

In my application

A user completes registration with payment Application sends the user a payment confirmation email

Now I want to

send another email 10 minutes After payment confirmation email with welcome tips

Below is the function where for user setup .

 

public function finishUserSetup($Sub){

    if($Sub == 0){
        $subscription = SubscriptionPlans::where('identifier', '=', "Monthly")->first();
        $expiry = date('Y-m-d', strtotime('+' . $subscription->months . ' months'));
        $sub_period = "monthly";
    
    } else{
        $subscription = SubscriptionPlans::where('identifier', '=', "Annually")->first();
        $expiry = date('Y-m-d', strtotime('+' . $subscription->months . ' months'));
        $sub_period = "annually";
    }

    $this->expiry_date = $expiry;
    $this->user_type = "SUB";
    $this->subscription_period = $sub_period;
    $this->update();

    $replaceArray = array(
        'fullname' => $this->forename . " " . $this->surname,
        'subscriptionName' => $subscription->name,
        );
    EmailTemplate::findAndSendTemplate("paymentconfirm", $this->email, $this->forename . " " . $this->surname, $replaceArray);

  }

In the above function the last line of code is the one which sends a payment confirmation email to the user which is

EmailTemplate::findAndSendTemplate("paymentconfirm", $this->email, $this->forename . " " . $this->surname, $replaceArray);

I want to execute the following line of code 10 minutes after the above one

 

EmailTemplate::findAndSendTemplate("WelcomeTips", $this->email, $this->forename . " " . $this->surname, $replaceArray);

 

 

How to do that. that is running the last line of code 10 minutes after  

What i want to is

if content is more than one line but script should display only one line and add "...more" at the end of it. so that i can make it a link to the article.


is this possible?


Thanks in advance for the help and support.

gday all!

just starting to learn php but having a liitle problem with \n forcing a line break. in my situation it simply doesnt.
looking at this what have i done wrong?
Code: [Select]
echo "<div class=\"imgcontainer\"><a href='$row[filename]'  rel='shadowbox[thingo]'><img class= 'thumbnail' img src='$row[filename]'/></a><div class=\"thetext\">Artwork: $row[name]\nArtist:$row[artist]</div></div> ";
Thanks

i have a text from the database and i want to echo just the first line , but i dont know the character = new line

i tried those (to know the character) :

  Code: [Select]
if(strpos($question['q_text'],'\n')!==false){echo 'yes';}
 elseif(strpos($question['q_text'],'\n')===false){echo 'no';}

if(strpos($question['q_text'],'<br>')!==false){echo 'yes';}
 elseif(strpos($question['q_text'],'<br>')===false){echo 'no';}

if(strpos($question['q_text'],'<br/>')!==false){echo 'yes';}
 elseif(strpos($question['q_text'],'<br/>')===false){echo 'no';}

all of them are No !

Once you have a form compleated by the on line client how do you get the finished form sent to your E-Mail address?
 I know it has to have something to do with the submit button but being a newbie at this PHP I'm not quite sure.
Right now I have this long form all in HTML
www.lakegenevapieco.com/product_list.htm
Yeah, I know... it was originally done in the infamous Front Page software.
It will probably need to be compleatly rewritten but that's where I need the advice.
By the way I know what this is  but what is this one  ?

Hi,

I'm having a weird issue when I try to run PHP scripts from the command line on my server.  I'm trying to just run a very simple script to test it out:

#!/usr/bin/php-cgi -q
echo "Hello terminal\n"; 

And I get the following error in the terminal..

Code: [Select]
Error in argument 1, char 3: option not found
Usage: php-cgi [-q] [-h] [-s] [-v] [-i] [-f <file>]
       php-cgi <file> [args...]
When I try taking out the quiet (-q) parameter, I get the following error..

Code: [Select]
-bash: ./socket_server.php: /usr/bin/php-cgi^M: bad interpreterNo such file or directory
As you can see, in the second example, a rogue "^M" was appended to the end of the first line of my socket_server.php file.  What does ^M correlate to?  I realize it is a character code for something that can't be represented with an actual character, but I don't know what it is, and I'm not sure why it is being appended to the end of my first line.

My assumption is that this is happening in the first example too, which is why I get the "error in argument 1" message, since undoubtedly -q^M is an invalid argument...

Any help is greatly appreciated!

nethnet

<?php
ob_start();
include "connect.php";



// Define $myusername and $mypassword 
$username=$_POST['username']; 
$password=$_POST['password']; 

// To protect MySQL injection (more detail about MySQL injection)
$username = stripslashes($username);
$password = stripslashes($password);
$username = mysql_real_escape_string($username);
$password = mysql_real_escape_string($password);

$sql="SELECT * FROM accounts WHERE username='$username' and password='$password'";
$result=mysql_query($sql);

// Mysql_num_row is counting table row
$count=mysql_num_rows($result);
// If result matched $myusername and $mypassword, table row must be 1 row
if($count==1)
{
// Register $myusername, $mypassword and redirect to file "login_success.php"
session_register("username");
session_register("password"); 
echo "&msgText=Entrance Granted!\n";
}
else
{
echo "&msgText=Invalid Login!\n";
}
return false;
ob_end_flush();
?>


this line right here what would the URL be to work correctly
$sql="SELECT * FROM accounts WHERE username='$username' and password='$password'";

if this line means this
$sql="SELECT * FROM accounts WHERE username='$username'";

http://wiistream.net/flash.login.php?username=Mytest

= echo "&msgText=Entrance Granted!\n";

see i dont know is it
http://wiistream.net/flash.login.php?username=Mytest&password=123456

I cant seem to login with a URL code because I dont know what it is?

echo '<div class="gamename">'.$values[0].'</div>';
echo  '<div class="gameimage"><a href="'.$values[3].'"><img src="'.$values[1].'"></a></div>';

NOW i want 2nd echo under 1st echo. I tried every single <br> combination but no luck   

Also my 2nd question is: my image and link is a variable, it displays the image but there is something wrong with link.
Variable is just like this  www.mydomain.com\image\blabla.php
but it shows link as==> www.mydomain.com\     instead of what i wrote above.