PHP - Browse To File And Read Contents
Hi All, sure this is simple but I'm still new to php/mySQL so errors are abundant!
I have a simple form with one input: a browse button so the user can find a .csv file on their computer. User then clicks button, upon which I would like the file to be read and the contents put into an array, and the values to be added to the database. I do not need the file to be stored (uploaded). So far my code is not erroring, it just doesn't add the values to the db. I'm wondering if it's just that I HAVE to upload and save the file to the webserver else I can't read it? if(isset($_FILES['file_path']['tmp_name'])&& $_FILES['file_path']['tmp_name'] !=''){ $file_to_import = $_FILES['file_path']['tmp_name']; $import_data = file($file_to_import); print_r($import_data); if ($import_data !=''){ for($index = 1; $index < sizeof($import_data); $index++){ $order_data = explode(",",$import_data[$index]); tep_db_query("UPDATE orders SET act_shipping_cost = '" . $order_data[8]. "' WHERE orders_id = '". $order_data[0]."'"); echo "done it"; } }else{ echo 'error cant read file!'; } } else{ ?> <!doctype html public "-//W3C//DTD HTML 4.01 Transitional//EN"> etc etc etc <form id="shipping_costs_upload" name="csv_file_reader" method="post" action="shipping_cost_upload.php"> <div class="main" id="info_text"><h2>Upload Actual Shipping Costs CSV</h2><p>To upload actual shipping cost data, browse to your csv and click the Upload Data button.<br /><br /></p> <div class="date" id="file"> <strong>CSV File: </strong><input type="file" name="file_path" id="file_url" /> </div> <div class="date"><input type="submit" value="Upload Data"> </div> </form> etc etc etc Apologies if I'm being a complete dunce! Similar TutorialsHi, I assigned a project where i have to import the mobile numbers from the file, but i have no idea how to proceed this. What kind of file to accept as input and how to read. Thanks I don't know, it seemed simple but it turns out I don't know what to do.
I was told that storing a photo as a blob was much harder than simply storing a photo's url or directory location...
So... when a file has been selected through the browse-file manager triggered by
<input type="file"...>and the file selected is shown, when a person pusehs "upload" what is supposed to happen? Do I need some kind of FTP client to access the server and place the photo in there? It seems so easy in a way like the built in filemanager in cPanel... What am I missing? Thanks for any help. Hi guys, I've created some coding and a button allowing the user to browse their local machine and upload a file, with certain details then displayed on a new web page. Is there a way I can get the ouput to display on a popup window rather than navigate to a new browser page? The code I have used to create this is: Code: [Select] <form action="upload_file.php" method="post" enctype="multipart/form-data"> <label for="file">Filename:</label> <input type="file" name="file" id="file" /> <input type="submit" name="submit" value="Start" style="height:50px" /> </form> When the user clicks the 'start' button, the php script runs and retrieves the information required but I want this to be output on a popup window. Cheers for your time Ok, I have this code that is supposed to upload a csv file and save the contents into a specific sql table. I am getting an error when i hit submit that states the file is empty, meaning the csv file. I am thinking that the file isn't really being targeted i just don't know how to fix it. To start i have a php page with a the form and then i have another php page that is included in the form php page. The functions for submitting the csv info in the text file is located in the include file. here is the code: Code: [Select] $csv = new Quick_CSV_import(); $arr_encodings = $csv->get_encodings(); //take possible encodings list $arr_encodings["default"] = "[default database encoding]"; //set a default (when the default database encoding should be used) if(!isset($_POST["encoding"])) $_POST["encoding"] = "default"; //set default encoding for the first page show (no POST vars) if(isset($_POST["Go"]) && ""!=$_POST["Go"]) //form was submitted { $csv->file_name = $HTTP_POST_FILES['file_source']['tmp_name']; //optional parameters $csv->use_csv_header = isset($_POST["use_csv_header"]); $csv->field_separate_char = $_POST["field_separate_char"][0]; $csv->field_enclose_char = $_POST["field_enclose_char"][0]; $csv->field_escape_char = $_POST["field_escape_char"][0]; $csv->encoding = $_POST["encoding"]; //start import now $csv->import(); } else $_POST["use_csv_header"] = 1; ?> <tr> <td>Source CSV file to import:</td> <td rowspan="30" width="10px"> </td> <td><input type="file" name="file_source" id="file_source" class="edt" value="<?=$file_source?>"></td> </tr> and Code: [Select] class Quick_CSV_import { var $table_name = "tbl_product"; //where to import to var $file_name; //where to import from var $use_csv_header; //use first line of file OR generated columns names var $field_separate_char; //character to separate fields var $field_enclose_char; //character to enclose fields, which contain separator char into content var $field_escape_char; //char to escape special symbols var $error; //error message var $arr_csv_columns; //array of columns var $table_exists; //flag: does table for import exist var $encoding; //encoding table, used to parse the incoming file. Added in 1.5 version function Quick_CSV_import() { $this->file_name = $file_name; $this->arr_csv_columns = array(); $this->use_csv_header = true; $this->field_separate_char = ","; $this->field_enclose_char = "\""; $this->field_escape_char = "\\"; $this->table_exists = false; } function import() { if($this->table_name=="") $this->table_name = "temp_".date("d_m_Y_H_i_s"); $this->table_exists = false; $this->create_import_table(); if(empty($this->arr_csv_columns)) $this->get_csv_header_fields(); /* change start. Added in 1.5 version */ if("" != $this->encoding && "default" != $this->encoding) $this->set_encoding(); /* change end */ if($this->table_exists) { $sql = "LOAD DATA INFILE '".@mysql_escape_string($this->file_source). "' INTO TABLE `".$this-> table_name. "` FIELDS TERMINATED BY '".@mysql_escape_string($this->field_separate_char). "' OPTIONALLY ENCLOSED BY '".@mysql_escape_string($this->field_enclose_char). "' ESCAPED BY '".@mysql_escape_string($this->field_escape_char). "' ". ($this->use_csv_header ? " IGNORE 1 LINES " : "") ."(`".implode("`,`", $this->arr_csv_columns)."`)"; $res = @mysql_query($sql); $this->error = mysql_error(); } } //returns array of CSV file columns function get_csv_header_fields() { $this->arr_csv_columns = array(); $fpointer = fopen($file_name, "r"); if ($fpointer) { $arr = fgetcsv($fpointer, 10*1024, $this->field_separate_char); if(is_array($arr) && !empty($arr)) { if($this->use_csv_header) { foreach($arr as $val) if(trim($val)!="") $this->arr_csv_columns[] = $val; } else { $i = 1; foreach($arr as $val) if(trim($val)!="") $this->arr_csv_columns[] = "column".$i++; } } unset($arr); fclose($fpointer); } else $this->error = "file cannot be opened: ".(""==$this->file_name ? "[empty]" : @mysql_escape_string($this->file_name)); return $this->arr_csv_columns; } i just can't figure it out. could anyone help me out? the error i get says this: Warning: fopen() [function.fopen]: Filename cannot be empty in /Quick_CSV_import.php on line 83 hi- i'm trying to browse for a CSV file and then upload it to my mysql database. i found the code below and not working. i don't get any errors. the connection to the database is ok bcz i get the existing results but not the ones from the CSV file added to the db.. any ideas? Code: [Select] <?php ob_start(); require_once('../../connections/congif.php'); mysql_select_db($dbname, $db); $sql_get_project="SELECT * FROM gifts_tbl ORDER BY autoID DESC LIMIT 25"; $get_project = mysql_query($sql_get_project, $db) or die(mysql_error()); $row_get_project = mysql_fetch_assoc($get_project); //database connect info here //check for file upload if(isset($_FILES['csv_file']) && is_uploaded_file($_FILES['csv_file']['tmp_name'])){ //upload directory $upload_dir = "csv_dir/"; //create file name $file_path = $upload_dir . $_FILES['csv_file']['name']; //move uploaded file to upload dir if (!move_uploaded_file($_FILES['csv_file']['tmp_name'], $file_path)) { //error moving upload file echo "Error moving file upload"; } //open the csv file for reading $handle = fopen($file_path, 'r'); //turn off autocommit and delete the product table mysql_query("BEGIN"); while (($data = fgetcsv($handle, 1000, ',')) !== FALSE) { //Access field data in $data array ex. $name = $data[0]; //Use data to insert into db $sql = sprintf("INSERT INTO gifts_tbl (player_id) VALUES ('%s)", mysql_real_escape_string($name) ); mysql_query($sql) or (mysql_query("ROLLBACK") and die(mysql_error() . " - $sql")); } unlink($file_path); } ob_flush(); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>Gifts</title> </head> <body> <h1>Testing for CSV upload</h1> <form action="" method="post"> <input type="file" name="csv_file"> <input type="submit" name="csv_submit" value="Upload CSV File"> </form> <h2>Results</h2> <?php do { ?> <ul> <li><?php echo $row_get_project['player_id']; ?></li> </ul> <?php } while ($row_get_project = mysql_fetch_assoc($get_project)); ?> </body> </html> This topic has been moved to PHP Installation & Configuration. http://www.phpfreaks.com/forums/index.php?topic=307015.0 I am using apache web server on linux. I am using PHP for web designing. On web server, i want to show the configuration data by reading the ini file. I am creating this ini file from one php code itself. If this php code i run through linux terminal, the file is created with file and group owner as root.(i am having sudo rights on machine) Then if i try to read the ini file from my apache web server, it gives warning as failed to open stream: permission denied. I have tried changing the owner, and permissions to 777 of the file. Still it is not readable.
On the other hand, if i run the php code of ini file creation through web server, ini file is created with file and group owner as apche. and web server is able to read/ write the file.
But i want to create that file from root or some other user and later read/written by apache.
How to give this access permission?
I need some help...I want to read the contents of a file into a variable and then insert/write that content into another file. Code: [Select] $handle = fopen($create_mysql_db_url, "rb"); $contents = fread($handle, filesize($create_mysql_db_url)); fclose($handle); $userFileName = $_POST['mysqluser'] . time() . ".php.txt"; $fhandle = fopen($userFileName,"wb"); fwrite($fhandle, $contents); fclose($fhandle); $fh = fopen($userFileName,"wb"); $contents = fread($fh, filesize($userFileName)); $content = preg_replace("/###USERNAME###/", $_POST['mysqluser'], $contents); $content = preg_replace("/###PASSWORD###/", $_POST['mysqlpass'], $content); fwrite($fh, $content); fclose($fh); please help Hello friends, if i have the following $path = "http://*site*.com"; why can't i write the following $ORGtext= file_get_contents('$path'); it works only if i write $ORGtext= file_get_contents('http://*site*.com'); but i want to put $path instead of the url at file_get_contents is it possible and if yes then how ? thank you Hello, I have a simply query that will if a simple two different things: Code: [Select] $cssyn = mysql_query("SELECT `12` FROM `12345` WHERE `abc` = '$_SESSION[number]'"); $cssy = mysql_fetch_row($cssyn); if($cssy[0] == "YES") { echo "Yes"; } else { echo "No"; } The YES or NO result is stipulated earlier on so thats not the problem. But basically before I added the if statement simply would have echoed a table with all the rows etc from another query. However I would like to give the user a choice between echoeing the results into one table or a neater two. I have separated the code for the table and the queries into two separate files but say if I use: file_get_contents then it just prints the HTML and doesnt actually populate it will the queried parts. Nor if I use something like include() then it wont echo anything, which it wouldnt unless called so what I am asking is: Is there a way to get EVERYTHING from the file if the answer is YES or the other file if NO. eg http://www.xxxxxxx.com/index.php?action=viewarti&artid=5 How can I write the content of this link into file. Hi, I have a file which contains settings for a user. Similar to wordpress except simpler like setting a default email for error messages or something. The idea is that it's used as an installation script for web-ware where someone fills in a form with their database details, my script will hard-code them into the settings file and then delete itself. I'll admit I did get the idea from wordpress. Only the way it's coded currently requires a certain combination of characters at the end and seems really messy. The script looks like this (and does work): $endpos = strpos ( $contents, '"; //replace with name//', $startpos); The settings file looks like this: $hard_name = "Smith"; //replace with name// As you can see I use the comment in the settings file, which follows what I'm actually changing, to find the end of the variable. I am sure there must be a better way of doing things but don't know what. It just seems really inefficient because if the comment is removed the script breaks. Any info and tips would be much appreciated. IceKat I'm trying to extract the contents of a zip file to a folder. I found the ZipArchive class and followed the examples to get it to work for the most part. But I want to extract the files in the folder inside the zip file but leave the folder out. So it should extract just the files to my given destination. I found this on php.net. Code: [Select] If you want to copy one file at a time and remove the folder name that is stored in the ZIP file, so you don't have to create directories from the ZIP itself, then use this snippet (basically collapses the ZIP file into one Folder). <?php $path = 'zipfile.zip' $zip = new ZipArchive; if ($zip->open($path) === true) { for($i = 0; $i < $zip->numFiles; $i++) { $filename = $zip->getNameIndex($i); $fileinfo = pathinfo($filename); copy("zip://".$path."#".$filename, "/your/new/destination/".$fileinfo['basename']); } $zip->close(); } ?> For some reason that 'copy' line is not working for me. Obviosly I've changed the variables in the line to the correct variables. Can someone help me out. Thanks Mike I set up a Twilio number so a client could have a SMS keyword response setup... but I don't know how to get the contents of a file to be returned as the response. I am using the php functions.. I setup a system so that my client could change the responses to different keywords. Basicly it uses a webform to change the contents of a file which gets returned as a response. What I need to know is how to read in the contents of the file into this function: BTW... this works fine and will return "READ_FILE_CONTENTS_INTO_HERE" function app(){ $response = new Services_Twilio_Twiml(); $response->sms("READ_FILE_CONTENTS_INTO_HERE"); echo $response; } I tried this but it stopped the script dead: function app(){ $response = new Services_Twilio_Twiml(); $response->sms("<?php include 'file.txt'; ?>"); echo $response; } Any ideas? Thanks BTW... below is the entire php script: <?php /* Include twilio-php, the official Twilio PHP Helper Library, * which can be found at * http://www.twilio.com/docs/libraries */ include('Services/Twilio.php'); /* Controller: Match the keyword with the customized SMS reply. */ function index(){ $response = new Services_Twilio_Twiml(); $response->sms("Thank You For Contacting SweetLeafAZ.com - Reply with one of the following keywords: APP = Make Appt, CS = Current Strains, DP = Delivery Prices, SP = Current Specials."); echo $response; } function app(){ $response = new Services_Twilio_Twiml(); $response->sms("http://www.vcita.com...01f2c7d/home"); echo $response; } function cs(){ $response = new Services_Twilio_Twiml(); $response->sms("http://mobile.dudamo...sweetleafaz2"); echo $response; } function dp(){ $response = new Services_Twilio_Twiml(); $response->sms("As of Sept 26 2014, Our Delivery Rates are $2 per mile during the hours of 9am to 6pm. No deliveries will be made after 6pm."); echo $response; } function sp(){ $response = new Services_Twilio_Twiml(); $response->sms("We are currently offering FREE delivery within 10 miles for orders over $100."); echo $response; } /* Read the contents of the 'Body' field of the Request. */ $body = $_REQUEST['Body']; /* Remove formatting from $body until it is just lowercase characters without punctuation or spaces. */ $result = preg_replace("/[^A-Za-z0-9]/u", " ", $body); $result = trim($result); $result = strtolower($result); /* Router: Match the ‘Body’ field with index of keywords */ switch ($result) { case 'app’': app(); break; case 'cs': cs(); break; case 'dp': dp(); break; case 'sp': sp(); break; /* Optional: Add new routing logic above this line. */ default: index(); } Hello, I am a PHP newbie, and have been mostly playing around with PHP/MySQL in a CMS ares (i.e. building my own CMS). Now I am trying to expand my knowledge outside of the basic php commands, and a particular subject caught my attention. Getting page source code, parsing out bits from it, and displaying it. This is more of my personal goal to get it working, to learn more about some of PHP's abilities, and especially search parameter flag thingies D: http://nexrem.com/scripts/get_source/ That is my webpage i made real quick, as you can see it shows basic stuff. Code for it is: Code: [Select] <html> <head> <title>Content Site</title> </head> <body> <p>This is intro text</p> <a href="http://google.com" title="Search Engine">Google Link</a><br /> <a href="http://yahoo.com" title="">Yahoo Page</a></br > <a href="http://http://www.phpfreaks.com" title="Awesome Site">PHP Freaks Help</a><br /> Bottom of file </body> </html> Now, I have a php file called get_link.php >> http://nexrem.com/scripts/get_source/get_links.php Code: [Select] <?php $url = 'http://nexrem.com/scripts/get_source/'; $needle = 'google'; $contents = file_get_contents($url); if(strpos($contents, $needle)!== false) { echo 'found'; } else { echo 'not found'; } // The \\2 is an example of backreferencing. This tells pcre that // it must match the second set of parentheses in the regular expression // itself, which would be the ([\w]+) in this case. The extra backslash is // required because the string is in double quotes. $html = $contents; echo $contents; preg_match_all("/(<([\w]+)[^>]*>)(.*?)(<\/\\2>)/", $html, $matches, PREG_SET_ORDER); foreach ($matches as $val) { echo "matched: " . $val[0] . "\n"; echo "part 1: " . $val[1] . "\n"; echo "part 2: " . $val[2] . "\n"; echo "part 3: " . $val[3] . "\n"; echo "part 4: " . $val[4] . "\n\n"; } ?> From what I understand, file_get_contents gets what the user sees? Or it gets the source code, and I just can't output it as such, cause my browser renders it? Question 1: Is it possible to get the html code of the page, rather than what the html renders it to be? How? Question 2: I can just Right click > view source and paste that result into a text file. I think I know how to search for a specific string, but how would I do it recursively, along the lines of: Search for text between <a href=" and " so I get the raw link Then add the results to an array. And then use foreach to output all the links from the array? Any help, hints are appreciated! Thank You! P.S. I quite frankly, got no idea what "/(<([\w]+)[^>]*>)(.*?)(<\/\\2>)/ is... Can someone refer me to a page where I can learn about those expressions? i am trying to do a "file get contents" from the following website http://www.bet365.com/home/ It is necessary to input your account username and password here, and then I want to get the contents of this page http://www.bet365.com/extra/en/results-and-archive/results/?Fromdate=13%2f09%2f2014+00%3a00&SearchPath=result&FixtureId=46827110&Period=99&ChallengeId=26278650&CompetitionId=999999&SportId=1&SportDesc=Soccer&Todate=14%2f09%2f2014+00%3a00&LanguageId=1&Zoneid=1 I have tried a couple of scripts but just can't seem to get it to work. I have tried $context = stream_context_create(array( 'http' => array( 'header' => "Authorization: Basic " . base64_encode("$username:$password") ) )); $data = file_get_contents($url, false, $context); echo $data; with the username and password and url entered as variables. but get the message Warning: file_get_contents(http://www.bet365.com/extra/en/results-and-archive/results/?Fromdate=13%2f09%2f2014+00%3a00&SearchPath=result&FixtureId=46827110&Period=99&ChallengeId=26278650&CompetitionId=999999&SportId=1&SportDesc=Soccer&Todate=14%2f09%2f2014+00%3a00&LanguageId=1&Zoneid=1) [function.file-get-contents]: failed to open stream: HTTP request failed! in "myscript's address" on line 13 Maybe i don't need to visit the homepage first to log in? Any ideas please? Thank youapologies for the message being in code quotes, I wrote it in Word but then couldn't paste it, even using the special Word paste button. Hope the message comes out ok. Thank you. is there a way to print the file as it appears. I want to print the HTML and PHP within a file rather than just the output. Example: File contains: <?php echo "Hello World"; ?> i would like to echo: <?php echo "Hello World"; ?> instead of just hello world which is what i get with file_get_contents() ok so say I have a file with .. this information in one file Code: [Select] 548402354 7e99c2c49be0ad1a95fd3b4a2f65fc941e9cf194 548402225 9e0b2788f21a317eb76159f3e0c4e4a090492f2a 548402329 1aa382935c94d73f58bdb3203686cc0124fb3443 548402596 c41655fa8f14346cbd8a656a18ecb82caa3c1f9c 548402535 558e1ee14f2423681668a168a3980304ac54bd15 548402456 48ee03332c417cab51eaec13b415fde8c0b6a641 548400202 5bf3400e3c074eb8b42a962dc7e60777d2b2848a 548400842 cc672d4785ec5b9e22db7b60e203286c840c4f37 548400682 547c8ac38243b0f9a94609177d0dd12194059aa5 548400810 54afebbb3e884fea5563c017b18dd390ff1ff034 548400581 ec7305326b5514cbf05ab4a78647ed756da9db55 548400431 b3dcaa272c759ebe4e5b00053ef390b21b23f60c and I want to take and split the contents into 6 different files.. So it would take the first 2 lines and write to filename 1.txt, then it would take the 2 lines after that and write a file named 2.txt, so on and so forth Any help is appreciated, thanks I have a base64 encoded image -> http://pastebin.com/698ES5t0
Im trying to export this as a png file.
$picture = {data on paste bin}; $picture = base64_decode($picture); file_put_contents('/home/picture.png', $Picture);Now this creates a file picture.png and i can open it in Preview/Gimp etc. However, if i upload the file to my website, the image does not render in chrome/firefox, however it does render in Safarai. It seems that there is no height/width/depth data. So, I'm trying to get this read my text document "news.txt" and display the contents. My code: Code: [Select] div.newscontent{ padding:0px; margin-top:60px; margin-bottom:0px; margin-left:400px; margin-right:0px; position:absolute; width:457px; height:330px; text-align:center; color:#FFFFFF; } Code: [Select] <div class='newscontent'> <?PHP $filename = "news.txt"; $arr = file($filename); foreach($arr as $line){ print $line . "<br/>"; } ?> </div> This is the output I get: Code: [Select] "; } ?> Whats wrong? |