PHP - Php Problem
I Have An error on line 42 not sure what it is can any one tell?
$foundnum = mysql_num_rows($run); Similar TutorialsGuys thanks for helping me solve the problem i had but now i have another problem and i am lost. i have included the code below for you to have overview.
This is the code:
<table style="width:100%; margin-left:auto; margin-right:auto"> Hello everyone Just found this forum and really need some help. I'm trying to create a popup contact form for my product pages. I managed to get a php form from a random site and i cant get the form to pop up. http://www.e-sol.co.uk/printer-scanner-copier.php If someone could help i would be very grateful. so i want to call my php file with a query string to select a record out of a XML file... im close but cant get the variable i pass to be the record selected.. example... index.php?auction=1 i highlighted in red, where it doesnt pick up the proper row Code: [Select] <?php ini_set('display_errors', 1); error_reporting(E_ALL); $auction = $_GET{auction}; // parse the xml $xmlFileData = file_get_contents("items.xml"); $xmlData = new SimpleXMLElement($xmlFileData); [color=red]$location = $xmlData->item[$auction];[/color] //Retrieving the content from the selected item $title = $location->title; $value = $location->value; $itemnumber = $location->itemnumber; $description = $location->description; $donatedby = $location->donatedby; $image1 = $location->image1; $image2 = $location->image2; $image3 = $location->image3; $image4 = $location->image4; $image5 = $location->image5; $image6 = $location->image6; $image7 = $location->image7; $image8 = $location->image8; ?> <style> .itemimages img {width: 10px; height: 10px;} img.large {width: 100px; height: 100px;} </style> <script language="JavaScript" src="http://code.jquery.com/jquery-1.5.min.js" type="text/javascript"></script> <script> $().ready(function() { $(".itemimages img").click( $("#largepic").attr("src","this"); }); }); </script> <table border="1" cellpadding="10"> <tr> <td valign="top"> <img src="<?php echo $image1 ?>" alt="" border="0" class="large" id="largepic"><br> <div class="itemimages"> <?php // image 1 if (trim(''.$image1) != '') { echo "<img src='"; echo $image1; echo "' alt='' border='0'/> "; } // image 2 if (trim(''.$image2) != '') { echo "<img src='"; echo $image2; echo "' alt='' border='0'/> "; } // image 3 if (trim(''.$image3) != '') { echo "<img src='"; echo $image3; echo "' alt='' border='0'/> "; } // image 4 if (trim(''.$image4) != '') { echo "<img src='"; echo $image4; echo "' alt='' border='0'/> "; } // image 5 if (trim(''.$image5) != '') { echo "<img src='"; echo $image5; echo "' alt='' border='0'/> "; } // image 6 if (trim(''.$image6) != '') { echo "<img src='"; echo $image6; echo "' alt='' border='0'/> "; } // image 7 if (trim(''.$image7) != '') { echo "<img src='"; echo $image7; echo "' alt='' border='0'/> "; } // image 8 if (trim(''.$image8) != '') { echo "<img src='"; echo $image8; echo "' alt='' border='0'/> "; } ?> </div> </td> <td valign="top"> <?php echo $title ?><br> Estimated Value: <?php echo $value ?><br> Item Number: <?php echo $itemnumber ?><br><br> <?php echo $description ?><br><br> Donated by: <?php echo $donatedby ?><br> </td> </tr> </table> You may see a lot of things wrong with the code below, but please bring it to my attention! I'm trying to advance my knowledge on OOP, but I'm trying my best to get the basics down. The below code, after selecting the two characters to fight, the page returns nothing, just blank. I'm pretty sure the error lyes within class_li.php, but I'm not exactly sure. Script is attached. Helloo ever one i need know In PHP the function giving the current time stamp value is time(). So we can write a line like below to get the current time stamp value. <? echo time(); ?> my Question is how to display any value on specific time( where value is stored in database )... Hows it going guys. I am currently having a problem. I had a program that worked. I migrated the website and now the program is broken. Any time i try to run it, i get this error: Quote Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /home/thegoo20/public_html/class/wordgame/wordgame.php on line 31 Here is the code at that point: Code: [Select] function changeword(){ $result = mysql_query("Select words from CurrentWords"); $totalwords = array(); while ($row = mysql_fetch_array($result)){ $totalwords[] = $row["words"]; } $_SESSION['word'] = $totalwords[rand(0, count($totalwords)-1)]; $_SESSION['scrambled'] = str_shuffle($_SESSION['word']); } where line 31 is the while statement. Any help would be appreciated. Thanks Hi, I am trying to write in an existing excel file. But for some reason, I can't open the workbook (but I know I have made similar code work before). Here I am just pasting the code upto the error line $filename="C:\\apache\\htdocs\\GAC2\\dload\\template.xls"; $excel = new COM("excel.application") or die("Unable to instanciate excel"); $excel->Visible = 1; $excel->DisplayAlerts = 1; try{ $wkb = $excel->Workbooks->Open($filename); }catch (Exception $e) { echo 'Caught exception: ', $e->getMessage(), "\n"; } //........ Later part of the code This returns the following error Code: [Select] Caught exception: Source: Microsoft Office Excel Description: Unable to get the Open property of the Workbooks class For record, the I have already validated the file location. And I have tried the following line instead without any positive result. Code: [Select] $filename="C:\apache\htdocs\GAC2\dload\template.xls"; Looking for any help please. -Abd I am trying to use the following code snippet to return values from a database with a "," after each value apart form the last one. At the moment for testing I have 2 rows with values 1 and 3 $totalRows_Recordset3 equals 2 (I echoed this to check) $i=1; while($row_Recordset3 = mysql_fetch_assoc($Recordset3)) { if($i < $totalRows_Recordset3) { $str = $str.$row_Recordset3['reading'].","; $i=$i+1; } else { $str = $str.$row_Recordset3['reading']; $i=$i+1; } } I get the number 3 which is the last value in the database, but I can't see why I don't get "1,3" I am sure it is something simple but it just escapes me. Thanks in advance for any help Gordon Hi there, I have a map of America made in flash, where you click on a state and the page should display the SQL database information for that state in the HTML table - but instead all it shows is the first entry of the database regardless of which state you click and it doesn't display the 2 radio buttons. My code is as follows Flash Actionscript 3 (just showing one state) Code: [Select] function waClick(event:MouseEvent):void { var waURL:URLRequest = new URLRequest("restaurants.php?state=Washington"); navigateToURL(waURL, "_self"); } wa_btn.addEventListener(MouseEvent.CLICK, waClick); PHP code Code: [Select] <?php include("mvfconnect.php"); $theChoice = $_GET['state']; $query = "SELECT * FROM restaurants WHERE" .$theChoice; $result = @ mysql_query($query); if (!$result) { $message="Unfortunately we are having problems with this page, we promise to have it fixed as soon as possible"; die($message); } $num = mysql_num_fields($result); $i=0; while ($row = mysql_fetch_array($result, MYSQL_ASSOC)){ $show1=substr($row['state'],0,50)."..."; $show2=substr($row['city'],0,50)."..."; $show3=substr($row['rname'],0,50)."..."; $show4=substr($row['address'],0,50)."..."; $show5=substr($row['pnum'],0,50)."..."; $show6=substr($row['web'],0,50)."..."; $show7=substr($row['dishes'],0,50)."..."; $show8=substr($row['dish_details'],0,50)."..."; $show9=substr($row['challenges'],0,50)."..."; $show10=substr($row['challenge_details'],0,50)."..."; $show11=substr($row['youtube'],0,50)."..."; $show12=substr($row['images'],0,50)."..."; echo "<tr>". "<td>".$row['city']."</td>". "<td>".$row['rname']."</td>". "<td>".$row['address']."</td>". "<td>".$row['pnum']."</td>". "<td>".$row['web']."</td>". "<td>".$row['dishes']."</td>". "<td>".$row['challenges']."</td>". "<td id='state".$i."' style='display:none'>".$row['state']."</td>". "<td id='city".$i."' style='display:none'>".$row['city']."</td>". "<td id='rname".$i."' style='display:none'>".$row['rname']."</td>". "<td id='address".$i."' style='display:none'>".$row['address']."</td>". "<td id='pnum".$i."' style='display:none'>".$row['pnum']."</td>". "<td id='web".$i."' style='display:none'>".$row['web']."</td>". "<td id='dishes".$i."' style='display:none'>".$row['dishes']."</td>". "<td id='dish_details".$i."' style='display:none'>".$row['dish_details']."</td>". "<td id='challenges".$i."' style='display:none'>".$row['challenges']."</td>". "<td id='challenge_details".$i."' style='display:none'>".$row['challenge_details']."</td>". "<td id='youtube".$i."' style='display:none'>".$row['youtube']."</td>". "<td id='images".$i."' style='display:none'>".$row['images']."</td>". "<td><input type='radio' name='vid' id='vid".$i."' onclick='openVideo(".$i.")' /></td>". "<td><input type='radio' name='pic' id='pic".$i."' onclick='openImage(".$i.")' /></td>". "<td class='last'style='display:none'>".$show1." ".$show2." ".$show3." ".$show4." ".$show5." ".$show6." ".$show7." ".$show8." ".$show9." ".$show10."</td>". "</tr>"; $i++; } ?> I have used this code before and it has worked fine, can someone please help me out! Okay, so i'm using the basic php mysql insert into function but I have a strange (or maybe not so strange, I just don't get it..) problem.. I have two columns (do you call them columns? I don't really know for sure, whatever things that are in a table whatsoever). Name and Trailer. EDIT: they are TEXT's if that matters Name is really nothing important, just the name. But I want to embed trailers.. If I embed the Megavideo code below: Code: [Select] <object width="400" height="300"><param name="movie" value="http://www.megavideo.com/v/8UZFURZQ2b55ada04d73ae65c726a5383b9ee9d9"></param><param name="allowFullScreen" value="true"></param><embed src="http://www.megavideo.com/v/8UZFURZQ2b55ada04d73ae65c726a5383b9ee9d9" type="application/x-shockwave-flash" allowfullscreen="true" width="400" height="300"></embed></object> Everything works fine, no problems and no bullshit. But.. if I for an example try to embed this one (NovaMov): Code: [Select] <iframe style='overflow: hidden; border: 0; width: 400px; height: 300px' src='http://embed.novamov.com/embed.php?width=400&height=300&v=xngq7u8yejwbt' scrolling='no'></iframe> It doesn't work. It just doesn't insert. Is inserting an "iframe" a problem or something? I just don't get why the hell it would do this? Does anyone know anything about this? If so i'd be eager and very thankful to hear why and how to fix it. thanks in advance i have the following sql running on local but i get an error. the sql: $sql = "SELECT * FROM '".TBL_PARENTS."'" or die(mysql_error()); the config file: define('DB_PREFIX', 'forum_'); define('TBL_PARENTS', DB_PREFIX.'parents'); the error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''forum_parents'' at line 1 the echoed sql: SELECT * FROM 'forum_parents' as you can see when it is echoed it looks fine. Any ideas? The server im using is wamp server. Hi I make 3 querys first Order by DESC, second RAND() and third ASC. Now I want that in the second query can't be the same ids (produgg_users.id) that already taken in the first. And in the third not the ids from first and second. Like I have it now the same users can show up in the RAND() and the ASC like in DESC. Here my Script so far: $rs = mysql_query("select produgg_users.id, twitterUser, credits from produgg_users where twitterUser != '' and produgg_users.id IN (select concat_ws(',', id) from produgg_users where credits > 0 and id != ".$usersClass->userID().") and produgg_users.id NOT IN (select concat_ws(',', followedID) from produgg_activity where followerID = '".$usersClass->userID()."') and produgg_users.id NOT IN (select concat_ws(',', userid) from produgg_featured) ORDER BY credits DESC LIMIT 10") or die(mysql_error()); $nr = @mysql_num_rows($rs); if($nr != 0) { print "<p>Simply click <strong>get 1 point</strong> and you will automatically FOLLOW the USER and earn the credit!</p>"; print "<p><font color=\"#0066FF\">Top Members</font></p>"; while($row=@mysql_fetch_object($rs)) { $divLeft = '<div id="thediv_'.$row->id.'"><div style="float:left;width:400px;">'; $divRight = '<div style="float:left;width:150px;">'; $clearDiv = '<div style="clear:both;"></div>'; print "$divLeft<img src=\"http://api.twitter.com/1/users/profile_image/".strip_tags($row->twitterUser)."?size=mini\" alt=\"\" /> ".strip_tags($row->twitterUser)." <font color=\"#999999\" size=\"1\">$row->credits Points</font></div>$divRight <a href='javascript:void(0);' id='vote_$row->id' class='getPoint'>Get 1 Point</a></div>$clearDiv<hr /></div>"; $z = 1; } } //Lucky Riders $rs = mysql_query("select produgg_users.id, twitterUser, credits from produgg_users where twitterUser != '' and produgg_users.id IN (select concat_ws(',', id) from produgg_users where credits > 0 and id != ".$usersClass->userID().") and produgg_users.id NOT IN (select concat_ws(',', followedID) from produgg_activity where followerID = '".$usersClass->userID()."') and produgg_users.id NOT IN (select concat_ws(',', userid) from produgg_featured) ORDER BY RAND() LIMIT 5") or die(mysql_error()); $nr = @mysql_num_rows($rs); if($nr != 0) { print "<p><font color=\"#0066FF\">Lucky Riders</font></p>"; while($row=@mysql_fetch_object($rs)) { $divLeft = '<div id="thediv_'.$row->id.'"><div style="float:left;width:400px;">'; $divRight = '<div style="float:left;width:150px;">'; $clearDiv = '<div style="clear:both;"></div>'; print "$divLeft<img src=\"http://api.twitter.com/1/users/profile_image/".strip_tags($row->twitterUser)."?size=mini\" alt=\"\" /> ".strip_tags($row->twitterUser)." <font color=\"#999999\" size=\"1\">$row->credits Points</font></div>$divRight <a href='javascript:void(0);' id='vote_$row->id' class='getPoint'>Get 1 Point</a></div>$clearDiv<hr /></div>"; $z = 1; } } //Lucky Riders $rs = mysql_query("select produgg_users.id, twitterUser, credits from produgg_users where twitterUser != '' and produgg_users.id IN (select concat_ws(',', id) from produgg_users where credits > 0 and id != ".$usersClass->userID().") and produgg_users.id NOT IN (select concat_ws(',', followedID) from produgg_activity where followerID = '".$usersClass->userID()."') and produgg_users.id NOT IN (select concat_ws(',', userid) from produgg_featured) ORDER BY credits ASC LIMIT 5") or die(mysql_error()); $nr = @mysql_num_rows($rs); if($nr != 0) { print "<p><font color=\"#0066FF\">Last Rides</font></p>"; while($row=@mysql_fetch_object($rs)) { $divLeft = '<div id="thediv_'.$row->id.'"><div style="float:left;width:400px;">'; $divRight = '<div style="float:left;width:150px;">'; $clearDiv = '<div style="clear:both;"></div>'; print "$divLeft<img src=\"http://api.twitter.com/1/users/profile_image/".strip_tags($row->twitterUser)."?size=mini\" alt=\"\" /> ".strip_tags($row->twitterUser)." <font color=\"#999999\" size=\"1\">$row->credits Points</font></div>$divRight <a href='javascript:void(0);' id='vote_$row->id' class='getPoint'>Get 1 Point</a></div>$clearDiv<hr /></div>"; $z = 1; } } im making a website it works fine on firefox but on ie doesnt work correctly. page looks weird i see the error is <? include("index/index_files/front/php/include.php"); ?> anyone can help me its in a <html> tab. Hi. I am from poland. I am 17 old age and like webmastering. I write my social network. I have new server 10 GB VPS and my script no runing In my server. in my server do can not login. No runing function Code: [Select] mb_strtolower();as delete function mb_strtolower() ; this login runing. In my server haven`t installing liberary GD and no runing upload avatars. my code upload is: elseif ($_GET['act'] == "upload") { echo <<< KONIEC <hr> <center> <p> <h2>Dodaj zdjęcie</h2> <ul class="gallery clearfix"> <li class="extra"> KONIEC; error_reporting(E_ALL); // we first include the upload class, as we will need it here to deal with the uploaded file include('include/class.upload.php'); // retrieve eventual CLI parameters $cli = (isset($argc) && $argc > 1); if ($cli) { if (isset($argv[1])) $_GET['file'] = $argv[1]; if (isset($argv[2])) $_GET['dir'] = $argv[2]; if (isset($argv[3])) $_GET['pics'] = $argv[3]; } // set variables $dir_dest = (isset($_GET['dir']) ? $_GET['dir'] : 'test'); $dir_pics = (isset($_GET['pics']) ? $_GET['pics'] : $dir_dest); if (!$cli) { } // we have three forms on the test page, so we redirect accordingly if ((isset($_POST['action']) ? $_POST['action'] : (isset($_GET['action']) ? $_GET['action'] : '')) == 'simple') { // ---------- SIMPLE UPLOAD ---------- // we create an instance of the class, giving as argument the PHP object // corresponding to the file field from the form // All the uploads are accessible from the PHP object $_FILES $handle = new Upload($_FILES['my_field']); // then we check if the file has been uploaded properly // in its *temporary* location in the server (often, it is /tmp) if ($handle->uploaded) { // yes, the file is on the server // now, we start the upload 'process'. That is, to copy the uploaded file // from its temporary location to the wanted location // It could be something like $handle->Process('/home/www/my_uploads/'); $handle->Process($dir_dest); function TestProcess(&$handle, $title = 'test', $details='') { global $dir_pics, $dir_dest; $unlink = 'test/'. $handle->file_dst_name; $myid = $_SESSION['id']; $opis = htmlspecialchars(stripslashes(strip_tags(trim($_POST["opis"]))), ENT_QUOTES); $handle->Process($dir_dest); if ($handle->processed) { unlink("$unlink"); $link = ''.$dir_pics.'/' . $handle->file_dst_name .''; $addphoto = mysql_query("INSERT INTO photo VALUES('', '$myid', '$link', '$opis')"); echo <<< KONIEC <br> <center> <img src="$link" > <br> <br /> </center> KONIEC; } else { echo '<fieldset class="classuploadphp">'; echo ' <legend>' . $title . '</legend>'; echo ' Error: ' . $handle->error . ''; if ($details) echo ' <pre class="code php">' . htmlentities($details) . '</pre>'; echo '</fieldset>'; } } if (!file_exists($dir_dest)) mkdir($dir_dest); // ----------- $handle->image_convert = 'jpg'; $handle->image_resize = true; $handle->image_ratio_y = true; $handle->image_x = 500; $handle->image_precrop = 15; $handle->image_watermark = "watermark_large.png"; $handle->image_watermark_x = 20; $handle->image_watermark_y = -20; TestProcess($handle, '15px pre-cropping (before resizing 800 wide), large watermark automatically reduced, position 20 -20', "\$foo->image_convert = 'jpg';\n\$foo->image_resize = true;\n\$foo->image_ratio_y = true;\n\$foo->image_x = 800;\n\$foo->image_precrop = 15;\n\$foo->image_watermark = 'watermark_large.png';\n\$foo->image_watermark_x = 20;\n\$foo->image_watermark_y = -20;"); } else { // one error occured echo '<fieldset>'; echo ' <legend>file not uploaded to the wanted location</legend>'; echo ' Error: ' . $handle->error . ''; echo '</fieldset>'; } // we copy the file a second time // we delete the temporary files $handle-> Clean(); } else { // if we are here, the local file failed for some reasons echo '<fieldset>'; echo ' <legend>local file error</legend>'; echo ' Error: ' . $handle->error . ''; echo '</fieldset>'; } echo <<< KONIEC <li> </ul> </p> </center> KONIEC; is it the only problem that isn`t installing GD as i have something off in php.ini ? Plise Help me i'm getting this erro "Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 3 in /***/***/*****.php on line 278 not an active session, starts new" this is the code: if ($phase = mysql_result(mysql_query("SELECT `phase` FROM `as_support` WHERE `mission` = '$var2'"),0,0)) { if ($phase=='5') { // mysql_query("DELETE FROM `as_support` WHERE `mission` = '$var2'"); // header("Location: https://www.**********/*******/*******.php"); } else { echo date('h:i:s') . ": PHASE is $phase<br />"; echo "\$var1=$var1,\$var2=$var2<br />"; } } else { echo "not an active session, starts new<br />"; echo "\$var1=$var1,\$var2=$var2<br />"; mysql_query("INSERT INTO `as_support` (`mission`, `phase`) VALUES ('$var2', '0')") OR DIE(mysql_error()); the first line is line no. 278 can someone please tell me what to do? tnx shirley Hi, im creating a script for a website that will list products, i have the basic construct which lists the products from the database but it lists then vertically, i have set the width of each 'product' to 200px so i could have around 3 colums and many rows. can anybody advise how i would make them run vertically aswell as horizontally? my code below: <?php include_once("include/globals.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <link href="styles/stylesheet.css" rel="stylesheet" type="text/css" /> </head> <body> <div id="main"> <?php //Get database Results $result = mysql_query("SELECT * FROM Products WHERE is_active = 1") or die(mysql_error()); //keeps getting the next row until no more records while($row = mysql_fetch_array($result)) { //echo results ($result) echo '<div id="holder">'; echo '<div class="title">' . $row['Name'] . '</div>'; //insert image here echo '<div class="image">'; echo '<img src="' . $row['image'] . '" width="100" alt="">'; echo '</div>'; echo '<div class="tag_line">'; echo $row['Tag_Line']; echo '</div>'; echo '<div class="price">Now Only: £'; echo $row['Website_Price']; echo '</div>'; echo '<div class="prod-footer"></div>'; echo '</div>'; } ?> </div> </body> </html> table structu Field Type Null Default Comments MIME ID int(11) No product_code varchar(255) No Name varchar(255) Yes NULL Tag_Line varchar(255) Yes NULL Description varchar(255) Yes NULL Specification varchar(255) Yes NULL Technical_Info varchar(255) Yes NULL Cost_Price_USD decimal(10,2) Yes NULL Cost_Price_GBP decimal(10,2) Yes NULL Built_in_delivery decimal(10,2) Yes NULL Trade_Price decimal(10,2) Yes NULL Trade_Plus_Price decimal(10,2) Yes NULL Website_Price decimal(10,2) Yes NULL Is_active int(1) No image varchar(255) Yes NULL I do not receive email for my published php file which is: <?php ///// easend.php ///// $youremail = "acdelco40108@yahoo.com"; /*put the email address here, between quotes, the email address you want the message sent to*/ $to = $youremail; $email = $_POST['EMail']; $name2 = $_POST['Name']; $street2 = $_POST['Street']; $city2 = $_POST['City']; $state2 = $_POST['State']; $zip2 = $_POST['Zip']; $Phone = $_POST['Home_Phone']; $Cell = $_POST['Cell_Phone']; $education = $_POST['email1']; $comments = $_POST['email2'] ; $headers = "From:" . $email; $fields = array(); $fields{"Name"} = "Name"; $fields{"Street"} = "Street"; $fields{"City"} = "City"; $fields{"State"} = "State"; $fields{"Zip"} = "Zip"; $fields{"Home_Phone"} = "Home Phone"; $fields{"Cell_Phone"} = "Cell Phone"; $fields{"EMail"} = "Email"; $fields{"email1"} = "Education"; $fields{"email2"} = "Comments"; $subject = "We have received the following information from your employment application"; $body = "We have received the following information from your employment application:\n\n"; foreach($fields as $a => $b) { $body .= sprintf("%20s: %s\n",$b,$_POST[$a]); } mail ($to, $subject, $body, $headers); //send mail to owner #end create email vars $headers = "From:" . $to; mail ($email, $subject, $body, $headers); //send mail to user #end create email vars echo "<head><META HTTP-EQUIV=\"Refresh\" CONTENT=\"2; URL=ThankYou.html\"></head>"; ?> I have a simple text file called bio.txt: Code: [Select] wohlersr; Richie Wohlers; Intermediate; Four Aces meyersg; Greg Meyers; Novice; Four Aces I wrote a little script, to return the info for Greg Meyers if the user id is correct, or say "Member not found" if incorrect. For some reason, my output is giving me both. I assume it's a context error, but can't figure it out. Here's my script: Code: [Select] <?php $file=file("bio.txt"); $count=count($file); $i=0; while($i<=$count) { $row = explode(";", $file[$i]); $id = $row[0]; $name = $row[1]; $class = $row[2]; $club = $row[3]; if($id=="meyersg"){ echo $name."</br>"; echo $class."</br>"; echo $club."</br>"; }else{ echo "Member not found."; } $i++; } ?> And here's the output I'm getting: Code: [Select] Member not found. Greg Meyers Novice Four Aces Member not found. Hi, i use mysql_real_escape_string() function when insert in db, but when echo i use htmlentities($var, ENT_QUOTES, "UTF-8") Now problem is '\ in that text. In db it write text with single quote with \, example That\'s wrong, and when echo it show just the same like in db.. How can i fix this ? |