PHP - Convert String Into Integer
how can i convert string type into integer like when using parseInt in javascript...however i use (int)$string but not working
i have this $string1="10"; $string2="5"; and i wish to add both string ....using (int) still treat $string1 and $string2 as string so i get 105 as a result instead of 15 Similar TutorialsHey, If i have a string which contains numbers and symbols... such as 1:2:4 (its not always : for the symbol it changes) Is there a function that can convert the numbers that are 9 or less to have a 0 infront of them such as: 01:02:04 (also this is not timestamp format - just normal strings) I am making a online Bible with search function. I was able to do the boolean search for text keywords without much trouble. Now I want a user to be able to type in an exact verse into search form and have that verse display in results. IE: User types in John 3:16 and search result displays that verse. The following works if the user types John:3:16. I cannot figure out how to do this without requiring the user to type a : after book name. Code: [Select] if($search_type=='verse'){ $query2 = explode(":", $query); $bookquery = $query2[0]; $chapterquery = $query2[1]; $versequery = $query2[2]; $result4 = $db->sql_query("select * FROM Bible$version WHERE book = '$bookquery' AND chapter= '$chapterquery' AND verse ='$versequery'"); while ($row = $db->sql_fetchrow($result4)) { $book = $row['book']; $chapter = $row['chapter']; $verse = $row['verse']; $scripture = $row['scripture']; echo "<b><a href=\"modules.php?name=Bible&call=chapter&viewbook=$book&viewchapter=$chapter&version=$version\">$book</a> $chapter:$verse</b>"; echo "<br>"; echo "$scripture"; echo "<hr>"; } if(!$query){ echo "<b>You did NOT enter any keywords.</b><br>"; } if(!$scripture){ echo "<b>No results found.</b>"; } } } Is there a function to find first integer in the string and insert a : before it? Hello guys, I have a form where you can select a score between 0 and 10(only integers).
I want to check if the value that I recive, is integer.
Im using this code(exemple):
$integer = intval($_POST["p1"]); if(is_int($integer)){ echo 'INT'; } else { echo 'NO INT'; }My problem is that if it recive letters, the conversion converts it to 0, and it says that it is integer. So with this method I should discard the 0. You guys know a method to avoid that? Thank you guys Hi, When I run the following code... <?php if ($_GET['view']) { echo 'test'; } .. and then navigate to index.php?view=1 the above code outputs 'test', as intended. The same goes for any non-zero value after the ?view= However, navigating to index.php?view=0 does not work as intended because it assumes that the 0 is FALSE. So if I modify the code, like this: <?php if ($_GET['view'] || $_GET['view'] == 0) { echo 'test'; } ... it outputs 'test' even when view is not set, i.e. when I navigate to index.php without the ?view=. Is there an easy way to force the value to behave as an integer instead of boolean? I have tried putting (int) before, as well as the intval() function, but neither seem to work. Thanks. I want to perform a query which returns a subset of the fields in a table. One particular mySQL field is VARCHAR I have a query like this: $query = mysql_query("SELECT * FROM table WHERE code LIKE '3%') ; It's my understanding this should return all values which begin with "3", but it only returns about a dozen of the values 3, 30-39, 300-399, etc. (It works with string fields, but this field contains numerals.) Any help appreciated. thanks, Tom //$value1 = $_POST['game']; $value1 = "game7h"; if (strpos($value1, 'a')) { $team = 'a'; }elseif (strpos($value1, 'h')) { $team = 'h'; } if (strpos($value1, '7')) { $num = '7'; } elseif (strpos($value1, '8')) { $num = '8'; } elseif (strpos($value1, '9')) { $num = '9'; } $gm7hodds = $games[41]["BP"]; $gm7aodds = $games[40]["BP"]; $gm8hodds = $games[47]["BP"]; $gm8aodds = $games[46]["BP"]; $gm9hodds = $games[53]["BP"]; $gm9aodds = $games[52]["BP"]; /* $getratio = $num + $team; echo $getratio; Team is not a math operation so I'll finesse that later. */ $findratio = 'gm' . $num . 'h' . 'odds'; echo $findratio; gm7hodds How would I add the $ to it and return its array value $gm7hodds? Solved whoops -> echo eval('return $'. $findratio. ';'); Edited April 28 by Minzersolved I have a form that submits G How can I convert this to string of time when I need to insert it into the database and then turn it back around when it needs to be read? <option>11:00 AM</option> <option>11:30 AM</option> <option>12:00 PM</option> <option>12:30 PM</option> <option>1:00 PM</option> <option>1:30 PM</option> Thank you.
<?php $srs = array(); for ($section = 1; $section < 5; $section++) { for ($row = $section; $row < 10; $row++) { for ($seat = $row; $seat < 20; $seat++) { $srs[] = array( 'section_name' => $section, 'row_name' => $row, 'seat_name' => $seat); } } } output(convert_array($srs)); // Converts the array function convert_array($input) { return $input; } function output($obj) { echo "<pre>"; print_r($obj); echo "</pre>"; die; } ?>
I'm trying to convert those array number to string, add implode() to make it happen, but seem PHP didn't recognize variable in $input. Like this implode("Section: ", $input) or (Section: ", $srs). Can you help me? Thanks, Gary Edited October 16, 2019 by sigmahokiesHi everybody, I need some help about how to convert string to array name. I have the following function which pass $_REQUEST type as parameter. It is not working because I don't know how to convert $method to $_GET or $_POST in a proper way. Do anybody know how? Code: [Select] function validateIfFilled($method, $fields) { $exploded=explode(",",$fields); foreach($exploded as $field){ if(empty($method[trim($field)])){ return false; } } return true; }; if(!validateIfFilled('$_GET', "email, password, address")) ... Thank you! Hi, Sorry, me again! Ok, so i've got my url: http://www.mydomain.com/?ec3_after=2010-08-01&ec3_before=2010-08-07 I've then got the following code to get the values: $afterDateParts = split("-", $_GET['ec3_after']); $after = $afterDateParts[2] . " " . $afterDateParts[1] . " " . $afterDateParts[0]; echo $after; which returns: 01 08 2010 (correct for this demo) I've then got this to convert the above into a nicer format: $convertMe = strtotime($after); echo date('d-M-Y', $convertMe); But it always returns: 01 Jan 1970 For the love of god, I cannot work out why. Is it really not that simple? Please someone put me out my misery. I'm loosing hair by the minute! Lol TIA I have ip_addresses stored in the database as unsigned integers. I want to display them in standard xxx.xxx.xxx.xxx format in a table. In my code, I tried the following: <?php while ($row = $query->fetch()) { $address = inet_ntoa($row['IP_ADDRESS']); //Throws error here echo "<tr>"; // echo "<td>" . $row['IP_ADDRESS'] ."</td>"; echo "<td>" . $row['$address'] ."</td>"; echo "<td>" . $row['FILENAME'] ."</td>"; echo "<td>" . $row['country'] . "</td>"; echo "<td>" . $row['area'] . "</td>"; echo "<td>" . $row['city'] . "</td>"; echo "</tr>"; } ?> It throws the following error: Parse error: syntax error, unexpected 'inet_ntoa' (T_STRING) in /home/larry/web/test/public_html/report1.php on line 205 How do I do the conversion so I can display the ip_address? Thanks in advance, Larry
I have a simple form and need to convert it to XML so I can send it to my payment gateway. I have the XML data types (?) they are expecting, but do not have a clue of how to build the string. Can someone help me out? Thanks, Debbie I got a response from an api in json. How do i echo out the account_name in string. Thanks as usual. The response is below...
{ "status": true, "message": "Account number resolved", "data": { "account_number": "2067483918", "account_name": "BABALOLA MAYOWA ABEL", "bank_id": 18 } } "status": true, "message": "Account number resolved", "data": { "account_number": "2067483918", "account_name": "BABALOLA MAYOWA ABEL", "bank_id": 18 } }
Code: [Select] <?php $myServer = "202.138.125.155"; $myUser = "micro_fms"; $myPass = "micro_fms*#$"; $myDB = "micro_fms"; //create an instance of the ADO connection object $conn = new COM("ADODB.Connection")or die("Cannot start ADO"); //define connection string, specify database driver $connStr = "PROVIDER='SQLOLEDB'; SERVER=".$myServer.";UID=".$myUser.";PWD=".$myPass.";DATABASE=".$myDB; //Open the connection to the database $conn->open($connStr); //$table_name=$_GET['Device']; $table_data=$_GET['Data']; $data=(explode(",",$table_data)); $table_name=$data[0]; $speed=$data[1]; $time=$data[2]; $date=$data[3]; $lat=$data[4]; $long=$data[5]; //$newdate = substr($date,6,2) . "-" . substr($date,0,2) . "-" substr($date,3,2); $datetime=$date.$time; $new_lat = substr($lat,0,2).'.'.substr($lat,2); $new_long = substr($long,0,2).'.'.substr($long,2); echo $table_name."<br>"; echo $speed."<br>"; echo $new_lat."<br>"; echo $new_long."<br>"; echo $datetime."<br>"; $query="insert into $table_name (DeviceNumber,Speed,dtDateTime,Latitude,Longitude)values('$table_name','$speed','$datetime','$new_lat','$new_long')"; //execute the SQL statement and return records $rs = $conn->execute($query); if($rs) { echo 'Values Inserted'; } else { echo "faile"; } ?> Hi friends... I have two variables ($date and $time). I concat these two strings and make a new variable called "$datetime". Now in above code I want to insert it into table but I got the following error. Code: [Select] Fatal error: Uncaught exception 'com_exception' with message '<b>Source:</b> Microsoft OLE DB Provider for SQL Server<br/><b>Description:</b> Conversion failed when converting datetime from character string.' in C:\wamp\www\FMS\fms.php:44 Stack trace: #0 C:\wamp\www\FMS\fms.php(44): com->execute('insert into A00...') #1 {main} thrown in C:\wamp\www\FMS\fms.php on line 44 In my database, data type of column in which I want to insert is Date time stamp though I have string type ($datetime) variable. I think I have to convert this $datetime variable string to "DateTime type first but don't have any idea about it. Please help??/ Thanks in advance.... I'm hitting a SQL Server db and every table has a ts (timestamp) field that is a binary datatype - 8 bytes. Is there a way to "read" the binary and output it as a string? How can i convert an array of results to a single comma separated string so that I can run it through an SQL query? Hello, i have the code below and i need to have all results in a variable as a string, inside the loop they are displayed how i want but outside will echo the last result. Thank You. Code: [Select] foreach($_POST as $key=>$value){ if (is_numeric($value)) { $valoare = "$value,"; } } echo $valoare; Well the topic may not sound very explicit. So I'll do my best to explain it here. I have a pull down menu as part of a form, which contains the months of the year. I'm trying to store the value of this form entry using the $_POST['month'] variable into a database but first, I need to convert the month values into their corresponding integer values( that is 1 for January, 2 for February etc), in order to easily do date calculations later down the road. Any ideas about how to do this? It may be helpful to include the code for the pull down menu. Code: [Select] <p><tab> Date of Birth: <?php //Make the month pull down menu. //Array to store months. $months = array (1 => 'January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December'); print '<select name= "month">'; foreach ($months as $key => $value) { print "\n<option value=\"$key\">$value</option>"; } print '</select>'; ?> </tab> <tab> <?php //Make the day pull down menu print '<select name= "day">'; for ($day = 1; $day <= 31; $day++) { print "\n<option value=\"$day\">$day</option>"; } print '</select>'; ?> </tab> <tab><?php //Make the year pull down menu print '<select name= "year">'; $start_year = date('Y'); for ($y = ($start_year - 18); $y >= 1900; $y--) { print "\n<option value=\"$y\">$y</option>"; } print '</select>'; ?> </tab> </p>
Hello All, function convertTimeFormat($time12Hour) { // Initialized required variable to an empty string. $time24Hour = ""; // Used explode() function to break the string into an array and stored its value in $Split variable. $Split = explode(":",$time12Hour); // print_r(explode (":", $time12Hour)); => Array ( [0] => 09 [1] => 50 [2] => 08AM ) // Retrieved only "hour" from the array and stored in $Hour variable. $Hour = $Split[0]; $Split[2] = substr($Split[2],0,2); // Used stripos() function to find the position of the first occurrence of a string inside another string. if($Hour == '12' && strpos($time12Hour,"AM")!== FALSE) { // Code here } elseif(strpos($time12Hour,"PM")!== FALSE && $Hour != "12") { // code here } return $time24Hour; } $time12Hour = "09:50:08AM"; $result = convertTimeFormat($time12Hour); print_r($result); /* Input : "09:50:08AM"; Output : "21:50:08PM"; */
Hi, I am trying to convert a String date into numeric date using PHP function's, but haven't found such function. Had a look at date(), strtotime(), getdate(); e.g. Apr 1 2011 -> 04-01-2011 Could someone please shed some light on this? Regards, Abhishek |