PHP - Convert String To Date Issue
Hi,
Sorry, me again! Ok, so i've got my url: http://www.mydomain.com/?ec3_after=2010-08-01&ec3_before=2010-08-07 I've then got the following code to get the values: $afterDateParts = split("-", $_GET['ec3_after']); $after = $afterDateParts[2] . " " . $afterDateParts[1] . " " . $afterDateParts[0]; echo $after; which returns: 01 08 2010 (correct for this demo) I've then got this to convert the above into a nicer format: $convertMe = strtotime($after); echo date('d-M-Y', $convertMe); But it always returns: 01 Jan 1970 For the love of god, I cannot work out why. Is it really not that simple? Please someone put me out my misery. I'm loosing hair by the minute! Lol TIA Similar TutorialsHi, I am trying to convert a String date into numeric date using PHP function's, but haven't found such function. Had a look at date(), strtotime(), getdate(); e.g. Apr 1 2011 -> 04-01-2011 Could someone please shed some light on this? Regards, Abhishek I have tried a large number of "solutions" to this but everytime I use them I see 0000-00-00 in my date field instead of the date even though I echoed and can see that the date looks correct. Here's where I'm at: I have a drop down for the month (1-12) and date fields (1-31) as well as a text input field for the year. Using the POST array, I have combined them into the xxxx-xx-xx format that I am using in my field as a date field in mysql. <code> $date_value =$_POST['year'].'-'.$_POST['month'].'-'.$_POST['day']; echo $date_value; </code> This outputs 2012-5-7 in my test echo but 0000-00-00 in the database. I have tried unsuccessfully to use in a numberof suggested versions of: strtotime() mktime Any help would be extremely appreciated. I am aware that I need to validate this data and insure that it is a valid date. That I'm okay with. I would like some help on getting it into the database. Hi In sql we have dates like this 134238 In php it shows - 19:10:11 . we can make it by using date('d.m.y', $date); where $date=134238 ; my question is how can we turn 19:10:11 in to 134238 using PHP
<?php $srs = array(); for ($section = 1; $section < 5; $section++) { for ($row = $section; $row < 10; $row++) { for ($seat = $row; $seat < 20; $seat++) { $srs[] = array( 'section_name' => $section, 'row_name' => $row, 'seat_name' => $seat); } } } output(convert_array($srs)); // Converts the array function convert_array($input) { return $input; } function output($obj) { echo "<pre>"; print_r($obj); echo "</pre>"; die; } ?>
I'm trying to convert those array number to string, add implode() to make it happen, but seem PHP didn't recognize variable in $input. Like this implode("Section: ", $input) or (Section: ", $srs). Can you help me? Thanks, Gary Edited October 16, 2019 by sigmahokiesHi everybody, I need some help about how to convert string to array name. I have the following function which pass $_REQUEST type as parameter. It is not working because I don't know how to convert $method to $_GET or $_POST in a proper way. Do anybody know how? Code: [Select] function validateIfFilled($method, $fields) { $exploded=explode(",",$fields); foreach($exploded as $field){ if(empty($method[trim($field)])){ return false; } } return true; }; if(!validateIfFilled('$_GET', "email, password, address")) ... Thank you! I have a form that submits G How can I convert this to string of time when I need to insert it into the database and then turn it back around when it needs to be read? <option>11:00 AM</option> <option>11:30 AM</option> <option>12:00 PM</option> <option>12:30 PM</option> <option>1:00 PM</option> <option>1:30 PM</option> Thank you. //$value1 = $_POST['game']; $value1 = "game7h"; if (strpos($value1, 'a')) { $team = 'a'; }elseif (strpos($value1, 'h')) { $team = 'h'; } if (strpos($value1, '7')) { $num = '7'; } elseif (strpos($value1, '8')) { $num = '8'; } elseif (strpos($value1, '9')) { $num = '9'; } $gm7hodds = $games[41]["BP"]; $gm7aodds = $games[40]["BP"]; $gm8hodds = $games[47]["BP"]; $gm8aodds = $games[46]["BP"]; $gm9hodds = $games[53]["BP"]; $gm9aodds = $games[52]["BP"]; /* $getratio = $num + $team; echo $getratio; Team is not a math operation so I'll finesse that later. */ $findratio = 'gm' . $num . 'h' . 'odds'; echo $findratio; gm7hodds How would I add the $ to it and return its array value $gm7hodds? Solved whoops -> echo eval('return $'. $findratio. ';'); Edited April 28 by Minzersolved how can i convert string type into integer like when using parseInt in javascript...however i use (int)$string but not working i have this $string1="10"; $string2="5"; and i wish to add both string ....using (int) still treat $string1 and $string2 as string so i get 105 as a result instead of 15 Hi all, I'm having a bit of trouble a script running on a site where it converts a date of birth in a database shown like this '30/04/1993' to an actual age, for instance 18 in this case. Only the script I'm using below shows this age as 17, not 18 as it should be. Code: [Select] <?php $birthday = $row_getdets['dob']; function birthday ($birthday){ list($day,$month,$year) = explode("/",$birthday); $day_diff = date("d") - $day; $month_diff = date("m") - $month; $year_diff = date("Y") - $year; if ($day_diff < 0 || $month_diff < 0) $year_diff--; return $year_diff; } ?> So i've tried to remedy this myself with the following: Code: [Select] <?php $birthday = $row_getdets['dob']; function birthday ($birthday){ list($year,$month,$day) = explode("/",$birthday); $year_diff = date("Y") - $year; $month_diff = date("m") - $month; $day_diff = date("d") - $day; if ($month_diff < 0) $year_diff--; else if (($month_diff==0) && ($day_diff < 0)) $year_diff--; return $year_diff; } ?> ..but I'm having a syntax error (unexpected T_LINE), most probably down to my novice ability, I bet I've missed something simple. I'm still learning guys and I'd really appreciate any help at all. Is it possible to convert time(); to date();? while I'm reading the cell value '20/09/1980' from an excel file using phpexcel class method $student[$i]['d_o_b'] = $objWorksheet->getCell('G' . $intRow)->getValue(); getting the value as '29484' pls help me to convert it into the date format again. I have a simple form and need to convert it to XML so I can send it to my payment gateway. I have the XML data types (?) they are expecting, but do not have a clue of how to build the string. Can someone help me out? Thanks, Debbie I got a response from an api in json. How do i echo out the account_name in string. Thanks as usual. The response is below...
{ "status": true, "message": "Account number resolved", "data": { "account_number": "2067483918", "account_name": "BABALOLA MAYOWA ABEL", "bank_id": 18 } } "status": true, "message": "Account number resolved", "data": { "account_number": "2067483918", "account_name": "BABALOLA MAYOWA ABEL", "bank_id": 18 } }
Code: [Select] <?php $myServer = "202.138.125.155"; $myUser = "micro_fms"; $myPass = "micro_fms*#$"; $myDB = "micro_fms"; //create an instance of the ADO connection object $conn = new COM("ADODB.Connection")or die("Cannot start ADO"); //define connection string, specify database driver $connStr = "PROVIDER='SQLOLEDB'; SERVER=".$myServer.";UID=".$myUser.";PWD=".$myPass.";DATABASE=".$myDB; //Open the connection to the database $conn->open($connStr); //$table_name=$_GET['Device']; $table_data=$_GET['Data']; $data=(explode(",",$table_data)); $table_name=$data[0]; $speed=$data[1]; $time=$data[2]; $date=$data[3]; $lat=$data[4]; $long=$data[5]; //$newdate = substr($date,6,2) . "-" . substr($date,0,2) . "-" substr($date,3,2); $datetime=$date.$time; $new_lat = substr($lat,0,2).'.'.substr($lat,2); $new_long = substr($long,0,2).'.'.substr($long,2); echo $table_name."<br>"; echo $speed."<br>"; echo $new_lat."<br>"; echo $new_long."<br>"; echo $datetime."<br>"; $query="insert into $table_name (DeviceNumber,Speed,dtDateTime,Latitude,Longitude)values('$table_name','$speed','$datetime','$new_lat','$new_long')"; //execute the SQL statement and return records $rs = $conn->execute($query); if($rs) { echo 'Values Inserted'; } else { echo "faile"; } ?> Hi friends... I have two variables ($date and $time). I concat these two strings and make a new variable called "$datetime". Now in above code I want to insert it into table but I got the following error. Code: [Select] Fatal error: Uncaught exception 'com_exception' with message '<b>Source:</b> Microsoft OLE DB Provider for SQL Server<br/><b>Description:</b> Conversion failed when converting datetime from character string.' in C:\wamp\www\FMS\fms.php:44 Stack trace: #0 C:\wamp\www\FMS\fms.php(44): com->execute('insert into A00...') #1 {main} thrown in C:\wamp\www\FMS\fms.php on line 44 In my database, data type of column in which I want to insert is Date time stamp though I have string type ($datetime) variable. I think I have to convert this $datetime variable string to "DateTime type first but don't have any idea about it. Please help??/ Thanks in advance.... I have ip_addresses stored in the database as unsigned integers. I want to display them in standard xxx.xxx.xxx.xxx format in a table. In my code, I tried the following: <?php while ($row = $query->fetch()) { $address = inet_ntoa($row['IP_ADDRESS']); //Throws error here echo "<tr>"; // echo "<td>" . $row['IP_ADDRESS'] ."</td>"; echo "<td>" . $row['$address'] ."</td>"; echo "<td>" . $row['FILENAME'] ."</td>"; echo "<td>" . $row['country'] . "</td>"; echo "<td>" . $row['area'] . "</td>"; echo "<td>" . $row['city'] . "</td>"; echo "</tr>"; } ?> It throws the following error: Parse error: syntax error, unexpected 'inet_ntoa' (T_STRING) in /home/larry/web/test/public_html/report1.php on line 205 How do I do the conversion so I can display the ip_address? Thanks in advance, Larry
Hello, i need a fast convertor that converts the date format 03-03-2008, 08:26 PM into a timestamp fast. Like, you paste 03-03-2008, 08:26 PM into a post form, submit and it gives you the time stamp. I made a convertor a whille ago, but you need to insert each numbers into a separate input box (day, months, year etc) I cant remember how exactly it functions etc asi haventtouched PHP In a while..... sorry, I know this is simple, but stuck on it... how would one go about converting 1/21/11 to a UNIX timestamp, something like 1293035229? and while we are at it, how to convert 1293035229 to 1/21/11 ? (i know the timestamp is wrong, just for example) thanks!!!!! hello, i have the following code and it is ok. what im trying to do is convert a 2010-09-20 post from a form and have it read out as Monday September 20, 2010. is this possible? Code: [Select] $dateselected="$_POST[Y]-$_POST[M]-$_POST[D]"; echo "<table border='1'>"; echo "<tr><td width='100%' colspan='4' align='center'>$_POST[M]-$_POST[D]-$_POST[Y]</td></tr>"; 2011-02-05T18:07:57.00+0000 This is a string. How can i convert an array of results to a single comma separated string so that I can run it through an SQL query? |