PHP - How Can I Get The Current Script's Filename Without Path Info?

I want to validate my PHP files to ensure that I didn't forget to import all the classes assigned to attributes.  I will be using ReflectionClass to do so and need the FQCN's and not the filenames.  Originally, I tried get_declared_classes(), however, ran into issues where a class was already declared.  I came up with the following which appears to work, however, it was created based on trial and error and suspect there might be edge cases where it will not provide the desired results (and it is pretty damn ugly as well).  How would you recommend doing so?  A couple thoughts a

PS.  I originally wasn't 100% that attributes in traits and abstract classes would be propagated to the concrete class, but I should have known it to be true and this was confirmed by testing.  At this time, I really just need the concrete classes, however, maybe in the future I will use the script to do some analysis on interfaces, traits, etc. 

    private function parseFile(string $filename):array
    {
        $getNext=null;
        $getNextNamespace=false;
        $skipNext=false;
        $isAbstract = false;
        $rs = ['namespace'=>null, 'class'=>[], 'trait'=>[], 'interface'=>[], 'abstract'=>[]];
        foreach (\PhpToken::tokenize(file_get_contents($filename)) as $token) {
            if(!$token->isIgnorable()) {
                $name = $token->getTokenName();
                switch($name){
                    case 'T_NAMESPACE':
                        $getNextNamespace=true;
                        break;
                    case 'T_EXTENDS':
                    case 'T_USE':
                    case 'T_IMPLEMENTS':
                        //case 'T_ATTRIBUTE':
                        $skipNext = true;
                        break;
                    case 'T_ABSTRACT':
                        $isAbstract = true;
                        break;
                    case 'T_CLASS':
                    case 'T_TRAIT':
                    case 'T_INTERFACE':
                        if($skipNext) {
                            $skipNext=false;
                        }
                        else {
                            $getNext = strtolower(substr($name, 2));
                        }
                        break;
                    case 'T_NAME_QUALIFIED':
                    case 'T_STRING':
                        if($getNextNamespace) {
                            if(array_filter($rs)) {
                                throw new \Exception(sprintf('Namespace mus be defined first in %s', $filename));
                            }
                            else {
                                $rs['namespace'] = $token->text;
                            }
                            $getNextNamespace=false;
                        }
                        elseif($skipNext) {
                            $skipNext=false;
                        }
                        elseif($getNext) {
                            if(in_array($token->text,  $rs[$getNext])) {
                                throw new \Exception(sprintf('%s %s has already been found in %s', $rs[$getNext], $token->text, $filename));
                            }
                            if($isAbstract) {
                                $isAbstract=false;
                                $getNext = 'abstract';
                            }
                            $rs[$getNext][]=$token->text;
                            $getNext=null;
                        }
                        break;
                    default:
                        $getNext=null;
                }
            }
        }
        $rs['filename'] = $filename;
        return $rs;
    }

I am trying to get the actual filename so that I can attach it to an email. 

I tried echo $file;  but its not giving me anything.  Just a blank page.  Here's the code that I' working with:

$file = date('M-d-Y  H:i A'). '.png';
$uri =  substr($data,strpos($data,",")+1);
file_put_contents('./Collection_Posts/'.$file, base64_decode($uri));
echo $file;

exit;

Hi all,

I am working on the PHP to fetch the data from the database. I would like to fetch the filename only following by:

email1.png
email2.png
email3.png
my_inbox.png

When I try this:           

$mailbox_sql = 'SELECT * FROM ' . $mailfolder . ' WHERE email_id = ? AND message_id = ?';
$mailbox = $link->prepare($mailbox_sql);
$mailbox->execute([$id,$message_id]); 

// set the resulting array to associative
$row = $mailbox->fetch(PDO::FETCH_ASSOC);

if (is_array($row)) {
   $attached = $row['attached_files'];
   $attached_files_name = explode('attid: ', $attached);
}

I am getting this:

0 filename: email1.png
1 filename: email2.png
2 filename: email3.png
3 filename: my_inbox.png

Here is what I have stored in the database:

 attid: 0 filename: email1.png
 attid: 1 filename: email2.png
 attid: 2 filename: email3.png
 attid: 3 filename: my_inbox.png

Here is what I want to achieve:

email1.png
email2.png
email3.png
my_inbox.png

Can you please show me example how I could get the filename when I am fetching the data from the database?

Thanks in advance.