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PHP - Leaderboard Script
Does anyone know where I can find a php leaderboard or high scores script
Similar TutorialsHey guys, I've kind of taken over a project from a friend. It's a leaderboard for posting splits for drivers. The splits get posted to a leaderboard.xsl (which is working fine). The update.php page is designed to update a leaderboard.xml file, this way anyone can login and update new splits for each weeks race. (more info can be found here if you are curious). I found a small bug in the leaderboard.xsl file. It is meant for displaying the drivers splits, calculating the difference between drivers, what division they are, car they used and includes a 'Controller' column. This is where the bug is. Normally, it will display if that driver uses a gamepad or a steering wheel. If it's a one lap aka 'hotlap' race, the Controller column shows either a 'wheel' or 'controller' as it should. However, if it's a multi-lap race (2+ laps), then the Controller column automatically defaults to the <xsl:otherwise> option of a "?". Here is an example of the Controller column working properly for each driver: Here is what it does when there are two (or more) sets of splits for each driver on the leaderboard: The code makes the post over the character length, you can view the code here. Any assistance/help would be great appreciated as I'll be done with the project then Jerome how do i make a leaderboard that is capable of handling equal scores from a particular result? we use following points allocations: winner: 5pts second: 3pts third: 2pts fourth: 1pt however, if 2nd and 3rd have tied scores, i would like to combine their point allocations together and divide by 2, i.e. (3+2)/2=2.5points each. initial query for competition ranking: $q_lastcomp = "SELECT p.p_id, p.p_surname, p.p_forename, p.p_handicap, r.r_id, rp.rp_score, rp.rp_handicap, (rp.rp_score-rp.rp_handicap) as net_score "; $q_lastcomp .= "FROM dan_roundplayed rp, dan_round r, dan_player p "; $q_lastcomp .= "WHERE r.r_id = rp.rp_rid "; $q_lastcomp .= "AND p.p_id = rp.rp_pid "; $q_lastcomp .= "AND r.r_id = 6 "; $q_lastcomp .= "ORDER BY net_score"; $r_lastcomp = mysql_query($q_lastcomp) or die(mysql_error()); i then loop through this resultset in this order (top down), and do some more calculations to adjust the players golf handicaps based on these results too. basically, if there are 4 players, the winner has beaten 3 others, second has beaten 2 others, down to last place who has beaten no-one. the number of players you have beaten is multiplied by 10% of their handicap (not precisely this value, but something like it and makes easier to explain), then this adjustment is subtracted from the handicap to make a new handicap for the next comp. this works fine, so long as no-one is tied. but if 2nd and 3rd tie, then both players have effectively only beaten 1 other player (last placed). so i would want both to do "hcap - (1*(hcap*0.1))" for their handicap adjustment calculations. in my current code, even though they were tied, 2nd would have: "hcap - (2*(hcap*0.1))" 3rd would have: "hcap - (1*(hcap*0.1))" my current loop code is: $total_players = mysql_num_rows($r_lastcomp); $i = 1; while($row = mysql_fetch_array($r_lastcomp)){ echo "<br>"; $round_hcap = round($row[p_handicap]); SWITCH ($round_hcap){ CASE $round_hcap >= 0 AND $round_hcap <= 19: $multiplier = 0.1; break; CASE $round_hcap >= 20 AND $round_hcap <= 29: $multiplier = 0.2; break; CASE $round_hcap >= 30 AND $round_hcap <= 39: $multiplier = 0.3; break; CASE $round_hcap >= 40 AND $round_hcap <= 49: $multiplier = 0.4; break; } $hcap_reduce = ($total_players-$i)*$multiplier; $new_hcap = $row[p_handicap]-(($total_players-$i)*$multiplier); $sqlstr = "INSERT INTO dan_handicap VALUES (". $row[p_id]. ",". $row[r_id]. ",". $row[p_handicap]. ",". $i. ","; $sqlstr .= $total_players. ",". $hcap_reduce. ",". $new_hcap. ");"; $sqlstr2 = "UPDATE dan_player SET p_handicap = ". $new_hcap. " WHERE p_id = ". $row[p_id]. ";"; echo $sqlstr. "<br>"; echo $sqlstr2. "<br>"; $i++; } can anyone help with this please? my initial thoughts are i am going to need a drastic adjustment to the initial query add in position number in the comp, i.e. this would produce posn | name | score 1 | winner | 10 2 | tied 2nd | 8 2 | tied 2nd | 8 4 | last place | 5 the second section of code could then use this "position number" for the multiplier part of the calculations. apologies for the length of the post, but this covers the whole requirements. regards jingo_man Hi everyone! I've been working on a php script to replace links that contain a query with direct links to the files they would redirect to. Hi i have this upload script which works fine it uploads image to a specified folder and sends the the details to the database. but now i am trying to instead make a modify script which is Update set so i tried to change insert to update but didnt work can someone help me out please this my insert image script which works fine but want to change to modify instead Code: [Select] <?php mysql_connect("localhost", "root", "") or die(mysql_error()) ; mysql_select_db("upload") or die(mysql_error()) ; // my file the name of the input area on the form type is the extension of the file //echo $_FILES["myfile"]["type"]; //myfile is the name of the input area on the form $name = $_FILES["image"] ["name"]; // name of the file $type = $_FILES["image"]["type"]; //type of the file $size = $_FILES["image"]["size"]; //the size of the file $temp = $_FILES["image"]["tmp_name"];//temporary file location when click upload it temporary stores on the computer and gives it a temporary name $error =array(); // this an empty array where you can then call on all of the error messages $allowed_exts = array('jpg', 'jpeg', 'png', 'gif'); // array with the following extension name values $image_type = array('image/jpg', 'image/jpeg', 'image/png', 'image/gif'); // array with the following image type values $location = 'images/'; //location of the file or directory where the file will be stored $appendic_name = "news".$name;//this append the word [news] before the name so the image would be news[nameofimage].gif // substr counts the number of carachters and then you the specify how how many you letters you want to cut off from the beginning of the word example drivers.jpg it would cut off dri, and would display vers.jpg //echo $extension = substr($name, 3); //using both substr and strpos, strpos it will delete anything before the dot in this case it finds the dot on the $name file deletes and + 1 says read after the last letter you delete because you want to display the letters after the dot. if remove the +1 it will display .gif which what we want is just gif $extension = strtolower(substr($name, strpos ($name, '.') +1));//strlower turn the extension non capital in case extension is capital example JPG will strtolower will make jpg // another way of doing is with explode // $image_ext strtolower(end(explode('.',$name))); will explode from where you want in this case from the dot adn end will display from the end after the explode $myfile = $_POST["myfile"]; if (isset($image)) // if you choose a file name do the if bellow { // if extension is not equal to any of the variables in the array $allowed_exts error appears if(in_array($extension, $allowed_exts) === false ) { $error[] = 'Extension not allowed! gif, jpg, jpeg, png only<br />'; // if no errror read next if line } // if file type is not equal to any of the variables in array $image_type error appears if(in_array($type, $image_type) === false) { $error[] = 'Type of file not allowed! only images allowed<br />'; } // if file bigger than the number bellow error message if($size > 2097152) { $error[] = 'File size must be under 2MB!'; } // check if folder exist in the server if(!file_exists ($location)) { $error[] = 'No directory ' . $location. ' on the server Please create a folder ' .$location; } } // if no error found do the move upload function if (empty($error)){ if (move_uploaded_file($temp, $location .$appendic_name)) { // insert data into database first are the field name teh values are the variables you want to insert into those fields appendic is the new name of the image mysql_query("INSERT INTO image (myfile ,image) VALUES ('$myfile', '$appendic_name')") ; exit(); } } else { foreach ($error as $error) { echo $error; } } //echo $type; ?> I'm having trouble echoing $year in my script. Listed below is the script, just below ,$result = mysql_query("SELECT * FROM $dbname WHERE class LIKE '%$search%'") or die(mysql_error());, in the script I try to echo $year. It doesn't show up in the table on the webpage. Everything else works fine. Any help wold be appreciated greatly. Thanks in advance. <?php include 'config2.php'; $search=$_GET["search"]; // Connect to server and select database. mysql_connect($dbhost, $dbuser, $dbpass)or die("cannot connect"); mysql_select_db("vetman")or die("cannot select DB"); $result = mysql_query("SELECT * FROM $dbname WHERE class LIKE '%$search%'") or die(mysql_error()); // store the record of the "" table into $row //$current = ''; echo "<table align=center border=1>"; echo "<br>"; echo "<tr>"; echo "<td align=center>"; ?> <div style="float: center;"><a><h1><?php echo $year; ?></h1></a></div> <?php echo "</td>"; echo "</tr>"; echo "</table>"; // keeps getting the next row until there are no more to get if($result && mysql_num_rows($result) > 0) { $i = 0; $max_columns = 2; echo "<table align=center>"; echo "<br>"; while($row = mysql_fetch_array($result)) { // make the variables easy to deal with extract($row); // open row if counter is zero if($i == 0) echo "<tr>"; echo "<td align=center>"; ?> <div style="float: left;"> <div><img src="<?php echo $image1; ?>"></div> </div> <?php echo "</td>"; // increment counter - if counter = max columns, reset counter and close row if(++$i == $max_columns) { echo "</tr>"; $i=0; } // end if } // end while } // end if results // clean up table - makes your code valid! if($i > 0) { for($j=$i; $j<$max_columns;$j++) echo "<td> </td>"; echo '</tr>'; } mysql_close(); ?> </table> Hello, I stored a fsockopen function in a separate "called.php" file, in order to run it as another thread when it needs. The called script should return results to the "master.php" script. I'm able to run the script to get the socket working, and I'm able to get results from the called script. I tried for hours but I can't do the twice both My master.php script (with socket working): Code: [Select] <?php $command = "(/mnt/opt/www/called.php $_SERVER[REMOTE_ADDR] &) > /dev/null"; $result = exec($command); echo ("result = $result\r\n"); ?> and my called.php script Code: [Select] #!/mnt/opt/usr/bin/php-cli -q <?php $device = $_SERVER['argv'][1]; $port = "8080"; $fp = fsockopen($device, $port, $errno, $errstr, 5); fwrite($fp, "test"); fclose($fp); echo ("normal end of the called.php script"); ?> In the master script, if I use Code: [Select] $command = "(/mnt/opt/www/called.php $_SERVER[REMOTE_ADDR] &) > /dev/null"; the socket works, but I have nothing in $result (note also that I don't anderstand why the ( ... &) are needed!?) and if I use Code: [Select] $command = "/mnt/opt/www/called.php $_SERVER[REMOTE_ADDR]"; I have the correct text "normal end of the called.php script" in $result but the socket connection is not performed (no errors in php logs) Could you help me to find a way to let's work the two features correctly together? Thank you. I'm trying to use this script known as SimpleImage.php that can be found here <a href="http://www.white-hat-web-design.co.uk/articles/php-image-resizing.php">link</a> I'm trying to include what is on the bottom of the page to my existing script can anyone help me I've tried several ways but its not working. Code: [Select] <?php session_start(); error_reporting(E_ALL); ini_set('display_errors','On'); //error_reporting(E_ALL); // image upload folder $image_folder = 'images/classified/'; // fieldnames in form $all_file_fields = array('image1', 'image2' ,'image3', 'image4'); // allowed filetypes $file_types = array('jpg','gif','png'); // max filesize 5mb $max_size = 5000000; //echo'<pre>';print_r($_FILES);exit; $time = time(); $count = 1; foreach($all_file_fields as $fieldname){ if($_FILES[$fieldname]['name'] != ''){ $type = substr($_FILES[$fieldname]['name'], -3, 3); // check filetype if(in_array(strtolower($type), $file_types)){ //check filesize if($_FILES[$fieldname]['size']>$max_size){ $error = "File too big. Max filesize is ".$max_size." MB"; }else{ // new filename $filename = str_replace(' ','',$myusername).'_'.$time.'_'.$count.'.'.$type; // move/upload file $target_path = $image_folder.basename($filename); move_uploaded_file($_FILES[$fieldname]['tmp_name'], $target_path); //save array with filenames $images[$count] = $image_folder.$filename; $count = $count+1; }//end if }else{ $error = "Please use jpg, gif, png files"; }//end if }//end if }//end foreach if($error != ''){ echo $error; }else{ /* -------------------------------------------------------------------------------------------------- SAVE TO DATABASE ------------------------------------------------------------------------------------ -------------------------------------------------------------------------------------------------- */ ?> hey guys im really just after a bit of help/information on 2 things (hope its in the right forum).
1. basically I'm wanting to make payments from one account to another online...like paypal does...im wondering what I would need to do to be able to do this if anyone can shine some light please?
2.as seen on google you type in a query in the search bar and it generates sentences/keywords from a database
example:
so if product "chair" was in the database
whilst typing "ch" it would show "chair" for a possible match
I know it would in tale sql & json but im after a good tutorial/script of some sort.
if anyone can help with some information/sites it would be much appreciated.
Thank you
Well the subject line is pretty explicit. I found this script that uploads a picture onto a folder on the server called images, then inserts the the path of the image on the images folder onto a VACHAR field in a database table. Code: [Select] <?php //This file inserts the main image into the images table. //address error handling ini_set ('display_errors', 1); error_reporting (E_ALL & ~E_NOTICE); //authenticate user //Start session session_start(); //Connect to database require ('config.php'); //Check whether the session variable id is present or not. If not, deny access. if(!isset($_SESSION['id']) || (trim($_SESSION['id']) == '')) { header("location: access_denied.php"); exit(); } else{ // Check to see if the type of file uploaded is a valid image type function is_valid_type($file) { // This is an array that holds all the valid image MIME types $valid_types = array("image/jpg", "image/jpeg", "image/bmp", "image/gif"); if (in_array($file['type'], $valid_types)) return 1; return 0; } // Just a short function that prints out the contents of an array in a manner that's easy to read // I used this function during debugging but it serves no purpose at run time for this example function showContents($array) { echo "<pre>"; print_r($array); echo "</pre>"; } // Set some constants // This variable is the path to the image folder where all the images are going to be stored // Note that there is a trailing forward slash $TARGET_PATH = "images/"; // Get our POSTed variable $image = $_FILES['image']; // Sanitize our input $image['name'] = mysql_real_escape_string($image['name']); // Build our target path full string. This is where the file will be moved to // i.e. images/picture.jpg $TARGET_PATH .= $image['name']; // Make sure all the fields from the form have inputs if ( $image['name'] == "" ) { $_SESSION['error'] = "All fields are required"; header("Location: member.php"); exit; } // Check to make sure that our file is actually an image // You check the file type instead of the extension because the extension can easily be faked if (!is_valid_type($image)) { $_SESSION['error'] = "You must upload a jpeg, gif, or bmp"; header("Location: member.php"); exit; } // Here we check to see if a file with that name already exists // You could get past filename problems by appending a timestamp to the filename and then continuing if (file_exists($TARGET_PATH)) { $_SESSION['error'] = "A file with that name already exists"; header("Location: member.php"); exit; } // Lets attempt to move the file from its temporary directory to its new home if (move_uploaded_file($image['tmp_name'], $TARGET_PATH)) { // NOTE: This is where a lot of people make mistakes. // We are *not* putting the image into the database; we are putting a reference to the file's location on the server $sql = "insert into images (member_id, image_cartegory, image_date, image) values ('{$_SESSION['id']}', 'main', NOW(), '" . $image['name'] . "')"; $result = mysql_query($sql) or die ("Could not insert data into DB: " . mysql_error()); header("Location: images.php"); echo "File uploaded"; exit; } else { // A common cause of file moving failures is because of bad permissions on the directory attempting to be written to // Make sure you chmod the directory to be writeable $_SESSION['error'] = "Could not upload file. Check read/write persmissions on the directory"; header("Location: member.php"); exit; } } //End of if session variable id is not present. ?> The script seems to work fine because I managed to upload a picture which was successfully inserted into my images folder and into the database. Now the problem is, I can't figure out exactly how to write the script that displays the image on an html page. I used the following script which didn't work. Code: [Select] //authenticate user //Start session session_start(); //Connect to database require ('config.php'); $sql = mysql_query("SELECT* FROM images WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main' "); $row = mysql_fetch_assoc($sql); $imagebytes = $row['image']; header("Content-type: image/jpeg"); print $imagebytes; Seems to me like I need to alter some variables to match the variables used in the insert script, just can't figure out which. Can anyone help?? Hi, I am trying to run two scripts on one page. When I use just one script on the page they work however when I place both scripts on the same page one of them disrupts the other script. This script prevents the other following script from working: Code: [Select] ini_set('display_errors', 1); error_reporting(-1); { $query = "SELECT * FROM answers ORDER BY `aid` DESC LIMIT 0, 11"; } $result = mysql_query($query); while($row = mysql_fetch_assoc($result)) { $answer = $row['answer']; $aid = $row['aid']; echo " <div class='questionboxquestion'> <a href= 'http://www.domain.co.uk/test/easy/answer.php?aid=$aid' class='questionlink'>$answer</a> </div> <div class='questionboxnotes'> </br> </div> <div class='questionboxlinks'> <div class='questionboxcategory'> <div class='questionboxcategorytitle'> Category: </div> <a href= 'http://www.domain.co.uk/test/easy/furniture-category.php' class='questionanswerlink'></a> </div> <div class='questionboxanswerlink'> <a href= 'http://www.domain.co.uk/test/oeasy/index.php' class='questionanswerlink'>Answer</a> </div> </div> "; } Code: [Select] <?php if($error) echo "<span style=\"color:#ff0000;\">".$error."</span><br /><br />"; ?> <label for="username">Username: </label> <input type="text" name="username" value="<?php if($_POST['username']) echo $_POST['username']; ?>" /><br /> <label for="password">Password: </label> <input type="password" name="password" value="<?php if($_POST['password']) echo $_POST['password']; ?>" /><br /> <label for="password2">Retype Password: </label> <input type="password" name="password2" value="<?php if($_POST['password2']) echo $_POST['password2']; ?>" /><br /> <label for="email">Email: </label> <input type="text" name="email" value="<?php if($_POST['email']) echo $_POST['email']; ?>" /><br /><br /> <input type="submit" name="submit" value="Register" /> How would I go about making it to where,, I can tell the script to use a certain extension of php in the script like curl.. ? Thanks I have an application which runs on more than one server and need to launch one PHP script from another PHP script. Since this is different than a function call I'm not sure how it's done. I plan to include parameters in the URL I send and use GETs to pick up parameters in the "called" PHP script. Thanks for sugestions I need PHP script for create a program i have 1 header.html (which is my header file) 2 menu.html(which contain menu on right of the page) 3 footer.html(which is my footer) 4 content.html(which is my content area of the page) 5 multiple around 10 .php form pages now i want to use them into single page which have header,menu,footer as same & my php forms call on content area. so please help me out Kind of inherited this project and could use some assistance. The script below worked on a windows server running IIS and php 4. Upgraded server and PHP to version 5.5.3 and the script no longer works. Keep getting an error of undefined variable for the following lines of code:
$name=strtoupper($name); error Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/nrkgamin/public_html/perp/gameserver/fetch_users5.php on line 7 Code: [Select] <?php mysql_connect("xxxxxxx", "xxxxxxxx", "xxxxxxx"); mysql_select_db("phpbb"); $query = mysql_query("SELECT phpbb_profile_fields_data.pf_steamid, phpbb_users.user_rank FROM user, phpbb_profile_fields_data WHERE (phpbb_users.user_rank='16' OR phpbb_users.user_rank='10' OR phpbb_users.user_rank='9' OR phpbb_users.user_rank='14' OR phpbb_users.user_rank='11' OR phpbb_users.user_rank='15' OR phpbb_users.user_rank='13' OR phpbb_users.user_rank='12' OR phpbb_users.user_rank='44' OR phpbb_users.user_rank='47') AND phpbb_users.user_id=phpbb_profile_fields_data.user_id"); while ($row = mysql_fetch_assoc($query)){ if ($row['pf_steamid'] != "" && $row['user_rank'] != ""){ echo $row['pf_steamid'] . "\t" . $row['user_rank'] . "\n"; } } ?>srr for my bad english This does not work correctly and I need help with it. If $rating is equal to zero it displays 4 stars on this page http://rwdev.whekle.com/view.php?id=4571 what I am doing wrong, it is probably a simple mistake. Code: [Select] if($rating <= '1.5'){ $star1 = "yes"; }elseif($rating <= '2.5'){ $star2 = "yes"; }elseif($rating <= '3.5'){ $star3 = "yes"; }elseif($rating <= '4.5'){ $star4 = "yes"; }elseif($rating <= '5.0'){ $star5 = "yes"; } I cant figure out why my log out script doesnt work all you need is session_start(); session_destroy(); right? here is my script to keep people loged in which works fine. Code: [Select] if ($_SESSION['login_time'] < strtotime('-60 minutes')) { header("Location: signup.php"); exit(); session_destroy(); Hi guys, I have an issue. First see the code. 1) index.php <html> <?php include 'header.php';?> <div class = "nav"> <ul> <li> Menu 1 </li> <li> Menu 2 </li> <li> Menu 3 </li> <li> Menu 4 </li> </ul> </div> <div id = "left-panel"> <ul class = "left-menu"> <li>Sub Menu 1 </li> <li>Sub Menu 2 </li> <li>Sub Menu 3 </li> <li>Sub Menu 4 </li> </ul> </div> <div class = "content"> <?php loadContent($config); ?> </div> <?php include 'footer.php' ?> </html> My Function is: function loadContent($config) { if(empty($_GET['action'])) { $_GET['action'] = "start"; } $root = "include/".$_GET['action'].".php"; if(file_exists($root)) { include($root); } } No if I press the Menu 1 in the nav class I will redirect to index.php?action=category&item=Menu1 My question is can I detect the $_GET['item']; in the index page and print it. If so how can I ? I want like : if (empty($_GET['item'])){ echo "No menu item selected"; }else{ $cat = $_GET['item']; echo $cat; } at the top of the page Hi I am looking for help with this script to update mysql db, the script will not update data but gets data from the db Many thanks ############### Code Code: [Select] <?php $host="localhost"; // Host name $username=""; // Mysql username $password=""; // Mysql password $db_name="test"; // Database name $tbl_name="test_mysql"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // get value of id that sent from address bar $id=$_GET['id']; // Retrieve data from database $sql="SELECT * FROM $tbl_name WHERE id='$id'"; $result=mysql_query($sql); $rows=mysql_fetch_array($result); ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <form name="form1" method="post" action="update_ac.php"> <td> <table width="100%" border="0" cellspacing="1" cellpadding="0"> <tr> <td> </td> <td colspan="3"><strong>Update data in mysql</strong> </td> </tr> <tr> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> </tr> <tr> <td align="center"> </td> <td align="center"><strong>Name</strong></td> <td align="center"><strong>Lastname</strong></td> <td align="center"><strong>Email</strong></td> </tr> <tr> <td> </td> <td align="center"><input name="name" type="text" id="name" value="<? echo $rows['name']; ?>"></td> <td align="center"><input name="lastname" type="text" id="lastname" value="<? echo $rows['lastname']; ?>" size="15"></td> <td><input name="email" type="text" id="email" value="<? echo $rows['email']; ?>" size="15"></td> </tr> <tr> <td> </td> <td><input name="id" type="hidden" id="id" value="<? echo $rows['id']; ?>"></td> <td align="center"><input type="submit" name="Submit" value="Submit"></td> <td> </td> </tr> </table> </td> </form> </tr> </table> <? // close connection mysql_close(); ?> ############### Code [i]update_ac.php[/i] <?php $host="localhost"; // Host name $username=""; // Mysql username $password=""; // Mysql password $db_name="test"; // Database name $tbl_name="test_mysql"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // update data in mysql database $sql="UPDATE $tbl_name SET name='$name', lastname='$lastname', email='$email' WHERE id='$id'"; $result=mysql_query($sql); // if successfully updated. if($result){ echo "Successful"; echo "<BR>"; echo "<a href='list_records.php'>View result</a>"; } else { echo "ERROR"; } ?> Hi all, i'm working on a script which will allow staff members or "admins" to move users on a html table. Basically a user clicks on a cell within a table and there username is stored in a mysql database and there username also appears in that cell and its reserved for them and other users cant take there slot. I use this for a seating plan for events. I have made an identical table which pulls the same data from the database but is only availible to staff members but i want it so when a staff member clicks on a cell or "seat" it will ask them if they want to move themselves there or another user. Here is my code i have so far: Code: [Select] <?php require ("./auth.php");?> <?php require ("../secure/connect.php");?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>SouthWest LAN's</title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <link rel="stylesheet" type="text/css" href="../css/styles.css" /> </head> <body> <!-- Begin Wrapper --> <div id="wrapper"> <!-- Begin Header --> <div id="header"><h1><br />SouthWest LAN's</h1></div> <!-- End Header --> <!-- Begin Navigation --> <div id="navigation"><ul> <li style="margin-right:15px; display:inline;"><a href="../index.php">Home</a></li> <li style="margin-right:15px; display:inline;"><a href="../gallery/">Photo Gallery</a></li> <li style="margin-right:15px; display:inline;"><a href="../events.php">Events</a></li> <li style="margin-right:15px; display:inline;"><a href="../account.php">My Account</a></li> <li style="margin-right:15px; display:inline;"><a href="../forum.php">Forums</a></li> <li style="margin-right:15px; display:inline;"><a href="../faq.php">FAQ</a></li> </ul></div> <!-- End Navigation --> <!-- Begin Content Column --> <div id="content"> <h1>Staff Seating</h1><br /> <p>Below shows where users are currently seated and you can edit where users are sitting and place users that havent yet choosen a seat.</p><br /> <p>Click a seat for options:</p><br /> <?php session_start(); $user_id = array(); $query = "SELECT * from seats_table"; $result = mysql_query($query); while($row = mysql_fetch_array($result)){ $seat_status[] = $row['taken']; } $query5 = "SELECT * from seats_table"; $result5 = mysql_query($query5); while($row5 = mysql_fetch_array($result5)){ $user_id[] = $row5['user_id']; } $get2 = mysql_query("SELECT * FROM users WHERE username='".$_SESSION['username']."'")or die(mysql_error()); ?> <fieldset> <br /> <table width="100%" border="0" align="center"> <tr> <td><b>Seat 01</b></td> <td><b>Seat 02</b></td> <td><b>Seat 03</b></td> <td><b>Seat 04</b></td> <td><b>Seat 05</b></td> <td><b>Seat 06</b></td> <td><b>Seat 07</b></td> <td><b>Seat 08</b></td> <td><b>Seat 09</b></td> <td><b>Seat 10</b></td> <td><b>Seat 11</b></td> <td><b>Seat 12</b></td> </tr> <tr> <td>Servers</td> <td>Servers</td> <td><?php if($seat_status[2]) { echo '<font color="red"><a href="admin_seat.php?seat=3">'.$user_id[2];} else { ?> <a href="admin_seat.php?seat=3"><font color="green">Availible</a></font><?php } ?></td> <td><?php if($seat_status[3]) { echo '<font color="red"><a href="admin_seat.php?seat=4">'.$user_id[3];} else { ?> <a href="admin_seat.php?seat=4"><font color="green">Availible</a></font><?php } ?></td> <td><?php if($seat_status[4]) { echo '<font color="red"><a href="admin_seat.php?seat=5">'.$user_id[4];} else { ?> <a href="admin_seat.php?seat=5"><font color="green">Availible</a></font><?php } ?></td> <td><?php if($seat_status[5]) { echo '<font color="red"><a href="admin_seat.php?seat=6">'.$user_id[5];} else { ?> <a href="admin_seat.php?seat=6"><font color="green">Availible</a></font><?php } ?></td> <td><?php if($seat_status[6]) { echo '<font color="red"><a href="admin_seat.php?seat=7">'.$user_id[6];} else { ?> <a href="admin_seat.php?seat=7"><font color="green">Availible</a></font><?php } ?></td> <td><?php if($seat_status[7]) { echo '<font color="red"><a href="admin_seat.php?seat=8">'.$user_id[7];} else { ?> <a href="admin_seat.php?seat=8"><font color="green">Availible</a></font><?php } ?></td> <td><?php if($seat_status[8]) { echo '<font color="red"><a href="admin_seat.php?seat=9">'.$user_id[8];} else { ?> <a href="admin_seat.php?seat=9"><font color="green">Availible</a></font><?php } ?></td> <td><?php if($seat_status[9]) { echo '<font color="red"><a href="admin_seat.php?seat=10">'.$user_id[9];} else { ?> <a href="admin_seat.php?seat=10"><font color="green">Availible</a></font><?php } ?></td> <td><?php if($seat_status[10]) { echo '<font color="red"><a href="admin_seat.php?seat=11">'.$user_id[10];} else { ?> <a href="admin_seat.php?seat=11"><font color="green">Availible</a></font><?php } ?></td> <td><?php if($seat_status[11]) { echo '<font color="red"><a href="admin_seat.php?seat=12">'.$user_id[11];} else { ?> <a href="admin_seat.php?seat=12"><font color="green">Availible</a></font><?php } ?></td> </tr> </table> <br /> </fieldset> <br /> <SCRIPT LANGUAGE="JavaScript"> if (window.print) { document.write('<form><input type=button name=print value="Print this page" onClick="window.print()"></form>'); } </script> <br /> <hr /><br /> Above has been edited down to just show the first 12 seats. And heres my admin_seat.php so far: Code: [Select] <?php session_start(); /* connect to data base */ require ('../secure/connect.php'); /* get the seat number */ $seat_id = mysql_real_escape_string(trim($_GET['seat'])); ?> I want this script so that when i click on a seat it will ask me if i want to seat myself there, in which case it will place my username into that "seat" and remove anyone currently in that seat and reset them. If i dont want to seat myself there i want the script to give me the option to place a user there, so i would need to list all of my registered users, ideally in a dropdown box (i will only have around 80 users tops) and then submit that and it will move that user to that seat and wipe there current seat if applicable. something like this: Code: [Select] $query = "UPDATE seats_table set taken = FALSE, user_id = '0' WHERE user_id = '$user_id'"; $result = mysql_query($query) or die (mysql_error()); $query = "UPDATE seats_table set taken = TRUE, user_id = '$user_id' WHERE id = '$seat_id'"; $result = mysql_query($query) or die (mysql_error()); the top line resets the seat back to default and availible for a user. the third line is when a user selects a seat, it sets that seats "taken" to equal true stores there user ID and the seat ID. any help with this would be great and also im not sure if its possible to list all of my registered users inside a dropdown box. Lee |
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