PHP - Coding Help, Changing Color!
Hey Guys!
First off, great looking resource, looks like tons of helpful people here. Secondly, I'll upload the file I need help with. Basically I'm looking to change the color of certain words that don't show up well now that I changed the background color.. but there are so many things in this script I can't figure out which one to change. I'm trying to change the words across the top that are in grey, to a lighter color. The site is laughing2myself.com if you need to have a look THANKS! Any help would be greatly appreciated! Similar Tutorialsi dont know if this is strictly a php problem, anyway... i have a query which returns rows from my database and then displays them in a table.. but what i want to know is how do i then get the bg color to change? Code: [Select] <?php if ($_GET['quantity'] == null) { $_GET['quantity'] = 20; } if (mysql_numrows($gold) != 0) { ?> <table width="100%"> <tr> <td>Seller</td> <td>Sellers Average Delivery Speed</td> <td>Price (per <?=$_GET['quantity'];?>M)</td> <td></td> </tr> <?php while ($row = mysql_fetch_array($gold)) { $seller_id = $row['seller_id']; $price_unit = $row['price_unit']; $order_id = $row['id']; $user = mysql_query("SELECT * FROM users WHERE id='$seller_id'"); $user = mysql_fetch_array($user); $average_time = ($user['transcation_time'] / $user['transaction_amount']); ?> <tr> <td><center><a href="profile.php?id=<?=$seller_id;?>"><?= $user['username']; ?></a></center></td> <td><center><?php if ($user['transcation_amount'] <= 4){echo "Now Timing";} if ($user['transcation_amount'] >= 5){ echo $average_time; }?></center></td> <td><center>$<?= $price_unit; ?></center></td> <td><center><a href="offer/checkout.php?order_id=<?=$order_id;?>"><img src="image/buttons/checkout.gif" width="120" height="20"></a> </center></td> </tr> <?php } } ?> </table> I have a system on my forum where the admin can change the colors of certain elements. Take the divs with and id of header for example. They can change the color of these and the value is added to the database. Then in my initialize file which is always called with every page, i set the color for the headers to the database value: $color['headers'] = $row['headers']; but then i have to go to every header div and add <div id="header" style="color:'.$color['headers'].'";> this means doing this for every header div and i dont just allow them to change the font color, but also background color and borders. Would there be a better way of doing this without adding these variables to the style attr of the element? when i view the code in firebug there are alot of style attr with all of these variables and it makes the code look a mess, and also makes it tedious work to add these variables to every element. Thanks Hi people I'm trying to show all my data in my database, and I'm trying to make the font color change after 7 days to yellow and after 14 days it should show up red. But it does not work, could someone see any error in the code? It turns up green all the time.. Code: [Select] while($row = mysql_fetch_array($result)) { $postTime = $row['date']; $thisTime = time(); $timeDiff = $thisTime-$postTime; if($timeDiff <= 604800) { // Less than 7 days[60*60*24*7] $color = '#D1180A'; } else if($timeDiff > 604800 && $timeDiff <= 1209600) { // Greater than 7 days[60*60*24*7], less than 14 days[60*60*24*14] $color = '#D1B30A'; } else if($timeDiff > 1209600) { // Greater than 14 days[60*60*24*14] $color = '#08C90F'; } echo '<tr style="color: '.$color.';">'; echo '<td>'. $row['id'] .'</td>'; echo '<td>'. date("d.m.y", strtotime($row["date"])) .' </td>'; echo '<td><a href="detaljer.php?view='. $row['id'] .'">'. $row['Navn'] .'</a></td>'; echo '<td>'. $row['Telefon'] .'</td>'; echo '<td>'. $row['Emne'] .'</td>'; echo '</tr>'; } echo '</table>'; I was trying to show different hex codes as background in a loop for each section of a list. Here's what I done Code: [Select] $rgb; $rgb["c1"] = "ff4c54"; $rgb["c2"] = "ff764c"; $rgb["c3"] = "ffde4c"; $rgb["c3"] = "c7f25f"; $rgb["c4"] = "33c9f7"; $i=0; $pargs = array( 'numberposts' => 10,'orderby'=> 'comment_count', ); $myposts = get_posts( $pargs );$max_count=0; <ul> foreach( $myposts as $post ) : setup_postdata($post); <li style="width:300px;background-color:#<?php foreach($rgb as $color => $hex) { echo $hex[i]; $i++; } ?>"> <a href="<?php the_permalink(); ?>"><?php the_title(); ?></a> - </li> <?php endforeach; ?> </ul> Ending up with just the white background.. and no change in the background colors. Kindly help Hello everyone! I need a little help to get functions names from the GD library. first i want to say i have a little knowledge with GD library like create image with words and etc. So , what i'm trying to do is to take image and than take the color of the first pixel on the top left than do some function work and than set this pixel on the top left to another color. now , i know how the algorithm should look like , i just don't know what function i need to use to: take specific pixel color from the image set new color for pixel on specific place i'll be glad if you could help me with that , regards , Mor. I'm unable to update the table. Could someone tell me why? $dfield1 = mysql_real_escape_string($field1); $dfield2 = mysql_real_escape_string($field2); $dfield3 = mysql_real_escape_string($field3); $dfield4 = mysql_real_escape_string($field4); $result =sprintf("SELECT * FROM db1 WHERE username ='%s'", $dfield1); $resultf = mysql_query($result); if (mysql_num_rows ($resultf) > 0){ $register = "&err=Not Available. Retry."; echo($register); } else { mysql_query("INSERT INTO db1 (name, birthday, street, phone) VALUES ('$dfield1', '$dfield2', '$dfield3', '$dfield4')"); $register = "Successful."; echo($register); } Hi All I am fairly new to the PHP world so please excuse my ignorance. (I am trying!) Basically I bought a commercially available PHP script and created my own script to work alongside the bought one. What happened then is that the developers of the script I bought released a new version of the software. My script no longer works and is throwing up the following error PHP Fatal error: Using $this when not in object context in C:\wamp\www\classifieds\system\core\System.php on line 175 I've worked out that the script fails on this line, in the new version of the software. $dbhost = System::getSystemSettings('DBHOST'); On review of the commercial script's coding, I noticed that where the old version used the syntax above, the new version uses a syntax as shown below $this->appContext->getSystemSettings('DBHOST'); So I went and modified my script (mismatched.php) to read as follows $dbhost = $this->appContext->getSystemSettings('DBHOST'); But im now getting the following errors PHP Parse error: syntax error, unexpected T_REQUIRE_ONCE, expecting T_FUNCTION in C:\wamp\www\classifieds\admin\mismatched.php on line 5 I'd appreciate any ideas you may have that could help me get my script (mismatched.php) working again. Thanks again Ali How can I get it so the following work: echo utf8_decode($xml->healings[0]->$xmla[0]->descrip[0]); // NOT work echo utf8_decode($xmlb); // NOT work <?php $xml = simplexml_load_file('extra.xml'); $xmla = "test"; $xmlb = "$xml->healings[0]->".$xmla."[0]->descrip[0]"; echo utf8_decode($xml->healings[0]->test[0]->descrip[0]); // works echo utf8_decode($xml->healings[0]->$xmla[0]->descrip[0]); // NOT work echo utf8_decode($xmlb); // NOT work ?> I have a small mp3 script and its running accurately ...i want to check the mp3 URL before playing it whether the mp3 link active or broken ....how to check the link is active or broken in php thanks Hai everbody; I am finishing my site to open for public but before i have a small problem! Actually I am using SMF forum software! I need this help very urgently ! Just need to add login (logout) & register in the template menu!! Please guys try to help me out !! I will join the index_template.php file for you to make the correction ! (sorry for my bad english) Thank You a LOT in advance Daya Hi I need some help. I have a page which will show all the result based on the user sign in. And it will show something like this ID | Event Start Date | Event End Date | Event Details 1 19-11-2011 20-11-2011 View Event Details The view event details is a link so when I click on the link, it will link me to the next page (eventDetails.php?id=1) And at eventDetails.php?id=1 page, it would requires user to input whether they will be attending or not and will they be bringing their friend along then submit the form. When I submit, how do I pass all the data from eventDetails.php?id=1 page to confirmation.php page (after submitting)? You might want to refer to the attached coding. All the 2 php pages are working fine but when submit to confirmation.php page, the data are not post over so I didn't attach the confirmation.php page. Thanks Ben Chew [attachment deleted by admin] Im having trouble making a code for a feedback system. Can anyone help me to make a code like this. I have a table w/c contains -------------------------------------------- | Itemname | Itemprice | Seller | Laptop | 15000 | Name Phone | 5000 | Name ----------------------------------- Then.. i want a code that will query those values.. And have a button : [BUY] and [POST FEEDBACK] after the values. Then after clicking POST FEEDBACK it will show the values of the SELLER name in another page. HELP ME PLS I have a sql statement w/c suppose to output only those records w/c has a name of seller. But, it keeps showing all the records. Code: [Select] <?php session_start(); if(isset($_SESSION['name']) || ($_SESSION['contact']) || ($_SESSION['address']) ) { ini_set('display_errors', 0); $name = $_SESSION['name']; $contact = $_SESSION['contact']; $address = $_SESSION['address']; ?> <div id="apDiv1"> <?php echo "Name : $name"; echo "</br>"; echo "Name : $contact"; echo "</br>"; echo "Name : $address"; ?> <div id="apDiv2"> <?php $host="localhost"; $username="root"; $password=""; $db_name="feedbackdb"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM Feedbacks WHERE Seller = $name"; $result=mysql_query($sql); echo "<table border=\"5\" width=\"600\" >"; echo "<tr><th>Feedbacks</th><th>From</th><th> To </th>"; if(mysql_num_rows($result)) { while($row = mysql_fetch_assoc($result)) { echo "<tr><td>"; echo "" .$row['Feedback']."<br></td>"; echo "<td>".$row['From']."<br></td>"; echo "<td>".$row['Seller']."<br></td>"; echo "</tr>"; } } else { echo "<tr><td align=\"center\"> No Feedback</td></tr>"; } ?></div> </div> <?php } else { header("location:loginpage.php");; } ?> So I put this in the wrong place so ill try again, I need to write a code to add the price of five items with a subtotal, with tax, and then a grand total. What is the best way to do this? Every way I have tried isnt working PLEASEEEEEE HELP!!! Using crimson editor Hi,
I need to change 'Products with stock >60' to 'there are no products that have more than 60 in stock' in php script. I am not sure how to do the coding to change this in php script. If someone could help me within the next hour or two that would be amazing. thank you
I'm trying to update a field in my MySQL but instead of updating this makes the field BLANK. my code: $SomeVar = $_POST['finco']; mysql_query("UPDATE c_applicants SET streetz='$cts' WHERE username = '".$SomeVar."'"); $result = mysql_query($query); I am self taught and am trying very hard to get a log in page to work. The way i want it to work is that when they log in it uses a url stored in the database for their account. But i am having some much trouble working out a code that works and this is all i got: <?php include ('connection.php'); $username=$_POST['username5']; $password=$_POST['password5']; $query="SELECT password FROM merchants WHERE username = '$_POST(username5)'"; if ($password == $query) { $url = "SELECT url FROM merchants WHERE username = '$_POST(username5)'"; header("Location: $url"); } else { echo urgh } ?> I have 4 files like attached.... if i clicked on index.php content-1 link... that open templet.php and body load with content-1.txt please helpme <?php
$Title=$_POST['title']; why it gives "insertion failed" as a result?
Is there a way i can make a php code for making a lesson then upload to my made system? Im newbie here. so basically, i need to make an e-learning system that lets the user make a lesson then upload it so that other user can view their made lesson.. Someone help me pls. |