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PHP - Php Next Month Issue With Year End
Thanks to aleX_hill and RussellReal for the help so far. I'm trying to utilise the code before to find the next month. However, it needs to be used with the current year. So I altered the below
<?php $nextMonth = date("m") + 1; $daysInNextMonth = date("t",mktime(0,0,0,$nextMonth)); echo $daysInNextMonth;?> to #NEXT MONTH $nextMonth = date("m") + 1; echo $nextMonth; $daysInNextMonth = date("t",mktime(0,0,0,$nextMonth)); echo $daysInNextMonth ; $year = date("o"); echo $year; I can then pass it into my url query like so: <a href="<?php echo $url_path; ?>after=<?php echo $year; ?>-<?php echo $nextMonth; ?>-01&before=<?php echo $year; ?>-<?php echo $nextMonth; ?>-<?php echo $daysInNextMonth; ?>">Next Month</a> Brilliant I thought, until it comes to December 2010, the next month needs to be January 2011. Now I'm bamboozled. How do I get around this one? Many thanks, your help is always appreciated! Similar TutorialsHello this code is supposed to sort by year and month, but it doesn't. It sort by year and months are random. Any suggestions? Many thanks,
$sortdata =[];
$namecolumn = array_column($data, '0');
foreach($data as $datecolumn){
$dateexplode = explode('/', $datecolumn[3]);
$sortdata[] = (isset($dateexplode[1])) ? $dateexplode[1] : ((isset($dateexplode[0])) ? $dateexplode[0] : '');
}
array_multisort($namecolumn, (($sorttype=='DESC') ? SORT_DESC : SORT_ASC), $sortdata, (($sorttype=='DESC') ? SORT_DESC : SORT_ASC), $data);
Edited May 13 by Barand code tags added Hello, not sure if lack of sleep or just staring at code too long. This is what I have: Code: [Select] while($rowy = mysql_fetch_array( $resulty )) { mpdate = YYYY-MM-DD $date = $rowy['mpdate']; $year = explode('-', $date); $month = date("F", mktime(0, 0, 0, $year[1])); ?> <?php echo $year[0]; ?> <br> <?php echo $month; ?> <br> <?php echo $rowy['mptitle']; } ?> I figure if I use: if ($year[0] == date('Y"){ echo month and entry stuff } but I keep getting errors. What I am trying to do is sort everything out into year month and day ie: 2012 March Entry 1 Entry 2 February Entry 1 Entry 2 Entry 3 etc... This is what I am getting 2012 March Entry 1 2012 March Entry 2 2012 February Entry 1 etc... Is there a way to fix this? right now i have my date system to say "X amount of seconds ago, X hours ago, X days ago, X years ago, How could i turn mktime() (1290874161) into a mm/dd/yyyy format? so it would say like, "Nov 27, 2010 at Hour:Minute" (whatever the hour/minute is) How to acheive it friends? i want my current codes to show results accouding to current month followed by year, the precious month goes to the page two.
would really appreciate if someone could help me acheive it
$tableName="records"; Edited by lovephp, 02 December 2014 - 11:50 AM. Hi Guys, Been a while since I've been on here, but I'm currently bashing my head against a wall trying to figure this one out. Basically I have a calendar that outputs Monday through Sunday, and the user clicks on a date and outputs it to the URL.... ie. ?day=$day&month=$month&year=$year. Now the next part I need to find out what day (0-6) say the 25th Feb 2011 will be wday 5... now how can I do this in code? And before anyone says why not output it to url, I cannot as the first week and last weeks use different code Cheers James Hi, I've got a date picker on a form which puts data into a database in the YYYY-MM-DD format. Just wondering how I could also put the name of the month (extracted from that) as well as just the year into separate columns. Ie: To use the field race_date from the form to also fill the 'race_month' and 'race_year' columns in the database. This code obviously only fills the 'race_date' column so far: Code: [Select] global $_POST; $race_date = $_POST["race_date"] ; .... $query = "INSERT INTO 10k_races (race_date, race_month, race_year)" . "VALUES ( '$race_date', '$race_month', '$race_year')"; Hi,
I want to display my data in this format
format.JPG 54.52KB
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Expense data i am getting like this
<td><?php
$in = "SELECT sales_invoice.invoice_id as INID, DATE_FORMAT(sales_invoice.date_invoiced,'%M') AS month, sales_invoice_line_items.invoice_id, SUM(sales_invoice_line_items.sub_total) AS Total, SUM(sales_invoice_line_items.tax_amount) AS total_tax FROM sales_invoice INNER JOIN sales_invoice_line_items ON sales_invoice.invoice_id=sales_invoice_line_items.invoice_id GROUP BY sales_invoice.invoice_id, DATE_FORMAT(sales_invoice.date_invoiced, '%Y-%m')";
$in1 = mysql_query($in) or die (mysql_error());
$total=0;
$tax =0;
while($income = mysql_fetch_array($in1))
{
$total +=$income['Total'];
$tax +=$income['total_tax'];
echo $total - $tax; }
?>
</td>
And Profit i am getting like this
<td><?php
$in = "SELECT purchase_invoice.invoice_id as INID, DATE_FORMAT(purchase_invoice.date_invoiced,'%M') AS month, purchase_invoice_line_items.invoice_id, SUM(purchase_invoice_line_items.sub_total) AS Total, SUM(purchase_invoice_line_items.tax_amount) AS total_tax FROM purchase_invoice INNER JOIN purchase_invoice_line_items ON purchase_invoice.invoice_id=purchase_invoice_line_items.invoice_id GROUP BY purchase_invoice.invoice_id, DATE_FORMAT(purchase_invoice.date_invoiced, '%Y-%m')";
$in1 = mysql_query($in) or die (mysql_error());
$total=0;
$tax =0;
while($income = mysql_fetch_array($in1))
{
$total +=$income['Total'];
$tax +=$income['total_tax'];
echo $total - $tax; }
?>
</td>
I dont know how to display data like this. Do i need to change the the table structure in my database? Please suggest
Hello. I have a mysql database with an 'entrytime' field which contains the unix timestamp the record was added. How do I create a mysql query to select all records for a given month/year? For example, if I wanted to create a query to display all records for October 2010 how do I go about it? I am at a loss and can't find my answer via google. Thanks in advance for any help! I have a file upload script that will eventually process a ton of files. I would like to upload them into sub-directories according to what year, month, and day they are uploaded.
A typical tree should look like this:
attachments/
--/2014
-----/January
--------/01
--------/02
--------/03 , etc.
-----/February
--------/01
--------/04
--------/09
--------/18
--------/20, etc
-----/March, etc
--/2015, etc.
So a file called image.jpg uploaded on 10/31/2014 would have a URL of attachments/2014/October/31/image.jpg. I understand that every time a file is uploaded, the script would have to detect through FTP whether or not folders for the year, month, and day exist, and if they don't create them. My problem is that I have no idea what the logic of this script would be. What order should I do things in? Is there a way to use maybe foreach to detect/create the folders? Any input would be appreciated.
Hello. I'm new to pHp and I would like to know how to get my $date_posted to read as March 12, 2012, instead of 2012-12-03. Here is the code: Code: [Select] <?php $sql = " SELECT id, title, date_posted, summary FROM blog_posts ORDER BY date_posted ASC LIMIT 10 "; $result = mysql_query($sql); while($row = mysql_fetch_assoc($result)) { $id = $row['id']; $title = $row['title']; $date_posted = $row['date_posted']; $summary = $row['summary']; echo "<h3>$title</h3>\n"; echo "<p>$date_posted</p>\n"; echo "<p>$summary</p>\n"; echo "<p><a href=\"post.php?id=$id\" title=\"Read More\">Read More...</a></p>\n"; } ?> I have tried the date() function but it always updates with the current time & date so I'm a little confused on how I get this to work. Hi, I'm wanting to find rows whose date is within the next week of the current month of the current year. The format of the date is, for example: 2010-10-28 Any ideas guys? Thanks lots! Or am I just going crazy? OK, I've been running a query that uses the snippet below to get the previous month. It's : Code: [Select] $sql = "SELECT COUNT(`id`) as `counted` FROM `click_tracking` WHERE `date` LIKE '". date('Y-m', mktime(0, 0, 0, (date('m')-1), date('d'), date('Y'))) ."-%'"; Here's a snippet for people to try: Code: [Select] date_default_timezone_set('America/Toronto'); echo date('Y-m', mktime(0, 0, 0, (date('m')-1), date('d'), date('Y'))); //prints 2012-03 (March, which is incorrect; should be February- 2012-02) That should have printed 2012-02, but instead, it prints 2012-03. If I modify the mktime() to (date('m')+1): Code: [Select] date_default_timezone_set('America/Toronto'); echo date('Y-m', mktime(0, 0, 0, (date('m')+1), date('d'), date('Y'))); //prints 2012-05 (May, which is incorrect; should be April - 2012-04) It prints 2012-05 which is incorrect for the given timezone. Should be 2012-04 I'm thinking it's a leap year bug and will work itself out tomorrow (per my timezone, anyways). So, when I use the mktime() function, it seems to be thinking we're in April already. A standard date('Y-m') prints the correct YYYY-MM (2012-03) though. Am I tripping out? Hello, i have two fields. a beginning year and an ending year. How can i make new fields out of the years in between the beginning and ending years. i hope that makes sense. Hi.. I need help in getting the 3 Months Name from my table field FromMonth and ToMonth. Here is the scenario. First, I select FromMonth and ToMonth. Ex. FromMonth = 5 ToMonth = 7 So it means FromMonth is May ToMonth is July. Now I save the MonthNumber to my database: table- so_month FromMonth = 5 ToMonth = 7 Now I need to get the between Months Name from FromMonth to ToMonth which are (May, June, July). How does it possible? Thank you so much. Trying to get the below to generate the month in word form from a numeric entry in a database. Code: [Select] elseif($_GET['rma']=="calander"){ $sql101010="SELECT DISTINCT rma_year_issued FROM $tbl_name4 ORDER BY rma_year_issued"; $result101010=mysql_query($sql101010); while($row101010=mysql_fetch_array($result101010)){ extract($row101010); $content.='<a href="./acp_admincp.php?rma=calander&year='.$rma_year_issued.'">'.$rma_year_issued.'</a> <br />'; } if(isset($_GET['year'])){ $logout.=' | <a href="./acp_admincp.php?rma=calander">Back to RMA Calander</a>'; $rma_year_issued=$_GET['year']; $sql111010="SELECT DISTINCT rma_month_issued FROM $tbl_name4 WHERE rma_year_issued='$rma_year_issued' ORDER BY rma_month_issued"; $result111010=mysql_query($sql111010); while($row111010=mysql_fetch_array($result111010)){ extract($row111010); $months = array('Janurary', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December'); for($i=0; $i <=11; $i++){ if($rma_month_issued=$i){ $rma_month_issued2=$months[$i]; } } $content=""; $content.='<a href="./acp_admincp.php?rma=calander&year='.$rma_year_issued.'&month='.$rma_month_issued.'">'.$rma_month_issued2.'</a> <br />'; } } } Basically in the data base I may have 2,5,7 under the year 2011. I want to get the numeric months into words for use in the text of the link. The above is returning December even though the entry in the database is 5. So I am creating a list of events. There will be a drop down menu to change between months. I only want the months to be listed if an event during that month exists. So if I have events listed for September and November, list only September and November, skipping October. Any idea on how to approach this or if there are any functions for such a thing? Why does this work: $dateAllowedSelect = date('Y') -18; But this doesn't: $dateAllowedSelect = date('Y') +5; I nee to get the current year plus 2010 - 2015 in a select box. Thank you. So I have decided to do research as my project and gain something from this. But also I will have to include programming which i prefer PHP. and will be testing these for my research. Does this sound like a good project and also If it is good sound.. Where do I start?... need a starting point and then I could go on to doing it.. Gud Pm! Im trying to display a list of years (last year, current year and next year) with these simple code i made.. It displays the current and next year correctly except last year, which gives me "1970". I don't get why it gives me that since may next year works properly.. Code: [Select] $currentyear = date('Y'); $subtract_year = strtotime(date('Y', strtotime($currentyear)) . '-1 year'); $lastyear = date('Y', $subtract_year); $addyear = strtotime(date('Y', strtotime($currentyear)) . '+1 year'); $newyear = date('Y', $addyear); $year_array = array($lastyear, $currentyear, $newyear); foreach($year_array as $year) { echo "<option value='{$year}'>"; echo $year; echo "</option>"; } I'm not familiar with dates yet.. so i'm gonna read the manual while w8ting for your kind replies. |
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