|
PHP - Convert A Dynamically Created Page To Pdf
I have heard there is a way to convert an html document to pdf with fpdf. I will need to pull information from a database though so it will be a php file instead. Does anyone know of a way to convert a php output to pdf in the same way?
Similar TutorialsHi all I have a form with a few textareas and a bunch of input fields. The input fields are dynamically created from querying a country table. $query = $DB->query("SELECT country_code, country_id, IF(country_code = '".$country_code."', '', '') AS sel FROM countries WHERE site = 'test' ORDER BY country_name ASC"); foreach ($query->result as $row) { $options .= '<label>' . 'Phrase for ' . $this->settings['countries'][$row['country_code']] . '</label>' . '<br />'; $options .= '<input style="width: 100%; height: 5%;" id="country_data" type="text" name="' . $row['country_id'] . '" />' . '<br /><br />'; $options .= '<input type="hidden" name="country_id" id="country_id" value="' . $row['country_id'] . '" />'; } This is fine and outputs all the input fields I need. The problem comes when I need to get the value of each field input field and pass it into a query. The 'value' field of the inputs are numbers, such as 68, 70, 124, 108 etc so I can't get them in a for loop etc What's the easiest way to get all of these input field values? Can I use $_POST? my name is fairooj and ama new to php and jquery. i have a proplam. i want your help.
<script type="text/javascript">
var count = 0;
$(function(){
$('p#add_field').click(function(){
count += 1;
$('#container').append(
'<strong>Link #' + count + '</strong><br />'
+ '<input id="field_' + count + '" name="fields[]' + '" type="text" />'
+ '<input id="code_' + count + '" name="code[]' + '" type="text" /><br />' );
});
});
</script>
I'm trying to create a table form that pulls in "Extra" choices from a table and allows users to select a number of days and number of guests for each choice. I started creating it a a checkbox field but am thinking just using the name as a label and setting days and guests to default "0" might be a better bet. Guidance from someone more experienced with this? Also, how do I store the submission (db structure - in the "reservations" table, another?). I'm new to this and feel kind of lost with this challenge. //Extras $query = "select * from extras"; $data = mysqli_query($db, $query); $num = mysqli_num_rows($data); echo "<p><b>Extras:</b></p>"; for ($i=0; $i<$num; $i++) { $row = mysqli_fetch_array($data); $extra_id = $row['extra_id']; $extra_name = $row['extra_name']; $extra_rate = $row['extra_rate']; echo "<p><input type='checkbox' name='extra_id[]' value = '$extra_id' />$extra_name <i>\$$extra_rate</i> Num Days<input type='text' name='d$extra_id' /> Num Guests<input type='text' name='g$extra_id' />"; } i have created an object in one page. it has a submit button which upon clicking opens a new page. is it possible to access that created object and its data members in that second page? here is the code for creating the object in the first page. $viewcart = new Cart(); $viewcart->GetProductCart($user); I am a newby using php as the backbone for my web design, with a help from phpFreeks, I have come along way in a short time. Below is a short script of two buttons created with php, how can I use the buttons to link to a new web page (similar to using "href" in html)? I would like to use the php created buttons to keep the general look and feel to my site the same through. In advance, thank you for the support... This is the part in my normal page that shows the buttons: echo "<form action='processButtonsDdr.php' method='POST'> <input type='submit' name='display_button' value='homepage' /> <input type='submit' name='display_button' value='new entry' /> This is a snippet from my two button process page: <?php if($_POST['display_button'] == "home page") { ????????????????? // what do I enter in this area to point the button to another webpage? } else { ????????????????? } ?> Hi, I'm trying to make a gallery, and it more or less works. But I don't like having to load so many images for the user to view.
What happens is I have a very basic method of loading the images into the index file using require.
<?php
foreach (glob("*.jpg") as $filename) {
echo "<div class='itemContainer'><img src='" . $filename . "' class='item' id='" . $filename . "' /></div>";
}
?>
Pretty simple. but it just loads everything in the directory. What I'd like to do is make it so 30 images load, and then it creates a new "div container" and loads the next 30 in. As well as a page counter, and a next and previous button.
I'm not too sure how to control the flow of information from PHP to the index file when using require. Or if this is even the right way of doing it.
My thoughts are sorta like this
$imageCounter = 0;
$newPageStandard = 30;
foreach($imageDir as $image){
// echo image;
$imageCounter++
if($imageCounter == $newPageStandard){
$newPageStandard += $newPageStandard; // increase standard for next page if there are enough images
//create new image container(div)
//somehow re-direct the echo into this new image container
}
// continue echoing images
}
Something Along those lines. Is this at all on the right path, or should I be grabbing all the images, and stuffing them into an multidimensional array and breaking each array into segments of 30? Or perhaps another completely different method? (yeah I dont have a clue what Im doing atm)
Edited by 7blake, 10 November 2014 - 06:37 AM. http://2eastvalleyhomes.expandyourwebpresence.com/ In this site on the right widget the search option opens a new page and directs you off the page. I have created a page not visible on the home page called MLS and I would like the search on the right side to have its information populate in a page I created in my wordpress site, does any one have any suggestions or any ideas for this thank you for any help. <?php require_once('upper.php'); $error_msg=''; if(!isset($_COOKIE['LoginIdCookie'])){ if(isset($_POST['submit'])) { require_once('database.php'); $LoginId=mysqli_real_escape_string($dbc,trim($_POST['LoginId'])); $Password=mysqli_real_escape_string($dbc,trim($_POST['Password'])); if((!empty($LoginId)) && (!empty($Password))){ $query="SELECT * FROM registration WHERE LoginId='$LoginId' AND Password=SHA('$Password') AND Flag='A'"; $result=mysqli_query($dbc,$query) or die('Not Connected'); if(mysqli_num_rows($result)==1) { $row=mysqli_fetch_array($result); setcookie('LoginIdCookie',$row['LoginId']); //$home_url = 'http://' . $_SERVER['HTTP_HOST'] . dirname($_SERVER['PHP_SELF']) . '/index1.php'; header('Location: index1.php'); } else{ echo 'Enter right UserName/Password combination or You may not approved yet. '; echo '<a href="ForgetPassword.php">Can\'t access your account?"</a>'; }} else{ echo' Fill all fields'; } }} ?> <html> <title>Log In</title> <body> <?php if(empty($_COOKIE['LoginIdCookie'])) { echo $error_msg; ?> <form method="post" action="<?php echo $_SERVER['PHP_SELF'] ;?>" > <div class="LoginValidator"> <fieldset> <legend> Log In</legend><table><tr><td> <label for="username">User Name :</label><br/><br/></td> <td><input type="text" name="LoginId"><br/><br/></tr> <td><label for="password">Password :</label></td> <td><head> <div id="divMayus" style="visibility:hidden">Caps Lock is on.</div> <SCRIPT language=Javascript> function capLock(e){ kc = e.keyCode?e.keyCode:e.which; sk = e.shiftKey?e.shiftKey:((kc == 16)?true:false); if(((kc >= 65 && kc <= 90) && !sk)||((kc >= 97 && kc <= 122) && sk)) document.getElementById('divMayus').style.visibility = 'visible'; else document.getElementById('divMayus').style.visibility = 'hidden'; } </SCRIPT> </HEAD> <input onkeypress='return capLock(event)' type="password" name="Password"><br/></td></tr></table> <input type="submit" name="submit" value="Login" class="Login_button"> </fieldset> </div> </form> <?php } else{ echo 'You are logged in as '.$_COOKIE['LoginIdCookie']; } require_once('lower.php'); mysqli_close($dbc); ?> HI friends.......... In above code when I enter wrong user name or password, it displays error msg properly but problem is that when i enter right user name and password instead to redirect to index1.php it displays LoginPage again.......... I think cookie is not created as well.......... I can't understand where is problem???????/ please help me.................... I have created a login page, but i want the users to be directed to another page only if the login details are correct. How would i do this?any help is appreciate. Coding for the PHP is below: thank you. Code: [Select] <?php $username = $_POST["username"]; $password = $_POST["password"]; //This if statement asks if the $username variable is set. If it is it executes the php script. Otherwise it echoes the login form. if(isset($username)){ if (!($username == " " && $password == " ")) { $connect = mysql_connect("","","") or die("Couldn't connect!"); mysql_select_db("") or die("Couldn't find db"); $query = mysql_query("SELECT * FROM users WHERE username='$username'"); $row = mysql_fetch_array($query); $numrows = mysql_num_rows($query); $dbusername = $row['username']; $dbpassword = $row['password']; } else { echo ('<div id="username"> <form action="" method="post"/> <font color="red"> Please enter a username and password </font> <table><tr><td> <img src="imgs/Log In/username.png" alt=""/> </td><td> <input type="text" size="30" name="username" style="background-color:transparent;" /> </td></tr></table> <table><tr><td> <img src="imgs/Log In/password.png" alt=""/> </td><td> <input type="password" name="password" size="30" /> </td></tr></table> <form id="submitb" action=""> <input type="submit" value="Log in" /> </form> <p class="register">Not yet a member? <a href="Form.html">Register Here</a>, its Free!</p> </div>'); } //check to see if they match if ($username == $dbusername && $password == $dbpassword) { echo "You Are Now Logged In, Welcome To AdobeTuts!"; } else echo ('<div id="username"> <form action="" method="post"/> <div id="new"> <font color="red"> Wrong Username Or Password, Please Try Again </font> </div> <table><tr><td> <img src="imgs/Log In/username.png" alt=""/> </td><td> <input type="text" size="30" name="username" style="background-color:transparent;" /> </td></tr></table> <table><tr><td> <img src="imgs/Log In/password.png" alt=""/> </td><td> <input type="password" name="password" size="30" /> </td></tr></table> <form id="submitb" action=""> <input type="submit" value="Log in" /> </form> <p class="register">Not yet a member? <a href="Form.html">Register Here</a>, its Free!</p> </div>'); } //This next bit echoes the login form unless the $username variable is set. else { echo ('<div id="username"> <form action="" method="post"/> <table><tr><td> <img src="imgs/Log In/username.png" alt=""/> </td><td> <input type="text" size="30" name="username" style="background-color:transparent;" /> </td></tr></table> <table><tr><td> <img src="imgs/Log In/password.png" alt=""/> </td><td> <input type="password" name="password" size="30" /> </td></tr></table> <form id="submitb" action=""> <input type="submit" value="Log in" /> </form> <p class="register">Not yet a member? <a href="imgs/Homepage tuts/Form.php">Register Here</a>, its Free!</p> </div>'); } ?> Hi again.... I'm working on a project that creates a profile page for the user (i.e. 'username.php') when they register. Because there are two ways to register, through Facebook and through the website itself, there has to be an if statement in this page that it crates as to which ID to use for that user. Because Facebook usernames are not unique, we must identify a user through their OAuth User ID which is a 10 digit number. When a user registers through the website itself, usernames are unique so their profile page can be ID'd by their username. Here's the code that creates that profile page: function createProfile($user) { $userFile = 'users/'.$result['oauth_uid'].'.php'; $fh = fopen($userFile, 'w') or die("can't open file"); $stringData = "<?php\n" . '$pageowner = "' . $result['oauth_uid'] . '";' . "\n" . 'include "profile.php";' . "\n?>"; fwrite($fh, $stringData); fclose($fh); } $user is the username passed to the function when it's called. Currently that is set to create a line of code in the new profile page ('userid'.php) that looks like this: <?php $pageowner = "100001745088506"; include "profile.php"; ?> I want to add an IF to that page that follows this structu if oauth_provider == facebook { $pageowner = "oauth_uid" } else { $pageowner = username } But I don't know how to write that he $stringData = "<?php\n" . '$pageowner = "' . $result['oauth_uid'] . '";' . "\n" . 'include "profile.php";' . "\n?>"; to make it show up in the page it creates. I want that if statement to be written IN the page that is created. I just don't know the syntax well enough yet to do that. Would somebody help me out or point me in the right direction? Thanks! Ok i am stuck, i created a php script that draws data from a mysql dB into a php page. How can I send the page as the body in email? I do not need to preview the page, but can send it without ever viewing if that helps. When I put my code into a variable it does nothing. Is it caching? Should I load the results into mysql then send?please advise.. This is a bit of a long shot, but hopefully somebody can point me in the right direction. I have a wordpress website that has a 'Wine List' page, in which it lists over 100 'custom posts' detailing each wine. I have tried out several plugins to convert the wine list into a PDF but none work in the way that I require. So now I'm thinking to just do it outside of wordpress and find a PHP script that may help me. I imagine it would be impossible to simply execute a script at the bottom of a page for it to convert whatever HTML has been generated into a PDF? Or is there anything that would allow me to specify what records from the database to add to the PDF? E.g. for me to type a PHP script with a MySQL command and for that to be converted into a PDF? Thanks if anybody has any ideas what action I should take!
I need to convert the following table and graph to PDF when button is clicked. Please help
I am using fusion charts and generated graph will be swf file
// Table and graph for all students
if(isset($_POST['ReportAll'])){
$strQuery = ("SELECT registration_number,SUM(Fine) AS Total_Fine
FROM lended_book_cd
GROUP BY registration_number");
$result=mysql_query($strQuery);
if (!$result){
Error (mysql_error()) ;
}
if (mysql_num_rows($result)!==0){
$table=1;
echo $input_table;
echo "<center>Fine report for All Students </center>";
echo "<br>";
echo "<table border='2' align='center'>";
echo("<tr>");
for($i=0;$i<mysql_num_fields($result);$i++){
echo("<th>".mysql_field_name($result,$i)."</th>");
}
while($data=mysql_fetch_array($result)){
echo("<tr>");
for($i=0;$i<mysql_num_fields($result);$i++){
echo("<td>".$data[$i]."</td>");
}
}
echo "</table>";
}
else{
Info ("No Fine Reports found for Student $_POST[regnum]");
}
$strQuery = ("SELECT registration_number,SUM(Fine) AS Total_Fine
FROM lended_book_cd
GROUP BY registration_number");
//Where lended_book_cd.registration_number = students.registration_number
$result=mysql_query($strQuery);
$strXML = "<graph caption='Fine report for All Students' showLabels='1' xAxisName='Student Registration Number' yAxisName='Fine Value' showNames='1' showValues='1' useRoundEdges='1' palette='3'>";
while($ors = mysql_fetch_array($result)) {
// Append the names of the countries and their respective populations to the chart's XML string.
$strXML .= "<set name='$ors[registration_number]' value='$ors[Total_Fine]' />";
}
$strXML .= "</graph>";
echo renderChart('charts/FCF_Column2D.swf', // Path to chart type
'', // Empty string when using Data String Method
$strXML, // Variable that contains XML string
'chart1Id', // Unique chart ID
'560', '400', // Width and height in pixels
false, // Disable debug mode
true // Enable 'Register with JavaScript' (Recommended)
);
}
/*i have some pages and i want to user to see an appropriate title when user click new page
example: at home page on the tab the title must be written as
welcome at hendra|home
and when user clicked on about page, the tab must show another title like this
you are at hendra|about page
how to do this in php*/
//head
<!doctype html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1, shrink-to-fit=no">
<title><?php echo $title; ?></title>
</head><!--/end of head-->
<body>
//index page
<?php
include_once('head.php');
$title = 'welcome at hendra|home';
?>
//about page
<?php
include_once('head.php');
$title = 'you are at hendra|about page';
?>
Hi all, Hope to find you all good. I have the following, which creates a php file. This works fine and without error. However, once created, the content of the page, which is got from the Database, is not showing.
<?php
include_once('includes/header.php');
if(isset($_POST['new']) && $_POST['new']==1){
if(isset($_POST['submit'])){
$trn_date = mysqli_real_escape_string($con, date("Y-m-d H:i:s"));
$name = mysqli_real_escape_string($con, $_POST['name']);
$description = mysqli_real_escape_string($con, $_POST['description']);
$body = mysqli_real_escape_string($con, $_POST['body']);
$submittedby = mysqli_real_escape_string($con, $_SESSION["username"]);
$sql = "SELECT * FROM pages WHERE name='$name'";
$res = mysqli_query($con, $sql);
if (mysqli_num_rows($res) > 0) {
$message = '<i class="fa fa-times text-danger"> - A Page already exists with that name!</i>';
}else{
$ins_query="insert into pages (`trn_date`,`name`,`description`, `body`, `submittedby`)values ('$trn_date','$name','$description', '$body', '$submittedby')";
mysqli_query($con,$ins_query)
or die(mysqli_error($con));
if(mysqli_affected_rows($con)== 1 ){
// Name of the template file.
$template_file = 'template.php';
// Root folder if working in subdirectory. Name is up to you ut must match with server's folder.
$base_path = '/protour/';
// Path to the directory where you store the "template.php" file.
$template_path = 'includes/';
// Path to the directory where php will store the auto-generated couple's pages.
$page_path = '../';
// Posted data.
$row['name'] = str_replace(' ', '', $_POST['name']);
$row['description'] = str_replace(' ', '', $_POST['description']);
$row['body'] = $_POST['body'];
// Data array (Should match with data above's order).
$placeholders = array('{name}', '{description}', '{body}');
// Get the template.php as a string.
$template = file_get_contents($template_path.$template_file);
// Fills the template.
$new_file = str_replace($placeholders, $row, $template);
// Generates couple's URL and makes it frendly and lowercase.
$page_url = str_replace(' ', '', strtolower($row['name'].'.php'));
// Save file into page directory.
$fp = fopen($page_path.$page_url, 'w');
fwrite($fp, $new_file);
fclose($fp);
// Set the variables to pass them to success page.
$_SESSION['page_url'] = $page_url;
// If working in root directory.
$_SESSION['page_path'] = str_replace('.', '', $page_path);
// If working in a sub directory.
$_SESSION['page_path'] = substr_replace($base_path, '', -1).str_replace('.', '',$page_path);
$message = '<i class="fa fa-check"></i> - Page Created Successfully';
}
}
}
}
?>
<!-- Header-->
<div class="breadcrumbs">
<div class="col-sm-4">
<div class="page-header float-left">
<div class="page-title">
<h1>Pages</h1>
</div>
</div>
</div> <div class="col-sm-8">
</div>
</div>
<div class="content mt-3">
<div class="animated fadeIn">
<div class="row">
<div class="col-lg-12">
<div class="card">
<div class="card-header"><strong>Add </strong><small>Page <?php
if($message = isset($message) ? $message : ''){
printf($message);
}
?></small></div>
<div class="card-body card-block">
<form role="form" method="post" action"">
<input type="hidden" name="new" value="1" />
<div class="modal-body">
<div class="form-group"><label for="name" class=" form-control-label">Page Name</label><input type="text" id="name" name="name" placeholder="name" class="form-control">
</div>
<div class="form-group"><label for="description" class=" form-control-label">Description</label><input maxlength="100" type="text" id="description" name="description" placeholder="descriptioon" class="form-control"></div>
<div class="form-group"><label for="body" class=" form-control-label">Body</label>
<textarea class="form-control" id="body" name="body" placeholder="body"></textarea>
</div>
<div class="modal-footer">
<button type="submit" name="submit" id="submit" class="btn btn-primary">Confirm</button>
</div>
</form>
</div>
</div>
</div><!-- .animated -->
</div><!-- .content -->
</div><!-- /#right-panel -->
<!-- Right Panel -->
<script src="assets/js/vendor/jquery-2.1.4.min.js"></script>
<script src="assets/js/popper.min.js"></script>
<script src="assets/js/plugins.js"></script>
<script src="assets/js/main.js"></script>
<script src="assets/js/bing.js"></script>
<script src="assets/js/lib/data-table/datatables.min.js"></script>
<script src="assets/js/lib/data-table/dataTables.bootstrap.min.js"></script>
<script src="assets/js/lib/data-table/dataTables.buttons.min.js"></script>
<script src="assets/js/lib/data-table/buttons.bootstrap.min.js"></script>
<script src="assets/js/lib/data-table/jszip.min.js"></script>
<script src="assets/js/lib/data-table/pdfmake.min.js"></script>
<script src="assets/js/lib/data-table/vfs_fonts.js"></script>
<script src="assets/js/lib/data-table/buttons.html5.min.js"></script>
<script src="assets/js/lib/data-table/buttons.print.min.js"></script>
<script src="assets/js/lib/data-table/buttons.colVis.min.js"></script>
<script src="assets/js/lib/data-table/datatables-init.js"></script>
<script src="https://cdn.tiny.cloud/1/sw6bkvhzd3ev4xl3u9yx3tzrux4nthssiwgsog74altv1o65/tinymce/5/tinymce.min.js" referrerpolicy="origin"></script>
<script>
tinymce.init({
selector: 'textarea',
plugins: 'advlist autolink lists link image charmap print preview hr anchor pagebreak',
toolbar_mode: 'floating',
});
</script>
<script type="text/javascript">
$(document).ready(function() {
$('#customer-table').DataTable();
} );
</script>
</body>
</html>
My guess is the placeholder section is not working.
// Posted data.
$row['name'] = str_replace(' ', '', $_POST['name']);
$row['description'] = str_replace(' ', '', $_POST['description']);
$row['body'] = $_POST['body'];
// Data array (Should match with data above's order).
$placeholders = array('{name}', '{description}', '{body}');
Here is template.php
<?php
include_once('includes/header.php');
require_once('admin/includes/config.php');
if(isset($_POST['new']) && $_POST['new']==1){
$trn_date = mysqli_real_escape_string($con, date("Y-m-d H:i:s"));
$name = mysqli_real_escape_string($con, $_POST['name']);
$email = mysqli_real_escape_string($con, $_POST['email']);
$pickup = mysqli_real_escape_string($con, $_POST['pickup']);
$dropoff = mysqli_real_escape_string($con, $_POST['dropoff']);
$dep_date = mysqli_real_escape_string($con, $_POST['dep_date']);
$ret_date = mysqli_real_escape_string($con, $_POST['ret_date']);
$dep_time = mysqli_real_escape_string($con, $_POST['dep_time']);
$pax_numbers = mysqli_real_escape_string($con, $_POST['pax_numbers']);
$ins_query="insert into quotes (`trn_date`,`name`,`email`, `pickup`, `dropoff`, `dep_date`, `ret_date`, `dep_time`, `pax_numbers`) values ('$trn_date','$name','$email', '$pickup', '$dropoff', '$dep_date', '$ret_date', '$dep_time', '$pax_numbers')";
mysqli_query($con,$ins_query)
or die(mysqli_error($con));
if(mysqli_affected_rows($con)== 1 ){
$message = "Thank you. We will be in touch soon.";
}
}
$sql = "SELECT * FROM slide";
$result = $con->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
?>
<div class="hero-wrap" style='background-image: url("admin/uploads/<?php echo $row['image']; ?>")' data-stellar-background-ratio="0.5">
<div class="overlay"></div>
<div class="container">
<div class="row no-gutters slider-text justify-content-start align-items-center">
<div class="col-lg-6 col-md-6 ftco-animate d-flex align-items-end">
<div class="text">
<p style="font-size: 18px;"><?php echo $row['slide_text']; ?></p>
<a href="<?php echo $row['youtube']; ?>" class="icon-wrap popup-vimeo d-flex align-items-center mt-4">
<div class="icon d-flex align-items-center justify-content-center">
<span class="ion-ios-play"></span>
</div>
<div class="heading-title ml-5">
<span>Play Our Short Video</span>
</div>
</a>
</div>
</div>
<div class="col-lg-2 col"></div>
<div class="col-lg-4 col-md-6 mt-0 mt-md-5 d-flex">
<form method="post" action="" role="form" class="request-form ftco-animate">
<input type="hidden" name="new" value="1" />
<h2>Get A Quote</h2>
<div class="d-flex">
<div class="form-group mr-2">
<label for="name" class="label">Name</label>
<input class="form-control" type="text" id="name" name="name" placeholder="Your Name" />
</div>
<div class="form-group ml-2">
<label for="email" class="label">Email</label>
<input class="form-control" type="email" id="email" name="email" placeholder="Your Email" />
</div>
</div>
<div class="form-group">
<label for="searchBox" class="label">Pick-Up Location</label>
<input class="form-control" type="text" id="searchBox" name="pickup" placeholder="Start Typing..." />
</div>
<div class="form-group">
<label for="searchBoxAlt" class="label">Drop-Off Location</label>
<input type="text" class="form-control" id="searchBoxAlt" name="dropoff" placeholder="Start Typing..." />
</div>
<div class="d-flex">
<div class="form-group mr-2">
<label for="" class="label">Departure Date</label>
<input type="text" class="form-control" id="book_pick_date" name="dep_date" placeholder="Date">
</div>
<div class="form-group ml-2">
<label for="" class="label">Return Date</label>
<input type="text" class="form-control" id="book_off_date" name="ret_date" placeholder="Date">
</div>
</div>
<div class="d-flex">
<div class="form-group mr-2">
<label for="" class="label">Pick-Up Time</label>
<input type="text" class="form-control" id="time_pick" name="dep_time" placeholder="Time">
</div>
<div class="form-group ml-2">
<label for"" class="label">Passenger Numbers</label>
<input type="number" class="form-control" id="pax_numbers" name="pax_numbers" placeholder="Amount" />
</div>
</div>
<div class="form-group">
<button type="submit" class="btn btn-primary py-3 px-4">Request Quote</button>
<p><?php
if($message = isset($message) ? $message : ''){
printf($message);
}
?></p>
</div>
</form>
</div>
</div>
</div>
</div>
<?php
}
}
?>
<script type="text/javascript" src="https://www.bing.com/api/maps/mapcontrol?key=AqIY0ivSCCdBIe3-EKGuox9cwBFw2wWRWIErZi1iy57EfD67PoiSra9wl_wu48de&callback=bingMapsReady" async defer></script>
<?php
if(isset($_GET['id'])){
$id = mysqli_real_escape_string($con, $_GET['id'] ?? DEFAULT_ID);
$sql = "SELECT * FROM pages WHERE id = $id";
$result = $con->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_array()) {
?>
<!-- HOW IT WORKS -->
<section class="ftco-section ftco-no-pt ftco-no-pb">
<div class="container">
<div class="row no-gutters">
<div class="col-md-12 wrap-about py-md-5 ftco-animate">
<div class="heading-section mb-5 pl-md-5">
<span class="subheading"><?php echo $row['description']; ?>
</span>
<h2 class="heading"><?php echo $row['name']; ?></h2>
<?php echo $row['body']; ?>
</div>
</div>
</div>
</div>
</section>
<?php
}
}
}
?>
<!-- FOOTER -->
<?php
include_once('includes/footer.php');
?>
Please note that this is just a project and will not be going live. It's for learning purposes and I am aware there are some vulnerabilities within parts of the code. Any assistance with the above issues though would really be appreciated. Thanks and have a ripper evening. Hello! http://tutudragon3.info/maths_problem_image.php My problem is: I want to get the link to this image...but in .jpg, see what I mean? a file_get_contents of that page gets me some weird binary text and stuff. Is it possible? Thanks ! I found it helpful to configure all my objects in one or several bootstrap scripts. Before doing so, I would often find myself forgetting that I already had written some class which is located deep in some script and recreating it for some other need (granted, composer definitely helped in this regard, but using it wasn't always applicable).
<?php
$c=new Pimple\Container(getMySettings());
$c['pdo'] = function ($c) {
$db = $c['settings']['mysql'];
return new \PDO(bla);
};
$c['foo'] = function ($c) {
return new Foo(
$c->get('pdo')
);
};
$c['bar'] = function ($c) {
return new Bar(
$c->get('foo')
);
};
It is all good until I find myself needing to create some new instance of some class instead of just passing some common instance to whoever needs it.
class Foo
{
private $pdo;
public function __construct(\PDO $pdo)
{
$this->pdo=$pdo;
}
public function getSomething():SomeClass
{
return new SomeClass($this->getAllDataFromDB($GET['id']));
}
}
class SomeClass
{
private $arr;
public function __construct(array $records)
{
foreach($records as $record) {
$arr[]=new SomeOtherClass($record);
}
}
}
I've read that one shouldn't create new objects in a given class's constructor, and while I could instead do so in some class's method and pass the object to the given class's constructor, to me it seems to really be the same thing. The three issues I have with this scenario a Needing to remember that these classes exist as they are hidden deep in some classes. Makes it more difficult to replace one of the classes with some other class in the future. Some duplication of code.Are there other compelling reasons not to do so? Is it worth the effort to do differently? If so, how would you recommend doing so? My thoughts would either to use Pimple's factory() method are create my only factory which also relies on anonymous functions. Maybe something else?
$c['someClass'] = $c->factory(function (array $record, Container $c) {
return new SomeClass($record);
});
Thanks How can I save an image created on-the-fly on the server? For example, $img = "<img src=ChessImager/ChessImager.php?ds_color=(176,144,112)&ls_color=(224,200,160)&coordinates=on&square_size=$square_size&fen=" . urlencode($fen) . ">"; I can display the diagram, but I want to save these images with PHP. Hi,
I'm a newbie learning web development in my spare time. I've built a LAMP server from scratch on an old PC as a learning exercise and I think the basic install and setup of that is fine as I installed PHPBB previously and that runs and is working. I've backed the server up at that point and restored so everything up to there is pretty much out of the box. I'm now coding my own web pages, so I've setup virtual hosting so I can hit them and start learning PHP, MySQL etc using quite an old book (PHP4 days) so yes things have changed. I've got an issue right at the start with sessions. It's a basic user authorisation exercise setting a session value authorising the user, and then when you click on a link, the authorised user session variable is tested to determine whether the user is allowed to view the page. This is not working and I've worked out what is happening. I can see the first being created containing the authorised user variable, and then a second empty session being created with just the session id. The session folder group is www-data with rwx permissions. The session file owner and group is www-data with rw permissions ...
-rw------- 1 www-data www-data 13 Nov 29 21:29 sess_bgih8hu82plbrvo0f9naledmdd I don't think permissions is the issue as I can read and display the $_SESSIONID in each page – which also confirms different sessions are being used. I'm also seeing the following error in the apache error log when the second page is requested ... [Fri Nov 29 20:58:27.829382 2019] [php7:notice] [pid 1065] [client x.x.x.x:x] PHP Notice: Undefined index: authuser in /var/www/licks/moviesite.php on line 22, referer: http://licksdev.com/moviemain.php There's hardly any code, it's a very basic exercise, but here you go, this is the main page ...
<?php Here is the second page. when I hit this page I get the not authorised error message:
<?php Versions ...
Ubuntu 18.04. Thanks for any help you can give. I have the following code which displays images and captions from a directory. I would like the images to be displayed in the order they were created. Somebody suggested I use glob(), but I have no idea how. <?php $dir = "exclusive_images/"; if ($opendir = opendir($dir)) { //read directory while(($file = readdir($opendir)) !==FALSE) { if ( file_exists($dir.'/'.$file) && in_array( strtolower(pathinfo($file,PATHINFO_EXTENSION )), array('png','jpg','jpeg','gif'))) { if (file_exists($dir.'/'.$file. '.txt')) $caption = file_get_contents($dir.'/'.$file. '.txt'); else $caption = ucwords(str_replace(array('-','_'),' ', substr($file, 0, (strlen ($file)) - (strlen (strrchr($file,'.')))))); echo '<tr><td><img src="' . $dir.'/'.$file .'" alt="'. $file .'" title="' . $file . '" width="200"></td><td>' . $caption . '</td></tr>'; } } } ?> |
|||||||