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PHP - Active State For Dynamic Created Subnav
Hi all, great forum so far. Am new so hope I find my way around ok.
I have been working on a site that uses mysql to store the info and then php to talk to mysql. Basically the site has a custom build CMS (I'm learning). I have created a dynamic subnav in my page where entries can be added or removed in the admin area for the site. Here is the code that pull the info etc. How can I set an active state for nav? Each sub nav link dynamically created the href. I need to find if the url is the same as the href for each subnav link. If it is then add a class called .active to that li item only. Hope that makes sense? any help would be great thank you, Code: [Select] $subnav = new DataConn; //connection to database with my classes file $subnav->query("SELECT * FROM stock_categories ORDER BY category_order"); $currCatID = 0; $currCatTitle = ''; $i = 1; ?> <ul class="subnav"> <?php while($rs_subnav = mysql_fetch_array($subnav->result)) { if ($i == 1) { $currCatID = $rs_subnav['category_id']; $currCatTitle = $rs_subnav['title']; } ?> <li><a href="stock-list.php?cat=<?php echo $rs_subnav['category_id']; ?>"><?php echo $rs_subnav['title']; ?></a></li> <?php $i++; } ?> </ul> Similar TutorialsI added <?php $_menu = ''?> <?php foreach ($this->getStoreCategories() as $_category): ?> <?php $_menu .= $this->drawItem($_category) ?> <?php endforeach ?> <?php if ($_menu): ?> <div class="nav-container"> <ul id="nav"> <li class="level0 first nav-home"><a href="<?php echo $this->getUrl() ?>"><span><?php echo $this->__('Home') ?></span></a></li> <?php echo $_menu; ?> <li class="level0 nav-1 parent"><a href="<?php echo $this->getUrl('contacts')?>"><span><?php echo $this->__('Contact') ?></span></a></li> <?php echo $this->getLayout()->createBlock('cms/block')->setBlockId('menu')->toHtml() ?> </ul> </div> <?php endif; ?> to top.phtml and it works as expected, I now have CMS links in my nav but how can I make them have active state like the category links do?? here is the site: http://pro-tools-training.com/new-magento/index.php/video-1.html Code: [Select] <div id="nav"> <ul> <li class="item"><a href="/">Home</a>/</li> <li class="item"><a href="/one">one</a></li> <li class="item"><a href="/two>two</a></li> <li class="item"><a href="/three">three</a></li> </ul> <div> i want to add class='active' to the a tags . when the menu is the current page. namely.when i on the home page. the a label is Code: [Select] <li class="item"><a href="/" class="active">Home</a>/</li> .but the others a label are not have class="active". when i on the one page. it is is Code: [Select] <li class="item"><a href="one" class="active">one</a>/</li>.the others a label are not have class="active". Am new to php... I have been battling on my dynamic checkboxes in such a way that if none is checked the form is return, also I need to retain what was checked when the form postback due to other invalid inputs. Code: [Select] $result = mysql_query("SELECT * FROM course") or die(mysql_error()); if ($result) { while ($row = mysql_fetch_array($result)){ if (isset($_POST['courses']) and $_POST['courses'] == $row['cid']) {echo $row['cid'];} print "<input type=\"checkbox\" name=\"courses[]\" value=\"$row[cid]\">$row[cname]\n"; } } Help needed purely on php codes. Thanks in advance Hi I'm hoping someone can point me in the right direction. I'm trying to create a single page that contains a couple of checkboxes. When the first checkbox is checked I want to set a session. When the second chechbox is checked I want to set a different session. When the page submits ( to itself ) I'd like the checkboxes to reflect if they are checked or not. I can sort of do that part,but I'm having major issues with unsetting the sessions and updating the checkboxes to reflect this. Does anyone have a simple example on how to do this. Many Thanks Is there a way, and if so how would I detect the state of the user on my site. Like by using their ip? Thanks! I have a class (P3TElement) that extends the DOMElement class in PHP. In there i have a public variable "attributes" which is an array, and an method named add_attribute($attr), the argument is a different class (P3TAttribute). However I am getting an error when trying to use it. The exact error is: Warning: P3TElement::add_attribute() [p3telement.add-attribute]: Invalid State Error in D:\www\p3textract\extract.php on line 110 Please see the code: http://pastebin.com/CbsM9V5W This class is supposed to extract .p3t (ps3 themes) files, and is a direct port of the python equivalent found at http://p3textractor.googlecode.com/svn/trunk/p3textractor.py Could you please help me fix this? thanks in advance, Hosh Folks, I need help (Php code ) to generate a Dynamic Text on a Base Image. What i want to do is, to make this Image as header on my Site and to make this Header Specific to a Site, i want to Add the Domain Name on the Lower Left of the Image. Got the Idea? Here is the Image link: Quote http://img27.imageshack.us/i/shoppingheader1.jpg/ PHP Variable that holds the Domain name is: $domain All i need the Dynamic PHP Codes that i can put on all my sites to generate this Text on Image (Header) Dynamically... May Anyone Help me with this Please? Cheers Natasha T. This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=312305.0 In this report I want to create a line break and a Total line for each State.
while ($row = odbc_fetch_array($result))
{
echo "<tr><td>" . $row['cmlstate']."</td>";
echo "<td>" . $row['cmlpostcode']."</td>";
echo "<td>" . $row['cmlcity']."</td>";
echo "<td>" . $row['ompSalesOrderID']."</td>";
echo "<td>" . $row['cmoName']."</td>";
echo "<td>" . number_format($row['UOMPVOLUMETOTAL'],2)."</td>";
echo "<td>" . number_format($row['UOMPTOTALBOXCOUNT'],0)."</td>";
echo "<td>" . $row['Hold']."</td></tr>";
I want to sum 'UOMPVOLUMETOTAL' for each state and create a line break between it and the next state.
}
I've got 2 database tables (states, stores) and I want to output all the states with a list of specific locations under each state. My 'states' table has a 'state_id' and 'state' while my 'stores' table has all the store information along with the 'state_id' to work with the 'states' table. How would I ago about formulating a loop to display all locations organized by each state, etc.? Any help on this would been very much appreciated. I am trying find a way to save the state of the JQuery accordions on my webpage after a user refreshes or changes webpages within my website. I have tried installing different scripts and downloading different cookie plugins but they either don't work or breaks all of the jquery functions on my webpage. Thank you.
This is in my header
<head> <link rel="stylesheet" type="text/css" href="css/styles.css"> <link rel="stylesheet" type="text/css" href="css/jquery-ui.css"> <script src="js/jquery.js"></script> <script src="js/jquery-ui.js"></script> <script type="text/javascript" src="Cookies/jquery.cookie.js"></script> </head>My Html <div id="History"> <!---Images---> <p>Today In History</p> <div> <script type="text/javascript" src="http://rss.brainyhistory.com/link/historyevents.js"></script><small><i>more <a href="http://www.brainyhistory.com/" target="_blank">History</a></i></small> </div> </div>This is my original JQuery code
$( "#History" ).accordion({
collapsible: "true",
heightStyle: "content"
});
hey guys just wondering what u think the best way to do this.....on my form registration for users....I have a drop down for countrys....but I dont want to have 2 drop downs 1 for state and 1 for province if they choose canada/usa....I have seen alot of java scrit on such sites where if you choose Canada for country, then it switches to a drop down for just provinces, not states. Same for zip code/postal code...american zip code would be like 90210 where as a postal code would be like n5j2S1. Is there a script or something already I can use with all the countrys/provinces/states etc already entered so im not re-inventing the wheel here? If someone can point me in right directon id appreciate it. Thanks This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=345840.0 Hello, mates! I am new to PHP. I want to store some data shared between requests. I know that it is possible with memcached and shared memory in Unix. What ways to do it could you advice? How could I realize background service in PHP? Thank you.
This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=306496.0 I found it helpful to configure all my objects in one or several bootstrap scripts. Before doing so, I would often find myself forgetting that I already had written some class which is located deep in some script and recreating it for some other need (granted, composer definitely helped in this regard, but using it wasn't always applicable).
<?php
$c=new Pimple\Container(getMySettings());
$c['pdo'] = function ($c) {
$db = $c['settings']['mysql'];
return new \PDO(bla);
};
$c['foo'] = function ($c) {
return new Foo(
$c->get('pdo')
);
};
$c['bar'] = function ($c) {
return new Bar(
$c->get('foo')
);
};
It is all good until I find myself needing to create some new instance of some class instead of just passing some common instance to whoever needs it.
class Foo
{
private $pdo;
public function __construct(\PDO $pdo)
{
$this->pdo=$pdo;
}
public function getSomething():SomeClass
{
return new SomeClass($this->getAllDataFromDB($GET['id']));
}
}
class SomeClass
{
private $arr;
public function __construct(array $records)
{
foreach($records as $record) {
$arr[]=new SomeOtherClass($record);
}
}
}
I've read that one shouldn't create new objects in a given class's constructor, and while I could instead do so in some class's method and pass the object to the given class's constructor, to me it seems to really be the same thing. The three issues I have with this scenario a Needing to remember that these classes exist as they are hidden deep in some classes. Makes it more difficult to replace one of the classes with some other class in the future. Some duplication of code.Are there other compelling reasons not to do so? Is it worth the effort to do differently? If so, how would you recommend doing so? My thoughts would either to use Pimple's factory() method are create my only factory which also relies on anonymous functions. Maybe something else?
$c['someClass'] = $c->factory(function (array $record, Container $c) {
return new SomeClass($record);
});
Thanks Hello! http://tutudragon3.info/maths_problem_image.php My problem is: I want to get the link to this image...but in .jpg, see what I mean? a file_get_contents of that page gets me some weird binary text and stuff. Is it possible? Thanks ! Hi all I need to combine these two scripts: Firstly, the following decides which out of the following list is selected based on its value in the mySQL table: <select name="pack_choice"> <option value="Meters / Pack"<?php echo (($result['pack_choice']=="Meters / Pack") ? ' selected="selected"':'') ?>>Meters / Pack (m2)</option> <option value="m3"<?php echo (($result['pack_choice']=="m3") ? ' selected="selected"':'') ?>>Meters / Pack (m3)</option> <option value="Quantity"<?php echo (($result['pack_choice']=="Quantity") ? ' selected="selected"':'') ?>>Quantity</option> </select> Although this works OK, I need it also to show dynamic values like this: select name="category"> <?php $listCategories=mysql_query("SELECT * FROM `product_categories` ORDER BY id ASC"); while($categoryReturned=mysql_fetch_array($listCategories)) { echo "<option value=\"".$categoryReturned['name']."\">".$categoryReturned['name']."</option>"; } ?> </select> I'm not sure if this is possible? Many thanks for your help. Pete How can I save an image created on-the-fly on the server? For example, $img = "<img src=ChessImager/ChessImager.php?ds_color=(176,144,112)&ls_color=(224,200,160)&coordinates=on&square_size=$square_size&fen=" . urlencode($fen) . ">"; I can display the diagram, but I want to save these images with PHP. Hi,
I'm a newbie learning web development in my spare time. I've built a LAMP server from scratch on an old PC as a learning exercise and I think the basic install and setup of that is fine as I installed PHPBB previously and that runs and is working. I've backed the server up at that point and restored so everything up to there is pretty much out of the box. I'm now coding my own web pages, so I've setup virtual hosting so I can hit them and start learning PHP, MySQL etc using quite an old book (PHP4 days) so yes things have changed. I've got an issue right at the start with sessions. It's a basic user authorisation exercise setting a session value authorising the user, and then when you click on a link, the authorised user session variable is tested to determine whether the user is allowed to view the page. This is not working and I've worked out what is happening. I can see the first being created containing the authorised user variable, and then a second empty session being created with just the session id. The session folder group is www-data with rwx permissions. The session file owner and group is www-data with rw permissions ...
-rw------- 1 www-data www-data 13 Nov 29 21:29 sess_bgih8hu82plbrvo0f9naledmdd I don't think permissions is the issue as I can read and display the $_SESSIONID in each page – which also confirms different sessions are being used. I'm also seeing the following error in the apache error log when the second page is requested ... [Fri Nov 29 20:58:27.829382 2019] [php7:notice] [pid 1065] [client x.x.x.x:x] PHP Notice: Undefined index: authuser in /var/www/licks/moviesite.php on line 22, referer: http://licksdev.com/moviemain.php There's hardly any code, it's a very basic exercise, but here you go, this is the main page ...
<?php Here is the second page. when I hit this page I get the not authorised error message:
<?php Versions ...
Ubuntu 18.04. Thanks for any help you can give. |
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